The block of mass m sits at rest on a rough inclined ramp that makes an angle θ with the horizontal. If the force of static friction f on the block is less than the force due to gravity, then the block will begin to slide down the ramp.
The static frictional force is defined as the force exerted on an object by a surface that is attempting to move it, but which is not yet moving. So, f>mg sin θ.The force of static friction must be greater than the force due to gravity, i.e., f>mg sin θ.
When the block is at rest, the force of static friction is equal and opposite to the force due to gravity, i.e., f = mg sin θ. In order to prevent the block from sliding down the ramp, the force of static friction must be equal to or greater than the component of the force due to gravity that is parallel to the ramp.
In order to calculate the force of static friction, we need to consider the components of the force due to gravity that are parallel and perpendicular to the ramp. The component of the force due to gravity that is perpendicular to the ramp is mg cos θ, and the component that is parallel to the ramp is mg sin θ.
The force of static friction is equal to or greater than mg sin θ, so the correct answer is (C) F > mg sin θ.The force of static friction is defined as the force exerted on an object by a surface that is attempting to move it, but which is not yet moving.
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Calculate the area of the plates of a 1 pF parallel plate capacitor in a vacuum if the separation of the plates is 0.1 mm. [ε0=8.85×10-12C2N-1m-2 ]Select one:6.2 m214.4 m211.3 m218.4 m2
Apply:
C = A e0 / d
Where:
C = capacitance = 1pf = 1 x10^-12 F
A = area
ε0 = 8.85×10^-12
1 pf = 1 x 10^-12 F
A = Cd / ε0 = 1 x 10^-12 ( 1 x 10^-4 ) / 8.85×10^-12 = 1.13 x10 ^-5 m^2
A radio announcer's voice is transmitted via radio waves a distance of 998.25 km. How much time, in microseconds, will it take to transmit the wave over this distance?
A radio wave travels at the speed of light, which is equal to approximately 300,000 km/s.
So, to travel a distance of 998.25 km, the time needed is:
\(\begin{gathered} distance=speed\cdot time\\ \\ 998.25=300000\cdot time\\ \\ time=\frac{998.25}{300000}\\ \\ time=0.0033275\text{ seconds}\\ \\ time=3327.5\text{ microseconds} \end{gathered}\)Therefore the time required is approximately 3327.5 microseconds.
Select the correct answer. What is the main function of a telescope? A. It brings scientists closer to distant objects. B. It magnifies light received from distant objects. C. It measures the temperature of distant objects. D. It measures the wavelengths of incoming light rays.
Answer: A. It brings scientists closer to distant objects.
Explanation:
When light from infinite coming toward the lens of the telescope then this light is converge at the focal plane of the lens. This will image which is formed at the focal plane worked as an object for another lens of the telescope.
Now another lens made the final virtual image which is seen by the observer.
So here in this whole process the main working of Telescope is to form the image of a distant object near to the eye of an observer. So the light coming from the infinite distance is collected together and then a bright image is formed by that light so that observer is able to see the image clearly
so here correct answer would be
A. It brings scientists closer to distant objects.
Answer:
Answer: A. It brings scientists closer to distant objects.
Explanation:
Please Help! Thanks
Study the scenario.
A rock falls off the edge of a cliff. The system consists of the rock, the cliff, and the Earth.
Which choice best describes the changes in kinetic and potential energy?
Responses:
Before the rock falls, all the energy is stored as potential energy. The potential energy remains the same because the Earth’s pull on the rock does not change. The kinetic energy remains the same because the acceleration remains constant. The total energy remains constant.
Before the rock falls, all the energy is stored as potential energy. The kinetic energy increases as the rock falls because its speed increases. The potential energy decreases as the rock falls because its position relative to the ground decreases. The total energy remains constant.
Before the rock falls, all the energy is stored as kinetic energy. As the rock falls, the kinetic energy remains constant because the rock’s acceleration remains constant. The potential energy decreases as the rock falls because its position relative to the ground decreases. The total energy decreases.
Before the rock falls, all the energy is stored as potential energy. The kinetic energy increases as the rock falls because its speed increases. The potential energy increases as the rock falls because its position relative to the ground increases. The total energy increases.
