a bullet hits a block at rest, the resulting kinetic energy if 6 j what is the bullet starting speed

1. Earth is located at one focus of the Moon's orbit.

2. According to kepler's second law, jupiter will be traveling most slowly around the sun's aphelion

3. Earth orbits in the shape of a/an ellipse around the sun.

4. The mathematical form of Kepler's third law measures the period in years and the semimajor axis in astronomical units (AU).

5. According to Kepler's second law, Pluto will be traveling fastest around the Sun when at perihelion.

6. The extent to which Mar's orbit differs from a perfect circle is eccentricity.

Kepler's second law is a mathematical principle that states the distance between two objects in space is proportional to the square of their timescale of revolution. This means that as two objects orbit around each other, the further they will be from each other over time.

Kepler's Third Law is a scientific law that states the amount of time it takes for planets to orbit their star is inversely proportional to their distance from the sun.

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Yes! All orbiting objects adhere to Kepler's Second Law and other rules as well. Pluto moves more quickly when it is nearer the sun and less quickly when it is distant from it, much like every other object in our solar system.

In astronomy, Johannes Kepler's laws of planetary motion, which were written between 1609 and 1619, define the paths taken by planets as they round the Sun. The laws altered Nicolaus Copernicus' heliocentric theory, substituting elliptical trajectories for circular orbits and epicycles, thereby explaining the variation in planetary velocities. According to the three laws:

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Answer:

folk dancing is old music and ball room is young dancing

if a charged particle is moving in a uniform magnetic field, its path can be circular.

The magnetic field is the region of the space where the charged particle experiences the magnetic force. The magnetic field is uniform, when it does not change with time.

From the Fleming's left hand rule shows that the magnetic force is perpendicular to the motion of a charged particle. It follows a curved path in a uniform magnetic field. The particle will continue to follow this curved path until and unless it completes a circle.

Thus, if a charged particle is moving in a uniform magnetic field, its path can be circular.

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Answer:

A flying aircraft, bird.

Falling down or dropping an object

Throwing a ball
Driving a car

Walking, jogging, bicycling, swimming, dancing, or running.

Explanation:

Because kinetic means movement.

So anything moving.

Answer:

Any object in motion.

Explanation:

KE=0.5mv^2

thus is an object has a velocity and/or momentum it will have KE.

The object that had a mass of 4 kilograms and was lifted at a rate of 3 m/s has a greater kinetic energy.

We know that the kinetic energy has to do with the energy of an object that is in motion. Thus the kinetic energy is the energy that is said to be possessed by a moving object.

In the first case we have;

Kinetic energy = 1/2 mv^2 = (0.5 * 2 * 2^2)

= 4 J

In the second case;

Kinetic energy =  1/2 mv^2 = (0.5 * 4 * 3^2)

= 18 J

The second object had more kinetic energy.

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The voltage at the inverting terminal is 7.5 V. V out is -12.5 V. The current flowing through R4 is 0.5 mA.

Given that Vn, Vout, and lout for the circuit shown below and op amp is ideal.In the circuit, current I2 flows through the 2.5 kΩ resistor.

Therefore, the voltage drop across the 2.5 kΩ resistor is given by,

Vn = I2 x R2Vn = 3 mA x 2.5 kΩ = 7.5 V

Therefore, the voltage at the inverting terminal is 7.5 V.

Since op-amp is assumed to be ideal, no current flows into the inverting and non-inverting terminals.

Therefore, current through R3 is given by,

I3 = (Vn - Vout) / R3=> Vout = Vn - I3 x R3=> Vout = 7.5 V - 4 mA x 5 kΩ=> Vout = - 12.5 V

Therefore, Vout is -12.5 V.

Let's calculate the current flowing through R4:

This current will also flow through the 5 kΩ resistor.

Let lout be the current flowing through R4.

Therefore, current through the 5 kΩ resistor is also lout.

Now, I4 + lout = I3=> I4 = I3 - lout=> I4 = 4 mA - lout

Also, I4 = (5 V - Vout) / R4=> 4 mA - lout = (5 V - (-12.5 V)) / 5 kΩ=> 4 mA - lout = 3.5 mA=> lout = 0.5 mA

Therefore, lout is 0.5 mA.

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Answer:

The comet is locked in the Sun's gravity. as it falls deeper in the gravity we'll, its velocity increases. As is travels closer to the Sun, it is trying to break away, but cannot. This transforms into a sideways movement that produces a tight turn. It races further out of the gravity well, and sheds velocity.

The centroid of the cross-sectional area has been determined to be 51 mm from the top. The moment of inertia (I) of area about the neutral axis can be determined by using the parallel axis theorem.

Parallel Axis Theorem states that I = I0 + Ad2, where I0 is the moment of inertia about the centroidal axis, A is the cross-sectional area, and d is the distance between the centroidal axis and the neutral axis.To determine the moment of inertia, we first need to determine the centroidal moment of inertia (I0).I0 can be determined by using the formula, I0 = (bd^3)/12, where b is the breadth and d is the depth.

Here, b = 50 mm and d = 102 mm (since the centroid is 51 mm from the top, the depth from the top to the neutral axis will be 51 mm and the depth from the neutral axis to the bottom will also be 51 mm).

Therefore,I0 = (50 x 102^3)/12= 8,617,040 mm4 \(I0 = (50 x 102^3)/12= 8,617,040 mm4\\\)The distance between the centroidal axis and the neutral axis (d) is 51 mm.

Hence, using the parallel axis theorem,\(I = I0 + Ad2I = 8,617,040 + (150 x 51^2)= 14,692,590\) mm4Therefore, the moment of inertia (I) of area about the neutral axis is 14,692,590 mm4.

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Answer:

about the chances of u getting to ever actually fu,ck ur gf

Explanation:

Fossils are the remains of plants, animals, fungi, bacteria, and single-celled living things that have been replaced by rock material or impressions of organisms preserved in rock.

Answer:

W = 76 N

Explanation:

In this exercise you are asked to find the weight of the body.

Mass is a quantity that is invariant, it measures the same everywhere, the weight depends on where it is measured, a simple way to find the weight of a body is

          W = g m

where g is the constant of the place, in this case we have the weight of the body on Mars and its mass which is constant on Earth and on Mars

            W = 3.8 20

            W = 76 N

Answer:

\(q / q_{1} = 2\), assuming that \(q_{1}\) and \((q - q_{1})\) are point charges.

Explanation:

Let \(k\) denote the coulomb constant. Let \(r\) denote the distance between the two point charges. In this question, neither \(k\) and \(r\) depend on the value of \(q_{1}\).

By Coulomb's Law, the magnitude of electrostatic force between \(q_{1}\) and \((q - q_{1})\) would be:

\(\begin{aligned}F &= \frac{k\, q_{1}\, (q - q_{1})}{r^{2}} \\ &= \frac{k}{r^{2}}\, (q\, q_{1} - {q_{1}}^{2})\end{aligned}\).

Find the first and second derivative of \(F\) with respect to \(q_{1}\). (Note that \(0 < q_{1} < q\).)

First derivative:

\(\begin{aligned}\frac{d}{d q_{1}}[F] &= \frac{d}{d q_{1}} \left[\frac{k}{r^{2}}\, (q\, q_{1} - {q_{1}}^{2})\right] \\ &= \frac{k}{r^{2}}\, \left[\frac{d}{d q_{1}} [q\, q_{1}] - \frac{d}{d q_{1}}[{q_{1}}^{2}]\right]\\ &= \frac{k}{r^{2}}\, (q - 2\, q_{1})\end{aligned}\).

Second derivative:

\(\begin{aligned}\frac{d^{2}}{{d q_{1}}^{2}}[F] &= \frac{d}{d q_{1}} \left[\frac{k}{r^{2}}\, (q - 2\, q_{1})\right] \\ &= \frac{(-2)\, k}{r^{2}}\end{aligned}\).

The value of the coulomb constant \(k\) is greater than \(0\). Thus, the value of the second derivative of \(F\) with respect to \(q_{1}\) would be negative for all real \(r\). \(F\!\) would be convex over all \(q_{1}\).

By the convexity of \(\! F\) with respect to \(\! q_{1} \!\), there would be a unique \(q_{1}\) that globally maximizes \(F\). The first derivative of \(F\!\) with respect to \(q_{1}\!\) should be \(0\) for that particular \(\! q_{1}\). In other words:

\(\displaystyle \frac{k}{r^{2}}\, (q - 2\, q_{1}) = 0\).

\(2\, q_{1} = q\).

\(q_{1} = q / 2\).

In other words, the force between the two point charges would be maximized when the charge is evenly split:

\(\begin{aligned} \frac{q}{q_{1}} &= \frac{q}{q / 2} = 2\end{aligned}\).

Logistics managers use the integrated approach to coordinate materials management and physical distribution in a cost-efficient manner.

This approach involves integrating different functions and activities within the supply chain to optimize overall performance.

1. Materials management: Logistics managers focus on managing the flow of materials from suppliers to manufacturers, ensuring that the right materials are available at the right time and in the right quantities.

2. Physical distribution: Logistics managers also oversee the movement of finished goods from the manufacturer to the end consumer. This includes activities such as warehousing, transportation, and order fulfillment.

