A body with a mass of 3kg is rotating around its axis at a
constant speed, and completes
one round in 20s what's its angular speed in rad/s?
explain with clear handwriting please

Answers

Answer 1

The angular speed of the body rotating around its axis is π/10 rad/s.

Angular speed is defined as the rate at which an object rotates or moves around a fixed point. It is measured in radians per second (rad/s). In this case, the body completes one round in 20 seconds, which means it travels a full circle.

To calculate the angular speed, we need to determine the angle covered by the body in one second. Since the body completes one round in 20 seconds, it covers an angle of 2π radians in 20 seconds.

So, the angular speed is given by:

Angular speed = Angle covered / Time taken

Angular speed = 2π radians / 20 seconds

Simplifying this expression, we get:

Angular speed = π/10 rad/s

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Related Questions

suppose that the internal energy of a system has been increased, resulting in an increase in the temperature of the system. which of the following is the cause of this change?

Answers

No, according to the first law, whether a certain amount of energy is added by doing work on the system or by adding heat, the internal energy will change in the same way.

A thermodynamic system's total internal energy is defined as the energy it possesses. It consists of both internal kinetic energy and potential energy contributions, and it is the energy required to develop or prepare the system in its current internal condition. The system's energy gains and losses resulting from modifications to its internal state are tracked by this mechanism. It excludes all external energies from surrounding force fields as well as the kinetic energy of the system's overall motion. The first law of thermodynamics, which is based on the idea that an isolated system's internal energy is constant, is stated as the law of conservation of energy. An vast quality is the internal energy.

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A piece of debris breaks off the stone facing of a high building 99.4 m above the sidewalk. Fortunately the sidewalk is deserted, because the debris strikes the ground at very high speed. Calculate this speed.

Answers

The speed at the debris strikes the ground is 44.1399 m/s.

Given  information,

Height, s = 99.4 m

The speed is defined as the rate of change of distance in any direction. Speed is a scalar quantity.

speed = Distance/time

Using the third equation of motion, we can find the speed of debris.

From the relation between velocity, acceleration, and distance, we get

(velocity)² = 2×acceleration×distance

Substituting the values,

v² = 2×a×s

v² = 2× 9.8×99.4

v² = 1948.24

Taking the square root of the value,

v = 44.1399 m/s

Hence, The speed at the debris strikes the ground is 44.1399 m/s.

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two wire lie perpendicular to the plane of the paper, and equal electric currents pass through the paper in the directions shown. Point p is equidistance from the two wires.

Answers

The direction of the magnetic field produced at point P will be perpendicular to the plane of the paper, as shown in the figure. The magnetic field will be pointing into the paper. We can also determine the magnitude of the magnetic field produced at point P by using the right-hand rule. The magnitude of the magnetic field will depend on the distance of point P from the two wires and the magnitude of the electric currents in the wires.

Two wires lying perpendicular to the plane of the paper and equal electric currents pass through the paper in the directions shown. Point p is equidistant from the two wires. The problem requires us to determine the direction of the magnetic field produced at point P. We will use the right-hand rule to determine the direction of the magnetic field produced at point P.
To use the right-hand rule, we take our right hand and point our fingers in the direction of the current in wire

1. Then, we curl our fingers toward the direction of the current in wire

2. Our thumb will then point in the direction of the magnetic field produced at point P.

We can also use the right-hand rule to determine the direction of the magnetic field produced at a given point in a current-carrying wire. We know that the two wires are carrying equal electric currents, so the magnitude of the magnetic fields produced at point P by each wire will be the same. The magnetic fields produced by the two wires will add together, resulting in a net magnetic field at point P. The magnetic fields produced by the two wires will be perpendicular to each other and also perpendicular to the plane of the paper.

