A car is rolling backwards when I hit the gas after 8.2 five seconds it is movie Florida 8.62 M/s is 12.9m to the right of its starting point

Answers

Answer 1

The correct answer -5.49 m/s.

The data is provided as follows.

Initial velocity (u) =?, Final velocity (v) = 8.62 m/s.

Time is 8.25 seconds, and the distance is 12.9 meters.

As a result, the following formula can be used to determine beginning velocity.

v = v_0 + at

8.62 m/s = v_0 + a×8.25

v_0 = 8.62-8.2a ____(1)

s = v_0×t +1/2 a ×t^2 _____(2)

As a result, enter the value from equation (1) into equation (2) in the manner described below.

s =8.62m/s-8.25a×t+1/2 a×t^2 ______(3)

Now enter the following values for s and t into equation (3).

12.9 m = (8.62-a×8.25)×8.25+1/2 a× (8.25)^2

a= 1.71 m/s^2

As a result, the value of initial velocity using equation (1) will be as follows.

v_0=8.62-8.25×1.71

v_0=-5.49 m/s

As a result, we may say that the car's beginning speed is -5.49 m/s.

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Related Questions

Suppose that a driver applies a force of 140 N to the master cylinder, which has a diameter equal to 14 the diameter of the brake cylinder. What is the force applied by the brake cylinder on the brake shoe?

Answers

Answer:

force on brake shoes is 10 N

Explanation:

for the master cylinder;

force applied = 140 N

diameter = 14d

for brake cylinder;

force applied on the brake shoe by the brake cylinder f = ?

diameter = d

The pressure will be transmitted undiminished from the master cylinder to the brake cylinder according to pascals pressure law.

pressure = force/area

but cross sectional area is proportional to diameter of the cylinder

therefore

\(\frac{140}{14d } = \frac{f}{d }\)

the diameters will cancel out, and we're left with

force on brake shoes = 10 N

Explain the structure of a clinical thermometer​

Answers

Explanation:

a clinical thermometer is a thermometer used to measure human body temperature. mostade in the 20th century are mercury-in-glass thermometer. they ate accurate and sensitive having a narrow place where the mercury level rises very fast. a kink in the tube stops the mercury level from falling on its own.

hope it helps you

What is the velocity (in m/s) of a 0.179kg billiard ball of its wavelength is 7.83cm​

Answers

Answer: 472.556m⋅s−1

Explanation: λ=7.83cm=7.83⋅(1cm)=7.83⋅(1cm×0.01m1cm)=0.0783m

why does it require much less force to accelerate a low mass object

Answers

It requires much less force to accelerate a low mass object because force is directly proportional to mass according to Newton's second law of motion.

Newton's second law states that the force acting on an object is equal to the product of its mass and acceleration, and it can be expressed as F = m * a. This means that for a given force, if the mass of an object is lower, the resulting acceleration will be higher.When a force is applied to an object, its mass determines how much inertia the object possesses. Inertia refers to an object's resistance to changes in its motion. Objects with lower mass have less inertia, making it easier to change their velocity or accelerate them. With less mass, there is less resistance to overcome, and a smaller force is needed to produce the same acceleration compared to a heavier object.In practical terms, this means that low mass objects can be accelerated more easily and quickly compared to high mass objects. It is why lighter objects can be moved, lifted, or accelerated with less effort or force applied to them.

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In your own words What is a molecule?

Answers

Answer:

The smallest particle in a chemical element or compound is called a molecule. Molecules are composed of atoms bonded together by chemical bonds. The sharing or exchange of electrons between atoms forms these bonds. Two hydrogen atoms are an example of a molecule.

please help.. i got it wrong on my last attempt

please help.. i got it wrong on my last attempt

Answers

Answer:

The answer is C.

Explanation:

The answer is a , Thermo means heat & dynamic is when something moves.

A ________ is a system of government in which member states retain almost all of their sovereign authority and delegate limited powers to a weak central body. Group of answer choices confederation bicameral state republic unitary state

Answers

A "confederation" is a system of government in which member states retain almost all of their sovereign authority and delegate limited powers to a weak central body.

