A car accelerates uniformly in a straight line
from rest at the rate of 3.7 m/s2.
What is the speed of the car after it has
traveled 63 m?
Answer in units of m/s

Answers

Answer 1

Answer:

21.59 m/s

Explanation:

recall that one of the equations of motions can be expressed as

v² = u² + 2as

where,

v = final velocity (we are asked to find this)

u = initial velocity = 0m/s (because it says that it starts from rest)

a = acceleration = 3.7m/s²

s = distance travelled = 63 m

simply substitute the known values above into the equation:

v² = u² + 2as

v² = 0² + 2(3.7)(63)

v² = 466.2

v = √466.2

v = 21.59 m/s


Related Questions

Select all the correct answers. which three forms of light are invisible light? blue light infrared rays radio waves red light x-rays

Answers

Infrared rays, radio waves, and x-rays are the three kinds of light that are invisible to human vision.

What is a visible spectrum?

The region of the electromagnetic spectrum that the human eye can see is known as the visible light spectrum. This group of wavelengths is most commonly referred to as visible light. The range of wavelengths that the human eye can typically see is from 380 to 700 nanometers.

Example of visible spectrum is visible light.

Examples of invisible light are;

Infrared raysRadio wavesx - rays

Thus, the three forms of light that are invisible light or invisible to human eyes are Infrared rays, Radio waves and x - rays.

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An Athelice complete :Round of a circular track of diameter 200m in base Distance travelled by athletes And displacement

Answers

Answer:

Distance = 1256 m

Displacement = 0

Explanation:

Distance :

Distance may be defined as the actual length between two points along its path.

It is a scalar quantity and its value can be positive or zero.

Displacement :

Displacement is defined as the shortest length between two point , i.e. between the initial point and the final point.

It is a vector quantity and it has values which can be either positive or negative or zero.

From the question, the diameter of the circular track is, r = 200 m

∴ Distance travelled by an athlete is = circumference of the circular track

                                                            = 2πr

                                                            = 2 x 3.14 x 200

                                                            = 1256 m

 Displacement = 0  (since the original point coincides with the final point).


Please help what is the mass ??
•358.20 g
•358.3 g
•358.30 g
•358.2 g

Please help what is the mass ??358.20 g358.3 g358.30 g358.2 g

Answers

Answer:

The answer is 358.2 g.

In 2 - 3 sentences, explain the difference in Kinetic energy and Potential energy.

Answers

The main difference between Kinetic energy and Potential energy is that kinetic energy refers to movement while potential energy refers to storage.

What are Kinetic energy and Potential energy?

Kinetic energy is a type of energy in motion or energy in movement such as a turbine (mechanical energy), while Potential energy refers to the energy that is stored to be used when required (e.g. chemical bonds of foods).

Therefore, with this data, we can see that  Kinetic energy is used as movement, while Potential energy is stored to be used in the future.

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Take the location of particle 5 as the reference point for all angular momentum calculations when answering the following questions. Be sure to express your answer as a vector.

Consider all six particles as a system. What is the rotational momentum of the system? a. < 0 b. 0 c. -2*m*v*d > 0 0 -2 · m · vid

Answers

-2*m*v*d is the rotational momentum of the system.

Hence, the correct option is C.

We are taking the location of particle 5 as the reference point for all angular momentum calculations, the angular momentum of the system can be found by calculating the angular momentum of each particle about particle 5 and adding them.

Let the mass of each particle is "m", and their velocities are v1, v2, v3, v4, v5, and v6, respectively, and their positions relative to particle 5 are d1, d2, d3, d4, d5, and d6, respectively, the angular momentum of each particle about particle 5 can be calculated as

Where

L1 = m * (r1 x v1), where r1 = d1 - d5

L2 = m * (r2 x v2), where r2 = d2 - d5

L3 = m * (r3 x v3), where r3 = d3 - d5

L4 = m * (r4 x v4), where r4 = d4 - d5

L5 = 0, where r5 = d5-d5 = 0, since the reference point is particle 5

L6 = m * (r6 x v6), where r6 = d6 - d5

The total angular moment of the system is defined by the vector sum of these
L = L1 + L2 + L3 + L4 + L5 + L6

We didn't know the values of the velocities and position of the particle so, we can't determine the value of L. However, we can eliminate the option A and B.

