A bond angle is the angle formed by the nuclei of _____ surrounding atoms with the nucleus of a central atom.

Answer:

Relative atomic mass = 35.5

Explanation:

Given data:

Abundance of Cl -35 = 75%

Abundance of Cl -25 = 25%

Average atomic mass = ?

Solution:  

Relative atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Relative atomic mass = (75×35)+(25×37) /100

Relative atomic mass =  2625 + 925 / 100

Relative atomic mass = 3550 / 100

Relative atomic mass = 35.5

Therefore, the bubble will occupy a volume of 0.223 mL near the surface of the lake.

To solve this problem, we can use the combined gas law:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

where P1, V1, and T1 are the initial pressure, volume, and temperature of the bubble, and P2, V2, and T2 are the final pressure, volume, and temperature of the bubble.

Substituting the given values:

P1 = 12.31 atm

V1 = 0.0750 mL = 0.0000750 L

T1 = 12°C + 273.15 = 285.15 K

P2 = 1.17 atm

T2 = 38°C + 273.15 = 311.15 K

(P1 * V1) / (T1) = (P2 * V2) / (T2)

(12.31 atm * 0.0000750 L) / (285.15 K) = (1.17 atm * V2) / (311.15 K)

Solving for V2:

V2 = (12.31 atm * 0.0000750 L * 311.15 K) / (1.17 atm * 285.15 K)

V2 = 0.000223 L

= 0.223 mL (rounded to three significant figures)

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The expected ground-state electron configuration for the element with one unpaired 5p electron that forms a covalent compound with fluorine is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^2.

To determine the expected ground-state electron configuration, we need to consider the element with one unpaired 5p electron that forms a covalent compound with fluorine.

Since we are looking for an element with one unpaired 5p electron, we can refer to the periodic table.

The element in question is in the p-block of the periodic table, and its electron configuration can be written as:

1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^1

To determine the expected ground-state electron configuration, we need to understand that elements tend to achieve a stable configuration by filling their valence shell. In this case, the valence shell is the 5p orbital.

To form a covalent compound with fluorine, the element must gain one electron from fluorine.

This electron would occupy one of the unpaired 5p orbitals, resulting in the following electron configuration:

1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^2

Therefore, the expected ground-state electron configuration for the element with one unpaired 5p electron that forms a covalent compound with fluorine is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^2.

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To produce one molecule of glucose, 6 molecules of carbon dioxide (\(CO_{2}\)), 18 molecules of adenosine triphosphate (ATP), and 12 molecules of nicotinamide adenine dinucleotide phosphate (NADPH) are required.

Glucose, a six-carbon sugar, is synthesized through the process of photosynthesis in plants. It involves the Calvin cycle, which incorporates carbon dioxide, ATP, and NADPH to produce glucose. For each molecule of glucose formed, 6 molecules of carbon dioxide are required.

The energy needed for glucose synthesis is provided by ATP, which is an energy-rich molecule. In the Calvin cycle, the synthesis of one glucose molecule requires 18 molecules of ATP.

NADPH, a coenzyme involved in energy transfer reactions, is required for the reduction of carbon dioxide during the Calvin cycle. In the process, 12 molecules of NADPH are utilized to produce one molecule of glucose. These components play crucial roles in capturing and storing energy, as well as providing carbon atoms for the formation of glucose, which serves as a vital energy source for organisms.

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Answer:

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

\(P_1V_1 = P_2V_2\)

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the new pressure

\(P_2 = \frac{P_1V_1}{V_2} \\\)

We have

\(P_2 = \frac{350 \times 0.85}{450} = \frac{297.5}{450} \\ = 0.661111...\)

We have the final answer as

Hope this helps you

The greater the electronegativity difference between two bonded atoms, the greater the ionic character of the bond. Option B.

The electronegativity difference between two bonded atoms determines the bond polarity. It is calculated by subtracting the electronegativity of the less electronegative atom from that of the more electronegative atom. Bond polarity can range from nonpolar covalent to polar covalent to ionic.

The greater the electronegativity difference between two bonded atoms, the greater the ionic character of the bond. If the electronegativity difference between the bonded atoms is greater than 1.7, the bond is ionic. The bond is polar covalent if the electronegativity difference is between 0.4 and 1.7, and it is nonpolar covalent if the electronegativity difference is less than 0.4.