The falling of the rock will follow the principle of conservation of energy.
Energy conservation principleBefore the rock falls, all the energy is stored as potential energy. The kinetic energy increases as the rock falls because its speed increases. The potential energy decreases as the rock falls because its position relative to the ground decreases.
Thus, the total energy remains constant.
When the rock falls, it gains kinetic energy due to its motion, and loses potential energy due to its decrease in height. However, the total energy of the system (rock, cliff, and Earth) remains constant because energy is conserved. This is known as the conservation of energy principle.
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how does an objects size affect the gravity exerted by that object
Answer:
The size of an object is directly proportional to the gravity
Explanation:
The size of an object has significant impact on the gravity exerted by such a body.
The more massive a body is, the larger the gravity it exerts.
The reason for this is because of the newton's law of universal gravitation.
It states that "the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them". As such, gravity is directly proportional to massCompare the values for index of refraction of glass for each trial (values in last column) Is there good agreement between them? Would you conclude that index of refraction is constant for & given medium? Compare your calculated nz with the given index of refraction, nglass. Do they agree? Explain why it does or doesn't"
The calculated average n2 does not agree with the given index of refraction, indicating a potential discrepancy that may be attributed to experimental limitations or errors.
To analyze the agreement between the values for the index of refraction (n2) of glass in each trial, we can observe the trend and variation in the data. From the table, it appears that the values for n2 increase as the angles θ1 and θ2 increase. However, it is difficult to determine the level of agreement between the values without further statistical analysis or calculation of uncertainties.
The conclusion regarding whether the index of refraction is constant for a given medium depends on the level of agreement observed. If the values for n2 in each trial are close to each other and do not deviate significantly, it suggests good agreement and supports the hypothesis of a constant index of refraction.
On the other hand, if there is significant variation and inconsistency among the values, it indicates that the index of refraction may not be constant for the given medium.
To determine the average value of n2 from the provided results, we can calculate the mean of the n2 values:
Average n2 = (1.46 + 1.61 + 1.73 + 1.96 + 2.08 + 2.13) / 6 ≈ 1.85
Comparing the calculated average n2 (1.85) with the given index of refraction of the glass (1.50), we can see that they do not agree. The calculated average n2 is higher than the given value of 1.50. This suggests that there might be some systematic error or uncertainties in the measurements or calculations.
The difference between the calculated and given values could be due to factors such as experimental errors, instrumental limitations, or other sources of uncertainty in the measurement process.
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Complete question is:
Calculate sinθ1, sinθ2 and n2 for each of your results and add them to table 1. Keep your results to 2 or 3 significant figures.
Compare the values for index of refraction of glass for each trial (values in last column). Is there good agreement between them? Would you conclude that index of refraction is a constant for a given medium?
Determine the average value of n2 from your results.
Compare your calculated n2 with the given index of refraction of the glass (1.50). Do they agree? Explain why it does or doesn’t.
On an aircraft carrier, a jet can be catapulted from 0 to 250 km/h in 2.05 s
If the average force exerted by the catapult is 9.40×10^5 N , what is the mass of the jet?
Answer:
mass = 27750 kg
Explanation:
acceleration: (change in velocity)÷(time)
acceleration = (final velocity - initial velocity) ÷ time taken
Given that:
Final velocity is 250 km/h and initial is 0 km/h and time is 2.05s
change 2.05s to hrs. that is 0.0005694444 hrsacceleration = [(250 - 0) ÷ 0.0005694444]
acceleration = 439024.4 km/h²
conversion to m/s² :
acceleration = 439024.4 m/s²
--------------------------------------------------------------------
Force = mass(kg) * acceleration(m/s²)
we know that force is 9.40×10^5 N
9.40×10^5 = mass(kg) * 33.875 (m/s²)
mass = 9.40×10^5 ÷ 33.875
mass = 27750 kg
help me PLEASE, it's physical science D:
Answer:
90
Explanation:
The bottom number on the element is the number of protons and the top number is the total of the protons + neutrons
30 PTS NEED THIS FAST
Answer:
the one made from aluminum
Explanation:
The composition of a star is determined from... Group of answer choices the amount of shift in the spectral lines in the spectrum. the pattern of spectral lines in its spectrum. the depth of spectral lines in the spectrum. the red or blue shift of spectral lines in a spectrum the width of the spectral lines in the spectrum
The composition of a star is determined from the red or blue shift of spectral lines in a spectrum, the width of the spectral lines in the spectrum.
What is spectroscopy ?The study of light and other radiation absorption and emission by matter is called spectroscopy. Electromagnetic radiation into its constituent wavelengths, in a spectrum, just like a prism splits light into a rainbow of colors.
The composition of a star is determined from the red or blue shift of spectral lines in a spectrum, the width of the spectral lines in the spectrum.
Hence, option D is correct.
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A wrestler bench presses 64 kg. If the barbell accelerates upward at a rate of 2.57 m/s2, what is the force exerted by the wrestler on the weights?
A wrestler bench presses 64 kg. If the barbell accelerates upward at a rate of 2.57 m/s2, The force exerted by the wrestler on the weights will be 164.48 N
Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
given
mass = 64 kg
acceleration = 2.57 \(m/s^{2}\)
Using newton's second law
force = mass * acceleration
= 64 * 2.57 = 164.48 N
The force exerted by the wrestler on the weights will be 164.48 N
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On
a summer day in Narragansett, Rhode Island, the air temperature is
70 degrees F and the barometric pressure is 15.5 lbf/in^2 estimate
the air density in kg/m^3
To estimate the air density in kg/m^3 given the air temperature of 70 degrees F and barometric pressure of 15.5 lbf/in^2 in Narragansett, Rhode Island, we can use the ideal gas law.
The air density can be calculated by converting the temperature to Kelvin and the pressure to Pascals, and then applying the ideal gas law equation.
To begin, we need to convert the temperature from Fahrenheit to Kelvin. The Kelvin temperature scale is used in scientific calculations, and the conversion is done by adding 273.15 to the temperature in Celsius. In this case, 70 degrees F is approximately 21.1 degrees Celsius, so adding 273.15 gives us a temperature of approximately 294.25 Kelvin.
Next, we need to convert the barometric pressure from pounds per square inch (lbf/in^2) to Pascals (Pa). One atmosphere is approximately equal to 101,325 Pascals. To convert from pounds per square inch to Pascals, we can use the conversion factor of 6894.76 Pascals per square inch. Therefore, the barometric pressure of 15.5 lbf/in^2 is approximately equal to 106,686.38 Pascals.
Now, we can apply the ideal gas law equation, which states that the density (ρ) of a gas is equal to the pressure (P) divided by the product of the gas constant (R) and the temperature (T). The gas constant R is approximately 8.314 J/(mol·K). However, since we are interested in air density in kg/m^3, we need to convert the units. The molar mass of air is approximately 28.97 g/mol, so we can use the ideal gas law equation with the appropriate units to calculate the air density in kg/m^3.
By substituting the values into the equation, we have:
ρ = (P / (R * T)) * (M / V)
Where ρ is the air density, P is the pressure, R is the gas constant, T is the temperature, M is the molar mass of air, and V is the volume.
With the given temperature of 294.25 K and barometric pressure of 106,686.38 Pascals, we can calculate the air density in kg/m^3 using the ideal gas law equation.
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______is when different species live in close association.
Answer:
Symbiosis
Explanation:
When you have a symbiotic relationship, it is between two or more organisms of different species.
If a 96 n force of gravity is happening to a falling basketball what is the ball mass? The accelydue to gravity is 9.8m/s^2
Answer:
9.80 kg
Explanation:
F = ma
96 N = m(9.8 m/s^2)
m = 9.80 kg
The mass of the ball will be m= 9.8 kg
What is Newton's second law of motion?
It states that the force is equal to the rate of change of momentum . For a constant mass , force is equal to mass times acceleration
given :
Force due to gravity = 96 N
g = acceleration due to gravity = 9.8 m /s^2
using Newton's second law of motion
Since , F = ma
96 = m g
m = 96/9.8
m= 9.8 kg
The mass of the ball will be m= 9.8 kg
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The Enterprise wants to orbit a4.15 x 10^24kg planet with a period of14100 s. What should the radius oftheir orbit be?
