9514 1404 393
Answer:
2.05 hours
Step-by-step explanation:
Using the given equation with the given time, we have ...
55x +35(2.5) = 200
55x = 112.5 . . . . . . . . subtract 87.5
x = 2.05 . . . . . . . . . . divide by 55
The car spends 2.05 hours at 55 mph.
100 points!!!
Determine the solution to the system of equations graphed below and explain your reasoning in complete sentences.
The solution to the system of equations graphed below is,
⇒ (0, 1)
Since, We have to given that;
Two system of equations are,
⇒ g (x) = 3x + 2
⇒ f (x) = |x - 1| + 1
Here, The graph of both system of equation are shown in graph.
We know that;
In a graph, the solution of system of equation are represented by a intersection point of both graph.
Here, In the graph of system of equation,
Intersection point is,
⇒ (0, 1)
Hence, The solution to the system of equations graphed below is,
⇒ (0, 1)
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two more and that it 30 + 30 × 30 + 20 ÷ 20
Let's see
30+30×30+20/2030+30^2+131+900931Done!
A salesperson sells $2700 in merchandise and earns a commission of $513.
Find the commission rate. Write your answer as a percentage.
Answer:
1.9%.
Step-by-step explanation:
2g(4g+3)+g(g-7) expand linear brackets
Answer:
7g^2 - 13g
Step-by-step explanation:
2g(4g+3)= 8g^2 + 6g
g(g-7)+ g^2 - 7g
8g^2 + 6g = g^2 - 7g
7g^2 = -13g
Shawn is typing a paper for class. He can type 1 5/14 pages in 1/3 of an hour. How many pages can shawn type in one hour?
Answer:
4 1/14
Step-by-step explanation:
1 5/14 x 3 = 4 1/14
Answer:
4 1/14 pages
Step-by-step explanation:
multiply 1 5/14 by 3
start by multiplying 1 by 3 which is 3
then multiply 5/14 by 3, you just have to multiply the 5 and you get 15/14 which is 1 1/14
add 3 and 1 1/14 and you get 4 1/14
a baseball player has a batting average of 0.315. what is the probability that he has exactly 4 hits in his next 7 at bats?
The probability that he has exactly 4 hits in his next 7 at bats is 0.12 .
In the question ,
it is given that
the batting average of the baseball player is = 0.315
so the probability of hitting the ball (p) = 0.315
and the probability of not hitting the ball (q) = 1 - 0.315 = 0.685
we have to find the probability of exactly 4 hits in his next 7 at bats
which means the number of trials (n) = 7
number of hits (x) = 4
Substituting the values of p , q, n , x in the Binomial Probability ,
we get
P(x) = ⁿCₓ*(p)ˣ*(q)ⁿ⁻ˣ
P(x=4) = ⁷C₄ * (0.315)⁴ * (0.685)³
= 35 * (0.315)⁴ * (0.685)³
= 35 * 0.00984 * 0.32141
= 0.1106936
≈ 0.12
Therefore , The probability that he has exactly 4 hits in his next 7 at bats is 0.12 .
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Which expression is equivalent to 4/9(2n-3)
A.)8/9n - 1 1/3
B.)2n-3
C.)2n - 1 1/3
D.) 8/9n -3
Step-by-step explanation:
your answer is 8.9 and minus 11 by 3 means your answer is A
Find the minimum value of sin²x-12 cos x-37.
To find the minimum value of the expression sin²x - 12cosx - 37, we can use various mathematical techniques such as differentiation and trigonometric identities.
Let's consider the expression sin²x - 12cosx - 37. To find the minimum value, we can start by taking the derivative of the expression with respect to x. The derivative will help us identify critical points where the function may have a minimum or maximum.
