A book is moved once around the perimeter of a tabletop with dimensions 1.2 m x 1.8 m.
(a) If the book ends up at its initial position, what is its displacement
(b) What is the distance traveled?​

Answer:

the answer to this is letter b

Answer:

B) Technology helps scientists study things that are very small, far away, or hard to reach.

Answer:

Friction is a force that slows down the motion of a moving object. ... Eventually, friction and gravity will work together to stop the motion of the slide. Gravity is a force that pulls two objects toward each other because of their mass. Mass is the measurement of the amount of material (matter) that makes up an object.

My science notebook is drawn to the desk's surface by gravity. Unless pressing the book is hard enough to overcome static friction, friction prevents it from slipping off the desk's surface.

The amount of power required to move my pencil over the page to write depends on how much friction there is between my pencil and the paper.

Rock, soil, and debris will continue to slide once it starts until the friction between the material and the ground slows it down. Gravity and friction will eventually combine to stop the slide's momentum.

Therefore, due to their mass, two objects are drawn toward one another by the force of gravity, so forces of gravity and friction affect the motion.

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Answer:

The speed of a wave is equal to the wavelength divided by the period. The wavelength is the distance between two consecutive nodes, and the period is the time it takes for one complete cycle of the wave.

In this case, the wavelength is 6 m and the period is 0.2 s. Therefore, the speed of the wave is 30 m/s.

The answer is 30 m/s.

Explanation:

(a) The minimum force F he must exert to get the block moving is 38.9 N.

(b) The acceleration of the block is 0.79 m/s².

The minimum force F he must exert to get the block moving is calculated as follows;

Fcosθ = μ(s)Fₙ

Fcosθ = μ(s)mg

where;

F = [0.1(36)(9.8)] / [(cos(25)]

F = 38.9 N

F(net) = 38.9 - (0.03 x 36 x 9.8) = 28.32

a = F(net)/m

a = 28.32/36

a = 0.79 m/s²

Thus, the minimum force F he must exert to get the block moving is 38.9 N.

The acceleration of the block is 0.79 m/s².

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The reason why photons take about 170,000 years to reach the surface of the Sun while neutrinos take only approximately three minutes for the same trip lies in the interaction of these particles with matter.

Photons are electromagnetic radiation and they interact strongly with the charged particles present in the dense plasma of the Sun's core. These interactions cause frequent scattering and absorption, resulting in a random walk-like path for the photons. As a result, they experience numerous collisions and absorptions, which significantly slows down their journey to the Sun's surface. The process is often referred to as "radiative diffusion."

On the other hand, neutrinos are electrically neutral particles that interact only very weakly with matter. This weak interaction allows neutrinos to pass through the dense plasma of the Sun's core almost unimpeded. Neutrinos can traverse matter, including the Sun, without being significantly absorbed or scattered, making their journey from the core to the surface much faster than photons.

The differing interaction strengths of photons and neutrinos with matter explain why photons take much longer to reach the Sun's surface compared to neutrinos. This phenomenon highlights the unique properties and behavior of these fundamental particles in the realm of astrophysics and particle physics.

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Answer:

0.0109 m ≈ 10.9 mm

Explanation:

proton speed = 1 * 10^6 m/s

radius in which the proton moves = 20 m

determine the radius of the circle in which an electron would move

we will apply the formula for calculating the centripetal force for both proton and electron ( Lorentz force formula)

For proton :

Mp*V^2 / rp  = qp *VB   ∴  rp = Mp*V / qP*B    ---------- ( 1 )

For electron:

re = Me*V/ qE * B -------- ( 2 )

Next: take the ratio of equations 1 and 2

re / rp = Me / Mp                                 ( note: qE = qP = 1.6 * 10^-19 C )

∴ re ( radius of the electron orbit )

= ( Me / Mp ) rp

= ( 9.1 * 10^-31 / 1.67 * 10^-27 ) 20

= ( 5.45 * 10^-4 ) * 20

= 0.0109 m ≈ 10.9 mm

The distance covered by the particle in 10 seconds, given that the particle starts from rest is 25 m

First, we shall list out the given parameters from the question. This is shown below:

We shall use equation of motion to obtain the distance covered in 10 seconds. This is shown below:

s = ut + ½at²

s = (0 × 10) + (½ × 0.5 × 10²)

s = 0 + (½ × 0.5 × 100)

s = 0 + 25

s = 25 m

Thus, we can conclude that the distance covered by the particle in 10 seconds is 25 m

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The value of the second charge is 1.2 nC.

