The approximate number of atoms in the block of aluminum is 3.76 * 10²³ atoms.
What is heat capacity?Heat capacity or thermal capacity is described as a physical property of matter expressed as the amount of heat to be supplied to an object to produce a unit change in its temperature.
Heat capacity = Mass of the substance x Specific heat capacity.
Specific heat capacity of aluminum = 0.89 J/g/°C
Mass of the substance = heat capacity / specific heat capacity
Mass of aluminum = 15 / 0.89
Mass of aluminum = 16.85 g
Number of atoms = 6.02 * 10²³ * mass / molar mass
The molar mass of aluminum = 27.0 g/mol
The number of atoms = 3.76 * 10²³ atoms.
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please help me with this
What are three different types of electromagnetic radiation that you use in your everyday life? Be sure to identify the source of the radiation as well as the type of electromagnetic radiation that is used.
Explanation:
Some Uses of Electromagnetic waves :
(A) Microwaves
Satellite CommunicationFor cooking food, etc(B) X - Rays (produced by slowing fast moving electrons)
Used in diagnosis of bones, etcluggage content search at airport, etc(C) Radio Waves
Radio and television broadcasting Navigational communication, etcconsider a projectile fired vertically in a constant gravitational field. for the same initial velocities, find the times required for the projectile to reach its maximum height (a) with no resisting force and (b) for a resisting force proportional to the instantaneous velocity of the projectile. (c) show that the result in (a) can be recovered from the result in (b).
Compare the amount of time needed is for projectile to go from its initial velocity to its highest point. (A) for a resistive force of zero.
What types of things are velocities?A number called velocity describes the speed and direction of a point's motion. Because it has both direction and magnitude, velocity is referred to as a linear momentum and cannot be fully expressed in numerical terms, unlike time or length, that are scalar numbers.
How is speed measured?According to the equation v = s/t, velocity (v) is indeed a vector quantity which quantifies displacement (and change in position, s), over change in time (t).
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instead of using the timer to measure the period of many individual oscillations, how would you find the period with good accuracy using a stopwatch?
You can use the stopwatch by doing the following:
How to find the periodTo find the period of an oscillation using a stopwatch instead of a timer, you can follow these steps:
Start the stopwatch at the beginning of an oscillation (for example, when a pendulum starts swinging from one side to the other).Count the number of oscillations that occur while the stopwatch is running. For greater accuracy, it is best to count multiple oscillations (at least 10) to reduce the impact of any human error in counting.Stop the stopwatch when the desired number of oscillations has occurred (or when a set amount of time has passed).Divide the total time recorded by the number of oscillations counted to obtain the average period.For example, if you counted 10 oscillations over a period of 20 seconds, the average period would be 2 seconds (20 seconds divided by 10 oscillations). This method can provide good accuracy if the oscillations are regular and the timing is done carefully.
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What happens to the direction of an object as an unbalanced force acts on
it? Give an example
Answer:
When an unbalanced force acts on a body the side with the greater force's dircetion makes the object move along its direction
Also to find the net force acting on the bofldy you can subtract the two force acting on the body
In case of balanced force the net force will always be 0
Hello :)
Answer:
When an unbalanced force acts on an object, the side with the greater force's direction makes the object move along its direction. For example, when two cars collide on a head-on collision, both vehicles will move in the direction that the vehicle with the greater force is moving in.
Plz help me im really confused. The questions are in the second pic and the vehicles are in the first the fetures are in the last 3 the check mars are just to see which data for that vehicle is safer. The check marks are just to see which data is safer for that car.
Answer:
1.ima say car 2 is safer than car 1.
2.airbags: airbags make it safer because if you get in a reck they will protect you againsed more harm then if you didnt have airbags.
breaking distance: it takes less distance to stop so if there was a reck up the streat you could stop and turn around so you wouldnt get into that wreck.
accrleration: it can make you go faster so incase someoe behind you is speading you could speadup and turn into a parking lot and you wouldent get hurt.
