A car increases its velocity from zero to 97 km/h in 8.4 s. What is its acceleration?
Answers
Answer:
\(a=\frac{v-u}{t}\)
\(v=\)final velocity =97km/h(change to m/s) =26.9m/s NEVER FORGET TO DO THAT BECAUSE TIME IS GIVEN IN SECONDS
\(u=\)initial velocity 0 m/s
\(t=\)time 8.4s
\(a=\frac{26.9-0}{8.4}\)
\(a=\) \(3.2m/2^{2}\)
Related Questions
how much does a change in mass affect the kinetic energy of two balls of comparable diameter?
Answers
Answer:
Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.
In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.
Un camion de envios se encuentra detenido en una señal de pare, permitiendo que pase una ambulancia. Inicia su recorrido y al cabo de 15 segundos alcanza una velocidad de 40 km/h esta se mantiene constante drante 20 s, observa una señal de pare y se detiene 8s despues ¿cual es la aceleracion del camion en el primer intervalo de tiempo?
Answers
Answer:
\(0.741\ \text{m/s}^2\)
Explanation:
v = Velocidad final = \(40\ \text{km/h}=\dfrac{40}{3.6}\ \text{m/s}\)
u = Velocidad inicial = 0
t = Tiempo empleado = 15 s
a = Aceleración
De las ecuaciones cinemáticas tenemos
\(v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{40}{3.6}-0}{15}\\\Rightarrow a=0.741\ \text{m/s}^2\)
La aceleración del camión en el primer intervalo de tiempo es \(0.741\ \text{m/s}^2\).
The volume of a plastic covered sealed box is 350 cm³ and the box has a mass 500 g will the box float on water or sink on water. What will the mass of water displaced by the box?
Answers
Answer:
Density= 1.43 g/cm^3. Mass of water displaced= 500 g
Explanation:
The density of the box is 1.43 g/cm^3 thus, it would float.
mass of water displaced is equal to mass of object. therefore the mass of water displaced by the box is 500g.
If your engine is flooded with gasoline, you should push the accelerator to the floor and hold for:_______.
Answers
You should push the accelerator all the way to the floor and hold for five seconds if your engine is flooded with gasoline.
To find the answer, we need to know about the flooded engine.
What is flooded engine?An engine that is flooded is one that has too much fuel in the vehicle and insufficient airflow.The signs of a flooded engine include difficulty starting the engine, car engine failure after only a few feet, black smoke, and unusual engine noise. We can solve the issue in different ways.In the right manner, push the accelerator or gas pedal all the way to the ground. You must open the car's throttle and let the engine's air flow before depressing the gas pedal.Thus, we can conclude that, You should push the accelerator all the way to the floor and hold for five seconds if your engine is flooded with gasoline.
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When two vehicles collide, momentum is conserved _______.a)if the collision is elasticb)only if deformation of either vehicle does not occur.c)if the collision is inelastic.d)whether the collision is elastic or inelastic.
Answers
When two vehicles collide, momentum is conserved whether the collision is elastic or inelastic. Option D is correct.
Momentum conservation is a fundamental principle of physics that states that the total momentum of a system is conserved if no external forces are acting on the system. In other words, the total momentum of a system before a collision is equal to the total momentum of the system after the collision.
This applies regardless of whether the collision is elastic or inelastic. In an elastic collision, both kinetic energy and momentum are conserved. In an inelastic collision, some kinetic energy is transformed into internal energy, causing the objects to deform or stick together, but the total momentum is still conserved.
Hence option D is correct.
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what is a radio active element
Answers
A radioactive element, also known as a radionuclide or radioisotope, is an element that exhibits radioactivity.
Radioactive elements are the elements that have an unstable nucleus and emit radiation when their nucleus undergoes a process called radioactive decay. Radioactive decay is a random process that occurs in some of the elements with unstable atomic nuclei.
During this process, the nucleus emits alpha, beta, or gamma particles, which transform the nucleus into a more stable state. As a result, these elements are radioactive and can release high-energy particles or electromagnetic waves in the form of radiation, which can be dangerous for living organisms. Radioactive elements are mainly classified into two types: natural radioactive elements and artificially produced radioactive elements.
Natural radioactive elements are those that occur in nature, and their nuclei naturally undergo radioactive decay. For example, Uranium, thorium, and radium are natural radioactive elements. The artificially produced radioactive elements are those that are synthesized through nuclear reactions in a laboratory. For example, technetium and plutonium are artificially produced radioactive elements.
