A box with a mass of 100.0 kg slides down a ramp with a 50 degree angle.

What is the weight of the box?

Answer:

352,088.37888Joules

Explanation:

Complete question;

A hiker of mass 53 kg is going to climb a mountain with elevation 2,574 ft.

A) If the hiker starts climbing at an elevation of 350 ft., what will their change in gravitational potential energy be, in joules, once they reach the top? (Assume the zero of gravitational potential is at sea level)

Chane in potential energy is expressed as;

ΔGPH = mgΔH

m is the mass of the hiker

g is the acceleration due to gravity;

ΔH is the change in height

Given

m = 53kg

g = 9.8m/s²

ΔH = 2574-350 = 2224ft

since 1ft = 0.3048m

2224ft = (2224*0.3048)m = 677.8752m

Required

Gravitational potential energy

Substitute the values into the formula;

ΔGPH = mgΔH

ΔGPH = 53(9.8)(677.8752)

ΔGPH = 352,088.37888Joules

Hence the gravitational potential energy is 352,088.37888Joules

The change in gravitational potential energy be, once the hiker reach the top of the mountain is 352088 joules or 352.1 kJ.

Gravitational potential energy is the energy which a body posses because of its position.

The gravitational potential energy of a body is given as,

\(U=mgh\)

Here, (m) is the mass of the body, (g) is the gravitational force and (h) is the height of the body.

The mass of the hiker is 53 kg and the height of the climb is 2574 ft.

Now, the hiker starts climbing at an elevation of 350 ft. Thus, the net height of the hiker has to climb is,

\(h=2574-350\\h=2224\rm\; ft\)

Convert this into the meter by multiplying 03048 as,

\(h=2224\times0.3048\\h=677.8752\rm\; m\)

It is known that the value of g is 9.8 m/s². Plug in all the values as,

\(U=53\times9.8\times677.8752\\U=352088J\\U=352.1 \;\rm kJ\)

Thus, the change in gravitational potential energy be, once the hiker reach the top of the mountain is 352088 joules or 352.1 kJ.

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The x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

Mass of the ball: M = 6.35 kg.

Initial velocity of ball: U = 8.49 m/s.

Mass of the pin at rest: m = 1.59 kg.

Final velocity of pin: v = 20.1 m/s at a -77.0° angle.

Let the x and y component of the ball's final velocity are respectively V₁ m/s and  V₂ m/s.

Appling conservation of momentum along x axis:

MU + m.0 = MV₁ + mvcos(-77.0°)

⇒ V₁ = u - (m/M) v cos(-77.0°)

After putting the values we get:

V₁ = 7.35 m/s.

Appling conservation of momentum along y-axis:

M.0 + m.0 = MV₂ + mvsin(-77.0°)

⇒ V₂ = - (m/M) vsin(-77.0°)

After putting the values we get:

V₂ = 4.90 m/s.

Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

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Answer:

50

Explanation:

Answer:

Education and knowledge

Explanation:

Science is important because it teaches the understanding of life and nature. Science teaches how every thing works and it have advantages in life like technology and medicine

The torque is equal to zero since the coil is in equilibrium. As a result, will also equal zero, indicating that the coil's plane is parallel to the vertical direction at equilibrium.

The current-carrying coil in a magnetic field is given by:

τ = μ * B * I * A * sin(θ)

where:

τ = torque (in Nm)

μ = magnetic moment of the coil (in Am^2)

B = magnetic field strength (in T)

I = current flowing through the coil (in A)

A = area of the coil (in m^2)

θ = angle between the plane of the coil and the magnetic field (in radians)

μ = N * A * I

N = number of turns of the coil

A = area of the coil (in m^2)

I = current flowing through the coil (in A)

the equations to calculate the angle θ:

m = 0.100 kg (mass of the wire)

L = 4.00 m (total length of the wire)

side length = 0.100 m

I = 3.80 A (current flowing through the coil)

B = 0.0100 T (magnetic field strength)

Calculations:

A = side length^2 * N = 0.100^2 * 1 = 0.0100 m^2

μ = N * A * I = 1 * 0.0100 * 3.80 = 0.0380 Am^2

Now we can rearrange the equation for torque to solve for θ:

θ = arcsin(τ / (μ * B * I * A))

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Answer: P=30W

Explanation:

formula is p=w/t

p = power

w = work

t = elapsed time

input variables, solve then simplify.

