A car started moving from rest and reached the speed of 160 km h in 30 minutes. The distance travelled is 40 km.
Initial velocity of the car, u = 0 m/s (as car started from rest)
Final velocity, v = 160 km/h = 160 × 1000/3600 m/sec = \(\frac{400}{9}\) m/sec
Time taken, t = 30 minutes = 30 × 60 seconds = 1800 seconds
Using the equation,
v = u + at
\(\frac{400}{9}\) = 0 + a × 1800
a = \(\frac{400}{9}\)×\(\frac{1}{1800}\) = \(\frac{2}{81}\) \(m/sec^{2}\)
Putting the value of a into the equation ,
\(v^{2}\) - \(u^{2}\) = 2as
\((\frac{400}{9} )^{2}\) - \((0)^{2}\) = 2 × \(\frac{2}{81}\) × s
s = \(\frac{160000}{81}\) × ×\(\frac{81}{4}\) = 40000 m = 40000 ÷ 1000 km
distance travelled by car, s = 40 km
So the distance travelled by the car is 40 km when it started moving from rest and reached the speed of 160 km h in 30 minutes.
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The distance traveled by the car is approximately 22.22 meters.
To calculate the distance traveled by the car, we need to convert the given information to appropriate units and apply the formula:
Distance = Speed × Time
Given:
Initial speed = 0 km/h (since the car started from rest)
Final speed = 160 km/h
Time = 30 minutes
First, we convert the time from minutes to hours:
Time = 30 minutes = 30/60 = 0.5 hours
Next, we convert the speeds to meters per second (m/s) for consistency:
Initial speed = 0 km/h = 0 m/s
Final speed = 160 km/h = (160 × 1000) / (60 × 60) = 44.44 m/s (rounded to two decimal places)
Now, we can calculate the distance using the formula:
Distance = Speed × Time
Distance = 44.44 m/s × 0.5 hours = 22.22 meters (rounded to two decimal places)
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A Student 330 m 990m from another tall flip between the the Student stands Sound Interval beteeen cliff is cliff from of 1 st and 630 tall Hip which speed of 330 if the 330 m/s 2nd eh what is echo?
The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.
Let's break down the distances and calculate the time for each part of the journey:
Distance from the student to the first cliff: 330 meters
Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second
Distance from the first cliff to the second cliff: 990 meters
Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds
Distance from the second cliff back to the student: 990 meters
Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds
Now, we can calculate the total interval between the first and second echo by adding up the individual times:
Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds
Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.
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Note the complete questions is:
A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?
An evil mastermind has stranded you in the middle of a frictionless frozen pond where you are unable to push against anything. Suggest a way that you would be able to save yourself and get to safety without any help.
Explanation:
One way to save yourself and get to safety without any help on a frictionless frozen pond is to make use of the conservation of angular momentum. By spinning your body, you can create an angular momentum that can be used to propel yourself in the opposite direction.
To do this, you could start by extending your arms and legs outwards and then tucking them in towards your body. This will cause your body to start spinning in the opposite direction. By changing the position of your arms and legs, you can control the speed and direction of your spin.
As you spin, you can gradually increase the speed of your spin by tucking your arms and legs in closer to your body. This will cause your body to spin faster and faster, generating a larger angular momentum.
Once you have built up enough angular momentum, you can then extend your arms and legs outwards again to slow down and stop your spin. At this point, your body will be moving in the opposite direction to your initial spin, allowing you to glide across the ice without any external force.
By repeating this process, you can continue to generate angular momentum and propel yourself in the opposite direction until you reach safety. It may take some practice to master this technique, but with enough determination and persistence, it is possible to save yourself and get to safety without any help on a frictionless frozen pond.
Answer:
by using gravity to push off the floor
Explanation:
or by using ur own body heat to melt some of the ice around u
3. Would you expect a system with objects that have an equal amount of positive and negative
charge to have a large amount of electric potential energy? Why or why not?
Yes, I would expect a system with objects that have an equal amount of positive and negative charge to have a large amount of electric potential energy.
Why I will expect equal positive and negative chargeThis is because the electric potential energy of a system of charges is proportional to the product of the charges and inversely proportional to the distance between them. When positive and negative charges are brought close together, the electric potential energy of the system increases because the charges are attracted to each other due to their opposite charges.
