A block of cheese is pulled on by a string and remains at rest.
What is the correct free body diagram for the block of cheese?
Choose 1 answer:

Answers

Answer 1

Answer:

Explanation:

- The friction acts leftwards to balance the tension that must be pulling up and to the right.

- The force of gravity is straight down.

- The normal force is perpendicular to the contact surface.

A Block Of Cheese Is Pulled On By A String And Remains At Rest.What Is The Correct Free Body Diagram
Answer 2

The force of gravity is straight down.

What is force of gravity?

On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them.

Gravity is measured by the acceleration that it gives to freely falling objects.

According to the question,

A block of cheese is pulled on by a string and remains at rest until we will not apply an external force.

It also posses force of gravity.

The friction acts leftwards to balance the tension that must be pulling     up and to the right.

The force of gravity is straight down.

The normal force is perpendicular to the contact surface.

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A Block Of Cheese Is Pulled On By A String And Remains At Rest.What Is The Correct Free Body Diagram

Related Questions

Selection
boy throws a 1.2 kg ball straight up at 12 m/s. How high does the ball go? 1 point
(Answer to two digits)

Answers

Answer:

69

Explanation:

4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V

4. Calculate the total resistance of the circuit if R1=4 , R2=30 , R3=10, R4=5 Determine the current

Answers

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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HELP ANSWER is 17.5 m, 5m, or 0m

HELP ANSWER is 17.5 m, 5m, or 0m

Answers

Answer: 5m

Explanation:

The graph shows a constant velocity from t=0 to t=5 of 1m/s.

if V= 1 m/s for 5 seconds we multiply 1m/s(5s)=5m

Which section shows the greatest rate of positive acceleration?

Which section shows the greatest rate of positive acceleration?

Answers

The rate at which an object changes its velocity is known as acceleration, a vector quantity.

What kind of positive acceleration is the greatest?When the rate of change of velocity in an increasing sense (the slope of the velocity-time curve) is at its highest positive value, acceleration will be at its maximum positive value.The rate of change in velocity is greater for the graph with the sharpest slope. That thing is moving with the most velocity.The velocity-time graph displays a line with an upward slope, indicating a positive acceleration; the line is situated in the graph's positive area (corresponding to a positive velocity).When the car accelerates positively, its speed rises. As the car slows down, its speed decreases.When an object accelerates in the same direction as its velocity, it is doing so in that same direction. This object is therefore moving at a positive rate.

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Write a hypothesis about how the mass of the cylinder affects the temperature of the water. Use the "if . . . then . . . because . . .” format and be sure to answer the lesson question: "How is potential energy converted to thermal energy in a system?”

Answers

Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.

According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.

As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.

As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.

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4. A 990 kg car reduces its velocity from 22 m/s to 13 m/s. Calculate the change in the car's momentum:

Answers

Answer:

The change in the car's momentum is equal to -8910 kgm/s.

Explanation:

Given that,

The mass of a car, m = 990 kg

Initial speed, u = 22 m/s

Final momentum, v = 13 m/s

We need to find the change in the car's momentum. The change in momentum of the car is given by :

\(\Delt p=m(v-u)\\\\=990\times (13-22)\\\\=-8910\ kg-m/s\)

So, the required change in the car's momentum is equal to -8910 kgm/s.

"An egg is free-falling from a nest in a tree. Neglect air resistance."
A There are two forces acting on the egg and
the forces are balanced.
C There are three forces acting on the egg and
the forces are unbalanced.
B There is one force acting on the egg and the
force is unbalanced.
D
There are four forces acting on the egg and
the forces are balanced.

Answers

In a scenario where an egg is free-falling from a nest in a tree and neglecting air resistance, there is one force acting on the egg and the force is unbalanced which is denoted as option B.

What is a Force?

This is referred to as an external agent which is capable of influencing the motion of an object or body. It is also capable of changing the state of rest of a body and the unit in Newton.

When an object is falling from a height and there is no air resistance then the only force acting on it is gravitational force which is unbalanced as there is no equal and opposite force to make it stable.