Hence, the angular momentum of the system can't not be negative or zero as defined in specific direction.
Hence, the correct option is C.

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The distance between mankato, mn, and duluth, mn, is approximately 237 miles one way. how far is that in kilometers?

Answers

The distance between Mankato and Duluth is 237 miles i.e.  equal to 381.415 kilometer approximately.

Distance can be define as, the total movement of an object without any regard to direction. Thus in very simple word the distance between two points is the length of the line segment that connects them. The distance between two points is always positive.

A line segment is a term of geometry that, the part of a line having two endpoints

The distance between Mankato and Duluth = 237 miles

1 miles = 1.60934 kilometers

237 miles = 237 × 1.60934 kilometers

237 miles = 381.41358 kilometers

Therefore ,we can write the distance between Mankato and Duluth in kilometers is 381.4 kilometers.

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A 0.045-kg golf ball is dropped from rest. Is dropped from a height of 1.3m and comes back up at a height of .7m

Answers

The  time to drop from 1.3m and velocity after height at 0.7 mis mathematically given as

t1 = 0.515 sec  

v0 = 3.7m/s

What is the time to drop from 1.3m and velocity after height at 0.7?

Question Parameters:

A 0.045-kg golf ball is dropped from rest.

Is dropped from a height of 1.3m and comes back up at a height of .7m

Generally, the equation for the time to drop from 1.3m   is mathematically given as

yf - yi = vi t + a t^2/ 2

Therefore

0 - 1.3 = 0 - 9.8 t^2 /2

t1 = 0.515 sec  

Hence, after its max height is 0.7 m,

vf^2 - vi^2 = 2 a (yf - yi)

0^2 - (v0)^2 = 2(-9.8)(0.7 - 0)

v0 = 3.7m/s

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URGENT : need this for tmmr

URGENT : need this for tmmr

Answers

2.2cm^3

As per the statement the given measurement of different volumes

Let consider

V1 = 2.1cm^3

V2 = 2.1cm^3

V3 = 2.4cm^3

Now, we are supposed to find the mean value

mean value = submission of total number observation÷ sum of no. of observation

mean value = 2.1+2.1+2.4÷ 3

mean value = 6.6÷3

mean value= 2.2cm^3

The central tendency of data is measured by the term "mean." It is a value that, in general, may be used to express the primary value of a group of data. It is determined by adding up all of the data set's observations and dividing the result by the total number of observations.

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In young's double silt experiment if the distance between the silts is 0.5 and the distance between the silts and screen is 2 times.Then what will be the width of bands

Answers

Answer: The width of bands will be 2λ

Explanation: Please see the attachments below

In young's double silt experiment if the distance between the silts is 0.5 and the distance between the

The equilibrium concentration of a strong acid (H3O+) may be_____
(mol/L)

Answers

The chemical equilibrium concentration of a strong acid may be equal to it's corresponding conjugate base.

What is chemical equilibrium?

Chemical equilibrium is defined as the condition which arises during the course of a reversible chemical reaction with no net change in amount of reactants and products.A reversible chemical reaction is the one wherein the products as soon as they are formed react together to produce back the reactants.

At equilibrium, the two opposing reactions which take place take place at equal rates and there is no net change in amount of the substances which are involved in the chemical reaction.At equilibrium, the reaction is considered to be complete . Conditions which are required for equilibrium are given by quantitative formulation.

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❤️❤️❤️❤️WILL MARK BRAINLIEST PLEASE ANSWER BOTH PARTS!❤️❤️❤️❤️

WILL MARK BRAINLIEST PLEASE ANSWER BOTH PARTS!

Answers

Answer:

the answer to the first one is B and the second one is c I hope I got them right

Discuss how the testing frequency affects the measurement of glass transition temperature (T2) in a Dynamic Mechanical Analysis

Answers

The glass transition temperature (Tg) is an important property of materials, especially polymers, and it can be measured using various techniques, including Dynamic Mechanical Analysis (DMA).