3. car 2 is safer because it has breaking distance and it can stop you way before you get into a wreck than car 1 that doesnt have that ability
Explanation: ima award myself brainliest. Dont ask why i just answerd my own question on here. Yay
If the diameter of Mara is 53.3 percent of Earths diameter (12,756km), determine its diameter in kilometers
The diameter of mars in kilometers is 6,799 km
Any straight line segment that traverses a circle's center and has endpoints that are on the circle is considered a segment of the circle's diameter. The circle's longest chord is another way to describe it. For a sphere's diameter, both definitions are appropriate.
As you are aware: 12,756 km is Earth's diameter; the percentage of Earth's diameter: 53.3% in decimal form is 0.533 (53.3% 100).
You must look for the following: the size of Mars
The equation you must apply is as follows: (Earth's radius) (decimal equivalent)
the size of Mars
Find the solution to the equation for Mars' diameter: (12,756 km) (0.533) (0.533)
6,799 km
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The complete question is-The diameter of the Earth is 12,756 kilometers. Mars has a diameter that is 53.3 percent that of Earth. Determine the diameter of Mars.
what fraction of the engine power is being used to make the airplane climb? (the remainder is used to overcome the effects of air resistance and of inefficiencies in the propeller and engine.)
The fraction of the engine power used to make the airplane climb is 83% to two significant figures.
The power generated by the engine is given by the equation P=W/t, where P is power, W is work, and t is time.
The work done in lifting the airplane can be calculated as W=mgh, where m is mass, g is the gravitational constant, and h is the altitude gained.
Therefore, the power used to make the airplane climb can be calculated as P=mgh/t, where t is the time taken to gain the altitude.
Since the rate of climb is given as 2.5 m/s, the time taken to gain the altitude can be calculated as t=h/2.5, where h is the altitude gained.
Substituting the values into the equation, the power used to make the airplane climb can be calculated as P=750*9.8*h/2.5, where h is the altitude gained.
Therefore, the fraction of the engine power used to make the airplane climb is
P/(80*1000)=750*9.8*h/(2.5*80*1000).
Finally, the fraction of the engine power used to make the airplane climb expressed as a percentage is
(750*9.8 h/(2.5*80*1000))*100=83%.
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what is CHA-CHA-CHA.
Answer:
The cha-cha-cha, is a dance of Cuban origin. It is danced to the music of the same name introduced by Cuban composer and violinist Enrique Jorrin in the early 1950s. This rhythm was developed from the danzón-mambo
Suppose that in problem #6 above the length of the block is known to an accuracy of +/-0.3 cm, while the timer is limited to an accuracy of +/- 0.05 seconds.
a. What is the maximum speed you would calculate for this block, based on these error limits?
Maximum error > minimum error
What is the difference between minimum and maximum error?METHOD OF MIN-MAX. The min-max approach is the fundamental mechanism we will utilize to propagate faults. We establish a minimum and maximum value for each of the measures required to determine the final result when using this approach. The minimum and maximum values are (best value – uncertainty) and (best value + uncertainty), respectively.
According to the size of the sample, researchers have recognized three basic categories of error analysis. There are three categories of samples: enormous, particular, and accidental. Offset mistakes routinely result in incorrect readings.
Scale factor mistakes add (or subtract) a proportion or percentage to the correct value.
There is no pattern to random failures.
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Please help only have a short amount of time left!
Which of the meters illustrated will display the greatest amount of current?
Answer:
I think all will display the same value
Explanation:
Sorry if this is wrong
Answer:
I think it's option a. this is because,it has longer conductivity.
this might be wrong. I am just in jss2 but I read physics
what are 3 sources of heat inside earth?
1. Heat from when Earth was formed.
2. Frictional Heat, which is caused by heavier core material sinking to the center of the Earth.
3. Heat from the decay of elements that are radioactive.
A 2.0 c charge moves with a velocity of (2.0i+4.0j+6.0k)m/s and experiences a magnatic force of (0.4i-20j+12k)N. The x component of the magnatic field is equal to zero. Determine the y component of the magnatic field
Answer:
\(\vec{B}_{y}=6T\)
Explanation:
Here we can use the Lorentz force equation.
\(\vec{F}_{B}=q(\vec{v}\times \vec{B})\)
We know:
v is the velocity (2.0i+4.0j+6.0k) m/sF is the magnetic force (0.4i-20j+12k) NB is the magnetic force (ai+bj+ck) Tq is the charge 2 CSo we will have:
\( (0.4i-20j+12k)=2((2.0i+4.0j+6.0k) \times (ai+bj+ck))\)
Let's solve the cross product, knowing that x component of B is 0, it means a=0.
