The CAT- III rating relates to high voltage and high energy. The correct options are Option A and Option B
What is CAT- III ?Circuit breakers, wiring, switches, and other electrical installations found in a structure are referred to as CAT III.
The transient voltage range present on the majority of distribution circuits can be handled by test equipment having a CAT III rating. These devices are mostly utilized on branch circuits or fixed primary feeds.
The primary distinction between Category II and Category III operations is that Category II offers enough visual cues to allow a manual landing at DH, whereas Category III does not and necessitates an autonomous landing system.
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(c) The plastic tube is attached to a metal mast.
This would cause the metal mast to become positively charged.
Explain why there is a wire connecting the metal mast to the Earth.
can someone please help by answering the question and not write anything
Explanation:
Since the mast is a conductor and connected to the plastic so charge transfer takes place between the mast and the tube because the mast is connected to the ground with wire which is called grounded which means its potential is 0 equal to the ground so that charge can transfer from plastic tube to the ground. This is why the wire is used to connect the metal mast to the Earth.
11. Amy is in a car that is moving at a speed of 50 kilometers/hour. If she moves a total distance of
230 kilometers, how long was she in the car?
You apply a force of 68N to lift a box 4m off the ground in 2s. What was your power?
Answer:
136........
.............
The electromagnetic spectrum has waves of varying levels of energy. Which
wave has the least energy?
Answer:
Radio waves, I believe
Explanation:
Answer:
radio yes yup yup yup yup
Which type of matter is likely to absorb the most sound waves
A:hot air
B:metal door
C:foam wall:
D:Loudspeaker
Answer:
im postive its D) loudspeaker
Answer:
foam wall
Explanation:
ap3x
One half of a balanced chemical equation is shown. 3Mg(OH)2 + 2H3PO4 Which lists the numbers of each atom the other half of the equation would contain? 3 Mg, 2 P, 14 O, 12 H Mg, 2 P, 14 O, 6 H 3 Mg, 8 P, 7 O, 6 H 6 Mg, 6 P, 2 O, 12 H
Answer: 3 Mg , 2 P , 14 O , 12H
Number of atoms of sama elements remains same
In both sides
Answer:
3 Mg, 2 P, 14 O, 12 H
Explanation:
A duck flies in a straight line for 500m (60° N of W)
a.) What angle is this in polar coordinates?
b.) What is the North/South and East/West components of its displacement?
Please help me t-t
(A) The angle of this in polar coordinates is 30⁰.
(B) The North/South and East/West components of its displacement is 250 m and 433 m respectively.
The angle is this in polar coordinates60° N of W lies in the fourth quadrant;
θ = 90 - 60 = 30⁰
in polar coordinate = (r,θ) = (500 m, 30⁰)
Vertical component of the displacement (North/South)Dy = D sinθ
Dy = 500 m x sin(30) = 250 m
Horizontal component of the displacement (East/West)Dx = D cosθ
Dx = 500 m x cos(30) = 433 m
Thus, the angle of this in polar coordinates is 30⁰.
The North/South and East/West components of its displacement is 250 m and 433 m respectively.
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Calculate the magnitude and direction of the centripetal acceleration of the following objects moving in a circle:
A 2000 kg truck drives along a circular round a bout with a radius of 20 m at a constant speed of 10 m/s.
Answer:
The magnitude and direction of the centripetal acceleration will be:
\(a_c=5\) m/s² (towards the center of the circle).
Explanation:
Given
v = 10 m/sr = 20 mUsing the formula to determine the centripetal acceleration
\(a_c=\frac{v^2}{r}\)
\(a_c=\frac{\left(10\right)^2}{20}\)
\(\:a_c=\frac{100}{20}\)
\(a_c=5\) m/s²
As the truck is moving in a circle, therefore the direction is towards the center of the circle.
Hence, the magnitude and direction of the centripetal acceleration will be:
\(a_c=5\) m/s² (towards the center of the circle).
In F test statistics, the larger sample variance is placed in the numerator. Hence, the tabled F ratio is always Select one:
a. Less than 1.00.
b. Greater than 1.00.
c. Less than 0.00.
d. Greater than 0.00.
e. Between 0 and 1.
In F test statistics, the larger sample variance is placed in the numerator. Hence, the tabled F ratio is always greater than 1.00 (option b).