Given:
Mass of planet, m = 4.15 x 10²⁴ kg.
Period, T = 14100 s
Let's find the radius.
To find the radius, apply the formula from Kepler's Third aw:
\(\begin{gathered} \frac{T^2}{R^3}=\frac{4\pi^2}{GM} \\ \\ \end{gathered}\)Where R is the radius.
Rewrite the formula for r:
\(R=\sqrt[3]{\frac{GM*T^2}{4\pi^2}}\)Where:
G is gravitational constant = 6.67 x 10⁻¹¹ m3 kg-1 s-2
M is the mass = 4.15 x 10²⁴ kg
T is the period = 14100 s
π = 3.54
Plug in values and solve for R;
\(\begin{gathered} R=\sqrt[3]{\frac{6.67\times10^{-11}*4.15\times10^{24}*14100^2}{4\pi^2}} \\ \\ R=\sqrt[3]{\frac{5.503\times10^{22}}{39.4784}} \\ \\ \end{gathered}\)Solving further:
\(\begin{gathered} R=\sqrt[3]{1.394\times10^{21}} \\ \\ R=11170796.49\approx1.12\times10^7\text{ m} \end{gathered}\)Therefore, the orbital radius will be 1.12 x 10⁷ meters.
ANSWER:
1.12 x 10⁷ m
A Xerox machine is set to reduce the size of a printed object by 50%. When the print is regular size, both the image and the object are 16.0 cm from the lens.
b) If the lens is moved so that it is 24 cm from the object, what is the distance to the image?
The distance to the image when the lens is moved to 24 cm from the object is 48 cm.
When the Xerox machine is set to reduce the size of the printed object by 50%, it means that the size of the image produced will be half the size of the original object. Therefore, if the object and image are 16.0 cm away from the lens when they are regular size, the distance between the lens and the image when reduced will be half of that or 8.0 cm.
Now, if the lens is moved so that it is 24 cm away from the object, we can use the lens equation:
1/f = 1/di + 1/do
Where f is the focal length of the lens, di is the distance to the image, and do is the distance to the object.
Assuming that the focal length of the lens is constant, we can solve for di as follows:
1/f = 1/di + 1/do
1/24 = 1/di + 1/16
1/di = 1/24 - 1/16
1/di = 1/48
di = 48 cm
Therefore, the distance to the image when the lens is moved to 24 cm from the object is 48 cm.
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suppose an airline allows a maximum of 40 kg for each suitcase a passenger brings along. (a) what is the weight in newtons of a 40 kg suitcase? n (b) what is the weight in pounds?
The weight of a 40 kg suitcase is 392 N (newtons). In pounds, it would be approximately 88.18 lbs.
Weight is the force exerted on an object due to gravity. It is given by the formula:
Weight = mass * gravitational acceleration
where the mass is measured in kilograms. Given that the mass of the suitcase is 40 kg, we can multiply it by the gravitational acceleration (approximately 9.8 m/s^2) to calculate the weight in newtons. Therefore, the weight of a 40 kg suitcase is 40 kg * 9.8 m/s^2 = 392 N.
To convert the weight from newtons to pounds, we need to divide the weight in newtons by the conversion factor of 4.448 N/lb (since 1 N is approximately equal to 0.2248 lbs). Therefore, the weight of a 40 kg suitcase is approximately 392 N / 4.448 N/lb = 88.18 lbs.
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pls help asap. will mark as brainliest if correct
Answer:
Hey mate, here is your answer answer. Hope it helps you
Explanation:
1. If a worker has come into contact with electricity the worker may not be able to remove themselves from the electrical source. The human body is a good conductor of electricity. If you touch a person while they are in contact with the electrical source, the electricity will flow through your body causing electrical shock. Firstly attempt to turn off the source of the electricity (disconnect). If the electrical source can not readily and safely be turned off, use a non-conducting object, such as a fibreglass object or a wooden pole, to remove the person from the electrical source.
2. C- Electrical energy.The term electrical activity means that the food itself has the power to generate electric energy that persists some period of time. This work presents a purely renewable energy as energy comes. the zinc reacts with food tissue.
