A box contains 6 red pencils and 8 blue-pencils. A pencil is chosen at random and not
replaced. A second pencil is then chosen at random. Calculate the probability that at least one
of the pencils is red
Answers
Answer:
There are 14 pencils and 8 are blue
The probability of picking blue in the first pick = 8/14 =4/7.
The probability of picking blue in the second pick = 7/13 (as no replacement was there).
There are 14pencils and 6 are red.
The probability of picking red in the first pick = 6/14 =3/7
The probability of picking red in the second pick = 5/13. (as no replacement was there).
Related Questions
Solve for u. 7/6=u+4/8 Simply the answer.
Answers
Answer:
plz mark brainliest
Step-by-step explanation:
16/3 or 5 1/3
Answer:
\(u=\frac{16}{3}\)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDASEquality PropertiesStep-by-step explanation:
Step 1: Define
\(\frac{7}{6} =\frac{u+4}{8}\)
Step 2: Solve for u
Cross-multiply: \(7(8)=6(u+4)\)Multiply: \(56=6(u+4)\)Distribute 6: \(56=6u+24\)Isolate u term: \(32=6u\)Isolate u: \(\frac{32}{6} =u\)Simplify: \(\frac{16}{3} =u\)Rewrite: \(u=\frac{16}{3}\)Step 3: Check
Plug in u into the original equation to verify it's a solution.
Substitute in u: \(\frac{7}{6} =\frac{\frac{16}{3} +4}{8}\)Add: \(\frac{7}{6} =\frac{\frac{28}{3}}{8}\)Divide: \(\frac{7}{6} =\frac{7}{6}\)Here we see that 7/6 does indeed equal 7/6.
∴ \(u=\frac{16}{3}\) is a solution of the equation.
I think it can be a triangle but want another opinion
Answers
Answer:
I think It's a triangle too
Step-by-step explanation:
determine whether the raltion r on the set ofall integers is reflexin x =y^2
Answers
The relation "r" on the set of all integers, where x = y^2, is not reflexive.
A relation is reflexive if every element in the set is related to itself. In this case, for the relation x = y^2 to be reflexive, every integer "x" should be related to itself, meaning that x = x^2. However, this is not true for all integers.
For example, if we consider x = 2, it is not equal to 2^2 = 4. Similarly, if we consider x = -3, it is not equal to (-3)^2 = 9.
Since there are integers that do not satisfy the condition x = x^2, the relation x = y^2 is not reflexive on the set of all integers.
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Jack drove to the train station and back. It
took two hours less time to get there than
it did to get back. The average speed on
the trip there was 40 km/h. The average
speed on the way back was 24 km/h. How
many hours did the trip there take?
Answers
Answer:
8hoursStep-by-step explanation:
let the time taken to get back be x
so that the time needed to go is (x-2)
we know that speed= distance/time
therefore the speed for the return is 24 km/h.
distance (return)= 24*x
distance (return)=24x
therefore the speed to the station is 40 km/h.
distance (return)= 40*(x-2)
distance (return)=40x-80
We know that the distance is the same
24x=40x-80
24x-40x=-80
16x=80
divide both sides by 16
x=5
the time taken to get back is x=5hours
the time taken to is x-2=(5-2)= 3hours
the total trip takes 3+5= 8hours
Can someone help me with this ?
Answers
Step-by-step explanation:
shifts up and down are easy. we only need to adjust the original functional value by the constant of the shift.
the whole curve of the function stays optically the same, but as every calculated functional value is increased or decreased by the same value, the whole curve simply shifts up or down.
shift down 3 units means "f(x) - 3".
so, just for the shift down we would have
g(x) = 2×sqrt(x) - 3
but we also need to shift right by 5 units.
what does that mean ?
it means that we want to have every functional value as before, but ... 5 units of x "later" (to the right) than before.
so, e.g.
f(0) = 2×sqrt(0) = 2×0 = 0
so, we still want that 0 as functional value, but it should happen now at x = 5 instead of x = 0.
in other words
g(5) = f(0)
and further on
g(6) = f(1)
g(7) = f(2)
...
but also
g(4) = f(-1)
...
g(0) = f(-5)
and so on.
now look at the structure :
this means
g(x) = f(x-5)
and so,
g(x) = 2×sqrt(x-5) - 3
this function is now exactly like f(x), just shifted 5 units right and 3 units down.
