a cannon launches a 3.0\,\text {kg}3.0kg3, point, 0, start text, k, g, end text pumpkin with 110\,\text j110j110, start text, j, end text of kinetic energy. what is the pumpkin’s speed?

Yes every electromagnetic wave moves at a speed of 300000000 m/s. Through empty space, all electromagnetic waves move at the same speed. The speed of light is approximately 300,000,000 meters per second (3.0 x 10^8 m/s).

It is known that nothing else in the known cosmos moves thus quickly. Even moving at the speed of light, the Sun's beams take roughly 8 minutes to reach the Earth. Electromagnetic waves move at a speed of about 300,000,000 m/s.

In the void of space, all electromagnetic waves move at a speed of 300,000 km/s. Because they do not require molecules to move, electromagnetic waves differ from sound waves in this regard. This implies that electromagnetic waves can go through solid substances, such as air, as well as across space.

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Andrea, a 63.0-kg sprinter, starts a race with an acceleration of 4.2 m/s2, The net external force on the sprinter is 264.6 N.

According to Newton's second law of motion, the net external force acting on an object is equal to the product of its mass and acceleration. In this case, the mass of the sprinter is given as 63.0 kg, and the acceleration is 4.2 m/s².

Net external force (F) = mass (m) × acceleration (a)

Substituting the given values:

F = 63.0 kg × 4.2 m/s²

Calculating the product:

F = 264.6 N

Therefore, the net external force on the sprinter is 264.6 N. This force is responsible for accelerating the sprinter according to her mass. It's important to note that the net external force includes all forces acting on the sprinter, such as the force applied by her muscles, air resistance, and friction with the ground.

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Answer:

if it is totally frictionless you can only need to throw the hockey stick to one other side and wait for yourself to move slowly to the other side. this will happen by the law of conservation of momentum and Newton's First law (continues to move in the uniform velocity without external I. e. friction, Force).

Answer:

C. 2.5 g/ml

Explanation:

Divide mass by volume

True. Humidity refers to the amount of water vapor present in the air. It is a measure of the moisture content in the atmosphere.

Humidity is a measurement of the quantity of water vapour in the atmosphere. Water vapour, the gaseous form of water, is frequently imperceptible to the unaided eye. The humidity foretells the presence of precipitation, dew, or fog.

The temperature and pressure of the system of interest affect humidity. In comparison to warm air, chilly air has a greater relative humidity when the same amount of water vapour is present. The dew point is another relevant variable. As the temperature rises, more water vapour is required until saturation is reached. A parcel of air will ultimately approach saturation as its temperature drops, without adding or losing water mass.

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(a) The normal force on the sleigh is 596.36 N.

(b) The magnitude and direction of acceleration of the sleigh is 3.2 m/s² upwards.

The given parameters;

The normal force on the sleigh is calculated as follows;

\(F_n = mg \times cos(\theta)\\\\F_n = 63 \times 9.8 \times cos(15)\\\\F_n = 596.36 \ N\)

The magnitude and direction of acceleration of the sleigh is calculated as follows;

\(\Sigma F= ma\\\\F - mgsin(\theta) - F_f = ma\\\\F - mgsin(\theta) - \mu F_n = ma\\\\510\ - \ 63 \times 9.8 \times sin15 \ -\ 0.25\times 596.36 = 63a\\\\201 .11 = 63a\\\\a = \frac{201.11}{63} \\\\a = 3.2 \ m/s^2 \ upwards\)

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A dark-colored rock that forms a straight line on the surface is most likely a type of igneous or metamorphic rock that has been exposed by erosion or weathering. The straight line could be a result of a geological feature such as a fault, joint, or fracture where the rock was broken and then later exposed.

One specific type of rock that commonly forms straight lines on the surface is basalt. Basalt is a dark-colored volcanic rock that often forms columns due to the cooling and contraction of lava as it solidifies. These columns can create straight lines or polygonal shapes on the surface of the rock. Other types of igneous or metamorphic rocks, such as gabbro, diabase, or schist, could also potentially form straight lines on the surface.

It's worth noting that without additional information or a visual reference, it can be difficult to accurately identify the type of rock based solely on the description of its appearance.

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A car that has a forward thrust of 3kN and accelerates from 20 m/s to 40 m/s in 10 s has a mass of 1500 kg. Thus, the mass of the car is the 1500 kg

From the question, we are to calculate the mass of the car.

From Newton's second law of motion, we have that

F = ma

Where F is the Net force

m is the mass

and a is the acceleration

Also, from one of the equations of linear motion, we have that

v = u + at

Then, we can write that

\(a = \frac{v-u}{t}\)

Where v is the final velocity

u is the initial velocity

a is the acceleration

and t is the time taken

Therefore,

\(F = m\frac{(v-u)}{t}\)

From the given information,

u = 20 m/s

v = 40 m/s

t = 10 s

F = 3 kN = 3000 N

Putting the parameters into the equation, we get

\(3000 = m \frac{(40-20)}{10}\)

\(3000 = m \times \frac{20}{10}\)

3000 = 2m

Then,

m = 3000 ÷ 2

m = 1500 kg

Hence, the mass of the car is the 1500 kg.

