A car accelerates at a rate of 2.0 m/s2. If its original speed is 8.0 m/s, how many seconds will it take the car to reach a final speed of 28.0 m/s?(Prefered is using KWEPA method)

Lagrange error bound can be used when the function being integrated is continuous on a closed interval [a,b] and differentiable on the open interval (a,b).

Lagrange error bound can be used to estimate the error when approximating a definite integral using a polynomial interpolation.

The Lagrange error bound provides a way to estimate the difference between the true definite integral of a function and the definite integral of its polynomial interpolant. The error bound is expressed as a multiple of the maximum value of the function's second derivative on the interval (a,b) and the size of the interval.

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The elastic potential energy of the spring is 1.6 J.

The elastic potential energy of the spring is the energy stored in the spring and it is calculated as follows;

U = ¹/₂kx²

where;

The given parameters include;

U = ¹/₂kx²

U = ¹/₂ (80) (0.2)²

U = 1.6 J

Thus, the elastic potential energy of the spring is a function of the spring constant and the extension of the spring.

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The time taken for the passenger jet to move from 5 km/h to 460 km/h on the run way during the take off is 10.03 s

From the question given above, the following data were obtained:

The time taken for the the passenger jet to move from 5 km/h to 460 km/h can be obtained as follow:

a = (v – u) / t

12.6  = (127.78 – 1.39) / t

12.6 = 126.39 / t

Cross multiply

12.6  × t = 126.39

Divide both sides by 12.6

t = 126.39 / 12.6

t = 10.03 s

Thus, we can conclude that the time taken is 10.03 s

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It's important to note that the time required for bed accumulation can vary greatly depending on the specific depositional setting and the geological context. Therefore, while thick beds generally suggest longer deposition periods, the exact relationship between bed thickness and time can be influenced by a range of geological factors.

The time required for the accumulation of sedimentary beds, whether thick or thin, can vary depending on various factors. Thick beds generally represent a longer period of sediment deposition compared to thin beds or laminations. This is because thick beds typically result from the continuous or episodic deposition of sediment over an extended period of time, whereas thin beds or laminations may form more rapidly or in a shorter time span.

The formation of thick beds can be influenced by factors such as sediment supply, depositional environment, and sedimentation rates. For example, in environments with high sediment input, such as river deltas or turbidite systems, thick beds may accumulate relatively quickly due to the large volume of sediment being transported and deposited.

On the other hand, thin beds or laminations often result from more rapid or intermittent sedimentation processes. These thinner layers can be associated with processes like periodic flooding events, storm deposition, or the settling of fine-grained sediments in calm environments.

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This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2 Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

Here's the solution to the given problem: Let the origin of our coordinate system be located at the center of the platform. We can assume that there is no friction between the platform and the ground. If v  Rw, the woman will collide with the center of the platform after the platform stops moving because it is not able to move with the required speed to reach the center of the platform before it stops. The net torque about the origin, assuming that the angular momentum is conserved, is Iα = τ, or, assuming that the angular momentum is conserved,T2−T1=IwoR2wR2+mr2αT2 = Mg/2 + Mv/RT1 = (M + m)g/2Let a be the speed of the platform just after the woman reaches the center, which is given by a = v + αr. This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

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(a) The RMS output voltage of the transformer is 12 V.

(b) The power delivered to the DVD player is 0.42 watts.

(e) If the transformer had an efficiency of 86.0%, the current drawn from the house outlet would be approximately 4.07 mA.

An electrical device known as a transformer enables the flow of energy by varying the voltage level. Alternating current (AC) from one circuit is taken, the voltage is adjusted, and the energy is then transferred to another circuit.

(a) We can utilize the transformer's turns ratio to get its RMS output voltage. The secondary voltage is one-tenth of the primary voltage according to the turns ratio

N2/N1 = 1:10.

The secondary voltage can be calculated using the formula below if the primary voltage is 120 V (rms).

Secondary voltage = (1/10) * 120 V = 12 V

Therefore, the RMS output voltage of the transformer is 12 V.

