Using proportions, it is found that the total cost of three bottles of detergent is of $11.55.
What is a proportion?A proportion is a fraction of a total amount.
A certain brand of laundry detergent is manufactured for $4.40 and then marked up 25% by the local store before selling, hence the price of each bottle is given by:
P = 4.40 x 1.25 = $5.50.
The store offers a 30% discount with the purchase of three or more bottles of the detergent, hence the total cost is given by:
T = (3 x 5.50) x 0.7 = $11.55.
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Mr. Green orders some cookies from a local youth group. Using his order form shown below, complete the last column to find the total to be paid. Quantity Description Unit Price Total of Line 1 Krispy Kosmos $2.89 $ 2 Chewy Chocos $3.19 $ 1 Gooey Globs 2.99 $ Total $ 5.2% tax $ Total to be paid $ a. $9.54 b. $12.26 c. $12.90 d. $18.64 Please select the best answer from the choices provided A B C D
From the computation done, it can be denoted that the total price that will be paid will be $12.90.
1 Krispy Kosmos at $2.89 = $2.89
2 Chewy Chocos at $3.19 each = 2 × $3.19 = $6.38
1 Gooey Globs at $2.99 = $2.99
Total = $2.89 + $6.38 + $2.99 = $12.26
We'll then add the sales tax of 5.2%, therefore, the total value will be:
= $12.26 + (5.2% × $12.26)
= $12.26 + $0.638
= $12.90
In conclusion, the correct option is $12.90.
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Answer:
C
Step-by-step explanation:
Edg 2022
in 1940 john atansoff a physicist from iows state university wanted to solvve a 29 x 29 linear system of equations. how many arithmetic operations would this have required.
In 1940, John Atanasoff, a physicist from Iowa State University, wanted to solve a 29 x 29 linear system of equations. To solve this system using Gaussian elimination, it would have required approximately 29^3/3 = 24389 arithmetic operations.
In 1940, John Atanasoff developed the Atanasoff-Berry Computer (ABC), which was the first electronic computer. Atanasoff wanted to use the ABC to solve a 29 x 29 linear system of equations.
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I know how to do this, but for some reason got it wring on a Test. Can someone demonstrate how to do it so that I know what I'm doing wrong?
Answer:
Answer on a graph
Combine like term
82x - 26y - 60z - 15y+49z - 53x
Answer:
29x-41y-11z
Step-by-step explanation:
Answer:
29 x − 41 y- 11 z
Step-by-step explanation:
The radioactive element carbon-14 has a half-life of 5750 years. A scientist determined that the bones from a mastodon had lost 70.3% of their carbon-14. How old were the bones at the time they were discovered?
The bones at the time they were discovered when the radioactive element carbon-14 has a half-life of total 5750 years are 10062.5-year-old.
What is half-lives?Half lives is the time interval which is need to decay the atomic nuclei of a radioactive sample.
There is a scientist who determined that the bones from a mastodon had lost 70.3% of their carbon-14. Thus, the fraction remaining is,
f=1-(70.3/100)=1-0.703
f=1-(70.3/100)=0.297
Now the fraction remaining can be given as,
f=(1/2)ⁿ
Here, n is the half life elapsed. Put the value of fraction remaining.
0.297=(1/2)ⁿ
n=1.75
The radioactive element carbon-14 has a half-life of total 5750 years. Thus,
Years=1.75*5750
Years=10062.5
Thus, the bones at the time they were discovered when the radioactive element carbon-14 has a half-life of total 5750 years are 10062.5-year-old.
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A number that is at most 30 as an inequality
Answer:
n ⩽ 30
Step-by-step explanation:
1. If three squares have sides that make an acute triangle. then the sum of the areas of the two small squares...
2. If three squares have sides that make an obtuse triangle. then the sum of the areas of the two small squares...
3. If three squares have sides that make a right triangle. then the sum of the areas of the two small squares...
then the sum of the areas of the two smaller squares will be equal to the area of the largest square.
if three squares have sides that make an acute triangle, then the sum of the areas of the two small squares is equal to the area of the largest square. This is known as the Pythagorean Theorem, which states that in a right triangle, the sum of the squares of the two shorter sides is equal to the square of the longest side (the hypotenuse). However, in an acute triangle, there is no side that is longer than the other two sides, and so the three squares cannot form a right triangle. Therefore, the sum of the areas of the two smaller squares cannot be determined from the information given.
