The car’s average acceleration is 6 meter/second^2.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given that: the car can accelerate from rest to 30 m/s in 5 seconds.
Hence, average acceleration of the car = change in speed/time interval
= ( final speed - initial speed)/time interval
= ( 30 m/s - 0 m/s) / 5 second
= (30/5) meter/second^2
= 6 meter/second^2.
Hence, the average acceleration of the car is 6 meter/second^2.
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What is 170 Degrees in Celsius to Fahrenheit?
"170 Degrees" is a temperature measurement unit commonly used in the Fahrenheit scale. If you are trying to convert "170 Degrees" from Fahrenheit to Celsius, it is important to understand how the two scales relate to each other.
The Fahrenheit scale is based on 32° being the temperature at which water freezes and 212° being the temperature at which water boils. In contrast, the Celsius scale has 0° as the temperature at which water freezes and 100° as the temperature at which water boils.
To convert "170 Degrees" from Fahrenheit to Celsius, you can use the formula:
C = (F - 32) * 5/9, where F is the temperature in Fahrenheit and C is the temperature in Celsius.
Plugging in "170 Degrees" for F, we get:
C = (170 - 32) * 5/9 = 76.67 * 5/9 = 76.67 * 0.5556 = 42.78°C.
So "170 Degrees" Fahrenheit is equivalent to 42.78°C in the Celsius scale.
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the name of the opening that lets light into any camera is called . a. the portal be. the aperture c. the lumen of. the iris e. the eye
The name of the opening that lets light into any camera is called the aperture.
The aperture is a circular opening within the camera lens that can be adjusted to control the amount of light that enters the camera. It is a crucial component in determining the exposure of a photograph.
The aperture is an adjustable opening in a camera's lens that controls the amount of light that enters the camera. It works similarly to the iris in the human eye. By adjusting the size of the aperture, you can control the exposure and depth of field in your photos.
The correct term for the opening that lets light into a camera is the aperture, which plays a crucial role in controlling exposure and depth of field. Therefore, the correct answer is b. the aperture.
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The accompanying figure shows a current loop consisting of two concentric circular arcs and two perpendicular radial lines. Determine the magnetic field at point p
To determine the magnetic field at point P in the given figure, we can use the Biot-Savart Law.
The Biot-Savart Law states that the magnetic field at a point due to a current-carrying element is proportional to the current, the length of the element, and the sine of the angle between the element and the line connecting the element to the point.
In this case, we have two current-carrying arcs and two radial lines. Let's consider each part separately:
1. The circular arcs: Since the circular arcs are concentric, the magnetic fields they produce cancel each other at point P. Therefore, we don't need to consider the circular arcs in our calculation.
2. The radial lines: The radial lines are straight and perpendicular to the line connecting them to point P. The magnetic field produced by a straight current-carrying wire at a point on the wire is given by the equation:
B = (μ₀ * I) / (2π * r)
where μ₀ is the permeability of free space, I is the current, and r is the distance from the wire to the point.
For both radial lines, we can use this equation to calculate the magnetic field at point P. The contribution from each line will have a magnitude of:
B_line = (μ₀ * I) / (2π * r_line)
Since the two lines are parallel and carry the same current, their magnetic fields add up. Therefore, the total magnetic field at point P is:
B_total = 2 * B_line = 2 * (μ₀ * I) / (2π * r_line)
Finally, we can substitute the given values into the equation to calculate the magnetic field at point P.
Note: Without the specific values for the current and distances, we can't provide a numerical answer.
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there are a variety of units for power. which of the following would be fitting units of power (though perhaps not standard)? include all that apply. A. WattB. JouleC. Joule * SecondD. HP
The two units of Power are Watt and Horse power. The correct options are A and D.
Thus, Watt - In the International System of Units (SI), the watt (W) serves as the default unit of power.
It displays the amount of effort or energy transferred per unit of time. Hp. The horsepower (HP) unit of power is a non-SI measure of power that is frequently used when discussing mechanical power.
In the automotive and industrial industries, in particular, it is frequently employed for rating the engine power. Watt and D. HP are the appropriate units of power from the listed options.
Thus, The two units of Power are Watt and Horse power. The correct options are A and D.
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a bag is dropped from a hovering helicopter. the bag has fallen for 1.6 s. what is the bag's velocity?
