A car speeds up and accelerates for 5.1 seconds at a rate of 2.2 m/s2. if the car's initial velocity was 9.3 m/s, what was the car's final velocity
after accelerating?
-9.7m/s
-11.2m/s
1.9m/s
20.5m/s

Answers

Answer 1

Recall the definition of average acceleration:

a = (v - u)/∆t

where u and v are the initial and final velocities, respectively.

So we have

2.2 m/s² = (v - 9.3 m/s) / (5.1 s)

v - 9.3 m/s = (2.2 m/s²) * (5.1 s)

v = 9.3 m/s + (2.2 m/s²) * (5.1 s)

v = 20.52 m/s ≈ 21 m/s


Related Questions

1. An object was launched from the ground to the top of a building at a
distance of 65 m from its foot on a horizontal plane at an angle of 60
degrees. Using SOHCAHTOA, find the height of the building the
projectile was launched to from the ground.

Answers

Using SOH,CAH,TOA, we can calculate the height of the building by taking the sine of the launch angle (60°) and the distance traveled (65 m). The height of the building is 56.9 m.

What is SOH,CAH,TOA?

SOH,CAH,TOA stands for Sine = Opposite/Hypotenuse, Cosine = Adjacent/Hypotenuse and Tangent = Opposite/Adjacent. This is a set of trigonometric ratios that can be used to solve for angles and lengths of sides of a right triangle. It is used when the angle and length of two sides of a right triangle are known, but the length of the third side needs to be calculated.

Calculation using SOH, CAH, TOA

The distance from the ground to the top of the building is 65 m and the angle is 60 degrees. the height (h) of the building.has to be found

Using the trigonometric ratio of Sine,  calculate the height of the building:

Sin(60°) = Opposite/Hypotenuse

h/65 = sin(60°)

h = 65sin(60°)

h = 65(0.866)

h = 56.59 m

Therefore, the height of the building the projectile was launched to from the ground is 56.59 m.

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What is the independent variable if a scientist is turning bulb on and off to check behaviour of the earthworm?





Answers

The independent variable in this experiment is the act of turning the bulb on and off, while the dependent variable is the behavior of the earthworm in response to changes in light. The scientist can analyze the data collected to determine the impact of light on the earthworm's behavior.

In the experiment where a scientist is turning a bulb on and off to check the behavior of an earthworm, the independent variable is the manipulation performed by the scientist, which is the act of turning the bulb on and off.

The independent variable is the variable that the scientist deliberately changes or controls in order to observe its effect on the dependent variable. In this case, the scientist is interested in investigating how the earthworm responds to changes in light. By turning the bulb on and off, the scientist is manipulating the presence or absence of light in the environment of the earthworm.

The behavior of the earthworm, which is the dependent variable, will be observed and measured in response to the changes in light. The scientist may record various behaviors such as movement, burrowing, or changes in activity level exhibited by the earthworm when the light is turned on and off.

By systematically controlling the independent variable (turning the bulb on and off) and observing the dependent variable (behavior of the earthworm), the scientist can analyze the relationship between light exposure and the earthworm's behavior. This allows for drawing conclusions about how the earthworm responds to light stimuli.

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You are inside the Great Hall, 15 m from the north wall with the doors to the RMC, and centered between two open doors that are 3 m apart. Someone is blairing a 200 Hz tone outside the Great Hall so that it enters the doors as a plane wave. You hear a maximum intensity in your current position. As you walk along the direction of the wall with the doors (but maintain a distance 15 m from the wall), how far will you walk (in m) to hear a minimum in the sound intensity

Answers

Answer:

Δr = 0.425 m

Explanation:

This is a sound interference exercise, the expression for destructive interference is

          Δr = (2n + 1) λ / 2

in this case the movement is in the same direction as the sound, therefore the movement is one-dimensional

let's use the relationship between the speed of sound and its frequency and wavelength

          v = λ f

          λ = v / f

the first minium occurs for n = 0

           Δr = λ / 2

            Δr = v / 2f

            Δr = \(\frac{340}{2 \ 400}\)

             Δr = 0.425 m

this is the distance from the current position that we assume in the center of the room

If the same force is applied to each of these balls, which one will have the LEAST
acceleration
A
m 1.0 kg
B
m=7.3 kg 1
С
m=0.75 kg
D
m=0.5 kg

Answers

Answer:

d is the awnser

Explanation:

MABY?!??