If three squares have sides that make an obtuse triangle, then the sum of the areas of the two small squares is less than the area of the largest square. In an obtuse triangle, one of the angles is greater than 90 degrees, which means that the square with its side opposite the obtuse angle will have a larger area than the other two squares. Therefore, the sum of the areas of the two smaller squares will be less than the area of the largest square.
If three squares have sides that make a right triangle, then the sum of the areas of the two small squares is equal to the area of the largest square. This is the Pythagorean Theorem, as mentioned in the first answer. In a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Therefore, if the squares are constructed with their sides equal to the lengths of the sides of the right triangle, then the sum of the areas of the two smaller squares will be equal to the area of the largest square.
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Which table has a constant of proportionality between y and 2 of 0.3?
Choose 1 answer:
х
y
6
2.
А
12
4
30
10
х
у
3
1.8
B
7
4.2
9
5.4
T
y
4
1.2
с
8
2.4
13
3.9
Answer:
C
Step-by-step explanation:
y=kx or xy=k are true such that k=0.3
in C, 1.2=4*0.3, 2.4=8*0.3, and 3.9=13*0.3, so C follows this rule
Khan Academy
We want to find the zeros of this polynomial:
p(x) = (x + 2)(2x - 3)(x − 3)
Plot all the zeros (x-intercepts) of the polynomial in the interactive graph.
All the zeros of the polynomial function p(x) = (x + 2)(2x - 3)(x − 3) are
x = -2, x = 2/3 and x = -3How to find the zeros of the polynomial functionThe zeros of the polynomial function is solved by equating each term in parenthesis to zero.
for the function, p(x) = (x + 2)(2x - 3)(x − 3)
firstly, x + 2 = 0
x = -2
secondly, (2x - 3)
2x - 3 = 0
2x = 3
x = 3/2
thirdly, (x + 3)
x + 3 = 0
x = -3
the zeros are x = -2, x = 2/3 and x = -3
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What is 230 kilometers converted to meters per minute?
Your answer would be 230,000
please only geniussssssssssssssssss
Check the picture below.
ha- me again
help me please
Answer:
The first one
Step-by-step explanation:
The dots are the farthest away from the line in that one.
Determine whether the given vectors are orthogonal, parallel, or neither.(a) a = 9, 3, b = -2, 6(b) a = 4, 7, -2, b = 3, -1, 7(c) a = -6i + 9j + 3k, b = 4i - 6j - 2k(d) a = 3i - j + 3k, b = 3i + 3j - 2k
(a) a = 9, 3, b = -2, 6 are orthogonal
(b) a = 4, 7, -2, b = 3, -1, 7 are neither parallel nor orthogonal
(c) a = -6i + 9j + 3k, b = 4i - 6j - 2k are neither parallel nor orthogonal
(d) a = 3i - j + 3k, b = 3i + 3j - 2k are orthogonal
(a) To determine if vectors a = (9, 3) and b = (-2, 6) are orthogonal, parallel, or neither, first check if their dot product is 0. If it is, they are orthogonal.
a · b = (9 * -2) + (3 * 6) = -18 + 18 = 0, so a and b are orthogonal.
(b) For vectors a = (4, 7, -2) and b = (3, -1, 7), calculate the dot product.
a · b = (4 * 3) + (7 * -1) + (-2 * 7) = 12 - 7 - 14 = -9, which is not 0, so they are not orthogonal. Since the vectors are not scalar multiples of each other, they are neither parallel nor orthogonal.
