Answers
Answer:
Its northeast. Just took the exam.
Explanation:
Answer:
See image
Explanation:
Plato
Related Questions
how is newtons first law of motion related to the concept of inertia?
Answers
# 5 what will most likely happen when an air mas of low temperature exists above a water body at a higher temperature?
Heat will transfer from the wetter to the air
Answers
Answer:
yes u are correct
Explanation:
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When metal strips are place in a liquid, bubbles are observed to form around the metal. When the gas from these bubbles is collected in a balloon, the balloon rises.
what can be concluded in this experiment
A- the gas is poisonous
b- the gas is hydrogen
c- if the balloon is touched with a match, the collected gas will explode
d- the gas is lighter than air
e- the gas is hot because the liquid boiled
Answers
Answer:
option d - "the gas is lighter than air"
Explanation:
Based on the given experiment, the most likely conclusion is that the gas collected in the balloon is lighter than air, which causes the balloon to rise. Therefore, option d - "the gas is lighter than air" is the correct answer.
It is not possible to conclude whether the gas is poisonous, hydrogen, or hot because these properties cannot be determined solely from the given experiment. Additionally, it is not safe to assume that the collected gas will explode when touched with a match, as this would depend on the specific properties of the gas collected.
PLS HELP!! Our eyes perceive colors because of differences in which of the following properties of light?
Amplitude
Brightness
Wavelength
Source
Answers
Answer:
Your answer is wavelength
1) Which of the following is not true about vectors.a) Must have magnitude and direction.b) When doing math with vectors, we can usually treat the x and y components independently.c) If several vectors are added together, their order does not matter.d) The magnitude of a vector is the sum of the magnitude of its x and y components.2) Explain briefly your argument or reasoning.
Answers
a) A vector must have a magnitude and direction. A physical quantity with only the magnitude is called a scalar.
b) When doing the math we can treat the x and y components independently. We can use only x-component or only y-component for the necessary calculations. For example, the projectile motion. In projectile motion, we use the components of velocities independently.
c) We can add or subtract more than two vectors in any order. For example, If there are 3 vectors, A, B, and C then, from the associative law of vector addition,
\(\vec{A}+(\vec{B}+\vec{C})=(\vec{A}+\vec{B})+\vec{C}\)d) The magnitude of the vectors is not the sum of their x and y components. Let vector A be represented as
\(\vec{A}=x\hat{i}+y\hat{j}\)Where x and y are the x and y components of vector A respectively. And î and j cap are the unit vectors along the x and y direction respectively.
Then, the magnitude of vector A is given by,
\(A=\sqrt[]{x^2+y^2}\)Thus the correct answer is option d. That is the statement in option d is not true.
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Answers
Answer:
b
Explanation:
this because if force (f) are resultant cos then the point is proportional to the direction of c at greatest possible forces
Define thermal conductivity.
Answers
Answer:
A measure of the ability of a material to transfer heat.
Explanation:
Please mark me as brainliest please
4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V
Answers
The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.
To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.
Given:
R1 = 4 Ω
R2 = 30 Ω
R3 = 10 Ω
R4 = 5 Ω
Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:
RT1-2 = R1 + R2
RT1-2 = 4 Ω + 30 Ω
RT1-2 = 34 Ω
Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:
1/RTotal = 1/RT1-2 + 1/R3
1/RTotal = 1/34 Ω + 1/10 Ω
1/RTotal = (10 + 34) / (34 * 10) Ω
1/RTotal = 44 / 340 Ω
1/RTotal ≈ 0.1294 Ω
RTotal ≈ 1 / 0.1294 Ω
RTotal ≈ 7.74 Ω
Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:
RTotalCircuit = RTotal + R4
RTotalCircuit = 7.74 Ω + 5 Ω
RTotalCircuit ≈ 12.74 Ω
Therefore, the total resistance of the circuit is approximately 12.74 Ω.
To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:
I = V / RTotalCircuit
I = 56 V / 12.74 Ω
I ≈ 4.39 A
Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).