DMA involves subjecting a material to a range of temperatures and measuring its mechanical response, such as storage modulus and loss modulus.

The testing frequency in DMA refers to the frequency at which the material is subjected to an oscillatory force or strain. It affects the measurement of Tg because the glass transition is a thermally activated process, and the testing frequency can influence the rate at which this transition occurs.

Here are some key points to consider regarding the impact of testing frequency on Tg measurement in DMA:

Sensitivity to the glass transition: Higher testing frequencies tend to increase the sensitivity of DMA to the glass transition. When the frequency is high, the material has less time to relax and transition between its glassy and rubbery states.

As a result, the glass transition appears to be shifted to higher temperatures. Conversely, lower testing frequencies provide more time for relaxation, resulting in a lower apparent Tg.

Measurement accuracy: The accuracy of Tg determination can be influenced by the testing frequency. If the chosen frequency is not appropriate for the specific material, it can lead to inaccuracies in the measured Tg value.

It is important to select a testing frequency that aligns with the expected behavior of the material and ensures the most accurate determination of Tg.

Polymer molecular weight: The molecular weight of a polymer can affect its viscoelastic behavior and, consequently, its glass transition. In DMA, the effect of molecular weight on Tg can be modulated by adjusting the testing frequency.

Higher testing frequencies can help differentiate the Tg of low molecular weight polymers, while lower frequencies may be more suitable for high molecular weight polymers.

Material relaxation behavior: Different materials exhibit different relaxation behaviors, and these behaviors can be affected by the testing frequency. Some materials may have multiple.

le relaxation processes, including secondary or sub-Tg relaxations. The testing frequency can selectively amplify or suppress certain relaxation processes, leading to variations in the observed Tg.

Standardization and comparison: To ensure consistency and facilitate comparison, it is important to establish standard testing conditions, including the testing frequency, for Tg determination using DMA.

Standardization allows researchers to compare results across different studies and enables better understanding and interpretation of the glass transition behavior.

In summary, the choice of testing frequency in DMA can influence the measurement of glass transition temperature (Tg). It affects the sensitivity, accuracy, differentiation of materials, and observed relaxation behavior.

Understanding the material properties and selecting an appropriate testing frequency is crucial for obtaining reliable and meaningful Tg measurements using DMA.

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An impulse of 20,000 N*s is applied to a car, bringing it to a stop in 0.17 seconds. What force was applied to the car?

Answers

F =

t = 0.17 s

Impulse (J) = 20,000 N

J = F x t

F = J / t = 20,000 Ns / 0.17 s = 117,647.0588 N

A machine puts out 20 watts of power for every 100 watts put into it what’s the efficiency of the machine?

Answers

The answer is 4 dived by 3

An object with a mass of 2.0 kg accelerates 2.0 m/s 2when an unknown force is applied to it. What is the amount of force?

Answers

Answer:

4 N

Explanation:

mass = 2 kg

acceleration = 2 m/s^2

Force = mass * acceleration

         = 2 *2

         = 4 N

How is an apple falling from a tree like the potential difference in a battery?

Answers

The gravitational potential energy of a falling apple is similar to the potential difference of a battery because both are energy stored in the object

The gravitational potential energy of a falling apple is maximum when the apple is at maximum height. As the apple begins fall to the ground the potential energy decreases and it will be transformed to kinetic energy.

\(P.E_i + K.E_i = P.E_f + K.E_f\)

The potential difference in a battery is total energy stored in the battery.

Thus, the gravitational potential energy of a falling apple is similar to the potential difference of a battery because both are energy stored in the object.

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The similarity is that both the battery and the falling apple have stored energy.

We define the potential energy of an object as stored energy in that object.

A battery has potential energy, it is stored until you connect it to something and allow that energy to flow.

Similarly, when the apple is in the air it has potential energy, that will be transformed into kinetic energy as it falls (as the apple falls, its velocity increases, thus, the kinetic energy increases).

So both, the apple and the battery have stored energy, and that is the similarity between these two.