The bag's velocity when a bag is dropped from a hovering helicopter is 15.68m/s
Its initial velocity is zero. In a free-falling body, the value of the final velocity is obtained through the equation
Vf =u + gt
u = o ( because the bag is dropped, so it falls starting from rest)
Vf = gt
u is initial velocity
Vf is final velocity
t is time
where g is the acceleration due to gravity, 9.8 m/s².
using above values we get
Vf = (9.8 m/s²)(1.6s)
= 15.68m/s
The bag's velocity when a bag is dropped from a hovering helicopter is 15.68m/s
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Write your reflection about the three levels of perfection of mahayana Buddhism. Your reflection paper must contain 100 words?............please help me
Answer: Mahayana is a term for Buddhist culture. It is considered as existing branches of Buddhism.
Explanation:
The mahayanas is a major movement typically in the history of Buddhism. It was originated in Northern India. It comprises of many schools. It involves the reinterpretation of the fundamental human beliefs. This also involves the interpretation and teaching of Buddhism.
The three-level of perfection of Mahayana Buddhism are:
generositymorality, andpatienceThese three are mainly related to the virtuous practices for anyone, for a better and happy life in society. There are three more perfections those are-energy, meditation, and wisdom.
Mahanayan is a term under the Buddhist culture and is considered as the present or existing branch of Buddhism. It was originated in Nothern India, which comprises many schools.
The three main perfections state how the human being should live. The perfection of generosity is said as the entryway to dharma, it is the beginning of the aspiration to realize enlightenment for all beings. The perfection of morality guides us until we find our own balance, and the perfection of patience literally means "able to withstand."
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A parachutist bails out and freely falls 63 m. Then the parachute opens, and thereafter she decelerates at 1.5 m/s2. She reaches the ground with a speed of 3.3 m/s. (a) How long is the parachutist in the air
Answer:
(a) The parachutist spent 24.84 secs in air
(b) The height the fall begins is 472 m
Explanation:
Here is the complete question:
A parachutist bails out and freely falls 63 m. Then the parachute opens, and thereafter she decelerates at 1.5 m/s2. She reaches the ground with a speed of 3.3 m/s. (a) How long is the parachutist in the air (b) At what height does the fall begin?
Explanation:
From one of the equations of kinematics for free fall
\(H = ut - \frac{1}{2}gt^{2}\)
Where H is the height
u is the initial velocity
t is the time
and g is the acceleration due to gravity (Take g = 9.8 m/s2)
Now, we can find the time spent before the parachute opens.
u = 0 m/s (we assume the parachutist starts from rest)
H = - 63 m
∴\(-63 = 0(t) - \frac{1}{2}(0.98) t^{2} \\-63 = -4.9 t\\t^{2} = \frac{63}{4.9} \\t^{2} = 12.86\\t = \sqrt{12.86} \\t = 3.59 s\)
This the time spent before the parachute opens
Also from one of the equations of kinematics for free fall
\(v = u - gt\)
where v is the final velocity
We can determine the final velocity before the parachute opens and she starts to decelerate
∴\(v = - 9.8(3.59)\\v = - 35.18m/s\)
Now, we will calculate the time spent after the parachute opens
From one of the equation of kinematics for linear motion,
\(v = u + at\)
Here, the initial velocity will be the final velocity just before the parachute opens, that is
\(u = - 35.18 m/s\)
From the question,
\(v = - 3.3 m/s\)
\(a = 1.5 m/s^{2}\)
We then get
\(-3.3 = - 35.18 + (1.5)t\)
\(-3.3 + 35.18 = 1.5t\\31.88 = 1.5t\)
\(t = \frac{31.88}{1.5}\)
\(t = 21.25 secs\)
(a) To determine how long the parachutist is in the air,
That is sum of the time used when falling freely and the time used after the parachute opens
= 3.59 secs + 21.25 secs
24.84 secs
Hence, the parachutist spent 24.84 secs in air
(b) To determine what height the fall begins
First, we will calculate the height from which the parachute opens
From one of the equation of kinematics for linear motion,
\(x = ut + \frac{1}{2}at^{2} \\\)
\(x = -35.18(21.25) + \frac{1}{2}(1.5)(21.25)^{2} \\x = -747.58 + 338.67\\x = -408.91m\\\)
\(x\) ≅ \(- 409m\)
Hence, the height the fall begins is 63m + 409m
= 472 m
Which material transmits the most visible light?
A.Sunglass lens
B.Mirror
C.Clear glass
D.Black cloth
Answer:
c
Explanation:
What metaphor (object) shows how Aristotle's Three Artistic Proofs hold up one's argument?
1. wagon
2. stool
3. hammock
4. easel
The metaphor (object) that shows how Aristotle's Three Artistic Proofs hold up one's argument is a stool. The correct option is 1.
