A car is driving at 88 kilometres an hour I’m Europe how fast is the car going in miles per hour. One kilometer = 0.62 mile.

Using the combination formula, the probability that a person with one combination of five numbers will win is:

\(\frac{1}{1,221,759}\)

\(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by:

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

For this problem, 5 numbers are taken from a set of 45, hence the number of combinations is:

\(C_{45,5} = \frac{45!}{5!40!} = 1,221,759\)

Hence the probability is:

\(\frac{1}{1,221,759}\)

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The expected value in a binomial situation with n = 18 and π = 0.60 is E(X) = np = 18 * 0.60 = 10.8.

In a binomial situation, the expected value, denoted as E(X), represents the average or mean outcome of a random variable X. It is calculated by multiplying the number of trials, denoted as n, by the probability of success for each trial, denoted as π.

In this case, we are given n = 18 and π = 0.60. To find the expected value, we multiply the number of trials, 18, by the probability of success, 0.60.

n = 18 (number of trials)

π = 0.60 (probability of success for each trial)

To find the expected value:

E(X) = np

Substitute the given values:

E(X) = 18 * 0.60

Calculate the expected value:

E(X) = 10.8

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Answer:

222 cups

Step-by-step explanation:

24*3=72

72*3=216

3*2=6

216+6=222

L = k/f, where k is the variational constant, is the formula for the inverse variation.

A mathematical relationship between two variables in which they vary in opposing directions is referred to as an inverse proportion, also known as an inverse relationship. When one variable increases while the other decreases, this is known as having inverse proportions.

Using the variables length of violin 'l' and frequency of vibration 'f'

If the length of violin 'l' is inversely proportional to the frequency of vibration 'f', this is expressed as:

l α 1/f

l = k/f

Hence the formula for the inverse variation is l = k/f where k is the constant of variation.

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Answer:

according to ur question..

ANSWER IS

.........................

................

...

XD.

Step-by-step explanation:

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I'm new here....

What is your question?

Answer:

yes, school is hard

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The more coins that are tossed for both gamblers, the less advantageous Gambler A is. But when a few coins are tossed, Gambler A will continue to hold a significant edge.

The binomial distribution;

In probability theory and statistics, the binomial distribution with parameters n and p is used to describe the discrete probability distribution of the number of successes in a set of n independent experiments.

Let X be the number of wins in the first n flips by A, Y be the signal that the last flip by A also wins, and Z be the number of wins in the n flips by B.

As Y is unrelated to X and Z, the following follows:

P(X + Y > Z) = P(Y = 1) P(X ≥ Z) + P(Y = 0) P(X > Z)

= 1/2(P(X = Z) + 2P(X > Z))

P(X > Z) = P(Z > X)

Here,

The less favorable Gambler A is, the more coins are tossed for both players. However, Gambler A will continue to have a sizable advantage even after a few coins are tossed.

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Answer:

y = 8

Step-by-step explanation:

for the triangles to be congruent, 2y + 20 must equal 36.

2y + 20 = 36

subtract 20 from each side of the equation:

2y = 16

divide both sides by 2:

y = 8

Answer:

9

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

9

The correct example of a discrete variable among the given options is the Number of customers who visited a store. The correct answer is option A.

Option A is an example of a discrete variable because the number of customers visiting a store can only take on whole numbers, such as 0, 1, 2, 3, and so on. It cannot have fractions or decimals. The variable is countable and has distinct, separate values. Each customer visit is a distinct event that can be counted.

In contrast, options B, C, and D involve variables that are continuous. Temperature levels can take on any value within a range and can include decimal points. The height of students can also vary continuously, as it can take on any value within a range, including fractions or decimals.

Similarly, the weight of newborn babies can vary continuously, as it can take on any value within a range, including fractions or decimals.

Therefore, among the given options, only the number of customers who visited a store represents a discrete variable.

Hence, option A is the correct answer.

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The equation for the hyperbola with foci (0,±5) and asymptotes y=± 3/4 x is:

y^2 / 25 - x^2 / a^2 = 1

where a is the distance from the center to a vertex and is related to the slope of the asymptotes by a = 5 / (3/4) = 20/3.

Thus, the equation for the hyperbola is:

y^2 / 25 - x^2 / (400/9) = 1

or

9y^2 - 400x^2 = 900

The center of the hyperbola is at the origin, since the foci have y-coordinates of ±5 and the asymptotes have y-intercepts of 0.