As the charges get closer together, the electric potential energy of the system increases even more, because the charges are closer to each other and their attraction is stronger.
Therefore, when there are equal amounts of positive and negative charges in a system, the electric potential energy of the system will be high because there will be many oppositely charged pairs of particles that are close together and attracting each other strongly.
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What is the minimum amount ( in kg) of liquid water at 26 degrees that would be required to completely melt 41 grams of ice? The specific heat capacity of liquid water is 4180 J/kg/°C and the specific heat of fusion of ice is 3.33×105 J/kg.
Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.
To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.
The energy required to melt 1 kg of ice is 3.33×105 J/kg.
Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.
To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.
Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.
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Which of these boxes will not accelerate!
30 Newtons
40 Newtons
50 kg
15 Newton
B.
10 kg
30 Newtons
C.
30 Newtons
80 kg
20 Newtons
20 Newtons
20 Newtons
D.
75 kg
Answer:
(possibly) Box D
Explanation:
The one that has balanced forces will not accelerate. The forces are unbalanced in figures A, B, C. We cannot tell about figure D, because the downward force is not shown. If that force is 20 N, box D will not accelerate.
Blake records the amount of daily rainfall along with the average daily temperature for several days. The scatterplot shows his data.
Which statement about the outlier in the data set is true?
O Blake should not include the outlier because it overstates the effect of rainfall on temperature.
O Blake should include the outlier because it shows there is no relationship between rainfall and average daily temperature.
O Blake should not include the outlier because it understates the effect of rainfall on temperature.
O Blake should include the outlier because it shows there is a relationship between rainfall and temperature.
The scatterplot data set is true Because the outlier overstates how much rain affects temperature, Blake shouldn't include it.
A scatter plot displays what information?The changes seen in two different sets of variables might be related in several ways, according to a scatter plot. The strength of a relationship between two variables can be tested statistically and visually with this method.
What is the purpose of a scatter plot?The graphs known as scatter plots show how two variables within a data collection relate to one another. Both a two-dimensional plane and the Cartesian system are used to represent the data points. The Y-axis is used to plot the dependent variable, while the X-axis is used to represent the independent variable or attribute.
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. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification
The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.
Given:
Object height (h) = 5 cm
Focal length of the convex lens (f) = 10 cm
Object distance (u) = 15 cm (positive since it's on the same side as the incident light)
To determine the nature, position, and size of the image, we can use the lens formula:
1/f = 1/v - 1/u
Substituting the given values:
1/10 = 1/v - 1/15
To simplify the equation, we find the common denominator:
3v - 2v = 2v/3
Simplifying further:
v = 30 cm
The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.
To find the magnification (M), we use the formula:
M = -v/u
Substituting the values:
M = -30 / 15 = -2
The magnification is -2, indicating that the image is inverted and twice the size of the object.
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A 80kg stone falls from the top of the 360 meter cliff. Neglecting friction, how fast will the stone be moving just before it hits the ground?
The stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.
To find how fast will the stone be moving just before it hits the ground?This problem can be solved using the laws of kinematics and conservation of energy. The potential energy of the stone at the top of the cliff is converted to kinetic energy as it falls. We can equate the potential energy at the top of the cliff to the kinetic energy just before hitting the ground.
Potential energy = mgh,
Where
m is the mass of the stone g is the acceleration due to gravity (9.8 m/s^2) h is the height of the cliff (360 meters)Kinetic energy = (1/2)mv^2,
Where
v is the velocity of the stone just before hitting the ground.Equating these two expressions and solving for v, we get:
mgh = (1/2)mv^2
v^2 = 2gh
v = sqrt(2gh)
Plugging in the given values, we get:
v = sqrt(2 x 9.8 m/s^2 x 360 m) = 84.4 m/s
Therefore, the stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.
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Select the correct answer.
In general, how does an increase in distance from the Sun affect a planet?
ОА. .
The amount of sunlight the planet receives decreases.
OB.
The gravitational force exerted by the Sun increases.
ОС.
The thickness of a planet's atmosphere increases.
OD. The planet's atmosphere absorbs more heat.
Answer:
a.
gravity decreases by distance
thickness doesn't change
Less heat.