Calculate the net force on the particle q1.

Calculate the net force on the particle q1.

Answers

Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers

Which refers to the sum of all the forces that act upon an object?
O absolute force
O net force
O positive force

Answers

Answer:

Net force refers to the sum of all the forces that act upon an object.

Explanation:

In which case would there be an electrostatic force between two objects?
O a positively charged object and a neutral object
O two positively charged objects
O two neutral objects
O a negatively charged object and a neutral object

Answers

Answer: Two positively charged objects

Explanation:

Because I said so. JK a neutral object will not react so no forces will be exerted by it.

What does Supernova mean?

Answers

Answer:

explosion of

A supernova is a large explosion that takes place at the end of a star's life cycle. A supernova is the explosion of a star. It is the largest explosion that takes place in space.

Explanation:

A car with an initial speed of 22.1 km/h accelerates at a uniform rate of 0.84 m/s2 for 4.4 s. Find the final speed of the car. Answer in units of m/s. Find the displacement of the car after that time. Answer in units of km.

(Desperately need help with Part 2)

A car with an initial speed of 22.1 km/h accelerates at a uniform rate of 0.84 m/s2 for 4.4 s. Find the

Answers

Answer:

Final speed of car = 9.834 m/s

Displacement = 0.035 km

Explanation:

Part 1

Final velocity, v of an object moving with an acceleration a m/s² for t seconds and an initial velocity u m/s is given by the formula
v = u + at m/s


\(\textrm{Initial velocity } u = 22.1 km/h\\\\\textrm{Convert this to m/s:}\\\\\textrm{1 km/h = 1000m/3600 s}\\\\ 22.1 km/h = 22.1 x 1000/3600 = 6.139 m/s\\\\\boxed{\textrm{Final velocity } v = u + at = 6.138 + 0.84 x 4.4 = 9.834 m/s}\)

Displacement s in m for a constant acceleration of a m/s² for a time t seconds is given by the formula:
\(x = ut+\dfrac{1}{2}at^2\)
where u is initial velocity

Plugging in the values we get
\(s = 6.139\cdot 4.4 + \dfrac{1}{2}\cdot0.84\cdot (4.4)^2 = 35.143 \;\mathrm {meters}\)
35.143 meters = 35.143/1000 =  0.035 km


Answer:

1)  9.83 m/s (2 d.p.)

2)  0.04 km (2 d.p.)

Explanation:

Constant Acceleration Equations (SUVAT)

\(\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}\)  

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Part 1

Given:

u = 22.1 km/ha = 0.84 m/s²t = 4.4 s

Convert km/h into m/s by dividing by 3.6:

\(\implies \sf 22.1\;km/h=\dfrac{22.1}{3.6}\;m/s\)

Substitute the given values into the formula and solve for v:

\(\begin{aligned}v&=u+at\\\implies v & = \dfrac{22.1}{3.6}+0.84(4.4)\\v & = 6.1388...+3.696\\v & = 9.834888...\\v & = 9.83 \sf \;m/s\;(2\:d.p.)\end{aligned}\)

Therefore, the final speed of the car was 9.83 m/s (2 d.p.).