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Keyana and Sam are testing the law of conservation of energy. They use the same ball and release it from the same vertical height. Keyana is using a frictionless track, while Sam's track has friction. They discover Keyana's ball had more kinetic energy than Sam's when it reached the bottom. Which statement best explains why this happened if energy is conserved? Sam's ball lost mass as it traveled along the track. Sam's ball interacting with the track converted energy into heat. Keyana's ball was able to gain momentum. Keyana's ball had more potential energy.
Answers
The true statement is "Sam's ball interacting with the track converted energy into heat." The correct option is B.
The law of conservation of energy states that energy cannot be created or destroyed, only transferred or converted from one form to another. This means that the total amount of energy in a closed system remains constant.
The friction between Sam's ball and the track caused some of the energy to be lost as heat, while Keyana's ball experienced no such loss due to the absence of friction in her experiment. Therefore, Keyana's ball retained more of its initial potential energy as kinetic energy, resulting in a greater velocity and hence more kinetic energy at the bottom.
Option A (Sam's ball lost mass as it traveled along the track) is not true because it is not possible for the ball to lose mass during the experiment. The mass of the ball is a constant value and is not affected by the experiment.
Option C (Keyana's ball was able to gain momentum) is not the best explanation because momentum is not conserved in this scenario since external forces like friction are acting on the ball. The ball is only gaining kinetic energy.
Option D (Keyana's ball had more potential energy) is not true because both Keyana and Sam released the ball from the same vertical height. Therefore, both balls had the same initial potential energy. The difference in their kinetic energies at the bottom can be explained by the difference in their conservation of energy due to friction.
Therefore, The correct statement that best explains why Keyana's ball had more kinetic energy than Sam's when it reached the bottom, even though energy is conserved, is: Sam's ball interacting with the track converted energy into heat.
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Explain what happens with the 0.25 days each year
Answers
Answer:
leap year
Explanation:
which statement describes an example of constructive interference
Answers
Answer:
For example, if we see two loudspeakers next to each other, it can make sense to place each loudspeaker at the same distance from the viewer.
Explanation:
Answer:light forms bars on a surface after passing through two slits
Explanation:
A 1000 kg rollercoaster requires a braking force of 8780N from point D to point E in order to stop. Find
a) The Total Mechanical Energy of the rollercoaster at Point A. b) The velocity of the coaster at point A. c)
The velocity of the coaster at point B. d) The highest hill the coaster could have gotten over before point A
with no additional mechanical energy. (Ans. a) 591,100 J b) 2.5 m/s c) 34.4 m/s d) 60.3 m)
Answers
The total mechanical energy at point A is 617,400 J, and the velocity of the coaster at point A is 25 m/s, the velocity of the coaster at point B is 34.4 m/s. and the highest hill the coaster could have gotten over before point A with no additional mechanical energy is 63 m.
To solve this problem, we can use the conservation of mechanical energy, which states that the sum of kinetic energy and potential energy is constant in a closed system where there is no work done by non-conservative forces like friction. We can use this principle to find the answers to the questions.
a) The Total Mechanical Energy of the rollercoaster at Point A
The total mechanical energy of the rollercoaster at point A is the sum of its potential energy and kinetic energy. At point A, the rollercoaster is at its highest point, so its kinetic energy is zero. Therefore, the total mechanical energy at point A is equal to the potential energy, which is given by:
mgh = 1000 kg × 9.8 m/s^2 × 63 m = 617,400 J
b) The velocity of the coaster at point A
To find the velocity of the coaster at point A, we can use the conservation of mechanical energy principle again. At point A, all of the potential energy is converted into kinetic energy. Therefore, we can write:
1/2 mv^2 = mgh
where m is the mass of the rollercoaster, v is the velocity at point A, g is the acceleration due to gravity, and h is the height of point A relative to point E. Solving for v, we get:
v = sqrt(2gh) = sqrt(2 × 9.8 m/s^2 × 63 m) = 25 m/s
Therefore, the velocity of the coaster at point A is 25 m/s.