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proof the equation of motion third
Answers
The proof of third equation of motion is determined as v² = 2as + u².
What is the proof of third equation of motion?
The proof of third equation of motion is determined as follows;
The first equation is given as;
v = u + at
t = ( v - u ) /a
where;
u is the initial velocitya is the accelerationt is the time of motionThe formula for the average distance traveled by an object is;
s = (v + u)/2 x t
Expand the equation above as;
s = (v + u)/2 x (v - u)/a
s = (v² - u²) / 2a
2as = v² - u²
v² = 2as + u², proved
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Imagine a sphere of gas of density rho0 and radius R0, with magnetic field of strength B0 running through it along the z direction. What is the mass M of the sphere, and what is the flux Φ crossing through it?
Answers
The mass of the sphere is M = (4/3)πR₀³ρ₀, and the flux crossing through the sphere is Φ = B0πR₀².
The mass M of the sphere is given by M = (4/3)πR₀³ρ₀, where ρ₀ is the density of the gas and R₀ is the radius of the sphere.
The flux Φ crossing through the sphere is given by Φ = B0πR₀², where B0 is the strength of the magnetic field and R0 is the radius of the sphere.
This problem can be solved by using the formulae for the mass and flux of a spherical object. The mass of a spherical object is given by the formula M = (4/3)πR³ρ, where R is the radius of the sphere and ρ is its density. In this case, the radius of the sphere is R₀ and the density of the gas isρ₀.
The flux crossing through a surface of area A in a uniform magnetic field of strength B is given by the formula Φ = BA. In this case, the sphere has a circular cross-section of area πR₀² and the magnetic field has a strength of B₀ along the z direction.
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At the top of the loop, what is the magnitude of the force exerted on a 65 kg rider by the roller-coaster seat?
Answers
The magnitude of the force exerted on the 65 kg rider by the roller-coaster seat at the top of the loop is approximately 3697.34 N.
What is force?Force is defined as the influence that causes an object to undergo a change in motion or shape.
Force is a vector quantity, which means it has both magnitude and direction. Its SI is Newton (N).
At the top of a loop, the rider of a roller-coaster experiences a downward acceleration due to gravity (9.81 m/s²) and a centripetal acceleration towards the centre of the loop. The magnitude of the force exerted on the rider by the roller-coaster seat is the sum of the gravitational force and the centripetal force required to keep the rider moving in a circular path at the top portion of the rollercoaster loop.
With a radius of curvature of 6.4 meters for the loop, the speed of the rider at the top of the loop can be calculated using the conservation of energy, which states that the sum of kinetic energy and potential energy remains constant. At the top of the loop, all the rider's potential energy has been converted to kinetic energy, so:
mgh = 1/2mv²
Where m is the mass of the rider (65 kg), g is the acceleration due to gravity (9.81 m/s²), h is the height of the loop (which is the same as the radius of curvature, 6.4 meters), and v is the speed of the rider.
Solving for v:
v = \(\sqrt{2gh}\) = \(\sqrt{2*9.81*6.4}\) = 11.20 m/s
The centripetal force required to keep the rider moving in a circular path at this speed can be calculated using the formula:
F = mv² / r
Where F is the force, m is the mass of the rider, v is the speed of the rider, and r is the radius of curvature of the loop. Substituting the values:
F = (65 kg) x (19.08 m/s)² / 6.4 m = 3697.34 N
Therefore, the magnitude of the force exerted on the 65 kg rider by the roller-coaster seat at the top of the loop is approximately 3697.34 N.
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Select the correct answer.
Which of these is described as force per unit charge on a positive test charge?
А.test charge
B.source charge
C.electric force
D. electric field
E.electric current
Answers
Answer:
I'm not ASTRO physicist but an electro field is where I put my bets on
Explanation:
could be wrong
Which of the following is most likely to make it safer while lighting the rocket?
A. decreasing the size of the cap
B. increasing the length of the fuse
C. increasing the length of the body
D. decreasing the length of the stick
Answers
While lighting the rocket you should ensure D) decreasing the length of the stick
What are the precautions you should take while lighting the rocket?When lighting fireworks, avoid holding them in your hand or placing any part of your body over them. Don't carry fireworks in your pocket since the friction could set them off; instead, use eye protection. Keep pyrotechnics away from flammable objects, such as brush, leaves, and dwellings.
