A car on flat ground accelerates at 0.785 m/s2 when a net force of 1050 N acts on it. How much normal force acts on it?

Answer:

With the increase in depth, age of layer increases.

Explanation:

According to the law of superposition, the layer of the Earth that is present in the deep is considered as the oldest layer while on the other hand, those layer which is present on the top of all layers is considered as youngest layer of earth. When we move from the top layer towards the bottom layer, the age of layer increases or in other words, when we move upward the age of the layer decreases so label the layers of earth on the basis of this phenomenon.

Starburst galaxies is simply known as the rate at which the galaxy is now converting gas into stars. The statement that is not a general characteristic of starburst galaxies is that The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center.

They are known to be rare. A starburst is known to be an astrophysical process. It is the process of star formation happening at a rate that is large when compared to the rate that is often observed.

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Which is not a general characteristic of starburst galaxies?

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The common speed in mph of the combined piece right after the collision was 30 mph. The cars move towards the lighter car.

An inelastic collision is a collision in which there is no internet loss in kinetic energy within the gadget because of the collision. each momentum and kinetic electricity are conserved portions in elastic collisions.

Calculation:-

50 mph = (50 × 0.477)

    = 22.35

   Applying the law of conservation of momentum.

we get the:-

m₁u₁ + m₂u₂ = (m₁ + m₂)V

V = m₁u₁ + m₂u₂/(m₁ + m₂)

   = 4000 × 22.35 + 1000 × (-22.35) / 4000 +1000

V = 13.41 m/s

 = 13.41/0.447

= 30 mph

Hence, the common speed of the car is 30mpH.

An inelastic collision is a come between two bodies in which the full kinetic energy of the two bodies remains equal. In an ideal, perfectly elastic collision, there may be no internet conversion of kinetic strength into other kinds which includes heat, noise, or capacity electricity.

Elastic collisions arise whilst both the momentum and kinetic energy are conserved, just like how billiard balls bounce off each different and move at the same speeds as earlier. Inelastic collisions appear whilst simplest the momentum is conserved but not the kinetic power.

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Answer: d) the elements in two compounds switch places

Explanation: just took it

Answer:

Work is measured joules.

Answer:

Joule

Explanation:

Since energy and work are two sides of the same coin, they are measured with the same units. The SI unit of energy/work is the joule (J), named for English physicist James Prescott Joule (1818 - 1889).

Answer:

east

Explanation:

15km east

_______________

              X________

                    8km west

so you are where the xX is so you are still in the eastward direction

x max = (vi² sin 2α) / g

x max = (6.25² sin 90)/10

x max = 39.0625/10 = 3.91 m

The description you provided suggests that turning the sander towards the left was not the answer. So, the correct answer to the question is ""pull away from you"".

Based on the description you provided, as you turn the finishing sander towards the right, the tendency of the sander would be to pull away from you. This is because the rotation of the flywheel is counterclockwise as seen from behind the handle, and turning the sander towards the right would cause the edge of the sander to dig into the wall, resulting in the sander wanting to move away from you.

Turning the sander towards the left would cause it to turn upward, and turning it downward would cause it to push toward you.

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Answer: B: The car is speeding up in the same direction as it is traveling.

Explanation:

I took the test and got it right

Answer:

Explanation:

Vector quantities are those quantities which needs both magnitude and direction for their description.

Here, in all the options except option B, there is no direction. This means, other options are scalar quantities and option B is only vector quantity.

Physical Quantities : These are the quantities of the physics which can me measured.

There are two types of physical quantities,

Vector quantities are those quantities which needs both magnitude and direction for their description. Example : Velocity, acceleration etc.

Scalar quantities are those quantities which needs only magnitude for their description. Example : Speed , distance etc.

I. Horizontal motion can be uniform because there is no force acting in the horizontal direction to change the velocity of the object.

II. Vertical motion is accelerated due to the force of gravity acting on the object.

III. When drag due to air resistance is taken into consideration, the motion of a projectile is affected because it experiences a resistive force that opposes its motion.

According to Newton's first law of motion, in the absence of air resistance or any other forces, an object moving horizontally will continue to move at a constant speed in a straight line.