The power of a lift that transfers 450 J of energy in 15 seconds is 30 watts.

Power is defined as the rate of doing work, i.e. the amount of work done per unit time.

Mathematically, it can be represented as follows:

Power = Work done / time taken

Therefore, the power of a lift that transfers 450 J of energy in 15 seconds can be calculated as follows:

Power = Work done / time taken= 450 J / 15 s= 30 W

Therefore, the power of the lift is 30 watts.

To explain further, we know that power is measured in watts (W), and it is the rate at which work is done or energy is transferred.

Here, we are given that the lift transfers 450 J of energy in 15 seconds.

We can find the power of the lift by dividing the amount of work done by the time taken to do it. By substituting the given values, we get the power of the lift as 30 W.

In simple terms, this means that the lift can transfer energy at a rate of 30 joules per second. This can also be interpreted as the lift can do 30 joules of work in one second.

Hence, we can conclude that the power of the lift is 30 watts.

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The efficiency of the motor is 68.75%

What is efficiency of an engine?

Engine efficiency is a measure of how effectively an engine can convert the energy from its fuel into useful work. It is typically expressed as a percentage of the total energy from the fuel that is converted into useful work output, such as torque or thrust. The higher the engine efficiency, the less fuel is required for a given amount of work output. Factors that can affect engine efficiency include engine type, engine size, fuel type, compression ratio, and spark timing. Increasing engine efficiency is important for reducing emissions and improving fuel economy. Technologies such as turbocharging, direct injection, and variable valve timing have been developed to help improve engine efficiency.

Energy provided to the train engine = 80000J

Output energy from the tain engine = 55000J

Efficiency of the motor = (Output power÷Input power )*100

  = (55000J /80000J)*100

= 68.75%

Therefore efficiency of the motor is 68.75%

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a) Total momentum before collision is: \(\mathrm{\rho = M \times 3v_0 - M \times v_0 = 2M \times v_0}\)

b) Immediately after the collision, two objects move together with a speed of v₀. The direction of motion is to the right, as A was moving to right before collision.

Momentum may be defined as the product of mass and velocity of any object.

(a) Before the collision, total momentum of the system is :

\(\mathrm{\rho = m_A \times v_A + m_B \times v_B}\)

\(\mathrm{m_A = m_B = M, v_A = 3v_0, \ and \ vB = -v_0}\) (since B is moving to the left).

Therefore, total momentum before the collision is:

\(\mathrm{\rho= M \times 3v_0 - M \times v_0 = 2M \times v_0}\)

(b) Immediately after the collision, the two objects move with the same velocity v. Total momentum of the system is: p' = (mA + mB)  ×  v = 2M  ×  v

As total momentum is conserved: p' = p

\(\mathrm{2M \times v = 2M \times v_0}\)

\(\mathrm{v = v_0}\)

Therefore, immediately after the collision, two objects move together with a speed of v₀. The direction of motion is to the right, since A was moving to the right before collision.

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Answer:

Explanation:

p = mv = 0.075(0.5) = 0.0375 kg•m/s

There are two forces acting on the rock: the force of gravity pulling it downward and the force of the boulder supporting it from underneath.

The force of gravity is the gravitational attraction between the rock and the Earth. It pulls the rock downward with a force equal to its weight, which is given by the equation Fg = mg, where Fg is the force of gravity, m is the mass of the rock, and g is the acceleration due to gravity (approximately 9.81 m/s^2).

The concept of forces explains why the rock stays on top of the boulder because the forces are balanced. The force of gravity pulling the rock downward is equal and opposite to the force of the boulder supporting it from underneath. As a result, the rock remains in equilibrium, or a state of balance, on top of the boulder. If either force were to change, the equilibrium would be disrupted, and the rock would either fall to the ground or be pushed off the boulder.

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Answer:

Must include: 21

Explanation:

Mirrors are a common tool used by painters to depict a variety of viewpoints and nuanced interactions between the observer and the artist.

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While the region with the lowest electric potential (20 V) will have the highest electric field, the region with the highest electric potential (80 V and 70 V) will also have the highest electric field.

