A car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of 1.90 m/s2. The car makes it one quarter of the way around the circle before it skids off the track. From these data, determine the coefficient of static friction between the car and track.
Required:
Determine the coefficient of static friction between the car and the track.
Answers
Answer:
Approximately \(0.608\) (assuming that \(g = 9.81\; \rm N\cdot kg^{-1}\).)
Explanation:
The question provided very little information about this motion. Therefore, replace these quantities with letters. These unknown quantities should not appear in the conclusion if this question is actually solvable.
Let \(m\) represent the mass of this car.Let \(r\) represent the radius of the circular track.This answer will approach this question in two steps:
Step one: determine the centripetal force when the car is about to skid.Step two: calculate the coefficient of static friction.For simplicity, let \(a_{T}\) represent the tangential acceleration (\(1.90\; \rm m \cdot s^{-2}\)) of this car.
Centripetal Force when the car is about to skidThe question gave no information about the distance that the car has travelled before it skidded. However, information about the angular displacement is indeed available: the car travelled (without skidding) one-quarter of a circle, which corresponds to \(90^\circ\) or \(\displaystyle \frac{\pi}{2}\) radians.
The angular acceleration of this car can be found as \(\displaystyle \alpha = \frac{a_{T}}{r}\). (\(a_T\) is the tangential acceleration of the car, and \(r\) is the radius of this circular track.)
Consider the SUVAT equation that relates initial and final (tangential) velocity (\(u\) and \(v\)) to (tangential) acceleration \(a_{T}\) and displacement \(x\):
\(v^2 - u^2 = 2\, a_{T}\cdot x\).
The idea is to solve for the final angular velocity using the angular analogy of that equation:
\(\left(\omega(\text{final})\right)^2 - \left(\omega(\text{initial})\right)^2 = 2\, \alpha\, \theta\).
In this equation, \(\theta\) represents angular displacement. For this motion in particular:
\(\omega(\text{initial}) = 0\) since the car was initially not moving.\(\theta = \displaystyle \frac{\pi}{2}\) since the car travelled one-quarter of the circle.Solve this equation for \(\omega(\text{final})\) in terms of \(a_T\) and \(r\):
\(\begin{aligned}\omega(\text{final}) &= \sqrt{2\cdot \frac{a_T}{r} \cdot \frac{\pi}{2}} = \sqrt{\frac{\pi\, a_T}{r}}\end{aligned}\).
Let \(m\) represent the mass of this car. The centripetal force at this moment would be:
\(\begin{aligned}F_C &= m\, \omega^2\, r \\ &=m\cdot \left(\frac{\pi\, a_T}{r}\right)\cdot r = \pi\, m\, a_T\end{aligned}\).
Coefficient of static friction between the car and the trackSince the track is flat (not banked,) the only force on the car in the horizontal direction would be the static friction between the tires and the track. Also, the size of the normal force on the car should be equal to its weight, \(m\, g\).
Note that even if the size of the normal force does not change, the size of the static friction between the surfaces can vary. However, when the car is just about to skid, the centripetal force at that very moment should be equal to the maximum static friction between these surfaces. It is the largest-possible static friction that depends on the coefficient of static friction.
Let \(\mu_s\) denote the coefficient of static friction. The size of the largest-possible static friction between the car and the track would be:
\(F(\text{static, max}) = \mu_s\, N = \mu_s\, m\, g\).
The size of this force should be equal to that of the centripetal force when the car is about to skid:
\(\mu_s\, m\, g = \pi\, m\, a_{T}\).
Solve this equation for \(\mu_s\):
\(\mu_s = \displaystyle \frac{\pi\, a_T}{g}\).
Indeed, the expression for \(\mu_s\) does not include any unknown letter. Let \(g = 9.81\; \rm N\cdot kg^{-1}\). Evaluate this expression for \(a_T = 1.90\;\rm m \cdot s^{-2}\):
\(\mu_s = \displaystyle \frac{\pi\, a_T}{g} \approx 0.608\).