On the other hand, vertical motion is accelerated due to the force of gravity acting on the object. Gravity pulls the object downwards, causing it to accelerate towards the ground.

When drag due to air resistance is taken into consideration, the motion of a projectile is affected because it experiences a resistive force that opposes its motion. As a result, the projectile's velocity decreases over time, causing it to cover a shorter distance and reach a lower maximum height than it would without air resistance.

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Answer:

v = 27 m/s

Explanation:

To find the speed of cars after the collision  you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.

After the collision both cars traveled together, then you have:

\(m_1v_1+m_2v_2=(m_1+m_2)v\)   (1)

m1: mass of the Toyota = 3-ton = 3000 kg

m2: mass of the taxi = 2-ton = 2000kg

v1: speed of the Toyota before the collision = 45m/s

v2: speed of the car before the collision = 0 m/s (it is  at rest)

v: speed of both cars after the collision = ?

You solve the equation (1) for v:

\(v=\frac{m_1v_1+m_2v_2}{m_1+m_2}\)

Next, you replace the values of the rest of the variables:

\(v=\frac{(3000kg)(45m/s)+0kgm/s}{3000kg+2000kg}=27\frac{m}{s}\)

hence, just after the collision both cars have a speed of 27m/s

The temperature and dew point of the parcel at a height of 2km on the leeward side, after descending from 3km, will depend on the wet adiabatic lapse rate used.

As the saturated parcel of air rises up the windward side of the mountain, it cools at a rate of \(7^0C\) per kilometer due to the wet adiabatic lapse rate. So, for a height gain of 1 km, the temperature decreases by \(7^0C\). Therefore, at a height of 3 km, the temperature would be \(15^0C - (7^0C/km * 1 km) = 8^0C\).

When the parcel begins to descend down the leeward side, it undergoes compression and adiabatic warming. However, since the given lapse rate is the wet adiabatic lapse rate, it is applicable only if the parcel remains saturated. If the parcel remains saturated during the descent, the temperature change would be the same as the ascent, i.e., \(7^0C\) per kilometer. Therefore, at a height of 2 km on the leeward side, the temperature would be \(8^0C + (7^0C/km *1 km) = 15^0C\).

The dew point temperature is the temperature at which the air becomes saturated, and it remains constant during adiabatic processes. Hence, at a height of 2 km on the leeward side, the dew point temperature would still be \(15^0C\).

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To maintain a constant velocity, the force applied must be equal to the force of friction.

This is because, according to Newton's first law of motion, an object in motion will remain in motion at a constant velocity unless acted upon by an external force.

In this case, the external force is the force of friction, which is trying to slow down the crate.

Therefore, to maintain a constant velocity, we need to apply a force that is equal in magnitude but opposite in direction to the force of friction.

So, the force that must be applied to maintain a constant velocity is 272 N.

In equation form, this can be written as:

Fapplied = Ffriction

Fapplied = 272 N

Therefore, the force that must be applied to maintain a constant velocity is 272 N.

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The average force needed to accelerate a 9.20 gram object is 0.092 N.

To calculate the average force needed to accelerate a 9.20 gram object, we need to know the acceleration and the time of acceleration. Let's assume that the acceleration and the time of acceleration are not given. Thus, we have to find them using the following equation:

F = ma

Where, F = force (in Newtons)

m = mass (in kilograms)

a = acceleration (in m/s²)

From the question, the mass of the object is given as 9.20 grams = 0.0092 kg. We need to convert it to kilograms to use it in our equation.

m = 0.0092 kg Now, we can find the acceleration of the object.

But, let's assume that the acceleration is given as 10 m/s².

So, a = 10 m/s²

Now, let's use the equation F = ma to find the force needed:

F = ma

F = 0.0092 kg × 10 m/s²

F = 0.092 N

Therefore, the average force needed to accelerate a 9.20 gram object with an acceleration of 10 m/s² is 0.092 N.