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A rigid body is rotating with constant angular speed 3 radians per second about a fixed axis through the points A. (4, 1, 1), B. (2, -1; 0), distances being measured in centimeters. The rotation is in the left-handed sense relative to the direction AB
1, Determine the unit vector pointing in the direction BA.
2, What is the angular velocity () of the of the body?
3, Write the position vector of point P: P .
Find the instantaneous velocity of particle P [hint v = w×r)
4, What is meant by left-handed rotation (left-handed coordinate system)?
5, Write the position vectors of points A and B The rotation axis AB has direction BA. Write the direction BA in terms of the components given above. ​

Answers

1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.

5.Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA = (-2, -2, -1)

1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.

The direction vector BA is given by:

BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)

To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:

|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3

Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.

5.The position vectors of points A and B are:

Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:

BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)

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the efficiency of a machine cannot be 100 percent why?

Answers

Answer:

A machine cannot be 100 percent efficient because output of a machine is always less than input. A certain amount of work done on a machine is lost to overcome friction and to lift some moving parts of the machine

friction and heat and wearing down and fuel sources problems are why machine cannot be 100% efficient.

Hope this helps...

1. A charge of 6.4 C passes through a cross-sectional area or conductor in 2s. How much charge will pass through a cross sectional area of the conductor in 1 min?​

Answers

The amount of charge that will pass through the cross-sectional area of the conductor in 1 min is 192 C.

What is the  amount of charge?

We can use the formula Q = I * t,

where;

Q is the amount of charge, I is the current, and t is the time.

Given that a charge of 6.4 C passes through a cross-sectional area of the conductor in 2 s, we can find the current using the formula:

I = Q / t = 6.4 C / 2 s = 3.2 A

So, the current through the conductor is 3.2 A.

To find the amount of charge that will pass through the cross-sectional area of the conductor in 1 min (60 s), we can use the same formula:

Q = I * t = 3.2 A * 60 s = 192 C

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like pole of magnet ----------each other ​

Answers

Answer:

repeal each other......

Doctor prescribed drug which is 500mg for patient change this unit into gram

Answers

Answer:

.5 grams

Explanation:

1 gram is equal to 1000 milligrams (mg)

What is the relationship between the frequency of light and its color?

Answers

Answer:

we understand it by electromagnetic spectrum. and we velength is the distance between identical location on adjecent waves ( see figure below)

Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.

Answers

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

How do i determine the quantity of heat energy?

First, we shall list out the given parameters from the question. This is shown below:

Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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what substance will heat up quickest - Dry soil, granite, water or wet soil

Answers

Granite will heat up the quickest among dry soil, granite, water, and wet soil due to its lower specific heat capacity.

To determine which substance will heat up the quickest among dry soil, granite, water, and wet soil, we need to consider their specific heat capacities. The substance with the lowest specific heat capacity will heat up the quickest.

Specific heat capacity is defined as the amount of heat energy required to raise the temperature of a substance by a certain amount. Different substances have different specific heat capacities due to variations in their molecular structure and composition.

Water has a relatively high specific heat capacity of about 4.18 J/g°C, meaning it requires a significant amount of heat energy to raise its temperature. Dry soil and granite, on the other hand, have lower specific heat capacities compared to water.

Wet soil is a mixture of dry soil and water, and its specific heat capacity will lie between the values of dry soil and water. Since water has a higher specific heat capacity than dry soil, wet soil is expected to have a higher specific heat capacity than dry soil as well.

Therefore, based on the comparison of specific heat capacities, the substance that will heat up the quickest is granite. Granite has a lower specific heat capacity than water and wet soil, making it more susceptible to temperature changes. Dry soil and wet soil, including water, will heat up at a slower rate compared to granite.

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A 10 kg block of ice is sliding across the kitchen floor. If the coefficients of friction between ice
and floor are 0.2 static and 0.1 kinetic, how much friction is acting on the ice?
b) what will be the acceleration of the ice?