(Three significant figures.)
Related Questions
A metal ball with a constant speed of 15 m/s rolls off the edge of a table. The table is 2.7 m high. How far from the edge of the table does the ball land?
Answers
Answer:
11.135 m
Explanation:
First, we need to find time, recall:
\(x=vt+1/2at^2\)
We need to find time to ground, therefore:
\(y=vyt+1/2ayt^2\)
substitue values for vertical:
\(2.7=1/2*9.8t^2\\2.7=4.9t^2\\\sqrt{2.7/4.9}=\sqrt{t} \\0.74230=t\\\)
Now plug it in for velocity:
\(15*0.74230=11.135\)
A pair of glasses are dropped from the top of a 32.0 m high stadium. A pen is dropped 2.00 s later. How high above the ground is the pen when the glasses hit the ground? (Disregard air resistance. a = -g = -9.81 m/s2.)
Answers
Answer:
Explanation:
the distance have the following relation:
d = (1/2)gt2
D=32.0 m
t =√ (2D/g) = √(2*32.0m/9.8m/s2) = 2.56s
it take 2.56s from the glasses to hit the ground
when the glasses hit the ground, the pen only travel Δt =2.56s - 2.00s = 0.56s
x = (1/2)g(Δt)2 = 0.5*9.8m/s2*(0.56s)2 = 1.54 m
the pen only travel 1.54m
so the pen is above the ground 32.0m - 1.54m = 30.46m
The pen is 30.46m above the ground. when the glasses hit the ground. It is represented by x.
What is the height?Height is a numerical representation of the distance between two objects or locations on the vertical axis.
The height can refer to a physical length or an estimate based on other factors in physics or common use. |
The given data in the problem is;
h is the height from the top of a stadium = 32.0 m
t is the time period when the pen is dropped later = 2.00 s
x is the height above the ground
a is the air resistance. a = -g = -9.81 m/s²
From the second equation of motion;
\(\rm H =ut+\frac{1}{2} gt^2 \\\\ \rm H =\frac{1}{2} gt^2 \\\\ \rm t = \sqrt{\frac{2H}{g} } \\\\ \rm t = \sqrt{\frac{2 \times32.0 }{9.81} } \\\\ \rm t =2.56\ sec\)
When the glasses fall to the ground, the pen only travels a short distance;
\(\rm \triangle t = 2.56 -2.00 \\\\ \rm \triangle t = 0.56 \ sec\)
So the pen travel the distance;
\(\rm h= \frac{1}{2} g \triangle t^2 \\\\ \rm h= \frac{1}{2} \times 9.81 (0.56)^2 \\\\ h=1.54 \ m\)
The pen above the ground is found as;
\(\rm x = H-h \\\\ \rm x = 32.0-1.54 \\\\ \rm x =30.46 \ m\)
Hence the pen is 30.46m above the ground. when the glasses hit the ground.
To learn more about the height refer to the link;
https://brainly.com/question/10726356
the earth is broken into smaller subsystems including the atmosphere the biosphere and the hydrosphere true or false
Answers
Answer:
true
Explanation:
these are not the only parts of the atmosphere, i dont know the full list but i know these arent the only parts
A truck travelling at 22.5 m/s decelerates at 2.27 m/s2. (a) How much time does it take for the truck to stop? (b) How far does it travel while stopping? (c) How far does it travel during the third second after the brakes are applied?
Answers
We can use the "suvat" method
s is displacement
u is initial velocity
v is final velocity
a is acceleration
t is time
We substitute in what we know...
s = ?
u = 22.5 (the speed/velocity the trucks is initially)
v = 0 (the truck comes to a stop)
a = -2.27 (negative because it is decelerating
t = ?
\(\text{suvat formulae}:\\v = u + at\\s = ut + \frac{1}{2}at^2\\v^2 = u^2 + 2as\\s = \frac{v+u}{2}t\\s = vt - \frac{1}{2}at^2\)
We have \(u\), \(v\), \(a\) and we want to find the time for how long it takes the truck to stop.