What is the relationship of a battery to potential energy 
Answer: Their relationship is negative.
Explanation:
"What is the relationship of a battery to potential energy?"
The change in potential energy for the battery is negative, since it loses energy. These batteries, like many electrical systems, actually move negative charge—electrons in particular.
When vectors b+a= 5i-j & vectors b-a=i-7j, what is the magnitude and direction of vector a
Eliminate b by combining b + a and b - a, and solve for a :
(b + a) - (b - a) = (5i - j) - (i - 7j)
2a = 4i + 6j
a = 2i + 3j
Now compute the magnitude and direction.
mag: ||a|| = √(2² + 3²) = √13
dir: tan(θ) = 3/2 ⇒ θ = arctan(3/2) ≈ 56.3°
Given two metal balls (that are identical) with charges LaTeX: q_1q 1and LaTeX: q_2q 2. We find a repulsive force one exerts on the other to be LaTeX: 1.35\times10^{-4}N1.35 × 10 − 4 N when they are 20 cm apart. Accidentally, one the the experimenters causes the balls to collide and then repositions them 20 cm apart . Now the repulsive force is found to be LaTeX: 1.406\times10^{-4}N1.406 × 10 − 4 N. What are the initial charges on the two metal balls?
Answer:
\(q_1=\pm0.03 \mu C\) and \(q_2=\pm0.02 \mu C.\)
Explanation:
According to Coulomb's law, the magnitude of force between two point object having change \(q_1\) and \(q_2\) and by a dicstanced is
\(F_c=\frac{1}{4\pi\spsilon_0}\frac{q_1q_2}{d^2}-\;\cdots(i)\)
Where, \(\epsilon_0\) is the permitivity of free space and
\(\frac{1}{4\pi\spsilon_0}=9\times10^9\) in SI unit.
Before dcollision:
Charges on both the sphere are \(q_1\) and \(q_2\), d=20cm=0.2m, and \(F_c=1.35\times10^{-4}\) N
So, from equation (i)
\(1.35\times10^{-4}=9\times10^9\frac{q_1q_2}{(0.2)^2}\)
\(\Rightarrow q_1q_2=6\times10^{-16}\;\cdots(ii)\)
After dcollision: Each ephere have same charge, as at the time of collision there was contach and due to this charge get redistributed which made the charge density equal for both the sphere t. So, both have equal amount of charhe as both are identical.
Charges on both the sphere are mean of total charge, i.e
\(\frac{q_1+q_2}{2}\)
d=20cm=0.2m, and \(F_c=1.406\times10^{-4}\) N
So, from equation (i)
\(1.406\times10^{-4}=9\times10^9\frac{\left(\frac{q_1+q_2}{2}\right)^2}{(0.2)^2}\)
\(\Rightarrow (q_1+q_2)^2=2.50\times10^{-15}\)
\(\Rightarrow q_1+q_2=\pm5\times 10^{-8}\)
As given that the force is repulsive, so both the sphere have the same nature of charge, either positive or negative, so, here take the magnitude of the charge.
\(\Rightarrow q_1+q_2=5\times 10^{-8}\;\cdots(iii)\)
\(\Rightarrow q_1=5\times 10^{-8}-q_2\)
The equation (ii) become:
\((5\times 10^{-8}-q_2)q_2=6\times10^{-16}\)
\(\Rightarrow -(q_2)^2+5\times 10^{-8}q_2-6\times10^{-16}=0\)
\(\Rightarrow q_2=3\times10^{-8}, 2\times10^{-8}\)
From equation (iii)
\(q_1=2\times10^{-8}, 3\times10^{-8}\)
So, the magnitude of initial charges on both the sphere are \(3\times10^{-8}\) Coulombs\(=0.03 \mu C\) and \(2\times10^{-8}\) Colombs or \(0.02 \mu C\).
Considerion the nature of charges too,
\(q_1=\pm0.03 \mu C\) and \(q_2=\pm0.02 \mu C.\)
3(2x+4)=48 how do i solvethis
Answer:
hgeusugusuisdgfisyhdfygsdyfiusdgoWEGBDSFGVSI
Explanation:
Si
Explanation:
6x+12=48
6x=48-12
6x=36
x=6
strong evidence for the existence of dark matter comes from observations of: our solar system. the center of the milky way. clusters of galaxies.