Answers

(a) The amount of friction force acting on the ice is 9.8 N.

(b) The acceleration of the ice is 0.98 m/s².

What is the friction force acting on the ice?

The amount of friction force acting on the ice is calculated by applying the following equation based on Newton's second law of motion.

F = μmg

where;

μ is coefficient kinetic frictionm is mass of the blockg is acceleration due to gravity

F = 0.1 x 10 kg x 9.8 m/s²

F = 9.8 N

The acceleration of the ice is calculated as follows;

a = μg

a = 0.1 x 9.8 m/s²

a = 0.98 m/s²

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Which is the load ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎

Which is the load

Answers

Answer:

A is the load in the diagram

Answer:

i think the answer is A

You are sitting at your dinner table and notice three peas have fallen off of your plate as shown. Each pea has a mass of 0.22g and d=3.6cm. A. Find the magnitude and direction (CCW from the +axis) of the net gravitational force on the pea labeled M1 B. Find the direction (CCW from the +axis) of the net gravitational force on the pea labeled m1

You are sitting at your dinner table and notice three peas have fallen off of your plate as shown. Each

Answers

Answer:

force = 2.73 x 10^ -15 N

angle = 153.435

Explanation:

Let us redraw the diagram

Let us call

F13 = force on m1 due to m3

F12 = force on m1 due to m2

Now along the x-axis, we have

\(F_x=F_{13}\sin \theta\; \hat{i}\)

and along the y-axis, we have

\(F_y=F_{13}\cos \theta+F_{12}\; \hat{j}\)

Now,

\(F_{13}=G\frac{m_1m_3}{d^2+(2d)^2}\)

and

\(F_{12}=G\frac{m_1m_2}{d^2}\)

Therefore, the force along the x-axis becomes

\(\begin{gathered} F_x=F_{13}\sin \theta\; \hat{i} \\ \Rightarrow F_x=G\frac{m_1m_3}{d^2+(2d)^2}\sin \theta\; \hat{i} \end{gathered}\)

and the force along the y-axis becomes

\(\begin{gathered} F_y=F_{13}\cos \theta+F_{12}\; \hat{j} \\ \Rightarrow F_y=G\frac{m_1m_3}{d^2+(2d)^2}\cos \theta+G\frac{m_1m_2}{d^2}\hat{\; j} \end{gathered}\)

Since

\(\sin \theta=\frac{2d}{\sqrt[]{d^2+(2d)^2}}=\frac{2d}{d\sqrt[]{5}}=\frac{2}{\sqrt[]{5}}\)

and

\(\cos \theta=\frac{d}{\sqrt[]{d^2+(2d)^2}}=\frac{d}{d\sqrt[]{5}}=\frac{1}{\sqrt[]{5}}\)

The above equations become

\(F_x=G\frac{m_1m_3}{d^2+(2d)^2}\times\frac{2}{\sqrt[]{5}}\; \hat{i}\)\(\Rightarrow\boxed{F_x=G\frac{m_1m_3}{5d^2}\times\frac{2}{\sqrt[]{5}}\; \hat{i}}\)

and

\(\boxed{F_y=G\frac{m_1m_3}{5d^2}\times\frac{1}{\sqrt[]{5}}+G\frac{m_1m_2}{d^2}\hat{j}}\)

To find the numerical value, we now put

G = 6.67 x 10^-11

m_1 = m_2 = m_3 = 2.2 x 10^-4 kg

d = 0.036 m

into the above equations and get

\(F_x=(6.67\times10^{-11})\frac{(2.2\times10^{-4})^2}{5(0.036)^2}\times\frac{2}{\sqrt[]{5}}\; \hat{i}\)\(\boxed{F_x=4.46\times20^{-16}\; \; \hat{i}}\)

and

\(F_y=(6.67\times10^{-11})\frac{(2.2\times10^{-4})^2}{5(0.036)^2}\times\frac{1}{\sqrt[]{5}}+(6.67\times10^{-11})\frac{(2.2\times10^{-4})^2}{(0.036)^2}\hat{j}\)\(\Rightarrow\boxed{F_y=2.7\times10^{-15}\; \hat{j}}\)