Enzyme reaction rates Consider the illustration below. What variable might be on the horizontal axis? (Click on all that apply) Temperature pH
Activation energy Competitive inhibitor concentration Rate of reaction Noncompetitive inhibitor concentration Salt concentration
In general, a reaction is sped up by increasing temperature and slowed down by decreasing temperature. But extremely high temperatures can denature an enzyme, causing it to lose its form and cease functioning.
How is the rate of reaction affected by variations in pH or temperature?As enzymes have a maximum temperature and pH at which their rate is maximal, temperature and pH can both raise or reduce the enzyme reaction rate. The pace of reaction for the enzyme will be slowed down by changes in temperature and pH that are not optimal.
Which of the following factors will speed up an enzyme reaction?An enzyme's concentration increases along with the speed of an enzyme-catalyzed process. An enzyme-catalyzed process accelerates with rising temperatures at low temperatures. The protein is denatured at higher temperatures, which also causes a sharp drop in reaction rate.
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A response is typically sped up by rising temperature and slowed down by falling temperature. However, exceedingly hot temperatures can denature an enzyme, causing it to lose its shape and stop working.
Temperature and pH have the ability to increase and decrease the rate of an enzyme reaction since enzymes have a maximum temperature and pH at which they function at their highest rate. Unfavorable variations in temperature and pH will cause the enzyme's reaction to proceed more slowly. The rate of an enzyme-catalyzed process increases as the concentration of the enzyme rises. When temperatures are low, an enzyme-catalyzed reaction speeds up as they rise. At higher temperatures, the protein is denatured, which also results in a dramatic decrease in response rate.
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If a quarterback gets hit by a defensive lineman with a mass of 100 kg and accelerating at a rate of 1m/s2 at what force is the quarterback getting hit?
The quarterback is getting hit with a force of 100 Newtons.
How to calculate the force with which the quarterback is getting hit
We can use Newton's second law of motion:
Force = Mass * Acceleration
Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:
Force = 100 kg * 1 m/s²
Force = 100 N
Therefore, the quarterback is getting hit with a force of 100 Newtons.
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44.7
When Xavier places his hands near a light bulb, he notices that certain areas around the light bulb are warmer than
others. Which best explains this?
The areas to the sides of the light bulb are warmest because of conduction,
O The areas to the sides of the light bulb are warmest because of convection,
The area directly above the light bulb is warmest because of conduction,
The area directly above the light bulb is warmest because of convection.
Save and Exit
Submit
Mark this and retum
Nex
Answer:
The area directly above the light bulb is warmest because of convection.
Explanation:
if all the sides of the bulb are equally close to the light source inside the bulb, all area of the bulb would be equally heated by conduction. however, convection heating mainly heats up the surface above the light source. in convection heating, the air above the surface of the light source get heated by the light source and expands, casuing it to be less dense and rise to the top of the bulb. colder denser air at the top of the bulb sink to the light source adn gain heat and expands, becoming less dense. this process repeats and the surface above the light source becomes the warmest due to convection heating
A 0.842g sample of Hydrogen 3 decays until 0.0526g remains. How many half lives have occurred?
A 0.842g sample of Hydrogen-3 decays to 0.0526g. Approximately 4.206 half-lives have occurred.
To determine the number of half-lives that have occurred, we can use the decay equation and the concept of exponential decay. The decay equation for radioactive decay is given by:
N(t) = N₀ * (1/2)^(t/T),\((1/2)^(^t^/^T^),\)
where N(t) is the remaining amount of the substance at time t, N₀ is the initial amount, t is the time elapsed, and T is the half-life of the substance.
In this case, we have an initial mass of 0.842g (N₀) and a remaining mass of 0.0526g (N(t)). We can set up the equation as follows:
0.0526g = 0.842g \(* (1/2)^(^t^/^1^2^.^3^2)\),
where t represents the number of half-lives that have occurred.
To solve for t, we can take the logarithm of both sides of the equation:
log(0.0526g/0.842g) = log\([(1/2)^(^t^/^1^2^.^3^2^)\)].
Using the logarithmic property log(\(a^b\)) = b*log(a), we can rewrite the equation as:
log(0.0526g/0.842g) = (t/12.32) * log(1/2).
Simplifying further:
log(0.0526g/0.842g) = (t/12.32) * (-log2),
where log2 is the logarithm base 2.
Now, we can solve for t:
t = (12.32 * log(0.0526g/0.842g)) / (-log2).
