A canoe traveled 1200 miles in 25 hours. What was the average speed of the canoe

Answers

Answer 1

Answer:

48 miles / hour

Explanation:

aver. speed = distance / time

                   = 1200 miles / 25 hours

                   = 48 miles / hour


Related Questions

5. Hilda is trying to move a 40 kg couch across a level floor and pushes with a horizontal force of
150 N, but the couch does not move. What is the minimum coefficient of static friction with the
floor? Assume the acceleration due to gravity is g = 9.8 m/s2

Answers

The minimum coefficient of static friction with the floor is 0.3846.

To find the minimum coefficient of static friction with the floor, we need to consider the forces acting on the couch. In this case, the force of gravity is pulling the couch downward with a magnitude of mg, where m is the mass of the couch (40 kg) and g is the acceleration due to gravity (9.8 m/s²).

Since the couch does not move, the force of static friction between the couch and the floor must be equal in magnitude but opposite in direction to the horizontal pushing force of 150 N.

Therefore, we have the equation F_friction = F_push, where F_friction is the force of static friction.

The force of static friction can be calculated using the formula F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.

Since the couch is on a level floor and is not accelerating vertically, the normal force N is equal in magnitude but opposite in direction to the force of gravity, which is mg.

Substituting the values into the equation, we have μs * mg = 150 N.
Solving for μs, we get μs = 150 N / (mg).
Substituting the given values, we have μ_s = 150 N / (40 kg * 9.8 m/s²).
Simplifying, we find that μs = 0.3846.

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A cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed . The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time . a. What is the value of ? b. What is the y position of the cannonball at the time c. Find the initial speed of the projectile.

Answers

a) The value of t u = 140/t`b.

b) The y position of the cannonball at the time t is  55.5 mc.

c) The initial speed of the projectile is 52.4 m/s.

Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.

a. To find the value of t:Here, we have to use the formula of distance

i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`

Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is

(2H) = 2 × 55.5

= 111 m`2H/g

= 111/9.8`

= 11.32653 s

From equation (1),u×t = 140u = 140/t

Therefore, `u = 140/t`b.

b)To find the y position of the cannonball at the time t:

Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,

Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².

We have already calculated the time taken by the cannonball to hit the ground in the previous step.`

y = 140 - (1/2) × 9.8 × t²`

On substituting the value of t as `t = 11.32653`,

we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.

c)  To find the initial speed of the projectile:

To calculate the initial speed of the projectile, we need to use the formula of range of projectile

.i.e.,R = u²sin2θ/g

Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)

u² = R × g/sin2θ

   = 140 × 9.8/sin0°  

   = 2744m²/s²u  

   = \(\sqrt(2744m^2/s^2)\)

   = 52.4 m/s

Hence, the initial speed of the projectile is 52.4 m/s.

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A Carnot engine operates between temperatures of 450 K and 340 K. What is the efficiency of the engine ?

Answers

Who 450 K 265 K……………….

Two 31.49 volt batteries are connected in series. What is the total voltage of the combination ?

Answers

Batteries connected in series add up their voltage.

31.49 +31.49 = 62.98 volt

which equation can be used to solve for acceleration?

which equation can be used to solve for acceleration?

Answers

Answer:

the answer is the first one.

Explanation:

one way to find out is if you look at the other equations they are mixed matched. For an example a=d/t should be s= d/t.

Answer:

a

Explanation:

i did it

Difference between corpuscular theory and wave theory

Answers

Answer:

Explanation:

Isaac Newton argued that the geometric nature of reflection and refraction of light could only be explained if light were made of particles, referred to as corpuscles, because waves do not tend to travel in straight lines.

Given the Coulomb's formula F= ke q1*q2/r^2 where ke= (9.0 * 10^9 N m^2/c^2)

F is the force between charges in Newton, Qr and Q2 are the respective two charges in Coulombs, and r is the distance in meters. Calculate the distance between two charges of 20μc and 18μC if the force between the two charges is 2.8x10^4 N

Given the Coulomb's formula F= ke q1*q2/r^2 where ke= (9.0 * 10^9 N m^2/c^2)F is the force between charges

Answers

The distance between two charges is 1.075 cm.