Bonding character is determined by the electronegativity difference between two bonded atoms. The more electronegative an element is, the more it pulls electrons toward itself. As a result, electronegative atoms acquire a partial negative charge, whereas less electronegative atoms acquire a partial positive charge.

As a result, the bond between them is polarized. The bond is classified as covalent if it is polarized and the bond is classified as ionic if the electronegativity difference between the atoms is quite significant.

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Volumetric pipetts, volumetric flasks and burette are the most accurate, the glassware makers calibrate these to a high level of accurасу.

However, if we need exactly 25.0 ml to make up a 'standard' solution, only a volumetric flask would be appropriate

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Hydration is a specific example of the phenomenon known generally as a. solvation

The act of hydrating involves combining or dissolving an object in water. It is a particular instance of the more general phenomena known as solvation, which is the process by which solvent molecules surround and scatter a solute to create a homogeneous solution. However, hydration explicitly refers to solvation with water as the solvent.

Solvation may also happen with solvents other than water. Solvation is the process through which a solute and solvent interact to stabilise a solute species. Due to its impact on the solubility, reactivity, and behaviour of compounds in solution, solvation is a crucial mechanism in many chemical and biological processes.

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Answer:

Maria

Explanation:

Answer:

Maria loves Jarren more is the answer.

Answer:

a.)cations; free to move around

b.)cations; fixed in place

Answer:

5w2

Explanation:

Answer:

397,570 g/m^3

Explanation:

The volume of the cylinder can be calculated using its height and diameter.

Mass of the soil sample (m) = 30 g

Height of the cylinder (h) = 6 cm

Diameter of the cylinder (d) = 4 cm

First, we need to calculate the radius (r) of the cylinder

Radius (r) = diameter / 2 = 4 cm / 2 = 2 cm = 0.02 m

Now, we can calculate the volume (V) of the cylinder

V = π * r^2 * h

V = 3.14159 * (0.02 m)^2 * 0.06 m

V = 7.5398 E-5 m^3

Calculate the bulk density (ρ) using this formula

ρ = m / V

ρ = 30 g / 7.5398 E-5 m^3

ρ = 397,887 g/m^3

Answer:

The formula shows that there is one atoms of iron in each formula unit of FeCl3, and by definition the number of molecules or formula units in a mole is Avogadro's Number. Therefore, 5.33 moles contains 5.33 X Avogadro's Number of atoms, which is 3.21 X 1024 atoms, to the justified number of significant digits.

Answer:

The formula shows that there is one atoms of iron in each formula unit of FeCl3 , and by definition the number of molecules or formula units in a mole is Avogadro's Number . Therefore , 5.33 moles contains 5.33 X Avogadro's Number of atoms , which is 3.21 X 1024 atoms , to the justified number of significant digits .

The value of x in the x% nickel alloy is 15%.

To find the worth of x, we can set up a situation in light of how much nickel in the amalgams:

(0.35 * 2) + (x * 6) = 0.20 * (2 + 6)

To start with, we ascertain how much nickel contributed by the 35% nickel combination, which is 0.35 * 2 grams = 0.7 grams. The x% nickel compound contributes x grams of nickel when joined with 6 grams.

The aggregate sum of nickel in the subsequent 20% nickel compound is 0.20 * (2 + 6) = 1.6 grams.

Presently we can address the condition:

0.7 + 6x = 1.6

Taking away 0.7 from the two sides:

6x = 1.6 - 0.7

6x = 0.9

Partitioning the two sides by 6:

x = 0.9/6

x = 0.15

Hence, the worth of x is 0.15, or 15%.

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Answer

A

Explanation

letter a kase tama

To use Faraday's constant, which is the charge of one mole of electrons. It is equal to 96,485 C/mol. We also need to use the molar mass of nickel, which is 58.69 g/mol.

First, we need to calculate the total charge that passed through the circuit, which is equal to the number of moles of electrons multiplied by Faraday's constant.
Total charge = 0.84 moles x 96,485 C/mol = 81,102 C
Next, we need to use the balanced equation for the electrolysis of Ni2+(aq) to Ni(s):
Ni2+(aq) + 2e- → Ni(s)
For every 2 moles of electrons, 1 mole of Ni(s) is plated out. Therefore, we can calculate the moles of Ni(s) plated out by dividing the total charge by the charge per 2 moles of electrons:
Moles of Ni(s) = 81,102 C / (2 x 96,485 C/mol) = 0.420 moles
Finally, we can calculate the mass of Ni(s) plated out by multiplying the moles by the molar mass:
Mass of Ni(s) = 0.420 moles x 58.69 g/mol = 24.6 g

Therefore, the answer is (a) 24.6 grams.