Taking the derivative of sin²x - 12cosx - 37 with respect to x, we get:
d/dx (sin²x - 12cosx - 37) = 2sinx*cosx + 12sinx
Setting the derivative equal to zero, we can solve for critical points:
2sinx*cosx + 12sinx = 0
Factoring out sinx, we have:
sinx(2cosx + 12) = 0
From this equation, we find two cases: sinx = 0 and 2cosx + 12 = 0.
For sinx = 0, the critical points occur when x is an integer multiple of π.
For 2cosx + 12 = 0, we solve for cosx:
cosx = -6
However, since the range of the cosine function is [-1, 1], there are no real solutions for cosx = -6.
To determine the minimum value, we substitute the critical points into the original expression and evaluate. We also consider the endpoints of the interval if there are any constraints on x. By comparing the values, we can identify the minimum value of the expression.
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Here is one method to sample from the Poisson (λ) distribution: Pick a number U 0
uniformly in the interval (0,1), i.e. use the RNG to choose a number called U 0
. If log(U 0
)<−λ then set x=0 and stop. If instead log(U 0
)>−λ then pick U 1
uniformly in (0,1). If log(U 0
)+log(U 1
)<−λ then set x=1 and stop. If log(U 0
)+log(U 1
)>−λ then pick U 2
uniformly in (0,1). If log(U 0
)+log(U 1
)+log(U 2
)<−λ then set x=2 and stop. This process continues until the process stops and you get a value of x. It can be shown that x will follow the Poisson distribution with rate parameter λ. Use a while loop to write a code to draw 10 5
independent samples from the Poisson(1) distribution. If you did this correctly then the mean and variance of your samples should both be equal to approximately 1 .
Here is a code to draw 105 independent samples from the Poisson(1) distribution using a while loop:
#import math
#import random
#import numpy as np
# function to generate a Poisson(1) random variable using the given method
def poisson1():
u0 = random.random()
s = math.log(u0)
x = 0
while s > -1:
x += 1
u = random.random()
s += math.log(u)
return x - 1
# generate 105 samples from the Poisson(1) distribution
samples = []
for i in range(105):
samples.append(poisson1())
# calculate the mean and variance of the samples
mean = np.mean(samples)
variance = np.var(samples)
# print the mean and variance of the samples
print("Mean of samples:", mean)
print("Variance of samples:", variance)```
The code first defines a function to generate a Poisson(1) random variable using the given method. It then generates 105 samples from the Poisson(1) distribution using a for loop and appends each sample to a list called "samples".
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PLEASE HELP!!! 30+ POINTS
Use the following data to construct a frequency table and calculate the mean, mode, and median.
Answer:
A measure of average is a value that is typical for a set of figures. Finding the average helps you to draw conclusions from data. The main types are mean, median and mode. Data is also often grouped.
Step-by-step explanation:
To find the mean add all the ages together and divide by the total number of children.
If you type all those ages into a calculator it is easy to make an error.
Suppose triangle ABC will be dilated using the rule D Subscript Q, two-thirds.
Point Q is the center of dilation. Triangle A B C is 6 units away from point Q. The length of A B is 3, the length of B C is 7, and the length of A C is 8.
What will be the distance from the center of dilation, Q, to the image of vertex A?
2 units
3 units
4 units
6 units
The distance from the center of dilation, Q, to the image of vertex A will be 4 units.
According to the given rule of dilation, D subscript Q, two-thirds, the triangle ABC will be dilated with a scale factor of two-thirds centered at point Q.
Since point Q is the center of dilation and the distance from triangle ABC to point Q is 6 units, the image of vertex A will be 2/3 times the distance from A to Q. Therefore, the distance from A' (image of A) to Q will be (2/3) x 6 = 4 units.
By applying the scale factor to the distances, we can determine that the length of A'B' is (2/3) x 3 = 2 units, the length of B'C' is (2/3) x 7 = 14/3 units, and the length of A'C' is (2/3) x 8 = 16/3 units.
Thus, the distance from the center of dilation, Q, to the image of vertex A is 4 units.