(c) For vectors a = (-6i + 9j + 3k) and b = (4i - 6j - 2k), check the dot product:
a · b = (-6 * 4) + (9 * -6) + (3 * -2) = -24 - 54 - 6 = -84, which is not 0, so they are not orthogonal. Since the vectors are not scalar multiples of each other, they are neither parallel nor orthogonal.
(d) For vectors a = (3i - j + 3k) and b = (3i + 3j - 2k), calculate the dot product:
a · b = (3 * 3) + (-1 * 3) + (3 * -2) = 9 - 3 - 6 = 0, so a and b are orthogonal.
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A\:pair\:of\:parallel\:power\:lines\:are\:installed\:on\:a\:slope\:find\:m<\:3\:if\:m<\:2=143
According to the slope, the angle 3 also has a measure of 143 degrees.
To find the measure of angle 3, we first need to understand how angles 2 and 3 are related.
In other words, angles 2 and 3 are congruent (have the same measure). Therefore, if we can find the measure of angle 2, we can determine the measure of angle 3.
We know that angle 2 has a measure of 143 degrees. We also know that angles 2 and 3 are alternate interior angles, which means they are congruent.
Now, let's justify why this is true using the concept of slopes. Since the power lines are parallel, they have the same slope. This means that the angle between each power line and the horizontal is the same.
Since angle 2 is the angle between one of the power lines and the horizontal, we know that angle 3 must also have the same measure because it is the angle between the other power line and the horizontal.
Therefore, we can confidently say that the measure of angle 3 is also 143 degrees.
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Complete Question:
A pair of parallel power lines in Mohamed Bin Zayed City is installed on a slope. Find m∠3 if m∠2= 143 degrees . Justify your answer
Two charges, Q
1
=6.80×10
−9
C and Q
2
=6.20×10
−9
C lie on the y-axis an equal distance, d=0.77 m, from the origin. Q
1
is at (x=0,y=d) and Q
2
is at (x=0,y=−d). What is the x-component of the total electric field due to these two charges at a point on the x-axis a disistance 3d from the origin, at the point (x=3d,y=0) ? Give your answer in N/C to at least three significant figures to avoid being counted off due to rounding...
The x-component of the total electric field due to the two charges at a point on the x-axis a distance 3d from the origin, at the point (x = 3d, y = 0) is 3.962 N/C.
The electric field at point P which is located on the x-axis a distance 3d from the origin due to two charges Q1 and Q2 is a vector sum of the individual electric fields created by the two charges.
Electric field due to point charge Q at a distance r from the point charge Q can be calculated using Coulomb's law as:
E = k Q / r^2where k = 9 x 10^9 Nm^2/C^2 is the Coulomb's constant
Now, the electric field created by Q1 at point P isE1 = k Q1 / r^2where r is the distance between Q1 and P.
Here, Q1 is at a distance d from P on the y-axis and the distance between Q1 and P is given as:
r1 = sqrt[(3d)^2 + d^2] = sqrt(10) * d
We know that, Q1 = 6.80 x 10^-9 CE1 = 9 x 10^9 * 6.80 x 10^-9 / [sqrt(10) d]^2= 4.628 N/C
Again, the electric field created by Q2 at point P isE2 = k Q2 / r^2where r is the distance between Q2 and P.
Here, Q2 is at a distance d from P on the y-axis and the distance between Q2 and P is given as:
r2 = sqrt[(3d)^2 + d^2] = sqrt(10) * d
We know that, Q2 = 6.20 x 10^-9 CE2 = 9 x 10^9 * 6.20 x 10^-9 / [sqrt(10) d]^2= 4.208 N/C
The x-component of the electric field E1 along the x-axis will be zero, since it is perpendicular to the x-axis.
The x-component of the electric field E2 is directed towards the origin and is given as:
Ex2 = E2 cos θ = E2 (x / r2) = E2 [3d / sqrt(10) d]= 0.9407 * E2
Therefore, the x-component of the total electric field at point P due to the two charges is:
Ex = Ex1 + Ex2= 0 + 0.9407 * E2= 3.962 N/C (approx.)