The Three Artistic Proofs are Aristotle's fundamental concepts of argument that build a convincing case when utilized together:
Ethos: It is the ethical appeal; it establishes credibility with an audience.
Pathos: This refers to the emotional appeal; it appeals to the audience's emotions and sentiments.
Logos: It is the logical appeal; it uses reasoning and logical argument to persuade and convince the audience.
The metaphor (object) that shows how Aristotle's Three Artistic Proofs hold up one's argument is a stool. A stool is a three-legged object that can stand on its own with each leg equally supporting the weight. It is like the three artistic proofs, which are required in a good argument to hold it up. Without one of the three legs, the stool would be unstable and would fall apart. This metaphor is commonly used to explain how the three artistic proofs work together to build a convincing case. Option 1.
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Draw a labelled diagram showing the main parts of a cathode ray oscilloscope I
Answer:
Hope it's help you !!!!! :)
An 80.8kg man is standing on a frictionless ice surface when he throws a 2.3kg book at 11.8m/s. with what velocity does the man move across the ice?
The man moves across the ice with a velocity of -1 m/s.
Formula:
To calculate the velocity we would be using the formula,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Given:
After applying the law of linear momentum, we get the following value before the throw;
M₁ = Man's initial mass= 80kg,
U₁ = Initial velocity of Man = 0,
M₂= Initial mass of Book = 4kg,
U₂= Initial velocity of Book = 0.
After the throw, the book's velocity will be
M₁ = Man final mass = 80kg,
V₁ = Man's final velocity = V.
M₂ = Final mass of Book = 4kg,
V₂ = Final velocity of Book = 20 m/s
After substituting the values in the formula, we get,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Or, (80 x 0) + (4 x 0) = (80V) + (4 x 20)
Or, 0 = 80V + 80
Or, 80V = -80
Or, V = -80/80
V= -1m/s
[Note: The -ve sign shows the opposite direction]
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Without the proper shielding, an individual who tries to construct a nuclear device would:________
Without the proper shielding, an individual who tries to construct a nuclear device would be exposed to unsurvivable levels of radiation.
Nuclear devices are explosive devices that produce nuclear explosions through nuclear processes, either fission (fission bombs) or a mix of fission and fusion reactions (thermonuclear bombs). Gamma rays are a radiation threat to the entire body. They can quickly pass through defences like skin and clothing that can stop alpha and beta particles. Gamma rays have such a strong penetrating force that stopping them may need several inches of a thick substance, like lead, or perhaps a few feet of concrete.
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The rotational inertia of a thin cylindrical shell of mass M, radius R, and length L about its central axis (X - X') is:
A. MR2/2
B. ML2/2
C. ML2
D. MR2
E. none of these
The rotational inertia of a thin cylindrical shell of mass M, radius R, and length L about its central axis (X - X') is MR²/2.
Determine the moment of inertia?The rotational inertia, also known as the moment of inertia, is a property that quantifies an object's resistance to rotational motion. For a thin cylindrical shell, the rotational inertia can be calculated based on its mass, radius, and length.
The formula for the rotational inertia of a thin cylindrical shell is given by I = MR²/2, where M represents the mass of the shell and R represents its radius.
In this case, since we are considering the rotational inertia about the central axis (X - X'), the length of the cylinder (L) does not come into play. The only relevant parameters are the mass (M) and radius (R).
Applying the formula, the rotational inertia of the thin cylindrical shell is MR²/2. Therefore, the correct answer is A. MR²/2.
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Sides km and fh in the triangles below will be placed together to form a quadrilateral. triangle m l k. side m l has a length of 15 and side l k has a length of 35. angle l is 110 degrees.triangle f g h. side f g has a length of 35 and side g h has a length of 15. angle g is 110 degrees. which best describes the quadrilateral that will be formed? parallelogram rectangle rhombus trapezoid
The shape that best describes the quadrilateral that will be formed is parallelogram because it has two pairs of parallel sides and equal opposite angles.
What is a recatangle?A rectangle is a four sided figure, with two equal lengths and two equal breadth.
Each angle of a reactangle is 90 degrees.
What is a rhombus?A rhombus is four sided shape, and four sides are equal.
From the given shape, there four sides and two sides are equal. It cannot be trapezoid because the two opposite angles are equal.
What is a parallellogram?This is a four sided shape, with two pairs of parallel sides and the opposite angles are equal.
Thus, the shape that best describes the quadrilateral that will be formed is parallelogram because it has two pairs of parallel sides and equal opposite angles.