Help me solve this.
Answers
Answer:
x=121.5
Step-by-step explanation:
Angle at the center =2 times angle at the circumference
Total angle at the center =360
Angle left=360-117=243
243/2=121.5
13 POINTS
Simplify the following expression
Answers
To simplify the expression "a^0b^-2c," we can apply the rules of exponents:
First, any number raised to the power of 0 is equal to 1. Therefore, "a^0" simplifies to 1.
Next, to simplify "b^-2," we can apply the rule that states "a^-n = 1/a^n." In this case, "b^-2" simplifies to "1/b^2."
Finally, we have "1 * 1/b^2 * c," which can be simplified as "c/b^2."
Therefore, the simplified exponents is "c/b^2."
The term "power" refers to the repeated multiplication of a factor, while the term "exponent" refers to the number increased to that base factor. The primary distinction between expression and power is this. The power 32, for instance, has a base of 3 and an exponent of 2.
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Triangle PQR is transformed to triangle P′Q′R′. Triangle PQR has vertices P(8, 0), Q(6, 2), and R(−2, −4). Triangle P′Q′R′ has vertices P′(4, 0), Q′(3, 1), and R′(−1, −2).
Plot triangles PQR and P′Q′R′ on your own coordinate grid.
Part A: What is the scale factor of the dilation that transforms triangle PQR to triangle P′Q′R′? Explain your answer. (4 points)
Part B: Write the coordinates of triangle P′′Q′′R′′ obtained after P′Q′R′ is reflected about the y-axis. (4 points)
Part C: Are the two triangles PQR and P′'Q′'R′' congruent? Explain your answer. (2 points)
Answers
Answer:
Part A: The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' is 1/4
Part B:
P''(-1, 0)
Q''(0, -1)
R''(2, -1)
Part C:
The two Triangles PQR and P''Q''R'' are not congruent.
It is geometry the question is on the paper can you please help me I’m desperate
Answers
Given:
The lines l and m are parallel lines and x=40 degrees.
To find the angle:
\(\angle\text{DEF}\)We know that alternate angles are equal.
So that,
\(\begin{gathered} \angle EDG=x \\ =40^{\circ} \end{gathered}\)And then, using the angle sum property of a triangle,
\(\begin{gathered} \angle EDG+\angle DFE+\angle DEF=180^{\circ} \\ 40^{\circ}+40^{\circ}+\angle DEF=180^{\circ} \\ \angle DEF=180^{\circ}-40^{\circ}-40^{\circ} \\ \angle DEF=100^{\circ} \end{gathered}\)Thus, the measure of angle DEF is 100 degrees.
Peter bought three Note 20 Android phones costing 1050 dollars each. If he had 4000 dollars in his checking account, write a numerical expression and then find his balance after he paid for the phones. Solution
Answers
Answer:
4000 - 3(1050)
= 850
Step-by-step explanation:
Start with the 4000 that's in the account. Then subtract 3(1050) which represents 3×1050, the cost of three phones.
4000 - 3(1050)
= 4000 - 3150
= 850
He has 850 left in his account.
A partly-full paint can has 0.878 U.S. gallons of paint left in it. (a) What is the volume of the paint, in cubic meters? (b) If all the remaining paint is used to coat a wall evenly (wall area = 13.7 m2), how thick is the layer of wet paint? Give your answer in meters.
Answers
a) The volume of paint left in the can is:
.878 gallons * 0.00378541 m^3/gallon = 0.003321 m^3
b) the thickness of the layer of wet paint is 0.000242 meters or 0.242 millimeters (since there are 1000 millimeters in a meter).
