A charged particle moves from point A to point B in an external electric field, and in the process its kinetic energy decreases fro, 87.6 J at A to 57.3 J at B. The electric potential at A is -48.0 V, and the electric potential at B is 18.0 V. What is the charge of the particle, including sign

'In a collision between a huge SUV and a small hybrid car, the SUV exerts a larger force on the hybrid than the hybrid exerts on the SUV' is false.

Every action has an equal and opposite response, according to Newton's third law of motion.

The above law says that, forces on both the vehicles are equal and opposite.

So, the force exerted by a huge SUV and a small hybrid car are the same. And SUV does not exert a larger force as it is huge.

Impact on both the vehicles is also same as the impulse is nothing but the force multiplied by the time of contact. The time of contact is same for both vehicles.

Thus, the above statement is false.

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One notable athlete who has been associated with the use of performance-enhancing drugs (PEDs) is the American professional cyclist Lance Armstrong.

Armstrong gained worldwide recognition for his unprecedented seven consecutive victories in the Tour de France from 1999 to 2005. However, his remarkable achievements were tarnished when it was revealed that he had engaged in systematic doping throughout his career.

In 2012, after years of denial, Armstrong finally admitted to using banned substances, including erythropoietin (EPO), testosterone, corticosteroids, and blood transfusions, to enhance his performance. These substances boosted his endurance and oxygen-carrying capacity, providing him with an unfair advantage over his competitors. Armstrong's confession came after substantial evidence, including testimonies from teammates and extensive investigations, exposed his involvement in one of the most elaborate and sophisticated doping schemes in sports history.

Following his admission, Armstrong was stripped of his Tour de France titles and received a lifetime ban from professional cycling. The revelations surrounding his drug use had a profound impact on the sport, shaking its credibility and raising concerns about the prevalence of doping in cycling.

Armstrong's story serves as a cautionary tale, highlighting the ethical and moral dilemmas associated with doping in sports. His case underscores the importance of maintaining the integrity of athletic competition, the significance of stringent anti-doping measures, and the need for education and awareness regarding the risks and consequences of performance-enhancing substances.

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The extension of the cable is  8.48 x 10⁻⁴ N/m².

The extension of the cable is calculated by applying the formula for Young's modulus as shown below.

ΔL = ( FL₀ ) / ( AY )

where;

The extension of the cable is calculated as follows;

ΔL = ( 922 x 9.86 ) / ( π x 0.00413² x 2 x 10¹¹ )

ΔL = 8.48 x 10⁻⁴ N/m²

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Answer:

yes

Explanation:

gl m8

Hi there!

We can use the following equation:
\(\large\boxed{V = I R}\)

V = potential difference (? V)
I = Current (16A)
R = Resistance (192Ω)

Plug in the givens and solve:

\(F = 16 \times 192 = \boxed{3072 V}\)

The pattern of lines of force around two positive charges separated from each other demonstrates the repulsive nature of like charges and the direction and strength of the electric field between them.

When two positive charges are separated from each other, the lines of force (also known as electric field lines) originate from one positive charge and terminate on the other positive charge. The lines of force follow a pattern that reflects the repulsion between the positive charges.

Here's a verbal description of the pattern:

From each positive charge, the lines of force radiate outward in all directions.

The lines of force are evenly spaced and radially symmetric around each charge, indicating that the electric field strength is the same at all points along a given line.

As the lines of force move away from each charge, they curve away from each other, reflecting the repulsion between the positive charges.

The density of lines of force is higher near the charges and decreases as they move further apart.

The lines of force never cross each other, maintaining their continuous and unbroken nature.

look more  Sketch the pattern

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The x component of the vector is determined as 8.03 m.

The x component of the vector is calculated by applying the following formula as shown below;

Vx = V cosθ

where;

The  x component of the vector is calculated as follows;

Vx = 12.1 m x cos (48.4⁰)

Vx = 8.03 m

Thus, the x component of the vector is determined as 8.03 m.

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Answer: I think the ans is A but I’m not sure.

Can someone check it and tell me I would like to know

When the overcurrent protection for a conductor is located on the load end rather than the supply side of a conductor it is considered to be a tap conductor.