The continuous smoke from cracker explosions may sting or wet the eyes. Because bottle rockets are thought to be the riskiest cracker type, it's crucial to avoid them, keep a safe distance from the burning crackers, wear safety goggles, and avoid wearing contact lenses while popping crackers.
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A student with mass 50 kg is standing in a canoe (with mass of 30 kg) in still water. The student
then jumps out of the canoe to the right with a speed of 1.5 m/s. The initial velocity of the canoe
IS
Select one:
A 1.5 m/s to the left.
B.2.5 m/s to the left.
C. 0. The canoe does not move.
D.2.5 m/s to the right
Answers
Answer:
B
Explanation:
your answer is B. 2. 5 m/s to the left
A student with a mass of 50 kg is standing in a canoe the initial velocity of the canoe is 2.5 m/s to the left. The correct option is option (B).
Given that the mass of the student is 50 kg, the mass of the canoe is 30 kg, and the velocity of the student is 1.5 m/s to the right, we can calculate the velocity of the canoe.
Before the jump, the total momentum is the sum of the momentum of the student and the momentum of the canoe, since they are initially at rest.
Total momentum before the jump = (mass of the student + mass of the canoe) × (initial velocity)
= (50 + 30) × 0 = 0
After the jump, the total momentum is the sum of the momentum of the student and the momentum of the canoe.
Total momentum after the jump = mass of the student × velocity of the student + mass of the canoe × velocity of the canoe
Total momentum after the jump = (50 × 1.5) + (30 × velocity of the canoe)
0 = (50 × 1.5) + (30 × velocity of the canoe)
-75 = 30 × velocity of the canoe
velocity of the canoe = -75 / 30 = -2.5 m/s
Therefore, the initial velocity of the canoe is 2.5 m/s to the left. Hence, the correct option is (B).
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define unit aland how many types of unit are there . Name them?
Answers
Answer:
7. They arethe meter (m), the kilogram (kg), the second (s), the kelvin (K), the ampere (A), the mole (mol), and the candela (cd)
Explanation:
7. They arethe meter (m), the kilogram (kg), the second (s), the kelvin (K), the ampere (A), the mole (mol), and the candela (cd)
A piano has a mass of 99 kg. What is the weight of the piano?
A. 1030 N
B. 842 N
C. 1129 N
D. 970 N
Help!!
Answers
Answer:
\(D.\ 970\ N\)
Explanation:
Given:
Mass of Piano: 99kg
Required:
Calculate its weight
The weight of an object is calculate as thus;
\(Weight = Mass\ (m) * Acceleration\ due\ to\ gravity\ (g)\)
\(m = 99kg\) and \(g = 9.8m/s^2\)
The formula becomes
\(Weight = 99kg * 9.8m/s^2\)
\(Weight = 970.2\ kgm/s^2\)
\(Weight = 970.2\ N\)
\(Weight = 970\ N\) Approximated
Hence, the weight of the piano is 970N
How does convection current helps cooling the system of engines
Answers
Hope this helps!
Experiment 1: Exploring Charge with Scotch® Tape
In this experiment, you will observe the behavior of charged objects using pieces of Scotch® tape.
Materials
Scotch® Tape
Ruler
*Pen
*Flat Work Surface
Procedure
Part 1
1. Use the ruler to measure a piece of tape that is 10 cm long.
2. Tear the tape to remove the 10 cm piece from the roll.
3. Create a "handle" on one side of the piece of tape by folding down the piece of tape 1 cm from the end, leaving a 9 cm sticky piece with a 1 cm handle.
4. Stick the entire sticky surface of the tape to a table top, counter top, or another flat surface.
5. Repeat Steps 1 – 4 with a second 10 cm piece of tape. Stick the second piece of tape at least 15 cm away from the first piece on the same surface.
6. Quickly pull off both strips of tape from the surface and ensure that the pieces do not touch.
7. Carefully bring the non-sticky sides of the tape together and record observations about the behavior of the pieces in Table 1.
8. Discard the tape.
Part 2
1. Use the ruler to measure a piece of tape that is 10 cm long.
2. Tear the tape to remove the 10 cm piece from the roll.
3. Create a "handle" on one side of the piece of tape by folding down 1 cm of tape from one end.
4. Stick the entire sticky surface of the tape to a table top, counter top, or another flat surface.
5. Use a pen and write "B1" on the tape. "B" stands for bottom.
6. Repeat Steps 1 – 4 with a second 10 cm piece of tape. This time, press the second strip of tape on top of the one labeled "B1".