(a) To convert gallons to cubic meters, we need to know the conversion factor between the two units. One U.S. gallon is equal to 0.00378541 cubic meters. Therefore, the volume of paint left in the can is:
0.878 gallons * 0.00378541 m^3/gallon = 0.003321 m^3
(b) We can use the formula for the volume of a rectangular solid to find the volume of wet paint needed to coat the wall evenly:
Volume = area * thickness
We want to solve for the thickness, so we rearrange the formula to get:
Thickness = Volume / area
The volume of wet paint needed is equal to the volume of dry paint needed since they both occupy the same space when the paint dries. Therefore, the volume of wet paint needed is:
0.003321 m^3
The area of the wall is given as:
13.7 m^2
So the thickness of the layer of wet paint is:
0.003321 m^3 / 13.7 m^2 = 0.000242 m
Therefore, the thickness of the layer of wet paint is 0.000242 meters or 0.242 millimeters (since there are 1000 millimeters in a meter).
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r1(t)=(2,1,8)+t⟨0,−2,1⟩
r2(t)=(6.5,0.5,10.5)+t⟨−3,3,−3⟩
Find the point of intersection, PP, of the lines r1r1 and r2r2.
P =
Answers
To find the point of intersection (P) of the lines r1 and r2. First, let's express the parametric equations of the lines as follows:r1(t) = (2, 1 - 2t, 8 + t)
r2(t) = (6.5 - 3t, 0.5 + 3t, 10.5 - 3t)
For these lines to intersect, the corresponding coordinates must be equal. Let's denote the parameter for r1 as t1 and for r2 as t2. This gives us the following system of equations:
1. 2 = 6.5 - 3t2
2. 1 - 2t1 = 0.5 + 3t2
3. 8 + t1 = 10.5 - 3t2
Solving equation 1 for t2, we get t2 = (6.5 - 2) / 3 = 1.5. Now, we can plug this value into equations 2 and 3:
1 - 2t1 = 0.5 + 3(1.5) => t1 = -2
8 + (-2) = 10.5 - 3(1.5) => t1 = -2
Since both equations result in t1 = -2, we have a consistent solution. Now, we can find the point of intersection P by plugging t1 and t2 into the parametric equations of r1 and r2:
P = r1(-2) = (2, 1 - 2(-2), 8 - 2) = (2, 5, 6)
Therefore, the point of intersection P is (2, 5, 6).
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Solve equation by using the quadratic formula. 6 x squared minus 2 x = 8 a. X = three-fourths, negative 1 c. X = three-fourths, 0 b. X = three-fourths, 1 d. X = four-thirds, negative 1.
Answers
The roots of the quadratic equation 6x²-2x=8 are x=4/3 and x=-1.
Given that,
The equation is 6x²-2x=8
To find : The roots of the quadratic equation 6x²-2x=8
Any equation that can be rearranged in standard form as where x represents an unknown value, and a, b, and c represent known values, where a 0, is referred to as a quadratic equation in algebra (from Latin quadratus, "square"). The equation is linear, not quadratic, if a = 0 and b 0. The coefficients of the equation are the numbers a, b, and c, which can be separated by naming them, respectively, the quadratic coefficient, the linear coefficient, and the constant coefficient or free term.
We know that,
The solutions are x1 and x2 = -b±√b²-4ac/2a
Here b = -2 ,a = 6 and c= -8
No substitute those values in the formula,
= -b±√b²-4ac/2a
= -(-2) ± √(-2²)-4(6)(-8) / 2(6)
x = 4/3 and x =-1
So, The roots of the quadratic equation 6x²-2x=8 are 4/3 and -1
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Which are two possible reasons for the change within the frog population?
–3.2, 4.8, –7.2, 10.8, …
Answers
The given sequence;–3.2, 4.8, –7.2, 10.8, is a geometric progression common ratio of -1.5.
What is a geometric series?When all the terms of a geometric sequence are added, then that expression is called geometric series.
The given sequence ;
–3.2, 4.8, –7.2, 10.8, …
The common ratio
= -4.8/ 3.2
= - 1.5
The terms having a common ratio of -1.5 best describe the relationship between the successive terms in the sequence of the terms.
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The cost of four brands of spray paint are listed in the table below. Which brand of spray paint costs the least per ounce?