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What is one star that has run out of hydrogen

Answers

One star that has run out of hydrogen is known as a white dwarf

a police car, whose siren has a natural frequency of 620hz, moves away from a wall and towards a stationary observer at a speed of 30km/h. what is the beat frequency perceived by the observer? if the observer stands between the car and the wall, what beat frequency does he perceive?

Answers

If v is the frequency of the emission, then the frequency of the reflected wave is ′=(vv+vs)=620(340340+8.333)=605.2 Hz. v v + v s = 620 (340 340 + 8.333) = 605.2 H z is what "′" equals.

How does the observer's frequency change as the source gets further away?

Moving away from the source causes an observer to pick up a lower frequency, while moving toward it causes them to pick up a higher frequency. Therefore, the perceived frequency often rises as the source and observer get closer to one another.

Why does a siren's frequency increase as an ambulance using that siren approaches?

This is because the moving ambulance is squishing the sound waves in front of the car together. Your ear receives more vibrations per second as a result.

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The Big Bang theory makes predictions about the age, dark matter and dark energy content, and the average density of the universe. Which observation has provided the most accurate values of these quantities

Answers

One of the most significant observations that has provided the most accurate values of the age, dark matter, dark energy content, and the average density of the universe is the cosmic microwave background (CMB) radiation.

The CMB radiation is the afterglow of the Big Bang and is a remnant of the hot, dense early universe. The CMB radiation provides a snapshot of the universe when it was only 380,000 years old, and its properties can be analyzed to infer the universe's current state.

By analyzing the CMB radiation, cosmologists have determined that the universe is approximately 13.8 billion years old. Furthermore, they have found that dark matter constitutes around 27% of the universe's total energy density, and dark energy constitutes around 68%.

The CMB radiation has also provided insight into the universe's average density. By measuring tiny fluctuations in the CMB, scientists have determined that the average density of the universe is very close to the critical density required for a flat universe. This result is consistent with the inflationary Big Bang model and the concept of a flat universe.

Therefore, the observation of the cosmic microwave background radiation has been crucial in providing some of the most accurate values of the age, dark matter, and dark energy content, and the average density of the universe.

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Suppose you pull a suitcase with a strap that makes a 45° angle with the horizontal. The magnitude of the force you exert on the suitcase is 30 lb. a. Find the horizontal and vertical components of the force. b. Is the horizontal component of the force greater if the angle of the strap is 30° instead of 45°? c. Is the vertical component of the force greater if the angle of the strap is 30° instead of 45°?

Answers

A physics concept called force defines the impact one thing has on another, causing it to accelerate or change shape. The rate at which an object's momentum changes is measured in newtons (N) by the International System of Units (SI).

a. To find the horizontal and vertical components of the force, we can use trigonometry. Let F be the force you exert on the suitcase, and then the horizontal component of the force (F_h) is given by F_h = F cos(theta), where theta is the angle between the strap and the horizontal. In this case, theta = 45°, so F_h = 30 lb * cos(45°) = 21.2 lb. Similarly, the vertical component of the force (F_v) is given by F_v = F sin(theta), so F_v = 30 lb * sin(45°) = 21.2 lb.

b. If the angle of the strap is 30° instead of 45°, then the horizontal component of the force would be greater. This is because the horizontal component of the force is proportional to the cosine of the angle, and the cosine of 30° is greater than the cosine of 45°. Specifically, F_h = 30 lb * cos(30°) = 25.9 lb.

c. If the angle of the strap is 30° instead of 45°, then the vertical component of the force would be smaller. This is because the vertical component of the force is proportional to the sine of the angle, and the sine of 30° is smaller than the sine of 45°. Specifically, F_v = 30 lb * sin(30°) = 15 lb.

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In water quality, the symbol "mg/L" is equivalent to:
a. Micrograms per liter
b. Parts per million
c. Parts per billion
d. Mostly good levels

Answers

The symbol "mg/L" in water quality represents milligrams per liter, which is a unit of measurement commonly used to express the concentration of substances in water. Option a is right choice.