7. Use the pen to label the top piece with a "T1". "T" stands for top.
8. Create a second pair of pieces of tape by repeating Steps 1 – 7. This time, label the bottom piece "B2" and the top piece "T2".
9. Use the T1 handle to quickly pull off T1 strip of tape from the flat surface.
10. Use the B1 handle to peel off the bottom strip from the flat surface. Keep both B1 and T1 pieces away from each other.
11. Bring the non-sticky sides of B1 and T1 together and record observations about the behavior of the pieces in Table 1.
12. Set the pieces of tape, non-sticky side down, on the table approximately 15 cm away from each other. Do not stick them back on the table!
13. Repeat Steps 9 - 12 for B2 and T2.
14. Carefully bring the non-sticky sides of piece "T1" and "B2". Record observations about the behavior of the pieces in Table 1.
15. Set them back down, non-sticky side down.
16. Repeat Steps 14 - 15 for "T1" and "T2". Record your observations in Table 1.
17. Repeat Steps 14 - 15 for "B1" and "B2". Record your observations in Table 1.
18. Repeat Steps 14 and 15 for "T1" and the hair on your leg or arm. Record your observations in Table 1.
19. Repeat Steps 14 and 15 for "B1" and the hair on your leg or arm. Record your observations in Table 1.
Table 1: Electric Charge Observations
procedure
interacting pieces observation
Part 1 Two pieces on table Part 2 T1 / B1 T2 / B2 T1 / B2 T2 / B1 B1 / B2 T1 / Arm Hair B1 / Arm Hair ***The observation is filled.
Post-Lab Questions
1. Describe the interaction between the top and bottom strips as they relate to electric charge. Did the behavior of the pieces change when the tape was from different sets?
2. Describe the interaction between two top and two bottom pieces of tape as they relate to electric charge. Is this consistent with the existence of only two types of charge? Use your results to support your answer.
3. Did the top tape attract your arm hair? Did the bottom tape attract your arm hair? Usually arm hair is neutral; it has equal number positive and negative charges. Use this information to explain your results.
4. Which pieces of tape are positively charged? Which pieces of tape are negatively charged? Explain your reasoning.
5. Use your data to create a rule describing how like charges, opposite charges, and neutral bodies interact.
6. What do you observe about the force of attraction or repulsion when the pieces of tape are closer together and farther apart? Does this change happen gradually or quickly?
Answers
1.When the non-sticky sides of the two pieces of tape recording are brought together, they repel each other. This is due to the buildup of electric charge on the face of the tape recording when it was hulled off from the flat face.
2.The pieces didn't change when the tape recording was from different sets. When two top or two nethermost pieces of tape recording are brought together, they repel each other.
3.When a top and nethermost piece of tape recording are brought together, they attract each other. This is harmonious with the actuality of only two types of charge, positive and negative. The results support the fact that the top and nethermost pieces of tape recording had contrary charges. The top tape recording attracted the arm hair, while the bottom tape recording didn't attract the arm hair. Arm hair is generally neutral, but it can be concentrated by the electric field of the charged tape recording.
4.The top tape recording is negatively charged, and it concentrated the arm hair, which has a positive charge. This redounded in magnet between the top tape recording and the arm hair. The pieces of tape recording labeled" T1" and" B2" are appreciatively charged, while the pieces of tape recording labeled" B1" and" T2" are negatively charged. This can be determined from the compliances.
5.When the appreciatively charged tape recording was brought near to a negatively charged tape recording, they attracted each other. When two appreciatively charged videotapes or two negatively charged videotapes were brought near together, they repelled each other. Like charges repel each other, contrary charges attract each other, and neutral bodies aren't affected by electric fields.
6.The force of magnet or aversion between the pieces of tape recording increases as they get near together and decreases as they move further piecemeal. This change happens gradationally, not snappily.
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Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. He turned the car one more time and went 35 meters east. His car was 15 meters from the starting line. This took 5 seconds.
What is the car’s velocity?
Answers
Answer:
3 m/s east
Explanation:
I took a test a got it right
Answer:
3 m/s east
Explanation:
50 points for correct answer.
Answers
Un ladrillo de 2kg que se encuentra a 200º c, se sumerge en 5 kg de agua a 32º¿a que temperatura se alcanza el equilibrio térmico?