In a confederation, the central government has limited authority and primarily serves as a coordinating body for the member states. The member states maintain a significant degree of independence and have the power to make decisions on matters that directly affect them.

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A 25-newton weight falls freely from rest from the roof of a building. what is the total distance the weight falls in the first 1.0 second?

Answers

The weight falls 4.9 metres in total throughout the first 1.0 seconds.

What is the total distance the weight falls in the first 1.0 second?The equation of motion can be used to calculate the total distance the weight travels during the first 1.0 seconds. The acceleration of an object is proportional to the net force acting on it, according to Newton's second law, which is the basis for this equation. d = 0.5at2 is the motion equation.Where an is the acceleration, t is the time, and d is the total distance the weight falls. The acceleration in this situation is 9.8 m/s2, which is the acceleration brought on by gravity. As a result, 4.9 metres are covered by the weight in the first second.The kinematic equation for velocity, which is: v = v0 + at, can also be used to determine this.Where v0 is the initial velocity (which in this case is 0 because the weight is initially at rest), t is the time, and v is the end velocity. You can rewrite this equation to find the overall distance:d = v0t + 0.5at^2The outcome is the same when we substitute in the values for v0, a, and t.The total distance the weight falls in the first 1.0 second is 12.5 meters. This is calculated using the formula: distance = (1/2) x acceleration (due to gravity) x time squared. In this case, acceleration due to gravity is 9.8 m/s2 and time is 1.0 second, so the equation would be: 12.5 = (1/2) x 9.8 x (1.0)2, which simplifies to 12.5 = 4.9 x 1.0, and finally 12.5 = 4.9.

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A vector points 12.0 units along the x-axis, and 9.00 units along the y-axis.

Find the direction of the vector.​

Answers

Answer:

15 units NE

Explanation:

Assuming the coordinate plane is a compass with N being the positive y-axis, we can use the Pythagorean theorem to find the magnitude of the vector. Since the vector is going up by 12 and right by 9 at the same time, it should form a diagonal line, aka the hypotenuse of a triangle. This triangle has both of its leg units as 12, and 9. Pythagorean theorem states that a^2 + b^2 = c^2, that is both of their legs squared is the hypotenuse of the triangle squared. 12^2 + 9^2 = c^2. c = 15. Now that we know the magnitude, let's go back to the quadrants as the compass. Since both units are positive, the vector goes in the positive direction on both sides, which is Quadrant 1. North and East would be the appropriate say for the vector's direction, thus the vector's direction will be 15 units North East.

Two spheres are launched horizontally from a 1.2 m high table. Sphere A is launched with an initial speed of 3.5 m/s. Sphere B is launched with an initial speed of 1.5 m/s.
What is the time for the sphere A to hit the floor?
What is the time for the sphere B to hit the floor?
What is the distance that sphere A travels from the edge of the table?
What is the distance that sphere B travels from the edge of the table?

Answers

(a) The time for the sphere A to hit the floor is 0.5 second.

(b) The time for the sphere B to hit the floor is 0.5 second

(c) The distance travelled by sphere A from the edge of the table is 1.75 m.

(d) The distance travelled by sphere B from the edge of the table is 0.75 m.

What is the time of motion of sphere A?

The time of motion of sphere A is calculated by applying the following formula.

t = √ ( 2h / g )

where;

h is the height of fall of sphere Ag is acceleration due to gravity

t = √ ( 2 x 1.2 / 9.8 )

t = 0.5 second

The time of motion of sphere B is calculated as;

t = √ ( 2 x 1.2 / 9.8 )

t = 0.5 second

The distance travelled by sphere A from the edge of the table is calculated as;

d = vt

where;

v is the speed of sphere At is the time of motion

d = 3.5 m/s  x 0.5 s

d = 1.75 m

The distance travelled by sphere B from the edge of the table is calculated as;

d = 1.5 m/s  x  0.5 s

d = 0.75 m

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Imagine you have a ball tied to the end of a string. You hold the other end of the string and swing it around. Suppose the string breaks, what direction will the ball travel

Answers

It will move in a curving motion starting in the direction where it snapped from. In the end it goes down :D

