A car engine provides 2500 n of force for a car that has a mass 1000 kg. If an engineer develops a new chassis for a car that is half as massive, what is the acceleration of the car with the new chassis?.

Open clusters, O and B stars, globular clusters and gas and dust lie in the halo of our galaxy, therefore the correct option is (E) all of the above

The halo of our galaxy contains a diverse array of objects, including open clusters, O and B stars, globular clusters, and gas and dust. Open clusters are groups of relatively young stars that formed from the same molecular cloud, while globular clusters are much older and contain hundreds of thousands of stars.

O and B stars are massive, hot stars that emit large amounts of ultraviolet radiation, which can ionize surrounding gas clouds. Gas and dust in the halo can form new stars or be illuminated by nearby stars, producing emission nebulae and other interesting structures.

Therefore, the correct option is (E) all of the above

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Answer:

B

Explanation:

because it would change the direction and speed

The ratio of longitudinal effective mass m_l* to the transverse effective mass m

_t* is given by:m_l* / m_t* = 5 / 1 = 5:1.

The ratio of longitudinal effective mass m_l* to the transverse effective mass m_t* is 5:1.

Given: Near the conduction band minima the energy can be expressed as In Si there are six cigar-shaped minima along [100]. The ratio of the axes of constant energy ellipsoid is 5:1.

The formula for effective mass is,

m* = ℏ² / (∂²E / ∂k²)

In Si, there are six cigar-shaped minima along the [100] axes of constant energy ellipsoid is 5:1.

The longitudinal direction is along the [100] direction.

The transverse directions are along the [010] and [001].

Let's assume that the masses in the two transverse directions are equal and are denoted by m_t*.

Therefore, for effective mass along the [100] direction, we need to calculate the derivative

∂²E / ∂k² with k along the [100] direction.

Using the formula for effective mass along the [100] direction,

m_l* = ℏ² / (∂²E / ∂k²)

Along the [100] direction, the effective mass is given by,

m_l* = ℏ² / (∂²E / ∂k²)  = ℏ² / (5 / m_t* + 1 / m_l*)

Therefore, the ratio of longitudinal effective mass m_l* to the transverse effective mass m

_t* is given by:m_l* / m_t* = 5 / 1 = 5:1.

The ratio of longitudinal effective mass m_l* to the transverse effective mass m_t* is 5:1.

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Answer:

7. They arethe meter (m), the kilogram (kg), the second (s), the kelvin (K), the ampere (A), the mole (mol), and the candela (cd)

Explanation:

7. They arethe meter (m), the kilogram (kg), the second (s), the kelvin (K), the ampere (A), the mole (mol), and the candela (cd)

Answer:

15kg

Explanation:

mass = weight / gravitational field strength

mass = 150 / 9.8 = 15kg (nearest whole no)

The mass of the object on earth whose weight is 150 N will be 15.3 Kg

Mass is the amount of matter present inside a body. It is defined as the product of density and volume. It remains constant through out the universe. Mathematically -

M = ρV

where -

M is Mass

ρ is density

V is volume

Given is your weight on earth which is equivalent to 150 N.

We know that the weight of of an object is a force exerted by the earth towards its center. It can be written as -

W = mg

Weight of the object = [W] = 150 N

Acceleration due to gravity on earth = [g] = 9.8 m/s²

Substituting the values -

150 = m x 9.8

m = 150/9.8

m = 15.3 Kg

Therefore, the mass of the object on earth whose weight is 150 N will be 15.3 Kg.

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It takes approximately 108 days for the radioactive material to decay to 2/5 grams.

To find the number of days it takes for the radioactive material to decay to 2/5 grams, we can use the concept of half-life.

Given:

Half-life of the radioactive material = 6 days

Initial amount of the material = 2 grams

We need to determine the time it takes for the material to decay from 2 grams to 2/5 grams.

Let's calculate the number of half-lives required to reach 2/5 grams:

2 grams → 1 half-life

1 gram → 2 half-lives

1/2 gram → 3 half-lives

1/4 gram → 4 half-lives

1/8 gram → 5 half-lives

1/16 gram → 6 half-lives

1/32 gram → 7 half-lives

1/64 gram → 8 half-lives

1/128 gram → 9 half-lives

1/256 gram → 10 half-lives

1/512 gram → 11 half-lives

1/1024 gram → 12 half-lives

1/2048 gram → 13 half-lives

1/4096 gram → 14 half-lives

1/8192 gram → 15 half-lives

1/16384 gram → 16 half-lives

1/32768 gram → 17 half-lives

1/65536 gram → 18 half-lives

Therefore, it takes approximately 18 half-lives for the material to decay to 2/5 grams.

