A cannery needs to know the volume-to-surface-area ratio of a can to find the size that will create the greatest profit. Find the volume-to-surface-area ratio of a can.
Hint : For a cylinder, S = 2πr2 + 2πrh and V = πr2h.

Answer:

Step-by-step explanation:

the answer is 1/4

Answer: 7 - (-5)+12

Step-by-step explanation: best I can put it

(-5) - (-12) = 7 . Option b,c, and d are correct.

Subtraction is a mathematical operator which gives diffrence between two numbers.

Given expression is,  (-5) - (-12)

                                 = -5 +12

                                 = 7

Absolute difference between -5 and -12 is equal to 7.

And, absolute difference between -12 and -5 is equal to 7.    

Also,                          (-5) + 12 = 7  

Hence, expressions with value = 7 are correct.

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Answer: the price of one senior citizen ticket is $10, and the price of one student ticket is $5.

Step-by-step explanation:

Let's assume the price of one senior citizen ticket is 's' dollars and the price of one student ticket is 't' dollars.

According to the given information, on the first day, the school sold 7 senior citizen tickets and 11 student tickets, totaling $125. This can be expressed as the equation:

7s + 11t = 125 ---(1)

On the second day, the school sold 14 senior citizen tickets and 8 student tickets, totaling $180. This can be expressed as the equation:

14s + 8t = 180 ---(2)

We now have a system of two equations with two variables. We can solve this system to find the values of 's' and 't'.

Multiplying equation (1) by 8 and equation (2) by 11, we get:

56s + 88t = 1000 ---(3)

154s + 88t = 1980 ---(4)

Subtracting equation (3) from equation (4) eliminates 't':

(154s + 88t) - (56s + 88t) = 1980 - 1000

98s = 980

s = 980 / 98

s = 10

Substituting the value of 's' back into equation (1), we can solve for 't':

7s + 11t = 125

7(10) + 11t = 125

70 + 11t = 125

11t = 125 - 70

11t = 55

t = 55 / 11

t = 5

Therefore, the price of one senior citizen ticket is $10, and the price of one student ticket is $5.

The most general antiderivative of \( f(x) = \sin(x) \) is \( F(x) = -\cos(x) + C \), where \( C \) represents the constant of integration.

The derivative of \( F(x) \) is indeed \( f(x) \) since the derivative of \(-\cos(x)\) is \(\sin(x)\) and the derivative of the constant \( C \) is zero.

In calculus, the antiderivative of a function represents the set of all functions whose derivative is equal to the original function. In this case, the derivative of \( -\cos(x) \) is \( \sin(x) \), and the derivative of any constant \( C \) is zero. Thus, the antiderivative of \( f(x) = \sin(x) \) is given by \( F(x) = -\cos(x) + C \), where \( C \) can be any real number. Adding the constant of integration allows us to account for all possible antiderivatives of \( f(x) \).

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The altitude of the equilateral triangle with side lengths of 6 cm is approximately 5.2 cm.

An equilateral triangle has all three sides equal in length and all three angles equal to 60 degrees. To find the altitude, we can split the equilateral triangle in half lengthwise to create two right triangles.

Drawing a diagram, we can see that one of the right triangles will have a base equal to half the length of one side of the equilateral triangle, which is 3 cm. The other leg of the right triangle will be the altitude of the equilateral triangle.

Using the Pythagorean theorem, we can calculate the length of the altitude. Let's denote the altitude as h. Applying the theorem, we have 6² = 3² + h², which simplifies to 36 = 9 + h².

Solving for h, we subtract 9 from both sides and take the square root, giving us h ≈ √27 ≈ 5.2 cm.

Therefore, the altitude of the equilateral triangle is approximately 5.2 cm.

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Answer: f( x + -8)+6

Step-by-step explanation: f (x – number) shifts the function b units to the right so we need negative 8 to move to the right and positive 6 to go six up

Answer:

D. 25x-5

Step-by-step explanation:

you need to add all the sides of the square to get 16x-12 and then add 9x+7 to get D.

The equations is inconsistent and has infinitely many solutions. The solution set can be written as {(x, (33-22z)/11, z) : x, z E R}.