Distance between the charges

The distance between the charges is calculated using Coulomb's law as shown below;

F = kq1q2/r²

Fr² = kq1q2

r² = kq1q2/F

r = √( kq1q2/F)

where;

r is the distance between the chargesF is the force of attraction

r = √( 9 x 10⁹ x 20 x 10⁻⁶ x 18 x 10⁻⁶/2.8 x 10⁴)

r = 0.01075 m

r = 1.075 cm

Thus, the distance between two charges is 1.075 cm.

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7. A particle of mass 3 kg is held in equilibrium by two light unextensible strings. One string is horizontal, as shown in Figure 7.30. The tension in the horizontal string is PN and the tension in the other string is N. Find a) the value of 0 b) the value of P.​

Answers

The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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A car is travelling in a straight line and has its velocity uniformly reduced from 20 m * s ^ - 1 to 12m * s ^ - 1 in a distance of 80 m. The car the travels at the lower velocity for 1 minute, and then decelerates uniformly to rest in a further 12 sec. show the whole journey on a velocity-time graph and calculate
(i) the initial deceleration and the time taken to travel 80 m.
(ii) the final deceleration
(iii) the total displacement for the whole journey​

Answers

i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

What is the initial deceleration of the car?

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

v is the initial velocityu is the final velocitya is acceleration/decelerations is the displacement

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

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Explain the light detection technique of photovoltaic detection​

Answers

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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QUESTIONS An athlete, during his race in the 100 m sprint in the 2008 Beijing Olympics, exerted #force of 850 s on the race track using his show on the right foot at an angle of 50/' to the horizontal, 850 N 3.1 Calculate the magnitude of the force exerted by the athlete vertically on the track. 3.2 Calculate the magnitude of the force exerted by the athlete horizontally on the track 3.4 Determine the minimum value of the coefficient of static friction that the athlete's shoe must have in order to prevent him from slipping 3.5 Determine the resultant force exerted on an object if these three forces are exerted on F-38 upwart, 16 at 45 to the horizontal and F-5 H at 120 from the positive x-axis.​

Answers

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

an electromagnetic wave has an electric field with peak value 120. What is the averge energy delievered to a surface

Answers

Answer:

The average energy delivered to a surface is 19.116 W/m².

Explanation:

Given;

maximum electric field, E₀ = 120 v/m

The average energy delivered by the wave to a surface is given by

\(I_{avg} = \frac{c\epsilon_ o E_o^2}{2}\)

where;

c is the speed of light, = 3 x 10⁸ m/s

ε₀ is the permittivity of free space = 8.85 x 10⁻¹² c²/Nm²

\(I_{avg} = \frac{c\epsilon_ o E_o^2}{2} \\\\I_{avg} = \frac{(3*10^8)(8.85*10^{-12})( 120)^2}{2}\\\\ I_{avg} =19.116 \ W/m^2\)

Therefore, the average energy delivered to a surface is 19.116 W/m².

How has Physics improved
or affected our society?

Answers

By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life

From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.

The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.

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If a third resistor is added in a parallel to the other 2 resistors, How will that affect the brightness of the original 2 light bulbs?

Answers

The original two light bulbs will appear brighter when the third resistor is added in parallel.

When a third resistor is added in parallel to the other two resistors in a circuit, it will have an impact on the overall brightness of the original two light bulbs.

In a parallel circuit, each resistor has its own branch connected to the power source. The current flowing through each branch is inversely proportional to the resistance of that branch. Adding a third resistor in parallel means an additional path for current to flow.

The introduction of the third resistor reduces the total resistance of the circuit. As a result, the total current drawn from the power source increases, as per Ohm's Law (I = V/R). The increased current is distributed among the parallel branches, including the original two light bulbs.

Since the current through the bulbs is now greater, their brightness will also increase. This is because the brightness of an incandescent light bulb is directly proportional to the current passing through it.

It's worth noting that the specific effect on brightness depends on the resistance values of the resistors and the characteristics of the light bulbs. However, in general, adding a resistor in parallel reduces the overall resistance, increases the current, and subsequently enhances the brightness of the light bulbs in the circuit.

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The "Screaming Swing" is a carnival ride that is - not surprisingly - a giant swing. It's actually two swings moving in opposite directions. At the bottom of its arc, a rider in one swing is moving at 34 m/s with respect to the ground in a 46- m -diameter circle. The rider in the other swing is moving in a similar circle at the same speed, but in the exact opposite direction. What is the acceleration, in m/s2 , that riders experience?

Answers

The acceleration, in m/s² , that riders experience is 50.3 m/s²

What is the acceleration, in m/s² , that riders experience?

Since the riders move in a circle, they undergo circular motion and will have a centripetal acceleration.

So, the centripetal acceleration, is given by a = v²/r where

v = speed of rider andr = radius of circle

Given that a rider in one swing is moving at 34 m/s with respect to the ground in a 46- m -diameter circle. We have that

v = speed of rider = 34 m/s and r = radius of circle = 46/2 = 23 m

So, substituting the values of the variables into the equation for the acceleration, we have

a = v²/r

a = (34 m/s)²/23 m

a = 1156 m²/s²/23 m

a = 50.26 m/s²

a ≅ 50.3 m/s²

So, the acceleration, in m/s² , that riders experience is 50.3 m/s²

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If the Sun’s mass increased, how would the gravity between the Sun and Earth change?
Possible Answers :
1. It would increase
2. It would decrease
3. It would not change

Answers

Answer:

1. increase

Explanation:

Mass is proportional to gravity. The bigger two objects are, the stronger the force of gravity between them will be.

12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.

Answers

The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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Pls help me 10 points

Pls help me 10 points

Answers

Answer:

d is the right answer

it's was helpful to you

three difference between boiling and temperature of a liquid.​

Answers

When a liquid is boiling that means it has gotten heated to the point where the oxygen particles start rising towards the top of the liquid.

When a liquid has a temperature (as it always will) it can be read, however, a liquid does not need to be hot to have a temperature.

A liquid requires an extremely high level of heat (thermal energy) to begin boiling, while a liquid doesn't require any heat to have a temperature.

The difference between the two is that boiling requires high heat and a temperature doesn't require heat (That is 3 total the ones above count).

Hope this helps and have a nice day.

-R3TR0 Z3R0

What is the maximum wavelength of light needed to eject electrons from a metal whose work function is 4.48 eV? What is the frequency of the light?

Answers

Given,

The work function of the metal, W=4.48 eV

The work function is given by the formula,

\(W=h\upsilon_0\)

Where ν₀ is the threshold frequency of the metal.

But the frequency is related to wavelength as,

\(\upsilon=\frac{c}{\lambda}\)

Where c is the speed of light and λ is the wavelength.

Thus the work function will be,

\(W=\frac{hc}{\lambda_0}\)

Where λ₀ is the maximum wavelength needed to eject the electron from the given metal.

On substituting the known values in the above equation,

\(\begin{gathered} 4.48\times1.6\times10^{-19}\text{ J}=\frac{6.63\times10^{-34}\text{ Js}\times3\times10^8\text{ m/s}}{\lambda_0} \\ \Rightarrow\lambda_0=\frac{6.63\times10^{-34}\text{ Js}\times3\times10^8\text{ m/s}}{_{}4.48\times1.6\times10^{-19}\text{ J}} \\ =277.48\times10^{-9}\text{ m} \end{gathered}\)

Thus the maximum wavelength of the light required is 277.48 nm.

The frequency of the light is,

\(\begin{gathered} \upsilon_0=\frac{c}{\lambda_0} \\ =\frac{3\times10^8}{277.48\times10^{-9}} \\ =1.08\times10^{15}\text{ Hz} \end{gathered}\)

Thus the frequency of the required light is 1.08×10¹⁵ Hz.