A: Brand K (4 ounces, $3.97)
B: Brand L (6 ounces, $5.89)
C: Brand M (8 ounces, $7.29)
D: Brand N (5 ounces, $4.49)
Answers
Brand L - $0.9816 per ounce
Brand M - $0.91125 per ounce
Brand N - $0.898 per ounce
-> cheapest is Brand N
A girl buys a monthly bus pass, which entitles her to unlimited bus travel, for $40 per month. Without the pass each bus ride costs $1.60. How many rides per month would she have to take so that the cost of the rides without the bus pass is equal to the total cost of the rides with the bus pass?
The number of rides at which the unlimited ride pass equals the cost of individual ride purchases is ?.
Answers
Answer: 25 Rides
Step-by-step explanation:
Forty (cost of pass per month) divided by 1.60 (Cost of rides) = 25 rides until the cost of the rides equals the price of the pass.
Pls help asap!!!
You have studied the properties and theorems of circles related to radii, chords, secants, and tangents. These components help to create angles and segments inside and outside a circle. However, there are also properties and components associated with two circles together. Alicircles are similar to each other and all circles are congruent when their radii have the same length. For this project, let's consider the intersection of two circles. There are three possible arrangements.
1. No point of intersection
Answers
Therefore , the solution of the given problem of circle comes out to be the intersection points can be used to make chords and secants, among other forms and angles.
What is circle?A circle is formed by each region of a plane that is a certain distance from this extra point (center). It thus consists of spots that are isolated from one another by the surface and is curved. It also revolves about the centre equally from all angles. In the constrained, the double sphere of a circular, every group of endpoints is uniformly separated from the "centre." By tracing a thread through a circle, one can create a line to circular symmetry.
Here,
The sum of the radii determines the distance between the circular centres.
a single intersection
Two circles are said to be "tangent" or "touching" at a particular location when their paths cross. This indicates that there is only one spot in common between the two circles. The difference in radii is equivalent to the distance between the circle centres.
There are two intersections.
Two circles are said to be "intersecting" when they touch at two places. This indicates that there are two similarities between the two spheres. Less than the total of the radii, but larger than the difference of the radii, is the distance between the centres of the circles.
The intersection points can be used to make chords and secants, among other forms and angles.
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Is (5.7) a solution for the following system of equations?
y=2x-3
yr+2
Answers
Answer:
There are no solution to those equations
Step-by-step explanation:
An English examination has two sections. Section A has five questions and section B has four questions, Four questions must be answered in total.
how many different ways are there of selecting four questions if there must be at least one question answered from each section?
Answers
Next, we find the number of ways of selecting four questions if none are selected from section A or none are selected from section B. The number of ways of selecting four questions from section A is 5C4 = 5, and the number of ways of selecting four questions from section B is 4C4 = 1. So the total number of ways of selecting four questions if none are selected from section A or section B is 5 + 1 = 6.
Finally, we subtract the number of ways of selecting four questions if none are selected from either section from the total number of ways of selecting four questions to get the number of ways of selecting four questions if at least one question is selected from each section: 126 - 6 = 120.
Therefore, there are 120 different ways of selecting four questions if there must be at least one question answered from each section.
Using a truck, Mr. Salazar needs to haul (4.2 tons) of gravel from a quarry to his house. His truck can hau (3/5 tons) of gravel at one time. What is the least number of trips Mr. Salazar will need to make from the quarry to his house?
A.7
B.8
C.6
D.12
Answers
Armando wants to raise funds at his school fair. He plans to charge 10 cents to pick marshmallows from his bag without looking. He will give: • 20 cents to anyone who picks a Blue marshmallow. • 50 cents to anyone who picks a Yellow marshmallow. • $1 to anyone who picks a White marshmallow. • Anyone picking a Red or Green marshmallow will lose their money There are as equal number of marshmallows of each color. 3a. Show work and explain why Armando will lose money with this game. Justify using mathematics.
Answers
Since the expected value for this game is negative, Armando will lose money.