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PLEASE HELPPP
Force: Adding vectors (find resultant force)
50N north plus 50N west Plus 50N north west

Answers

To find the resultant force of the vectors 50N north, 50N west, and 50N northwest, we can use vector addition.
One way to do this is to draw a diagram of the vectors and use the head-to-tail method to find the resultant vector. We can start by drawing the vector 50N north, then draw the vector 50N west starting from the end of the first vector, and finally draw the vector 50N northwest starting from the end of the second vector and ending at the tip of the resultant vector. The resultant vector is the vector that starts at the beginning of the first vector and ends at the tip of the last vector.
Alternatively, we can use trigonometry to find the magnitude and direction of the resultant vector. We can break down each vector into its x and y components, then add up the x components and the y components separately to get the x and y components of the resultant vector. The magnitude of the resultant vector is then given by the square root of the sum of the squares of the x and y components, and the direction is given by the arctangent of the y component divided by the x component.
Using either method, we can find that the magnitude of the resultant force is approximately 70.7N, and the direction is approximately 45 degrees north of west

a roller skater starts from rest (velocity initial=0m/s) and speeds up a final velocity (10m/s) what is the acceleration during a time of 2 seconds

Answers

Answer:

10-0÷2=5 that's the answer

Does a neutral object contain no electric charge at all?

Answers

Answer:

Bonjour à toi,

QUESTION)

An electrically neutral object does not mean that it has no electrical charge. If today we find some elementary particles without electric charge (Higgs Boson, photon and gluon), the neutrality of the atom and molecules, or more globally of matter is due to various processes. An atom is electrically neutral because the electric charges that compose it compensate each other (as much negative charge, the electron, as positive, the proton). Ionic molecules arrange themselves so that the electric charges that compose them compensate each other.

Does a neutral object contain no electric charge at all?

PART ONE
A merry-go-round rotates at the rate of 0.24 rev/s with an 71 kg man standing at a point 2.7 m from the axis of rotation.
What is the new angular speed when the
man walks to a point 1 m from the center?
Consider the merry-go-round is a solid 79 kg cylinder of radius of 2.7 m.
Answer in units of rad/s.

PART TWO
What is the change in kinetic energy due to this movement?
Answer in units of J.

Answers

Answer:

In order to answer this correctly I will need the answers to the question

Explanation:

I can then work it out and give you the best answer I can give you

using the scientific definition, which statement is always true of work? a) it is difficult. b) it involves levers. c) it involves a transfer of energy. d) it is done with a machine

Answers

It involves a transfer of energy is always true for work.

In physics,work is the energy transferred to or from an item through the application of pressure alongside a displacement. In its most effective form, for a consistent pressure aligned with the route of motion, it equals the manufactured from the force strength and the space traveled.

Work modifications the quantity of mechanical and internal energy possessed by gadgets. Whole work is achieved on a machine or item, energy is introduced to it.

The character of work achieved can be categorised in three classes. they are +ve work, -ve work and zero work. The character of work relies upon on the perspective among pressure and displacement.

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A pole 10 m long lies on the ground next to a barn that is 8 m long. AN athlete picks up the pole, carries it far away and then runs with it towards the barn at speed 0.8c. The athlete's friend remains at rest, standing by the open door of the barn.

Answers

Answer:

okay

Explanation:

but what is the question here?

A car is stopped at a stop light. When the light turns green, it travels south 55 m/s in 5s. What is its acceleration? *

Answers

Answer:

11m/s^2

Explanation:

Acceleration can be calculated by diving speed by time. Since we know speed and time, acceleration can be calculated.

55/5 = 11m/s^2

A 75.0 kg man pushes backward on a 300.0 kg boat with a force of 150.0N causing the boat to accelerate backward at 0.5m/s^2. What is the acceleration of the man?

A) 150.0 m/s^2
B) 8.00 m/s^2
C) 2.00 m/s^2
D) 4.00 m/s^2

Answers

Answer:

C) 2.00 m/s^2

Explanation:

F = m*a

150N = 75kg(a)

a = 150N/75kg

a = 2.0m/s²

A gas is enclosed in a container fitted with a piston of cross-sectional area 0.10 m2 . the pressure of the gas is maintained at 8000 nm-2 . when heat is slowly transferred, the piston is pushed up through a distance of 4 cm. if 42 j heat is transferred to the system during the expansion, what is the change in internal energy of the system?

Answers

The change in internal energy is 10 J.

Calculation:

Given,

Cross-sectional area, A = 0.10 m²

Pressure of gas, P = 8000 N/m²

Displacement, s = 4 cm = 0.04 m

Heat transferred, H = 42 J

To find,

Change in internal energy =?

We know that, as per Law of thermodynamics,

Change in internal energy = Heat - Work

Force = pressure × area

          = 8000 × 0.10

          = 800 N

Work = Force × Displacement

         = 800 × 0.04

         = 32 J

Change in internal energy = Heat - Work

                                            = 42 - 32

                                            = 10 J

Hence, the change in internal energy is 10 J.