Therefore, the net gravitational force is

\(F_{\text{tot}}=4.46\times20^{-16}\; \; \hat{i}+2.7\times10^{-15}\; \hat{j}\)

the magnitude of this net force is

\(|F_{\text{tot}}|=\sqrt[]{(4.46\times20^{-16})^2+(2.7\times10^{-15})^2}\)\(\boxed{|F_{\text{tot}}|=2.73\times10^{-15}}\)

Finally, we need to find the direction of this force.

To specify, the direction, we need to find the angle this force makes counterclockwise with respect the x-axis.

The angle is given by

\(\cos \theta=\frac{1}{\sqrt[]{5}}\)\(\Rightarrow\theta=63.435^o\)

adding additional 90 degrees gives the angle with respect to the positive x-axis.

\(\theta+90^o=153.435^o\)

Hence, the force is directed at about 153 degrees counterclockwise with respect to the x-axis.

You are sitting at your dinner table and notice three peas have fallen off of your plate as shown. Each

The mass of the moon is 7.35 × 1022 kg and the mass of the earth is 5.98 × 1024 kg. The average distance between the moon and the earth is 3.84 × 108 m. What is this satelite's speed, in km/s (kilometer per second)? Use G = 6.67 × 10-11 N·m2/kg2.

Answers

The speed of the moon is approximately 4.70 km/s.

What is the formula to calculate the gravitational force between two objects?

The formula to calculate the gravitational force between two objects is F = G * (m1 * m2) / r^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers.

How does the distance between two objects affect the gravitational force between them?

The gravitational force between two objects is inversely proportional to the square of the distance between them. This means that as the distance between two objects increases, the gravitational force between them decreases. Conversely, as the distance between two objects decreases, the gravitational force between them increases.

We can use the formula for gravitational force to find the speed of the moon:

F = ma = GMm/r^2

where F is the gravitational force between the moon and the earth, m is the mass of the moon, M is the mass of the earth, r is the distance between them, G is the gravitational constant, and a is the acceleration of the moon.

Solving for a, we get:

a = GM/r^2

Using the given values and converting to km and s units:

a = (6.67 × 10^-11 N·m^2/kg^2) × (5.98 × 10^24 kg) / (3.84 × 10^8 m)^2 = 1.99 × 10^-3 m/s^2

Then, we can use the formula for speed (v) and time (t):

v = at

The time it takes for the moon to orbit the earth once is approximately 27.3 days, or 2.36 × 10^6 s. So, we have:

v = (1.99 × 10^-3 m/s^2) × (2.36 × 10^6 s) = 4.70 × 10^3 m/s

Converting to km/s:

v = 4.70 × 10^3 m/s ÷ 1000 = 4.70 km/s

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Why should people pay attention to scientists when making decisions?
A. Scientists are always correct.
B. Sclentists are the smartest people.
C. Scientists make the best decisions.
D. Scientists back up their statements with facts.

Answers

Answer:

D. Scientist back up their statements with facts.

Explanation:

The majority of the laws, theorems and thesis are base on with experiments. The follow different strategies for confirm the hypothesis with facts, one of the most famous models is the scientific method. That is a way of proof something in a trustworthy.

In the image is the resume about this method (graphical organizer).

Why should people pay attention to scientists when making decisions?A. Scientists are always correct.B.

A boy with a mass of 45 kg runs towards a stationary trolley with a total mass of 30 kg. The boy then jumps on the trolley and the trolley starts to move.
a) Explain why the trolley starts to
move after the boy jumps on it.
b) Calculate the magnitude of the
velocity of the trolley after the boy jumps on it.

anyone here cold helps me to solve and explain the answer... thanks in advance

Answers

Answer:

The trolley moves because a force of exertion is pushed onto it when the boy launches himself onto it. It also moves in a direction, so velocity is applied to it.