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Put these numbers in order from least to greatest.-12/40 -5 19/38
this is the answer: -5 < -12/40 < 19/38
Each of the four shaded rectangles has an area of 21 cm square and a perimeter of 20cm what is the perimeter of the square formed in middle
Answer:
16cm
Step-by-step explanation:
Given
\(Area = 21cm^2\)
\(Perimeter = 20cm\)
\(n=4\) --- rectangles
Required
The perimeter of square in the middle
The area of a rectangle is:
\(Area = L * W\)
So, we have:
\(L * W =21\)
The perimeter is:
\(P = 2*(L + W)\)
So, we have:
\(2*(L + W) = 20\)
Divide by 2
\(L + W = 10\)
Make L the subject
\(L = 10 - W\)
Substitute \(L = 10 - W\) in \(L * W =21\)
\((10 - W) * W = 21\)
Open bracket
\(10W - W^2 = 21\)
Rewrite as:
\(W^2 -10W +21 = 0\)
Expand
\(W^2 -3W - 7W + 21 = 0\)
Factorize
\(W(W - 3) - 7(W - 3) = 0\)
Factor out W - 3
\((W - 7)(W - 3) = 0\)
Solve for 7
\(W = 7\ W = 3\)
We have:
\(L = 10 - W\)
This means that:
\(W = 7\ W = 3\)
\(L = 3,\ L = 7\)
The length (l) of the square is:
\(l = |W - L|\) ---- the difference between the dimension of the rectangle
\(l = |7 - 3|\)
\(l = |4|\)
\(l = 4\)
The perimeter is:
\(P = 4l\)
\(P = 4*4\)
\(P =16\)
Let B= ⎣
⎡
a
b
c
0
b+1
c+2
a+3
1
c+3
a+2
b+1
0
⎦
⎤
Obtain QR decomposition of the resulting matrix B (possible always?).
The QR decomposition of the given matrix B, B = ⎣⎡ abc0 b+1c+2a+31 c+3a+2b+10 ⎦⎤, is possible and can be obtained. QR decomposition decomposes a matrix into an orthogonal matrix (Q) and an upper triangular matrix (R).
To obtain the QR decomposition of the matrix B, we need to find the orthogonal matrix Q and the upper triangular matrix R such that B = QR.
The QR decomposition is possible for any matrix as long as it has full rank and is non-singular. In other words, the matrix should have linearly independent columns.
In this case, the given matrix B does not have a specific structure that guarantees the QR decomposition. Therefore, we need to perform the decomposition through numerical methods such as Gram-Schmidt process or Householder reflections.
The process involves orthogonalizing the columns of B to obtain an orthogonal matrix Q, and then finding the upper triangular matrix R that relates the original matrix B to Q.
However, since the given matrix B is not explicitly provided and only the elements are given in terms of variables (a, b, c), it is not possible to calculate the exact QR decomposition without specific values for a, b, and c.
In conclusion, the QR decomposition of the matrix B is possible, but without the specific values for a, b, and c, we cannot provide the exact orthogonal matrix Q and upper triangular matrix R.
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Be sure to follow all the directions for writtenhomework as listed in the document Writing Requirements on our Canvas Homepage. Use only the material from this class covered in assignments HW1A- HW9A and HW2B-HW9B. Letter to a Friend 1 (5 points). Write a letter to a friend highlighting two of the main calculus ideas of the course. Be honest. Give your own understanding of the two ideas, not a textbook explanation. If there are some concepts you had trouble understanding at first, point these out and describe how you came to a better understanding. If there are other concepts you do not yet fully understand, point these out as well. After describing these ideas, make up and completely solve at least three of your own problems illustrating these ideas. The problems must be about "real-world" applications. One problem should use a trigonometric function, another an exponential function (with a base different from e), and the third is up to you (but it cannot be a linear function). You may base your problems on our homework assignments or outside sources, but you must modify such problems to make them your own. Be sure to cite your sources. You will be graded on the clarity, thoroughness and depth of your expla nations as well as on the quality of your problems (choosing tangential ideas or trivial problems will result in a low score. Please check with me if you are unsure.) The letter should run about 5-7 pages, typed and double-spaced. While differentiation "rules", like the power rule, did play a significant role in this class, they should not be considered main ideas. And while limits also played a key role in developing the idea of the derivative, limits in and of themselves are also not a main idea of the course. Nor are precalculus concepts. End your letter by asking questions about some concepts that you do not fully understand or about some ideas related to the course that pique your curiosity and you would like to know more about. Do not copy from a source. Submissions that do so, even only in part, will not receive credit.