How many walking paces are there approximately as you walk down Main Street (0.25 miles)?
1 mile = 5280 feet;
1 foot = 12 inches;
22 inches = 1 walking pace

Answers

The number of walking paces as you walk down main street (0.25 miles) is 720 walking paces

How to convert 0.25 mile to feet

1 mile = 5280 feet

Therefore,

0.25 mile = (0.25 mile × 5280 feet) / 1 mile

0.25 mile = 1320 feet

How to convert 1320 feet to inches

1 feet = 12 inches

Therefore,

1320 feet = (1320 feet × 12 inches) / 1 feet

1320 feet = 15840 inches

How to convert 15840 inches to walking pace

22 inches = 1 walking pace

Therefore,

15840 inches = (15840 inches × 1 walking pace) / 22 inches

15840 inches = 720 walking paces

Thus, we can conclude that as you walk down main street (0.25 miles), there are 720 walking paces

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A shopper in Whole Foods pushes their cart with a force of 40 N directed at an angle of
30 degrees downward form the horizontal. Find the work done by the shopper on the
cart as he moves down a 15 m aisle to the tofu section.

If the mass of the cart (24kg), from problem 1, and we neglect friction, how fast will the cart
be moving when it reaches the tofu section if it started from rest?

The shopper brings the cart to rest is 2.7 s when he reaches the tofu. What power
does he exert in stopping the cart?

You take the bus with your bike to the top of Twin Peaks in San Francisco. You are
facing a long descent: the top of Twin Peaks is 600 m higher than its base. The
combined mass of you and your bicycle is 85 kg. How much gravitational potential
energy do you have before your descent?

• On an unknown airless planet an astronaut drops a 4 kg ball from a 60 m ledge. The
mass hits the bottom with a speed of 12 m/s. What is the acceleration of gravity g on
this planet?

You descend. If all that potential energy is converted to kinetic energy, what will your
speed be at the bottom?

The planet has a twin in an alternate universe with exactly the same acceleration of
gravity. The difference is that this planet has an atmosphere. In this case, when
dropped from a ledge with the same height, the 4 kg ball hits bottom at the speed of 9
m/s. How much energy is lost to air resistance during the fall?

A 1500 kg car starts at rest and speeds up to 3 m/s with a constant acceleration. If the
car reaches its final speed in 1.2 s, what is its acceleration?

How far does the car travel in that time?
• What is the car's gain in kinetic energy?
• What power is exerted by the engine?

Answers

Answer:

Work done by the shopper on the cart: The force of 40 N at an angle of 30 degrees downward from the horizontal can be resolved into its horizontal and vertical components. The horizontal component of the force is:F_horizontal = F * cos(theta) = 40 N * cos(30) = 34.64 N


The work done by the shopper on the cart is equal to the force applied multiplied by the distance moved, multiplied by the cosine of the angle between the force and the displacement. In this case, the displacement is 15 m, and the angle between the force and the displacement is 30 degrees. Therefore:Work = F * d * cos(theta) = 34.64 N * 15 m * cos(30) = 448.5 J


Speed of the cart at the tofu section: The initial potential energy of the cart and shopper is equal to their combined mass (85 kg) multiplied by the acceleration due to gravity (9.81 m/s^2) multiplied by the height of Twin Peaks (600 m). 

Therefore: Potential energy = m * g * h = 85 kg * 9.81 m/s^2 * 600 m = 498,690 J


Since the shopper neglects friction, all of the potential energy is converted into kinetic energy at the bottom of the hill. The kinetic energy of the cart and shopper can be found using the formula:


Kinetic energy = 0.5 * m * v^2

where m is the mass of the cart and shopper, and v is their speed.

