A bouncy ball with mass m =50, kg is moving toward the wall at v = 20 m/s
and at an angle of 0 = 45° with respect to the horizontal. The ball makes a perfectly elastic
collision with the solid, frictionless wall and rebounds at the same angle with respect to the
horizontal. The ball is in contact with the wall for t = 0.5s,

What is the change in momentum AP of the bouncy ball? (3 pts)


What is the average force F the wall exerts on the bouncy ball (3 pts)

Answer: 8v

Explanation:

The total voltage drop across the first and second resistor is 8 V, hence option A is correct.

Voltage is the fluctuation in electric potential between the two places. It is sometimes produced by electric pressure, electric tension, or voltage source. The work required to move a test charge between two places in a static electric field corresponds to this. The derived measure for voltage in the International System of Units is called a volt. Work per unit energy is expressed in SI units as joules per coulomb, with 1 volt equaling 1 joule per 1 coulomb.

To detect the voltages between two locations in a circuit, use a voltmeter. A common reference point, like the system's foundation, is frequently utilized as one of the points.

A voltage can indicate either a supply of energy or its loss, dissipation, or storage.

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The wave velocity is found to be v = w/k.

The velocity associated with the disturbance propagating in the given medium is defined as wave velocity; in other words, wave velocity is the distance traveled by waves per unit of time.

The wave velocity is determined by the medium employed.

The wave velocity is often referred to as the phase velocity.

The perturbations in wave motion pass across the medium as a result of the particles' recurrent periodic oscillations. The velocity of the wave will differ from the velocity with which the particles vibrate about their mean positions. The wave velocity will always be constant, while the particle velocity will vary over time.

Given that

E = E₀ sin(kx-wt)j

B = B₀ sin(kx-wt)j

E₀ - Amplitude of electric field

B₀ - Amplitude of magnetic field

and k = 2π/λ

λ = 2π/k

and w = 2πn

where n is the angular frequency

Thus, the velocity of the wave

v= nλ

v = (w/2π) (2π/k)

v = w/k

Thus, the velocity of the wave is v = w/k.

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Starting from the core of the sun and going outward, the temperature decreases. yet, above the photosphere, the temperature increases. it is because the temperature is related to  the average kinetic energy of the components

The deepest layer of the sun is the core. With a thickness of 160 g/cm^3, 10 times that of lead, the core could be anticipated to be strong.. In the core, combination responses create energy within the frame of gamma rays and neutrinos. The gamma rays are retained and re-emitted by numerous molecules on their travel from the envelope to the exterior of the sun. The photosphere is the zone from which the daylight we see is radiated. The photosphere may be a comparatively thin layer of low-pressure gasses encompassing the envelope. It is as it were many hundred kilometers thick, with a temperature of 6000 K. The thickness of the sun-oriented envelope is much less than that of the center. The core contains 40 percent of the sun's mass in 10 percent of the volume, whereas the sun-oriented envelope has 60 percent of the mass in 90 percent of the volume. The sun-oriented envelope puts pressure on the center and keeps up the core's temperature.

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Answer:

2000

Explanation:

well it is just   20 * 100 = 2000 v

The total distance covered before take off is 6234.38 meters, under the condition that  airplane from rest accelerates on a runway at 6.25 m/s2 for 31.50 s .

The distance covered by the airplane before takeoff can be evaluated applying the formula

distance = initial velocity × time + 0.5 × acceleration × time²

Then, the initial velocity is 0 m/s since the airplane starts from rest. The acceleration is 6.25 m/s² and the time taken is 31.50 s.

Staging these values in the formula

distance = 0 × 31.50 + 0.5 × 6.25 × (31.50)²

= 6234.38 meters (approx)

Then, the evaluated distance taken by the airplane before takeoff is  6234.38 meters.

Acceleration is called  the rate of alteration of velocity concerning time. It is said to be  a vector quantity that possess both magnitude and direction. When an object accelerates, it experiences alterations to its velocity by either changing its speed or direction or both.

The SI unit regarding acceleration is meters per second squared (m/s²).

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The car is slowing down at a rate of 2.5mph/s

2. The greatest acceleration is 10 mph/s.

3. In the interval 4s to 16s the speed remains constant and has magnitude 25 mph.

Step-by-step explanation:

1. The deceleration of the car is from 16 seconds to 24 seconds is the slope mm of the graph from 16 to 24:

m=δs/δt

m=(5-25)/(24-16)

m= -2.5mph/s

δtime

δspeed

the negative sign indicates that it is deceleration.

2. The automobile experiences the greatest change in speed when the slope is greatest because that is when acceleration/deceleration is greatest.

From the graph we see that the greatest slope of the graph is between 28 and 24 seconds. The acceleration the interval is the slope mm :

m= {45-5}/{28-24}= 10mph/s

= 28−24

45−5

​

=10mph/s

3. The automobile experiences no acceleration in the interval 4 s to 16 s—that's the graph is flat.

The speed of the automobile in that interval, as we see from the graph, is 25 mph.

Disclaimer: the question is incomplete in the portal. Here is the complete question.

question: The function shown below was created to track the different intervals of speed that an automobile travels over a period of 28 seconds. Use the graph of the function to complete Parts 1-3. After traveling for 16 seconds, the automobile begins to slow its speed at a steady rate. Use the coordinates on the graph to determine the rate at which the car is slowing down, in miles per hour per second. During which interval of time does the automobile experience the greatest change in its speed? What is the change in the automobile’s speed during this interval? For a time period of approximately 10 seconds, the automobile experiences no change in its speed. During which interval of time does the automobile’s speed remain constant? At what speed is the automobile traveling during this interval?

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Answer:

The first one is wrong, they don’t push nor pull, it’s an invisible force that acts on everything equally

Explanation:

Hopes this helps

A Year on mercury is less than 40% as long as a year on earth.

According to Kepler's Third Law, the cubes of the semi-major axes of the orbits of the planets are directly proportional to the squares of the planets' orbital periods. According to Kepler's Third Law, as an orbiting planet's radius increases, so does the time of its orbit around the Sun. Thus, we learn that Mercury, the innermost planet, completes its orbit of the Sun in just 88 days. Saturn needs 10,759 days to complete the same task as the earth does in 365 days. Despite the fact that Kepler had no knowledge of gravitation at the time he developed his three laws, Isaac Newton used them to derive his theory of universal gravitation, which explains the mysterious force behind Kepler's Third Law.

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The strength of the electric field at (2.0m, 3.0m) is 880 V/m and the direction of the electric field is 116.6 degrees counterclockwise from the positive x-axis.

To find the electric field strength and direction, we need to take the negative gradient of the electric potential. Therefore, we first need to find the partial derivatives of V with respect to x and y:

Vx = 400x V/m

Vy = -440y V/m

Next, we can calculate the electric field components:

Ex = -Vx = -400x V/m

Ey = -Vy = 440y V/m

At the point (2.0m, 3.0m), the electric field strength can be calculated as:

E = sqrt(Ex^2 + Ey^2) = sqrt((-400x)^2 + (440y)^2) = 880 V/m

The direction of the electric field can be determined as:

theta = arctan(Ey/Ex) = arctan(440y/(-400x)) = 116.6 degrees counterclockwise from the positive x-axis.

Therefore, the electric field strength at (2.0m, 3.0m) is 880 V/m and the direction of the electric field is 116.6 degrees counterclockwise from the positive x-axis.

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R(F) = 4F - 160

a. R¹(P) represents the temperature at which a cricket chirps at a rate of P chirps per minute.

b. R(60) refers to the chirping rate of the cricket when the temperature is 60 degrees Fahrenheit, while R¹(60) represents the temperature at which the cricket chirps at a rate of 60 chirps per minute.

The equation R(F) = 4F - 160 represents the relationship between the temperature of the cricket's environment (F) and its chirping rate (R). By plugging in different temperature values, we can determine the corresponding chirping rate.

For example, when we calculate R(60), we find the chirping rate at 60 degrees Fahrenheit.

In this case, R(60) = 4(60) - 160 = 240 - 160 = 80 chirps per minute.

On the other hand, when we calculate R¹(60), we are looking for the temperature at which the cricket chirps at a rate of 60 chirps per minute. Solving the equation 60 = 4F - 160, we find F = 70 degrees Fahrenheit. Therefore, R¹(60) = 70.

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Answer:4 miles

Explanation:

When the initial velocity of the particle is perpendicular to the magnetic field lines, The particle will undergo circular motion.

When a charged particle moves through a uniform magnetic field at a constant speed and with an initial velocity perpendicular to the magnetic field lines, it will experience a force that is perpendicular to both its velocity and the magnetic field lines.

This force will cause the particle to move in a circular path, with the radius of the path depending on the particle's speed, charge, and the strength of the magnetic field. This phenomenon is known as the Lorentz force and is the basis for many applications, including particle accelerators and MRI machines.

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Complete Question:

A charged particle moving at a constant speed enters a uniform magnetic field. the initial velocity of the particle is perpendicular to the magnetic field lines. the particle will _____.

While every celestial object appears to go around the Earth once a day due to the Earth's rotation, the celestial object with the fastest apparent motion in the sky is the Moon.

The apparent motion of celestial objects in the sky is a combination of their actual motion and the rotation of the Earth. As the Earth rotates on its axis, it creates the illusion that all celestial objects are moving across the sky from east to west once every 24 hours.

However, the Moon, being the closest celestial object to Earth, has a noticeable and relatively fast apparent motion compared to other celestial objects. Due to its orbital motion around the Earth, the Moon moves across the sky at an average rate of about 13.2 degrees per day. This rapid motion makes the Moon easily observable as it changes its position against the background stars and planets over relatively short periods.

In contrast, other celestial objects such as stars, planets, and distant galaxies have much slower apparent motion in the sky. Their movement is predominantly governed by their own motion through space and not primarily influenced by the Earth's rotation.

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Answer:

Work done = 80 gm/s

Explanation:

Given:

Final velocity (v) = 4 m/s

Initial velocity (u) = 0 m/s

Mass of ball (m) = 40 g

Find:

Work done.

Computation:

Using work energy rule

Work done = Change in kinetic energy

Work done = 1/2[mv-mu]

Work done = 1/2[(40)(4) - (40)(0)]

Work done = 1/2[(40)(4)]

Work done = 80 gm/s

Answer:

See Explanation

Explanation:

Given

Cyclist 1:

\(Distance = 40km\)

\(Time = 2hr\)

\(Direction = East\)

Cyclist 2:

\(Distance = 10km\)

\(Time = 0.5hr\)

\(Direction = West\)

The question requires options. Since none is given,  I'll answer on a general term.

First, calculate the speed of both cyclists

\(Speed = \frac{Distance}{Time}\)

Cyclist 1:

\(Distance = 40km\)

\(Time = 2hr\)

\(Speed = \frac{40km}{2hr}\)

\(Speed = 20km/hr\)

Cyclist 2:

\(Distance = 10km\)

\(Time = 0.5hr\)

\(Speed = \frac{10km}{0.5hr}\)

\(Speed = 20km/hr\)

The following can be deduced from above:

While the magnet become desk bound, a modern-day of milliamps turned into generated. we discovered the outcomes to be exactly in present day route, at the same time as the present day maximums have been 0, negative, positive, opposite, and the equal.

A magnet is a material or object that produces a magnetic field, which is a force that can attract or repel certain other materials, such as iron or steel. Magnets are characterized by their ability to attract ferromagnetic materials, which are those that contain iron, cobalt, nickel, or other magnetic elements.

Magnets can be natural, such as lodestone, or man-made, such as those made from alloys or magnets created by passing an electrical current through a coil of wire. They can be permanent or temporary, and can come in a variety of shapes and sizes, from small refrigerator magnets to large industrial magnets. Magnets have many practical applications, including in electric motors, generators, magnetic storage devices such as hard drives, and medical imaging equipment such as MRI machines.

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Complete Question: -

Use the drop-down menus to complete each description about the experimental results.

First, we verified that magnet movement would induce a current. Each time the magnet moved near the wire loop, whether it was moving forward or in reverse, a current registered. When the magnet was stationary, a current of milliamps was generated.

Under normal magnet polarity, whenever the magnet was moving toward the loop, the induced current had a value, and a value if the magnet was moving in reverse. Under reversed polarity, we found the results to be exactly in current direction, while the current maximums were .

Answer:

In order:

> 0

> Negative

> Positive

> Opposite

> The same

Answer:

hola me llamo bruno y tu?

Explanation:

pero yo soy de mexico

Answer:

Ions are formed by the addition of electrons to, or the removal of electrons from, neutral atoms or molecules or other ions; by combination of ions with other particles; or by rupture of a covalent bond between two atoms in such a way that both of the electrons of the bond are left in association with one of the ..

Answer:

Ions are formed when atoms lose or gain electrons, simply when electrons from the metal transfers electrons from its outermost shell( forming a positively charged metallic ion) to the outermost shell of the non-metallic atom( forming a negatively charged ion)

El calentamiento del instrumento viento antes de un concierto asegura que todos los instrumentos estén afinados y existan un mejor sonido, debido al cambio de frecuencia del instrumentos por los cambios de velocidad del aire debido al cambio de temperatura

Los instrumentos musicales trabajan por procesos de resonancia, ya sean de cuerda o viento; en los instrumentos de viento la frecuencia que emites esta dada por la relación  

                   fₙ = \(n \ \frac{v_s}{2L}\)    n = 1, 2, 3, ...

Donde f es la frecuencia emitida, L la longitud del tubo n es una constante entera y v_s es la velocidad del sonido

La velocidad del sonido en el aire depende de la temperatura del aire, según la relacion          

               vs = vo + 0,6 T  

Donde v₀ es la temperatura del aire a 0ºC, v₀ = 331 m/s y T la temperatura en grados centígrados.

De esta dos expresiones podemos ver que la frecuencia que emite el instrumento de viento depende  de la temperatura del aire, además en los instrumentos con boquilla la frecuencia de resonancia de la boquilla también depende de la temperatura de la boquilla que por ser liviana cambia fácilmente.

En conclusión el calentamiento del instrumento antes de un concierto asegura que todos los instrumentos estén afinados y existan un mejor sonido, debido al cambio de frecuencia del instrumentos por los cambios de velocidad del aire debido al cambio de temperatura

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Answer:

a

 \(a = 21.7 \ m/s^2\)

b

\(F = 108.5 \ N\)  

Explanation:

From the question we told that

   The mass is  m  =  5 kg

    The initial speed \(u = 5 m/s\)

    The time taken to attain \(v = 70 \ m/s\) is  t =  3 s

Generally from kinematic equation we have that

     \(v = u + at\)

=> \(70 = 5 + a * 3\)

=>  \(a = 21.7 \ m/s^2\)

Generally  the force acting is mathematically represented

        \(F = m * a\)

=>      \(F = 5 * 21.7\)  

=>      \(F = 108.5 \ N\)  

1. If the plug is moved from one position to another, the frequency of the standing wave remains constant.

2. If the plug is moved to a position where the distance between nodes or antinodes decreases, the wavelength of the standing wave will decrease.

3. The wave speed of the standing wave will remain constant regardless of the position of the plug.

As the plug is moved from one position to another in a system where a standing wave is formed, several changes occur in the standing wave frequency, wavelength, and wave speed:

1. Standing wave frequency: The frequency of a standing wave is determined by the vibration frequency of the source that creates the wave. Therefore, if the plug is moved from one position to another, the frequency of the standing wave remains constant as long as the source frequency remains the same. The movement of the plug does not directly affect the frequency of the standing wave.

2. Standing wave wavelength: The wavelength of a standing wave is determined by the distance between two consecutive nodes or antinodes. When the plug is moved, the position of nodes and antinodes may change, affecting the wavelength of the standing wave. If the plug is moved to a position where the distance between nodes or antinodes increases, the wavelength of the standing wave will also increase. Conversely, if the plug is moved to a position where the distance between nodes or antinodes decreases, the wavelength of the standing wave will decrease.

3. Wave speed: In a medium, the wave speed is determined by the properties of the medium, such as its density and elasticity. The movement of the plug does not directly change the properties of the medium, so it does not affect the wave speed. As long as the medium remains the same, the wave speed of the standing wave will remain constant regardless of the position of the plug.

It's important to note that the specific changes in the standing wave frequency, wavelength, and wave speed will depend on the details of the system and the nature of the wave being generated.

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Answer:

Fc = 4340,93 Newton

Explanation:

Dados los siguientes datos;

Masa = 900 kg

Velocidad, V = 50 km/h a metros por segundo = (50 * 1000)/(60 * 60) = 50000/3600 = 13,89 m/s

Radio, r = 40 m

Para encontrar la fuerza centrípeta;

Fc = mv² / r

Fc = (900 * 13,89²)/40

Fc = (900 * 192,93)/40

Fc = 173637/40

Fc = 4340,93 Newton

Once a beam of light enters a black hole, it can never exit.

Moreover, A black hole is a region where space-time is so curved that every possible path that light could take eventually curves back inside the black hole. As a result, once a beam of light enters a black hole, it can never exit. Because of this, a black hole is truly black and never emits light. It appears as a dark circle silhouetted by an orbiting disk of hot, glowing matter. The supermassive black hole is located at the heart of a galaxy called M87, located about 55 million light-years away, and weighs more than 6 billion solar masses.

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The angle of incline is 17.2 degrees above horizontal.

The acceleration of an object down a slope is directly proportional to the sine of the angle of inclination of the plane.

This means that the acceleration is constant for a given slope angle.

Therefore, we will be able to determine the angle of inclination by dividing the given acceleration by the gravitational acceleration.  