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Answer:
A
Explanation:
Parallelogram
A pontoon boat travels across a lake in a straight line and increases in speed uniformly from vi = 18.5 m/s to vf = 36.0 m/s in a displacement Δx of 250 m. We wish to find the time interval required for the boat to move through this displacement. g
(a) Draw a coordinate system for this situation.
(b) What
analysis model is most appropriate for describing this situation?
(c) From the analysis model, what equation is most
appropriate for finding the acceleration of the speedboat?
(d) Solve the equation selected in part (c) symbolically for
the boat’s acceleration in terms of vi , vf , and ?x. (e) Substitute
numerical values to obtain the acceleration numerically.
(f) Find the time interval mentioned above.
Answer:
Explanation:
a ) The motion is one dimensional , so motion is along x - axis , starting from origin ( 0 , 0 )
b ) Initial velocity is 18.5 m /s when boat is situated at origin . When he displaces by 250 m along x axis and his position is ( 250 , 0 ) along x axis , his velocity becomes 36 m /s . Both his velocity and acceleration is along x - axis.
c ) Initial velocity vi = 18.5 m /s
final velocity vf = 36 m/s
Displacement x = 250 m
Acceleration a = ?
Most appropriate formula is given below .
vf² = vi² + 2 a x
2ax = vf² - vi²
x = ( vf² - vi² ) / 2 a
d )
Putting the given values
36² - 18.5² / 2 x 250
= 1296 - 342.25 / 500
= 1.9 m /s².
f ) Time interval t = ?
Required formula
vf = vi + at
t = (vf - vi ) / a
Putting the values
t = (30 - 18.5) / 1.9
= 6.05 second .
Thinking about planck's law, which star would give off the most orange light?
Thinking about Planck's law, the Red star would give off the most orange light.
According to Planck's Law, distinct atoms and molecules can emit or take in power in discrete portions simplest. The smallest amount of strength that can be emitted or absorbed inside the form of electromagnetic radiation is called quantum.
Planck's Law describes the quantity of spectral radiance at a particular wavelength radiated through a black body in equilibrium. The equation is E=hv.
The floor temperature of a celeb determines the color of mild it emits. Blue stars are warmer than yellow stars, which are hotter than red stars. The bright orange celebrity Arcturus is particularly noteworthy for its massive right motion, The color is a characteristic of their floor temperatures.
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5. What structure did Friedrich Kekule discover that allowed carbon atoms can bond
with up to four other atoms at the same time?
Can someone please answer this, ill give you brainliest Would be very appreciated.
A decrease in the ice caps causes a(n) (options decrease, increase) in the absorption of sunlight. This causes the global temperature to (options rise, fall) causing more ice caps to melt. As more ice caps melt, the temperature (options rises, falls). This is an example of a (options negative, positive) feedback loop.
Answer:
See below ~
Explanation:
A decrease in the ice caps causes a(n) increase in the absorption of sunlight. This cause the global temperature to rise causing more ice caps to melt. As more ice caps melt, the temperature rises. This is an example of a negative feedback loop.
A decrease in the ice caps causes a(n) increase in the absorption of sunlight. This causes the global temperature to rise causing more ice caps to melt. As more ice caps melt, the temperature rises. This is an example of a negative feedback loop.
The options are followed by
IncreaseRiserisesnegativeName three ways a workout in the healthy heart zone benefits your health
The work function of a metal is 3.69 eV. What is the cutoff frequency of this metal? 07.86 x 1014 Hz 4.79 x 10¹4 Hz 8.92 x 1014 Hz 6.63 x 1014 Hz O 1.60 x 10¹4 Hz Submit Answer Save for Later
The cutoff frequency of the metal, given a work function of 3.69 eV, is calculated to be 8.92 × 10¹⁴ Hz. The cutoff frequency represents the frequency required to dislodge an electron from the metal surface, and it is determined by the ratio of the work function to Planck's constant.
The work function of a metal is given as 3.69 eV. We need to determine the cutoff frequency of this metal, which represents the frequency required to knock an electron out of the metal surface. The cutoff frequency can be calculated using the formula f_cutoff = Φ/h, where Φ is the work function and h is Planck's constant.
Given that the work function is 3.69 eV, we need to convert it to joules to use in the formula. The conversion factor is 1 eV = 1.602 × 10⁻¹⁹ J.
Therefore, the work function in joules is:
Φ = 3.69 eV × 1.602 × 10⁻¹⁹ J/eV = 5.908 × 10⁻¹⁹ J.