Relationship between electric potential and electric field

E = V/d

where;

V is electric potential (V)

E is electric field (V/m)

d is the distance (m)

A two-dimensional curve where a function's value is constant. Isarithm, isopleth, and contour line are other names that are equivalent.

A location with a high electric potential (80 V or 70 V) will have a high electric field, whereas a region with a low electric potential (20 V) will have a low electric field since electric field and electric potential are directly proportional.

The field that surrounds electrically charged particles and pulls on all other charged particles in the field is known as the electric field.

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Answer:

Explanation:

The formula for weight is

W = mg, where

W = the weight of the object or person

m = mass of the object or person

g = acceleration due to gravity

Now, we're given the mass of the person to be 60 kd, and thus, the weight of that person would be

W = 60 * 9.81

W = 588.6 N

On the surface of the moon, the weight of the person would be

W = 60 * 1.625

W = 97.5 N

Therefore, the weight of the person on both surfaces are 588.6 and 97.5 respectively

If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.

A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.

If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.

In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.

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a) The value of t u = 140/t`b.

b) The y position of the cannonball at the time t is  55.5 mc.

c) The initial speed of the projectile is 52.4 m/s.

Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.

a. To find the value of t:Here, we have to use the formula of distance

i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`

Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is

(2H) = 2 × 55.5

= 111 m`2H/g

= 111/9.8`

= 11.32653 s

From equation (1),u×t = 140u = 140/t

Therefore, `u = 140/t`b.

b)To find the y position of the cannonball at the time t:

Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,

Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².

We have already calculated the time taken by the cannonball to hit the ground in the previous step.`

y = 140 - (1/2) × 9.8 × t²`

On substituting the value of t as `t = 11.32653`,

we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.

c)  To find the initial speed of the projectile:

To calculate the initial speed of the projectile, we need to use the formula of range of projectile

.i.e.,R = u²sin2θ/g

Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)

u² = R × g/sin2θ

   = 140 × 9.8/sin0°  

   = 2744m²/s²u  

   = \(\sqrt(2744m^2/s^2)\)

   = 52.4 m/s

Hence, the initial speed of the projectile is 52.4 m/s.

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We can use the conservation of momentum to solve both problems:

Conservation of momentum:

0 = m1(v1') + m2(v2')

where m1 = 50 kg, v2' = 3 m/s, and m2 = 80 kg. We can solve for v1' to get:

v1' = -(m2/m1) v2'

v1' = -(80 kg/50 kg) (3 m/s) = -4.8 m/s

Therefore, the 50 kg swimmer moves away from the raft with a velocity of -4.8 m/s.

Conservation of momentum:

m1(v1) + m2(v2) = m1(v1') + m2(v2')

where m1 = 90 kg, v1 = 6 m/s, m2 = 60 kg, and v1' = 4 m/s. We can solve for v2 to get:

v2 = (m1v1 + m2v2 - m1v1') / m2

v2 = (90 kg)(6 m/s) + (60 kg)(2 m/s) - (90 kg)(4 m/s) / 60 kg

v2 = -1 m/s

Therefore, the velocity of the 60 kg player after the collision is -1 m/s, which means they are moving in the opposite direction to the 90 kg player.

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Answer:

I think it is Big Band theory

Explanation:

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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Answer:

i think u times them im not sure but then divide

Explanation:

Answer:

The horizontal distance of the package fall before landing is (30 m/s)*(time to fall 200 m). Furthermore the velocity of the package just before it hits the ground is - g*t is the vertical component

30 m/s is the horizontal component.

t is the time required to fll H = 200 m, which is

sqrt(2H/g)

You do the numbers

Answer:

Charges are transferred from one object to another.

Explanation:

The charges from one object to another are sharing there energy.

Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then  the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

The acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

The magnitude of the acceleration of the object is 3  \(m/s^{2}\).

To find the magnitude and direction of the resultant force, we need to add the two given forces together.