c) The velocity of the coaster at point B
To find the velocity of the coaster at point B, we can use the conservation of mechanical energy principle again. At point B, the rollercoaster is at a height of 42 m above the ground. Therefore, the potential energy at point B is:
mgh = 1000 kg × 9.8 m/s^2 × 42 m = 411,600 J
At point B, some of the potential energy is converted into kinetic energy, so we can write:
1/2 mv^2 + mgh = mgh_D
where v is the velocity at point B, h is the height of point B relative to point E, and h_D is the height of point D relative to point E. Solving for v, we get:
v = sqrt(2(mgh_D - mgh)/m) = sqrt(2(8780 J)/1000 kg + 2gh) = 34.4 m/s
Therefore, the velocity of the coaster at point B is 34.4 m/s.
d) The highest hill the coaster could have gotten over before point A with no additional mechanical energy
If the rollercoaster had no additional mechanical energy, its total mechanical energy at point A would be equal to its potential energy, which we calculated in part (a) to be 617,400 J. Therefore, the maximum height that the rollercoaster could reach without any additional mechanical energy is given by:
mgh_max = 617,400 J
Solving for h_max, we get:
h_max = 617,400 J / (1000 kg × 9.8 m/s^2) = 63 m
So, the highest hill the coaster could have gotten over before point A with no additional mechanical energy is 63 m.
Therefore, The coaster has a total mechanical energy of 617,400 J at point A, a velocity of 25 m/s, a velocity of 34.4 m/s, and a maximum hill height of 63 m that it could have traversed without using any further mechanical energy.
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What is scintillator
Answers
Answer:
Scintillators are materials that are able to convert high energy radiation such as X or gamma-rays to a near visible or visible light. They are widely used as detectors in medical diagnostics, high energy physics and geophysical exploration (ref. Knoll).
https://web.stanford.edu › scintillators
What are scintillator materials? - Stanford: Advanced Optical Ceramics Laboratory
The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
Answers
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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Assume that helium behaves as an ideal monatomic gas. If 2 moles of helium undergo a temperature increase of 100 K at constant pressure, how much energy has been transferred to the helium as heat
Answers
Answer:
6235.5J
Explanation:
Using ( nစ)p= ncp x change in temp
But cp= ( 1+ f/2)R
So cp= ( 1+ 3/2R
Cp= 5R/2
So = n x 5R/2x 150k
= 2 x 5/2x 8.314 x150
= 6235.5J
Answer:
2500 J
Explanation:
Q=(3/2)nRΔT
Q=(3/2)*2 mol*(8.314 J/mol*k)*100 k
Q=2494 J
if the angle opf elevation of the cannon is decreased from 35 degrees to 30 degrees, the ertical compent of the balls iontial veclotiy will
Answers
Answer:
Decrease
Explanation:
Decrease
Vertical component = v sin (angle)
sin 30 is less than sin 35
which of the following set of tools would be most useful in an experiment measuring the rate of thermal energy in four different liquids?
Answers
What is an inexpensive, portable, and common way to assess body fat in the fitness industry?
DEXA
Bioelectrical impedance
Skinfold testing
Hydrostatic weighing
Answers
Answer: Skinfold testing
Explanation:
Skinfold testing, is also referred to as calliper testing and it's used to know the body fat percentage. Skinfold testing is an inexpensive, portable, and common way to assess body fat in the fitness industry.
It is typically done with the use of caliper tapes, marker pens which makes it cheap. Skinfold testing isn't usually accurate which is as a result of human errors.
A sample of The halflife of the substance is 21 minutes the number of atoms remaining underway. radioactive Substances has 812X1020 atom Determine the number of atoms remaining
Answers
After 42 minutes, there are 203 x \(10^{20\) atoms remaining of the radioactive substance.