Using the given values and performing the calculation, we find:
t ≈ 4.206.
Therefore, approximately 4.206 half-lives have occurred.
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The steps in the formation of extrusive igneous rocks are listed below in an incorrect order:
1. Rock melts due to high temperature.
2. Rock is buried deep under Earth's surface.
3. Magma is forced out of Earth's surface during volcanic eruption.
4. Lava cools and crystallizes to igneous rock.
Which of these best shows the correct order of steps in the formation of extrusive igneous rocks?
The correct order of steps in the formation of extrusive igneous rocks is 1,3,4,2.
One of the three major categories of rocks that may be found on Earth is igneous rocks; the other two are sedimentary and metamorphic rocks. They are created as a result of molten rock, such as lava or magma, cooling and solidifying. Magma that has risen from the Earth's mantle has formed intrusive igneous rocks like granite and gabbro after it has cooled and solidified underground. These rocks' long cooling and crystallization processes gave them a rough texture.
Therefore, the correct order of steps is:
Rock melts due to high temperatures.Magma is forced out of Earth's surface during a volcanic eruption.Lava cools and crystallizes into igneous rock. Weathering and erosion expose the igneous rock at Earth's surface.To learn more about igneous rocks, refer to:
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Answer:
The correct answer is 2,1,3,4
Explanation:
I took the test and got the answer wrong using the one provided above and was corrected to 2,1,3,4 when reviewing the correct answers.
In hiking, what fitness component is required of you
A person rides in an elevator.
What is the equal and opposite force for the Earth’s force of gravity pulling down on the person as described by Newton's third law?
A) person's force of gravity pulls up on the elevator
B) person's normal force pushes down on the elevator
C) elevator's floor normal force pushes up on the person
D) person's force of gravity pulls up on the earth
The equal and the opposite force is the person's force of gravity pulls up on the elevator. Option A
What is an elevator?We know that the elevator is the kind of device that can be used when we are going up or down a high rise building. We have to note that the elevator that we talking about will also work based on the law of Newton.
We have to note that for every force there is an equal and an opposite force and the same is true when you are using the elevator to move up or down as we can see here.
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Mass
7. If the mass of the diver is 75 kg. What is the height he jumped
from?
Answer:
The height from which the diver jumped can be calculated using the laws of motion and the principle of conservation of energy.
Let's assume that the diver jumped from a platform with an initial velocity of zero. The potential energy (PE) of the diver at the top of the platform is given by:
PE = mgh
Where m is the mass of the diver, g is the acceleration due to gravity (9.8 m/s^2), and h is the height from which the diver jumped.
When the diver jumps, the potential energy is converted into kinetic energy (KE) as the diver moves downwards. The kinetic energy of the diver just before hitting the water is given by:
KE = (1/2)mv^2
Where v is the velocity of the diver just before hitting the water.
According to the principle of conservation of energy, the potential energy at the top of the platform is equal to the kinetic energy just before hitting the water. Therefore, we can equate the two equations above and solve for h:
mgh = (1/2)mv^2
h = (1/2)v^2/g
We need to find the value of v to calculate h. We can use the kinematic equation:
v^2 = u^2 + 2as
Where u is the initial velocity (which is zero in this case), a is the acceleration due to gravity (9.8 m/s^2), and s is the distance travelled by the diver (which is equal to h).
Substituting the values, we get:
v^2 = 2gh
v^2 = 2 * 9.8 * h
v^2 = 19.6h
Therefore:
h = v^2/(19.6)
Now, let's assume that the velocity of the diver just before hitting the water was 10 m/s (a reasonable value for a diving competition). Then:
h = (10^2)/(2*9.8) = 51 meters
Therefore, the height from which the diver jumped is approximately 51 meters.
How does methodology in natural science influence knowledge produced
Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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A falling object with a mass of 2.55 kg encounters 4.0 N of air resistance. What is the acceleration of the object? (Choose up to be the positive direction, and remember the definition of weight).
The acceleration of the falling object with a mass of 2.55 kg that encounters 4.0 N of air resistance is 1.57m/s².
How to calculate acceleration?Acceleration is change of velocity with respect to time (can include deceleration or changing direction).
