A car is moving at a constant speed along a straight line. Which statement is true about the forces acting on the car?

Answers

Answer 1

The statement that is true about the forces acting on the car is that the net force acting on the car from all directions is zero. Option A is correct.

What is force?

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The complete question is

"A car is moving at a constant speed along a straight line. Which statement is true about the forces acting on the car?

A.

The net force acting on the car from all directions is zero.

B.

The net force acting on the car is greater than the car's weight.

C.

The net force acting on the car is in the direction of the car's motion.

D.

The net force acting on the car is in the opposite direction of the car's motion."

The net force operating on the automobile in all directions is zero,

The statement that is true about the forces acting on the car is that the net force acting on the car from all directions is zero. Option A is correct.

Hence option A is correct.

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Related Questions

Shrinking Loop. A circular loop of flexible iron wire has an initial circumference of 166 cm , but its circumference is decreasing at a constant rate of 12.0 cm/s due to a tangential pull on the wire. The loop is in a constant uniform magnetic field of magnitude 0.900 T , which is oriented perpendicular to the plane of the loop. Assume that you are facing the loop and that the magnetic field points into the loop.

Answers

Answer:

plis plis pilis plis plis plis plis plis plis plis plks plis plis plis

Nowton's third law refers to 'action reaction forces*. These forces are
always:

Answers

equal in magnitude but opposite in direction

QUESTION 6 Which of the following sources is also NOT considered a scholarly source? O Journal of Counseling Psychology Early Childhood Education Journal Psychology Today Social Psychology Quarterly QUESTION 7 and reference sch​

Answers

Explanation:

I hope.this answer is helpful ):
QUESTION 6 Which of the following sources is also NOT considered a scholarly source? O Journal of Counseling

HELP PLEASE THIS IS URGENT!!!

HELP PLEASE THIS IS URGENT!!!

Answers

The neutron number of an atom X, which undergoes alpha, and beta decay reduces the neutron number by 6.  

Alpha decay is the nuclear process in which the parent nucleus emits an alpha or helium particle to form a daughter nucleus. When a particle emits an alpha nucleus, the nucleus loses its two protons and two neutrons. Beta decay is the nuclear process in which the parent nucleus undergoes the emission of electrons to produce a daughter nucleus.

Alpha decay decreases the atomic mass number decreases by 4 and the atomic number decreases by 2. In beta decay, the neutron is converted into a proton and the atomic number decreases by one. The neutron number is affected by alpha decay.

From the given,

X atom undergoes alpha decay. X -----> ₐ₋₂Xᵇ⁻⁴ + He₂⁴. The neutron number decreases by two.  ₐ₋₂Xᵇ⁻⁴ ----->    ₐ₋₂₋₂Xᵇ⁻⁴⁻⁴ + He₂⁴. The neutron number decreases by two.

When the X atom undergoes beta decay, ₐ₋₄Xᵇ⁻⁸---> ₐ₋₅Xᵇ⁻⁸ + ₋₁e⁰. The neutron number does not get affected. When the atom again undergoes alpha decay,  ₐ₋₅Xᵇ⁻⁸ ----->  ₐ₋₇Xᵇ⁻¹². Thus, the neutron number decreases by 6 when the atom undergoes three alpha decay.

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in an electroscope being charged by induction, what happens when the charging rod is moved away before the ground is removed from the knob?

Answers

The electroscope will remain charged and continue to show the presence of an electric charge if the ground is withdrawn from the knob before the charging rod is removed.


What is an electroscope?

An early scientific tool used to find electrical charge on a body is called an electroscope. The movement of a test object caused by the Coulomb electrostatic force is used to detect charge. Voltage and charge on an object are inversely correlated.

There are three traditional electroscope types: the needle electroscope, the gold-leaf electroscope, and the pith-ball electroscope (third).

electroscopes are utilized to determine whether a body has an electric charge. The movement of a test object caused by the Coulomb electrostatic force is used to detect charge. Voltage and charge on an object are inversely correlated.

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write state of matter with 5 example of each

Answers

There are broadly 3 states of matter (there are 5, but they don't teach 2 of them at school).

1. Solid

Examples: Iron, wood, steel, ice, paper

2. Liquid

Examples: Water, mercury, milk, soup, juice

3. Gas

Examples: Oxygen, Chlorine, Carbon dioxide, Sulphur dioxide, Nitrogen

5. You are driving at a constant speed of 35.0 m/s
when you pass a traffic officer on a motorcycle
hidden behind a billboard. One second after your
car passes the billboard, the traffic officer sets out
from the billboard to catch you, accelerating at a
constant rate of 3.0 m/s². How long does it take the
traffic officer to overtake your car?