The velocity goes from stand-still to something. Also, to find velocity, I think acceleration and time are 2 constants that are needed to find velocity, which is not present in the question.

Sorry if this is not the answer you wanted.. I just gave a basic guess as to what I think the answer is. I just started to learn physics.

Explanation:

You know you can provide 600 W
of power to move large objects. You need to move a 60-kg
safe up to a storage loft, 18 m
above the floor.
Part A
With what average speed can you pull the safe straight up?

Answers

A. The average speed you can use to pull the safe is 1.02 m/s

B. The time needed to pull the safe up is 17.65 s

A. How do i determine the velocity?

First, we shall obtain the force. This is shown below:

Mass of safe (m) = 60 KgAcceleration due to gravity (g) = 9.8 m/s² Force (F) =?

F = mg

F = 60 × 9.8

F = 588 N

Finally, we shall obtain the average speed. Details below:

Power = 600 WForce = 588 NAverage speed =?

Power = force × average speed

600 = 588 × average speed

Divide both sides by 588

Average speed = 600 / 588

Average speed = 1.02 m/s

B. How do i determine the time?

The time needed to pull the safe up can be obtained as follow:

Average speed = 1.02 m/sTotal distance = 18 mTime = ?

Time = Total distance / average speed

Time = 18 / 1.02

Time = 17.65 s

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Complete question:

You know you can provide 600 W

of power to move large objects. You need to move a 60-kg

safe up to a storage loft, 18 m

above the floor.

Part A

With what average speed can you pull the safe straight up?

Part B

What is the time needed to pull the safe up?

A mom pushes her 19.3 kg daughter on the swing. If she gives her an initial velocity of 7.5 m/s at the bottom of the swing and the swing sits 0.6 m above the ground at it's lowest point, what height does she reach above the ground?

Answers

Answer:

3.17333333333? I hope I get it right

Explanation:

..................hello

If the error in the angle is 0.50, the error in sin 90o is​

Answers

At the given erro in angle, the error in the measurement of sin 90 degrees would be 0.001.

Percentage error

The percentage error of any measurement is obtained from the ratio of the error to the actual measurement.

The error of sin 90 degrees is calculated as follows;

sin 90 = 1

error in measurement = sin(90 - 0.5)

error in measurement = sin(89.5) = 0.999

Error in sin 90 degrees

Error in sin 90 degrees = 1 - 0.999

Error in sin 90 degrees = 0.001

Thus, at the given erro in angle, the error in sin 90 degrees would be 0.001.

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The distance of an illuminated object from its light source is decreased to 1/3 while the luminous flux remains constant. Which is true of the illuminance on the object?1) The illuminance will be tripled.2) The illuminance will be multiplied by 9.3) The illuminance will be divided by three.4) The illuminance will be doubled.

Answers

Illuminance is inversely proportional to the square of the distance from the light source.

Then, if we decrease the distance to 1/3, the illuminance will grow up to a factor of 1/(1/3)^2:

\(\frac{1}{(\frac{1}{3})^2}=\frac{1}{(\frac{1}{9})}=9\)

Therefore, the answer is:

2) The illuminance will be multiplied by 9.

You apply a constant 15 N force while pushing a box through a distance of 2.5 m across the floor.

a) How much work, in Joules, did you do?
b) If the box, starting from rest only gains 23 J of kinetic energy, how much of the work that you
did was converted into thermal energy through friction?

Answers

Answer:

Total work done  =force X displacement                      = 15 N X 2.5 m       [ given  F=15 N & d=2.5 m]                W   = 37.5 joules

Explanation:

this is just what i was able to find

The World Snail Racing Championships have been held in the English village of Congham, Norfolk since the 1960s. The contestants are placed at the center of a circular table covered with a damp tablecloth and race outwards 13 inches (33 cm) towards the finish line. A contestant known only as Archie set the current world record of 2 minutes 20 seconds in 1995. Determine Archie's speed in m/s and km/h.