Using the formula f_cutoff = Φ/h and substituting the values, we have:
f_cutoff = (5.908 × 10⁻¹⁹ J) / (6.626 × 10⁻³⁴ J s) = 8.92 × 10¹⁴ Hz.
The cutoff frequency of the metal, given a work function of 3.69 eV, is calculated to be 8.92 × 10¹⁴ Hz. The cutoff frequency represents the frequency required to dislodge an electron from the metal surface, and it is determined by the ratio of the work function to Planck's constant.
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12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.
Answer:
i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii) Find the value of k first: F = 400 + k(15^2) k = 28/9 F = 400 +(28/9)(30^2) = 320
Explanation:
If an object falls from rest and lands 3.2 seconds later, how many
meters did it fall
Answer:
50.2 meters
Explanation:
When an object falls, it goes a distance d in time t according to the formula:
\(d=\frac{1}{2}*g*t^{2}\)
d is the distance in meter, g is the acceleration due to gravity with the value of 9.8\(m/s^{2}\) , t is the time in seconds
Therefore, \(d = \frac{1}{2}*9.8*(3.2)^{2}\)
d= 50.176 ≈ 50.2m
An axon of a human nerve cell is 5 x 10-6m in radius and 0.5-mm long. If the resistivity of the cytoplasm (inside the axon) is 1.6 x 107 Ω.m; Calculate the resistance along the axon, Raxial.
Raxial = ----- Ω
The axial resistance of an axon is calculated using the formula R = ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area. In this case, the axial resistance is 11.28 MΩ.
The resistance along the axon is calculated using the following formula:
R = ρL/A
where:
R is the resistance in ohms
ρ is the resistivity in ohms per meter
L is the length in meters
A is the cross-sectional area in meters squared
In this case, we have:
ρ = 1.6 x 107 Ω.m
L = 0.5 mm = 0.0005 m
A = πr² = π(5 x 10-6)² = 7.854 x 10-13 m²
Therefore, the resistance is:
R = ρL/A = (1.6 x 107 Ω.m)(0.0005 m) / (7.854 x 10-13 m²) = 11.28 MΩ
Therefore, the axial resistance of the axon is 11.28 MΩ.
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An athlete walks 8 meters East , 2 meters South, 8 meters West, and finally 2 meters North. What is the total distance traveled?
Answer:
the sum of all the values which is 20 meters
Explanation:
total is everything combined
Distance is the sum of an object's movements, regardless of direction. The distance can be defined as the amount of space an object has covered, regardless of its starting or ending position. The total distance traveled is 20m.
A scalar quantity distance measures "how much ground an object has covered" while moving. The term "how far out of place an object is" relates to displacement, a vector number that describes the total change in the position of the object.
Distance is the length of an object's real route in its entirety. The International System of Units specifies that the unit of distance is the meter.
Total distance = 8 + 2 + 8 + 2
D = 20 m
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Newton's law of cooling says that the rate at which a body cools is proportional to the difference in temperature between the body and an environment into which it is introduced. This leads to an equation where the temperature f(t) of the body at time t after being introduced into an environment having constant temperature To is f(t)= To + Ce where C and k are constants. Find the temperature of an object when t = 10 T_{0} = 16 C = 5 and k = 0.6
The temperature of the object when t = 10 is 14.36 degrees Celsius.
According to Newton's law of cooling, the temperature of a body at time t after being introduced into an environment with a constant temperature To can be represented by the equation f(t) = To + Ce, where C and k are constants.
Given that T0 = 16, C = 5, and k = 0.6, we need to find the temperature of the object when t = 10.
Substituting the given values into the equation, we have:
f(t) = T0 + Ce
f(10) = 16 + 5 * e^(0.6 * 10)
Using the exponential function e^x, we can simplify the equation:
f(10) = 16 + 5 * e^6
Evaluating the exponential function, we find:
f(10) ≈ 16 + 5 * 403.43
f(10) ≈ 16 + 2017.15
f(10) ≈ 2033.15
Therefore, the temperature of the object when t = 10 is approximately 14.36 degrees Celsius.
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a train travels at 20m/s for 30 seconds.How far has it moved?
Answer:
600m
Explanation:
We can use the equation speed = distance / time.
We are trying to find the distance, so rearrange to get distance = speed x time.
Substituting in our values, 20m/s x 30s = 600m
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a circuit containing an electromotive force (a battery), a capacitor with a capacitance C farads (F), and a resistor with a resistance of R ohms (Ω
). The voltage drop across the capacitor Q/C, where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives
RI+QC=E(t)
.