Part 2

Substitute the given values into the formula and solve for s, remembering to use the initial velocity in m/s:

\(\begin{aligned}s & = ut+\dfrac{1}{2}at^2\\\implies s &=\dfrac{22.1}{3.6}(4.4)+\dfrac{1}{2}(0.84)(4.4)^2\\s &=27.0111...+8.1312\\s &=35.1423111...\sf m\end{aligned}\)

Convert meters into kilometers by dividing by 1000:

\(\implies \dfrac{35.1423111...}{1000}=0.0351423111...=0.04 \sf \; km\;(2\:d.p.)\)

Therefore, the displacement of the car after 4.4 s was 0.04 km (2 d.p.).

Pls help!!
Which situation describes a system with increasing gravitational potential energy?
a boy jumping down from a tree limb
a girl stretching a horizontal spring
a bicyclist riding up a steep hill
a train speeding up on a flat track

Answers

C) a bicyclist riding up a steep hill

The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:

A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.

     Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.

Question 8 (5 points)
What is indicated by the slope of an acceleration vs. time graph?
The maximum speed of the object
The total displacement of the object
The change in position of the object
The velocity of an object

Answers

The velocity of an object is indicated by the slope of an acceleration vs. time graph

What is velocity of an object?

Acceleration is how much velocity changes,from the definition here, the  slope of the graph tells us  how quickly the object's velocity is changing over time.

To dtermine object's velocity from an acceleration vs. time graph, you would have  to carry out the  integration of  the acceleration to get the object's velocity as a function of time.

Hence the last option is the corrcet answer here

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Answer:The velocity of an object

Place in chronological order the following steps in the formation and evolution of Earth's atmosphere: Correct Answer List Question List (6 items) (Drag and drop into the appropriate area) Life releases CO2 from the subsurface into the atmosphere. Oxygen enables the growth of new life-forms. No more items Hydrogen and helium are captured from the protoplanetary disk. Volcanoes, comets, and asteroids increase the inventory of volatile matter. Hydrogen and helium are lost from the atmosphere. Plant life converts CO2 to oxygen.

Answers

Earth had essentially no atmosphere when it originated around 4.6 billion year ago out of a volatile mixture of gases and minerals. The ground had melted on it. An atmosphere developed while Earth cooled, primarily from gases emitted by volcanoes.

What elements make up the atmosphere on Earth?

Approximately 78% of the gas in Upper orbit is nitrogen, while 21% is oxygen. In trace proportions, additional gases like carbon dioxide, neon, & hydrogen are also present in air.

What is significant about the atmosphere of Earth?

In addition to providing us with the oxygenation we need to survive, it shields us from dangerous UV solar radiation. Without it, the pressure needed for liquid water to exist on the surface of our planet would not be possible. And it warm our globe, maintaining habitable temperatures.

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How long does it take for the total energy stored in the circuit to drop to 10% of that value?

Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.

Answers

The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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A white blood cell has a diameter of approximately 12 micrometers or 0.012 um a model represents its diameter as 24 um what ratio of model size

Answers

Answer:

The ratio of the model size is 1 : 2000

Explanation:

Given

Real Diameter =  0.012 um

Scale Diameter =  24 um

Required

Determine the scale ratio

The scale ratio is calculated as follows;

\(Scale = \frac{Real\ Measurement}{Scale\ Measurement}\)

Substitute values for real and scale measurements

\(Scale = \frac{0.012\ um}{24\ um}\)

Divide the numerator and the denominator by 0012um

\(Scale = \frac{1}{2000}\)

Represent as ratio

\(Scale = 1 : 2000\)

Hence, the ratio of the model size is 1 : 2000

Answer:

Explanation: The Answer Is D Two Thousand & The Number



The sound intensity at a distance 2.00 m from a sound source is 5.00 Find the total sound energy emitted by the source in each second.