(b) The following formula can be used to determine the amount of power sent to the DVD player:

Power (P) = Voltage (V) * Current (I)

The transformer's RMS voltage is computed to be 12 V in section (a), and the RMS current drawn from the home outlet is represented as 35.0 mA.

Changing the current's unit to amperes:

35.0 mA = 35.0 * 10^(-3) A = 0.035 A

The power delivered to the DVD player can now be calculated as follows:

Power (P) = 12 V * 0.035 A = 0.42 W

Therefore, the power delivered to the DVD player is 0.42 watts.

(e) Only 86.0% of the input power would be transmitted to the output if the transformer had an efficiency of 86.0%. The following formula determines a transformer's effectiveness:

Efficiency = (Output Power / Input Power) * 100

This formula can be changed to determine the input power:

Input Power = (Output Power / Efficiency) * 100

The output power is 0.42 W, and the efficiency is 86.0%, as we already know. These values can be substituted into the formula to determine the input power:

Input Power = (0.42 W / 86.0%) * 100 = 0.488 W

Now, we must utilise the input power and the primary voltage to determine the current drawn from the home outlet.

Power (P) = Voltage (V) * Current (I)

Substituting the values, we can find the current (I):

0.488 W = 120 V * I

I = 0.488 W / 120 V = 0.00407 A

Converting the current to milliamperes:

0.00407 A = 4.07 mA

Therefore, if the transformer had an efficiency of 86.0%, the current drawn from the house outlet would be approximately 4.07 mA.

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Answer:

We found out more about how the universe had started (Big Bang theory), how the planets were created and how stars are born.

Answer:

2m/s

Explanation:

Given parameters:

Mass of truck  = 9000kg

Kinetic energy = 18000J

Unknown:

Speed  = ?

Solution:

Kinetic energy is the energy due to the motion of a body;

  K.E  = \(\frac{1}{2}\) mv²  

 So;

 m is the mass

  v is the speed

   2 KE = mv²

  2 x 18000 = 9000 x v²

     v²  = 4

     v = 2m/s

Answer:

Explanation:

Density=mass÷volume

=45÷3

=15

The space station ISS orbits the Earth approximately every 90 minutes. That is, the space station he orbits the Earth about 16 times in 24 hours a day.

The International Space Station is the largest modular space station in low earth orbit. Five space agencies are involved in this project.

These include NASA in the United States, Roscosmos in Russia, JAXA in Japan, ESA in Europe, and his CSA in Canada. Each orbit takes 90-93 minutes, so there are about 16 orbits per day (24 hours). Depending on the altitude of the ISS, the exact number of orbits per day is usually less than 16 (typically 15.5-15.9 orbits per day). 

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The correct answer is 3. 2.7 × 106 N/C.

To determine the strength of the electric field at a certain distance from a charged object, we can use Coulomb's law and the formula for electric field intensity. Coulomb's law states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

The formula for the electric field intensity (E) due to a point charge is given by:

E = k * (Q / \(r^2\))

Where:

E is the electric field intensity

k is Coulomb's constant (k = 9 x \(10^9\) Nm²/C²)

Q is the charge

r is the distance from the charge

In this case, we are given a charge of 12 µC (microcoulombs) and a distance of 0.020 m. Plugging these values into the formula, we get:

E = (9 x \(10^9\) Nm²/C²) * (12 x \(10^{-6}\) C) / (0.020 m)²

Simplifying the calculation, we find:

E = (9 x \(10^9\) Nm²/C²) * (12 x \(10^{-6}\) C) / (0.020 m)²

  = (9 x \(10^9\) Nm²/C²) * (12 x \(10^{-6}\) C) / (0.0004 m²)

  = 108 N/C * 12 x \(10^{-6}\) C / 0.0004 m²

  = 108 N/C * 0.012 C / 0.0004 m²

  = 1296 N/C / 0.0004 m²

  = 3240000 N/C

Therefore, the strength of the electric field at a distance of 0.020 m from a 12 µC charge is 3,240,000 N/C.

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The sentence can constitute the inequality in the quotient of more than a few and four.2 is less than or identical to 21.