The work done in moving the charge from infinity to the given position is calculated as follows;

W = Eq₂

E = W/q₂

The magnitude of the second charge is determined by applying Coulomb's law.

\(E = \frac{kq_2}{r^2} \\\\\frac{kq_2}{r^2} = \frac{W}{q_2} \\\\kq_2^2 = Wr^2\\\\q_2^2 = \frac{Wr^2}{k} \\\\q_2 = \sqrt{\frac{Wr^2}{k} } \\\\q_2 = \sqrt{\frac{(8.1 \times 10^{-6}) \times (0.04)^2}{9\times 10^9} } \\\\q_2 = 1.2 \times 10^{-9} \ C\\\\q_2 = 1.2 \ nC\)

Thus, the  value of the second charge is 1.2 nC.

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Explanation:

The first law of Newton's says that the velocity of an object will remain unless there is a force acting on the object, the second law of newton says that the force is proportional to the mass and the acceleration, and the third law of newton says that there is always an equal an opposite forces acting on two objects that interact.

So, the normal force can be described as a result of the third law of Newton. It means that it is equal in magnitude to the weight of the cart.

Therefore, the answer is:

C. Yes, the student is correct because the normal force is the equal and opposite reaction to the cart's weight being applied on a surface, as described in Newton's Third Law of Motion.

Answer:

Explanation:

Here,

P=Pressure

V=Volume

Subscript meanings: 1 is before, 2 is after. So P1 is starting pressure, P2 is ending pressure.

In the P1V1 = P2V2 equation, P and V are inversely proportional.

It means that when a quantity will increase then another will decrease.

The pressure of a gas is directly proportional to the. The temperature when volume and amount of substance are constant. P1/T1 = P2/T2. Combined gas law: P1V1/T1 = P2V2/T2 Use the gas laws for pressure, volume, and temperature calculations. Avagadro's law and the Ideal gas law.

The terminal velocity of the sphere is approximately 22.68 mph.

The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:

Fd = (1/2) * rho * Cd * A * v²

where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.

The gravitational force pulling the sphere down is given by:

Fg = m * g

where m is the mass of the sphere and g is the acceleration due to gravity.

At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:

Fd = Fg

Substituting the expressions for Fd and Fg and solving for v, we get:

v = √((2 * m * g) / (rho * Cd * A))

where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.

Plugging in the given values, we get:

v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s

To convert this to mph, we multiply by 2.23694:

v ≈ 22.68 mph

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Two objects are held close together. When they are released, they move toward one another. The conclusion is supported by this evidence is  the objects have opposite charges.

An electric charge is a physical property that causes matter to experience a force when in close proximity to other electrically charged matter. There are two types of electric charges: positive and negative. Protons, which are positively charged, and electrons, which are negatively charged, are subatomic particles that make up matter.

In general, the protons and neutrons in the nucleus of an atom have a net positive charge, while electrons, which orbit the nucleus, have a net negative charge. The charges of these subatomic particles are indicated by the symbols "p" for proton, "n" for neutron, and "e" for electron.

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Warm air from outside is pushed into the house to replace the cold air is the right answer.

A heat pump extracts heat from the cold air that is present outside the house and then transfers this warm air inside in our home. There is a compressor inside the device that uses electricity which increase the temperature of the heat that is extracted from the outside air. The heat pump can also provide cooling air by transferring warm indoor air to the outside.

So we can conclude that Warm air from outside is pushed into the house to replace the cold air is the right answer.

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To resolve the star-planet system at a distance of 4 light-years, a telescope on Earth would need an aperture with a minimum diameter of 55.88 mm.

In optical microscopy, the Rayleigh criterion is frequently used to estimate the resolution of the microscope. The resolution limit imposed by this criterion has long been regarded as a roadblock to using an optical microscope to study biological phenomena at the nanoscale.

We can use the Rayleigh criterion,

θ = 1.22 λ / D

θ = angular resolution

λ = wavelength of light

D = diameter of the telescope's aperture

θ = arctan (r / d)

r = radius of the planet's orbit

d = distance to the star

Now, we use the given values,

r = 149.6×106 km = 149.6×109 m

d = 4 × 9.461×1015 m = 3.7844×1016 m

λ = 550 nm = 550×10-9 m

θ = arctan (r / d)

   =arctan (149.6×109 / 3.7844×1016) = 0.000012 radians

we can use the Rayleigh criterion,

θ = 1.22 λ / D

D = 1.22 λ / θ

D = 1.22 × 550×10-9 / 0.000012

D = 55.88 mm

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Answer:

The decrease in decibels is 0.1 dB.

Explanation:

Let the intensity of one chorus is Io.

let the intensity of 1000 vocalist is dB.

The intensity of 1000 vocalist is 1000 Io.

\(dB = 10log\frac{1000Io}{Io}=30\)..... (1)

let the intensity of 999 vocalist is dB'.

\(dB' = 10log\frac{999Io}{Io}=29.9\)..... (2)

So, the change is

= dB - dB' = 30 - 29.9 = 0.1 dB

The resultant velocity of the boat is 7.5 km/h.

The resultant displacement of the boat is calculated as follows;

Sum of the vertical displacement of the boat is calculated as;

∑Fy = -24 km sin(50)  + 8 km sin(60)

∑Fy = -11.5 km

Sum of the horizontal displacement of the boat is calculated as;

∑Fx = -24 km cos(50)  - 8 km cos(60)

∑Fx = -19.4 km

The resultant displacement is calculated as follows;

d = √ (-11.5² + 19.4²)

d = 22.55 km

The resultant velocity of the boat is calculated as follows;

v = ( 22.55 km ) / ( 3 hrs )

v = 7.5 km/h

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Imagine you have three flashlights. One has a blue light, one has a green light and one is red. If you were to shine each of those lights in the same spot, I think i would see white color.

At one end of the electromagnetic wave line, which has the group of the visible spectrum. This has been referred to as the visible light of the spectrum. The visible light with the shortest of the wavelength has the blue light and the one with the longest has the red light.

The primary colors of the light has been the spectrum are red, blue, and green. The combination of these colors will form other as well as the colors which has been referred to as the secondary colors. The combination of the beam of the red light and the beam of green light will form yellow color.

Therefore, Imagine you have three flashlights. One has a blue light, one has a green light and one is red. If you were to shine each of those lights in the same spot, I think i would see white color.

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Answer:

The correct answer is:

(a) 27.5 Joules

(b) 141.5 Joules

Explanation:

Given:

Energy,

\(Q_c = 110 \ J\)

Coefficient of performance refrigerator,

\(Cop(refrig)=4\)

(a)

As we know,

⇒ \(Cop(refrig) = \frac{Q_c}{Work}\)

or,

⇒ \(Work=\frac{Q_c}{Cop(refrig)}\)

              \(=\frac{110}{4}\)

              \(=27.5 \ Joules\)

(b)

⇒ \(Heat \ expelled = Heat \ removed +Work \ done\)

or,

⇒ \(Q_h = Q_c+Work\)

         \(=114+27.5\)

         \(=141.5 \ Joules\)

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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Answer:

640.5

Explanation: i got it right on acellus

The wavelength of the light is 320.23 nm.

Light passing through a double slit with separation is given as

d = 3.33 × 10⁻⁵ m.

Line number m = 1

Angle θ = 0.551°

   The distance between two sound waves i.e., crest and trough is called the wavelength.

Human eye can detect the wavelength of about 380 nm to 700 nm.

To find the wavelength, here we use the formula as,

             sin θ = Line number × λ ÷ ( distance )

By substituting all the values,

            Sin ( 0.551 ) = 1 × λ ÷ ( 3.33 × 10⁻⁵)

Rearranging the equation,

             λ= (Sin ( 0.551 ) ×  ( 3.33 × 10⁻⁵) ) ÷ (1)

              λ = 320.23  nm.

Thus, wavelength λ of the light is 320.23 nm.

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Answer:

         v₃ = - (3 i ^ + 4 j ^) m / s

v₃ = 5 m / s,  θ = 233º

Explanation:

This is a momentum problem. Let us form a system formed by the three objects so that the forces during the collisions have been internal and the moment is conserved.

Let's start working with the first two objects.  As each object moves in a different direction let's work with the components in an xy coordinate system

X axis

initial instant. Before the shock

       p₀ₓ = m₁ v₁₀ + 0

final instant. After the crash

      p_{fx} = (m1 + m2) vₓ

the moment is preserved

       p₀ₓ = p_{fx}

       m₁ v₀₁ = (m₁ + m₂) vₓ

       vₓ = \(\frac{m_1}{m_1+m_2} \ v_{o1}\)

Y axis  

initial instant

       p_{oy} = 0 + m₂ v₀₂

final moment

       p_{fy} = (m₁ + m₂) v_y

the moment is preserved

      p_{oy} = p_{fy}

      m₂ v₀₂ = (m₁ + m₂) v_y

      v_y = \(\frac{m_2}{m_1 +m_2 } \ v_{o2}\)

We already have the speed of the set of these two cars, now let's work on this set and vehicle 3

X axis    

initial instant

      p₀ₓ = (m₁ + m₂) vₓ + m₃ v₃ₓ

final instant

      p_{fx} = 0

      p₀ₓ = p_{fx}

      (m₁ + m₂) vₓ + m₃ v₃ₓ = 0

       v₃ₓ = \(- \frac{m_1+m_2 }{m_3} \ v_x\)

Y Axis

initial instant

        p_{oy} = (m₁ + m₂) v_y + m₃ v_{3y}

final moment

        p_{fy} = 0

        p_{oy} = p_{fy}

        (m₁ + m₂) v_y + m₃ v_{3y} = 0

        v_{3y} = \(- \frac{m_1+m_2}{m_3} \ v_y\)

now we substitute the values ​​of the speeds

       v₃ₓ = \(- \frac{m_1+m_2}{m_3} \ \frac{m_1}{m_1+m_2} \ v_{o1}\)  

       v₃ₓ = \(- \frac{m_1}{m_3} \ v_{o1}\)

       v_{3y} = \(- \frac{m_1+m_2}{m_3} \ \frac{m_2}{m_1+m_2} \ v_{o2}\)

       v_{3y} = \(- \frac{m_2}{m_3} \ v_{o2}\)

let's calculate

         v₃ₓ = - ⅓ 9

         v₃ₓ = - 3 m / s

         v_{3y} = - ⅔ 6

         v_{3y} = - 4 m / s

therefore the speed of vehicle 3 is

         v₃ = - (3 i ^ + 4 j ^) m / s

It can also be given in the form of modulus and angles using the Pythagorean theorem

         v₃ = \(\sqrt{v_{3x}^2 + v_{3y}^2}\)

          v₃ = \(\sqrt{3^2+4^2}\)

          v₃ = 5 m / s

let's use trigonometry for the angle

          tan θ' = \(\frac{v_{3y}}{v_{3x}}\)

          θ' = tan⁻¹ (\frac{v_{3y}}{v_{3x}})

          θ' = tan⁻¹ (4/3)

          θ'  = 53º

That the two speeds are negative so this angle is in the third quadrant, measured from the positive side of the x axis

          θ = 180 + θ'

          θ = 180 +53

          θ = 233º

The three missing categories of expenditure that contribute to a country's GDP are

Government spending This includes all expenditures made by the government on goods and services, such as salaries of government employees, public infrastructure, defense spending, and social welfare programs. Government spending is represented by the letter "G" in the formula for GDP GDP = C + I + G + (X-M).

Exports This refers to the value of all goods and services that a country produces and sells to other countries. Exports are represented by the letter "X" in the formula for GDP GDP = C + I + G + (X-M).

Imports This refers to the value of all goods and services that a country purchases from other countries. Imports are subtracted from the formula for GDP since they represent a leakage from the economy. Imports are represented by the letter "M" in the formula for GDP  GDP = C + I + G + (X-M).

Here is a brief description of the categories of expenditure that have already been filled in

Personal consumption expenditures (C) This category includes all spending by households on goods and services, such as food, housing, healthcare, and education.

Gross private domestic investment (I)  This category includes all investment spending by businesses, such as purchases of machinery, equipment, and structures, as well as changes in inventories.

GDP formula The formula for GDP is the sum of all final goods and services produced within a country's borders in a given time period. It can be expressed as  GDP = C + I + G + (X-M).