To graph the hyperbola, we can plot the foci at (0,±5) and draw the asymptotes y=± 3/4 x. Then, we can sketch the branches of the hyperbola by drawing a rectangle with sides of length 2a and centered at the origin. The vertices of the hyperbola will lie on the corners of this rectangle. Finally, we can sketch the hyperbola by drawing the two branches that pass through the vertices and are tangent to the asymptotes.

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*see attachment for diagram

Answer:

✔️m<BAC = 72°

✔️m<BCD = 108°

Step-by-step explanation:

Given:

m<ABC = (4x - 16)°

m<ACB = (5x + 7)°

Find the numerical value of m<ABC, m<ACB, m<BAC, and m<BCD.

First we need to determine the value of x.

The ∆ given is an isosceles triangle with two equal sides, therefore, the angles opposite the two equal sides would also be equal.

Therefore:

(4x - 16)° + 2(5x + 7)° = 180° (sum of ∆)

Solve for x

4x - 16 + 10x + 14 = 180

Add like terms

14x - 2 = 180

Add 2 to both sides

14x = 182

Divide both sides by 14

x = 13

Find the measure of each angle by plugging in the value of x where necessary:

✔️m<ABC = (4x - 16)° = 4(13) - 16

m<ABC = 36°

✔️m<ACB = (5x + 7)° = 5(13) + 7

m<ACB = 72°

✔️m<BAC = m<ACB (both are base angles of the isosceles ∆, so they are equal)

Therefore,

m<BAC = 72°

✔️m<BCD = m<ABC + m<ACB (exterior angle theorem of a triangle)

m<BCD = 36 + 72 (Substitution)

m<BCD = 108°

Therefore, the angle measures that are correct are:

✔️m<BAC = 72°

✔️m<BCD = 108°

Jada can buy approx. 4 bags of chips if each bag costs $0.99 and she also buys a bottle of soda.

Given, Jada has $6. She goes to the store and buys one bottle of soda for $1.20.

Each bag of chips cost $0.99

We have to find the number of chips bags she can buy,

as, she has $6 from which she spent $1.20 for a bottle of soda.

now she left with,

= 6 - 1.20

= $ 4.8

Now, as each chips bag is of $0.99

so, the number of chips bags she can buy are

= 4.8/0.99

= 4.84

So, she can buy approx. 4 bags of chips.

Hence, she can buy approx. 4 bags of chips if each bag costs $0.99 and she also buys a bottle of soda.

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A beam splitter is an optical device used to split an incident beam of light into two or more beams. A beam splitter with two input modes and two output modes is called a symmetric beam splitter.

When the input state is ∣20⟩, we must determine the output. We can use the given information to solve this problem.To solve this problem, we will use the following steps:

Step 1: Determine the unitary operator U for the symmetric beam splitter

We can use the information provided to determine the unitary operator U for the symmetric beam splitter.

The input state ∣10⟩ produces an output \(U^∣10⟩=2​1​(∣10⟩+i∣01⟩)\) where U is the unitary operator.

We can rearrange this expression to get U^∣10⟩=2​1​∣10⟩+i2​1​∣01⟩.

Since the beam splitter is symmetric, it must be the case that U∣01⟩=2​1​(∣10⟩+i∣01⟩).

We can use this expression to find U:

\(U^∣01⟩=2​1​(∣10⟩+i∣01⟩)Ua^2†​U^†=2​1​(a^1†​+ia^2†​)U^∣01⟩=2​1​(a^1†​+ia^2†​)\)

Since a^1†​=∣10⟩ and a^2†​=∣01⟩, we can substitute these expressions into the above equation to get:

U^∣01⟩=2​1​(∣10⟩+i∣01⟩)U^|01> = 1/√2(|10⟩ + i|01⟩)

Step 2: Calculate the output for the input state ∣10⟩

Using the expression for U^ from step 1, we can calculate the output for the input state ∣10⟩.U^∣10⟩=2​1​(∣10⟩+i∣01⟩)U^|10> = 1/√2(|10⟩ + i|01⟩)∣10⟩ is an eigenstate of the symmetric beam splitter, so the output for this input state is simply ∣10⟩.

Therefore, the output for ∣10⟩ is 1/√2(|10⟩ + i|01⟩)

Step 3: Use the output from step 2 to calculate the output for the input state ∣20⟩

We can use the superposition principle to calculate the output for the input state ∣20⟩.