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Answer:

-25

Explanation:

To solve this all you need to do is find the difference the difference between 35 and 10 is 25 however the number is getting smaller so this is negative displacement, therefore it is -25 displacement.

The ant’s aunt travels from the 35.00 cm mark to the 10.00 cm mark. The Aunt’s displacement is 25 cm.

Displacement is vector quantity. It has both magnitude and direction. It is expressed in m. Displacement is nothing but distance from mean position. Main difference between distance and displacement is distance is a total distance travelled by a body and displacement is distance from mean position. for example when a body moves from a point and travels to exact initial point where it has started, then distance will be the total distance it has travelled and displacement is zero cause mean position of point and final position of points are same.

Displacement is given by,

x = x₂ - x₁

where x₂ is final position and  x₁ is initial position.

given,

x₂ = 10 cm

x₁ = 35 cm

Displacement x = 10-35 = -25 cm

negative sign represents, ant is moving in negative x direction.

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The ant’s travels from the 35.00 cm mark to the 10.00 cm mark. The Aunt’s displacement is 25 cm.

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The least possible uncertainty in a measurement of the speed of an electron in an atom of lead, expressed as a percentage of the average speed, is approximately 0.85%.

The uncertainty in the measurement of the speed of an electron can be determined using the Heisenberg uncertainty principle, which states that there is a fundamental limit to the precision with which certain pairs of physical properties, such as position and momentum, can be known simultaneously. Mathematically, the uncertainty principle is expressed as:

\(\(\Delta x \cdot \Delta p \geq \frac{h}{4\pi}\)\)

where \(\(\Delta x\)\) is the uncertainty in position, \(\(\Delta p\)\) is the uncertainty in momentum, and h is the reduced Planck's constant.

In this case, we are interested in the uncertainty in the speed of the electron, which is related to its momentum. The momentum of an electron can be approximated as \(\(p = m \cdot v\)\), where m is the mass of the electron and v is its velocity. Since the mass of the electron remains constant, the uncertainty in momentum can be written as:

\(\(\Delta p = m \cdot \Delta v\)\)

To find the uncertainty in velocity, we can rearrange the equation as:

\(\(\Delta v = \frac{\Delta p}{m}\)\)

Now, we can substitute the values given in the problem. The mass of an electron is approximately \(\(9.10938356 \times 10^{-31}\)\) kg, and the average orbital speed is \(\(1.8 \times 10^8\)\) m/s. The uncertainty in velocity can be calculated as:

\(\(\Delta v = \frac{\Delta p}{m} = \frac{\frac{h}{4\pi}}{m} = \frac{h}{4\pi \cdot m}\)\)

Substituting the known values, we get:

\(\(\Delta v = \frac{6.62607015 \times 10^{-34}}{4\pi \cdot 9.10938356 \times 10^{-31}} \approx 2.20 \times 10^{-3}\) m/s\)

Finally, we can express the uncertainty in velocity as a percentage of the average speed:

\(\(\text{Uncertainty \%} = \frac{\Delta v}{\text{Average speed}} \times 100 = \frac{2.20 \times 10^{-3}}{1.8 \times 10^8} \times 100 \approx 0.85\%\)\)

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Answer:

Yeah it's right there from the one next to the exclamation point

Answer:

its not there

Explanation:

its literally not there

Answer:

Sample answer: part 1:

What was your hypothesis?

This is what you wanted to prove or study with the experiment. Reading the question I can see that the experiment seems to study the relation between the viscosity of honey and the temperature, so the hypothesis may be something like:

"The viscosity of honey decreases as temperature increases".

According to your data, do you think your hypothesis was correct?

Here you need to see your experimental data, probably, you found that yes, as you increase the temperature the viscosity decreases.

The last thing we need to do here is to summarize difficulties and problems that you had in the experiment, and propose how you could solve them in order to have a better experiment.

Obviously, this depends on how you performed the experiment, but for example, if you saw that the temperature of the honey increased too fast, you could say:

"one problem was that the temperature of the honey increased too fast"

And one way to solve that would be submerging the honey in a water bath so the temperature increases a bit slower.

part 2:

Viscosity depends strongly on temperature, but this relation depends also on the given material.

Generally, we would see that the viscosity decays exponentially as the temperature increases.

So for the first question:

What effect did the temperature have on the viscosity of the honey?

You should have seen that, as the temperature increased, the viscosity decreased.

Now, we need to give some practical examples where knowledge of viscosity is important.