Since the half-life is 6 days, the total time it takes can be calculated by multiplying the number of half-lives by the half-life period:

Total time = 18 half-lives * 6 days/half-life = 108 days

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Explanation:

mass = newton ÷ g

m = 1025 ÷ 10

mass= 102.5kg

Answer:

A

Explanation:

Think about rubbing your hands together- the friciton produces heat

The efficiency of the wheel and axle of the system is 80% then it takes 62.5N of effort to raise a 20-kilogram.

The ratio notion is used in mathematics when evaluating two or more numbers. It works as a comparison tool to demonstrate how big or small a particular number is. A ratio divides two quantities in order to compare them.

As per the given information provided in the question,

Axle and wheel system efficiency(e) = 80%

System's velocity to mass ratio(V.R) = 4

e = M.A/V.R × 100

80% = M.A/4 × 100

Make "M.A" the subject of the formula

M.A = 80/100 × 4

M.A = 3.2

Added weight on the wheels and axles (L) = 20kg = 200N

Measures are taken to lift the load (E) =?

M.A = Load/Effort

3.2 = 200/ Effort

Effort = 200/3.2 = 62.5N

Consequently, it takes 62.5N of effort to raise a 20-kilogram.

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The net charge contained within the cube is {eq}-1.29 \times 10^{-2} \text{ C} {/eq}. Note that the negative sign indicates that the net charge is negative, which means that there are more negative charges than positive charges within the cube.

To solve this problem, we can use Gauss's law, which states that the flux of the electric field through any closed surface is proportional to the charge enclosed within the surface. We can choose a Gaussian cube that encloses the original cube and has its faces parallel to the faces of the original cube. Since the electric field is parallel to the z-axis at each point on the surface of the original cube, we can choose the Gaussian cube such that its top and bottom faces coincide with the top and bottom faces of the original cube, respectively.

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Answer:

12.3°C should be the correct answer

Answer:

12.3

Explanation:

54.54% is the cycle's new efficiency.

Superheated steam, for instance, can be used in turbines, where it is sprayed from nozzles onto a rotor. The rotor begins to rotate as a result. Due to the fact that only steam could have provided the energy necessary for this to occur, steam will be less energetic after passing through the turbine rotor.

The equation: would be used to determine the cycle's efficiency.

\(Efficiency = (1 - (\frac{T2}{T1})) * 100\%\)

where T1 is the steam's absolute temperature at the turbine's inlet and T2 is the steam's absolute temperature at the turbine's output.In this instance

\(T1 = 500 + 273.15 = 773.15 K\\and \\ T2 = 80 + 273.15 = 353.15 K.\)

\(Efficiency = (1 - (\frac{353.15}{773.15})) * 100\%= 54.54\%\)

Therefore, The cycle's new efficiency is 54.54%.

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Answer:

B is the answer!!

Explanation:

Explanation:

a ray of light pass through raindrops which acts like prism and split the light into its 7 constituent...which when seen by our eyes , we presume it to be a rainbow

Answer:

766.7 watts

Explanation:

P=W/T

work= F*d

= F*5.3 m/4.2s

to student is working against gravity

so mgh= 62kg* 5.3m*9.8 m/s2= 3220.28 Nm

so that divided by 4.2 should be 766.7 watts

if my answer helps please mark as brainliest.

The average coefficient of rolling friction between the driveway and the skateboard wheels is 0.15.

The average coefficient of rolling friction can be determined by analyzing the given information. We know that the combined mass of the boy and his skateboard is 60 kg and the force of gravity acting on them is 590 N. The force of gravity can be calculated using the formula F = m * g, where F is the force, m is the mass, and g is the acceleration due to gravity (approximately 9.8 m/s²). Thus, we have 590 N = 60 kg * 9.8 m/s².

Since the force of gravity acts in the opposite direction of motion, it is necessary to consider the net force to calculate the coefficient of rolling friction. The net force can be determined using Newton's second law, F = m * a, where F is the net force, m is the mass, and a is the acceleration. In this case, the acceleration is calculated by dividing the change in velocity by the time taken to stop. The initial velocity is 5.5 m/s, and the time taken to stop is 5.0 seconds. Therefore, the acceleration is (0 m/s - 5.5 m/s) / 5.0 s = -1.1 m/s².

Next, we can calculate the net force using F = m * a. The net force is equal to the force of gravity plus the force of friction, which is given by the equation F = μ * N, where μ is the coefficient of rolling friction and N is the normal force. The normal force is equal to the force of gravity, which is 590 N. Therefore, we have μ * 590 N = 60 kg * -1.1 m/s².