To determine the number of atoms remaining after a certain amount of time has passed, we can use the formula for radioactive decay:
N(t) = N0 * \((1/2)^{(t / T)\),
where:
N(t) = number of atoms remaining at time t,
N0 = initial number of atoms (812 x \(10^{20\) atoms),
T = half-life of the substance (21 minutes), and
t = time that has passed.
Let's calculate the number of atoms remaining after a given time.
Suppose the time passed is t = 42 minutes (twice the half-life).
N(t) = 812 x \(10^{20\) * \((1/2)^{(42 / 21)\)
N(t) = 812 x \(10^{20\) * \((1/2)^2\)
N(t) = 812 x \(10^{20\) * 1/4
N(t) = 203 x \(10^{20\) atoms.
So, after 42 minutes, there are approximately 203 x \(10^{20\) atoms remaining of the radioactive substance.
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A physics student was studying falling bodies and decided to drop a water balloon from an outdoor stairwell to measure its speed. If the balloon was dropped a distance of 6 meters and it only took 1.1 seconds to fall, how fast was the balloon traveling on average? A. 0.2 m/s B. 6.6 m/s C. 5.5 m/s D. 66 m/s
WILL NAME BRAINLIEST
Answers
Answer:
C. 5.5 m/s
Explanation:
How fast the balloon travels is determined from the velocity or v
The formula is v = s/t or velocity equals distance divided by time
So, v = 6 meters divided by 1.1 seconds = 5.5 meters per second
Answer:
C. 5.5 m/s
Explanation:
How fast the balloon travels is determined from the velocity or v
The formula is v = s/t or velocity equals distance divided by time
So, v = 6 meters divided by 1.1 seconds = 5.5 meters per second
A uniform meter stick has its center of mass at 50 cm mark. A mass of 50 gram is hung at 20 cm mark of the meter stick. An unknown mass is hung at 70 cm mark. The system is balanced at the fulcrum at 50 cm mark as shown in the figure. Find the unknown mass M.
Question 2 options:
85 gram
100 gram
33.33 gram
14.29 gram
75 gram
Answers
Hi there!
We can use a summation of torques to find the unknown mass:
∑F = R · F (distance from fulcrum × force in this instance)
Since there are masses on both sides, we can set their torques equal to each other since they must balance:
∑F = 0
R₁F₁ = R₂F₂
F = weight of mass, or Mg
50(g)(50 - 20) = M(g)(70 - 50)
Cancel out the g's, or acceleration due to gravity:
50(30) = M(20)
Solve:
1500 = M(20)
1500/20 = M = 75 grams
Group B[1] 12 State Huygens's Principle [2] b) In a Young's double slit experiment, the fringe width obtained is 0.6 cm. When light of wave length 4500 Aº is used if the distance between the screen and the slit is reduced in half, what should be the wavelength of light used to obtain fingers 0.0045 m wide? [3]
Answers
The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.
Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.
Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.
Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.
We can use the formula for fringe width in Young's double-slit experiment:
w = (λ * D) / d
Where:
w is the fringe width,
λ is the wavelength of light,
D is the distance between the screen and the double slits, and
d is the distance between the two slits.
Let's calculate the value of D/d using the given information:
D/d = w / λ
= 0.006 m / 4500 Å (1 m = 10^10 Å)
= 0.006 * 10^10 / 4500 m^-1
Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:
(D'/d) = (0.006/2) * 10^10 / 4500 m^-1
Now, we can rearrange the equation to solve for the new wavelength (λ'):
(λ' * D') / d = (D/d)
λ' = (D/d) * d / D
= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å
= 0.0045 m * 10^10 / 2 Å
= \(0.00225 * 10^{10\) Å
=\(2.25 * 10^7\)Å
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Jack is pushing a 30.0 kg cart at a constant acceleration of 2.1 m/s^2. He is combatting a force of 24N of gravity. If Jack let go of the cart when the velocity was 1.5 m/s, how far would the cart travel before stopping?
Answers
Answer:
The car will travel 1,41 m before stop.