Answers

Speed = distance / time

Speed = (33 cm) / (2min 20sec)

Speed = (0.33 m) / (140 sec)

Speed = 0.0024 m/s

Speed = (0.0024 m/s) x (3600 sec / 1 hr) x (1 km / 1000 m)

Speed = (0.0024 x 3600 / 1000) (m-sec-km / sec-hr-m)

Speed = 0.0085 km/hr

For the time of 2 min and 20 seconds, Archie's speed in m/s will be 0.0024 m/s and Archie's speed in km/hr will be 0.0085 km/hr.

What is Speed?

The "speed at which an object is traveling," or speed, is a scalar quantity. The speed of an object is the rate at which it moves through space. A fast-moving object covers a considerable distance in a short amount of time while traveling at a high speed. An object moving slowly, on the other hand, moves a comparatively modest distance in the same amount of time. An object with zero speed is one that is not moving at all.

According to the question, the given values are :

Distance, d = 33 inches or,

d = 33 cm

Time, t = 2 minutes 20 seconds, or,

t = 140 seconds.

Speed is the ratio of distance to time.

s = 33/140

s = 0.0024 m/s

Now the distance in km/hr will be :

s = 0.0024 m/s × 3600 sec / 1hr × 1 km/ 1000 m

s= 0.0085 km/hr

Hence, the speed in km/hr is 0.0085 km/hr and in m/s speed is 0.0024 m/s.

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How many x-ray photons per second are created by an x-ray tube that produces a flux of x rays having a power of 1.00 W? Assume the average energy per photon in 78.0 keV.

Answers

Answer:

The correct solution is "\(8.012\times 10^{13} \ per/sec\)".

Explanation:

Given:

Power,

P = 1.00 W

Time,

t = 1 sec

Average energy,

E₀ = 78.0 KeV

Or,

    = \(78.0\times 10^3\times 1.6\times 10^{-19}\)

    = \(124.8\times 10^{-16} \ J\)

As we know,

⇒ \(Power =\frac{Total \ energy}{Time}\)

or,

⇒         \(P=\frac{nE_0}{t}\)

⇒      \(1.00=\frac{n(124.8\times 10^{-16})}{1}\)

⇒          \(n=8.012\times 10^{13} \ per/sec\)  

What is the direction of the electric field at a point a distance d = 34.00 cm directly to the right of the positive charge?

Answers

Answer:

s the charge is positive, the electric field lines leave it at the point a d = 0.034 cm, the electric field lines go to the right.

Explanation:

The electric field around the cagases oisitvi, field leaving this means that the field lines move away from

If the charge is negative the lines of the field are directed towards the charge

Let's apply this to our case, as the charge is positive, the electric field lines leave it at the point a d = 0.034 cm, the electric field lines go to the right.

The amount of energy needed to a power a 0.20kw bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of

Answers

The amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.

To calculate the energy required to lift a 2.5 kg object through a vertical distance, we need to consider the gravitational potential energy formula:

Potential energy (PE) = mass (m) × gravity (g) × height (h)

Where:

m = 2.5 kg (mass of the object)

g = 9.8 m/s² (acceleration due to gravity on Earth)

h = ? (height)

First, let's find the height (h) by rearranging the formula:

h = PE / (m × g)

Now, let's calculate the potential energy (PE) needed to lift the object. We are given that the power of the bulb is 0.20 kW, and we want to find the energy required for one minute. To convert kilowatts (kW) to joules (J), we multiply by the conversion factor of 3,600 (60 seconds × 60 minutes):

Energy (E) = power (P) × time (t)

E = 0.20 kW × 1 min × 3,600 J/kW

Now, we can substitute the values into the equation to find the height:

h = (0.20 kW × 1 min × 3,600 J/kW) / (2.5 kg × 9.8 m/s²)

Calculating the expression on the right side:

h ≈ 0.20 × 1 × 3,600 / (2.5 × 9.8) ≈ 29.03 meters (rounded to two decimal places)

Therefore, the amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.

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