The National Electrical Code (NEC), the benchmark for safe electrical design, installation, and inspection to protect people and property from electrical hazards, defines a tap conductor as a conductor, other than a service conductor, that has overcurrent protection rated more than the ampacity of a conductor. A tap conductor has overcurrent protection ahead of its point of supply that exceeds the value permitted for similar conductors that are protected as described in NEC 240.4. Hence, when the overcurrent protection for a conductor is located on the load end rather than the supply side of a conductor it is considered to be a tap conductor.

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It will take the toy  5.02 seconds to reach the ground, The speed at which the toy hits the ground is 49.0 m/s.

Free fall is the motion of an object falling solely under the influence of gravity. In free fall, the object experiences an acceleration of 9.8 m/s^2 downwards towards the ground (assuming no air resistance), regardless of its mass or size.

a. To determine the time it takes for the toy to reach the ground, we can use the formula for the height of an object in free fall:

h = (1/2)gt^2

Where h is the initial height, g is the acceleration due to gravity, and t is time.

At the instant the toy is dropped, its initial height above the ground is h = 120.0 m, and the acceleration due to gravity is g = 9.8 m/s^2. Thus, we can rearrange the formula to solve for time:

t = sqrt(2h/g)

t = sqrt(2(120.0 m)/(9.8 m/s^2)) = 5.02 s

So, it will take the toy approximately 5.02 seconds to reach the ground.

b. To find the speed at which the toy hits the ground, we can use the formula for final velocity in free fall:

v = sqrt(2gh)

Where v is the final velocity, g is the acceleration due to gravity, and h is the initial height. At impact, the initial height of the toy is 0 m. Therefore:

v = sqrt(2gh)

v = sqrt(2(9.8 m/s^2)(120.0 m))

v = 49.0 m/s

So, the speed at which the toy hits the ground is approximately 49.0 m/s.

Hence, The toy will fall to the earth in 5.02 seconds, hitting the ground at a speed of 49.0 m/s.

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Answer:

61.33 Kg

Explanation:

From the question given above, the following data were obtained:

Distance = 1×10² m

Time = 9.5 s

Kinetic energy (KE) = 3.40×10³ J

Mass (m) =?

Next, we shall determine the velocity Leroy Burrell. This can be obtained as follow:

Distance = 1×10² m

Time = 9.5 s

Velocity =?

Velocity = Distance / time

Velocity = 1×10² / 9.5

Velocity = 10.53 m/s

Finally, we shall determine the mass of Leroy Burrell. This can be obtained as follow:

Kinetic energy (KE) = 3.40×10³ J

Velocity (v) = 10.53 m/s

Mass (m) =?

KE = ½mv²

3.40×10³ = ½ × m × 10.53²

3.40×10³ = ½ × m × 110.8809

3.40×10³ = m × 55.44045

Divide both side by 55.44045

m = 3.40×10³ / 55.44045

m = 61.33 Kg

Thus, the mass of Leroy Burrell is 61.33 Kg

a) The total surface area of tin G in terms of π is 170π cm².

b) The mass of tin H is 336 g.

To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.

a) Total surface area of tin G in terms of π:

The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:

Lateral surface area = 2πrh

where r is the radius of the base and h is the height of the cylinder.

In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:

Lateral surface area = 2π(5 cm)(12 cm)

Lateral surface area = 120π cm²

Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:

Area of a circle = πr²

The radius of the circular base of tin G is 5 cm, so the area of each circular base is:

Area of each circular base = π(5 cm)²

Area of each circular base = 25π cm²

To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:

Total surface area of tin G = Lateral surface area + 2 × Area of each circular base

Total surface area of tin G = 120π cm² + 2 × 25π cm²

Total surface area of tin G = 120π cm² + 50π cm²

Total surface area of tin G = 170π cm²

Therefore, the total surface area of tin G in terms of π is 170π cm².

b) Mass of tin H:

We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:

(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)

Using the given values, we have:

(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)

Cross-multiplying and solving for the mass of tin H, we get:

(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)

mass of tin H = (72 g) × (792π cm²) / (170π cm²)

mass of tin H = 336 g

Therefore, the mass of tin H is 336 g.