The first one is for cleaning: We know that if we increase the temperature, the viscosity decreases. Thus if we have some object with some viscous thing on it, increasing the temperature will cause it to be easier to clean.

Another example is to store/transport viscous things, for example, honey, it is actually a lot easier to pour honey in bottles if you first heat it a little, so it becomes less viscous.

So there you have two examples where knowing about viscosity (and how it relates to temperature) may be important.

Explanation:

Answer:  

Explanation:

at first the rock is at rest so initial velocity is zero
after accelerating it reaches a final velocity
we are supposed to find that final velocity


\(v^{2} = u^{2} +2ax\)
v= final velocity
u= initial velocity
x= distance
a= acceleration

\(v^{2} = 0^{2} + 2(9.8)(14.4)\)
\(v^{2} = 282.24\)
\(v= \sqrt{282.24}\)
\(v= 16.8 m/s\)

Answer:

Velocity = 6.89 m/s

Explanation:

The equation for momentum: \(Momentum=(Mass)(Velocity)\)

Substitute the given information into the equation and solve for velocity.

\(239.5=34.75(Velocity)\\\frac{239.5}{34.75}=\frac{34.75(Velocity)}{34.75\\}\\6.89=Velocity\)

Answer:

the bottom one is wollsiegel

Answer:

open the dictionary/glossary. it will give you the definitions of the words there.

Explanation:

Answer:

i think it goes like this

Explanation:

Answer:

The correct answer is - do nothing.

Explanation:

If two same or identical objects, in this instance two glass rods, were rubbed together they neither attract nor repel each other as there is no transfer of electrons from one material to the other material as there is no difference in their charges.

Only two different objects are able to transfer electrons from one material to the other material if rubbed together, to produce the conditions for static electricity to be observed. Therefore there would be no charge on the glass rod so there would be no charge to balls to repel or attract.

Answer:

B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.

Explanation:

From Physics we get that resultant velocity of an airplane is the sum of an absolute velocity and a relative velocity, that is:

\(\vec v_{A} = \vec v_{W}+\vec v_{A/W}\) (Eq. 1)

Where:

\(\vec v_{W}\) - Wind velocity, measured in meters per second.

\(\vec v_{A/W}\) - Airplance velocity relative to wind, measured in meters per second.

\(\vec v_{A}\) - Airplane velocity, measured in meters per second.

If we assume that \(\vec v_{W} = 20\,\hat{i}\,\,\,\left[\frac{m}{s} \right]\) (The airplane flies with the wind), \(\vec v_{A/W} = 130\,\hat{i}\,\,\,\left[\frac{m}{s} \right]\), then the resultant velocity of the airplane is:

\(\vec v_{A} = 20\,\hat{i}+130\,\hat{i}\,\,\,\left[\frac{m}{s} \right]\)

\(\vec v_{A} = 150\,\hat{i}\,\,\,\left[\frac{m}{s} \right]\)

Therefore, correct answer is B.

Answer:

B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.

Explanation:

Answer:

Explanation:

Discussion

The ones that are certain are

If you have a normal, and the player slides into 2nd, and stops (which he must before he is tagged), then there must be friction involved. There must be gravity, or he would keep going up.

I don't think there is tension. There might be some Air Resistance, but that force is very tiny. Don't be surprised if you answer includes Air Resistance, but I won't try it to begin with.

Answer:

3.54 x 10^-7 coulombs

Explanation:

The magnitude of the charge can be determined using the formula:

Electric field intensity (E) = Force (F) / Charge (q)

Rearranging the formula, we get:

Charge (q) = Force (F) / Electric field intensity (E)

Substituting the given values, we get:

Charge (q) = 0.137 N / (3.87 x 10^5 N/C)

q = 3.54 x 10^-7 C

Therefore, the magnitude of the charge is 3.54 x 10^-7 coulombs.

1. Time in the air:

When the ball is tossed upward, it reaches its maximum height and then falls back to the ground. The time it takes for the ball to reach its maximum height and fall back down is equal to the total time the ball is in the air.

To find the time in the air, we can use the equation for vertical motion:

h = u*t + (1/2)*g*t^2 ,

where:

h = height

u = initial velocity

g = acceleration due to gravity (approximately 9.8 m/s^2)

t = time

Since the ball starts from an initial height of 1.8 m and reaches the same height on its way back down, we can set the height (h) equal to 0:

0 = (21 m/s)*t + (1/2)*(9.8 m/s^2)*t^2

Rearranging the equation and solving for t using the quadratic formula, we get:

t = (-u ± sqrt(u^2 - 4*(1/2)*g*(0))) / (2*(1/2)*g)

  = (-21 ± sqrt(21^2 - 4*(1/2)*9.8*(0))) / (2*(1/2)*9.8)

 = (-21 ± sqrt(441)) / 9.8

Since we are only interested in the positive value of t, we can ignore the negative solution. Calculating t:

t = (-21 + sqrt(441)) / 9.8

 = (-21 + 21) / 9.8

 = 0 / 9.8

 = 0

Therefore, the ball is in the air for 0 seconds.