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Answer:

ionic compound

Explanation:

ionic bonding

In ionic bonding, electrons are completely transferred from one atom to another. In ionic bonding, electrons are completely transferred from one atom to another. In the process of either losing or gaining negatively charged electrons, the reacting atoms form ions.

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Option C provides the right response. Reaction (10) Needs to be halved.

We must confirm that the amount of oxygen in both reactions is the same in order to solve for reaction (7). There is 12 O2(g) in reaction (10), and there is also 12 O2 in reaction (7). (g). Thus, we do not have to change the amount of oxygen used in the reaction (10).

Yet, one molecule of h2(g) is present in reaction (10) while one atom of mg is present in reaction 7. (s). We must cut the reaction in half to equalize the reactant amounts in both reactions (10). This will produce equal amounts of 12 h2(g) and 14 O2(g), matching the number of reactants in the reaction (7).

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The complete question is

for reaction (10) given as: h2(g) ½ o2(g) → h2o(l) select how reaction (10) should be manipulated in order to solve for reaction (7): mg(s) ½ o2(g) → mgo(s)

a. Reaction (10) needs to be doubles

b. Reaction (10) should remain as written

c. Reaction (10) Needs to be halved

d. Reaction (10) Needs to be reversed

The percent of chloride ion in a sample if 2. 500 g of the sample produces 1. 750 g of agcl when treated with excess ag⁺ is 17.2 percent.

What is mass percent?

The ratio of the mass of the solute contained in a solution to the mass of the solution as a whole is known as the mass percent.

Explanation:

Given:

Mass of sample = 2. 500 g

Mass of AgCl = 1. 750 g

The percent of chloride ion in a sample is calculated as,

Molar mass of AgCl = 143.32 g/mol

\(Molar mass of Chlorine atom = 35.45 g/mol\)

Assume that all of the sample's chlorine has precipitated into silver chloride. As a result, the amount of chlorine in silver chloride will match the amount of chlorine in the sample.

First we have to find mass of chlorine,

\(In 143.32 g of silver chloride, mass of chlorine present is 35.45 gSo, in 1.3487 g of silver chloride, mass of chlorine present will be =35.45g/143.32 g * 1.750 g = 0.43 g\)

Therefore, the percent of chloride ion in a sample is

\(Mass of pure chloride compound = 2.500 gMass of chlorine = 0.43 g%Chlorine = 0.43/2.5 *100%Chlorine = 17.2 %\)

Hence, the percent of chloride ion in a sample is \(17.2%\) percent.

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Answer:

Healthcare system is one of the most important in any country’s economy.

Health care system Inputs include Medication, patients, locations

Outputs: Treating injured or sick people, taking care of people's health

Side effects: Lack of medication/drugs or no right medication, wrong diagnosis or prescription.

Explanation:

We have a 63.9 g sample of calcium hydroxide. First we have to convert those grams into moles. To do that we have to use the molar mass of calcium hydroxide.

Calcium hydroxide = Ca(OH)₂

molar mass of Ca = 40.08 g/mol

molar mass of O = 16.00 g/mol

molar mass of H = 1.01 g/mol

molar mass of Ca(OH)₂ = 1 * 40.08 g/mol + 2 * 16.00 g/mol + 2 * 1.01 g/mol

molar mass of Ca(OH)₂ = 74.10 g/mol

mass of Ca(OH)₂ = 63.9 g

moles of Ca(OH)₂ = 63.9 g /(74.10 g/mol)

moles of Ca(OH)₂ = 0.862 moles

In 1 molecule of Ca we have 2 atoms of O. So in 1 mol of Ca(OH)₂ we will have 2 moles of O atoms.

1 mol of Ca(OH)₂ = 2 moles of O atoms

moles of O atoms = 0.862 moles of Ca(OH)₂ * 2 moles of O /1 mol of Ca(OH)₂

moles of O atoms = 1.724 moles

One mol is similar to a dozen. When we say that we need a dozen eggs we know that we need 12 eggs. If we want a mol of eggs, we want 6.022*10^23 eggs. So one mol of something is 6.022 * 10^23 of that.