A quotient is a quantity produced by the division of numbers. The quotient has extensive use throughout mathematics and is generally called the integer part of a department, or as a fraction or a ratio.

The range we reap when we divide one quantity via some other is the quotient. as instance, in 8 ÷ 4 = 2; here, the end result of the department is 2, so it's miles the quotient. eight is the dividend and 4 is the divisor.

The quotient of department trouble is determined with the aid of dividing the dividend through the divisor. this can be accomplished thru repeated subtraction or long division. it's far possible to find the quotient of two integers,  fractions, or two algebraic terms.

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Answer:

What is 120 °F in °C ?

48.8889

120°F is equal to 48.9°C. To convert the temperature from Fahrenheit (°F) to Celsius (°C), we use the formula : °C = (°F - 32) * 5/9

Fahrenheit to Celsius formula represents the conversion of degree Fahrenheit to degree Celsius and the formula for Fahrenheit to Celsius is as °C = [(°F-32)×5]/9.

To convert temperature from Fahrenheit (°F) to Celsius (°C),  we can use this formula: °C = (°F - 32) * 5/9

Given 120 °F:

Now, °C = (120 - 32) * 5/9

°C = 88 * 5/9

So, °C = 48.9 °C

Hence, 120 °F is approximately equal to 48.9 °C.

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Answer:

94.5kJ

Explanation:

To calculate the energy released by the thermal energy store associated with the water cooling, we can use the following formula:

Q = mcΔT

where Q is the energy released, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

We first need to calculate the temperature change of the water. The initial temperature of the water is the boiling point of 100°C, and the final temperature is the room temperature of 25°C. Therefore, the temperature change is:

ΔT = (25°C - 100°C) = -75°C

Note that the temperature change is negative because the water is cooling down.

Next, we can substitute the given values into the formula and solve for Q:

Q = (0.3 kg) x (4200 J/kg°C) x (-75°C)

Q = -94500 J

The negative sign indicates that energy is released by the thermal energy store associated with the water cooling. Therefore, the energy released is 94,500 J, or approximately 94.5 kJ.

Answer:

300x480 teaspoons

Explanation:

when converting cups to teaspoons just multiply by 48

Answer:

The answer should be 3tsp

Explanation:

3tsp

Let's call the length of the race track as "x".

To solve for "x", we can use the formula:

\(\implies\text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

Since the race ends in a tie, we know that Jan and Mary both took the same amount of time to run the race. Let's call this time "t".

\(\implies \text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

\(\implies t = \dfrac{x - 25}{7.5}\)

\(\implies\text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

\(\implies t = \dfrac{x}{8.0}\)

Since both expressions represent the same time, we can set them equal to each other and solve for "x":

\(\implies \dfrac{x - 25}{7.5} = \dfrac{x}{8.0}\)

Multiplying both sides by 60 (the least common multiple of 7.5 and 8.0) to get rid of the decimals:

\(\implies 8(x - 25) = 7.5x\)

\(\implies 8x - 200 = 7.5x\)

\(\implies 0.5x = 200\)

\(\implies x = 400\)

\(\therefore\) The length of the race track is 400 meters.

\(\blue{\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}\)

The sound pressure caused by the jackhammer is approximately 2 Pascals (Pa).

To calculate the sound pressure, we can use the given equation for loudness in decibels (dB), which is L = 20 × log10(P/P0), where L is the loudness in dB, P is the sound pressure, and P0 is the reference sound pressure, which is 20 µPa. We have L = 100 dB and need to solve for P.

Rearranging the equation, we get:
P = P0 × 10^(L/20) = 20 × 10^(-6) × 10^(100/20) = 20 × 10^(-6) × 10^5 = 2 Pa

Summary: A jackhammer producing 100 dB of sound from 1 meter away has a sound pressure of approximately 2 Pascals.

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The tension in the rope is 340 N

The x component of the tension triangle is equal to the friction force, 320 N, BUT the tension is not equal to this.

