A certain half-reaction has a standard reduction potential E0red = +0.13V . An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 1.10V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell.

Required:
a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?
b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?

The heat capacity of liquid is  1.53 J/ g°C

Heat capacity measures the energy required to raise temperature of a unit mass of a substance by a unit degree

Formula used:

          Q = m × c ×  ΔT

               = m × c × ( T₂ - T₁ )

where,

Q = Amount of heat gained or lost  = 53 J

m = mass of liquid = 15 g

c = specific heat of liquid = ?

ΔT = change in temperature

T₁ = initial temperature = 10.7 °C

T₂ = final temperature = 13 °C

Substituting the values in the formula

        53 J = 15 g × c × ( 13 - 10.7) °C

         53 J = 15 g × c × 2.3 °C

             c = 53/ ( 15 × 2.3 )

                = 1.53 J/ g°C

Thus we can conclude that the heat capacity of liquid is  1.53 J/ g°C

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The gravimetric factor for Br- using silver bromide is 0.425.

The gravimetric factor is an expression that is used to convert grams of a compound into grams of a single element.

It is expressed as a ratio of the formula weight (FW) of the substance that is being determined to that of a second substance that is weighed.

For example formula of silver bromide is AgBr and the formula mass of silver bromide is 188 g/mol

Formula mass of bromide ion = 80 g/mol

Gravimetric factor = 80/1188

Gravimetric factor = 0.425

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Answer:

It is important for you find a job that matches your skills, interests and abilities when searching for a career because then you will be satisfied with what you do and your career because since it fits your wants, skills, interests and abilities you will do a great job while working and completing tasks. Overall you'll be happy because that's the perfect job for you.

Explanation:

Answer:

hey what up

Explanation:

Answer:

D produce energy

Explanation:

Mitochondria are membrane-bound cell organelles (mitochondrion, singular) that generate most of the chemical energy needed to power the cell's biochemical reactions.

Answer:produce energy

Explanation:

In 0.8291 moles of hexane (\(C_6H_1_4\)) there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

To determine the number of liters in 0.8291 moles of hexane (C6H14), we need to use the ideal gas law equation:

PV = nRT

where:

P = pressure (atm)

V = volume (L)

n = moles of gas

R = gas constant (0.0821 L*atm/mol*K)

T = temperature (K)

We need to rearrange this equation to solve for V:

V = nRT/P

First, we need to calculate the number of moles of hexane:

n = mass/molar mass

The molar mass of hexane (C6H14) is:

6(12.01 g/mol) + 14(1.01 g/mol) = 86.18 g/mol

n = 0.8291 moles

Next, we need to convert the temperature to Kelvin. Assuming room temperature (25°C or 298 K):

T = 298 K

Finally, we need to assume a pressure value. Let's assume atmospheric pressure (1 atm).

P = 1 atm

Now we can plug in the values and solve for V:

V = (0.8291 mol)(0.0821 L*atm/mol*K)(298 K)/(1 atm)

V = 20.8 L

Therefore, there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

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Answer:

1. This reaction is: B. Endothermic.

2. When the temperature is increased the equilibrium constant, K: A. Increases.

3. When the temperature is increased the equilibrium concentration of NO2: A. Increases.

Explanation:

Hello,

In this case, considering the images, we can state that the red color at high temperature is due to the presence of nitrogen dioxide (product) and the lower coloring is due to the presence of dinitrogen tetroxide (reactant) at low temperature.

With the aforementioned, we can conclude that the chemical reaction:

\(N_2O_4(g) \rightleftharpoons 2 NO_2(g)\)

Is endothermic since high temperatures favor the formation of the product and the low temperatures favor the consumption of the the reactant. thereby:

1. This reaction is: B. Endothermic.

2. When the temperature is increased the equilibrium constant, K: A. Increases. In this particular case, since the dinitrogen tetroxide has 1 molecule and nitrogen dioxide two molecules in the chemical reaction, the entropy change should be positive, therefore, by increasing the T, the Gibbs free energy of reaction becomes more negative:

\(G=H-TS\)

As Gibbs free energy becomes more negative, the equilibrium constant becomes bigger given their relationship:

\(K=exp(-\frac{\Delta G}{RT} )\)

3. When the temperature is increased the equilibrium concentration of NO2: A. Increases.

Regards.

Answer:

a. n = 3

b. n = 4

Explanation:

n is just the number in front of the orbital, as n represents the energy level of the orbital.