Answers

Answer:

     P = 251, 3 W

Explanation:

The intensity is defined as the power emitted per unit area

           I = P / A

Since sound is distributed in all directions spherical shape, the area of ​​a sphere is

           A = 4π r²

let's clear the power and replace

         P = I A

         P = I (4π r²)

let's calculate

         P = 5.00 (4π 2²)

         P = 251, 3 W

An electron entering the lower left side of a parallel plate capacitor and exiting at the upper right side. The initial speed of the electron is 5.69 x 106 m/s. The capacitor is 2.00 cm long, and its plates are separated by 0.150 cm. Assume that the electric field between the plates is uniform everywhere and find its magnitude.

Answers

Answer:

magnitude is 1382.59 N/C

Explanation:

Given the data in the question;

The time taken is;

t = x / v

we substitute;

t = ( 2 × 10⁻²) / ( 5.69  × 10⁶ )

t = 3.5149 × 10⁻⁹ s

next, the acceleration is;

a = 2y/t² = [2( 0.150 × 10⁻²)] / [ ( 3.5149 × 10⁻⁹ )² ]

a =  2.42826 × 10¹⁴ m/s²

now, the electric field is;

E = ma / q

we know that;

mass of electron m = 9.11 × 10⁻³¹ kg,

charge of electron q = 1.60 × 10⁻¹⁹ coulomb

we substitute

E = ( 9.11 × 10⁻³¹ )(2.42826 × 10¹⁴) / 1.60 × 10⁻¹⁹

E = 2.21214 × 10⁻¹⁶  / 1.60 × 10⁻¹⁹

E = 1.3826 × 10²¹

E = 1382.59 N/C

Therefore, magnitude is 1382.59 N/C  

A 5kg monkey is running with a velocity of 5 m/s to the right

Answers

The momentum of the monkey of mass 5 kg is 25 kgm/s.

What is Momentum?

Momentum is the product of mass and velocity.

To calculate the momentum of the monkey, we use the formula below.

Formula:

M = mv..................... Equation 1

Where:

M = Momentum of the monkeym = Mass of the monkeyv = Velocity of the monkey

From the question,

Given:

m = 5 kgv = 5 m/s

Substitute these values into equation 1

M = 5×5M = 25 kgm/s

Hence, the momentum of the monkey is 25 kgm/s.

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Complete question: A 5kg monkey is running with a velocity of 5 m/s to the right. Find the momentum of the monkey

An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. What is its speed when it hits its target?

Answers

The speed of the artillery shell when it hits its target is 100 m/s.

Given:

Initial vertical displacement (y) = 200 m

Vertical displacement at 100 m in the air (y') = 100 m

Final velocity in the vertical direction (vy') = 0 m/s (at the highest point of the trajectory)

Using the equation for vertical displacement in projectile motion:

y' = vy^2 / (2g),

where g is the acceleration due to gravity (approximately 9.8 m/s^2), we can solve for the initial vertical velocity (vy).

100 m = vy^2 / (2 * 9.8 m/s^2),

vy^2 = 100 m * 2 * 9.8 m/s^2,

vy^2 = 1960 m^2/s^2,

vy = sqrt(1960) m/s,

vy ≈ 44.27 m/s.

Now, since the horizontal motion is independent of the vertical motion, the horizontal speed of the shell remains constant throughout its trajectory. Therefore, the speed of the shell when it hits its target is 100 m/s.

Hence, the speed of the artillery shell when it hits its target is 100 m/s.

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what heavy element was the chernobyl nuclear accelarators supposed to make?​

Answers

Answer

plutonium

Explanation:

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find the magnetic filed strength at acenter of a soleneind with 500 turns and acurrent of 5A the permability of free space 4× 10-7n/m​

Answers

Answer:

The magnetic field strength at the center of a solenoid can be found using the formula:

B = u_0 * N * I / L

where B is the magnetic field strength, u_0 is the permeability of free space (4π × 10^-7 T·m/A), N is the number of turns in the solenoid, I is the current flowing through the solenoid, and L is the length of the solenoid.