1 mol of O atoms = 6.022 * 10^23 atoms

n° of O atoms = 1.724 moles * 6.022 * 10^23 atoms/1 mol

n° of O atoms = 1.04 * 10^24 atoms

Answer: In a 63.9 g sample of Ca(OH)₂ we have 1.04 *10^24 atoms of oxygen.

N-Pentane has a higher boiling point than the other three elements

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n-Pentane and 2,2-Dimethylpropane are isomers of one another and have the same chemical formula. Only London dispersion forces (LDFs), the smallest intermolecular forces, exist between the two molecules. The connectedness of the carbon skeleton accounts for the variation in their boiling points. While 2,2-dimethylpropane is a branching hydrocarbon, n-pentane is a straight hydrocarbon. Because of the n-linear pentane's shape, which results in greater surface areas between molecules, there are more LDFs between the molecules. N-Pentane has a higher boiling point as a result.

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Complete Question

Rank the following compounds in terms by increasing boiling point, starting with the lowest boiling point first. I. 1-pentanol II. n-pentane III. 2,2-dimethylpropane IV. (R)-4-hydroxypentanoic acid.

0.0014 atm is the pressure of nitrogen at 20 °C and 730 mm Hg initial pressure when its volume increases from 875 ml to 955 ml

Since the mass of the gas is maintained during the change in volume, the number of moles with the initial volume must first be calculated.

To calculate the moles of gas, the ideal gas equation is used:

PV = nrt

where

P = Pressure

V=Volume

n = moles

T = temperature

R = gas constant

It is cleared n:

n = PV/Rt

n = PV/Rt

Data

P = 730 mmHg = 0.96 atm

V = 875ml = 0.875L

n = ?

T = 20°C = 293.15K

R = 0.082 L atm/mol °K

n = PV/Rt

n = 0.96. 0.875 / 0.082. 293.15

n = 0.84 / 24.03

n = 0.035 moles

Knowing the moles of nitrogen, the new pressure of the gas is calculated after changing its volume.

Data

P = ?

V = 955ml = 0.955L

n = 0.035 moles

T = 20°C = 293.15K

R = 0.082 L atm/mol °K

P = nRt/V

P = 0.035. 0.955 / 0.082. 293.15

P = 0.033 / 24.03

P = 0.0014 atm

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If the hydrogen gas is combusted and produces 645L of water vapor at 400 kelvin and 1.75 atm, 2796.96 g mass of the zinc is produced .

Using the ideal gas law equation:

PV = nRT

n = (PV) / (RT)

= (1.75 atm * 645 L) / (0.0821 atm·L/(mol·K) * 400 K)

= 42.71 moles

the balanced equation for the reaction between zinc and hydrochloric acid:

Zn + 2HCl -> \(ZnCl_{2}\)  + \(H_{2}\)

1 mole of zinc produces 1 mole of hydrogen gas. Therefore, the moles of zinc are also 42.71.

The molar mass of zinc is 65.38 g/mol.

Mass of zinc = moles of zinc * molar mass of zinc

= 42.71 moles * 65.38 g/mol

= 2796.96 g

Therefore, the mass of the zinc is 2796.96 grams.

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Answer:

P2=0.385atm

Explanation:

The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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This process favor products at high temperature because  ∆G is positive (∆G > 0), it indicates that the reaction is non-spontaneous and favors the formation of products at high temperature.

In the context of a non-spontaneous reaction, the process would favor products at a high temperature. Non-spontaneous reactions require an input of energy to proceed, and increasing the temperature can provide the necessary energy to drive the reaction in the forward direction.

By supplying heat and raising the temperature, the system can overcome the energy barrier and favor the formation of products.

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The helium pressure is 799 torr.

As 1 mm Hg is equal to 1 torr. In an open-ended mercury manometer, the pressure will be equal to the atmospheric pressure.

Also, the pressure of the mercury level in the open arm is 47 mm above that in the arm connected to the flask of helium. Add both the given numbers,

(752 + 47) mm Hg = 799 torr

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Answer:

A mid-ocean ridge is a seafloor mountain system formed by plate tectonics. It typically has a depth of ~ 2,600 meters and rises about two kilometers above the deepest portion of an ocean basin. This feature is where seafloor spreading takes place along a divergent plate boundary.

Answer:

A mid-ocean ridge is a seafloor mountain system formed by plate tectonics. It typically has a depth of ~ 2,600 meters and rises about two kilometers above the deepest portion of an ocean basin. This feature is where seafloor spreading takes place along a divergent plate boundary.

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You would need to add 250 mL of water.