The symbol "mg/L" in water quality refers to milligrams per liter, which is a unit of measurement commonly used to express the concentration of substances in water.

This unit represents the number of milligrams of a particular substance that are present in one liter of water.

In the context of water quality, the concentration of various substances is typically measured in parts per million (ppm) or parts per billion (ppb). For example, the concentration of dissolved oxygen in water is typically expressed in milligrams per liter (mg/L), which is equivalent to ppm.

Micrograms per liter (µg/L) is another unit of measurement that is commonly used to express the concentration of substances in water.

However, this unit is typically used for substances that are present in very low concentrations, such as certain pollutants or toxins. In some cases, concentrations may be expressed in parts per trillion (ppt), which is equivalent to µg/L.

Option a is right choice.

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Refraction occurs at the interface between two transparent media because:
A. The frequency of the light changes.
B. The speed of light is different in the two media.
C. The direction of the light changes.
D. Some of the light is reflected.
E. None of the above.

Answers

Refraction occurs at the interface between two transparent media because the speed of light is different in the two media.

When light passes through a transparent medium, such as air, and enters another transparent medium, such as water, the speed of light changes. This change in speed causes the light to bend or refract. The amount of bending depends on the difference in the speed of light between the two media. If the two media have the same speed of light, there would be no refraction.

Therefore, the correct answer to the question is B. The speed of light is different in the two media. The frequency of the light, direction of the light, and reflection of the light may all be affected by refraction, but the main reason for refraction is the change in speed of light between two transparent media.

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can someone help me convert these?

can someone help me convert these?

Answers

Assuming you are supposed to write each conversion in scientific notation:

(2) 1 m = 100 cm, so

(67 cm) × (1/100 m/cm) = 67/100 m = 0.67 m = 6.7 × 10 ⁻¹ m

(3) 1 km = 1,000 m, so

(1.2 km) × (1000 m/km) = 1200 m = 1.2 × 10³ m

(4) 1 m = 1,000 mm = 10³ mm, so

(6.2 × 10 ⁻³ m) × (10³ mm/m) = 6.2 mm

(5) 1 m = 1,000,000,000 nm = 10⁹ nm, so

(4.05 × 10³ nm) × (1/10⁹ m/nm) = 4.05 × 10 ⁻⁶ m

(6) 1 g = 1,000,000 µg = 10⁶ µg, so

(3200 µg) × (1/10⁶ g/µg) = 3200 × 10 ⁻⁶ g = 3.2 × 10 ⁻³ g

the observed slowing of a clock in the vicinity of a black hole is a prediction of______

Answers

The observed slowing of a clock in the vicinity of a black hole is a prediction of general relativity, the theory formulated by Albert Einstein.

General relativity describes the effect that massive objects, like black holes, have on the fabric of space-time. In the presence of a strong gravitational field, such as the one produced by a black hole, time is observed to pass more slowly than in regions of weaker gravity. This phenomenon is known as time dilation.

As a clock approaches a black hole, the gravitational pull on the clock increases. According to general relativity, this increased gravitational force causes the clock to tick more slowly relative to an observer far away from the black hole. This time dilation effect has been experimentally verified through various tests, including the use of atomic clocks on Earth and in satellites orbiting our planet.

The closer the clock gets to the black hole's event horizon (the point of no return), the more pronounced the time dilation effect becomes. An observer watching the clock from a safe distance would see it slow down until it appears to stop altogether at the event horizon. However, from the perspective of the clock, time continues to pass normally.

In conclusion, the observed slowing of a clock near a black hole is a result of the time dilation effect, as predicted by Einstein's theory of general relativity.

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a piston has an external pressure of 13.0 atm . how much work has been done in joules if the cylinder goes from a volume of 0.150 liters to 0.460 liters?

Answers

The work done on the cylinder against the external pressure is 408.34 J.

Work done on the cylinder

The work done on the cylinder against the external pressure is calculated as follows;

W = PΔV

where;

P is the external pressureΔV is change in velocity of the gas

Substitute the given parameters and solve for work done on the cylinder.

W = 13 atm (0.46 L - 0.15 L)

W = 4.03 atm.L

1 atm.L = 101.325 J

4.03 atm.L = ?