This is a system of three linear equations with three variables, x, y, and z. The system can be represented in matrix form as AX = B where A is the coefficient matrix, X is the variable matrix, and B is the constant matrix.

A = |1 -3 -8| |2 5 6| |3 2 -2|

X = |x| |y| |z|

B = |-10| |13| | 3|

To determine the number of solutions for this system, we can use Gaussian elimination to reduce the augmented matrix [A|B] to row echelon form.

R2 - 2R1 -> R2

R3 - 3R1 -> R3

A = |1 -3 -8| |0 11 22| |0 11 22|

X = |x| |y| |z|

B = |-10| |33| |33|

Now we can see that there are only two non-zero rows in the coefficient matrix A. This means that there are only two leading variables, which are y and z. The variable x is a free variable since it does not lead any row.

We can express the solutions in terms of the free variable x:

y = (33-22z)/11

x = x

z = z

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The three-inch cube would be worth \(9\text{ lb}\times $20/\text{lb} = $180$.\)

Since the cube is made of silver, we know that the ratio of volume to weight is constant, meaning that the density of silver is the same throughout the cube. Therefore, if a two-inch cube of silver weighs 3 pounds, then its volume is \($(2\text{ in})^3=8\text{ in}^3$\) and its density is \(3\text{ lb}/8\text{ in}^3 = 0.375\text{ lb/in}^3$.\)

Now let's consider a three-inch cube. Its volume is \($(3\text{ in})^3=27\text{ in}^3$\), which is 3 times the volume of the two-inch cube. Since the density is the same, the weight of the three-inch cube will be 3 times the weight of the two-inch cube, or \(3\times 3\text{ lb}=9\text{ lb}$.\)

To find the value of the three-inch cube, we need to know the price of silver per pound. Let's assume it's \($$20$\) per pound (this is just an example). Then the three-inch cube would be worth \(9\text{ lb}\times $20/\text{lb} = $180$.\)

In general, the value of the three-inch cube would be proportional to the weight and the price of silver per pound.

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The probability that a randomly selected cable repair visit will take at least 43 minutes will be 88%.

Given: The times required for a cable company to fix cable problems in its customers' homes are uniformly distributed between 40 minutes and 65 minutes.

It can be deduced that the probability that a randomly selected cable repair visit will take at least 43 minutes will be calculated thus:

= 1 - [(43 - 40)/(65 - 40)

= 1 - 0.12

= 0.88

Hence, The probability that a randomly selected cable repair visit will take at least 43 minutes will be 88%.

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Utilizing the Sieve of Eratosthenes method is simple. In order to encircle the remaining numbers, we must cancel all multiples of each prime number starting with 2 (including the number 1, which is neither a prime nor a composite).

The Sieve of Eratosthenes can be used to locate all prime numbers that are less than 100, as seen in the example below. In ten rows, start by writing the numbers 1 through 100.

Therefore, based on the preceding table, we can conclude that the prime numbers 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97 are. There are ten prime numbers between 50 and 100 in all. The required prime numbers are those that are surrounded.

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Answer:

i answered this question so the other guy can get brainliest he deserves it

Step-by-step explanation:

B. 20; 3,460

smiley face

The equivalent fractions of 2/5 and 1/7 are 14/35 and 5/35

From the question, the fractions are given as

2/5 and 1/7

The denominators of the fractions are

Denominators = 5 and 7

Take the LCM of the denominators

LCM = 5 * 7

Evaluate

LCM = 35

This means that the denominators of the equivalent fractions must be 35

When this is done, we have

14/35 and 5/35

This is done by multiplying the numerator and the denominator by the same factor

Hence, the fractions are 14/35 and 5/35

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To work out the mean cost of a present in pounds (£), we need to divide the total cost of the presents (£80.52) by the number of presents (4).

The calculation will look like this:

£80.52 ÷ 4 = £20.13

Therefore, the mean cost of a present in pounds (£) is £20.13.

The answer is option (b) The sample size is increased.

A Type II error is a mistake made when accepting the null hypothesis when the alternate hypothesis is true.

It occurs when the researcher assumes that there is no significant effect between two variables when, in fact, there is.

However, there are several factors that can be altered to reduce the possibility of a type II error: If the true parameter is closer to the null hypothesis, it would increase the probability of a type II error and decrease the power of the test.

Increasing the sample size of the study will decrease the probability of a type II error.

Decreasing the significance level would increase the possibility of a type II error as the likelihood of rejecting the null hypothesis will be reduced.

Hence, it is not the correct answer.

Increasing the standard error, also increases the possibility of a type II error as it widens the range of values that the true parameter can take and may include the null hypothesis value.

Type II error cannot be decreased, only increased, this statement is incorrect since there are ways to reduce the possibility of a type II error.

The correct answer is The sample size is increased.

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In the given quadratic equation: 1/2x²  + x + 7.

A polynomial equation is said to be quadratic if the maximum power associated with a variable would be of order 2.

In the given quadratic equation: 1/2x²  + x + 7.

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The correct question is-

Consider the expression 1/2x²  + x + 7.

.

TheoremThe SAS Theorm prove that 2 triangles are congruent using 2 sides and the including angles between the sides

In triangles ABC and EDK

AB = DE have the same length

AC = EK have the same length

Then the two triangles are congruent using the SAS Theorem

Danny is correct

Part B:

Since AB = 5 units and ED = 5 units

Then AB = ED

Since AC = 7 units and EK = 7 units

Then AC = EK

Since right angles

Then the 2 triangles are congruent using SAS Theorem

Given:

The geometric sequence is

To find the common ratio,

Hence the common ratio, r is 14/35.

Answer:

8.5 x 10^-5

Step-by-step explanation:

Step-by-step explanation:

160 + 37x <= 900

37x <= 740

x <= 20

the custodian can move max. 20 boxes on the elevator at one time.

if he/she is always riding with the boxes.

if the custodian would climb the stairs and let the books ride alone, there could be

37x <= 900

x <= 900/37 = 24.32432432 ≈ 24

boxes on the elevator at one time.

Step-by-step explanation:

So the measure of angle O is 360°- 230°

<O= 360°- 230°

= 130°

And to get <X it is intrusive angle is the half of suspended arc.

< X = 230°/ 2

< X = 115°

Answer: x=1115

Step-by-step explanation:

The approximate value of the integral using the Midpoint Rule with n=4 is 1.8909.

To approximate the integral ∫₀₈₈ sin(x) dx using the Midpoint Rule with n=4, we divide the interval [0, 88] into 4 subintervals of equal width. The width of each subinterval is Δx = (88-0)/4 = 22.

Next, we evaluate the function sin(x) at the midpoints of each subinterval and multiply by the width of the subinterval. The midpoints are x₁ = 11, x₂ = 33, x₃ = 55, and x₄ = 77.

Using these values, we calculate the approximate integral as follows:

Approximation = Δx * [sin(x₁) + sin(x₂) + sin(x₃) + sin(x₄)]

= 22 * [sin(11) + sin(33) + sin(55) + sin(77)]

≈ 22 * [0.9999 + 0.9999 + -0.9998 + -0.9998]

≈ 22 * 0.0002

≈ 0.0044

Rounded to four decimal places, the approximate value of the integral is 0.0044.

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i) The mean of x is 68.33 grams.

ii) The standard deviation of x is 2.23 grams.

A standard deviation or (σ ) is a measurement of the data's dispersion from the mean. A low standard deviation indicates that data are concentrated around the mean, whereas a high standard deviation shows that data are more dispersed.

If the standard deviation is close to zero, the data points are close to the mean; otherwise, if the standard deviation is high or low, the data points are, respectively, above or below the mean.

i) Properties of expected values establish that

\($\mathrm{E}(W)=\mathrm{E}(P)+\mathrm{E}\left(X_1\right)+\ldots+\mathrm{E}\left(X_{12}\right)$\)

Because all 12 eggs have the same mean weight, this becomes

\($\mathrm{E}(W)=\mathrm{E}(P)+12 \times \mathrm{E}\left(X_i\right)$\)

We were told that

\($\mathrm{E}(W)=840$ and $\mathrm{E}(P)=20$, so we can solve\)

\($840=20+12 \times \mathrm{E}\left(X_i\right)$ to find $\mathrm{E}\left(X_i\right)=\frac{840-20}{12} \approx 68.33$ grams.\)

ii) Because of independence, properties of variance establish that

\($${Var}(W)={Var}(P)+{Var}\left(X_1\right)+{Var}\left(X_2\right)+\ldots+{Var}\left(X_{12}\right)$$\)

Because all 12 eggs have the same variance of their weights, this becomes

\(${Var}(W)={Var}(P)+12 \times {Var}\left(X_i\right)$\)

We were told that

\(${SD}(W)=7.9\ \text {and}\ {SD}(P)=1.7$ Therefore, ${Var}(W)=(7.9)^2=62.41$ and ${Var}(P)=(1.7)^2=2.89$\)

We can solve

\($ 62.41=2.89+12 \times {Var}\left(X_i\right)$\)

To find

\(${Var}\left(X_i\right)=\frac{62.41-2.89}{12}=4.96$\)

Thus, SD\((X_i\right))=\sqrt{(4.96)} \approx\) 2.23 grams.

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Answer:

Step-by-step explanation:

the type is virtical angle

well we know that

6x +18 = 8x-2

this is an equation , so we need to find x:

6x +18 = 8x-2

-6x          -6x

18  = 2x-2

+2          +2

20 = 2x

10  =x

and done!

To find the value of "a" that makes the expressions 11(a+2) and 55-22a equal, we need to set them equal to each other and solve for "a".

11(a+2) = 55 - 22a

First, distribute 11 to (a+2):

11a + 22 = 55 - 22a

Next, combine like terms by adding 22a to both sides:

33a + 22 = 55

Then, subtract 22 from both sides:

33a = 33

Finally, divide both sides by 33 to solve for "a":

a = 1

Therefore, the value of "a" that makes the two expressions equal is a = 1.

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Answer:

2

Step-by-step explanation:

Given expression:

\(\log_82+3\log_82+\dfrac{1}{2}\log_816\)

\(\textsf{Apply the Power law}: \quad n\log_ax=\log_ax^n\)

\(\implies \log_82+\log_82^3+\log_816^{\frac{1}{2}\)

Simplify:

\(\implies \log_82+\log_88+\log_84\)

\(\textsf{Apply the Product law}: \quad \log_ax + \log_ay=\log_axy\)

\(\implies \log_88+\log_8(2 \cdot 4)\)

\(\implies \log_88+\log_88\)

\(\implies 2\log_88\)

\(\textsf{Apply log law}: \quad \log_aa=1\)

\(\implies 2 \cdot 1\)

\(\implies 2\)

please look above for your answer .

The factors of the trinomial are x-7, x-2.

A trinomial has three terms.

The complete question is

The model of a trinomial is shown. An algebra tile configuration. 0 tiles are in the Factor 1 spot and 0 tiles are in the Factor 2 spot. 24 tiles are in the Product spot: 1 is labeled x squared, 7 are labeled negative x, the 2 tiles below x squared are labeled x, and the 14 tiles below the negative x tiles are labeled negative. What are the factors of the trinomial? Select two options. X – 14 x 7 x – 7 x – 2 x 2.

Here, among all the given factors, model of trinomial, which is represented by the algebra tile configuration is

x-7, x-2

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The Great Depression and the memories of the catastrophic losses in World War I combined in the 1930s to push American public opinion and policy in the direction of isolationism. Isolationists favored staying out of international affairs and staying out of conflicts in Europe and Asia.

The devastation and expense of World War One had left their imprint on America, and the majority of people there just wanted to be left alone to focus on fostering prosperity in their country rather than be involved in any further politics in Europe.

Because they did not want the US to be drawn into another conflict the way they (perceived) it had been into World War I, many Americans in the 1930s backed an isolationist stance.

Because when he first became office, he felt at ease reaching out to the globe in a variety of ways. However, after realizing that his neighbors did not get along, he decided it would not be best for the US to become involved.

Therefore,

The Great Depression and the memories of the catastrophic losses in World War I combined in the 1930s to push American public opinion and policy in the direction of isolationism. Isolationists favored staying out of international affairs and staying out of conflicts in Europe and Asia.

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