Answer:

1. n=3

2.n=4

Explanation:n is the number infront of the orbital that representgsthe energy level

Answer:

0.147

Explanation

PV/RT

Answer:

0.2257kg

Explanation:

Using the formula density= mass/ volume

22.57g/cm³=mass/10cm³

mass = 22.57g/cm³*10cm

=225.7g

but in kg

= 0.2257kg

In this question, we have to use the Ideal gas Law formula in order to find the missing volume, for this formula we have:

PV = nRT

We have:

P = 1.0 atm

V = ?

n = 3.2 moles

R is the gas constant = 0.082

T = 25°C, but we need it in Kelvin, 298 K

Now adding these values into the formula:

1 * V = 3.2 * 0.082 * 298

V = 78.2 Liters of Volume

Answer:2-chloro-1,3-dimethylcyclopentane

Explanation

Answer:

p = 900 kg·m/s

Explanation:

Calculate momentum given mass and velocity:

P = M*V

p = 150*6

The volume of the water is obtained as 72 mL.

We know that the heat of vaporization is the heat that is required to raise convert the substance from the liquid state to the gaseous state. Now, we know that we can be able to find the energy from the use of the formula;

H = mL

H = heat that is required

m = Number of moles of the object

L = Heat of vaporization

We know from the problem that we have that;

H = 163 kJ

L = 40.66 kJ/mol

Then we would have;

Number of moles = H/L

= 163kJ/40.66 kJ/mol

=  4 moles

Mass of water = 4 moles * 18 g/mol = 72 g

Since the density of water = 1 g/mL

Volume = Density * mass

= 1 g/mL * 72 g

= 72 mL

Thus, the volume of the water that would be vaporized in the process that we have described is about a volume of 72 mL.

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Answer:

See the answer below

Explanation:

Organic molecules in the form of carbohydrates are created during photosynthesis or chemosynthesis and these processes cause carbon to be removed from the atmosphere or other environment into the biosphere - the living organisms of the ecosystem.

During photosynthesis, atmospheric carbon dioxide is fixed as carbohydrates into green plants in a two-stage process that requires sunlight energy and water. The entire process can be summarized as an equation below:

\(6CO_2 + 6H_2O + sunlight --> C_6H_1_2O_6 + 6O_2\)

Instead of using water as a reactant, chemosynthetic organisms make use of high energy chemicals such as hydrogen sulfide to fix carbon dioxide in order to generate carbohydrates.

\(CO_2 + 4H_2S + O_2 -> CH_20 + 4S + 3H_2O\)

Both processes ensure that carbon dioxide moves from the environment into living organisms.

In an ecosystem, the  impact of soil Science to the development of Ghana's agriculture is that it provides suitable conditions for root germination and growth.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

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​

Answer:

don't understand make it clear

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Answer:

It is commonly used as a fertilizer or feed supplement

The mass of oxygen, O₂ required to react with the 23.780 g of acetaldehyde, CH₃CHO is 8.636 g

The mass of oxygen, O₂ required to react with the 23.780 g of acetaldehyde, CH₃CHO can be obtain as follow:

2CH₃CHO + O₂ → 2HC₂H₃O₂

From the balanced equation above,

88.106 g of CH₃CHO reacted with 32 g of O₂

Therefore,

23.780 g of CH₃CHO will react with = (23.780 × 31.998) / 88.106 = 8.636 g of O₂

Thus, the mass of oxygen required for the reaction is 8.636 g. None of the options are correct

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The general gas equation, commonly referred to as the ideal gas law, represents the state of a fictitious ideal gas through an equation. Here the mass of helium gas required to pressurize 86 L tank to 201 atm is 2561.8 g.

According to the ideal gas law, the sum of the absolute temperature of the gas and the universal gas constant is equal to the product of the pressure and volume of one gram of an ideal gas.

The ideal gas equation is given as:

PV = nRT

n = PV / RT

56°C = 329 K

n = 201 × 86 / 0.08206 × 329 = 640.45 mol

Molar mass of 'He' = 4.00 g / mol

Mass =  640.45 × 4.00 = 2561.8 g

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Answer:

It is made out of granite.

Explanation:

This is because of the tectonic plates.

Answer:10.26

Explanation:given data ,

The pH of the resulting eqilibrium is solution is 10.26

The net ionic equation for the reaction between potassium sulfide and magnesium iodide is S2- + Mg2+ -> MgS, as the potassium and iodide ions are spectator ions and do not participate in the reaction.

To determine the net ionic equation for the reaction between potassium sulfide (K2S) and magnesium iodide (MgI2), we first need to identify the ions present in each compound and then determine the products formed when they react.