The average force needed to accelerate a 9.20 gram object is 0.092 N when the acceleration of the object is 10 m/s². We can find the force using the equation F = ma, where F is force, m is mass, and a is acceleration.The mass of the object is given as 9.20 grams, which is 0.0092 kg when we convert it to kilograms. The acceleration is given as 10 m/s². Therefore, the force needed to accelerate the object can be calculated using the equation:

F = ma

F = 0.0092 kg × 10 m/s²

F = 0.092 N

Thus, the average force needed to accelerate a 9.20 gram object is 0.092 N.

We can say that the average force needed to accelerate a 9.20 gram object can be found using the equation F = ma, where F is force, m is mass, and a is acceleration. If the mass of the object and the acceleration are given, then we can find the force easily. In this case, the mass of the object is 9.20 grams, and the acceleration is 10 m/s². Therefore, the average force needed to accelerate the object is 0.092 N.

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The shortest time interval that you have to listen to the sound from the two loudspeakers to hear three beats is 1.3 seconds.

In order to get the shortest time interval, the following formula will be used:

Δt = 1/|f1 - f2|Where Δt is the time interval and f1 and f2 are the frequencies of the first and second loudspeakers, respectively.

Substituting the given values, we have:Δt = 1/|236.30 - 236.42| Δt = 1/0.12Δt = 8.33

Therefore, the shortest time interval is 8.33 milliseconds or 1.3 seconds. The appropriate unit to express the answer is seconds.

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The current in the secondary is half the current in the primary when the secondary voltage is twice the primary voltage.

According to the transformer equation, the ratio of secondary voltage to primary voltage is equal to the ratio of secondary turns to primary turns:

V2 / V1 = N2 / N1

If the secondary voltage is twice the primary voltage (V2 = 2V1), then we have:

2V1 / V1 = N2 / N1

Simplifying this expression, we get:

2 = N2 / N1

This means that the secondary has twice as many turns as the primary.

According to the principle of conservation of energy, the power input to the primary coil is equal to the power output from the secondary coil (neglecting losses due to resistance and other factors):

P = VI

Since the voltage is stepped up by a factor of 2, the current in the secondary must be half the current in the primary to maintain the same power output:

I2 = I1 / 2

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Answer:

D

Explanation: need good posture other wise will injury yourself during activity

When, a 10 kg box will accelerates forward at a rate of 12 m/s². Then, the  force acting on the box is 120 Newtons.

Force is the physical quantity which describes the interaction between two objects, which tends to cause a change in the motion of an object.

We can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration;

F = m × a

where F will be the net force, m will be the mass of the object, and a will be the acceleration.

Substituting the given values, we get:

F = 10 kg × 12 m/s²

Simplifying, we get;

F = 120 N

Therefore, the force acting on the box is 120 Newtons.

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When the block slides up the ramp to point p, the total mechanical energy of the block remains constant and the total mechanical energy of the block-earth system decreases.

What is mechanical energy?

Mechanical energy of a body is the sum of the Kinetic energy and potential energy.

As the block slides up the ramp to point P, its mechanical energy decreases due to the work done by gravity against the block's motion. This work is equal to the change in the block's potential energy, which is mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the ramp.

At the same time, the block gains kinetic energy due to its motion up the ramp. This gain in kinetic energy is equal to the work done by the component of the block's weight parallel to the ramp, which is mgh sin(theta), where theta is the angle of the ramp with respect to the horizontal.

Therefore, the total mechanical energy of the block alone remains constant since the loss in potential energy is equal to the gain in kinetic energy.

However, the total mechanical energy of the block-earth system decreases as the block gains potential energy and the Earth gains an equal amount of potential energy in the opposite direction. This is because the block and Earth together form a closed system, and the total mechanical energy of a closed system remains constant only if there are no external forces acting on it. In this case, gravity is an external force that does work on the block and transfers energy to the Earth, causing a decrease in the system's total mechanical energy.

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When the block slides up the ramp to point p, the total mechanical energy of the block remains constant and the total mechanical energy of the block-earth system decreases.

The mechanical energy of a body is the sum of the Kinetic energy and potential energy.

The mechanical energy of the block diminishes as it slides up the ramp to point P due to the effort done by gravity against the block's motion. This effort is equivalent to the change in potential energy of the block, which is mgh, where m is the mass of the block, g is gravity's acceleration, and h is the height of the ramp.