Hence, the x-component of the total electric field due to the two charges at a point on the x-axis a distance 3d from the origin, at the point (x = 3d, y = 0) is 3.962 N/C.
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i need to pass can you help me
Answer:
its 90°
Step-by-step explanation:
because its a right angle triangle
after you find the confidence interval, how do you compare it to a worldwide result
To compare a confidence interval obtained from a sample to a worldwide result, you would typically check if the worldwide result falls within the confidence interval.
A confidence interval is an estimate of the range within which a population parameter, such as a mean or proportion, is likely to fall. It is computed based on the data from a sample. The confidence interval provides a range of plausible values for the population parameter, taking into account the uncertainty associated with sampling variability.
To compare the confidence interval to a worldwide result, you would first determine the population parameter value that represents the worldwide result. For example, if you are comparing means, you would identify the mean value from the worldwide data.
Next, you check if the population parameter value falls within the confidence interval. If the population parameter value is within the confidence interval, it suggests that the sample result is consistent with the worldwide result. If the population parameter value is outside the confidence interval, it suggests that there may be a difference between the sample and the worldwide result.
It's important to note that the comparison between the confidence interval and the worldwide result is an inference based on probability. The confidence interval provides a range of values within which the population parameter is likely to fall, but it does not provide an absolute statement about whether the sample result is significantly different from the worldwide result. For a more conclusive comparison, further statistical tests may be required.
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k/5 + 8= 23 what solution is k?
Answer:
k=75
Step-by-step explanation:
\(\frac{k}{5}\)+8=23
(subtract 8 from both sides of the equation)
\(\frac{k}{5}\)+8-8 = 23-8
(simplify)
\(\frac{k}{5}\) = 15
(multiple all terms by the same value to eliminate fractional denominators)
5. \(\frac{k}{5}\) = 5.15
(cancel multiplied terms that are in the denominator, multiply the numbers)
k=75
6.) Giovanni makes $0.75 profit for each cupcake that he sells. He wants to 4 polu
buy a new $10 cupcake tin. He wants to know how many cupcakes will he
need to sell so that he can buy the cupcake tin and still have $35 profit
eft. Which equation can be used to solve this problem?*
Answer:
60
Step-by-step explanation:
you add what he needs to make in total up ten dollars for the cupcake tin and the thirty five dollars for the profit he wants to make then I used the guess and check strategy knowing that 100 cupcakes would make him 75 dollars I worked my way down multiplying 0.75 times 90, 80, 70 and then landed on the answer 60
determine whether or not the vector field is conservative. f(x,y) = 39x2y2i + 26x3yj
The given vector field f(x,y) = 39x^2y^2i + 26x^3yj is conservative.
The vector field f(x,y) is given by:
f(x,y) = 39x^2y^2i + 26x^3yj
To check if the vector field is conservative, we need to verify if the curl of the vector field is zero. The curl of a 2D vector field is defined as:
Curl(f) = (∂(26x^3y) / ∂x) - (∂(39x^2y^2) / ∂y)
Calculate the partial derivative with respect to x for the second component (j):
∂(26x^3y) / ∂x = 78x^2y
Calculate the partial derivative with respect to y for the first component (i):
∂(39x^2y^2) / ∂y = 78x^2y
Subtract the second derivative from the first derivative:
Curl(f) = 78x^2y - 78x^2y = 0
Since the curl of the vector field f(x,y) is 0, the vector field is conservative.
The correct question should be :
Determine whether or not the vector field given below is conservative.
f(x,y) = 39x^2y^2i + 26x^3yj
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Express (x+1) (x+1) as a trinomial in standard from
Answer:
x^2 + 2x + 1
Step-by-step explanation:
(x + 1)(x + 1) = x^1 + x + x + 1 = x^2 + 2x + 1
Answer:
x² + 2x + 1
Step-by-step explanation:
(x+1)(x+1)
x² + 1x + 1x + 1
Directions: Simplify the following expressions. Refer to the rules for signed numbers in solving these problems.