Answers

The traffic cop needs 23.3 seconds to pass the automobile.

What is the acceleration of a car moving in a straight line at a constant speed?

When your velocity (not speed) changes, you are accelerating. A automobile moving at a steady 100 km/h in a straight line has no acceleration. Average acceleration is equal to (change in velocity) / (duration). The car's acceleration is zero because its change in velocity is also zero.

\(d1 = v1*t1 = 35.0 m/s * 1 s = 35.0 m\)

\(d = d1 = 35.0 m\)

\(d2 = v2*t + (1/2)at^2\)

\(d2 = (1/2)at^2\)

\(v2*t + (1/2)at^2 = (1/2)at^2\)

\(v2*t = (1/2)at^2\)

Solving for t, we get:

\(t = (2v2/a) = (235.0 m/s)/3.0 m/s^2 = 23.3 s\) (rounded to 2 decimal places)

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Choose all the right answers.

Each new cell produced by mitosis:

is different
inherits all the traits from its parent
obtains new traits
is identical to the parent's structure

Answers

Answer:

B and D

Explanation:

Answer:

It is B. inherits all the traits from its parent

And D. is identical to the parent's structure

Explanation:

Hope this helped have an amazing day!


In a ______ wave, particles
the medium move perpendicular
to the direction of the wave.

In a ______ wave, particlesthe medium move perpendicularto the direction of the wave.

Answers

Answer:

Transverse wave

Explanation:

I hope this helps you! :)

what exercises most beneficial for your overall health​

Answers

Answer:

Endurance, or aerobic

Strength, or resistance training

Balance

Flexibility

Explanation:

Answer:

Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).

Every exercise regimen should include both a warm-up and a cool down.


Please select the best answer from the choices provided.

Answers

Answer:

True

Explanation:

A child on roller skates undergoes as acceleration of 0.6m/s^2 due to a horizontal net force of 24N . What is the mass of the child?

Answers

Answer:

40Kg

Explanation:

F=m×a

24N÷0.6m/s^2=40

URGENTTTT
Referring to the graph in the section header, what was his displacement between 100 and 300 seconds?


Referring to the graph in the section header, what was the runner's velocity during segment D?

URGENTTTT Referring to the graph in the section header, what was his displacement between 100 and 300

Answers

The displacement of the runner according to the graph is obtained as 250 m.

What is the displacement?

The term displacement has to do with the distance that is covered in a specified direction. The difference between distance and displacement is that displacement is a vector while distance is a scalar quantity.

Thus we bring the direction into play when we are talking about the displacement of the object. Now we have a graph that shows the displacement of the runner in the vertical axis and then shows the time that is taken in the horizontal axis.

Given the graph as we have it, we can be bale to pick out the following from the graph;

1) Displacement of the runner at 100 s = 500 m

2) Displacement of the runner at 300 s = 750 m

Therefore;

Displacement of the runner between 100 and 300 seconds;

750 m - 500 m = 250 m

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During the 1960's and 1970's, the Apollo spacecraft took humans to the moon in 3 days. Traveling to Mars requires a trip of about 2 astronomical units in total. How long would this trip take, traveling at the same speed as to the moon?

Answers

Answer:

join my z o o m

Explanation:

Part 3: Energy Conversions 7. Record your data in the chart and include at least 5 potential-kinetic energy conversions shown in your device's construction. Example Item Description of potential-kinetic energy conversion Example Book The book had gravitational potential energy when it was on the table. Then as the book fell off the table, it was in motion and had kinetic energy. 1 2 3 4 5

Answers

Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.

Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.

As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.

Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.

As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.

Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.

Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.

Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.

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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m

Answers

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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A car has an acceleration of 4m/s squared. What will the increase in its velocity be after 2 seconds? If it started with a velocity of 30m/s, what is its final velocity?

Answers

A car has an acceleration of 4m/s squared. If it started with a velocity of 30m/s, 38m/s is its final velocity.

What is acceleration?

Acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight forward is accelerated when it accelerates or decelerates.

Even though the speed is constant, motion on a circle accelerates so because direction is always shifting. Both tangential to the acceleration for all other motions.

v = u + at

V= final velocity=?

U= initial velocity=  30m/s

a= acceleration = 4m/s²

substituting all the given values in the above equation, we get

v = 30+ 4× 2

V= 38m/s

Therefore,  38m/s  is its final velocity.

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An object of mass 2kg moves in circles at radius 8m at uniform speed of 30m/s calculate. A_angular velocity B_ceritripetal force

Answers

The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.

The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.

Calculation:-

A. angular velocity ω = v/r

                                     = 30 /8

                                      = 3.75 m/s

                                     

B. Centripetal force = mv²/r

                             = 2×30²/8

                              = 225 N

There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.