Use Cos 20 degrees = a/H

Where a is 320 N and H will be the tension

If something is at an angle, don't assume it is equivalent to the thing on the other side because of the angle

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Answer:

my answer to that question was c

Explanation:

Answer:

Moon circles the earth

Explanation:

If you were at the sun and looking at the earth, from that point of view the moon appears to circle the earth.

Answer:

The Earth and the Moon both orbit around it together.

Explanation:

The Earth and the Moon both orbit around a common center of mass, called the barycenter, which is located within the Earth. From the point of view of the Sun, it appears that the Earth is orbiting around the barycenter, and the Moon is orbiting around the Earth. In other words, the Earth and the Moon are both in orbit around the Sun, but their paths around the Sun are perturbed by their mutual gravitational attraction. This means that, from the Sun's perspective, it looks like the Earth is orbiting around the Moon, even though the Earth and the Moon are actually both orbiting around the barycenter.

ALLEN

Answer: 853.88m

Explanation:

The 200 calorie donut is really 200 kilocalories or 200000 calories. Each calorie is 4.184 Joules. Therefore, the amount of energy the donut gives the student is 836800 Joules. In order to find the height (displacement) the student would have to climb, use W=Fd or work = force*displacement. We know the work and we can find the force easily with mg. 100kg*9.8m/s^2 = 980N. d = W/F. Therefore, d = 836800J/980N, or 853.88m.

Answer:

b. 4.6 %

Explanation:

From the question,

E = M.A/V.R................ Equation 1

Where E = percentage Efficiency of the machine, M.A = machanical accurancy of the machine, V.R = Velocity ratio of the machine

Make V.R the subject of the equation

V.R = M.A/E

Given: M.A = 3, E = 65% = 0.65

Substitute this values into equation 2

V.R = 3/0.65

V.R = 4.6

Hence the right option is b. 4.6 $

The magnitude of the centripetal acceleration of the car is 0.0314 m/s².

centripetal acceleration

Centripetal acceleration is described because the assets of the motion of an item, traversing a circular path. Any object that is shifting in a circle and has an acceleration vector pointed in the direction of the center of that circle is referred to as Centripetal acceleration.

a = v²/ r

r = 3500 m (SI unit)

t = 200 s

circumference = C

C = 2 * π * r

C = 2 * 3.141 * (3500 m)

C = 21987 m

v = D / t

v = (21987 m) / (200 s)

v = 109.935 m/s

a = (109.935 m/s)² / (3500 m)

a = (109.935 m/s²) / (3500 m)

a = 0.0314 m/s²

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The deceleration for a car traveling at 55 km/h can be interpolated to be 7.06 m/s².

A) To find whether the car will stop in time or not, we have to use the below formula:Where,

t = time taken to stop

v = initial velocity

u = final velocity

a = deceleration distance = vt + 0.5at²

We can use the above formula and find the distance covered by the car before stopping.

If the distance covered by the car is less than 40 m, then the car will stop in time and the child will be saved. If the distance is greater than or equal to 40 m, then the car will not be able to stop in time and the child will be hit.

For a car traveling at 55 km/h, the speed is 15.28 m/s. The deceleration values for different cars can be found from the table below:Speed (m/s) Braking Distance Toyota Corolla
(m) Nissan 200SX
(m) Mercedes C36
(m) Ferrari550 Maranello
(m) Lexus LS400
(m)60 14.9 17.2 20.1 24.8 16.070 20.3 23.4 27.4 33.8 21.880 26.5 30.6 35.8 44.1 28.490 33.6 38.7 45.3 55.8 36.0100 41.5 47.8 55.9 68.9 44.4110 50.2 57.8 67.7 83.4 53.8120 59.7 68.8 80.5 99.2 64.0

Therefore, Interpolation shows that the deceleration for an automobile moving at 55 km/h is 7.06 m/s2. .

Using the formula for deceleration with initial velocity of 15.28 m/s, we get the distance covered by the car before stopping to be:distance = (15.28)² / 2 * 7.06 = 19.68 m

As the distance covered by the car is less than 40 m, the car will stop in time.

B) The limitations of this model are:This model assumes that the car is traveling on a flat surface and the road conditions are good.