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A table tennis ball is dropped onto the flour from a height
€ 4m and It rebounds to a height of 3m. If the time of
ontact with the floor is o.ols, what is the magnitude and
irection of the acceleration during the contact.

Answers

The acceleration of the ball during the contact is 1652  m/s^2 in upward direction.

What is acceleration?

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

The velocity of the ball before hitting the floor in downward direction:

u = √(2gs)

= √(2×9.8×4) m/s

= 8.85 m/s.

The velocity of the ball after hitting the floor in upward direction:

v  = √(2gs)

= √(2×9.8×3) m/s

= 7.67 m/s.

Hence, the acceleration of the ball during the contact in upward direction is: a = change in velocity/time duration

= (7.67 - (-8.85))/0.01 m/s^2

= 1652  m/s^2

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If 3.5 waves have a distance of 42M what is the wavelength of one wave?

Please please please tell me how you exactly found the answer!!

Answers

Answer:

The answer is 12

Explanation:

Just divide 42/3.5

Which statement describes the electrostatic force between two charged objects?
A It is greater when two objects are farther apart.
B It is greater if two objects have the same charge.
C It is greater when the charges of the objects are greater.
D It is zero if the charges of the objects repel one another.

Answers

The electrostatic force connecting two electrostatic force is expressed by the statement that it is stronger when the voltages of the items are greater.

Electrostatics: What is it?

The study of energies between charged, as outlined by Coulomb's Law, is known as electrostatics. We introduce the idea of a magnetic charge encircling charges. The electric current near a line and a plane are examples that we go through as we create detailed definition for both "electric potential" and "voltage."

What is an example of electrostatics?

Examples involving electrostatic forces are: With the aid of a comb, we can create electrostatic force when i pass a piece of paper through to the oil in my heads. When one balloon is brushed with hair, the other balloon becomes drawn to it.

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The amount of kinetic energy in a moving object depends on its mass and what

Answers

Answer:

Kinetic energy depends on mass and speed (or magnitude of velocity).

K.E.  = 1/2 M S² or The amount of kinetic energy of a moving object has dependence on its  mass and its velocity.

Explanation: They are both right for a certain question

The kinetic energy of a moving object depends on its mass and velocity. The higher the velocity higher will be the kinetic energy. Mass also have the similar effect.

What is kinetic energy?

Kinetic energy of an object is the energy generated by virtue of its motion. When particles of an  object acquire much energy to overcome the intermolecular force, they gain kinetic energy to move apart.

Kinetic energy is related to the mass and velocity of the moving object. The expression relating kinetic energy with these parameters is written below:

Ke = 1/2 mv².

As per the relation, the kinetic energy of an object increases with an increase in mass or velocity or both. Hence, massive objects with greater velocity is having greater kinetic energy.

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A laser emitting light with a wavelength of 560 nm is directed at a single slit, producing an interference pattern on a screen that is 3.0 m away. The central maximum is 5.0 cm wide.

Determine the width of the slit and the distance between adjacent maxima.
What would the effect on this pattern be, if
the width of the slit was smaller?
the screen was moved further away?
a larger wavelength of light was used?

How would this interference pattern differ if the light was shone through a double slit?
diffraction grating?

Answers

Answer:

a) a = 6.72 10⁻⁵ m,  b)  the slit (a) is smaller, which represents a wider pattern

Explanation:

In is a diffraction experiment since we have a single slit, it is explained by the equation

          a sin θ = m λ

where a is the width of the slit

The diffraction pattern is characterized by a very intense central maximum, with a value of 5.0 cm, therefore the distance from the center to the first zero is y = 5.0 / 2 cm = 2.5 10⁻² m

let's use trigonometry to enter the angle

         tan θ = y / L

         tan θ = sin θ / cos θ = sin θ

         sin θ = y / L

substituting into the equation

          a y / L = m λ

the first maximum occurs for m = 1

          a = λ L / y

let's calculate

          a = 560 10⁻⁹ 3.0 / 2.5 10⁻²

          a = 6.72 10⁻⁵ m

b) if the width a of the slit (a) is smaller

        sin θ = m λ / a

therefore the sinus increases, which implies a greater angle, which represents a wider pattern

c) if the distance to the screen (L) goes away

           y = m λL / a

If L increases the width of the pattern they also increase of course the intensity must be less

d) If the wavelength increases

    In this case the width of the pattern also increases

e) What happens if the light passes through two slits in this case we have two diffraction patterns one centered in each slit and the resulting pattern is the sum of these patterns, this sum gives the double slit interference that characterizes a series of slits of equal height

in order for the average velocity to be different from the avergae speed, what has to be true of the object's motion?