3. Integration: The integrated approach involves coordinating materials management and physical distribution to achieve cost efficiency. For example, by closely aligning production schedules with transportation schedules, logistics managers can minimize inventory holding costs and reduce transportation expenses.

4. Cost-efficiency: By integrating materials management and physical distribution, logistics managers can reduce costs associated with excess inventory, transportation delays, and inefficient warehouse operations. This helps organizations improve their bottom line and deliver products to customers in a timely and cost-effective manner.

Overall, the integrated approach enables logistics managers to optimize the entire supply chain, enhancing efficiency and reducing costs.

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Answer:

9654.34 m

Explanation:

from conservation of momentum

\($$\begin{aligned}30 \times 250 &=-10 \times 120+20 \times V \\20 V &=30 \times 250+10 * 120 \\V &=\frac{30 \times 250+10 \times 120}{20}=435 \mathrm{~m} / \mathrm{s}\end{aligned}$$\)

And from Conservation of Energy

\(\frac{1}{2} m v^{2}=m g h\\h=\frac{v^{2}}{2 g}\\h=\frac{(435(m/s))^{2}}{2 \times 9.8(m/s^{2} )}\\h=9654.34 (m)\)

Answer:

λ = 75 µm, correct is A

Explanation:

In waves, speed is related to wavelength and frequency

          c = λ f

          λ = c / f

in this exercise indicate the frequency of rationality

          f = 4 THz = 4 10¹² Hz

let's calculate

        λ = 3 10⁸/4 10¹²

        λ = 7.5 10⁻⁵ m = 75 10⁻⁶ m

        λ = 75 µm

The resistance of the copper wire is 0.6 ohms. This means that it will take 0.6 volts of electrical potential difference to produce a current of 1 ampere through the wire.

The resistivity of copper is given as 2 × 10¯4 m, which is a measure of the material's inherent resistance to electrical flow. The resistance of a copper wire with a cross-sectional area of 1mm2 and a length of 3m can be calculated using Ohm's Law, which states that resistance equals resistivity multiplied by length divided by cross-sectional area.

Using this formula, we can find that the resistance of the copper wire is:

Resistance = Resistivity x Length / Cross-sectional area
Resistance = (2 × 10¯4 m) x (3 m) / (1mm2)
Resistance = 0.6 Ω

Knowing the resistance of a wire is important in determining its suitability for various electrical applications, as well as in designing and troubleshooting electrical circuits.

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What happens if you launch from a planet with so much angular velocity that the centrifugal force becomes significantly greater than the gravitational force is that you leave the planet's gravitational field which is therefore denoted as option D.

This is referred to as a model which is used to explain the influences that a massive body extends into the space around itself, producing a force on another massive body.

If you launch from a planet with so much angular velocity that the centrifugal force becomes significantly greater than the gravitational force is that you leave the planet's gravitational field and there is no gravitational force felt such as that in the moon etc and is therefore the reason why it was chosen as the correct choice.

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Answer:30s

Explanation:

Answer:

480

Explanation:

resistance equals to potential difference divide by electric current

120÷0.25

=480

Answer:

\(\mathsf {480 \Omega}\)

Explanation:

\(\textsf {Formula used for calculating resistance :}\)

\(\mathsf {Resistance = \frac{Voltage}{Current} }\)

\(\textsf {This is otherwise known as Ohm's Law, hence the unit of resistance.}\\\)

\(\textsf {Solving :}\)

\(\implies \mathsf {R = \frac{120}{0.25}}\)

\(\implies \mathsf {R = 480\Omega}\)

\(\textsf{If the fan uses higher current at higher speeds, then}\\\textsf{the resistance would decrease as it is inversely}\\\textsf {proportional to the current.}\)

Answer:

Explanation:

A simple pendulum consists of a mass (usually represented as a small object or bob) attached to a string or rod of negligible mass. The mass is free to swing back and forth under the influence of gravity.

In the figure, the point of suspension is denoted by "O," and the mass (bob) is represented by the small circle. The string or rod is represented by the vertical line connecting the point of suspension to the bob.

Amplitude:

The amplitude of a pendulum refers to the maximum displacement or swing of the bob from its equilibrium position. In the figure, the amplitude can be represented by the angle formed between the vertical position and the position of the bob when it swings to its maximum distance on one side. It is usually denoted by the symbol "A."

Effective Length:

The effective length of a pendulum refers to the distance from the point of suspension to the center of mass of the bob. It represents the distance over which the mass swings back and forth. In the figure, the effective length can be measured as the length of the string or rod from the point of suspension to the center of the bob. It is usually denoted by the symbol "L."