We can use \(v = u + at\)
\(v = u + at\\0 = 22.5 - 2.27 \times t\\\frac{-22.5}{-2.27} = t\\t = 9.91...\ \text{s}\)
To find the distance (displacement), we can use \(s = ut + \frac{1}{2}at^2\)
\(s = ut + \frac{1}{2}at^2\\s = 22.5 + \frac{1}{2} \times -2.27 \times 9.91^2\\s = -88.9661935\ \ \text{(we make it positive since you can't have negative distance)}\\s = 88.97...\ \text{m}\)
To find the distance travelled 3 seconds after breaks are applied;
We just use the same formula, but with \(t = 3\)
\(s = ut + \frac{1}{2}at^2\\s = 22.5 \times 3 + \frac{1}{2} \times -2.27 \times 3^2\\s = 12.285\ \text{m}\)
Can someone please help me? Please answer the question in the screenshot. Thank you! I need this answered!
Answers
Answer:
Explanation:
Photosynthesis is needed to store energy for the growth of the plant. It is like a factory that uses sunlight energy to convert 6CO₂ and 6H₂O into C₆H₁₂O₆ and 6O₂
Cell respiration is the process of breaking down the glucose and converting it into the other needed components of life. It's the engine that's fueled by the sugar of photosynthesis.
How did the atomic model changed from daltons model in 1803 to schrodingers model of 1926? In 3 to 4 sentences, describe the changes and explain whether the discoveries were independent or cited previous discoveries.
Answers
Explanation:
Niels Bohr improved Rutherford's model. Using mathematical ideas, he showed that electrons occupy shells or energy levels around the nucleus. The Dalton model has changed over time because of the discovery of subatomic particles .
A big lump of meat of mass 5Kg is hung from a spring balance in an elevator. Find the reading of the balance of (I) the elevator is moving with a steady speed. (iI) the elevator is moving upwards with acceleration of 0.2 ms^-2 (g=10ms^-2)
Answers
The reading of the balance if ,
I ) If the elevator is moving with a steady speed = 50 N
II ) If the elevator is moving upwards with acceleration of 0.2 m / s² = 51 N
T = m g + m a
T = Force
m = Mass
g = Acceleration due to gravity
a = Acceleration
m = 5 kg
g = 10 m / s²
I ) If the elevator is moving with a steady speed,
At steady speed, a = 0
T = ( 5 * 10 ) + ( 5 * 0 )
T = 50 N
II ) If the elevator is moving upwards with acceleration of 0.2 m / s²,
a = 0.2 m / s²
T = ( 5 * 10 ) + ( 5 * 0.2 )
T = 50 + 1
T = 51 N
Therefore, the reading of the balance if ,
I ) If the elevator is moving with a steady speed = 50 N
II ) If the elevator is moving upwards with acceleration of 0.2 m / s² = 51 N
To know more about reading on a spring balance
https://brainly.com/question/14819147
#SPJ1
A car accelerates from rest to 35m/s in a distance of 88 m. What was its acceleration in m/s2, assumed constant?
Answers
Answer:
6.96ms/2 or 7ms/2
Explanation:
v2=u2 +2as second equation of motion
u=o
v=35
S=88
a=?
35^2=0^2 +2xax88
=1225 =0+176a
1225=176a
1224/176=6.96ms/2 or 7ms/2
Calculate the resistance in milliOhms of a copper wire 2.84 m long and 0.04 m diameter? The resistivity of copper is 1.7 x 10^-8.