Given:

f1 = (8i + 3j) N

f2 = (4i + 6j) N

To find the resultant force (\(F_res\)), we simply add the corresponding components:

\(F_res\) = f1 + f2

= (8i + 3j) + (4i + 6j)

= (8 + 4)i + (3 + 6)j

= 12i + 9j

The magnitude of the resultant force (\(|F_res|\)) can be found using the Pythagorean theorem:

\(|F_res|\)= \(\sqrt{(12^2) + (9^2)}\)

= \(\sqrt{144 + 81}\)

= \(\sqrt{225}\)

= 15 N

So, the magnitude of the resultant force is 15 N.

To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:

θ = arctan(9/12)

= arctan(3/4)

≈ 36.87 degrees

Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:

F = ma

For the x-component:

\(F_x\)= 12 N

m = 5 kg

Using  \(F_x\)= \(ma_x\), we can solve for \(a_x\):

12 N = 5 kg * \(a_x\)

\(a_x\)= 12 N / 5 kg

\(a_x\) = 2.4 \(m/s^{2}\)

For the y-component:

\(F_y\) = 9 N

m = 5 kg

Using \(F_y\) = \(ma_y\), we can solve for \(a_y\):

9 N = 5 kg * \(a_y\)

\(a_y\) = 9 N / 5 kg

\(a_y\)= 1.8  \(m/s^{2}\)

So, the acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:

|a| = \(\sqrt{(a_x^2) + (a_y^2)}\)

= \(\sqrt{(2.4^2) + (1.8^2}\)

= \(\sqrt{5.76 + 3.24}\)

= \(\sqrt{9}\)

= 3  \(m/s^{2}\)

Therefore, the magnitude of the acceleration of the object is 3  \(m/s^{2}\)

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Answer:

The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.

Explanation:

Volume of a Sphere

The volume of a sphere of radius r is given by:

\(\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3\)

The volume of each little sphere is:

\(\displaystyle V_l=\frac{4}{3}\cdot \pi\cdot 2^3\)

\(V_l=33.51\ mm^3\)

When the seven little spheres coalesce, they form a single bigger sphere of volume:

\(V_b=7*V_l=234.57\ mm^3\)

Knowing the volume, we can find the radius rb by solving the formula for r:

\(\displaystyle V_b=\frac{4}{3}\cdot \pi\cdot r_b^3\)

Multiplying by 3:

\(3V_b=4\cdot \pi\cdot r_b^3\)

Dividing by 4π:

\(\displaystyle \frac{3V_b}{4\cdot \pi}= r_b^3\)

Taking the cubic root:

\(\displaystyle r_b=\sqrt[3]{\frac{3V_b}{4\cdot \pi}}\)

Substituting:

\(\displaystyle r_b=\sqrt[3]{\frac{3*234.57}{4\cdot \pi}}\)

\(r_b=3.83\ mm\)

The surface area of the seven little spheres is:

\(A_l=7*(4\pi r^2)=7*(4\pi 2^2)=351.86\ mm^2\)

The surface area of the bigger sphere is:

\(A_b=4\pi r_b^2=4\pi (3.83)^2=184.33\ mm^2\)

The ratio between them is:

\(\displaystyle \frac{351.86\ mm^2}{184.33\ mm^2}=1.91\)

The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.

The amount of work done on the toboggan by the tension force of 105 N with a rope directed 32° above the snow is 3.12 KJ

W = F d cos θ

W = Work done

F = Force

d = Distance

θ = Angle between force and displacement vector

d = 35 m

F = 105 N

θ = 32°

W = 105 * 35 * cos 35°

W = 105 * 35 * 0.85

W = 3123.75 N m

W = 3.12 KJ

Work done is energy transferred to make an object move to a distance. Its unit is Joules which is denoted as J. It is the amount of work done by a force of 1 Newton to move a distance of 1 meter.

Therefore, the amount of work done on the toboggan by the tension force is 3.12 KJ

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Answer:

is the fastest moving type of radiationhe

When an earthquake applies a force to the building, then the pendulum exerts a force in the opposite direction of motion.

The following diagram shows the force applied by the pendulum and earthquake,

The force applied by the pendulum balances the earthquake's force so that the net force becomes zero on the building.

Hence, the building is saved.

Answer:

Pendulums are practically scales with weights on two different sides, so if an earthquake hits, the pendulum will try and evenly balance out the weight on both sides of a building so that it stays sturdy and doesn't fall.

Explanation:

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