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Answer:

Serotonin

___________

Answer:

180

Explanation:

1) E=F*L, where E - energy of the baseball, F - the required force, L - backward moving (0.35m);

2) E=mV²/2, where E - energy of the baseball, m - the mass of the baseball (0.14kg), V - the velocity of the baseball (30m/s).

3) if E=F*L and E=mV²/2, then F*L=mV²/2, from which

\(F=\frac{mV^2}{2L};\)

4) according to the last formula

\(F=\frac{0.14*900}{2*0.35}=\frac{126}{0.7}=180(N).\)

The force exerted by the ball on the glove is 180 Newtons.

In mechanics, a force is any action that has the potential to change, maintain, or deform a body's motion. The three principles of motion outlined by Isaac Newton in his Principia Mathematica are frequently used to illustrate the concept of force (1687).

Newton's first law states that a body at rest or moving uniformly in a straight line will stay in that state until a force is applied to it. According to the second law, a body will accelerate (change in velocity) in the direction of any external force acting on it.

Given:

A baseball (m = 140 g) traveling at 30 m/s moves a fielder's glove backward 35 cm when the ball is caught,

Calculate the value of force as shown below,

Force = m × V² / 2L

Force = 0.140 × 30² / 2 × 0.35

Force = 0.140 × 900 / 0.70

Force = 126 / 0.7

Force = 180 N

Thus, the force exerted by the ball is 180 Newtons.

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The force and acceleration alter as the object moves away from its equilibrium position.

The force on the object at any point is given by Hooke's Law:

F = -kx

where F = force, k = force constant of the spring, and x = displacement of the object from its equilibrium position.

The acceleration of the object at any point is given by Newton's Second Law:

a = F/m

where a = acceleration, F = force, and m = mass of the object.

Using these equations, calculate the force and acceleration at each of the specified points:

At x = 0.100 m:

F = -kx = -(1.30 x 10 N/m)(0.100 m) = -0.130 N

a = F/m = (-0.130 N)/(0.350 kg) = -0.371 m/s² (the negative sign indicates that the acceleration is in the opposite direction to the displacement)

At x = 0:

F = -kx = -(1.30 x 10 N/m)(0) = 0 N (the spring is at its equilibrium position)

a = F/m = 0 N/0.350 kg = 0 m/s²

At x = -0.0500 m:

F = -kx = -(1.30 x 10 N/m)(-0.0500 m) = 0.065 N (note that the force is positive because the displacement is negative)

a = F/m = (0.065 N)/(0.350 kg) = 0.186 m/s²

At x = -0.100 m:

F = -kx = -(1.30 x 10 N/m)(-0.100 m) = 0.130 N

a = F/m = (0.130 N)/(0.350 kg) = 0.371 m/s²

So, the force and acceleration change with the displacement of the object from its equilibrium position.

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Explanation:

We have,

A projectile is launched at an angle 60° to the horizontal  with some initial speed 45 m/s.

The cliff is 265 m high.

(A) The final velocity of the projectile is given by :

\(v_f^2-v_i^2=2gs\\\\v_f^2=2gs+v_i^2\\\\v_f^2=2\times 9.8\times 265+45^2\\\\v_f=84.96\ m/s\)

(B) The maximum height of the projectile is given by :

\(H=\dfrac{v_i^2\sin^2\theta}{2g}\\\\H=\dfrac{45^2\times \sin^2(60)}{2\times 9.8}\\\\H=77.48\ m\)

(C) The  horizontal range of the motion is given by :

\(R=\dfrac{v_i^2\sin 2\theta}{g}\\\\R=\dfrac{(45)^2\times \sin 2(60)}{9.8}\\\\R=178.94\ m\)

Answer:

2 m

Explanation:

speed=frequency×wavelength

wavelength=speed/frequency

wavelength=1000/500

=2 m

Pretty sure the average speed of the bus is v = 1.55 m/s

Answer:

The first mechanical means for transmitting real-time stock market data from exchange floors to brokers and investors across the country.