Therefore:Kinetic energy = 0.5 * 85 kg * v^2 Since the potential and kinetic energies are equal, we can set them equal to each other and solve for the speed v: Potential energy = Kinetic energym * g * h = 0.5 * m * v^2v = sqrt(2 * g * h) = sqrt(2 * 9.81 m/s^2 * 600 m) = 109.43 m/s


Power exerted by the shopper in stopping the cart:The shopper brings the cart to rest over a distance of 15 m in a time of 2.7 s. The average force exerted by the shopper on the cart can be found using Newton's second law: F = m * a = m * (v_f - v_i) / twhere m is the mass of the cart, v_i is the initial speed of the cart (which is zero), v_f is the final speed of the cart, and t is the time taken to stop the cart. Solving for F gives:F = m * (v_f / t)The work done by the shopper in stopping the cart is equal to the force applied multiplied by the distance moved, which is 15 m. Therefore:Work = F * d = m * (v_f / t) * d = 24 kg * (0 - 0) / 2.7 s * 15 m = 0 JSince no work is done in bringing the cart to rest, the power exerted by the shopper is zero.Acceleration due to gravity on the unknown planet:The final speed of the 4 kg ball is 12 m/s, and it falls a distance of 60 m. The initial speed is zero, so the final velocity is equal to the velocity acquired due to gravity. The final velocity can be found using the formula:v_f^2 = v_i^2 + 2 * g * hwhere v_i is the initial velocity (which is zero), h is the height fallen, and g is the acceleration due to gravity.

1) A 2-kg object moving at 10 m/s has a 4-N force applied to it. Can you predict how the force will affect the object?
es
A) yes, it will slow it down at a rate of 2 m/s?
B) yes, it will speed it up at a rate of 2 m/s
yes, it will speed it up at a rate of 4 m/s?
D) It cannot be determined without more information,

Hint
Regular Calc
Graphing Calc
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Answers

Answer:D) It cannot be determined without more information,

Explanation:

Constructed Response Items:
11. (SPS7a) How many joules of heat energy are needed to raise the temperature of 10,0 g (0.0100
kg) of aluminum from 22 K to 55 K, if the specific heat of aluminum is 897J/kg * K.

Answers

Answer:

elp me please with the question  p osted rn im

taking a test and need it

Explanation:

a single source creates two beams of light with a wavelength of 750 nm. the beams travel two different paths to the same point. the lengths of the paths differ by 1500 nm what is seen at that point?

Answers

At that point, you would observe a dark fringe in the interference pattern created by the two beams of light. This is because the two waves destructively interfere with each other and cancel out their amplitudes. The exact location of the dark fringe will depend on the exact geometry of the paths taken by the two beams.

This scenario describes a classic example of an interference pattern created by two beams of light. The two beams will interact with each other when they meet at the same point, and the resulting pattern will depend on the phase difference between the two beams.The phase difference depends on the path length difference between the two beams. If the path length difference is equal to an integer multiple of the wavelength of the light, then the two beams will be in phase and will reinforce each other, creating a bright spot. If the path length difference is equal to a half-integer multiple of the wavelength of the light, then the two beams will be out of phase and will cancel each other out, creating a dark spot.

In this scenario, the wavelength of the light is 750 nm, and the path length difference is 1500 nm. This means that the path length difference is exactly equal to twice the wavelength of the light. Therefore, the two beams will be exactly out of phase when they meet at the same point, and they will create a dark spot.

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Question 2 A generator is connected through a transformer to a synchronous motor. Reduced to the same base, the per-unit subtransient reactances of the generator and motor are 0.15 and 0.35, respectively, and the leakage reactance of the transformer is 0.10 per unit. A three-phase fault occurs at the terminals of the motor when the terminal voltage of the generator is 0.9 per unit and the output current of the generator is 1.0 per unit at 0.8 power factor leading. Find the subtransient current in per unit in the fault, in the generator, and in the motor. Use the terminal voltage of the generator as the reference phasor and obtain the solution (a) by computing the voltages behind subtransient reactance in the generator and motor and (b) by using Thévenin's theorem.

Answers

(a) The sub transient current in per unit at the fault is approximately 0.6428, in the generator is approximately 2.523, and in the motor is approximately 0.9190.

(b) Using Thévenin's theorem, the subtransient current in per unit at the fault is approximately 0.6428.

(a) Computing the voltages behind subtransient reactance:

To find the subtransient current in per unit at the fault, in the generator, and in the motor, we need to compute the voltages behind subtransient reactance in both the generator and motor.