The acceleration of a body can be calculated by using the following expression;
a = F/m
Where;
a = acceleration (m/s²)F = force (N)m = mass (kg)According to this question, a mass of 2.55 kg encounters 4.0 N of air resistance. The acceleration of the object can be calculated as follows:
a = 4N ÷ 2.55kg
a = 1.57m/s²
Therefore, 1.57m/s² is the acceleration of the object.
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The diameters of the main rotor and tail rotor of a single-engine helicopter are 7.59 m and 1.00 m, respectively. The respective rotational speeds are 448 rev/min and 4,140 rev/min. Calculate the speeds of the tips of both rotors.
$\sf\textbf{Tip\:speed\:of\: main\:rotor}\:\:=\:\pi \times$
$\sf\textbf{diameter\:of\:main\:rotor} \times {rotational\: speed\:of main\:rotor}$
$\implies\sf\textbf\:=\:\pi \times 7.59\:{ m} \times 448\:{\:rev/min}$
$\implies\sf\textbf\:=\:10,676.68\:{\:m/min}$
$\sf\textbf\:{Tip\:speed\:of\:tail\:rotor}\:=\:\pi \times$
$\sf\textbf\:{diameter\:of\:tail\:rotor} \times\:{rotational\:speed\:of\:tail\:rotor}$
$\implies\sf\textbf\:=\:\pi \times 1.00\:{ m} \times 4140\:{\:rev/min}$
$\implies\red\bigstar{\boxed{\textsf{\textbf{\:=\:13,015.93 \text{ m/min}}}}}$
\(\huge{\colorbox{black}{\textcolor{lime}{\textsf{\textbf{I\:hope\:this\:helps\:!}}}}}\)
\(\begin{align}\colorbox{black}{\textcolor{white}{\underline{\underline{\sf{Please\: mark\: as\: brillinest !}}}}}\end{align}\)
\(\textcolor{blue}{\small\textit{If you have any further questions, feel free to ask!}}\)
\({\bigstar{\underline{\boxed{\sf{\textbf{\color{red}{Sumit\:Roy}}}}}}}\\\)
Pete roller skates with a constant speed of 8 miles per hour. How long will he take to travel a distance of 12 miles?
Answer:
8 divided by 12 is 1.6
Explanation:
. .......
Scientists have been able to develop a nuclear fusion plant to generate energy.
True or False
Answer: true
Explanation:
a substance that turns litmus paper blue and contains hydroxide ions is most likely
Answer:
If it turns the paper blue it would have to be a base.
Explanation:
I hope that answers your question!
Answer:
If it turns the paper blue it would have to be a base.
Explanation:
I hope that answers your question!
I don’t understand what it’s asking me to do
Because the mass and displacement are already given in Kg and m, respectively, in the first part of your question, there is no need to convert them. However, in the second part of your question, you must use the given equation to calculate the spring constant.
if the table data is given in grams and cm you have to convert it using the following conversion,
1. To convert grams to kilograms, we divide the mass values by 1000.
2. To convert centimeters to meters, we divide the displacement values by 100.
But here in the given table it's already given the mass in kg and the displacement in meters (m). so no need to convert it.
Now comes the second part of your question,
To calculate the spring constants for the given data, we can use the equation:
k = -mg/Δx
where:
k is the spring constant (in N/m),
m is the mass (in kg), and
Δx is the displacement of the spring (in m).
Let's calculate the spring constants using the provided data:
Mass (kg): 0.05 0.1 0.2 0.3 0.4 0.5 0.6
Displacement of Spring (m): 0.012 0.027 0.065 0.1 0.135 0.17 0.199
Using the equation
k = -mg/Δx,
we can calculate the spring constant for each data point:
For the first data point (m = 0.05 kg, Δx = 0.012 m):
k = -0.05 kg * 9.8 m/s² / 0.012 m
k ≈ -40.833 N/m
Similarly, we can calculate the spring constants for the other data points:
For the mass of 0.05 kg, the spring constant is approximately -40.833 N/m.
For the mass of 0.1 kg, the spring constant is approximately -18.519 N/m.
For the mass of 0.2 kg, the spring constant is approximately -6.154 N/m.
For the mass of 0.3 kg, the spring constant is approximately -3.267 N/m.
For the mass of 0.4 kg, the spring constant is approximately -2.222 N/m.
For the mass of 0.5 kg, the spring constant is approximately -1.716 N/m.