Since the current is I=dQdt
, we have
RdQdt+1CQ=E(t)
.
Suppose the resistance is 10Ω
, the capacitance is 0.2 F, a battery gives a constant voltage of E(t) = 50 V, and the initial charge is Q(0) = 0C.
Find the charge and the current time t.
The charge time t is given by Q = 10 - 10e^(-5t), and the current I time t is given by I = 50e^(-5t).
How to calculate the charge and current timeTo solve for the charge and current time, able to alter the equation RdQ/dt + (1/C)Q = E(t) as a first-order coordinate customary differential equation.
Given that R = 10Ω, C = 0.2 F, and E(t) = 50V, the equation gets to be:
10dQ/dt + (1/0.2)Q = 50
Directly, prepared to utilize a coordination figure to disentangle the differential equation. The coordination figure is given by e^(∫(1/RC)dt), which in this case unravels to e^(5t).
Replicating both sides of theequation by e^(5t), we get:
e^(5t) * (10dQ/dt) + e^(5t) * (1/0.2)Q = e^(5t) * 50
By and by, we'll disentangle the cleared outside of the equation utilizing the thing that run the show up and encouraged:
d/dt (e^(5t) * Q) = 50e^(5t)
Coordination both sides with respect to t, we get:
e^(5t) * Q = ∫(50e^(5t))dt
Understanding the essence, we have:
e^(5t) * Q = 10e^(5t) + C1
Separating both sides by e^(5t), we get:
Q = 10 + C1e^(-5t)
To find the regard of C1, we utilize the starting equation Q(0) = 0C:
= 10 + C1e^(0)
C1 = -10
Substituting this regard back into the equation, we have:
Q = 10 - 10e^(-5t)
To find the current I, we utilize the equation I = dQ/dt:
I = d/dt (10 - 10e^(-5t))
Modifying, we get:
I = 50e^(-5t)
Along these lines, the charge Q as a work of time t is given by Q = 10 - 10e^(-5t), and the current I as a work of time t is given by I = 50e^(-5t).
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A dog is running in a circle around a tree, trying to catch a rabbit. The dog's owner notices the
dog completes 4 laps around the tree in 32 seconds and the radius of the dog's circular path is
3 meters. What is the tangential velocity of the dog?
Answer: 2.35 m/s
Explanation:
Given
Dog completes 4 laps around the tree in 32 seconds
Radius of the circular path is 3 m
Time period for single lap is \(\frac{32}{4}=8\ s\)
Length of the track is equivalent to the perimeter of the path
\(\Rightarrow L=2\pi r\\\Rightarrow L=2\pi \times 3\\\Rightarrow L=6\pi\ m\)
Tangential velocity is given by
\(\Rightarrow v_t=\dfrac{L}{t}\\\\\Rightarrow v_t=\dfrac{6\pi}{8}\\\\\Rightarrow v_t=2.35\ m/s\)
Thus, the tangential velocity is 2.35 m/s
A body slides down a smooth inclined plane at 30° to the horizontal. The distance covered after 15s from rest is
The distance covered by the body after 15 seconds down the inclined plane is approximately 1102.5 meters.
We can use the equations of motion to solve this problem. The acceleration of the body down the inclined plane can be found using trigonometry:
a = gsin(30°) = (9.8 m/s²)(1/2) = 4.9 m/s²
where g is the acceleration due to gravity.
Using the equation of motion:
s = ut + (1/2)at²
where s is the distance covered, u is the initial velocity (which is zero in this case), and t is the time taken, we can find the distance covered after 15 seconds:
s = (1/2)4.9(15)² = 1102.5 meters
Therefore, the distance covered by the body after 15 seconds down the inclined plane is approximately 1102.5 meters.
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The nurse assessing an 11-year-old who is having an asthma attack expects to hear adventitious sounds of:_______
The nurse assessing an 11-year-old who is having an allergies attack expects to hear adventitious sounds of: sibilant wheezes.
Can asthma can be cured?
There's no therapy for asthma. However, it is a especially treatable disease. In fact, some medical doctors say modern day allergies remedies are so effective, many humans have near-complete manipulate of their symptoms
What can be the cause of asthma?Exposure to more than a few irritants and components that set off allergies (allergens) can set off signs and symptoms of asthma.
Asthma triggers are exceptional from character to man or woman and can include: Airborne allergens, such as pollen, dirt mites, mould spores, pet dander or particles of cockroach waste.
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