Which statement accurately describes a magnetic object? :
HURRY I WILL GIVE BRAINLIEST


A: They have many spinning electrons oriented in the same direction that create magnetic fields.


B: They have more electrons than non-magnetic materials that create magnetic fields.


C: Non-paired electrons spin in opposite directions that create a magnetic field.


D: Paired electrons spin in opposite directions to create a magnetic field.

Answers

The correct statement which best describes a magnetic object from among the options above is:

They have many spinning electrons oriented in the same direction that create magnetic fields.

The correct answer choice is option a.

How magnetic object carry their electrons in the same direction in a a magnetic field.

When magnetic material spins its electrons in the same axis in the magnetic field, the force of current which passes through the same direction results in the attraction which exists between the magnetic object and magnetic substance.

So therefore, we can now confirm that when we consider the orientation of electrons of magnetic material in a direction similar to field, it causes attraction.

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Why must humans limit their exposure to X-rays and gamma rays?

Answers

Answer:

The US Environmental Protection Agency (EPA) sets limits for exposure to x-rays and gamma rays in part because it recognizes that this form of radiation can cause cancer.

Explanation:

Humans  must limit their exposure to X-rays and gamma rays because these rays have huge penetrating power and it may ionize our body which may lead to cancer.

What are the health effects of ionizing radiation?

The amount of radiation received, or the absorbed dose, which is measured in a unit called the grey (Gy), determines whether or not tissue and/or organs will be damaged by radiation. The radiation type and sensitivity of various tissues and organs determine the possible harm from an absorbed dosage.

The ability of ionizing radiation to harm people is measured using the effective dosage. The unit of effective dose that takes into account the radiation type and sensitivity of tissues and organs is the sievert (Sv). It is a method for gauging the danger potential of ionising radiation. The Sv considers the radiation type and the sensitivity of tissues and organs.

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What system includes the system that starts the vehicle?

Answers

Explanation:

The electrical system provides the voltage necessary to operate the many electrical components on the vehicle such as the vehicle's lighting system. The main source of power for the electrical system is the battery. The electrical system also includes the starting system and the charging system.

The system that includes the system that starts the vehicle is known as the electrical system.

The electrical system is comprised of the alternator, battery, and starter. Each part plays a role in getting a car to work and its power is later reciprocated so that the car can start. It’s a good thing to think on this in relation to the human body; the electrical system in a way is like the heart because it provides energy for everything to successfully function.

Which two factors affect the amount of thermal energy an object has?
A. The amount of motion its particles have
B. The mass of the object
c. The directions in which its particles are moving
D. The amount of space between its particles

Answers

The two factors that affect the amount of thermal energy an object has are;

A. The amount of motion its particles haveD. The amount of space between its particles

What is thermal energy?

Thermal energy  can be regarded as the energy which is been contained within a system it can be considered as the one that is responsible for its temperature.

It should be noted that the Heat is the flow of thermal energy and it can be seen as opne that deals with how heat is transferred between different systems .

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What is the displacement from t=1s and t=5s on the graph?

What is the displacement from t=1s and t=5s on the graph?

Answers

The displacement from  t=1s and t=5s on the graph is zero.

What is displacement?

Displacement refers to the distance and direction of an object's change in position from its initial position to its final position. It is a vector quantity that indicates the shortest distance between the starting point and ending point of an object's motion, regardless of the path taken.

Displacement is often denoted by the symbol Δx, where Δ represents the change in position and x represents the position. The SI unit of displacement is meters (m) or any other unit of length.