Simplifying the equation, we find that μ = (-1.1 m/s²) / (590 N / kg) ≈ -0.0019. However, the coefficient of friction cannot be negative, so we take the absolute value, giving us the average coefficient of rolling friction as approximately 0.0019.

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Answer:

chemical energy, Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat; such reactions are called exothermic

Explanation:

hope it will help you

u have to divide it and u will get the answer

Option d is correct i.e. The wave model explains this behavior because waves can move through space without needing a medium.

According to the wave model of electromagnetic radiation, light and other forms of electromagnetic waves are characterized by oscillating electric and magnetic fields that propagate through space. Unlike mechanical waves, such as sound waves, electromagnetic waves do not require a medium (a material substance) to travel through. They can travel through empty space, such as a vacuum, as well as through different materials.

A scientist wants to explain the behavior of electromagnetic radiation which allows it to move through space. The correct explanation the scientist could use is:

d. The wave model explains this behavior because waves can move through space without needing a medium.

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Answer:

False

Explanation:

In the question it is given that a proton travels in the right moves in between the two plates. An electric field that is pointing in the vertically upward direction has magnitude of 3 N/C. The electric field is produced by the plates.

Now from here we can conclude that the direction of the force acting on the proton when the proton is in between the plates acts in the downward direction. While the electric field lines points in the upward direction. Thus the electric point will not be in the direction of the force that acts on the proton.

The cost of energy production is X SR/kWh. Maximum efficiency occurs at Y MW load. To increase output from 60MW to 90MW, Z MW additional input is needed.

a. To find the cost of producing a unit of energy (H/kWh), we need to calculate the operating cost per unit of energy produced by the power plant. The operating cost per unit of energy can be determined by dividing the total cost (including fixed and variable costs) by the total energy output. The total cost consists of the annual fixed charges and the annual operating and maintenance cost.

First, let's calculate the fixed charges per year:

Fixed charges = Installed capacity × Capital cost × FCR

Fixed charges = 140 MW × 2400 SR/kW × 11%

Fixed charges = 369,600 SR/year

Next, let's calculate the variable cost per year:

The variable cost is based on the fuel price and the energy output. The energy output can be determined by integrating the I/O curve equation, where P represents the power output of the power plant. We'll integrate the equation over the desired output range, from 0 MW to the maximum load of 120 MW.

Variable cost = ∫[0, P] (80 + 6P + 0.009P^2) dP

Variable cost = [80P + 3P^2 + 0.003P^3/3] evaluated from 0 to P

Variable cost = 80P + 3P^2 + 0.003P^3/3

Now, we can calculate the total cost per year:

Total cost = Fixed charges + Annual O&M cost + Variable cost

Total cost = 369,600 SR/year + 45,000,000 SR/year + (80P + 3P^2 + 0.003P^3/3)

To find the cost of producing a unit of energy, we divide the total cost by the total energy output:

H/kWh = Total cost / Total energy output

b. To determine the load at which maximum efficiency occurs, we need to find the point on the I/O curve where the slope is zero. This can be achieved by taking the derivative of the I/O curve equation with respect to P and setting it equal to zero.

d(I/O curve)/dP = 6 + 0.018P = 0

P = -6 / 0.018

P = -333.33 MW

Since a negative power output is not physically meaningful in this context, we can ignore this result. Therefore, there is no load at which maximum efficiency occurs within the given constraints.

c. To calculate the increase in input required to increase the output from 60 MW to 90 MW, we need to find the difference between the inputs required at these two output levels.

Input required at 60 MW: P1 = 60 MW

Input required at 90 MW: P2 = 90 MW

Increase in input = P2 - P1

Therefore, the increase in input required to increase the output from 60 MW to 90 MW is 90 MW - 60 MW = 30 MW.

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Answer:

Current

Explanation:

I think srry if im wrong

Answer: A River system

Explanation: A ___________ is a network of streams that drain an area of land and contains all of the land drained by a river including the main river and all its smaller streams or rivers that flow into larger ones, or tributaries (Source Quizlet)

The radius of the output cylinder is 0.11 m.

Radius of the input cylinder, r₁ = 0.01 m

Input force applied, F₁ = 200 N

Mass of the output cylinder, m₂ = 2500 kg

Since more collisions with the piston occur when the area is increased but the number of molecules per cubic centimetre remains constant, the force is proportional to the area.

Force applied on the output cylinder = Weight of the output cylinder

F₂ = m₂g

F₂ = 2500 x 9.8

F₂ = 245 x 10²N

We know that the force applied on an object is directly proportional to the area of the object.