Per-unit subtransient reactance of the generator (X''g) = 0.15

Per-unit subtransient reactance of the motor (X''m) = 0.35

Leakage reactance of the transformer (Xl) = 0.10

Terminal voltage of the generator (Vg) = 0.9 per unit

Output current of the generator (Ig) = 1.0 per unit

Power factor of the generator (pf) = 0.8 leading

The subtransient voltage in the generator (V''g) can be calculated using the formula:

V''g = Vg - (X''g * Ig)

V''g = 0.9 - (0.15 * 1.0)

V''g = 0.75 per unit

The subtransient voltage in the motor (V''m) can be calculated using the formula:

V''m = V''g * (X''g / X''m)

V''m = 0.75 * (0.15 / 0.35)

V''m ≈ 0.3214 per unit

Now, let's calculate the subtransient current at the fault (If):

If = V''m / (X''m + Xl)

If = 0.3214 / (0.35 + 0.10)

If ≈ 0.6428 per unit

The subtransient current in the generator (I''g) can be calculated using the formula:

I''g = (V''g - V''m) / X''g

I''g = (0.75 - 0.3214) / 0.15

I''g ≈ 2.523 per unit

The subtransient current in the motor (I''m) can be calculated using the formula:

I''m = (V''m - 0) / X''m

I''m = 0.3214 / 0.35

I''m ≈ 0.9190 per unit

Therefore, the subtransient current in per unit at the fault is approximately 0.6428, in the generator is approximately 2.523, and in the motor is approximately 0.9190.

(b) Using Thévenin's theorem:

By using Thévenin's theorem, we can calculate the subtransient current at the fault (If) directly.

The equivalent impedance looking back into the generator and motor combined can be calculated as:

Zeq = (X''g * X''m) / (X''g + X''m + Xl)

Zeq = (0.15 * 0.35) / (0.15 + 0.35 + 0.10)

Zeq ≈ 0.0567 per unit

The equivalent subtransient voltage behind the impedance (Veq) can be calculated as:

Veq = Vg - (Zeq * Ig)

Veq = 0.9 - (0.0567 * 1.0)

Veq ≈ 0.8433 per unit

Finally, the sub-transient current at the fault (If) is given by:

If = Veq / (Zeq + X''m)

If = 0.8433 / (0.0567 + 0.35)

If ≈ 0.6428 per unit

Therefore, using Thévenin's theorem, the sub-transient current in per unit at the fault is approximately 0.6428.

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if a highway curve of radius 75.0 m is banked at 15.0 degrees, what is the speed at which a car can negotiate this curve even in the complete absence of friction?

Answers

The minimum speed at which a car can negotiate this banked curve, even in the complete absence of friction, is approximately 18.8 m/s.

What is no slip condition?

The speed at which a car can negotiate a banked curve with a given radius and banking angle, even in the complete absence of friction, is called the "no-slip" or "minimum" speed.

here,

The gravitational force acting on the car is balanced by the normal force provided by the banked surface, and the car moves in a circular path with no slipping or skidding.

The minimum speed for a car to negotiate a banked curve can be found using the following equation:

v = √(r * g * tan(θ))

In this case, the radius of the curve is 75.0 m, and the banking angle is 15.0 degrees or 0.262 radians. Plugging these values into the equation, we get:

v = √(75.0 * 9.8 * tan(0.262))

v ≈ 18.8 m/s

Therefore, the minimum speed at which a car can negotiate this banked curve, even in the complete absence of friction, is approximately 18.8 m/s.

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what force is required to move 7 M if the work done is 9 J

Answers

Answer:

1.29 N

Explanation:

The equation for force (with work and distance) is:

\(Force=\frac{Work}{distance}\)

We can plug in the given values into the equation:

\(Force=\frac{9J}{7m}$\approx1.29 N\)

A force of 1.29 N is required to move 7 meters if the work done is 9 J.

What is the work?

Work can be described as the product of the component of the force (F) in the direction of displacement (d) and the magnitude of this displacement. Work can be described as the energy utilized when a force is applied to move a body through a displacement.

The force acts to move an object in the direction of the applied force over a distance in a straight line.