Answers
Answer:
El equilibrio térmico se alcanzará a los 152ºC.
Explanation:
Dado que un ladrillo de 2kg que se encuentra a 200º c, se sumerge en 5 kg de agua a 32º, para determinar a qué temperatura se alcanza el equilibrio térmico se debe realizar el siguiente cálculo:
2+5 = 7
(200 x 5 + 32 x 2) / 7 = X
1064 / 7 = X
152 = X
Por lo tanto, el equilibrio térmico se alcanzará a los 152ºC.
This equation goes with which law?
Answers
Answer:
I think that's Newton's second law of motion
Explanation:
f = m(v-u)
________
t
since a = (v-u)t
f = ma
Explain why the car in the photograph would get hot on a sunny day. How will the sunshield help to keep the car cool?
Answers
it will avoid the sun rays from penetrating into the glass to make it hot,and even fall on the seat and burn
Explanation:
Because of the type of metal it was made with
Answer:
The car gets hot in the photograph because of greenhouse effect. Most noticeably the fact that the sunlight enters the car through the windows to heat up the inside surfaces, which then gets trapped inside the car, causing a buildup of temperature.
Sunscreen can help keep the car cool by reflecting the sunlight, which in turn reduces the amount of heat that enters the car. This also decreases the inside surfaces to the exposure of UV lights.
John walks to the pizza place for lunch. He walks 2 km north, then 1 km east. To get home, he walks 2 km west and 1 km south. What distance did he travel? What is his displacement?
Answers
Answer:
The total distance covered is 3 km and the displacement is 2.24 km.
Explanation:
For the total distance covered by Anthony, we just add all of the distances.
1 km (going east) + 1 km (going east again) + 1 km (going south) = 3 km
Hence, the his total distance covered when he went to the pizza place is 3 km.
Solving for the displacement is a different matter. We cannot just add all of the distances. From analysis of the problem, Anthony traveled and formed a right triangle. He traveled 1 km east twice, making it 2 km east in total, then he traveled 1 km south.
When dealing with a right triangle with 2 sides given (for this problem the two sides are the 2 km east and the 1 km south), we use the Pythagorean Theorem.
Solution:
c² = a² + b² (Pythagorean Theorem)
c will be the longest side of the right triangle
a and b will be the other sides of the right triangle
c = √ (a² + b²)
c = √ (2² km + 1² km)
c = √5 km
c = 2.2361 km ≈ 2.24 km
Therefore, the displacement of Anthony is 2.24 km.
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a machine has mechanical advantage 2 , what does it mean ?
Answers
Answer:
The advantage gained by the use of a mechanism in transmitting force specifically : the ratio of the force that performs the useful work of a machine to the force that is applied to the machine.
Explanation:
0.5 times greater than the input force.
Select the correct answer.
What happens to the acceleration of an object if the net force on it increases?
ОА. .
The acceleration increases.
OB.
The acceleration decreases.
Ос.
The acceleration becomes zero.
OD
The acceleration remains the same.
Answers
Answer:
A
Explanation:
According to Newton's second law, acceleration is directly proportional to the net force. As the acceleration increases (when mass is constant), the net force increases. This is represented in the following formula.
\(f = ma\)
\(a = \frac{f}{m} \)
a = acceleration
f = force
m = mass
The solar wind is highly ionized plasma. Throughout its trajectory, it presents variations in temperature, density, pressure and speed, mainly due to the presence of eruptive phenomena such as Coronal Mass Ejections (CME). Assuming that on its journey between the Sun and the Earth (150X10^6 km), the temperature (1.3X10^5 K) and speed (450 km/s) remain constant. What kind of fluid is it? When an EMC is generated, the temperature (10^7 K) and the speed of the Solar Wind (10^3 km/s) increase and assuming that this increase remains constant along the same trajectory, what type of fluid will be the Solar Wind thanks to this disturbance?
laminar fluid <2100
transition 2,100-4,000
turbulent fluid >4000
Re=(Velocity)(Length)/ VISCOSITY
calculate the viscosity depending on the temperature
and explain in words the solution of the problem.
Answers
The solar wind, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, is a highly ionized plasma.
Due to the increase in temperature (10^7 K) and speed (10^3 km/s) during a Coronal Mass Ejection (CME), the solar wind becomes a turbulent fluid.The solar wind, which is a stream of charged particles (plasma) emitted by the Sun, exhibits characteristics of a highly ionized plasma. As it travels from the Sun to the Earth, the solar wind encounters variations in temperature, density, pressure, and speed. In this case, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, the solar wind can be classified as a highly ionized plasma.