Explanation:

Answer:

f = 44.83 Hz

Explanation:

The formula for series LCR circuit is given by :

\(f=\dfrac{1}{2\pi \sqrt{LC} }\)

Where

L is inductance, L = 900 mH = 0.9 H

Capacitance, C = 0.014 mF = 0.000014 F

Put the required values,

\(f=\dfrac{1}{2\pi \sqrt{0.9\times 0.000014} }\\\\f=44.83\ Hz\)

So, the required resonant frequency for series LCR circuit is 44.83 Hz.

Answer:

» The image is laterally inverted.

» The image is upright.

» The image geometry is same as object geometry.

» Image distance is same as object distance.

» Image is not real, it's virtual ( not formed on screen ).

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The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer:

A.) Work function = 2.3 eV

B.) Max. K.E observed = 1.1 eV

Explanation:

A.) Millikan observed a maximum kinetic energy of 0.550 eV when electrons were ejected with 433.9-nm light. When light of 253.5 m was used, he observed a maximum kinetic energy of 2.57 eV. 

work function (f) is the minimum energy required to remove an electron from the surface of the material.

hf = Ø + K.E (maximum)

Where

h = Plank constant 6.63 x 10-34 J s

Ø = work function

hc/λ = Ø + K.E (max)

(6.63×10^-34 × 3×10^8)/433.9×10^-9 = Ø + 0.550 × 1.6×10^-19

4.58×10^-19 = Ø + 8.8×10^-20

Ø = 4.58×10^-19 - 8.8×10^-20

Ø = 3.7 × 10^-19 J

Converting Joule to eV

Ø = 3.7 × 10^-19/1.6×10^-19

Ø = 2.3 eV

B.) When light of wavelength 362.4 m is used

The maximum K.E observed = incident light K.E - (the work function).

Incident K.E = hf = hc/λ

Incident K.E =

(6.63×10^-34 × 3×10^8)/362.4

Incident K.E = 5.5 × 10^-28J

Let's convert joule to eV

Incident K.E = 5.5×10^-28/1.6×10^-19

Incident K.E = 3.4 × 10^-9

Max. K.E observed = 3.4 - 2.3

Max. K.E observed = 1.1 eV

Answer:

x-component = 0.237 [m]

Explanation:

In order to solve this problem in an easy way, we must first make a sketch of the vector and its respective angle with the X-axis, in the attached image we can see that sketch.

Since the X component of the vector is needed, this component can be found by means of the cosine of the angle and its hypotenuse.

x-component = 0.250*cos(18.4)

x-component = 0.237 [m]

Answer:

x = 0.237

y = -0.0789

Explanation:

ANSWER

0.02 m³

EXPLANATION

By the Archimedes' Principle, the weight of a floating object is equal to the weight of the water displaced by the object,

This is,

We know that the weight of the canoe is 200N, so there is no need to find its mass. Also, the mass is the product of the density and the volume,

The density of water is 1000 kg/m³, the acceleration due to gravity g is 9.8m/s² and the weight of the canoe is 200N. Solve for the volume of water,

Hence, the volume of water displaced by the canoe is 0.02m³.

Answer:

The mean distance of Earth from the Sun is 149.6 × 10^6 km and the mean distance of Mercury from the Sun is 57.9 × 10^6 km.

hope it helps you

The average mean distance of Earth from the sun is 149.6 x 10⁶ km. Hence, option (c) is correct option.

The solar system is the collection of the sun, planets, and other celestial bodies that rotate around it. A belt of asteroids and eight planets make up our solar system. Considered a dwarf planet, Pluto.

In a constant orbit around the sun, every planet in the solar system orbits. Compared to planets farthest from the sun, planets closer to it revolve more quickly.

The star that is closest to Earth is the sun. Heat and light are continuously emitted from it. For all of the planets in our solar system, it is the primary source of heat and light energy.

In our solar system, only the earth is a planet that supports life. The presence of an atmosphere, water, and the proper distance from the sun are only a few of the ideal conditions that allow life to exist on earth.

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