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A 0.20 mass on a horizontal spring is pulled back a certain distance and released. The maximum speed of the mass is measured to be 0.20 . If, instead, a 0.40 mass were used in this same experiment, choose the correct value for the maximum speed.
a. 0.40 m/s.
b. 0.20 m/s.
c. 0.28 m/s.
d. 0.14 m/s.
e. 0.10 m/s.

Answers

Answer:

d

Explanation:

Ya gon find the Kenitic Energy first

K=½mv²===> K=½×0.2×(0.2)²===> 0.1(0.04)===> 0.004

and now the replacement:

0.004=½×0.4V²====> v²=0.02===> V=0.14m/s

When u combine two or more atoms of different elements, u make an_

Answers

Answer: *a molecule.

Explanation: A molecule is the combination of two or more atoms

You make a molecule!

A rock is thrown directly upward from the edge of a flat roof of a building that is 56.3 meters tall. The rock misses the building on its way down, and is observed to strike the ground 4.00 seconds after being thrown. Neglect air resistance.

With what speed was the rock thrown?
How high did the rock travel in the reference frame of the thrower?

Answers

Explanation:

Given that,

Distance, d = -56.3 m

It strikes the ground 4.00 seconds after being thrown.

Using second equation of motion to find the speed was the rock thrown. So,

\(d=ut+\dfrac{1}{2}at^2\)

Here, a = -g

\(d=ut-\dfrac{1}{2}gt^2\\\\-56.3=u(4)-4.9(4)^2\\\\-56.3=4u-78.4\\\\u=5.52\ m/s\)

Let it will cover a distance of s meters. So,

\(s=\dfrac{v^2-u^2}{-2g}\\\\s=\dfrac{0^2-(5.52)^2}{-2\times 9.8}\\\\s=1.55\ m\)

precaution taken to ensure accuracy​

Answers

keep the decimals in the midst of calculatingtake it slow, because taking it fast leads to mistake which takes more time always check your work for each step to ensure no mistake in between steps

If there is gravity where the International Space Station (ISS) is located above Earth, why doesn’t the space station get pulled back down to Earth? Can we use this same concept for the Earth orbiting the Sun? Moon orbiting the Earth?

Answers

The ISS do not fall to Earth because it is moving forward at exactly the right speed that if it is  combined with the rate it is falling, due to gravity, produces a curved path that matches the curvature of the Earth.

Yes the same concept can be used for the  Earth orbiting the Sun and the Moon orbiting the Earth.

What is the International Space Station (ISS)?

The International Space Station is described as the largest modular space station in low Earth orbit and a  project that involves five space agencies: NASA, Roscosmos, JAXA, ESA, and CSA.

Therefore we can conclude that the gravity pulling satellites, the moon and all planetary objects towards the center of Earth is balanced by the centrifugal force pushing it out.

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suppose a hiker is on a mountain ridge 1200 meters above sea level. approximately what air pressure will she experience

Answers

Assuming standard atmospheric conditions, the air pressure at sea level is approximately 1013.25 hectopascals (hPa) or 1 atmosphere (atm). The air pressure decreases with altitude following the barometric formula, which states that pressure decreases by about 1 hPa for every 8 meters of ascent.

Using this formula, we can estimate the air pressure at 1200 meters above sea level as follows:

1200 m / 8 m per hPa = 150 hPa

Therefore, the hiker on a mountain ridge 1200 meters above sea level would experience an air pressure of approximately 863.25 hPa (1013.25 hPa - 150 hPa) or about 0.85 atm.

GUYS THIS IS URGENTTTTTT CAN YOU PLS ANSWER???
It takes a machine 90 seconds to do 54,000 J of work moving a conveyor belt. How much power is used to move the conveyor belt?

600 watts
540 watts
1.6 x 10-3 watts
4.8 x 106 watts

Answers

Answer:

600 watts is used to move the conveyor belt

During the photoelectric effect experiment, a photon is emitted with 9.60 x10-20 J of kinetic energy. If the work function of the photosensitive surface is 1.68 eV, which is the frequency of the incident light? (h = 6.626 x 10-34 J·s; 1 eV = 1.60 x 10-19 J)

Answers

According to the given statement  5.50 *  10¹⁴Hz is the frequency of the incident light.

What does the term "photoelectric effect" mean?

The photoelectric effect, which happens when light strikes a metal, can release electrons out of its surface. As the electrons that are expelled first from metal are known as emitted electrons, this process is also sometimes referred to as photoemission.