It is important to note that the amplitude and effective length of a simple pendulum affect its period of oscillation (the time taken for one complete swing). The relationship between these parameters and the period can be described by mathematical formulas.

Overall, the simple pendulum is a fundamental concept in physics and provides a simplified model for understanding oscillatory motion and the principles of periodic motion.

They have a limited supply in nature, therefore if they are used excessively, they will become exhausted.

Today, we recognise that using fossil fuels has a negative impact on the environment. Fossil fuels produce and utilise local pollutants, and their continued use permanently alters the temperature of our entire world.

Wastes from combustion sources are those that result from carbon pollution (i.e., coal, oil, natural gas). Included in this are all ash and particles taken out of the flue gas.

The fossile fuel is limited in nature. So, it should not waste energy from fossil fuels.

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Answer:

Mechanical waves are A. Longitudinal and C. Transverse.

Explanation:

I hope this helps you.^_^

Answer:4

Explanation:

The weak nuclear force is responsible for the beta decay, therefore the false statement about strong and weak nuclear forces would be that both promote beta decay, therefore the correct answer is option C.

The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity.

The weak nuclear force is among the two nuclear forces that are responsible for beta decay.

The weak nuclear force is what causes beta decay, hence the incorrect statement regarding the strong and weak nuclear forces is that they both encourage beta decay. Therefore, option C is the best response.

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Answer:

d = Δv(t2-t1)

Explanation:

Speed is defined as the change of displacement with respect to time. It is expressed as shown;

Speed = change in displacement/change in time

Δv = d/Δt

d = Δv*Δt

d = ΔvΔt

Δt = t2-t1

d = Δv(t2-t1)

Δv is the change in rate of speed

Δt = change in time

The correct expression for the displacement of the car during this motion is d = Δv(t2-t1)

The displacement of the car at the given period is \(\Delta x = \Delta v (t_2 -t_1)\)

The given parameters;

The displacement of the car is calculated from the relationship between average velocity and displacement as shown below;

\(\Delta v = \frac{\Delta x }{\Delta t} \\\\\Delta x = \Delta t \times \Delta v\\\\\Delta x = \Delta v (t_2 -t_1)\)

Thus, the displacement of the car at the given period is \(\Delta x = \Delta v (t_2 -t_1)\)

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The example that is NOT an example of Simple Harmonic Motion is:

A ball rolling down a hill.

Simple Harmonic Motion is a type of periodic motion where the restoring force is proportional to the displacement from equilibrium and is directed towards the equilibrium point. The classic example of simple harmonic motion is the motion of a mass attached to a spring that is oscillating back and forth. Other examples of simple harmonic motion include a pendulum swinging back and forth and the vibration of a guitar string.

A ball rolling down a hill does not exhibit simple harmonic motion because it does not have a restoring force that is proportional to the displacement from equilibrium. The motion of the ball is affected by the force of gravity, which is not directed towards the equilibrium point, and the frictional force between the ball and the surface of the hill, which is not proportional to the displacement from equilibrium. Therefore, it is not an example of simple harmonic motion.

Answer:

r = 50.47 x 10³ m = 50.47 km

Explanation:

Using the formula for the acceleration due to gravity:

\(g = \frac{Gm}{r^2}\)

where,

g = acceleration due to gravity on the surface of asteroid = 0.0288 m/s²

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

m= mass of asteroid = 1.1 x 10¹⁸ kg

r = radius of asteroid = ?

Therefore,

\(0.0288\ m/s^2 = \frac{(6.67\ x\ 10^{-11}\ Nm^2/kg^2)(1.1\ x\ 10^{18}\ kg)}{r^2} \\\\r = \sqrt{\frac{(6.67\ x\ 10^{-11}\ Nm^2/kg^2)(1.1\ x\ 10^{18}\ kg)}{0.0288\ m/s^2}}\)

r = 50.47 x 10³ m = 50.47 km

Answer:

5.05x10^4

Explanation:

g=(GM)/r^2, so

.0288=(6.67x10^-11*1.10x10^18)/r^2, r=5.05x10^4.

This is correct on Acellus.

Answer:

\(T=62.9*10^{-9}\)

Explanation:

From the question we are told that:

Index of refraction of Rinestones \(\gamma_1 =1.5\)

Index of refraction of silicon \(\gamma_2 =2.0\)

Wavelength  \(\lambda=576nm=576*10^{-9}\)

Let each layer have thickness T

Therefore

Total Thickness =2T

Generally the equation for  Constructive interference is mathematically given by

\(2T=(m+0.5)\frac{l\lambda}{\gamma_2}\)

Where

 \(M=0\)

 \(2T=(0+0.5)\frac{576*10^{-9}}{2*2.0}\)

 \(T=62.9*10^{-9}\)