2. Maximum height:

The maximum height reached by the ball can be found using the formula:

v^2 = u^2 + 2gh ,

where:

v = final velocity (0 m/s at maximum height)

u = initial velocity (21 m/s upward)

g = acceleration due to gravity (approximately 9.8 m/s^2)

h = height

Solving for h:

0^2 = (21 m/s)^2 + 2*(-9.8 m/s^2)*h

441 = 2*(-9.8)*h

h = 441 / (-19.6)

  ≈ -22.5 m

Since the height cannot be negative in this context, we discard the negative value. Therefore, the maximum height reached by the ball is approximately 22.5 meters above the ground.

3. Velocity when it hits the ground:

When the ball hits the ground, its velocity will be downward. The final velocity can be found using the equation:

v = u + gt ,

where:

v = final velocity

u = initial velocity (21 m/s upward)

g = acceleration due to gravity (approximately 9.8 m/s^2)

t = time in the air (0 seconds)

Plugging in the values:

v = 21 m/s + (9.8 m/s^2)*(0 s)

 = 21 m/s

Therefore, the velocity that the ball hits the ground with is 21 m/s downward.

The de Broglie wavelength of an electron travelling at a speed of 5.0x10^6 m/s is approximately 0.012 nm.

According to the de Broglie equation, the wavelength of a particle is inversely proportional to its momentum. In the case of an electron, its momentum can be calculated by multiplying its mass by its velocity. Therefore, the de Broglie wavelength of an electron travelling at a speed of 5.0x10^6 m/s can be calculated by using the following equation:

λ = h / p

where λ is the de Broglie wavelength, h is Planck's constant (6.626x10^-34 J s), and p is the momentum of the electron.

p = m*v

where m is the mass of the electron (9.109x10^-31 kg) and v is its velocity (5.0x10^6 m/s).

Substituting the values into the equation, we get:

p = (9.109x10^-31 kg)*(5.0x10^6 m/s) = 4.5545x10^-24 kg m/s

λ = h / p = (6.626x10^-34 J s) / (4.5545x10^-24 kg m/s) ≈ 0.012 nm

Therefore, the de Broglie wavelength of an electron travelling at a speed of 5.0x10^6 m/s is approximately 0.012 nm.
The de Broglie wavelength is a property of matter that describes the wave-like behavior of particles, such as electrons. It is calculated by dividing Planck's constant by the momentum of the particle. The de Broglie wavelength of an electron travelling at a speed of 5.0x10^6 m/s is approximately 0.012 nm, which is a very small distance. This demonstrates the wave-like nature of electrons, as their behavior is governed by quantum mechanics, rather than classical physics. The de Broglie wavelength is an important concept in the field of quantum mechanics and helps to explain the behavior of subatomic particles.

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The correct Answer: would be A B C E

Explanation:

Can i get brainlyest ?

Answer:

D, high pressure is less than low pressure low pressure is less than high pressure

Explanation:

Answer:

a

Explanation:

Answer:

positive acceleration: releasing an object from a height - acceleration due to the force of gravity, the speed of the object will increase as it falls

negative acceleration: applying breaks on the tires to slow down the car - deceleration due to frictional forces

Answer:

Mass = 25 kg

Height = 5 m

Acceleration due to gravity = 10 m/s

Work done

We know that

W = mgh

W = 25 × 5 × 10

W = 250 × 5

W = 1250 J

\( \\ \\ \\ \)

Answer:

Number 6:

• From the formula of force:

\(force = mass \times acceleration \\ { \boxed{f = ma}}\)

• But we need to get the acceleration, from the first newtons equation of motion

\(v = u + at\)

• v is the final velocity, but v is zero because the bullet came to rest.

• u is the initial velocity, u = 350 m/s

• a is the acceleration that we need

• t is the time, t = 0.0018 seconds.

» let's now substitute:

\(0 = 350 + (a \times 0.0018) \\ 0.0018a = - 350 \\a = - 194444.44 \\ { \underline{ \: \: |a| = 194444.44 \: m {s}^{ - 2} }}\)

[ negative shows retârdation or deceleration or decrease in speed ]

• Therefore, let's find the force:

mass = 6g = (6/1000) kg = 0.006 kg

\(force = m \times |a| \\ f = 0.006 \times 194444.44 \\ { \underline{ \underline{ \: \: force = 1166.67 \: \: { \sf{newtons \: \: }}}}}\)

Answer:

a baseball hit with a baseball bat travels faster than a bowling ball hit with the same type of force

Explanation: