A car travels in a straight line for 5 h at a constant speed of 72 km/h. What is it’s acceleration

Given:

Scale number of a penny = 3.5

Scale number of a fingernail = 2.5

Let's determine the mineral from the options which could be scratched by a penny but not a fingernail.

A mineral with a scale number can scratch any material with equal or lower scale number.

Since a penny has a scale number of 3.5, it can scratch any material with a scale number of 3.5 or lower.

Also, since a fingernail could not scratch the material here, this means the scale number if the material must be greater than 2.5.

Thus, the mineral that could be scratched by a penny but not a fingernail must have a scale number equal to or less than 3.5 but greater than 2.5.

Hence, from the MOHS Hardness Scale, the mineral with a scale number between 3.5 and 2.5 is the Calcite with a scale number of 3.

Therefore, the mineral which could be scratched by a penny but not a fingernail is Calcite.

• ANSWER:

C) Calcite.

Explanation:

san Yung multiple choice dito may multiple choice kase to

Answer:

A

Explanation:

One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.

The question has two parts

beginning with part 1:

R1 and R2 are in series

R3 and R4 are in series with each other

R5 and R6 are in series with each other

R3 and R4 are parallel to R5 and R6

it is given that R1=R2=R3=R4 =2 Ohm

R5=R7=1 Ohm

R6 = 3ohm

We know that resistance is the sum of resistances in series and reciprocal sum of resistances in parallel

R1+R2=2+2=4 ohm

R3+R4 = 2+2 = 4ohm

R5+R6 =1+3=4Ohm

R3 and R4  and R5 and r6  are in parallel = 4 x 4/4+4 = 16/8 = 2 ohm

Resultant resistance = 4 + 2 +1 =7 phms

In part 2 of the question,

R1=R7=2 ohm

R2=R3=R6 =1 ohm

R4=R5=3 ohm

R2,R3 are in series, R5 and R6 are in series

R2,R3 AND R4 and R5 ,R6 in parallel

R2+R3 = 1+1 =2 ohm

R5 +R6 = 3+1 =4 ohm

R2,R3 AND R4 and R5 ,R6 in parallel= 1/(1/2+1/4+1/3 )=v 1/(6+3+4)/12

                                                            =12/13

Resultant resistance = 2+2+12/13 =4.93 ohm

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With a 7ms1 horizontal velocity, an object R departs from a platform XY and lands at Q. The length PQ is 0.45m if the identical object falls freely from Xy to P in 0.3 seconds.

There is no possible for the items to have the same start y-component velocity unless they're shot with distinct initial speeds given that each is launched at a various perspectives. The objects must have been shot at different speeds if they had the same maximum height.

We can observe that over the longest-range the signal reaches its maximum output value, 1, at an output data angle of 90 degrees Punts 2 are at a 90-degree angle, so is at a 45-degree angle. In other words, a projectile moves and furthest when it is fired at a 45-degree angle.

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Answer:

\(100\ cm\)

Explanation:

Given

\(Height = 120\ cm\)

\(Distance = 50\ cm\)

Required

Determine the image's distance from the object's distance

Though, it's not stated but I'll assume that we're dealing with a plane mirror.

When an image is reflected in a plane mirror, the distance of the object is the twice the distance between the mirror and the object itself.

Mathematically,

Object Distance from Image = 2 * Image Distance from Mirror

So, we have:

Object Distance from Image = 2 * 50 cm

Object Distance from Image = 100cm

The correct answer is 500 x 10^6 Joules.

Workk is defined as the force times the distance which is mathematically expressed W = Fxd. The given force is 5x10^4 and the distance is 10000 m (the distance is converted as meter because Nm = J) the work done by the wind is W = 5 x 10^4 N (10000) = 500 x 10^6 Joules.

What is work?

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Answer:a

Explanation:

The formation of salt takes place by the sharing of positive ions from a base and negative ions from an acid. Hence, option (a) is correct.

The given problem is based on the concept and fundamentals of Neutralization. The process of neutralization is the name given to the chemical reaction between that takes place between the acid and base.

Thus, we can conclude that the formation of salt takes place by the sharing of positive ions from a base and negative ions from an acid. Hence, option (a) is correct.

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The engineer must design an engine that can produce a force of over 3,100 Newtons.

A force is an energy that can cause change of motion. It can be a push or a pull. It also has both magnitude and direction, making it a vector quantity.

From the question;

total mass = mass of person + mass of cart

total mass = 80kg + 75kg

total mass = 155kg

acceleration = 20m/s²

The formula to be used;

F = m x a

F = 155kg x 20m/s²

F = 3,100N

In conclusion, the engineer needs a minimum force of 3,100 N in the engine to be able to power the cart.

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Answer:

true

Explanation:

Gravity (or the acceleration due to gravity) is 9.81 meters per second squared, on the surface of Earth, because of the size of Earth and the distance we are on its surface from its center.

(a) The amplitude of the wave is determined as 8 cm.

(b) The period of the wave motion is  20 s and the frequency of the wave is 0.05 Hz

(c) The wavelength of the wave is 500 cm.

(a) The amplitude of the wave is the maximum displacement of the wave.

from the graph, amplitude of the wave = 8 cm

(b) The period of the wave motion is calculated as;

T = 20 s

The frequency of the wave = 1/T = 1/20 s = 0.05 Hz

(c) The wavelength of the wave is calculated by applying the following wave formula.

λ = v / f

λ = 25 cm/s / 0.05 Hz

λ = 500 cm

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The half-life of hypothetical element  technetium-99 is 210,936 years.

Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.

Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.

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The moment of the force about point A found using the moments formula, \(|M| = |F| \cdot \: d \perp\) is 67.695 ft–lb.

The moment of a force is the turning effect of the force about a point.

The moment of the force is given by the formula;

\(|M| = |F| \cdot \: d \perp\)

Where;

d = The perpendicular distance from the point to the line of action of the force.

The length of the sides of ∆ABC are;

AB = √(20.5²+4.38²) ≈ 20.9626907

BC = √(17.2²+7.62²) ≈ 18.812347

AC = √((7.62+4.38)²+(20.5-17.2)²) ≈ 12.4454811

The semi–perimeter of triangle ABC = (20.9626907 + 18.812347 + 12.4454811)/2 ≈ 26.1102594

The area, A, of triangle ∆ABC found using Heron's formula is therefore;

A = √((26.1102594×(26.1102594-20.9626907)×(26.1102594-18.812347)×(26.1102594-12.4454811)) ≈ 115.773

The perpendicular distance, d, from point A to BC is therefore;

d = A/(BC)

Which gives;

d = 115.773/18.812347 ≈ 6.15409696

The magnitude of the moment about point A is therefore;

M = 132 lb × 0.51284138 ft. ≈ 67.695 ft.–lb

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Answer:

bc it was a universal explosion and It started the future

Explanation:

FACTS

Answer:

i wouldn't believe so.

Explanation:

because there was no room or air for the sound to move through. this is because of immense heat and the amount of hyperactive neutrons, electrons and protons clouding everywhere. This would mean that even if there was sound it would a. not travel far or b. go in a completely different direction than expected.

Answer:

Balanced forces will cause no change in the car's motion.

Explanation:

Balanced forces are 2 forces that are equal in opposite directions. This means they 'cancel each other out' in a way. Since both are equal, they cause no effect on the motion of the car

The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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The mass of the boat is 160 .37 kg.

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

Force = mass × acceleration

mass = force/acceleration

        = 85 / 0.530

       = 160 .37 kg

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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When a body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest, their common velocity after the collision is 1.68 m/s.

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Explanation:

i)h=ut+1/2at^2

h=0(2.5s)+1/2(10m/s^2)(2.5s)^2

h=26.25m

ii)v=gt

v=10m/s^2×2.5s=25

a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.

The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.

The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.

b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.

The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.

In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.

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The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.

The base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole

The unit of energy is Joules which is equivalent in mks unit as Kg m²s⁻²

Thus, The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

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Answer:

P=2940 Pa

Explanation:

Given that,

Side of a cube, a = 12 cm

It is submerged to  depth of 30 cm

The density of water, d = 1000 kg/m^3

We need to find the pressure at the bottom surface of the cube. We know that the pressure exerted is given by :

\(P=d gh\\\\P=1000\ kg/m^3\times 9.8\ m/s^2\times 0.3\ m\\\\P=2940\ Pa\)

So, 2940 Pa of pressure is exerted at the bottom surface of the cube due to water.​

1. Ranking Of The Same Monatomic Ideal Gas Sample on the basis of the temperature of the gas sample in each state is F=E>D>C=B>A.

Monatomic, which is a combination of the terms "mono" and "atomic" and refers to a single atom, is a term used in physics and chemistry. A monatomic gas is a gas in which atoms are not bonded to one another, and it is typically used to describe gases.

All of the noble gases (helium, neon, argon, krypton, xenon, and radon) are examples at conventional temperatures and pressures, yet at sufficiently high temperatures, all chemical elements become monatomic in the gas phase (or very low pressure). Because a monatomic gas has no rotational or vibrational energy, its thermodynamic behavior is significantly simpler than that of polyatomic gases.

We take into account an ideal monatomic gas with particles of mass m that don't interact and whose center of mass stays at rets.

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Complete Question -

If a plane is moving in a straight line down the tarmac after landing, its displacement will depend on its starting and ending points, its velocity depends on displacement and acceleration depends on velocity.