Strong evidence for the existence of dark matter comes from observations of clusters of galaxies.
Observations of clusters of galaxies provide compelling evidence for the presence of dark matter. When studying the motion of galaxies within clusters, it becomes apparent that the visible matter alone cannot account for the observed gravitational effects. The gravitational pull required to hold these galaxies together and explain their motions is significantly greater than what can be accounted for by the visible matter, such as stars and gas clouds. This suggests the presence of additional mass in the form of dark matter, which does not interact with light and thus cannot be directly observed.
While our solar system and the center of the Milky Way have also been subjects of study in the search for dark matter, the evidence from observations of clusters of galaxies is particularly strong. The large-scale distribution of dark matter within clusters, along with the observed gravitational lensing effects caused by dark matter, provide strong support for its existence.
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a 60 kg hiker wishes to climb 1200 meter high if he can generate a sustained average power of 500 watts, how long will the climb take
The time it will take do the hiker to climb the 1200m high wall is 1,411.2 seconds.
How to calculate time from power?Power refers to the measure of the rate of doing work or transferring energy.
Power = Work done/time
Since work = force × distance the body is moved
Power = (m × g × h) / t
Where;
m = the mass of the bodyg = the acceleration due to gravityh = the height the body has fallent = the time the body has fallenAccording to this question, a 60kg hiker wishes to climb 1200m high. If he can generate a sustained average power of 500 watts, the time it will take to climb is as follows;
500 = 60 × 9.81 × 1200/t
500t = 705,600
t = 1,411.2 seconds
Therefore, 1,411.2 seconds is the time it will take the hiker.
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Whats the cell that’s based on that persons sex
Answer:
gamete i think
You drive a bumper car into another bumper car whose driver has a much larger body mass than you do. Who experiences more of a jolt, you or the other driver?
Answer:
both drivers experience the same force. just with different "results"
Explanation:
Answer:
You do
Explanation:
Momentum is mass*velocity. So Newton's 3rd law equal and opposite reaction. Because you weigh less you will have more force act on you than the driver who weighs more.
Identify all the forms of energy in the picture below
identify thermal energy, mechanical energy, radiant energy, electrical energy, sound energy, and chemical energy
Answer:
we are going to focus on just a few. • Heat energy ( Thermal). • Mechanical energy. • Light (Radiant) energy. • Electrical energy. • Sound energy. • Chemical energy
What would most likely be included in the "Analysis" section of a lab report?
O a discussion of any errors in the experimental data
a list of the supplies that were used in conducting the experiment
Osuggestions for new experiments based on the results
Oa description of what the dependent and independent variables were
The "Analysis" section of a lab report would most likely includes:
a. a discussion of any errors in the experimental datad. a description of what the dependent and independent variables were.What components are typically found in the "Analysis" section of a lab report?In the "Analysis" section of a lab report, it is common to discuss any errors or uncertainties that may have affected the experimental data. This may involve identifying sources of systematic and random errors and discussing their potential impact on the results.
Also, the section would typically describe the dependent and independent variables used in the experiment, providing a clear understanding of the factors being investigated and manipulated. By addressing these aspects, the "Analysis" section helps to evaluate the reliability and validity of the experimental findings.
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Do all waves travel at the same speed in different materials
No, not all waves move through various materials at the same pace. The characteristics of the medium itself, the kind of wave, and the frequency of the wave are only a few of the variables.
that affect how quickly a wave moves through a given medium. Sound waves, for instance, go through various materials at varying rates, depending on the density and elasticity of the medium. In general, solids transmit sound more quickly than liquids or gases do. Similar to how sound waves go through various materials at various rates, depending on the refractive index of the medium. Light waves, for example, constantly travel in a vacuum at a constant speed of around 299,792,458 meters per second (or about 186,282 miles per second). Nevertheless, as they go on.
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Does the government think about the welfare of its citizens? Justify (Mention any 2 points)
Answer:
Yes government thinks about the welfare of its citizens because:-
1 they are developing new things day by day.
2 they distribute clothes and different things to their citizens