Simultaneously, the block accumulates kinetic energy as it moves up the ramp. This increase in kinetic energy is equal to the work done by the block's weight component parallel to the ramp, which is much sin(theta), where theta is the ramp's angle with respect to the horizontal.

Therefore, the total mechanical energy of the block alone remains constant since the loss in potential energy is equal to the gain in kinetic energy.

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This question involves the concepts of the parallel combination of springs, Hooke's Law and equivalent spring constant.

Each spring will stretch by "25 cm".

For static condition of spring:

Weight of Brick = Extension Force

using Hooke's Law:

\(mg = kx\)

Consider the following data for a single spring:

K₁ = spring constant of single spring = K

x₁ = stretch in single spring = 50 cm

m = mass of brick

g = acceleration due to gravity

Therefore,

\(mg = k_1x_1\\mg = K(50\ cm) ---- eqn(1)\)

Now, for the second scenario, where two identical copies of the single spring are placed side by side in a parallel combination:

K₂ = Equivalent spring constant of the parallel combination of springs

K₂ = K + K = 2K

x₂ = stretch in each spring in the parallel combination of springs = ?

m = mass of brick

g = acceleration due to gravity

Therefore,

\(mg = k_1x_1\\mg = 2K(x_2) ---- eqn(2)\)

dividing eqn (1) and eqn(2), we get:

\(1 = \frac{50\ cm}{2x_2}\\\\\)

x₂ = 25 cm

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The attached picture illustrates Hooke's Law.

The result of two or more vectors is the outcome.  it's the outcome of multiplying two or more vectors.  The resultant result of adding the displacement vectors A, B, and C are vector R. An appropriately drawn, scaled, vector addition diagram is often used to compute vector R, as illustrated within the diagram.

What do three resultant vectors add up to?

Afbeeldingsresultat for these vectors' offspring

The outcome of multiplying vectors A + B + C is the same as that of multiplying vectors B + A + C or even C + B + A.  The resultant result will be the same as long as all three vectors are present with the appropriate magnitude and direction. The resultant of two or more vectors is the outcome.

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The distance between the 7th and the tenth second is 29.4 m.

We know that we can have to formulate the information that has been given here so as to obtain a proper progression and this would help us to get the common difference of the progression that we are looking at.

Now we know that the progression would look something like; 4.9, 14.7, 24.5 ....

We can see that this is an arithmetic progression that has a common difference of 9.8.

U7 = a + (n - 1)d

a = first term

n = Number of terms

d = common difference

U7 = 4.9 + (7 - 1) 9.8

= 63.7

U10 = 4.9 + (10 - 1) 9.8

U10 = 93.1

Between the 7th and 10th seconds, we have;

93.1 - 63.7

= 29.4 m

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According to the octet rule, the first energy level, also known as the K shell, is stable with a maximum of 2 electrons. This is because the K shell only has one subshell, which can hold a maximum of 2 electrons.

The outermost energy level, also known as the valence shell, is stable with a maximum of 8 electrons. This is because the valence shell has multiple subshells, including s, p, d, and f subshells, which can hold a total of 8 electrons. The octet rule states that atoms tend to gain, lose, or share electrons in order to achieve a full outermost energy level with 8 electrons, which results in greater stability.

The octet rule states that atoms are most stable when they have a full set of electrons in their outermost energy level, which typically means having 8 electrons (except for the first energy level). This is why atoms often form bonds with other atoms to achieve this stable configuration.

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The particles in Figure 22.46 exhibit signs of both positive and negative charges.

In Figure 22.46, the presence of both positive and negative charges can be inferred based on the observed behavior of the particles. The interaction between charged particles can be explained through the principles of electrostatics. When two particles carry the same type of charge, they repel each other, while particles with opposite charges attract each other.

By observing the behavior of the particles in Figure 22.46, we can identify the signs of their charges. For instance, if two particles move away from each other or repel each other, it indicates that they possess the same charge. This behavior is characteristic of particles with either positive or negative charges.

Conversely, if two particles move closer together or attract each other, it suggests that they possess opposite charges. This behavior is indicative of particles with opposing charges, where one carries a positive charge and the other carries a negative charge.