Assuming the plane is moving in a straight line down the tarmac:

Displacement: The displacement of the plane will depend on the starting point and the end point of its motion. If we take the starting point as the point of touchdown, then the displacement will be the distance between the touchdown point and the current position of the plane on the tarmac.

Velocity: The velocity of the plane can be calculated by dividing the displacement of the plane by the time taken to travel that distance. If we assume that the plane is traveling at a constant speed, then its velocity will be constant as well. If the speed is not constant, then the velocity will be changing over time.

Acceleration: If the plane is slowing down as it travels down the tarmac, then it is experiencing negative acceleration (deceleration). If the plane is speeding up, then it is experiencing positive acceleration. The magnitude of the acceleration can be calculated as the change in velocity over time. If the plane is traveling at a constant velocity, then its acceleration will be zero.

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The total distance covered is 24 Km and Peter was not moving between the points marked 10 mins and 30 mins on the graph. His displacement according to the graph is zero.

The distance time graph shows the distance covered plotted on the vertical axis against the time taken plotted on the horizontal axis. Using this graph, the total distance covered can easily be obtained.

The total distance covered is 12 km + 12 km since equal distance was covered to and fro. Hence the total distance covered is 24 km. Perter was not moving between the points marked 10 mins and 30 mins on the graph.

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Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block (\(W\)), measured in newtons, is:

\(W = m\cdot g\) (1)

Where:

\(m\) - Mass of the block of ice, measured in kilograms.

\(g\)  - Gravitational acceleration, measured in meters per square second.

If we know that \(m = 14\,kg\) and \(g = 9.807\,\frac{m}{s^{2}}\), the magnitudes of the weight and normal force of the block of ice are, respectively:

\(N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\)

\(N = W = 137.298\,N\)

And the pull force is:

\(F_{pull} = 98\,N\)

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

\(m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f}\) (2)

Where:

\(v_{o}\), \(v_{f}\) - Initial and final speeds of the block, measured in meters per second.

\(\Sigma F\) - Horizontal net force, measured in newtons.

\(\Delta t\) - Impact time, measured in seconds.

Now we clear the final speed in (2):

\(v_{f} = v_{o}+\frac{\Sigma F\cdot \Delta t}{m}\)

If we know that \(v_{o} = 0\,\frac{m}{s}\), \(m = 14\,kg\), \(\Sigma F = 98\,N\) and \(\Delta t = 1.40\,s\), then final speed of the ice block is:

\(v_{f} = 0\,\frac{m}{s}+\frac{(98\,N)\cdot (1.40\,s)}{14\,kg}\)

\(v_{f} = 9.8\,\frac{m}{s}\)

The final speed of the block of ice is 9.8 meters per second.

a) La Distancia entre el telescopio y el satélite es aproximadamente \(8.602\times 10^{5}\) metros.

b) La señal sale del telescopio y se desplaza \(7\times 10^{5}\) metros en Dirección + x y \(5\times 10^{5}\) metros en Dirección +y.

a) Si asumimos la Posición del telescopio como el Origen de un Marco de Referencia, entonces la Distancia entre el telescopio y el satélite (\(d\)), en metros, mediante la siguiente expresión:

\(d = \sqrt{(S(x,y) - O(x,y))\,\bullet\,(S(x,y) - O(x,y))}\) (1)

Donde:

Si sabemos que \(O(x,y) = (0, 0)\) y \(S(x,y) = (7\times 10^{5}, 5\times 10^{5})\), entonces la Distancia entre el telescopio y el satélite es:

\(d = \sqrt{(7\times 10^{5})^{2}+(5\times 10^{5})^{2}}\)

\(d \approx 8.602\times 10^{5}\,m\)

Nota - (1) es una forma vectorial del Teorema de Pitágoras.

La Distancia entre el telescopio y el satélite es aproximadamente \(8.602\times 10^{5}\) metros.

b) La señal sale del telescopio y se desplaza \(7\times 10^{5}\) metros en Dirección + x y \(5\times 10^{5}\) metros en Dirección +y.

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The velocity of the object between 5 s and 9 s is 20 m/s.

The velocity of an object is the rate of change of displacement of the object with time.

Mathematically, the formula for velocity of an object is given as;

v = Δx/Δt

where;

v = (xf - xi) / (t₂ - t₁)

where;

From the given graph, we can infer the following;

xf, the final displacement of the object = 180 m

xi, the initial displacement of the object = 100 m

t₂, the final time of motion of the object = 9 seconds

t₁, the initial time of motion of the object = 5 seconds

v = (180 m - 100 m) / (9 s - 5 s)

v = (80 m) / (4 s)

v = 20 m/s

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Answer:

projectile motion

total time of flight= 2V° Sintheta / g

answer is 3second

Hope This would help you!