Explanation:
F = m * a
- 24 N (loss) = 30 Kg * a
a = -24/30 = -0,8 m/s^2
Using the Torricelli equation:
V^2 = Vo^2 = 2*a*S
final velocity = 0 (when the car stops)
initial velocity = 1,5 m/s (when the driver stops the acceleration)
0^2 m/s = (1,5 m/s)^2 + (2 * -0,8 m/s^2 * S)
0 = 2,25 - 1,6S
S = -2,25/-1,6
S = 1,41 m
The x component of vector is 8.7 units, and its y component is -6.5 units. The magnitude of is closest to
Answers
Answer:
F = 10.86 units
Explanation:
The magnitude of a vector in terms of the magnitude of its rectangular components is given by the following formula:
F = √(Fₓ² + Fy²)
where,
F = Magnitude of the Vector = ?
Fₓ = magnitude of the x-component of vector = 8.7 units
Fy = magnitude of y component of vector = - 6.5 units
Therefore, using these values in the equation, we get:
F = √[(8.7 units)² + (- 6.5 units)²]
F = √(117.94 units²)
F = 10.86 units
You are lowering two boxes, one on top of the other,
down a ramp by pulling on a rope parallel to the surface of the
ramp (Fig. E5.33). Both boxes move together at a constant speed
of 15.0 cm>s. The coefficient of kinetic friction between the ramp
and the lower box is 0.444, and the coefficient of static friction
between the two boxes is 0.800. (a) What force do you need to
exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?
Answers
To solve this problem, we need to use Newton's second law to find the net force acting on the two boxes. The net force is equal to the mass of the two boxes times the acceleration. Since the boxes are moving at a constant speed, the acceleration is zero, and the net force is also zero. This means that the sum of all the forces acting on the two boxes must be zero.The force you exert on the boxes is the force of tension in the rope, and this force is equal in magnitude and opposite in direction to the force of friction on the lower box. The magnitude of the friction force on the lower box is equal to the coefficient of kinetic friction times the normal force acting on the lower box.The normal force is the force exerted by the ramp on the lower box, and it is equal in magnitude to the weight of the lower box. The weight of the lower box is equal to the mass of the lower box times the acceleration due to gravity.The magnitude of the friction force on the upper box is equal to the coefficient of static friction times the normal force acting on the upper box. The normal force acting on the upper box is equal in magnitude to the weight of the upper box.Now that we have all the forces, we can use Newton's second law to solve for the force you need to exert. The equation is:F_tension - F_friction_lower = 0
F_tension = F_friction_lowerF_friction_lower = u_k * N_lower
F_tension = u_k * m_lower * gWhere:F_tension is the force you need to exertF_friction_lower is the force of friction on the lower boxu_k is the coefficient of kinetic friction between the ramp and the lower boxN_lower is the normal force acting on the lower boxm_lower is the mass of the lower boxg is the acceleration due to gravitySubstituting the given values, we get:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The force you need to exert is therefore:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The magnitude of the friction force on the upper box is:F_friction_upper = u_s * N_upperWhere:F_friction_upper is the force of friction on the upper boxu_s is the coefficient of static friction between the two boxesN_upper is the normal force acting on the upper boxSubstituting the given values, we get:F_friction_upper = (0.800) * (m_upper) * (9.8 m/s^2)The direction of the friction force on the upper box is opposite to the direction of motion of the upper box.
7. State condition of equilibrium when a borly is acted upon by a number of parallel forces. A uniform metal tube of length 5cm and mass 9 kg is suspended horizontally by two vertical wire attaches at 50cm and 150cm respectively from the ends of the tuber Find the tension in each wire. in tril Solution -
Answers
According to the question the tension in each wire is 1.96 N.
What is tension?Tension is a term that describes the psychological and physical state of a person or system in which there is a high degree of stress, uncertainty, and anxiety. It is often associated with conflict and is often experienced when individuals or groups feel threatened or constrained in some way. Tension can be experienced in a variety of different contexts, from interpersonal relationships to the workplace. It can result from a variety of different factors, including a lack of communication, conflicting goals or expectations, and unmet needs.