1. Slope of the hill: Slope = tan(30) = 0.577.
2. Average speed of the car: Average speed = (2*e^t)/((e^t)+1) = 45 mph.
3. Average annual growth rate of the business: Annual growth rate = (ln(5000/1000))/(2-1) = 1.609.
4. Distance traveled by the rocket: Distance = (1/2)*sin(60)*3^2 = 3.897.
The calculus class has been enlightening and interesting, and I have learned a lot from it. Calculus encompasses two fundamental concepts: the derivative and the integral.
The derivative represents the slope of the tangent line of a graph or function. It measures the rate at which a function is changing and is used to identify maximum and minimum values. Although I initially found the concept challenging in high school, I eventually grasped that the derivative provides the slope of a function at any given point. This concept has numerous real-life applications.
The integral, on the other hand, calculates the area under the curve of a function. It is employed to determine distance, velocity, and acceleration. The concept of integration was new to me and posed some difficulty initially. However, I later discovered its usefulness in physics and engineering. Integration is also applicable in calculating the volume of complex shapes.
Calculus holds significant importance in science, engineering, and technology. The range of problems solvable with calculus is vast. Here are some examples:
Determining the slope of a hill
Calculating the speed of a car
Estimating the volume of a sphere
Finding the area under a curve
Measuring the distance traveled by a rocket
Assessing the acceleration of an object
Analyzing the growth rate of a population
Evaluating the financial earnings of a business
Estimating the amount of water in a pool
Determining the height of a building.
To illustrate the application of calculus to problem-solving, I will provide examples for the first four problems.
For the first problem, let's consider a trigonometric function. Suppose a hill is inclined at an angle of 30 degrees. We can calculate the slope of the hill using the equation: Slope = tan(30) = 0.577.
Moving on to the second problem, let's utilize an exponential function. Imagine a car traveling at a speed of 60 mph. After one hour, the speed reduces to 30 mph. To find the average speed of the car, we can employ the equation: Average speed = (2*e^t)/((e^t)+1) = 45 mph.
Next, for the third problem, we can utilize a logarithmic function. Let's say a business earns $1000 in the first year and $5000 in the second year. The average annual growth rate of the business can be calculated using the equation: Annual growth rate = (ln(5000/1000))/(2-1) = 1.609.
Finally, for the fourth problem, let's consider a trigonometric function. Suppose a rocket is traveling at an angle of 60 degrees. We can calculate the distance traveled by the rocket after 3 seconds using the equation: Distance = (1/2)*sin(60)*3^2 = 3.897.
These examples demonstrate the practical application of calculus in problem-solving across various fields.
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Predict whether atoms of chlorine or atoms of sulfur would be more likely to attract electrons and, therefore, be more reactive. Explain your reasoning.
Chlorine will be more reactive.
Reactivity of elementsFrom the question, we are to predict whether the atoms of chlorine or atoms of sulfur would be more likely to attract electrons
The electronic configuration of chlorine (Cl) is
2,8,7
This means Cl needs only one electron to complete its octet configuration
and
The electronic configuration of sulfur (S) is
2,8,6
This means sulfur needs two more electrons to complete its octet configuration
Since chlorine needs fewer electrons to complete its octet configuration, then it will be more likely to attract electrons.
Thus, chlorine will be more reactive.