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The energy required to raise the temperature of the air in a room by 5.0°C is 428.4 kJ

U = \(c_{p}\) m ΔT

U = Energy

\(c_{p}\) = Specific heat

m = Mass

ΔT = Change in temperature

ρ = Density

V = Volume

ρ\(_{air}\) = 1275 g / m³ (Dry air )

\(c_{p}\) = 1 J / g K

ΔT = 5 °C

V = 4 * 4 * 3

V = 48 m³

m = ρ V

m = 1275 * 48

m = 61200 g

U = 1 * 61200 * 7

U = 428400 J

U = 428.4 kJ

Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 428.4 kJ

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Answer:

Δt ≈ 5.3 x 10⁻⁷ s  or  Δt ≈ 0.5 μs.

Explanation:

Sound waves propagate at a typical speed according to the physical media.

Using the wave equation of speed:

V = λ x f

V = 0.0760 x 25 x 10³

V = 1900 m/s

Then we must use this value to find the time recorded:

V = ΔS / Δt

1900 = 10⁻³ / Δt

Δt = 10⁻³ / 1900

Δt ≈ 5.2632 x 10⁻⁷ s

Δt ≈ 5.3 x 10⁻⁷ s  or  Δt ≈ 0.5 μs

The wavelength of the Ultrasonic wave in the coating is 0.0760 m, then the time recorded is 0.5 μs if the coating is of correct thickness, that is of 1 mm

Physics refers to frequency as the quantity of waves passing a fixed location in a unit of time. Additionally, it is the quantity of vibrations or cycles that a body in periodic motion experiences in a certain period of time. One cycle or vibration is defined as the movement of a body in periodic motion across a sequence of occasions or locations before returning to its initial state. Under angular velocity, a straightforward harmonic motion is also observed.

According to the question,

Use wave equation of speed :

V = λ (wavelength) x f (frequency)

V = 0.0760 x 25 x 10³

V = 1900 m/s

The time recorded will be :

V = ΔS / Δt

1900 = 10⁻³ / Δt

Δt = 10⁻³ / 1900

Δt = 5.2632 x 10⁻⁷ s

Δt = 5.3 x 10⁻⁷ s  or,

Δt = 0.5 μs

Hence, the time recorded will be 0.5 μs if the coating is of correct thickness that is 1 mm.

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5.73 seconds pass before the centripetal acceleration equals the tangential acceleration in strength.

This enables you to calculate the change in velocity in metres per second squared (m/s²). The change in velocity (v) over the change in time (t) is known as acceleration (a). It can be determined using the formula a = v/t.

a = v²/r

where a is the centripetal acceleration, v is the speed of the car, and r is the radius of the circular track (half the diameter).

a = (2.97 m/s²)

r = (195 m)/2 = 97.5 m

v² = ar = (2.97 m/s²)(97.5 m) = 289.58 m²/s²

v = √(289.58 m²/s²) = 17.01 m/s

at = dv/dt

where at is the tangential acceleration, and v is the speed of the car. Since the car is starting from rest, its initial speed is zero, so we can simplify the formula to:

at = v/t

where t is the elapsed time.

We want to find the time at which the magnitude of the tangential acceleration is equal to the magnitude of the centripetal acceleration, so:

at = ac

v/t = ac

t = v/ac = 17.01 m/s / 2.97 m/s² = 5.73 s

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Based on the flow of energy that's in the lake, it can be deduced that the diatoms and algae will have the highest concentration.

Energy flow refers to the flow of energy through living organisms that are within an ecosystem. Energy is passed from one trophic level to the next trophic level.

If the farmer sprays a field with chemical fertilizer, the organism that would contain the highest concentration of the chemical fertilizer are diatoms and algae since they're at the bottom of the ecosystem.

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Answer:

A and B.

Explanation:

Answer C is wrong - there are no tall trees underwater

Answer D is wrong, there are mountain chains underwater due to plate tectonics.

Answer:

-15 as it inverse to gravity

the direction of big force

The average speed of the cyclist over the time interval is 6m/s.

Average speed in physics is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity. It is represented by the magnitude and does not have direction.

The formula to calculate average speed is as follows;

S = ∆V/t

where

According to this question, a cyclist increases his speed from 10 m/s to 20 m/s in 5s. The average speed is calculated as follows:

S = (20 - 10)/5

S = 30/5

S = 6m/s

Therefore, 6m/s is the average speed.

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