Answers

Answer:

ok

Explanation:

Acceleration is defined as the rate of change of velocity.

Acceleration = (Change in velocity) / time taken

Acceleration = (Final velocity - initial velocity) / time

As the object velocity changes by the same amount in each second, it means the acceleration is constant.

Calculate Kinetic Energy The potential energy of a swing is 200 J
at its highest point and 50 J at its lowest point. If mechanical
energy is conserved, what is the kinetic energy of the swing at its
lowest point?

Answers

Answer:

150J

Explanation:

Pi = Pf + Kf

200 = 50 + Kf

---> Kf = 150J

The kinetic energy of the swing at its lowest point is 150 J.

What is energy?

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

Given in the question the potential energy of a swing is 200 J at its highest point and 50 J at its lowest point

Pi = Pf + K E

200 = 50 + K E

K E = 150 J

The kinetic energy of the swing at its lowest point is 150 J.

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4. Calculate the wavelength of waves that have a frequency of 0.50 Hz and a speed of 4.0

m/s.


Answers

The wavelength of waves can be calculated using the formula λ = v/f, where λ is the wavelength, v is the speed of the wave, and f is the frequency of the wave. The wavelength of the waves with a frequency of 0.50 Hz and a speed of 4.0 m/s is 8.0 meters.

In this case, the frequency of the waves is given as 0.50 Hz and the speed is given as 4.0 m/s.
Substituting these values in the formula, we get:
λ = 4.0 m/s / 0.50 Hz
λ = 8.0 m
It is important to note that the wavelength of a wave is directly proportional to its frequency and inversely proportional to its speed. This means that if the frequency of the wave increases, its wavelength also increases, while if the speed of the wave increases, its wavelength decreases.
Understanding the relationship between wavelength, frequency, and speed of waves is crucial in various fields, including physics, engineering, and telecommunications. These concepts are used to design and optimize systems that rely on the transmission and reception of waves, such as radios, televisions, and satellite communications.

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Two independent single phase semiconverters are supplying the armature and field circuits of a separately excited dc motor for controlling its speed. The firing angle of the converter supplying the field adjusted such that maximum field current flows. The machine parameters are armature resistance = 0.25 2, field circuit resistance 147 , motor voltage constant K = 0.7032 V/A *rad/s. The load torque is T = 45 Nm at 1000 rpm. The converters are fed from a 208 V, 50 Hz ac supply, and the friction and windage losses are neglected. The = m. 1032V/4 e ind inductance of the field and armature circuits is sufficient to make the armature and field current continuous and ripple free. Determine (a) The field current (b) The delay angle of the armature converters (c) The input power factor of armature circuit converters.

Answers

(a) Field current is calculated as;If = V/ff Rfwhere, V

= 208 V (supply voltage)ff

= 50 Hz (supply frequency)Rf

= 147 Ω (field circuit resistance)Therefore,If

= 208/50*147

= 0.282 A(b) The motor voltage equation is given by,Ea

= KφNwhere,Ea

= V - Ia Raφ is fluxN is the speedK

= 0.7032 V/A rad/sIa

= V1 / Rawhere V1 is the converter output voltage.Rearranging these equations,φ

= (Ea - V1) / KIa

= V1 / RaEa

= KφN + Ia RaV - V1

= KφN + V1 / Ra Ra∴ V1

= (V - KφN Ra ) / (1 + Ra ).

Where,V = 208 VK = 0.7032 V/A rad/sRa

= 0.25 ΩN = 1000 rpm

= 2πN / 60 rad/s≈ 104.67 rad/s Substituting all these values,V1

= (208 - 0.7032 * φ * 104.67 * 0.25) / (1 + 0.25)

= 31.79φHence, Ia

= V1 / Ra

= 31.79/0.25

= 127.16 A The power input to the armature circuit,P

= V1 Ia cos (α)
= 31.79 * 127.16 cos(α)

The load torque TL = 45 Nm
So, α = cos⁻¹ (TL / KIaN)
α = cos⁻¹ (45 / 0.7032 * 127.16 * 104.67)
α = 47.23°(c) The input power factor of armature circuit converters is given as:
PF = cos (α) = cos (47.23°)

= 0.68.
Therefore, the power factor of the armature circuit converters is 0.68.

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A single-turn current loop, carrying a current of 3.66 A, is in the shape of a right triangle with sides 50.0,101. and 113 cm. The loop is in a uniform magnetic field of magnitude 65.9mT whose direction is paraliel to the current in the 113 cm side of the loop. What is the magnitude of the magnetic force on (a) the 113 cm side, (b) the 50.0 cm side. and (c) the 101 cm side? (d) What is the magnitude of the net force on the loop?

Answers

a.  The force on the 113 cm side is 0N. b. The force on the 50.0 cm side is 0.120N. c. The 101 cm side force is 0.234N . d. The magnitude of the net force on the loop is 0.354 N

The magnitude of the magnetic force on each side of the loop can be determined using the formula F = I * L * B * sin(θ), where I is the current, L is the length of the side, B is the magnetic field magnitude, and θ is the angle between the magnetic field and the side of the loop. The net force on the loop can be obtained by summing the individual forces acting on each side.

(a) To calculate the magnitude of the magnetic force on the 113 cm side, we use the formula F = I * L * B * sin(θ). The current (I) is 3.66 A, the length (L) is 113 cm, the magnetic field magnitude (B) is 65.9 mT (converted to Tesla by dividing by 1000), and the angle (θ) is 0 degrees since the magnetic field is parallel to this side. Therefore, the force on the 113 cm side is F = 3.66 * 1.13 * 0.0659 * sin(0°) = 0 N.

(b) Similarly, for the 50.0 cm side, the force can be calculated using the same formula, but the length is 50.0 cm and the angle θ is 90 degrees since the magnetic field is perpendicular to this side. Thus, the force on the 50.0 cm side is F = 3.66 * 0.5 * 0.0659 * sin(90°) = 0.120 N.

(c) For the 101 cm side, the angle θ is also 90 degrees, so the force is F = 3.66 * 1.01 * 0.0659 * sin(90°) = 0.234 N.

(d) To find the net force on the loop, we sum the individual forces: 0 + 0.120 + 0.234 = 0.354 N.

Therefore, the magnitude of the net force on the loop is 0.354 N.

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Ten seconds after starting from rest, a freely-falling object will have a speed of about ________________________

Answers

Answer:

100 m/s

Explanation:

Speed increases at a rate of 10 m/s (actually 9.8 m/s) every second. Thus after 10 seconds, the speed is 10 x 10 = 100 m/s.

Next, given the equivalent resistance,
Req(23), what is the equivalent
resistance, Reg, of the series
combination of R1 and Req(23)?
Ri
Req(23)
100 12
120 12

Next, given the equivalent resistance,Req(23), what is the equivalentresistance, Reg, of the seriescombination

Answers

Answer:

Req= 220 ohm

Explanation:

In series combination just add the resistances.

Req=R1+Req(23)

Req=100+120

Req= 220 ohm

32) You are at the stern of a paddle boat and observe that the paddle wheel has a radius of 10ft and makes 15
revolutions per minute. What is the speed of the paddle boat with respect to the water?

Answers

The linear speed of the paddle boat is 15.7 ft/s.

What is the speed of the paddle boat?

The speed of the paddle boat is calculated by applying the following formula as shown below.

v = ωr

where;

ω is the angular speed of the paddle boatr is the radius of the circular path

The angular speed of the paddle boat = 15 rev / min

= 15 rev/min   x   2π rad/rev   x   1 min / 60 s

= 1.57 rad/s

The linear speed of the paddle boat is calculated as follows;

v = 1.57 rad/s  x   10 ft

v = 15.7 ft/s

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What is promising evidence of a habitat that might support life
on the planet Mars?
Detailed Answer please, will give thumb up rating definitely

Answers

A promising evidence of a habitat that might support life on the planet Mars is water.

There is evidence supporting the existence of liquid water on Mars from numerous sources. The finding of repeated black streaks on Martian slopes and the presence of hydrated minerals suggest the potential of seasonal or location-specific briny water flows. A necessary component of life as known is liquid water.

Additionally, Mars possesses underground ecosystems that could provide defence against radiation and severe surface conditions. Researchers have found evidence of ancient underground hydrothermal systems as well as beneath ice. These settings might offer consistent conditions for the development of microbial life.  Methane gas has been found in the Martian atmosphere, along with variations over time, and this has led to questions regarding its origin. Both geological and biological processes can result in the production of methane.

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Question 7 of 10
What is kinetic friction?
A. Friction that acts when an object is not moving
B. Friction that opposes air resistance
C. Friction that exerts no force
D. Friction that acts on a sliding object
SUBMIT

Answers

Kinetic friction (also referred to as dynamic friction) is the force that resists the relative movement of the surfaces once they're in motion.
https://www.khanacademy.org › stat...
Static and kinetic friction example (video) | Khan Academy

Answer a would be static friction
Answer b is fluid friction
(Air resistance is fluid friction. Fluid friction is the friction experienced by objects which are moving in a fluid and the air is a fluid.)
Answer c is static friction
ANSWER D IS KINETIC FRICTION

Hope this helps :D



Answer: Friction that acts on a sliding object

Explanation:

An issue the students encountered is that the marble doesn't land on the launch pad all of the time. To remedy this, they consider constructing a funnel to help direct the marble. How do you suggest the students move forward with their design process in order to find a solution?
A Test funnels of the same size and material with varying sized openings.
B Test funnels of the same shape and size with varying materials.
C Test funnels with identical openings and material with varying size.
D Test all of the above funnels and then construct a funnel with the best design elements from each.​

Answers

I suggest that the students move forward with option A.

Test funnels of the same size and material with varying sized openings. This will allow them to determine the optimal size for the opening that will help direct the marble to the launch pad. Once they have determined the optimal size, they can move forward with constructing the funnel with that size opening.

To find a solution to the issue of the marble not landing on the launch pad consistently, I suggest the students follow a systematic approach in their design process. Option D, testing all of the above funnels and then constructing a funnel with the best design elements from each, would be the most comprehensive and effective approach.

By testing funnels of different sizes, materials, and openings, the students can gather valuable data and insights about how each factor affects the marble's trajectory. This will help them identify the key design elements that contribute to successful landing on the launch pad.

Once the students have tested the various funnels, they can analyze the results and determine which design elements worked best in terms of directing the marble accurately. By combining these successful elements, they can then construct a new funnel that incorporates the best features from each tested funnel. This iterative approach allows them to refine their design and increase the chances of achieving consistent and reliable results.

Therefore, option D provides a comprehensive method for the students to explore different design possibilities, gather data, and ultimately create an improved funnel design.

Andy has a bath and uses 1500g of water heated from 10°C to 40°C and with a specific heat capacity of 4200J/kg°C. How much energy does he use?

Answers

Andy uses 189,000 joules of energy to heat 1500g of water from 10°C to 40°C.

How to find how much energy Andy used

The amount of energy used to heat the water can be calculated using the formula:

Q = m * c * ΔT

where:

Q = amount of energy used (in joules)

m = mass of water (in kilograms)  = 1500 g / 1000 = 1.5 kg

c = specific heat capacity of water (4200 J/kg°C)

ΔT = change in temperature (in °C)

plugging in the values into the formula:

Q = 1.5 kg * 4200 J/kg°C * (40°C - 10°C)

Q = 1.5 kg * 4200 J/kg°C * 30°C

Q = 189,000 joules

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Actividad
1: En general, la dificultad para arrancar electrones aumenta de izquierda a derecha en cada periodo de la tabla periódica. Busca en la tabla periódica potasio (K), calcio (Ca) y uranio (U) y basándote en sus posiciones indica cuál de ellos tendrá una función de trabajo más baja y cuál más alta:


Menor función de trabajo:

Mayor función de trabajo:


2.- La energía de un electrón emitido se mide en electrón-voltios(eV). Un electrón con una energía de 1 eV puede superar un campo eléctrico de 1 voltio. En el simulador, aumenta la tensión hasta que encuentres la tensión más alta que todavía permite a los electrones llegar al amperímetro.


Tensión =


El volaje que has encontrado es igual a la energía de los electrones emitidos en eV.

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