For the mass of 0.6 kg, the spring constant is approximately -1.449 N/m.
Therefore, In the first part of the question, there is no need to convert the mass into kg and the displacement cm into m because it is already given in kg and m respectively, and in the second part question you have to calculate the spring constant using the given equation.
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Give one example of a question that science would not be able to test. Then, explain how it could be changed into a testable question. (5 points)
Josh starts his sled at the top of a 3.5-m high hill that has a constant slope of 25∘
. After reaching the bottom, he slides across a horizontal patch of snow. The hill is frictionless, but the coefficient of kinetic friction between his sled and the snow is 0.08.
If the coefficient of kinetic friction between Josh's sled and the snow is 0.08, he slides 6.97 meter from the base of the hill.
To find how far from the base of the hill Josh's sled ends up, we need to first find the speed of the sled at the bottom of the hill using the conservation of energy principle,
mgh = (1/2)mv², plugging in the values given in the problem, we get,
m(9.81 m/s²)(3.5 m) = (1/2)mv²
Simplifying and solving for v, we get,
v = √(2gh)
v = √(2(9.81 m/s²)(3.5 m))
v = 8.29 m/s
Now we can use the kinematic equation,
d = vt - (1/2)at, to find how far the sled slides on the horizontal patch of snow before coming to a stop, where d is the distance traveled, v is the initial velocity (8.29 m/s), a is the acceleration due to friction (-μg), and t is the time it takes to come to a stop (which we can find by setting v = 0 and solving for t),
0 = 8.29 m/s - μg*t
t = 8.29 m/s / μg
Substituting this value of t back into the kinematic equation, we get,
d = (8.29)(8.29/μg) - (1/2)μg(8.29/μg)²
d = 6.97 m
Therefore, Josh's sled ends up 6.97 meters from the base of the hill.
To know more about energy conservation principle, visit,
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Lisa made the electromagnet shown. (Image above) What can Lisa do to increase the strength of the electromagnet?
O She can use a nail with weaker magnetic properties.
O She can change the direction of the nail.
O She can increase the number of wire loops.
O She can reduce the current in the wire.
If correct first gets Brainliest Please hurry this is a timed test( this is second time just in case I didn't go through)
Answer:
I think C
Explanation:
if im wrong then what is it im taking the exam too
Answer: C. She can increase the number of wire loops.
Explanation:
What is environmental?
Answer:
Environmental means relating to or caused by the surroundings in which someone lives or something exists. It protects against environmental hazards such as wind and sun. The form the human family takes is a response to environmental pressures.
Explanation:
I HOPE IT HELPS!!
THANX!!!
STAY SAFE!!!!
Highschool Physics
1. The driver of a car traveling at 9.0m/s is honking their horn. The horn has a frequency of 625 Hz. If the car is moving toward a person waiting at the crosswalk, what frequency of the horn does the person hear?
2. As the same car from question#1 passes the person, what frequency of the horn does the person hear as the car moves away from them?
Using the formula for the Doppler effect:
f' = (v + vr) / (v + vs) * f
Given:
Source frequency (horn): f = 625 Hz
Speed of sound: v = 343 m/s (approximate value at room temperature)
The velocity of the receiver, vr, is zero because the person waiting at the crosswalk is stationary.
The velocity of the source, vs, is the speed of the car, which is given as 9.0 m/s.
Thus:
f' = (v + vr) / (v + vs) * f
= (343 m/s + 0) / (343 m/s + 9.0 m/s) * 625 Hz
= (343 m/s) / (352 m/s) * 625 Hz
≈ 609 Hz
Therefore, the person waiting at the crosswalk hears a frequency of approximately 609 Hz.
(2)Using the same Doppler effect formula:
f' = (v - vr) / (v - vs) * f
In this case, the velocity of the receiver, vr, is still zero because the person remains stationary.
The velocity of the source, vs, is now negative, indicating that the car is moving away from the person.
Thus:
f' = (v - vr) / (v - vs) * f
= (343 m/s + 0) / (343 m/s - (-9.0 m/s)) * 625 Hz
= (343 m/s) / (352 m/s) * 625 Hz
≈ 609 Hz
In other words, as the car moves away from the person, they would still hear a frequency of approximately 609 Hz.
More on Doppler effect can be found here: https://brainly.com/question/15318474
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