The following equation may be used to determine a photon's energy in terms of frequency:

E = hf

The work function must first be changed from electron volts (eV) to joules (J):

1 eV = 1.602 × 10⁻¹⁹ J

Hence, the work function is:

1.68 eV × 1.602 × 10⁻¹⁹ J/eV = 2.69 × 10⁻¹⁹ J

The emitted photon's kinetic energy is:

E = 9.60 × 10⁻²⁰ J

E = E0 + KE

where KE is the kinetic energy of the released electron and E0 is the work function.

Inputting the values, we obtain:

hf = E0 + KE

hf = 2.69 × 10⁻¹⁹ J + 9.60 × 10⁻²⁰J

hf = 3.65 × 10⁻¹⁹ J

When we solve for f, we obtain:

f = E/h = (3.65 × 10⁻¹⁹ J) / (6.626 × 10⁻³⁴ J s)

f = 5.50 × 10¹⁴ Hz

As a result, the incident light has a frequency of 5.50 *  10¹⁴Hz.

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24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.

Answers

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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What is the weight of a 20 kg sack of cement?

Answers

Answer:

20kg = 40kil

Explanation:

Multiply 2.5 cubic feet by 94 pounds yields 208 pounds per bag.

The weight of a 20 kg sack of cement is 29.6N.

HOW TO CALCULATE WEIGHT:

The weight of an object can be calculated by multiplying its mass by acceleration due to gravity. That is;

Weight (N) = mass (kg) × acceleration due to gravity (m/s²)

According to this question, a cement is of mass 20kg, the weight can be calculated as follows:

W = 20 × 9.8

W = 29.6N

Therefore, the weight of a 20 kg sack of cement is 29.6N.

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A sodium ion, Na+ , has a positive charge because it
A. gained an electron.
B. lost a proton.
C. gained a neutron.
D. lost an electron.

Answers

D. lost an electron

because they have free electron in the outermost shell which they will like to denote, in order to attain stable configuration

The skin keeps __________ and ________ out of the body

Answers

Answer:

stable bone

save from sun rays

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Read the excerpt below from the Yung Wing's book My Life in China and America published in 1909.Fortunately, three of us were old enough to lend a helping hand. My brother was engaged in fishing, my sister helped in housework, and I took to hawking candy through my own village and the neighboring one. I took hold of the business in good earnest, rising at three o'clock every morning, and I did not come home until six o'clock in the evening. My daily earnings netted twenty-five cents, which I turned over to my mother, and with the help given by my brother, who was the main stay of the family, we managed to keep the wolf away from our door. I was engaged in hawking candy for about five months, and when winter was over, when no candy was made, I changed my occupation and went into the rice fields to glean rice after the reapers. My sister usually accompanied me in such excursions. But unlike Ruth of old, I had no Boaz to help me out when I was short in my gleaning. But my knowledge of English came to my rescue. My sister told the head reaper that I could speak, read and write English. This awakened the curiosity of the reaper. He beckoned me to him and asked me whether I wouldn't talk some "Red Hair Men" talk to him. He said he never heard of such talk in his life. I felt bashful and diffident at first, but my sister encouraged me and said "the reaper may give you a large bundle of rice sheaf to take home." This was said as a kind of prompter. The reaper was shrewd enough to take it up, and told me that if I would talk, he would give me a bundle heavier than I could carry. So I began and repeated the alphabet to him. All the reapers as well as the gleaners stood in vacant silence, with mouths wide open, grinning with evident delight. A few minutes after my maiden speech was delivered in the paddy field with water and mud almost knee deep, I was rewarded with several sheaves, and I had to hurry away in order to get two other boys to carry what my sister and I could not lug. Thus I came home loaded with joy and sheaves of golden rice to my mother, little dreaming that my smattering knowledge of English would serve me such a turn so early in my career. I was then about twelve years old. Even Ruth with her six measures of corn did not fare any better than I did.Select the sentence that best identifies the purpose of the excerpt. I took hold of the business in good earnest, rising at three o'clock every morning, and I did not come home until six o'clock in the evening. I was engaged in hawking candy for about five months, and when winter was over, when no candy was made, I changed my occupation and went into the rice fields to glean rice after the reapers. He beckoned me to him and asked me whether I wouldn't talk some 'Red Hair Men' talk to him. Thus I came home loaded with joy and sheaves of golden rice to my mother, little dreaming that my smattering knowledge of English would serve me such a turn so early in my career. How many electrons can carbon accept from other atoms while bonding? (1 point)twosixeightfour 5y + 6 + 3y = 30show me how you get the answershow me your work pls PH = log[H ] Aeen is drinking a beverage that has a pH of 3. 3. Marien is drinking a beverage that has a pH of 2. 7. About how many times the hydrogen ion concentration of Aeens drink is the hydrogen ion concentration of Mariens drink? Round to the nearest whole number.