The expected value is given by the sum of all outcomes multiplied by it's respective probability.In this problem:
There are blue, yellow, white, red and green marshmallows, each with a \(\frac{1}{5}\) probability of being picked.If red or green marshmallows are picked, Armando get the charge of $0.1.If someone picks a blue marshmallow, he loses $0.1.If someone picks a yellow marshmallow, he loses $0.4.If someone picks a white marshmallow, he loses $0.9.Thus, the expected value is:
\(E = 0.1\frac{2}{5} - 0.1\frac{1}{5} - 0.4\frac{1}{5} - 0.9\frac{1}{5} = \frac{0.2 - 0.1 - 0.4 - 0.9}{5} = -0.24\)
Since the expected value for this game is negative, Armando will lose money.
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An MP3 player costs $70 and song downloads cost $0.95 each. Write an expression that represents the cost of the MP3 player and x number of song downloads
Answers
y=0.95x+70
Answer: C
Step-by-step explanation: An MP3 player costs $70 and song downloads cost $0.95 each. Write an expression that represents the cost of the MP3 player and x number of song downloads
Where should you plot the ordered pair (3,4) in relation to the origin?
Answers
Answer:
3 goes on the x acsis 4 goes on the y axsis
Factor x^2-4x-63=-6x?
Answers
Check out the attached photo
( x + 9 ) ( x - 7 )
7. Using the diagram below, find the length of segment 5G
3x+1
6%
X+6
t
S
А G
w
Answers
Answer:
\(\huge\boxed{\sf SG = 31}\)
Step-by-step explanation:
Given:
SW = 3x + 1
WA = 6x
AG = x + 6
SW = AG
Required:
Length of SG = ?
Solution:
Given that:
SW = AG
3x + 1 = x + 6
Combining like terms
3x - x = 6 - 1
2x = 5
x = 5/2
x = 2.5
Now,
SG = SW + WA + AG
SG = 3x + 1 + 6x + x + 6
SG = 3x + 6x + x + 1 + 6
SG = 10x + 6
Put x = 2.5
SG = 10(2.5) + 6
SG = 25 + 6
SG = 31
\(\rule[225]{225}{2}\)
Hope this helped!
~AH1807Peace!(0,6) and the slope is 3
Answers
Answer:
Step-by-step explanation:
y-intercept (c)= 6
slope (m) = 3
Writing in slope intercept form
y = mx + c
y = 3x + 6
hope it helps :)
Nine more than the product of the rate And the time
Answers
Answer:
If r = rate and t = time: rt+9
Step-by-step explanation:
One type of uranium has a radioactive decay
rate of 0.4% per day. If 60 pounds of this
uranium is available today, how much will still
remain after 20 days? Use y = 60(0.996)*, and
let x be 20.
Answers
Remaining uranium after 20 days: 47.84 lbs (initial: 60 lbs, decay rate: 0.4% per day).
What is the remaining uranium after 20 days?To solve this problem, we need to use the formula for exponential decay:
\(y = a(1 - r)^t\)
where y is the final amount, a is the initial amount, r is the decay rate (as a decimal), and t is the time elapsed.
In this case, we are given that the initial amount is 60 pounds, the decay rate is 0.4% or 0.004 per day, and the time elapsed is 20 days. Therefore, we can plug these values into the formula to get:
y =\(60(1 - 0.004)^20\)
Simplifying the equation, we get:
\(y = 60(0.996)^20\)
Using a calculator, we find that:
\(y ≈ 47.84\)
Therefore, the amount of uranium that will still remain after 20 days is approximately 47.84 pounds.
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x+x/7 + 1/11 (x + x/7) = 60
Answers
x
x
by simplifying both sides of the equation, then isolating the variable.
Exact Form:
x
=
385
8
x
=
385
8
Decimal Form:
x
=
48.125
x
=
48.125
Mixed Number Form:
x
=
48
1
8
x
=
48
1
8
Answer:
X= 48.125
Step-by-step explanation:
Find the perimeter of the figure
Answers
Answer: 30
Step-by-step explanation: 6 + 4 + 4 + 9.5 + 6 + 6.5 = 30