Given:

N = 500 turns

I = 5 A

u_0 = 4π × 10^-7 T·m/A

Since we don't know the length of the solenoid, we can't calculate the magnetic field strength.

A train is slowing down with an average acceleration of −6.0 m/s2. If its initial velocity is 60.0 m/s, how far does it travel in 5.0 seconds?

140 m
230 m
270 m
530 m

Answers

If its initial velocity is 60.0 m/s, The velocity is 210 m.

What is Average acceleration?

Acceleration is crucial for understanding everything from the small world of subatomic physics to the huge expanses of space and our everyday experience.

In ordinary language, to accelerate is to increase speed; to depress the brakes will make a car slow down. For instance, we are familiar with our car's acceleration. The magnitude of the change in velocity over a particular period of time increases with acceleration.

linear particle accelerator studies, subatomic particles are accelerated to extremely high velocities in collision investigations, which reveal details about the structure of the subatomic world and the universe's beginning.

Therefore, If its initial velocity is 60.0 m/s, The velocity is 210 m.

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Which is the higher temperature? (Assume temperatures to be exact numbers.)(a)1.)265°C or 265°F?2.)265°C3.)265°F 4.)They are the same temperature..(b)1.)200°C or 370°F?2.))200°C3.)370°F 4.)They are the same temperature.

Answers

Remember the following formulas to convert temperatures between Farenheit and Celsius:

\(\begin{gathered} \text{ Farenheit to Celsius:} \\ C=\frac{5(F-32)}{9} \\ \\ \text{ Celsius to Farenheit:} \\ F=\frac{9}{5}C+32 \end{gathered}\)

Convert all the temperatures to Celsius to compare them.

Part a)

Convert 265ºF to Celsius:

\(\begin{gathered} C=\frac{5(F-32)}{9} \\ \\ =\frac{5(265-32)}{9} \\ \\ =129.444... \end{gathered}\)

Then, 265ºF is equal to 129.444...ºC. Then, 265ºC is higher than 265ºF.

The correct choice is option 2) 265ºC.

Part b)

Convert 370ºF to Celsius:

\(\begin{gathered} C=\frac{5(F-32)}{9} \\ \\ =\frac{5(370-32)}{9} \\ \\ =187.777...ºC \end{gathered}\)

Then, 370ºF is equal to 187.777...ºC. Then, 200ºC is higher than 370ºF.

The correct choice is option 2) 200ºC.

If a quarterback gets hit by a defensive lineman with a mass of 100 kg and accelerating at a rate of 1m/s2 at what force is the quarterback getting hit? ​

Answers

The quarterback is getting hit with a force of 100 Newtons.

How to calculate the force with which the quarterback is getting hit

We can use Newton's second law of motion:

Force = Mass * Acceleration

Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:

Force = 100 kg * 1 m/s²

Force = 100 N

Therefore, the quarterback is getting hit with a force of 100 Newtons.

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A car starts at a position of 1 km and moves to a final position of -3 km. What is the total distance traveled by the car?

Answers

The total distance covered by the car is 4 kilometers, this is because we are taking into account displacement and not just distance.

What is displacement?

Displacement is defined as the change in the position of an object while distance is an object's overall movement in a directionless fashion.

There are many different units that can be used to measure distance (inches, feet, miles, kilometers, and centimeters), but the meter is the SI unit. It is a scalar amount because it does not consider

On the number line, we can see the movement as follows

1 0 -1 -2 -3= 4km

Distance is always positive and never gets smaller as you move. Displacement can be negative, positive, or zero because it refers to the change in the position of an object with respect to its original location.

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for the circuit shown in find the output voltage(ii) the current through zenor diode

for the circuit shown in find the output voltage(ii) the current through zenor diode

Answers

A  Zener diode is a heavily made semiconductor device that is designed to operate in the reverse direction.Voltage drop across series resistance is 70 volts and  the current through zenor diode is 9mA.