The F test is used to compare the variances of two samples and determine if they are significantly different from each other. The F ratio is calculated by dividing the larger sample variance by the smaller sample variance. If the larger sample variance is in the numerator, the F ratio will always be greater than 1.00. If the F ratio is less than 1.00, it means that the smaller sample variance is in the numerator and the larger sample variance is in the denominator.
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a balloon of total mass 2200 kg hovers stationary at a height of several meters above the ground. a mass of 200 kg is released from rest from the balloon.calculate the acceleration of the balloon as it starts to rise.
Answer:
1 m/s²
Explanation:
added in the picture
Magnifications with values greater than one represent images that are smaller than the object. Is this true or false.
ANSWER
False
EXPLANATION
Magnification is a measure of an image's size compared to the size of the object that formed the image.
Since magnification is a ratio that is proportional to the sizes of the image and object, it follows that if magnification is less than 1, the image is smaller than the object, if magnification is equal to 1, the image and object are the same size and if magnification is greater than 1, the image is larger than the object.
Therefore, it is False.
define visible light radiation
It requires a force of 18 N to hold a spring stretched l m beyond its natural length. If L>l, how much work, in terms of l and L, is required to further stretch the spring from l m to L m ? Work =Nm
To further stretch the spring from l m to L m, the work done is given by W = 0.5k (L² - l²), where k is the spring constant and l and L are the initial and final lengths respectively.
Given, it requires a force of 18 N to hold a spring stretched l m beyond its natural length.Since the work done is equal to the change in potential energy, therefore, the work required to further stretch the spring from l m to L m is given by:
W = Uf - Ui
= 0.5 k L² - 0.5 k l²
Now, we have k = F / x where F is the force required to stretch the spring by a distance x.So,
k = 18 / l
Also, the force required to stretch the spring to length L is given by:
F' = k (L - l) = 18 (L - l) / l
Therefore, the work done is given by:
W = 0.5 k (L² - l²) = 0.5 x 18 / l x (L² - l²) = 9 (L² - l²) / l
Hence, the work done to further stretch the spring from l m to L m is 9 (L² - l²) / l J.
Therefore, the work required to stretch the spring from l m to L m is given by the equation: W = 9 (L² - l²) / l.
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What is the wavelength of an AM radio wave in a vacuum if its frequency is 810 kHz?
1. In physical science, work occurs when a ___
distance from the start point.
a. Voltage
b. Power
C. Force
d. Velocity
e. Energy
Groups of students are making measurements of small cars rolling across a table. the class has measuring tapes with markings in inches and centimeters. the teacher asks that students make all the measurements in centimeters. why would the teacher make a decision like this?
To find the accurate measurement of small cars, the teacher asks students to make all the measurements in centimeters.
Centimeters Measurements:
A centimeter is a metric unit of measurement used for measuring the length of an object, It is written as cmCentimeter is one hundredth of a meter, 1 meter is 0.01 cm.Inches measurements:
An inch can be defined as a unit of length in the customary system of measurement. Length in inches is either represented by in or ''.1 meter is equal to 39.37 incheshere, the cars are small objects.
The number of centimeters is always bigger,
because a centimeter unit is smaller than an inch unit, and it takes more of them when we are measuring.
Hence,
To find the accurate measurement of small cars, the teacher asks students to make all the measurements in centimeters.
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A force of 162 N is applied to an object causing it to accelerate at a rate of 3.8 m/s^2. What is its mass?
A. 0.2 kg
B. 616 kg
C. 43 kg
D. 102 kg
Answer:
43 kg
Explanation:
Force (F) = 162 N
acceleration (a) = 3.8 m/s²
mass (m) = ?
We know
F = m * a
162 = m * 3.8
m = 162 / 3.8
m = 43 kg
It's mass is 43 kg.
Hope it will help you :)
what is the weight of a 15 kg object
to get weight multiply Mass by 9.8
weight =9.8x15=147N
Will an object experience a greater force of gravity on the earth or moon? Why?
Answer:
Earth’s gravitational force is stronger
Explanation:
Earth’s gravitational force is stronger than the moon because of the presence of more massive objects in earth; on the flip side, the moon’s gravity is weaker than the earth due to smaller in size as compared to the earth. Earth gravity is denoted by g; conversely, moon gravity is denoted by gm
Answer: The greater an object's mass, the more gravitational force it exerts. So, to begin answering your question, Earth has a greater gravitational pull than the moon simply because the Earth is more massive. That's why the moon isn't pulled out of Earth's orbit by the gravity of larger planets or by the sun.
Explanation:
The second is a flexible _________.
Answer:
static stretching
Explanation:
hope this helped ^^
Embarking on a road trip, you hope to average a speed of 90.0 km/hr. Driving through bad weather, you finally reach the midpoint (half the distance) of your trip, but realize that you have only been averaging 5.0 X 10^1 km/hr. How fast would you have to drive the second half of the trip to keep your desired arrival time? *
Answer:
Explanation:
average speed = 90 km / hr
Let the total distance be 2 d .
time required to cover the time = 2 d / 90
time taken to cover distance d at 50 km /h = d / 50
time required to cover the nd half = 2 d / 90 - d / 50
.02222 d - .02 d = .002222 d
speed required = d/2 / .002222d
1 / 2 x .002222
= 225 km /h .
where do reduction and oxidation occur in an electrolytic cell
Answer:
Oxidation occurs at the anode and reduction occurs at the cathode
Explanation:
what is the dot product and cross product of of two vectors if the angle is between them is 90 degree?
\(\sf{\pink{\underline{\underline{\blue{GIVEN:-}}}}}\)
The angle between the two vectors is 90° .\(\sf{\pink{\underline{\underline{\blue{TO\: FIND:-}}}}}\)
The dot product of two vectors .The cross product of two vectors .\(\sf{\pink{\underline{\underline{\blue{SOLUTION:-}}}}}\)
⚡ Let \(\rm{\vec{a}}\) and \(\rm{\vec{b}}\) are the two vectors .
✍️ We have know that,
\(\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:.\:\vec{b}\:=\:ab\cos{\theta}\:}}}}\)
Where,
θ = 90°\(\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\cos{90^{\degree}}\:}\)
cos 90° = 0\(\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\times{0}\:}\)
\(\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:0\:}\)
\(\rm{\red{\therefore}}\) [1] The dot product of two vectors is “ 0 ” .
✍️ We have know that,
\(\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:\times\:\vec{b}\:=\:ab\sin{\theta}\:}}}}\)
Where,
θ = 90°\(\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\sin{90^{\degree}}\:}\)
sin 90° = 1\(\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\times{1}\:}\)
\(\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\:}\)
\(\rm{\red{\therefore}}\) [2] The cross product of two vectors is “ ab ” .
the dot and cross product will become zero if the angle becomes 90°
hope it helps you...
#from india ✌✌✌
Which of the following involves the emission of a particle that has the same mass of an electron with a positive charge.
a.
alpha decay
c.
positron emission
b.
beta decay
d.
nuclear forces
Answer:
The proper answer for this question would be B. Beta Decay
Explanation:
I hope this helps
(b) if one micrometeorite (a sphere with a diameter of 1.30 10-6 m) strikes each square meter of the moon each second, how many years would it take to cover the moon to a depth of 1.20 m? (hint: consider a box on the moon 1.00 m on a side and 1.20 m deep, and find how long it will take to fill the box.)
The time required to cover the Moon to a depth of 1.20 meters with micrometeorites.
To find out how long it would take to cover the Moon to a depth of 1.20 meters with micrometeorites, we can calculate the volume of the Moon and then divide it by the volume of one micrometeorite. Let's break down the calculation step by step:
Calculate the volume of the Moon:
The average radius of the Moon is approximately 1.737 ×10⁶ meters. Using the formula for the volume of a sphere, V = (4÷3)πr³, we can calculate the volume of the Moon.
\(V_{moon}\) = (4÷3)π(1.737 × 10⁶)³
Calculate the volume of one micrometeorite:
The diameter of the micrometeorite is given as 1.30 ×10⁽⁻⁶⁾ meters, which means the radius is half of that.
\(r_{meteorite}\) = (1.30 × 10⁽⁻⁶⁾)÷2
Using the formula for the volume of a sphere, V = (4÷3)πr₃, we can calculate the volume of one micrometeorite.
\(V_{meteorite}\) = (4÷3)π((1.30 × 10⁽⁻⁶⁾)÷2)³
Calculate the number of micrometeorites needed to fill the Moon:
To find the number of micrometeorites required to fill the Moon, we divide the volume of the Moon by the volume of one micrometeorite.