The model does not take into account the reaction time of the driver and assumes that the driver reacts immediately to the child running onto the road.

The model does not take into account the age of the vehicle, the weight of the vehicle, the condition of the brakes and tires, and other factors that may affect the braking distance of the car.

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False. Meissner's corpuscles do not sense deep pressure.

Meissner's corpuscles, also known as tactile corpuscles, are specialized sensory receptors located in the dermal papillae of the skin, particularly in areas with high tactile sensitivity such as the fingertips, palms, and soles of the feet. They are most sensitive to light touch, fluttering sensations, and fine textures. Meissner's corpuscles are especially responsive to low-frequency vibrations.

However, when it comes to deep pressure, other sensory receptors are responsible for detecting and relaying this information to the brain. Pacinian corpuscles, located deeper in the skin and within connective tissue, are specialized receptors that sense deep pressure and high-frequency vibrations. These receptors are larger and more responsive to mechanical forces associated with deep pressure.

In summary, Meissner's corpuscles are not involved in sensing deep pressure. They are primarily associated with light touch and fine tactile discrimination, while Pacinian corpuscles are the receptors specialized for deep pressure sensations.

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The minimum force (Fmin) required to move the block up the ramp is 12.7 N.

Mass of the block (m) = 3.3 kg

Angle of the ramp (θ) = 37°

Coefficient of friction between the block and the ramp (μg) = 0.44

Coefficient of kinetic friction between the block and the ramp (uk) = 0.30

Step 1: Resolve the forces acting on the block.

The weight of the block (mg) can be resolved into two components:

- The force acting parallel to the incline (mg*sinθ)

- The force acting perpendicular to the incline (mg*cosθ)

Step 2: Calculate the force of friction.

The force of friction can be calculated using the equation:

Force of friction (Ff) = μg * (mg*cosθ)

Step 3: Determine the minimum force required.

To move the block up the ramp, the applied force (Fapplied) must overcome the force of friction.

Thus, the minimum force required (Fmin) is given by:

Fmin = Ff + Fapplied

Step 4: Substitute the given values and calculate.

Ff = μg * (mg*cosθ)

Fmin = Ff + Fapplied

Now, let's calculate the values:

Ff = 0.44 * (3.3 kg * 9.8 m/s² * cos(37°))

Ff ≈ 12.717 N

Fmin = 12.717 N + Fapplied

Therefore, the minimum force (Fmin) required to move the block up the ramp is approximately 12.7 N.

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Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm maybe

a) The motion of the object between 15 s to 30 s is increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is 0.167 m/s.

(c) The position of the object at 5.0 seconds is 0.5 m.

(d) Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

(a) The motion of the object between 15 s to 30 s can be described as increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is calculated as;

average velocity = total displacement / total time

average velocity = (2.5 m - 0 m ) / ( 15 s - 0 s ) = 0.167 m/s

(c) The position of the object at 5.0 seconds is calculated as follows;

at 5.0 seconds, the position of the object is traced from the graph as 0.5 m.

(d) The motion of the object between 30 and 40 seconds is calculated as;

velocity = ( 0 m - 4 m ) / ( 40 s - 30 s ) = - 0.4 m/s

Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

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New initial velocity=59.1(5)=295.5m/s

We will use proportions to find the distance.

\(\\ \sf\longmapsto \dfrac{59.1}{70.9}=\dfrac{295.5}{x}\)

\(\\ \sf\longmapsto x=\dfrac{70.9(295.5)}{59.1}\)

\(\\ \sf\longmapsto x=\dfrac{20950.95}{59.1}\)

\(\\ \sf\longmapsto x=354.5m\)

Answer:

Have a blessed day!

Explanation:

The energy to launch the spacecraft came from moving the spacecraft against the magnetic force. The energy used to move a magnet against a magnetic force is stored as potential energy in the magnetic field. This magnetic force can convert potential energy stored in the magnetic field to kinetic energy.

Please give brainliest!

Answer:

Moving the spacecraft against the magnetic force provided the energy needed to launch it. The energy expended to move a magnet against a magnetic force is stored in the magnetic field as potential energy.

Explanation: