A calorie is defined as the amount of energy required to raise the temperature of one lb of water by one degree celsius.

a. Trueb. False

Answer:

B.

Explanation: Because it's at the bottom of the layer so it gets least sun and solar energy.

The number of molecules of HI  that are needed to produce 72.54g of BaL2 is6.365 x 10^23.

To determine the number of molecules of HI needed to produce 72.54g of BaL2, we need to first find the moles of BaL2 and then use the balanced chemical equation to find the moles of HI.

First, we'll find the moles of BaL2:

72.54 g of BaL2 / 137.3 g/mol = 0.529 moles of BaL2

Next, we'll use the balanced chemical equation to find the moles of HI:

BaSO4 + 2HI -> BaL2 + H2SO4

From this equation, we can see that for every 2 moles of HI that react, 1 mole of BaL2 is produced. Therefore, to produce 0.529 moles of BaL2, we need 0.529 x 2 = 1.058 moles of HI.

Finally, we'll convert the moles of HI to the number of molecules:

1.058 moles of HI x 6.022 x 10^23 molecules/mole = 6.365 x 10^23 molecules of HI.

Therefore  the number of molecules of HI needed to produce 72.54g of BaL2 is approximately 6.365 x 10^23.

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Explanation:

centimeter

multiply by 100

720 cm

inches

multiply value by 39.37

283.5 inches

Answer:

where the wind is going

Explanation:

direction is where something is going hope it helps

Answer: number 4 Where the wind is going

Explanation:hope this helps u

Answer:    

I am sure it is the reaction will shift right towards the

product

Answer:

no sodium occurs at the end plate potential

Explanation:

When a nerve impulse releases the neurotransmitter acetylcholine from the nerve terminal, it binds to channel-shaped receptor molecules on the end plate, opening the channels and allowing positively charged sodium ions to flow into the muscle cell.

We need to mix 120 mL of 50% dextrose solution with 480 mL of 5% dextrose solution to prepare 600 mL of 20% dextrose solution.

To prepare a solution of a desired concentration, we need to know the concentrations and volumes of the solutions we are mixing. In this case, we are mixing two solutions of different concentrations to get a desired concentration.

Let's assume x mL of the 50% solution is needed.

Amount of dextrose in the 50% solution = 50% of x

Amount of dextrose in the 5% solution = 5% of (600 - x)

Total amount of dextrose = 20% of 600 mL = 120 mL

So, we can write:

0.5x + 0.05(600 - x) = 0.2(600)

Solving this equation, we get x = 120 mL.

As a result, we must combine 120 mL of 50% dextrose solution with 480 mL of 5% dextrose solution to get 600 mL of 20% dextrose solution.

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The chemical formula for aluminum oxide based on ionic bonding from valence electrons is Al₂O₃.

The chemical formula of a compound is a symbolic representation of its chemical composition.

Chemical formulae gives information about the elements that constitute the molecules of a compound and also about the ratio in which the atoms of these elements combine to form such molecules.

In this compound, aluminum (Al) donates three electrons to oxygen (O), resulting in the formation of Al³⁺ cations and O²⁻ anions. The ionic bond is formed between these oppositely charged ions, resulting in the formula Al₂O₃.

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Three types of end products produced during fermentation lactic acid, formic acid, acetic acid durham tube to detect gas produced by microorganisms

Fermentation reacts NADH with an endogenous and organic electron acceptor and common end products of bacterial fermentation include lactic acid, formic acid, acetic acid, butyric acid, butyl alcohol, acetone, ethyl alcohol, carbon dioxide, and hydrogen and fermentation reactions are detected by the color change of a pH indicator when durham tube are mainly used in microbiology to detect gas by microorganism and gas production helps to identify the type of organism and these special tubes are placed upside down in bigger test tubes to detect the presence of gas production

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Answer:

b

Explanation:

they have coal mines that go down deep into the earth but they also have mines called strip pits where they dig down and create a large creator in the earth insted of a mine shaft

The major product(s) will be the ones that are formed via the most stable intermediate.

When an alkene is treated with concentrated HBr, the reaction is an electrophilic addition reaction, where the HBr molecule adds across the double bond of the alkene.

The reaction proceeds via a carbocation intermediate, which is formed by the addition of the H+ ion of HBr to one of the carbon atoms of the alkene.

The Br- ion then attacks the carbocation, resulting in the formation of a bromoalkane.

If the alkene has substituents, the reaction can result in the formation of multiple products, depending on the regiochemistry of the carbocation intermediate.

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Answer:

1200 millimeters

Explanation:

if there are 1000 millimeters in a meter then you have to multiply 1.2 meters by 1000 to get the number of millimeters. 1.2*1000=1200mm

Answer:

\(5850\ \text{cal}\)

Explanation:

m = Mass of water = 4500 g

c = Specific heat of water = \(1\ \text{cal/g}^{\circ}\text{C}\)

\(\Delta T\) = Change in temperature of water = \(1.3^{\circ}\text{C}\)

Heat is given by

\(q=mc\Delta T\\\Rightarrow q=4500\times 1\times 1.3\\\Rightarrow q=5850\ \text{cal}\)

A slice of the bread contains \(5850\ \text{cal}\).

The amount of heat gained by the water is 500 calories. Thus, option D is correct.

Given:

Mass of water (m) = 100 g

Change in temperature (ΔT) = 30°C - 25°C = 5°C

The specific heat capacity of water (c) is approximately 1 calorie/gram°C.

Now, the amount of heat gained by the water,

Q = mcΔT

Where:

Q is the heat gained or lost by the substance

m is the mass of the substance

c is the specific heat capacity of the substance

ΔT is the change in temperature

Plugging in the values into the formula:

Q = 100 × 1 × 5

Q = 500 calories

Therefore, the amount of heat gained by the water is 500 calories.

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The hydrolysis of \(P_{4}O_{10}\)(s) with \(H_{2}O\)(l) results in the formation of phosphoric acid, H3PO4(l) is given by
\(P_{4}O_{10}\)(s) + 6\(H_{2}O\)(l) → 4\(H_{3}PO_{4}\)l).

In this reaction, \(P_{4}O_{10}\)(s) + 6 \(H_{2}O\)(l) -> 4\(H_{3}PO_{4}\)(l),

1. Solid tetra phosphorus decoxide (\(P_{4}O_{10}\)) reacts with liquid water (\(H_{2}O\)).
2. The  \(P_{4}O_{10}\) molecule hydrolyzes, meaning it breaks apart in the presence of water.
3. As a result of the hydrolysis, 4 molecules of liquid phosphoric acid (\(H_{3}PO_{4}\)) are produced.

This reaction is a classic example of a Lewis acid-base reaction, where \(P_{4}O_{10}\) acts as the Lewis acid and \(H_{2}O\) acts as the Lewis base. The reaction is exothermic, releasing a significant amount of heat. This reaction is important in the production of phosphoric acid, which is widely used in the production of fertilizers, detergents, and other industrial applications.

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Answer:

I'm pretty sure it's b sorry if I get it wrong

The density of the marble in g/mL is 1.084g/mL. As the density of Marble is 1084kg/m3 that is greater than that of water 1,000 kg/m3, hence it will sink.

Describe density.

Density, or mass per unit volume, is defined as the ratio of mass to volume.

Density is the mass of a material substance per unit Density. Density is defined by the formula Density = M / V, where d stands for Density, M for mass, and V for volume.

It gauges how much "stuff" an object contains in relation to its volume (cubic metre or cubic centimeter). In essence, Density is a measurement of how closely together matter is packed.

Grams per cubic centimetre are a typical unit of measurement for density. For instance, while Earth has a density of 5.51 grammes per cubic centimetre, water has a density of 1 grammes per cubic centimetre.

Water Density = 1,000 kg/m3

Marble density=  0.230kg / 0.212L

                                = 1.084g/mL

                               =1084kg/m3

As the density of Marble is 1084kg/m3 that is greater than that of water 1,000 kg/m3, hence it will sink.

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To increase the equilibrium constant (K) of a reaction by a factor of 10, the change in Gibbs free energy (ΔG°) must decrease by approximately 5.708 kcal/mol. Whereas, the change in entropy (ΔS°) must increase by approximately 14.15 J/mol K.

This can be achieved by adjusting the reaction conditions or altering the concentrations of reactants and products.

If the change in entropy (ΔS°) is zero and the equilibrium constant of a reaction at 25°C is increased by a factor of 10, the change in enthalpy (ΔH°) must change by approximately 1.364 kcal/mol.

This implies a shift in the energy balance of the reaction, which can be influenced by adjusting temperature or introducing catalysts.

If the change in enthalpy (ΔH°) is zero and the equilibrium constant of a reaction at 25°C is increased by a factor of 10, the change in entropy (ΔS°) must increase by approximately 14.15 J/mol K.

This suggests that the reaction becomes more disordered or has an increased number of possible microstates, leading to a higher entropy value.

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Answer:

Choice D. Approximately \(61.2\) minutes.

Explanation:

The reaction rate of a second-order reaction is proportional to the square of one of its reactants.

Let \(k\) denote the rate constant of this reaction. Assume that \(y_0\) is the concentration of that reactant at the beginning of this reaction (when \(t = 0\).) Because this reaction is of second order, it can be shown that:

\(\displaystyle y = \frac{1}{k\, t + (1/y_0)}\).

The question states that the rate constant here is \(0.06\; \rm M\cdot min^{-1}\). Hence, \(k = 0.06\). For simplicity, assume that \(t = 0\) when the concentration is \(0.13\; \rm M\). Therefore, \(y_0 = 0.13\). The equation for concentration \(y\) at time \(t\) would become:

\(\displaystyle y = \frac{1}{\underbrace{0.06}_{k}\, t + (1/\underbrace{0.13}_{y_0})}\).

The goal is to find the time at which the concentration is \(0.088\). That's the same as solving this equation for \(t\), given that \(y = 0.088\):

\(\displaystyle \frac{1}{0.06\; t + (1/0.13)} = 0.088\).

\(t \approx 61.2\).

In other words, it would take approximately \(61.2\) minutes before the concentration of this second-order reactant becomes \(0.088\; \rm M\).

From the calculations, the final temperature of the object is 26.1 °C.

The specific heat capacity is defined as the temperature that is required to raise 1 Kg of a substance through a temperature rise  of 1 K.

When;

H = 950.0 J

T1 =  24.20°C

m = 120.1 g

c = 4.184 J/g･°C

T2 = ?

H = mc(T2 - T1)

950 = 120.1  * 4.184(T2 -  24.2)

950 = 502.5T2 - 12160.5

950 + 12160.5 = 502.5T2

T2 = 950 + 12160.5/502.5

T2 =  26.1 °C

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Answer:

C) Chalk powder

Explanation:

that's why it's often used in gymnastics ~~sweaty hands yk

Answer:

P¹V¹/T¹=P²V²/T² here

P²= 1.25- atm

V²=?

T²=345K

P¹=0.75-atm

V¹=120

T¹=295K

So V²= (0.75 x120/295)x(345/1.25)

Volume of the gas V²= 84.20- ml

Answer:

Solution given:

at first

volume\(V_{1}=120.0ml\)

pressure \(P_{1}=0.75atm\)

temperature \(T_{1}=22+273=295°K\)

after increasing temperature and pressure

volume\(V_{2}=xml\)

pressure \(P_{2}=1.25atm\)

temperature \(T_{2}=70+273=343°K\)

now

\(\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}\)

substituting value

\(\frac{0.75*120}{295}=\frac{1.25*x}{343}\)

0.305=5x/1372

Doing criss cross multiplication

5x=0.305*1372

x=418.46/5

x=83.69ml

x=84ml

the volume will be 84ml

Answer:

This option is correct

Explanation:

Molecules are expressed in the form of Lewis in order to simplify their expression or chemical study, but this does not mean that they manifest or respect this form in all three dimensions since some are generally unstable, or even in the third dimension, these locations between atoms are respected for the characteristics of their unions.

The empirical formula of Magnesium Fluoride is; MgF₂, Iron(II) Sulfide is  FeS,  Magnesium Sulfide will be MgS, and Iron(II) Fluoride is FeF₂ for four binary ionic compounds that can be formed using the given ions.

To determine the empirical formula of binary ionic compounds, we need to combine the cation (positive ion) with the anion (negative ion) in the lowest whole number ratio that results in a neutral compound. Here are four examples using the given ions;

Magnesium Fluoride;

Cation; Mg²⁺

Anion; F⁻

To achieve a neutral compound, we need two fluoride ions to balance the charge of one magnesium ion.

Empirical Formula; MgF₂

Iron(II) Sulfide;

Cation; Fe²⁺

Anion; S²⁻

To balance the charges, we need one iron ion to combine with one sulfide ion.