It's important to note that the exact nature of the charges cannot be determined solely based on the behavior of the particles in Figure 22.46. Further information or experimental data would be required to ascertain whether the charges are positive or negative. Nevertheless, the observed repulsion and attraction between the particles provide clear indications of the presence of both positive and negative charges.

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Number οf phοtοns per cubic millimeter = Number οf phοtοns / (Vοlume in cubic millimetres)

Tο find the physical length οf the pulse as it travels thrοugh space, we can use the equatiοn:

Length = (Speed οf light) x (Time)

(a) First, let's cοnvert the pulse duratiοn frοm picοsecοnds (ps) tο secοnds (s):

14.0 ps = 14.0 × \(10^{(-12)} s\)

The speed οf light is apprοximately 3 × \(10^8\) m/s, but we need tο cοnvert it tο the apprοpriate units tο match the pulse duratiοn. Sο, the speed οf light in picοmeters per secοnd (pm/s) is:

3 × \(10^8\) m/s = 3 × \(10^{14\) pm/s

Nοw we can calculate the length οf the pulse:

Length = (3 × \(10^{14\) pm/s) × (14.0 ×\(10^{(-12)} s\) )

(b) Tο find the number οf phοtοns in the pulse, we can use the equatiοn:

Energy οf the pulse = Number οf phοtοns × Energy per phοtοn

Given that the energy οf the pulse is 3.00 J and the wavelength οf the laser is 694.3 nm, we can calculate the energy per phοtοn using the equatiοn:

Energy per phοtοn = (Planck's cοnstant) × (Speed οf light) / (Wavelength)

Planck's cοnstant is apprοximately 6.626 × \(10^{(-34)\) J·s.

Nοw we can calculate the energy per phοtοn:

Energy per phοtοn = (6.626 × \(10^{(-34)\) J·s) × (3 × \(10^8\) m/s) / (694.3 × \(10^{(-9)\)m)

The number οf phοtοns in the pulse can be fοund by rearranging the equatiοn:

Number οf phοtοns = Energy οf the pulse / Energy per phοtοn

(c) Tο find the number οf phοtοns per cubic millimeter, we need tο knοw the vοlume οf the beam. The vοlume οf a cylinder is given by the equatiοn:

Vοlume = π × (Radius)² × Length

The radius οf the circular crοss sectiοn is half the diameter, sο it is 0.300 cm (οr 0.003 m).

The number οf phοtοns per cubic millimeter can be calculated by dividing the number οf phοtοns by the vοlume οf the beam in cubic millimeters:

Number οf phοtοns per cubic millimetre = Number οf phοtοns / (Vοlume in cubic millimeters)

Let's calculate the results:

(a) The physical length οf the pulse:

Length = (3 × \(10^{14\) pm/s) × (14.0 × \(10^{(-12)\) s)

(b) The number οf phοtοns in the pulse:

Energy per phοtοn = (6.626 × \(10^{(-34)\) J·s) × (3 × \(10^8\) m/s) / (694.3 ×\(10^{(-9)\)m)

Number οf phοtοns = Energy οf the pulse / Energy per phοtοn

(c) The number οf phοtοns per cubic millimeter:

Vοlume = π × (0.003 m)² × Length

Number οf phοtοns per cubic millimetre = Number οf phοtοns / (Vοlume in cubic millimetres)

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Yes, the center of the Milky Way is the most densely populated area of stars, and is therefore the most likely region to find newly formed stars.

What is the populated?

Populated refers to an area that has a large number of people residing in it. It is usually used to describe cities, towns, or other densely populated areas. Populated areas usually contain a variety of services and infrastructure to support their populations, such as schools, hospitals, transport links, and other amenities. Populated areas usually have higher rates of crime, pollution, and other problems associated with increased human activity.Populated refers to an area that has a high density of people living in it. It is usually used to describe cities and towns, but can also describe smaller areas, like neighborhoods.

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Answer:

Magnesium Chloride =MgCl 2

Explanation:

Hope I helped✌

Answer:

230 = x + 105

x= 125

Explanation:

v = v0 + at