Since ∣20⟩ = ∣10⟩ ⊗ ∣10⟩, we can write the input state as:

∣20⟩ = ∣10⟩ ⊗ ∣10⟩The output state for ∣20⟩ is given by:

U^∣20⟩=U^∣10⟩ ⊗ U^∣10⟩=1/2(|10⟩ + i|01⟩) ⊗ 1/2(|10⟩ + i|01⟩)=1/4(|10⟩⊗|10⟩ + i|10⟩⊗|01⟩+ i|01⟩⊗|10⟩ - |01⟩⊗|01⟩)Therefore, the output for ∣20⟩ is 1/4(|10⟩⊗|10⟩ + i|10⟩⊗|01⟩+ i|01⟩⊗|10⟩ - |01⟩⊗|01⟩).

Therefore, the output for the input state ∣20⟩ is 1/4(|10⟩⊗|10⟩ + i|10⟩⊗|01⟩+ i|01⟩⊗|10⟩ - |01⟩⊗|01⟩).

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The solution to the system of equations is (-2, 3)

Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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An unnormalized relation refers to a table in a relational database that contains more than one row. This means that there are duplicate rows in the table, which violates the rules of normalization.

Normalization is a process in database design that aims to eliminate data redundancy and ensure data integrity. It involves breaking down a database into multiple tables and defining relationships between them. By doing so, we can efficiently store and retrieve data while minimizing inconsistencies.

In an unnormalized relation, duplicate rows can lead to various problems. For example, it can result in data inconsistencies, as updating one instance of a row may not reflect changes in other duplicate rows. Additionally, it can cause unnecessary storage and maintenance overhead.

To normalize an unnormalized relation, we need to identify the functional dependencies in the table and create separate tables for related data. This helps organize the data and reduces redundancy.

In summary, an unnormalized relation is a table in a relational database that has duplicate rows. It is important to normalize such relations to ensure data integrity and efficiency.

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The probability of none of the graduates having a summer job is 0.262, which is calculated using the binomial probability distribution.

The probability of none of the graduates having a summer job can be calculated by using the formula of a binomial probability distribution. The formula is P(x) = nCx * p^x * q^(n-x). In this case, n represents the number of graduates, x represents the number of successes, p is the probability of success, and q is the probability of failure.

For this example, n = 6, x = 0, p = 0.2 (the probability of a graduate having a summer job is 0.2), q = 0.8 (the probability of a graduate not having a summer job is 0.8).

Plugging these values into the formula, we get P(x) = 6C0 * 0.2^0 * 0.8^6 = 0.262. Therefore, the probability of none of the graduates having a summer job is 0.262.

Therefore, The probability of none of the graduates having a summer job is 0.262, which is calculated using the binomial probability distribution. This is calculated by using the formula P(x) = nCx * p^x * q^(n-x), where n = 6, x = 0, p = 0.2 and q = 0.8.

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If a group of 6 graduates is selected at random, what is the probability that none of the graduates have a summer job assuming a binomial distribution?

Answer:

WX = 18

Step-by-step explanation:

given Δ V'W'X'  is \(\frac{2}{3}\) of Δ VWX , then the sides of Δ VWX are \(\frac{3}{2}\) of Δ V'W'X'

WX = \(\frac{3}{2}\) × W'X' = \(\frac{3}{2}\) × 12 = 3 × 6 = 18

We have:tan^(-1)(1/11) + tan^(-1)(5/6) + tan^(-1)(1/3) + tan^(-1)(1/2) = tan^(-1)(7/2)

To prove the equation tan^(-1)(1/11) + tan^(-1)(5/6) + tan^(-1)(1/3) + tan^(-1)(1/2) without using a calculator, we can utilize the trigonometric properties and identities to simplify the expression.

Let's start by using the addition formula for the tangent function:

tan(A + B) = (tan(A) + tan(B)) / (1 - tan(A) * tan(B))

We can rewrite the given expression as:

tan^(-1)(1/11) + tan^(-1)(5/6) + tan^(-1)(1/3) + tan^(-1)(1/2)

Using the addition formula, we can combine the first two terms:

tan^(-1)(1/11) + tan^(-1)(5/6) = tan^(-1)((1/11 + 5/6) / (1 - (1/11)*(5/6)))

Simplifying further:

tan^(-1)(1/11) + tan^(-1)(5/6) = tan^(-1)((11/66 + 55/66) / (1 - 5/66))

tan^(-1)(1/11) + tan^(-1)(5/6) = tan^(-1)(66/66 / (61/66))

tan^(-1)(1/11) + tan^(-1)(5/6) = tan^(-1)(1)

Using the same approach, we can combine the remaining terms:

tan^(-1)(1/3) + tan^(-1)(1/2) = tan^(-1)((1/3 + 1/2) / (1 - (1/3)*(1/2)))

tan^(-1)(1/3) + tan^(-1)(1/2) = tan^(-1)((5/6) / (3/2))

tan^(-1)(1/3) + tan^(-1)(1/2) = tan^(-1)(5/9)