When the voltage across the terminals of a diode is reversed, and the potential reaches the voltage (knee voltage), the junction break down, and the current flows in the reverse direction. This effect is known as the diode effect.

R = 5K ohms =  5 x 10^3 ohms

Input voltage  = 12V, Zener voltage = 50V

Output Voltage  = 50V

Voltage drop across series resistance = input voltage – zener voltage = 120 – 50 = 70 volts

Load Current  =  zener voltage / resistance   =  \frac{50}{10 x 10^3}   =   5 x 10^{-3}  A

Current through  = \frac{input voltage – zener voltage} {resistance}

                         = 70 /  5 x 10^{-3}   =  14 x 10^{-3}  A

According to kirchoff’s first law = current + zener current

       Zener current zener current = I - line current  = 14 x 10^{-3}  - 5 x 10^{-3}   = 9 x 10^{-3}   = 9 mA

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Space debris left from old satellites and their launchers is becoming a hazard to other satellites. (a) Calculate the speed in m/s of a satellite in an orbit 980 km above the Earth's surface.

Answers

Answer:

564

Explanation:

What is evidence used by Galileo to disprove Aristotle and Ptolemy?

Answers

Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.

Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:

1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.

2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.

3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.

4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.

These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.

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PLEASE HELP ME WITH THIS ONE QUESTION
A circular piston of radius 0.01 m is compressed by 0.02 meters. What is the change in volume of this compression?

Answers

Answer:6.28 cm³

Explanation radius of piston is 0.01 m = 1 cm

Area A =pi·r² = 3.14 cm². And height h= 0.02 m = 2 cm

Volume V= Ah

a 1 cm diameter sphere is charged to a potential of 3400 V. how much charge is on the sphere

Answers

The required sphere has a charge of 1.88 × 10⁻¹⁰C.

What is the charge?

A charge is a fundamental property of matter that describes the electrical property of matter that causes it to experience a force when placed in an electromagnetic field.

Here,
The charge on the sphere can be calculated using the formula:

Q = CV

The capacitance of a sphere can be calculated using the formula:

C = 4πεr / d

Assuming that the sphere is isolated in space, the capacitance is simply:

C = 4πεr

Substituting the given values:

C = 4π(8.85 × 10⁻¹² F/m)(0.5 cm) = 5.54 × 10⁻¹⁴ F

Now we can calculate the charge on the sphere:

Q = CV = (5.54 × 10⁻¹⁴ F)(3400 V) = 1.88 × 10⁻¹⁰ C

Therefore, the sphere has a charge of 1.88 × 10⁻¹⁰C.

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3. The mass of an electron is 9.1x10^-31 kg. The mass of a proton is 1.7x10^-27 kg.The gravitational force between them in the hydrogen atom is 1.0x10^-47 N.What is the separation distance between them?

Answers

Given:

The mass of the electron is,

\(m_e=9.1\times10^{-31}\text{ kg}\)

The mass of the proton is,

\(m_p=1.7\times10^{-27}\text{ kg}\)

The gravitational force between the electron and the proton in the hydrogen atom is,

\(1.0\times10^{-47}\text{ N}\)

To find:

the separation between them

Explanation:

The gravitational force between two masses is,

\(F=\frac{Gm_1m_2}{r^2}\)

Here, the universal gravitational constant is,

\(G=6.67\times10^{-11}\text{ Nm}^2kg^{-2}\)

Substituting the values we get,

\(\begin{gathered} 1.0\times10^{-47}=\frac{6.67\times10^{-11}\times9.1\times10^{-31}\times1.7\times10^{-27}}{r^2} \\ r^2=\frac{6.67\times10^{-11}\times9.1\times10^{-31}\times1.7\times10^{-27}}{1.0\times10^{-47}} \\ r^2=1.03\times10^{-20} \\ r=\sqrt{1.01\times10^{-20}} \\ r=1.01\times10^{-5}\text{ m} \end{gathered}\)

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