\(N_{meteorites}\) = \(V_{moon}\) ÷ \(V_{meteorite}\)
Calculate the time to fill the Moon:
Since one micrometeorite strikes each square meter of the Moon each second, we can equate the number of micrometeorites needed to fill the Moon to the number of seconds it would take.
Time = \(N_{meteorites}\) ÷ (1 m²/s)
Convert seconds to years:
Finally, we convert the time in seconds to years by dividing by the number of seconds in a year (assuming 365.25 days in a year and 24 hours in a day).
\(Time_{years}\) = Time ÷ (365.25 days/year × 24 hours/day × 3600 seconds/hour)
Performing these calculations will give us the time required to cover the Moon to a depth of 1.20 meters with micrometeorites.
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Use the drop-down menu to answer the question. according to "take a closer look", what type of lens is used to correct nearsightedness?
Answer: concave lens
Explanation:
Answer:
A or convex lens
Explanation:
a box has a length of .5 m and a width of .1m. if the box exerts a force of 10 N on the floor, what is the pressure of the box on the floor
Answer:
The pressure of the box on the floor is 200 Pa
Explanation:
Given,
Length of the box=0.5m
Width of the box= 0.1m
∴Area of the box, A= (0.5 X 0.1) sq.m
= 0.05 sq.m
We know,
Pressure, P= F/A
= 10/0.05 Pa
= 200 Pa
∴The pressure of the box on the floor is 200 Pa
If n is the normal vector and it is perpendicular to the plane and there is nother vector r−r0and these two vectors are orthogonal to each other. Therefore the dot product of two perpendicular vectors will also be equal to zero. Therefore n. n⋅(r−r0)=0 . This equation is called as the vector equation of the plane.
The equation n · (r - r₀) = 0 represents the vector equation of a plane, where n is the normal vector and (r - r₀) is any vector on the plane, with the dot product ensuring perpendicularity.
The equation you provided, n · (r - r₀) = 0, does indeed represent the vector equation of a plane. Let's break it down to understand its components:
n represents the normal vector to the plane. It is a vector that is perpendicular to the plane and defines its orientation.
r represents a position vector that describes any point in space, and r₀ represents a specific position vector corresponding to a point on the plane.
The expression (r - r₀) represents a vector that originates from the point r₀ and points to any other point on the plane.
The dot product (·) of two vectors measures the degree of alignment between them. In this case, the dot product of the normal vector n and the vector (r - r₀) is taken.
When two vectors are orthogonal (perpendicular) to each other, their dot product is zero.
Therefore, the equation n · (r - r₀) = 0 implies that the normal vector n is perpendicular to the vector (r - r₀), indicating that the plane is perpendicular to the direction given by (r - r₀).
In summary, the equation n · (r - r₀) = 0 represents the vector equation of a plane, where n is the normal vector and (r - r₀) is any vector on the plane.
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Which statement accurately describes the atmospheres of the inner planets?
Mars has no atmosphere.
Mercury has a thick atmosphere.
Mars and Venus have similar atmospheres.
Earth and Venus have similar atmospheres.
Answer:
The option your looking for is C- Mars and Venus have similar atmospheres
Answer:
C: Mars and Venus have similar atmospheres.
Discuss various process used by farmers from sowing of seeds to the market-ready products.
The various process used by farmers from sowing of seeds to the market-ready products are:
Preparation of the landSowing of seedsIrrigationWeedingPest controlHarvestingPost-harvest handlingMarketingWhat is land preparation?Here are the various processes used by farmers from sowing of seeds to the market-ready products:
Preparation of the land: The first step is to prepare the land for planting. This includes clearing the land of debris, tilling the soil, and adding fertilizer.Sowing of seeds: Once the land is prepared, the seeds are sown. The method of sowing depends on the type of crop being planted.Irrigation: Irrigation is essential for most crops. The amount of irrigation needed depends on the type of crop and the climate.Weeding: Weeds compete with crops for water, nutrients, and sunlight. Weeds must be controlled to ensure a good crop yield.Pest control: Pests can damage crops and reduce yields. Pests can be controlled with pesticides, biological control, or cultural practices.Harvesting: Once the crops are mature, they are harvested. The method of harvesting depends on the type of crop being harvested.Post-harvest handling: After harvesting, crops must be handled properly to prevent spoilage. Marketing: Once the crops are harvested, they must be marketed. This includes selling the crops to consumers or processors.Learn more about land preparation here:https://brainly.com/question/18359716
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