Answers
therefore, the resistivity is 0.019210 miliOhms
ExplanationStep 1
The resistance of a cylindrical segment of a conductor is equal to the resistivity of the material times the length divided by the area
\(\begin{gathered} R=\rho\frac{L}{A} \\ where\text{ }\rho\text{ is the resistivity of the material} \\ L\text{ is the lenght} \\ A\text{ is the area} \end{gathered}\)so
Step 1
a)let
\(\begin{gathered} \rho=1.7*10^{-8} \\ L=2.84 \\ diameter=\text{ 0.04 m} \\ Area\text{ = unknown} \end{gathered}\)bI find the area
the area of a circle is given by:
\(area=\pi(\frac{diameter^2}{4})\)so, replace
\(\begin{gathered} area=\pi(\frac{0.04m^2}{4}) \\ Area=0.0025132741\text{ m}^2 \end{gathered}\)c) now, we can replace the values in the formula
\(\begin{gathered} R=\rho\frac{L}{A} \\ R=1.7*10^{-8}\frac{2.84\text{ m}}{0.0025132741\text{ m}^2} \\ R=1.9*10^{-5}\text{ ohm} \\ to\text{ convert into miliOhms , multiply by 1000} \\ R=R=\frac{1.9\text{ohm}}{10^{5}}*\frac{1000\text{ miliOhms}}{1\text{ Ohms}}=0.01921\text{ ohms} \end{gathered}\)therefore, the resistivity is 0.019210 miliOhms
I hope this helps yo u
A mass hanging from a spring oscillates with a period of 0.15 s. Suppose the mass and spring are swung in a horizontal circle, with the free end of the spring at the pivot. What rotation frequency, in rpm, will cause the spring’s length to stretch by 16%?
Answers
The frequency of 160 rpm will cause the spring’s length to stretch by 16%.
What is the time period?The time period can be described as the time taken by oscillators to finish one complete oscillation.
\({\displaystyle T =2\pi \sqrt{\frac{m}{k} }\)
Given, the time for oscillation, T = 0.15s
The length of the spring changed, Δr/ r = 0.16
By rearranging the equation:
\({\displaystyle {\frac{k}{m }=\frac{4\pi ^2}{T^2}\)
k (Δr) = mω²r,
\({\displaystyle \omega =\sqrt{\frac{k}{m}. \frac{\triangle r}{r} }\)
\({\displaystyle \omega =\sqrt{\frac{4\pi ^2}{T^2}. \frac{\triangle r}{r} }\)
\({\displaystyle \omega =\sqrt{\frac{4\pi ^2}{(0.15)^2}. (0.16) }\)
ω = 16.75rad/s
ω = 16.75 × 60 / 2π rpm
ω= 160 rpm
Therefore, the frequency of the oscillation will be 160 rpm.
Learn more about time period, here:
https://brainly.com/question/29013016
#SPJ1
Determine the Specific Heat Capacity (Cs) of the liquid. Where: Mass of liquid (M₂) = 0.0012Kg, Initial temperature (₁)=23°C, Final temperature (9₂) = 62°C, Voltage (V)= 8v, Current (1) = 0.95A, Time (t) = 270s, Specific heat capacity of liquid (C₁) = ? 1
Answers
The Specific Heat Capacity of the liquid is 43.846 KJ/(Kg K).
It is given that Mass of liquid (M) = 0.0012Kg, Initial temperature (T1) = 23°C, Final temperature (T2) = 62°C, Voltage (V) = 8v, Current (I) = 0.95A, Time (t) = 270sThe quantity of heat that must be applied to an object in order to cause a unit change in temperature is known as the heat capacity or thermal capacity of that object.We know that heat capacity for a substance is :H = m*C*ΔT - equation (1)When a conductor is subjected to current flow, the conductor's free electrons are set in motion and collide with one another. Moving electrons experience kinetic energy loss and partial thermal energy conversion as a result of the collision. This impact of current is referred to as its heating effect.Due to electric current, heat energy is :H = Power * TimeH = Current * Voltage * TimeH = I*V*t - equation (2)Using equation (1) and (2),m*C*ΔT = I*V*tSubstituting the values for m, ΔT, I, V and t.0.0012Kg * C * (62 - 23)K = 0.95A * 8v * 270sSolving for C, we get C = 43.846 KJ/(Kg K)To learn more about Specific Heat Capacity visit :
https://brainly.com/question/1747943
#SPJ9
Professor Stauffer conducts basic research on the psychological, biological, and behavioral
factors that contribute to heart disease. She is most likely a
Answers
High blood pressure, high LDL cholesterol, diabetes, smoking, exposure to secondhand smoke, obesity, a poor diet, and inactivity are the main risk factors for heart disease and stroke.