W= F × d

Where W is work done, 'F' is the applied force, and 'd' is the displacement.

Given, the work done by the applied force, W = 9 J

The displacement by an object, d = 7 m

The force applied to the object can be determined as F = W/d

\(F = \frac{9J}{7m}\)

\(F = 1.29\times \frac{N.m}{m}\)

F = 1.29  N

Therefore, the force required is equal to 1.29 N.

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5.24 While standing in a low tunnel, you raise your arms and push against the ceiling with a force of 100 N. You mass is 70 kg. A what force does the ceiling exert on you?A 10 NB 100 NC 690 ND 790 NE 980 NB What force does the floor exert on you?A 10 NB 100 NC 690 ND 790 NE 980 N

Answers

While standing in a low tunnel, you raise your arms and push against the ceiling with a force of 100 N and mass is 70 kg.

Hence, the correct option is C.

When you push against the ceiling with a force of 100 N, the ceiling exerts an equal and opposite force on you (Newton's third law). This means that the ceiling exerts a force of 100 N on you downwards.

The force that the ceiling exerts on you is also known as the normal force (N) because it is perpendicular to the surface (ceiling) on which you are applying the force.

To calculate the force that the floor exerts on you, we need to consider the forces acting on you in the vertical direction. There are two forces your weight (due to gravity) and the normal force from the floor. When these forces are in equilibrium, you are not accelerating in the vertical direction, i.e. you are at rest.

The weight of you is given by

W = mg

Where W is the weight, m is the mass, and g is the acceleration due to gravity (9.8 m/\(s^{2}\)).

W = (70 kg)(9.8 m/\(s^{2}\)) = 686 N

W = 686 N

Since you are at rest, the forces in the vertical direction must balance each other out. Therefore, the normal force from the floor must be equal to your weight.

Normal force from floor = W = 686 N

Therefore, the force that the floor exerts on you is 686 N.

Hence, the correct option is C.

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As a warehouse worker pushes a crate across a concrete floor, the force he applies is not perfectly horizontal, as shown in the image below. If the coefficient of kinetic friction between the crate and concrete floor is 0.5, what is the net force on the crate?
A. 87 N
B. 110 N
C. 77 N
D. 135 N

Answers

The net force on the crate can be calculated using the formula Fnet = μmgcosθ, where μ is the coefficient of kinetic friction, m is the mass of the crate, g is the acceleration due to gravity, and θ is the angle between the force applied and the horizontal. In this case, μ = 0.5, m = 200 kg, g = 9.8 m/s2, and θ = 30°. Therefore, the net force on the crate is Fnet = (0.5)(200)(9.8)(cos30°) = 110 N. Therefore, the correct answer is B. 110 N.

The U.S. uses a household voltage of 110 V. However electric stoves and dryers are wired with 220 V outlet, or a German made 220 V rated curling iron into a 110 V outlet? explain​

Answers

23468=83821 yea yea yea

A teacher asks students to identify which demonstrations show physical changes and which show chemical changes.
Which demonstration shows a physical change?
A. Baking soda is mixed with vinegar. The mixture bubbles.
B. A dish of water is placed in the freezer. The water turns solid.
Ο Ο Ο Ο
C. A piece of pH paper is dipped in clear ammonia. The paper turns from yellow to pink.
D. Hydrogen peroxide solution is dropped on a potato slice. The liquid bubbles and fizzes.

Answers

Answer:

B. A dish of water is placed in the freezer and turns solid

Explanation:

it is a physical change because it can return to its original state by physical means. the other options are chemical changes because things like color change, bubbles or fizzing, and odor change all indicate a chemical change and cannot return to the original state it was in before.

difference between reflection of sound, echo and reverberation

Answers

Reflection of sound is the bouncing of sound waves off a surface. Echo is the repetition of sound due to reflection of sound waves off a surface. Reverberation is the persistence of sound in a particular space after the original sound has stopped.

Hope that helps!

a cylinder weighs 29.2 grams what is its density? and will it float in water?

Answers

In order to determine the density of a cylinder, we need to know its mass and volume. The mass of the cylinder is given as 29.2 grams, but the volume is not provided. Without the volume, it is impossible to calculate the density of the cylinder.