Example: - 4 + 5 = +1 (the signs are different, take the difference (subtract) and place the sign of the larger number)
1. + 2 - (+3) =
2. + 11 + (-10) =
3. 3 + (-5 ) =
4. + 22 - 21 =
5. - 8 - (-44) =
6. -12 - (-6 ) + 3 =
7. + 16 -(-12) =
8. - 36 - (-36) =
9. -4 * 10 =
10. -1 * -1 =
11. + 7 * - 7 =
12. -4 / 4 =
13. -7 * -5 =
14. -10 * + 8 =
15. -2 * - 7 =
Step-by-step explanation:
remember, when 2 signs collide (like a mathematical operation and the sign of an operand of that operation), the following is always true (for additions/subtractions and multiplications/divisions) :
+ + = +
+ - = -
- + = -
- - = +
and don't forget : when a number or term is positive, we usually don't write the sign. only the mathematical operation.
1. 2 - 3 = -1
2. 11 - 10 = 1
3. 3 - 5 = -2
4. 22 - 21 = 1
5. -8 + 44 = 36
6. -12 + 6 + 3 = -3
7. 16 + 12 = 28
8. -36 + 36 = 0
9. -4 × 10 = -40
10. -1 × -1 = 1
11. 7 × -7 = -49
12. -4 / 4 = -1
13. -7 × -5 = 35
14. -10 × 8 = -80
15. -2 × -7 = 14
Write the expression as a number in scientific notation.
quantity 7 times 10 cubed end quantity times quantity 5.4 times 10 to the fourth power end quantity all divided by quantity 9 times 10 squared
4.2 x 1010
3.4 x 1010
4.2 x 105
3.4 x 105
The expression as a number in scientific notation is 4.2 * 10^5
How to write the expression as a number in scientific notation?The expression is given as:
quantity 7 times 10 cubed end quantity times quantity 5.4 times 10 to the fourth power end quantity all divided by quantity 9 times 10 squared
Rewrite properly as:
[7 * 10^3 * 5.4 * 10^4]/[9 * 10^2]
Evaluate the product of 7 and 5.4
So, we have:
[37.8* 10^3 * 10^4]/[9 * 10^2]
Evaluate the product of 10^3 and 10^4
So, we have:
[37.8* 10^7]/[9 * 10^2]
Evaluate the quotient of 37.8 and 9
So, we have:
[4.2 * 10^7]/[10^2]
Evaluate the quotient of 10^7 and 10^2
So, we have:
4.2 * 10^5
Hence, the expression as a number in scientific notation is 4.2 * 10^5
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Given that: f(x) = 3x- 4 g(x)=2x²+5 h(x)= 8- 3x p(x) = x²- 2xFind f(x)-h(x).
Answer:
f(x)-h(x) = 6x - 12
Explanation:
Given the functions f(x) and h(x) defined as follows:
\(\begin{gathered} f(x)=3x-4 \\ h(x)=8-3x \end{gathered}\)We want to find: f(x)-h(x)
\(\begin{gathered} f\mleft(x\mright)-h\mleft(x\mright)=3x-4-(8-3x) \\ =3x-4-8+3x \\ =3x+3x-4-8 \\ =6x-12 \end{gathered}\)Write an equation of the line passing through point P(-1,-4) that is parallel to
y = -6x + 8
The equation of the line passing through point P(-1,-4) that is parallel to y = -6x + 8 is y = -6x - 10.
What is a straight line?A straight line is made up of an infinite number of points connected at their ends.
Any straight line's slope, "m," is determined by:
\(\rm m =\dfrac{y_2-y_1}{x_2-x_1}\)
The slope of the line y = -6x + 8
m = -6
The slope of the line passing point P (-1,-4)
M = -6
y - (-4) = -6(x - (-1))
y + 4 = -6(x + 1)
y = -6x - 10
Thus, the equation of the line passing through point P(-1,-4) that is parallel to y = -6x + 8 is y = -6x - 10.