F ∝ A

So, F₁/F₂ = A₁/A₂

F₁/F₂ = (r₁/r₂)²

200/24500 = (r₁/r₂)²

Therefore, the radius of the output cylinder is,

r₂ = r₁√(24500/200)

r₂ = 0.01 x√122.5

r₂ = 0.01 x 11.06

r₂ = 0.11 m

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Answer:

In physics, a state of matter is one of the distinct forms in which matter can exist. Four states of matter are observable in everyday life: solid, liquid, gas, and plasma.

...

To From Gas

Solid Deposition

Liquid Condensation

Plasma Ionization

The tension force in the rope is approximately 5151 N.

Firstly, the given value in the problem are:

Mass of trailer = 2500kg

Angle of rope to the horizontal = 20°

Frictional force = 220N

To find the tension in the rope, we need to draw the free body diagram (FBD).

From the free body diagram (FBD), we can conclude that the sum of the forces acting along the horizontal axis must be equal to the tension force in the rope.

Therefore, using Newton’s second law of motion (F = ma), we get:

Tension in the rope - frictional force = (mass of trailer) x (component of weight along the plane)

We can write the above equation as:

Tension in the rope - 220N = (2500 kg) x g x sin20° ---- (1)

Here, g is the acceleration due to gravity which is equal to 9.81m/s²

Substituting the values in equation (1), we get:

Tension in the rope = (2500 kg x 9.81 m/s² x sin20°) + 220N

Tension in the rope = 5150.87N (approximately 5151N.

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Data set A corresponds to the uniform line of charge and data set B corresponds to the uniformly charged sphere ar e correct . So, option A is the correct answer.

Data set A corresponds to the uniform line of charge because it shows a linear relationship between the electric field strength and the distance from the center of the object. This is characteristic of a uniform line of charge, where the electric field strength is directly proportional to the distance from the center of the line.

Data set B corresponds to the uniformly charged sphere because it shows a non-linear relationship between the electric field strength and the distance from the center of the object. This is characteristic of a uniformly charged sphere, where the electric field strength decreases as the distance from the center of the sphere increases.

Therefore, as per the above explanaions, option A is correct.

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The question is :

Which of the following options correctly identifies which data set corresponds to the uniform line of charge and which one corresponds to the uniformly charged sphere, and provides an explanation for the answer?

A) Data set A corresponds to the uniform line of charge because it shows a linear relationship between the electric field strength and the distance from the center of the object, while data set B corresponds to the uniformly charged sphere because it shows a non-linear relationship between the electric field strength and the distance from the center of the object.

B) Data set A corresponds to the uniformly charged sphere because it shows a non-linear relationship between the electric field strength and the distance from the center of the object, while data set B corresponds to the uniform line of charge because it shows a linear relationship between the electric field strength and the distance from the center of the object.

C) Both data sets correspond to the uniformly charged sphere because they both show a non-linear relationship between the electric field strength and the distance from the center of the object.

D) Both data sets correspond to the uniform line of charge because they both show a linear relationship between the electric field strength and the distance from the center of the object.

Explanation:

The extra space between outlets accommodates multiple "wall wart" plug-in power converters.

Answer:

Velocidad final, V = 8 m/s

Explanation:

Dados los siguientes datos;

Velocidad inicial, u = 4 m/s

Aceleración, a = 2 m/s²

Tiempo, t = 2 segundos

Para encontrar la velocidad final (v), usaríamos la primera ecuación de movimiento;

V = u + at

Sustituyendo en la fórmula, tenemos;

V = 4 + 2*2

V = 4 + 4

Velocidad final, V = 8 m/s

Answer:

K = (11*m*(ω*r)^2)/2

Explanation:

Not surprisingly, the formulas K = (1/2)*I*ω^2 and K = (1/2)*m*v^2 give the same result. They should, of course, since the rotational kinetic energy of a system of particles is simply the sum of the kinetic energies of the individual particles making up the system.

The time required for light to travel vertically from the surface of the ice to the bottom of the pond is approximately 0.0024 seconds.

To calculate this, we first need to find the distance the light has to travel through the ice and water. This can be found by subtracting the thickness of the ice from the total depth of the pond:

distance = total depth - thickness of ice
distance = 2.60 m - 0.36 m
distance = 2.24 m

Next, we can use the formula for the speed of light in a vacuum (c) and the index of refraction of water (n) to calculate the speed of light in water (v):

v = c/n
v = 3.00 x 10⁸ m/s / 1.33
v = 2.26 x 10⁸ m/s

Finally, we can divide the distance by the speed of light in water to find the time required for light to travel from the surface of the ice to the bottom of the pond:

time = distance / speed
time = 2.24 m / 2.26 x 10⁸ m/s
time = 0.0024 seconds

Therefore, it would take approximately 0.0024 seconds for light to travel vertically from the surface of the ice to the bottom of the pond.

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