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Decide whether the random variable x is discrete or continuous. Explain your reasoning.
i. Let x represent the number of Fortune 500 companies that lost money in the previous year.
ii. Let x represent the volume of gasoline in a 21-gallon tank.
i. The random variable x representing the number of Fortune 500 companies that lost money is discrete.
ii. The random variable x representing the volume of gasoline in a 21-gallon tank is continuous.
i. Let x represent the number of Fortune 500 companies that lost money in the previous year:
The random variable x can only take on discrete values because it represents a count of the number of companies.
The possible values for x are whole numbers (0, 1, 2, 3, and so on), indicating the count of companies that incurred losses.
There cannot be a fraction or continuous value for the number of companies that lost money.
Therefore, x is a discrete random variable.
ii. Let x represent the volume of gasoline in a 21-gallon tank:
The random variable x can take on any value within a continuous range.
The possible values for x can be fractional or decimal numbers, as the volume of gasoline can be any real value between 0 and 21 gallons.
It is not limited to specific discrete values.
Therefore, x is a continuous random variable.
Therefore, the random variable x in case (i) is discrete because it involves counting whole numbers, while in case (ii) it is continuous because it can take on any real value within a range. The distinction is based on the nature of the values that x can assume in each scenario.
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what is 1/2 plus 3/5 - 5
Answer:
-3.9
Step-by-step explanation:
hope it helps have a nice day
Answer:-3.9
Step-by-step explanation:
suppose that the true proportion of registered voters who favor the republican presidential candidate is 0,4 find mean and standard deviation of sample proportion if the sample size is 30
The mean and standard deviation of the sample proportion is 0.4 and 0.09798 respectively.
To find the mean and standard deviation of the sample proportion, we can use the following formulas:
mean of sample proportion = p = proportion in the population = 0.4
The standard deviation of sample proportion = σp = √(p(1-p)/n), where n is the sample size.
Plugging in the values given in the question, we get:
mean of sample proportion = p = 0.4
standard deviation of sample proportion = σp = √(0.4(1-0.4)/30) = 0.09798 (rounded to 5 decimal places)
Therefore, the mean of the sample proportion is 0.4 and the standard deviation of the sample proportion is 0.09798 (rounded to 5 decimal places).
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The manager of a grocery store has selected a random sample of 100 customers. The average length of time it took these 100 customers to check out was 3.0 minutes. It is known that the standard deviation of the checkout time is 1 minute.
Flag question: Question 11
Question 1125 pts
Refer to Exhibit 8-2. The standard error of the mean equals _____.
Group of answer choices
.001
.01
.1
1
The standard error of the mean for this random sample of 100 customers is 0.1.
The correct option is C.
The standard error of the mean is a measure that indicates the precision or variability of the sample mean in relation to the population mean. It represents the average amount of sampling error we can expect when estimating the population means based on a sample.
To calculate the standard error of the mean, we divide the standard deviation of the population by the square root of the sample size. In this case, the standard deviation is 1 minute and the sample size is 100.
Dividing 1 by the square root of 100, we get 1/10 or 0.1. This means that the standard error of the mean for this sample is 0.1.
A smaller standard error of the mean indicates that the sample mean is a more accurate estimate of the population mean. In this case, a standard error of 0.1 suggests that the average length of time it took customers to check out may vary around the sample mean by approximately 0.1 minutes.
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Question 15 of 25
If the factors of a polynomial are x + 8 and x+4, what values of x make that
polynomial O?
A. -8 and -4
B. 8 and -4
C. -8 and 4
D. 8 and 4
Answer:
Step-by-step explanation:
Polynomials are factored after they are set equal to 0. This i because the factors of the polynomial are also known as the x-intercepts, and x-intercepts exist where y = 0. Therefore, if the factors of the polynomial are
(x + 8)(x + 4) = 0, then by the Zero Product Property,
x + 8 = 0 so x = -8 or
x + 4 = 0 so x = -4. Choice A.