= 408.34 J

Thus, the work done on the cylinder against the external pressure is 408.34 J.

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Two conducting concentric spherical shells have radii a = 0.125 m and b = 0.23 m.
(a) Express the capacitance of the two concentric shells in terms of radii a and b and the Coulomb constant k.
(b) Calculate the numerical value of the capacitance in F.
(c) Express the capacitance C through the potential difference ΔV across the capacitor and charge Q.
(d) If the charge in the inner sphere is +Q = 3 μC, the outer sphere –Q = -3 μC, calculate the electric potential difference ΔV between the outside and the inside conductors in V.

Answers

(a) The capacitance of the two concentric shells is given by C = 4πε₀[(a * b) / (b - a)].

(b) Using the given radii a = 0.125 m and b = 0.23 m, and ε₀ ≈ 8.854 × 10⁻¹² F/m, the capacitance is numerically calculated as C = [value in Farads].

(c) The capacitance C can be expressed as C = Q / ΔV, where Q is the charge and ΔV is the potential difference across the capacitor.

(d) Given +Q = 3 μC and -Q = -3 μC, we can find ΔV using the equation ΔV = k * (Q / a - Q / b), where k ≈ 9 × 10⁹ N·m²/C².

How to calculate capacitance and potential?

(a) The capacitance of the two concentric spherical shells can be expressed as:

C = 4πε₀[(a * b) / (b - a)]

where:

C is the capacitance,

ε₀ is the vacuum permittivity (C²/(N·m²)),

a is the radius of the inner shell,

b is the radius of the outer shell.

(b) To calculate the numerical value of the capacitance, we need the value of the vacuum permittivity, ε₀. The vacuum permittivity is approximately ε₀ = 8.854 × 10⁻¹² F/m. Using this value and the given radii a = 0.125 m and b = 0.23 m, we can calculate the capacitance:

C = 4π(8.854 × 10⁻¹² F/m)[(0.125 * 0.23) / (0.23 - 0.125)]

(c) The capacitance C can be expressed in terms of the potential difference ΔV across the capacitor and the charge Q as:

C = Q / ΔV

(d) Given that the charge in the inner sphere is +Q = 3 μC and the outer sphere is -Q = -3 μC, we can calculate the electric potential difference ΔV between the outside and inside conductors. Since the potential difference is the work done per unit charge to move from one conductor to another, we can use the equation:

ΔV = k * (Q / a - Q / b)

where:

k is the Coulomb constant (k ≈ 9 × 10⁹ N·m²/C²),

Q is the charge,

a is the radius of the inner shell,

b is the radius of the outer shell.

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What's Alpha beta gamma emission??

Answers

Alpha radiation is the name for the emission of an alpha particle in fact an helium nuclei, beta radiation is the emission of electrons or positrons , and gamma radiation is the term used for the emission of energetic photons.

how do you test hydrogen gas ​

Answers

Explanation:

The test for hydrogen consists of holding a burning splint held at the open end of a test tube of gas. If the gas is hydrogen it burns with a loud “squeaky pop” which is the result of the rapid combustion of hydrogen with oxygen to produce water.

ANSWER FAST PLEASE 20P

If the child has a mass of 30 kg and is 5 meters off the ground at the top of the slide, how GPE much does he have?

Answers

PEg=mgh
PE=(30kg)(5m)(9.8m/s^2)
PE=1470J

A girl and a boy pulled horizontally on ropes attached to a 20 kg box and made it to slide over a concrete surface (uk=0.8). The angle between two ropes is 900. a. Sketch a the free-body diagram where forces exerted by both the girl and the boy are equal. b. Solve for the kinetic friction exerted by the surface on the box. c. Solve for the forces exerted by both the girl and the boy when the box slides at constant velocity. d. Solve for the net force acted on the box, and its acceleration, if the boy and the girl both applied 300 N force to the box. e. Identify at least 5 action-reaction pairs that you may think possible in this problem​

Answers

Answer:

:DDDDD thanks foooooooor joinin'

Explanation:

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