Explain about the contribute to heart disease?High blood pressure, high cholesterol, and smoking are the three main risk factors for heart disease that at least half of all Americans (47%) have. Age and family history are two uncontrollable risk factors for heart disease.
The most frequent cause of coronary artery disease is atherosclerosis, which is a buildup of fatty plaques in the arteries. Poor diet, lack of exercise, obesity, and smoking are risk factors. Choosing a healthy lifestyle can help reduce the risk of atherosclerosis.
The most prevalent type of heart disease is coronary heart disease (CHD). It happens when plaque deposits cause the arteries that carry blood to the heart to constrict or stiffen. Fat, cholesterol, and other components found in blood make up plaque. The term "atherosclerosis" also refers to this plaque accumulation.
To learn more about heart disease refer to:
https://brainly.com/question/18909207
#SPJ13
A car starts from rest and coasts down a hill with a constant acceleration.If it goes 90m in 8s,find the acceleration and velocity after 8s.
Answers
Physic question help
Answers
The good conductors of heat and electricity are Penny, and An aluminum soda can.
option A and B.
What are good conductors of electricity?Good conductors of electricity are those materials that allow easy passage of electric current through them.
All metals are good conductors of electricity, and some of their examples include;
Aluminum
Copper
Silver
Zinc, etc
Poor conductors on the other hand do not allow easy passage of electric current through them.
Learn more about good conductors here: https://brainly.com/question/1922856
#SPJ1
An 88 kg fullback moving east with a speed of 5.0 m/s is tackled by a 97 kg opponent running west at 3.0 m/s, and the collision is perfectly inelastic. Calculate the following:
a. the velocity of the players just after the tackle
b. the decrease in kinetic energy during the collision
Answers
The speed of the players just after the collision is 0.81 m/s.
What is an inelastic collision?An inelastic collision, as opposed to an elastic collision, is a collision in which there is no conservation of kinetic energy due to the action of internal friction.
Explanation of the above answer:Given that the mass of the fullback is m = 88 kg
mass of the opponent, M = 97 kg
speed of the fullback, u = 5 m/s
speed of the opponent, U = 3 m/s
In an inelastic collision, the two bodies move together at the same speed and the total momentum of the system remains conserved.
Let the final speed be v, then by conserving the momentum we get:
mu - MU = (m + M)v
Since the opponent must be moving in the opposite direction to the fullback, therefore his momentum is -MU.
88×5 - 97×3 = (88 +97)v
149 = 185v
v = 0.81 m/s
So, both the players move with a speed of 0.81 m/s
To know more about inelastic collision visit:
brainly.com/question/2356330
#SPJ1
How many magnetic pole reversals has Earth endured in the last 265 million years if the average time between reversals is 700,000 years?
Answers
Explanation:
265 000 000 yrs / 700 000 yrs/reversal = 378.6 reversals
(round as appropriate)
When carbon bonds with oxygen,
what
gas is formed?
When carbon bonds with oxygen, what gas is formed?
Answers
Answer:
Carbon dioxide
Explination:
I remember it from biology.
I hope this helps ^-^
In a chemical reaction, carbon combines with oxygen to form carbon dioxide gas.
What is a chemical reaction?A chemical reaction can be defined as a process that causes the chemical transformation of one chemical substance to another. The chemical reactions accompany chemical changes that involve the rearrangement of electrons in the forming and breaking of bonds between atoms, with no change to the nuclei.
The substances which are primarily involved in a reaction are known as reactants or reagents. Chemical reactions are commonly characterized by a chemical change, and yield products, which exhibit properties different from the reactants.