During a Coronal Mass Ejection (CME), eruptive phenomena on the Sun's surface cause a sudden release of a large amount of plasma and magnetic fields into space. This disturbance leads to an increase in the temperature of the solar wind to around 10^7 K and an increase in its speed to approximately 10^3 km/s. This enhanced energy and velocity result in a significant disruption of the solar wind's flow, making it a turbulent fluid.
Turbulent fluids are characterized by chaotic and irregular motion, with strong fluctuations and mixing. The increased temperature and speed during a CME generate turbulent behavior within the solar wind, leading to the disruption and mixing of plasma particles along its trajectory.
To determine the type of fluid flow, the Reynolds number (Re) is often used. It relates the flow's characteristics, such as velocity and length, to the fluid's viscosity. In this case, since the solar wind is a plasma and has negligible viscosity, the Reynolds number is extremely high, well above the turbulent threshold of 4000. Therefore, the solar wind with increased temperature and speed due to a CME can be classified as a turbulent fluid.
In summary, the solar wind, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, is a highly ionized plasma. However, during a Coronal Mass Ejection (CME), the temperature and speed of the solar wind increase significantly, leading to turbulent fluid behavior.
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Can someone explain what ice jacking is and how it can cause structures to fail?
Answers
Answer: Rock slope failures can occur due to the presence of water; ice jacking occurs when water between joint or fissure surfaces freezes and expands. This type of failure is progressive, resulting in incremental weakening over time, often requiring several cycles before failure. Ice jacking is one form of rock erosion.
Around the time that _______ burning finishes, the inert core of ________ in very massive stars will collapse and the star will explode as a supernova.
Answers
The Sun can explode in a supernova. Around the time that sun (massive star) burning finishes, the inert core of Iron in very massive stars will collapse and the star will explode as a supernova.
When the sun explode, their inert iron cores often collapse into an extremely dense neutron star.
In a massive star, hydrogen fusion in the core is accompanied by other different fusion reactions involving heavier elements.
When the core of a massive star dies during a supernova, The supergiant will explodes as a supernova.
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as an astronomer observes an object in space that has an irregular shape, that orbits the sun in a highly elliptical orbit, and that is made of ice and rock. which object is the astronomer most likely observing?
Answers
An astronomer sees an irregularly shaped, ice-and-rock object orbiting the sun in a highly elliptical orbit. Astronomers are most likely to observe comets. Thus, B is the correct option.
Comets are made of ice and rock, and they have irregular shapes. They also orbit the sun in highly elliptical orbits, meaning that their distance from the sun changes greatly over time. Unlike asteroids, which are usually made of rock or metal and have a more spherical shape, comets are known for their bright, glowing tails that result from the sublimation of ice as they near the sun.
Unlike meteoroids, which are small, rocky or metallic objects that can burn up in the Earth's atmosphere, comets are much larger and remain intact as they orbit the sun.
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Answer: Hes observing a comet.
Explanation: Comets are small, irregularly shaped bodies in the solar system composed mainly of ice and dust that typically measure a few kilometers across. They travel around the sun in very elliptical orbits that bring them very close to the Sun, and then send them out past Neptune.
Comets are cosmic snowballs of frozen gases, rock, and dust that orbit the Sun. When frozen, they are the size of a small town. When a comet's orbit brings it close to the Sun, it heats up and spews dust and gases into a giant glowing head larger than most planets.
You have finished running a marathon and you are relaxing and your body is
slowing down. What part of the autonomic nervous system is at work?
A. Sympathetic
B. Aphasic
C. Parasympathetic
D. Encoding
SUBMIT
Answers
A 2. 9 kg model rocket accelerates at 15. 3 m/s2 with a force of 44 N. Before launch, the model rocket was not moving. After the solid rocket engine ignited, hot gases were pushed out from the rocket engine nozzle and propelled the rocket toward the sky. Which of Newton’s laws apply in this example? Select three options. The first law the second law the third law the fourth law the fifth law.
Answers
Answer:
The first law: the law of Inertia.
Explanation:
Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
Answer:
1st, 2nd, & 3rd law
Explanation:
there is no 5th/4th law ppl
I did this question and it says SELECT 3 OPTIONS not 1 (This answer isn’t meant to be rude but just stating what the question says.)