The body is in equilibrium when the sum of all forces acting on it is equal to zero. In this case, the forces acting on the metal tube are the two wires and the weight of the tube due to gravity.
The tension in each wire is equal to the weight of the tube divided by the length of the tube. This is because the tube is suspended horizontally, so the forces in each wire must be equal in order to keep the tube in equilibrium.
Therefore, the tension in each wire is:
T = (9 kg × 9.8 m/s2) / (5 cm × 0.01 m)
= 1.96 N
Therefore, the tension in each wire is 1.96 N.
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A bug slides back and forth in a bowl 12 cm deep, starting from rest at the top, as shown in Fig. 7.20. The bowl is frictionless except for a 1.8-cm-wide sticky patch on its flat bottom, where the coefficient of friction is 0.83. How many times does the bug cross the sticky region?
Answers
The bug will cross the sticky region once in each cycle of its motion, where a cycle is defined as one complete round trip from the top of the bowl to the bottom and back to the top.
To find the number of cycles the bug goes through, we can use conservation of mechanical energy. At the top of the bowl, the bug has only potential energy, which is converted to kinetic energy as it slides down the bowl. At the bottom of the bowl, all of the potential energy has been converted to kinetic energy, and as the bug slides up the other side of the bowl, the kinetic energy is converted back into potential energy. At the top of the bowl again, the bug has only potential energy, and the cycle repeats.
Because there is no friction (except for the sticky patch), the total mechanical energy of the system is conserved. Therefore, the potential energy at the top of the bowl is equal to the potential energy at the bottom of the bowl, and the kinetic energy at the bottom of the bowl is equal to the kinetic energy at the top of the bowl.
We can set the potential energy at the top of the bowl to zero, and use the conservation of energy to find the potential energy at the bottom of the bowl:
mgh = (1/2)mv^2
where m is the mass of the bug, g is the acceleration due to gravity, h is the depth of the bowl, and v is the speed of the bug at the bottom of the bowl.
Solving for v, we get:
v = sqrt(2gh)
Plugging in the numbers, we get:
v = sqrt(29.810.12) = 0.775 m/s
The time it takes for the bug to slide from the top of the bowl to the bottom and back up to the top is twice the time it takes to slide from the top to the bottom:
t = 2sqrt(2h/g) = 2sqrt(2*0.12/9.81) = 0.774 s
Therefore, the frequency of the bug's motion is:
f = 1/t = 1/0.774 = 1.29 Hz
Since the bug completes one cycle in each oscillation, the bug will cross the sticky region 1.29 times per second, or approximately once every 0.78 seconds.
The train took 2 h 30 min to travel 3/5 of a journey at an
average speed of 96 km/h. If the train would complete the
journey in 4.1 h, what is the train's average speed for the
remaining journey?
km/h
Answers
Answer:
100km/h
Explanation:
96km•2.5=240km
240÷3/5=240•5/3=400km
400-240=160km
4.1-2.5=1.6h
160÷1.6=100km/h
Question 2 (1 point)
What happens to the number of waves when you change the light from green to red?
Increase
decrease
remain the same
there are zero waves
Answers
When you change the light from green to red, the number of waves remains the same.
Light waves behave similarly throughout the electromagnetic spectrum. Depending on the nature of the item and the light's wavelength, a light wave can be transmitted, reflected, absorbed, refracted, polarized, diffracted, or dispersed when it strikes a surface.
The number of waves doesn't vary when the light changes from green to red. The distance between each wave's consecutive peaks, or wavelength, determines the color of light. Red and green light both have waves with a set number of peaks and troughs per unit of time, despite green light having a shorter wavelength. As a result, the number of waves is unaffected by changing the colour of the light.
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A fifty-car train going 25 meters per second takes 150 seconds to stop. What is the acceleration?
( show work please )
Answers
Answer:
6
Explanation:
150 seconds divided by 25 meters per seconds = 6