(SAT Prep) In the given figure, C is the midpoint of AB and M is the midpoint of AC. Find the length of NB if MC = 4 and AN = 14. (A) 3 (B) 6 (C) 2 (D) 3.5
Answer:
C) 2
Step-by-step explanation:
I don't have an explanation, I just guessed.
Answer:
(C) 2
Step-by-step explanation:
We will need to make a Given, Statement, and Reason table to solve this problem.
Given: Statement: Reason:
AC=CB AC=2MC Part Whole Postulate
AM=CM AC=2x4=8 Substitution and Algebra
CM=4 AB=2AC Part Whole Postulate
AN=14 AB=2x8=16 Substitution and Algebra
Find: AB-AN=NB Part Whole Postulate
NB 16-14=2 Substitution and Algebra
NB=2
Hope this helps! :)
Marc eats an egg sandwich for breakfast and a big burger for lunch every day. The egg sandwich has 250 calories. If Marc has 5,250 calories for breakfast and lunch for the week in total, how many calories are in one big burger?
Answer: 5,000 calories
Step-by-step explanation:
Subtract both
Someone please help with 13 and 14
Answer:
Step-by-step explanation:
13 is 76 because it’s vertical to UYV
14 is 40 because it’s vertical to TYU
Help me please!!!!!!!
1/3
because there are 15 balls total and 5 are red, so 15/5 = 3 meaning 1/3 and also being that there are three different colors, so yeah, 1/3
These two polygons are similar.
4
2
9
16
15
w
w = [? ]
45 points asap for anyone who can answer
Solve the following equation for the value of X
giving brainliest answer
Answer:
A
Step-by-step explanation:
-5 represents the rate at which the temperature drops while 54 represents the initial temperature.
2
When the denominator of
is rationalized, it becomes
V3
21
3
Answer:
\( \sqrt{3} \)
Step-by-step explanation:
\( \frac{2}{ \sqrt{3} } \)
\( \frac{2}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{2 \sqrt{3} }{3} \)
The National Assessment of Educational Progress (NAEP) includes a mathematics test for eighth-grade students. Scores on the test range from 0 to 500. Suppose that you give the NAEP test to an SRS of 2500 eighth-graders from a large population in which the scores have mean - 282 and standard deviation e-40. The mean will vary if you take repeated samples.
Suppose that we took an SRS of 1600 eighth-graders and found - 285. Compared with an SRS of 2500 eighth-graders, the margin of error for a 95% confidence interval for u is
smaller.
either smaller or larger, but we cannot say which.
larger.
The correct option is "smaller".The margin of error for a 95% confidence interval for u will be smaller if we took an SRS of 1600 eighth-graders as compared to an SRS of 2500 eighth-graders.
The given standard deviation is σ = 40 and the sample size is n = 2500.
From the above data, the standard error can be calculated as:
$$SE=\frac{\sigma}{\sqrt n} = \frac{40}{\sqrt {2500}}
= 0.8$$For a 95% confidence interval, we have the z-value as 1.96.
From the above data, the margin of error is given as:
$$ME = z*\frac{σ}{\sqrt n}
= 1.96*\frac{40}{\sqrt {2500}} = 1.568$$
So, the margin of error is 1.568. Next, we will find out the margin of error for a sample size of n=1600.
Similarly, we can calculate the standard error as:
$$SE=\frac{\sigma}{\sqrt n}
= \frac{40}{\sqrt {1600}} = 1$$For a 95% confidence interval, we have the z-value as 1.96.
From the above data, the margin of error is given as:
$$ME = z*\frac{σ}{\sqrt n}
= 1.96*\frac{40}{\sqrt {1600}} = 1.568$$So, the margin of error is 1.96.
Therefore, the margin of error for a 95% confidence interval for u is smaller when we took an SRS of 1600 eighth-graders as compared to an SRS of 2500 eighth-graders. The correct option is "smaller".
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