The gravitational acceleration is 9.8 m/s^2.We will use the formula for the angle of inclination of a slope given by;θ=arcsin(a/g)where;a = accelerationg = gravitational accelerationθ = angle of inclination

Thus, we substitute the values we have;a = 3.00 m/s²g = 9.8 m/s²

Now,θ=arcsin(3.00/9.8)θ= 17.2 degrees (rounded to 3 significant figures)

Therefore, the angle of the incline above horizontal is 17.2 degrees.

Summary The angle of inclination of the plane is 17.2 degrees above horizontal.

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Answer:

R = 240 Ω

Explanation:

The resistance created by the light bulb can be calculated by using Ohm's Law:

\(V = IR\\\\R =\frac{V}{I}\)

where,

R = Resistance created by the light bulb = ?

V = Voltage across the bulb = 120 volts

I = current passing through the light bulb = 0.5 A

Therefore,

\(R = \frac{120\ volts}{0.5\ A}\)

R = 240 Ω

The resultant of the two given vectors is 346.4 units.

The resultant of the three vectors is the sum of all the three vectors acting together. The resultant vector is the single vector that will represent all the three vectors in terms of magnitude and direction.

The sum of the vectors in x-direction;

Vx = V cosθ

where;

for 200 units, θ = 0⁰ (above the horizontal)

for 400 units, θ = 60⁰ (above the horizontal)

Vx = 200 cos(0) - 400 cos(60)

Vx = 0

The sum of the vectors in y-direction;

Vy = 200 sin(0) + 400 sin(60)

Vy = 346.4 units

The resultant vector is calculated as;

V = √(Vx² + Vy²)

V = √(0² + 346.4²)

V = 346.4 units

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Answer:

the process of that happening is called Dissolving

the substance that is dissolved is called

Solute

The first law of thermodynamics provides a fundamental principle for energy conservation in thermodynamic systems. It states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (q) minus the work done by the system (w).

According to the first law of thermodynamics, the energy of a system can neither be created nor destroyed, only transferred or converted from one form to another. As a result, there are two ways to quantify energy change in a system: as a result of heat transfer and as a result of work done. The first law of thermodynamics is expressed mathematically as follows:

ΔU = q - w

where ΔU is the change in internal energy, q is the heat added to the system, and w is the work done by the system.

Therefore, to express q in terms of ΔU and w:q = ΔU + w. This equation allows us to quantify the relationship between heat, work, and the change in internal energy of a system, providing a basis for analyzing and understanding energy transfers in various processes.

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The equivalent capacitance Ceq of the circuit is 75 x 10⁻⁶ F, and the energy stored on capacitor C₁ is 49 x 10⁻⁶ J.

equivalent capacitance Ceq of a circuit with three capacitors in parallel can be found by adding the individual capacitances. In this case, C₁ = 16 µF, C₂ = 6 µ

F, and C₃ = 10 µ

F. So, Ceq = C₁ + C₂ + C₃

= 16 µ

F + 6 µ

F + 10 µ

F = 32 µF. Therefore, the answer to the first question is A. 75 x 10⁻⁶ F.

The energy stored on a capacitor can be calculated using the formula

E = 1/2 ×C ×V²

where E is the energy, C is the capacitance, and V is the voltage across the capacitor. Since the charge Q₁ on capacitor C₁ is given as 12 µC and the capacitance C₁ is 16 µF, we can calculate the voltage V₁ across capacitor C₁ using the formula Q = C ×V.

Thus, V₁ = Q₁ / C₁

= 12 µC / 16 µ

F = 0.75 V.

Now, we can calculate the energy stored on capacitor C₁ using the formula E₁ = 1/2 ×C₁ ×V₁²

= 1/2 ×16 µF ×(0.75 V)²

= 9 µJ.

Therefore, the answer to the second question is A. 49 x 10⁻⁶ J.

In conclusion, the equivalent capacitance Ceq of the circuit is 75 x 10⁻⁶ F, and the energy stored on capacitor C₁ is 49 x 10⁻⁶ J.

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The star with the highest temperature out of the six listed is Regulus.

The color index of a star is inversely proportional to its temperature. That is the higher the color index, the lower the temperature, the lower the color index, the higher the temperature.

This star has a temperature of around 12,000 Kelvin, which is much higher than the other stars listed. The temperature of a star can be determined by its color, with the hottest stars appearing blue or white and the coolest stars appearing red or orange. An index known as the B-V color index is often used to classify stars based on their temperatures. Regulus has a B-V color index of -0.09, indicating that it is a very hot star.

So, the Regulus with the lowest value of the color index is the hottest star among these.

Star data in the picture.

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