Now, we have:

tan^(-1)(1/11) + tan^(-1)(5/6) + tan^(-1)(1/3) + tan^(-1)(1/2) = tan^(-1)(1) + tan^(-1)(5/9)

Using the addition formula again:

tan^(-1)(1) + tan^(-1)(5/9) = tan^(-1)((1 + 5/9) / (1 - (1)*(5/9)))

tan^(-1)(1) + tan^(-1)(5/9) = tan^(-1)((14/9) / (4/9))

tan^(-1)(1) + tan^(-1)(5/9) = tan^(-1)(14/4)

tan^(-1)(1) + tan^(-1)(5/9) = tan^(-1)(7/2)

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Answer: distance 1min = 10in

In 1 minute the snail travels 10 inches  

In 2 minute the snail travels 20 inches

In 3 minute the snail travels 30 inches

In 4 minute the snail travels 40 inches

In 5 minute the snail travels 50 inches

y=10x

The amount in the account 31.00 years from today would be approximately $2,990,040.02.

To calculate the future value of annual deposits, you can use the formula for the future value of an ordinary annuity:

Future Value = Payment * [(1 + interest rate)^(number of periods) - 1] / interest rate

Given:

Payment = $5,171.00 per year

Interest rate = 12.00%

Number of periods = 15.00 years

First, let's calculate the future value of the deposits after 15 years:

Future Value = $\(5,171.00 * [(1 + 0.12)^(15) - 1] / 0.12\)

Future Value = $5,171.00 *\((1.12^15 - 1) / 0.12\)

Future Value = $5,171.00 * (4.040609 - 1) / 0.12

Future Value = $5,171.00 * 3.040609 / 0.12

Future Value = $131,525.53

Now, we need to calculate the future value of this amount after an additional 31 years:

Future Value = $131,525.53 * \((1 + 0.12)^(31)\)

Future Value = $131,525.53 * \(1.12^31\)

Future Value = $131,525.53 * 22.737542

Future Value = $2,990,040.02

Therefore, the amount in the account 31.00 years from today would be approximately $2,990,040.02.

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Derek will deposit $5,171.00 per year for 15.00 years into an account that earns 12.00% Assuming the first deposit is: made 400 years from today, how much will it be in the account 31.00 years from today?

Answer:

The blue point is at -15.

Step-by-step explanation:

It's counting by 3's. 3, 6, 9, 12, 15...

Step-by-step explanation:

t=d/r

......................

Complete question is;

Identify the sampling technique used, and discuss potential sources of bias (if any). Explain. After a hurricane, a disaster area is divided into 200 equal grids. Thirty of the grids are selected, and every occupied household in the grid is interviewed to help focus relief efforts on what residents require the most.

Answer:

A) Cluster Sampling

B) Non - response bias.

Step-by-step explanation:

A) There are different sampling techniques such as:

-Convenience Sampling

-Cluster Sampling

-Systematic random Sampling

-Simple random Sampling

-Stratified random Sampling

Now, the most appropriate type used would be Cluster sampling. Cluster sampling is defined as a sampling technique that divides the samples into clusters or non - overlapping sub-groups and some of these clusters will be in the sample.

So from the question, the disaster area has been divided into 200 equal grids. This 200 grids can also be referred to as clusters or non overlapping subgroups. They are also included in the sample being interviewed. Thus, it's clearly a cluster sampling technique that was used.

B) There are different sources of bias such as;

- Undercoverage bias

- Response bias

- Non - response bias.

The most likely potential source of bias will be non response bias. This source of bias arises when the data/results of some people in the sample are not provided.

In the question, it's very possible that some people in the sample may not be willing to provide answers to the interview questions. Thus there is a high possibility of non - response bias.

Using the SAS(Side-Angle-Side) Theorem, ASA(Angle-Side-Angle) Theorem, SSS(Side-Side-Side) Theorem and AA(Angle-Angle) Theorem we can easily prove that two triangles are similar.

If two triangles have an equal number of comparable angles and sides, they are said to be similar.

Similar figures are items that have two or more figures with the same shape but varying sizes.

Using the SAS(Side-Angle-Side) Theorem, ASA(Angle-Side-Angle) Theorem, SSS(Side-Side-Side) Theorem and AA(Angle-Angle) Theorem we can easily prove that two triangles are similar.

A portion on one polygon must correspond perfectly to a part in another polygon that is in a similar place. Even though two triangles are oriented differently from one another, you can conclude that their angles match if you can spin them to align in the same direction and notice that their angles are similar.

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