Potassium sulfide (K2S) dissociates into two potassium ions (K+) and one sulfide ion (S2-):

K2S -> 2K+ + S2-

Magnesium iodide (MgI2) dissociates into one magnesium ion (Mg2+) and two iodide ions (I-):

MgI2 -> Mg2+ + 2I-

Now, we need to determine the possible products when these ions combine. Since potassium (K+) has a +1 charge and iodide (I-) has a -1 charge, they can combine to form potassium iodide (KI):

K+ + I- -> KI

Similarly, magnesium (Mg2+) and sulfide (S2-) can combine to form magnesium sulfide (MgS):

Mg2+ + S2- -> MgS

Now, we can write the complete ionic equation by representing all the ions present before and after the reaction:

2K+ + S2- + Mg2+ + 2I- -> 2KI + MgS

To obtain the net ionic equation, we remove the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the spectator ions are the potassium ions (K+) and the iodide ions (I-).

Thus, the net ionic equation for the reaction between potassium sulfide and magnesium iodide is:

S2- + Mg2+ -> MgS

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The highest electric force exerted by charges -4 ×10⁻⁵ C and 3 ×10⁻⁵ C  placed 0.5 m apart is equal to 43.15 N.

The lowest electric force exerted by charges 3 ×10⁻⁵ C and 3 ×10⁻⁵ C  placed 1 m apart is equal to 8.10 N.

According to Coulomb’s law, the force of attraction between two charges is equal to the product of their charges and is inversely proportional to the square of the distance. This electric force applies along the line joining the two charges.

The magnitude of the electric force can be written as follows:

\(\displaystyle F = k\frac{q_1q_2}{r^2}\)

where k is constant proportionality = 8.99 × 10⁹ N.m²/C².

Given the charge on one point charge, q₁ =  4 ×10⁻⁵ C

The charge on the other point charge, q₂ = - 3 × 10⁻⁵C

The distance between these two charges, r = 0.5 m

The magnitude of electric force between the charges  will be:

\(\displaystyle F = 8.99\times 10^{9}\times \frac{4\times 10^{-5}\times 3\times 10^{-5}}{(0.5)^2}\)

F = 43.15 N

Given the charge on one point charge, q₁ =  3 ×10⁻⁵ C

The charge on the other point charge, q₂ = 3 × 10⁻⁵C

The distance between these two charges, r = 1 m

The magnitude of force between the charges will be:

\(\displaystyle F = 8.99\times 10^{9}\times \frac{3\times 10^{-5}\times 3\times 10^{-5}}{(1)^2}\)

F = 8.1 N

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The ion with a +3 charge, 28 electrons, and an atomic mass of 71 is the aluminum ion (\(Al^{3+}\)).

Aluminum (Al) typically has an atomic number of 13, which means it has 13 protons and 13 electrons in its neutral state. However, in the given ion, \(Al^{3+}\), the ion has lost three electrons, resulting in a +3 charge. This means that the ion now has 13 protons and only 10 electrons remaining, giving it a net positive charge of +3.

The atomic mass of aluminum is 26.98 atomic mass units (amu). The given ion has an atomic mass of 71 amu, which suggests that the ion has gained additional particles. In this case, the ion has also gained three neutrons, resulting in a higher atomic mass.

The total number of particles (protons, neutrons, and electrons) in the ion can be calculated by adding the number of protons (13) and the number of neutrons (3), which equals 16. Since the ion has a net charge of +3, it only contains 10 electrons.

In summary, the ion with a +3 charge, 28 electrons, and an atomic mass of 71 is the aluminum ion (\(Al^{3+}\)), which has 13 protons, 10 electrons, and 3 neutrons.

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Answer:

At standard temperature and pressure, 44.8

Explanation:

The cell potential is equal to the sum of the reduction potential and the oxidation potential, so the cell potential is equal to 0.21 V.

Cell potential is a measure of the potential difference between the inside and outside of a cell. It is also known as membrane potential, transmembrane potential, or transmembrane voltage. It is the voltage difference between the cytoplasm and the extracellular fluid of a cell. Cell potential is generated by the movement of ions across the cell membrane and is affected by the concentration of ions inside and outside the cell.

The first step in finding the cell potential of a cell is to calculate the reduction potentials of the half-reactions occurring in the cell. In this case, the two half-reactions occurring in the cell are the reduction of FeCl₂ to Fe and the oxidation of Cu to CuSO₄.
The reduction potential for the reduction of FeCl₂ to Fe can be calculated using the Nernst equation:
E° = -0.0257 log [FeCl₂] = -0.0257 log (0.00165) = 0.09 V
The oxidation potential for the oxidation of Cu to CuSO₄ can be calculated using the Nernst equation:
E° = 0.3414 log [CuSO₄] = 0.3414 log (0.0125) = 0.12 V
The cell potential is equal to the sum of the reduction potential and the oxidation potential, so the cell potential is equal to 0.21 V.

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