Chemical reactions take place at a characteristic rate of reaction at a given temperature, pressure, and chemical concentration. The rates increase with the increasing temperature of the reaction when more thermal energy is available to achieve the activation energy for breaking bonds between atoms.
The combustion reaction takes place when carbon combines with oxygen to produce carbon dioxide gas.
Learn more about Chemical reactions, here:
https://brainly.com/question/22817140
#SPJ2
A 10 KVA, 380 V, 50 Hz, 3-phas, star-connected salient pole alternator has direct axis and quadrature axis reactances of 12 ohms and 8 ohms respectively. The armature has resistance of 1 ohin per phase, The generator delivers rated load at 0.8 p,f lagging with the terminal voltage being maintained at rated value. If the load angle is 16.15, determine (i) the direct axis and quadrature axis components of armature current, (b) excitation voltage of the generator.
Answers
Direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.
Given:
Apparent power (S) = 10 KVA = 10,000 VA
Line voltage (V) = 380 V
Frequency (f) = 50 Hz
Xd = 12 ohms
Xq = 8 ohms
Ra = 1 ohm
Power factor (pf) = 0.8 lagging
Load angle (δ) = 16.15 degrees
(i) Armature current's direct axis and quadrature axis components
We know that the apparent power is given by S = 3VLILcos(φ), where VL is the line voltage, IL is the line current, and φ is the angle between them. For a star-connected alternator, line voltage is equal to phase voltage, so we can write:
S = 3Vphase Iphase cos(φ)
Iphase = S / (3Vphase cos(φ))
For a lagging power factor, cos(φ) = 0.8, so
Iphase = 10,000 / (3 x 380 x 0.8) = 10.46 A
The direct axis component (Id) and the quadrature axis component (Iq) make up the armature current. Using the given values of Xd, Xq, and Ra, we can calculate these components as follows:
Id = (VL - IaRa) / Xd
Iq = (VL - IaRa) / Xq
where Ia is the magnitude of the armature current, which is equal to the magnitude of the line current divided by √3. Thus,
Ia = Iphase / √3 = 10.46 / √3 = 6.03 A
Substituting the given values:
Id = (380 - 6.03 x 1) / 12 = 30.28 A
Iq = (380 - 6.03 x 1) / 8 = 46.92 A
(ii) Excitation voltage of the generator:
The excitation voltage (E) of the generator is given by:
E = Vphase + IqXq
Substituting the given values:
E = 380 + 46.92 x 8 = 765.36 V
Therefore, the direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.
Learn more about voltage here:
https://brainly.com/question/27861305
#SPJ1
Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.
Answers
The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.
To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.
The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.
The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.
By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:
The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.
The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.
The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.
Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.
Hence, the correct statement is: The graph shifts 2 units right and 7 units down.
For more such questions on graph, click on:
https://brainly.com/question/26865
#SPJ8
A flash light has a potential difference of 6 volts and a resistor of 2 Ohms . The current in the flash light is
amps.
Answers
Answer:
3 amps
Explanation:
Volts divided by ohms
A train approaching a crossing changes speed from 25 m/s to 10 m/s in 240 s. How can the train’s acceleration be described?
A. The train’s acceleration is positive.
B. The train is not accelerating.
C. The train will come to rest in 6 minutes.
D. The train’s acceleration is negative.
Answers
The acceleration of the train can be described as: The train’s acceleration is negative (Option D)
How do I know the nature of the acceleration?To describe the acceleration of the train, we shall determine the acceleration of the train. Details below:
From the question given above, the following were obtained:
Initial velocity (u) = 25 m/sFinal velocity (v) = 10 m/sTime (t) = 240 sAcceleration (a) =?a = (v - u) / t
a = (10 - 25) / 240
a = -15 / 240
a = -0.0625 m/s²
From the above calculation, we can see that the acceleration is -0.0625 m/s²
Thus, the correct answer to the question is: The train’s acceleration is negative (Option D)
Learn more about acceleration:
https://brainly.com/question/491732
#SPJ1
Question 10 of 10
Which of the following is an example of a surface wave?