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What is the slope of the line joining (8, 8) and (12, 6)? −2 negative one over two start fraction one over four end fraction start fraction one over two end fraction
Answer:
-1/2
Step-by-step explanation:
slope is \(\frac{y_{2}- y_{1}}{x_{2}-x_{1}}\)
so:
\(\frac{6-8}{12-8} = -\frac{2}{4} = -\frac{1}{2}\)
Consider this linear program: MINIMIZE 1x + 3y subject to x,y≥0 Type the ONE DIGIT NUMBER of the description below that best 1 bounded feasible region, unique optimal solution 2 bounded feasible region, alternative optima 3 unbounded program 4 unbounded feasible region, alternative optima 5 unbounded feasible region, unique optimal solution
The ONE DIGIT NUMBER that best describes the linear program is unbounded feasible region and unique optimal solution.
The given linear program states "MINIMIZE 1x + 3y subject to x, y ≥ 0." In this case, we have a bounded feasible region since the constraints restrict both x and y to be greater than or equal to zero. The feasible region is limited to the positive quadrant of the coordinate plane.
As for the objective function, 1x + 3y, it forms a linear equation with a positive slope. The objective function represents a family of parallel lines with a steeper slope of 3 compared to the slope of 1 for the x-axis. As we move away from the origin, the objective function increases.
Since the feasible region is unbounded, there are infinitely many points that satisfy the constraints. However, since the objective function is linear and the feasible region is unbounded, there exists a unique optimal solution. The optimal solution is the point in the feasible region that minimizes the objective function. Therefore, the linear program is best described as having an unbounded feasible region with a unique optimal solution, which corresponds to the digit.
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A student answers
92
%
of questions on a test before the end of class bell rings. If the student answers
46
questions before the end of class, how many questions are on the whole test?
Answer:
50 questions
Step-by-step explanation:
Given the following question:
92% of 50
To find the answer we have to use the formula to calculate percentage.
\(\frac{p\times n}{100}\)
\(\frac{92\times50}{100} =92\times50=4600\div100=46\)
\(=46\)
Which means in total there was "50 questions" on the test.
Hope this helps.
PQR ~MNO. What is the length of side QR?
The length of the QR is 16 cm when PQR ~MNO
In the given question, it is given that two similar triangles as PQR ~MNO
Then, the corresponding sides will be in equal proportion to each other as follows
PQ / MN = PR / MO = QR / NO
We need to find the length of the side QR
As above relations are given,
\(\frac{PQ}{MN}\) = \(\frac{PR}{MO}\) = \(\frac{QR}{NO}\)
\(\frac{30}{10}\) = \(\frac{5x + 7}{x+5}\) = \(\frac{4x}{\frac{16}{3} }\)
Equating all the fractions, equal to each we'll find
\(\frac{5x + 7}{x+5}\) = \(\frac{30}{10}\)
5x + 7 = 3(x +5)
5x + 7 = 3x + 15
2x = 8
x = 4
We know that, the length of the QR = 4x cm = 4 x 4 cm = 16 cm
Therefore, the length of the QR is 16 cm when PQR ~MNO
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Avery has two books and a lunch box in his backpack Each book weighs 7/8 pound. The total weight in his backpack it 2 2/3 pounds. How much does Avery's lunch box weigh?
The weight of the Avery's lunch box using given weights is equal to 0.92 pounds (rounded to two decimal places).
Total weight of the backpack= 2 2/3 pounds
= 8/3 pounds
The weight of the each book =7/8 pounds.
Let x be the weight of the lunch box in pounds.
An equation that represents the total weight in Avery's backpack,
2(7/8) + x = 8/3
To solve for x, simplify and solve for x,
⇒14/8 + x = 8/3
Multiplying both sides by 24 the least common multiple of 8 and 3 to clear the fractions,
⇒42 + 24x = 64
Subtracting 42 from both sides,
⇒24x = 22
Dividing both sides by 24,
⇒x = 22/24
Simplifying the fraction,
⇒x = 11/12
= 0.92 pounds (rounded to two decimal places).
Therefore, the weight of the lunch box is equal to 0.92 pounds (rounded to two decimal places).
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