Empirical Formula: FeS

Magnesium Sulfide;

Cation; Mg²⁺

Anion; S²⁻

To achieve a neutral compound, we need one magnesium ion to combine with one sulfide ion.

Empirical Formula: MgS

Iron(II) Fluoride;

Cation; Fe²⁺

Anion; F⁻

To balance the charges, we need two fluoride ions to combine with one iron ion.

Empirical Formula; FeF₂

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Answer:

true

Explanation:

A polyatomic ions is the combination of same kind or different kind of elements with a single charge as a whole . Hence, the statement is true.

What is a polyatomic ions?

A polyatomic ions is a group of elements joined together and possess a single charge as a whole. For example NH₄+. Here, nitrogen with four hydrogens forms a covalent bond with one unit of positive charge as a whole remains.

Polyatomic ions either three or more contains same or different kinds of elements. In the case of CO₃²⁻ , the carbonate ion contains 4 atoms and 2 units of negative charge which is possessed by the whole group.

Similarly, NO₃⁻, SO₄²⁻ etc are other examples of polyatomic ions. They are formed by gaining or losing electrons from their acidic or basic forms. Therefore, the statement is true.

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Answer:

C 8.09 SO2 gas

Explanation:

As we have the volume (3dm³ = 3L), temperature (25°C + 273 = 298K), and pressure (1atm), we can solve to moles of gas using:

PV = nRT

PV / RT = n

1atm*3L / 0.082atmL/molK*298K =¨

0.123 moles of gas you have.

Now, to convert these moles to mass we use molar mass (32g/mol for O2, 28g/mol for N2, 64g/mol for SO2, and 44g/mol for CO2).

Mass of 0.123 moles of these gases is:

O2 = 0.123 moles * 32g/mol = 3.94g of O2. A is wrong

N2 = 0.123 moles * 28g/mol = 3.4g of N2. B is wrong

SO2 = 0.123 moles * 64.1g/mol = 7.9g of SO2≈ 8.09g of SO2, C is possible

CO2 = 0.123 moles * 44g/mol = 5.4g of CO2. D is wrong

Right answer is:

The given cation acts as acid C₅H₅NH⁺ + H₂O → H₃O⁺ + C₅H₅N.

The following equation, cation acts as an acid.

C₅H₅NH⁺ + H₂O → H₃O⁺ + C₅H₅N

In electrochemistry, the anode is wherein oxidation occurs and is the positive polarity touch in an electrolytic cell. On the anode, anions negative ions are forced by way of the electric potential to react chemically and provide off electrons oxidation which then go with the flow up and into the riding circuit.

Cations are ions which might be undoubtedly charged. Anions are ions which might be negatively charged. Ions are charged atoms or molecules. If a balanced atom loses one or extra electrons, it becomes a undoubtedly charged cation.

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Answer:

The correct answer is "Stirring the water decreases the amount of time it takes for materials to dissolve"

C

Explanation:

Answer:

C) Stirring the water decreases the amount of time it takes for materials yo dissolve.

Explanation:

(a) Electron domain geometry - Octahedral.

(b) Molecular geometry - Square pyramidal.

(c) Smallest bond angle - 90°

(d) The polarity of BrF₅, best choice is: The molecule is polar and has polar bond.

(e) AsH₃ is polar molecule.

A molecule's valence shell electrons are shown in a very simple manner via a Lewis structure. It serves as a visual representation of how the electrons surrounding certain molecules' atoms are positioned.

It demonstrates the bonds that exist between a molecule's atoms and its lone pairs of electrons. When used in conjunction with hybrid orbitals, Lewis structures can also be helpful in predicting molecular geometry.

(a) Electron domain geometry - Octahedral.

(b) Molecular geometry - Square pyramidal.

(c) Smallest bond angle - 90°

(d) The polarity of BrF₅, best choice is: The molecule is polar and has polar bond.

(e) AsH₃ is polar molecule.

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Answer: \(1.6\times 10^4\)

Explanation:

Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example : 5000 is written as \(5.0\times 10^3\)

In division , the result would contain the same number of significant digits as there in the least precise number , thus the answer would have 2 significant digits.

\(\frac{1.248\times 10^{-2}}{7.8\times 10^{-7}}=1.6\times 10^4\)