Answers
Answer:
gravity wave
Explanation:
The y component of a vector R of magnitude k = Bcm shown in the figure below is Ky = +6 cm. What is the direction of this vector (The angle 8 that makes K with the x axis)?
Answers
Given
The y-component of vector K is
\(K_y=6\text{ cm}\)The magnitude of vector K is , K=8 cm
To find
The angle
\(\theta\)Explanation
Resolving K along its y-component we have,
\(\begin{gathered} K_y=Ksin\theta \\ \Rightarrow6=8sin\theta \\ \Rightarrow sin\theta=\frac{3}{4} \\ \Rightarrow\theta=48.59\text{ }^o \end{gathered}\)Conclusion
The angle made with the x-axis is
\(48.59^o\)find the acceleration of the elevator (magnitude and direction).express your answer with the appropriate units. enter positive value if the direction of the acceleration is upward and negative value if the direction of the acceleration is downward.
Answers
The acceleration of the elevator is -2.2 m/s2 downwards.
What is Acceleration?Acceleration is a vector quantity that describes the rate of change of an object's velocity over a period of time. It is measured in metres per second squared (m/s2). Acceleration is not the same as speed, which is the rate at which an object moves in a particular direction. Acceleration can be either positive (speeding up) or negative (slowing down) and is caused by an applied force, such as friction or gravity. The acceleration of an object changes with time and is dependent on the object's mass, drag, and the force that is applied to it.
To know more about Acceleration
https://brainly.com/question/460763
#SPJ1
A net force of 100 Newtons is applied to a 3kg ball. What is the ball's acceleration?
Answers
Force = Mass * Acceleration
100N = 3kg * a
Divide by mass (3) both sides
100/3= 3a/3
33.33m/s^2 = a
The ball’s Acceleration is 33.33m/s^2
Hope it helps!!
Which of the following objects requires the MOST power to lift?
A. A 2 kg box lifted 1 m in 1 s.
B. A 2 kg box lifted 2m in 1 s.
C. A 2 kg box lifted 1 m in 2 s.
D. A 2 kg box lifted 2 m in 2 s.
Answers
The object requires the MOST power to lift a 2 kg box 2 m in 1 s. Hence, option (B) is correct.
What is power?The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.
Power required for lifting a 2 kg box 1 m in 1 s = (2×9.8×1)/1 watt = 19.6 watt.
Power required for lifting a 2 kg box 2 m in 1 s = (2×9.8×2)/1 watt = 39.2 watt.
Power required for lifting a 2 kg box 1 m in 2 s = (2×9.8×1)/2watt =9.8 watt.
Power required for lifting a 2 kg box 2 m in 2 s = (2×9.8×2)/2watt =19.6 watt.
So, The most power required in lifting a 2 kg box 2 m in 1 s.
Learn more about power here:
https://brainly.com/question/29575208
#SPJ1
On a cold winter day, a steel metal fence post feels colder than a wooden fence post of identical size because: a. The specific heat capacity of steel is higher than the specific heat capacity of wood. b. The specific heat capacity of steel is lower than the specific heat capacity of wood. c. Steel has the ability to resist a temperature change better than wood. d. The mass of steel is less than wood so it loses heat faster. Selected:e. Two of the above statements are true.
Answers
Answer:
The specific heat capacity of steel is lower than the specific heat capacity of wood
Explanation:
THERE IS ONLY 1 ON MY assignment i geot dis right please brainlyist
The specific heat capacity of steel is lower than the specific heat of a piece of wood. Therefore, option (2) is correct.
What is the specific heat capacity?Specific heat can be defined as the heat energy required to change the temperature of one unit mass of a substance of a constant volume by 1 °C. The S.I. unit of the specific heat capacity of a material is KJ/Kg.