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The position x of a particle moving along x axis varies with time t as x = Asin(wt) , where A and w are constants . The acceleration of the particle varies with its position as

\( \small \red{ \rm Nonsense = Report} \checkmark\)

Answers

Let's see

\(\\ \rm\Rrightarrow x=Asin(\omega t)\dots(1)\)

Now we know the formula of acceleration

\(\\ \rm\Rrightarrow \alpha=-A\omega^2sin(\omega t)\)

\(\\ \rm\Rrightarrow \alpha=-Asin(\omega t)\times \omega^2\)

From eq(1)

\(\\ \rm\Rrightarrow \alpha=-x\omega^2\)

Or

\(\\ \rm\Rrightarrow \alpha=-\omega^2x\)

Given that the position x of a particle along X-axis varies with time t by the equation:

\({:\implies \quad \sf x=A\sin (\omega t)}\)

As it defines the position, so x is just displacement here, and we need to find the acceleration first for telling with what if varies, so by definition, the second differential coefficient of displacement is acceleration, so differentiating both sides w.r.t.x of the above equation in accordance with chain rule we have:

\({:\implies \quad \sf \dfrac{dx}{dt}=A\cos (\omega t)\cdot \omega \cdot \dfrac{dt}{dt}}\)

\({:\implies \quad \sf \dfrac{dx}{dt}=A\omega \cos (\omega t)}\)

Differentiating both sides w.r.t.x by chain rule again to get the 2nd order derivative

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-A\omega \sin (\omega t)\cdot \omega \dfrac{dt}{dt}}\)

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-A\omega^{2}\sin (\omega t)}\)

Re-write as :

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-\omega^{2}\{A\sin (\omega t)\}}\)

Can be further written as

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-x\omega^{2}}\)

This is the Required answer

If they ask you the differential equation for the acceleration of a wave (as the given equation was general equation of a wave), you can simply write:

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}+x\omega^{2}=0}\)

The Supreme Court decision in Brown v. Board of Education, which desegregated schools, is an example of judicial activism.

True

False

Answers

It’s true that’s the answer

In hiking, what fitness component is required of you

Answers

It’s strength, endurance and flexibility. Hope this helps

Plaskett's binary system consists of two stars that revolve In a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal . Assume the orbital speed of each star is |v | = 240 km/s and the orbital period of each is 12.5 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 times 1030 kg Your answer cannot be understood or graded.

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass is    \(M =1.43 *10^{32} \ kg\)

Explanation:

From the  question we are told that

       The mass of the stars are \(m_1 = m_2 =M\)

        The orbital speed of each star is  \(v_s = 240 \ km/s =240000 \ m/s\)

         The orbital period is \(T = 12.5 \ days = 12.5 * 2 4 * 60 *60 = 1080000\ s\)

The centripetal force acting on these stars is mathematically represented as

      \(F_c = \frac{Mv^2}{r}\)

The gravitational force acting on these stars is mathematically represented as

      \(F_g = \frac{GM^2 }{d^2}\)

So  \(F_c = F_g\)

=>        \(\frac{mv^2}{r} = \frac{Gm_1 * m_2 }{d^2}\)

=>      \(\frac{v^2}{r} = \frac{GM}{(2r)^2}\)

=>      \(\frac{v^2}{r} = \frac{GM}{4r^2}\)

=>    \(M = \frac{v^2*4r}{G}\)

The distance traveled by each sun in one cycle is mathematically represented as

     \(D = v * T\)

      \(D = 240000 * 1080000\)

      \(D = 2.592*10^{11} \ m\)

Now this can also be represented as

      \(D = 2 \pi r\)

Therefore

                  \(2 \pi r= 2.592*10^{11} \ m\)

=>   \(r= \frac{2.592*10^{11}}{2 \pi }\)

=>    \(r= 4.124 *10^{10} \ m\)

So  

       \(M = \frac{v^2*4r}{G}\)

=>    \(M = \frac{(240000)^2*4*(4.124*10^{10})}{6.67*10^{-11}}\)

=>    \(M =1.43 *10^{32} \ kg\)

       

     

Plaskett's binary system consists of two stars that revolve In a circular orbit about a center of mass

A man is standing away from the School
Building at a distance of
300m . He claps his hands and hears an echo calculate the time interval of him hearing his echo

Answers

The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

What do you mean by echo?

An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.

The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.

To calculate the time interval, we can use the following formula:

time = distance / speed

where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.

distance = 2 x 300m = 600m

speed = 343 m/s

time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)

Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

Learn more about echo here:

https://brainly.com/question/9527413

#SPJ9

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