As for whether or not the cylinder will float in water, that also depends on its density. If the density of the cylinder is less than the density of water (1), then it will float. However, without knowing the density of the cylinder, it is impossible to determine whether or not it will float in water.

A supply plane drops a package to the ground for stranded campers below. After falling for 8.14 seconds, the package will have a downward velocity of 80.79 m/s. How high was the plane when it dropped the package?

Answers

Answer:

333 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0 m/s.

Time (t) = 8.14 s.

Final velocity (v) = 80.79 m/s.

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

v² = u² + 2gh

80.79² = 0 + (2 × 9.8 × h)

6527.0241 = 0 + 19.6h

6527.0241 = 19.6h

Divide both side by 19.6

h = 6527.0241 / 19.6

h = 333 m

Thus, the plane was at a height of 333 m when the package was dropped.

1. A car travels 50 miles going at a constant speed of 60 miles per hour. How long did it take the
car to reach its destination?
a. 0.83 hours
b. 3.00 hours
c. 1.2 hours
d. 110 seconds

Answers

Answer:

A. 0.83 hours

Explanation:

Calculate the size of the magnetic field (in µT) at 10.76 m below a high voltage power line. The line carries 450 MW at a voltage of 300,000 V. You should round your answer to the nearest integer.

Answers

The magnetic field at 10.76 m below the high voltage power line is approximately 41,835,820 µT when the line carries 450 MW at a voltage of 300,000 V. Rounded to the nearest integer, the magnetic field is 41,836 µT.

To calculate the magnetic field at a distance below a high voltage power line, we use the formula \(B=\frac{u0IH}{2\pi r}\)

Current, I = 450 MW = 450 × 10^6 W

Height, H = 0 m (since the power line is at ground level)

Distance below the power line, r = 10.76 m

Using the formula for the magnetic field, we substitute the given values:

\( B = \frac{{(4\pi \times 10^{-7} \, \text{{T}} \cdot \text{{m/A}}) \cdot (450 \times 10^6 \, \text{{W}}) \cdot (0 \, \text{{m}})}}{{2\pi \cdot 10.76 \, \text{{m}}}} \)

Simplifying the expression:

\( B = \frac{{450 \times 10^6 \, \text{{W}}}}{{10.76 \, \text{{m}}}} \)

Calculating the value:

\( B \approx 41,835,820 \, \text{{T}} \)

Rounding the magnetic field to the nearest integer:

\( B \approx 41,836 \, \mu\text{{T}} \)

Therefore, the magnetic field at 10.76 m below the high voltage power line is approximately 41,836 µT (rounded to the nearest integer).

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which would cause a greater change in energy of motion doubling the weight or doubling the speed why

Answers

Answer:

Doubling the speed.

E - M v^2

M = W / g     energy is proportional to weight

But energy is proportional to v^2

estimate the overall resistance of a heating element which is 220 cm long and consists of nichrome wire with a diameter of 0.56 mm. the resistivity of nichrome is 110x10-8 ω•m.

Answers

The estimated overall resistance of the heating element is approximately 0.99 Ω. We can use the formula for the resistance of a wire.

To estimate the overall resistance of the heating element, we can use the formula for the resistance of a wire:

R = (ρ * L) / A

where R is the resistance, ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.

Given:

Length of the wire (L) = 220 cm = 2.20 m

Diameter of the wire (d) = 0.56 mm = 0.056 cm = 0.00056 m

Resistivity of nichrome (ρ) = 110 × 10^(-8) Ω·m

First, we need to calculate the cross-sectional area (A) of the wire using the diameter:

A = π * (d/2)^2

Substituting the values:

A = π * (0.00056/2)^2

= π * (0.00028)^2

= π * 7.84 × 10^(-8) m^2

≈ 2.461 × 10^(-7) m^2

Now, we can calculate the resistance (R):

R = (ρ * L) / A

= (110 × 10^(-8) Ω·m * 2.20 m) / 2.461 × 10^(-7) m^2

= 0.99 Ω

Therefore, the estimated overall resistance of the heating element is approximately 0.99 Ω.

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