The thermal capacity of a material is defined as a physical property of a substance. The amount of heat is given to a given mass to create a change in unit temperature.
The mathematical expression of specific heat capacity can be written as :
Q = m C ΔT Where C is the heat capacity.
The specific heat capacity is an intensive property of a substance as it does not depend upon the size of the material.
A steel metal fence post feels colder than a wooden fence post of similar size because the specific heat of steel is lower than the specific heat capacity of wood.
Learn more about specific heat, here:
brainly.com/question/11297584
#SPJ5
Refer to the picture!
Answers
(a) The work done by the donkey on the cart is 59,721.9 J.
(b) The work done by the force of gravity on the cart is -48,434.87 J.
(c) The work done on the cart by friction during this time is 11,315.12 J.
What is the work done by the donkey on the cart?(a) The work done by the donkey on the cart is calculated as follows;
Wd = Fd cosθ
where;
F is the applied force by the donkeyd is the displacementθ is the angle of inclinationWd = 375 N x 163 m x cos(12.3)
Wd = 59,721.9 J
(b) The work done by the force of gravity on the cart is calculated as;
Wg = Fg x d x cosθ
Where;
Fg is the force of gravityd is the displacementθ is the angle between the force of gravity and displacementθ = 90⁰ + 4.03⁰ = 94.03⁰
Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)
Wg = -48,434.87 J
(c) The work done on the cart by friction during this time is calculated as;
Wf = Ff x d x cosθ
where;
Ff is the force of friction;Ff = μmg cosθ
Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)
Ff = 69.59 N
Wf = 69.59 x 163 x cos (4.03)
Wf = 11,315.12 J
Learn more about work done by gravity here: https://brainly.com/question/15352390
#SPJ1
Which best describes the potassium ion that forms?
O It is a negative ion that has one less valence electron
than a neutral potassium atom.
O It is a negative ion that has one more valence
electron than a neutral potassium atom.
O It is a positive ion that has one less valence electron
than a neutral potassium atom.
O It is a positive ion that has one more valence electron
than a neutral potassium atom.
thank you
Answers
A potassium ion can be described as it is a positive ion that has one less valence electron than a neutral potassium atom. Therefore, option (C) is correct.
What is an ion?An ion can be described as a chemical specie that exhibits a positive or negative charge. The term ‘ion’ can be used to refer to atoms or molecules with non-zero charges associated with them.
Therefore, all ions possess either greater electrons than protons in their atomic structures or greater protons than electrons. If the protons are greater than electrons hold a net positive charge and are generally referred to as cations.
The electronic configuration of the Potassium is 1s²2s²2p⁶3s²3p⁶4s¹. As the Potassium atom donates one electron in its valence shell it becomes cation K⁺.
Learn more about an ion, here:
brainly.com/question/13692734
#SPJ1
Answer:
C) It is a negative ion that has one more valence electron than a neutral bromine atom.
Explanation:
A bromide is a synthetic composite including a bromide ion or ligand. Potassium bromide (KBr) is a salt, usually selected as an anticonvulsant and a drug in the late 19th and early 20th centuries, with over the stand value increasing to 1975 in the US. Potassium bromide is applied as a veterinary drug, as an antiepileptic medicine for dogs.
Hope this helps! <3
A car accelerates from rest (v. 0 m/s) with a constant acceleration of
a = 5m/s2 for 12 seconds. What is the final speed of the car after the
12 seconds?
Answers
Heya!!
For calculate final velocity, lets applicate formula
\(\boxed{V=V_o+a*t}\)
Δ Being Δ
V = Final Velocity = ?
Vo = Initial velocity = 0 m/s
a = Aceleration = 5 m/s²
t = Time = 12 s
⇒ Let's replace according the formula:
\(\boxed{V=0\ m/s +5\ m/s*12\ s}\)
⇒ Resolving
\(\boxed{V=60\ m/s}\)
Result:
The velocity after 10 sec is 60 meters per second (m/s)
Good Luck!!