\( (0.4i-20j+12k)=2((2.0i+4.0j+6.0k) \times (0i+bj+ck))\)
\( (0.4i-20j+12k)=2((4c-6b)i-2cj+2bk)\)
Comparing the k component we have:
\(12=2b \)
\(b=6 \)
If we see b is the y-component of the magnetic field, therefore \(\vec{B}_{y}=6T\)
I hope it helps you!
-0.033 units
Explanation:
According to Lorentz force law, the magnetic force, F, on a moving charge, q, moving with a velocity, v, in a magnetic field, B, is given by;
F = q v x B ----------------(i)
Where;
F, v and B are vectors. Therefore, equation (i) represents a vector product of the velocity and magnetic field vectors.
From the question;
v = (2.0i + 4.0j + 6.0k)m/s
F = (0.4i - 20j + 12k)N
q = 2.0C
Let the magnetic field vector be given by;
B = ai + bj + ck ---------------------(*)
Where;
a, b and c are the magnitudes of the x, y and z components of the magnetic field.
Substitute the values of F, v, B and q into equation (i) as follows;
(0.4i - 20j + 12k) = 2.0(2.0i + 4.0j + 6.0k) x (ai + bj + ck)
Expanding the second bracket gives
(0.4i - 20j + 12k) = (4.0i + 8.0j + 12.0k) x (ai + bj + ck) ---------------(ii)
Solving the right hand side of equation (ii) which is the vector product gives;
| |
| i j k |
(0.4i - 20j + 12k) = | 4.0 8.0 12.0 |
| a b c |
| |
(0.4i - 20j + 12k) = (8.0c - 12.0b)i - (4.0c -12.0a)j + (4.0b - 8.0a)k ----(iii)
Comparing both sides of equation (iii) gives the following three equations;
0.4 = 8.0a - 12.0b --------------------(iv)
-20 = 4.0c - 12.0a ---------------------(v)
12 = 4.0b - 8.0a ----------------------(vi)
From the question, it is given that the x component of the magnetic field is equal to zero. Now, recall that from equation (*) above, the magnitude of the x-component of the magnetic field is given as a
Therefore;
a = 0
To get the y component, which is b, substitute the value of a = 0 into equation (iv) as follows;
0.4 = 8.0(0) - 12.0b
0.4 = 0 - 12.0b
0.4 = - 12.0b
Solve for b;
b = \(\frac{-0.4}{12.0}\) = -0.033
Therefore the y component of the magnetic field is -0.033 units
A colege language class was chosen for a leaming experiment. Using a list of 50 woeds, the experiment measured the rate of vocabulary memorizatcon at different times during a continuous 6-hour study session. The average rate of leaning for the entie cless was inversoly proporional to the time spent studying, and was given approximately by V ( t)= t
13
for 1 sis 6 . Find the area betiven the greph of V l
and the f-axis ovor the interval {3,5], and interpret the retuts. The area botween the arsh of V ′
and the faxis over the interval (3,5) is appeorimathy (Round to the nearns whole number as necded)
A well designed experimen tests multiple variables at once supports your hypothesis does not need multiple trials is controlled to only test one variable Given that a college language class was chosen for a learning experiment. Using a list of 50 words,
the experiment measured the rate of vocabulary memorization at different times during a continuous 6-hour study session. The average rate of learning for the entire class was inversely proportional to the time spent studying, and was given approximately by V(t) = t^(−13) for 1 ≤ t ≤ 6.
We need to find the area between the graph of V(t) and the f-axis over the interval [3, 5], and interpret the results. The area between the graph of V(t) and the f-axis over the interval [3, 5] can be found as follows:∫[3,5]V(t)dt = ∫[3,5]t^(−13)dt = [−12t^(−12)]3 5= −12(5^(−12)−3^(−12))≈ 0.54The area between the graph of V′(t) and the f-axis over the interval (3, 5) can be found as follows: V′(t) = −t^(−14) ∴ ∫(3,5)V′(t)dt = −(5^(−14)−3^(−14))≈ 0.104Thus
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Does a wheel barrow have mechanical advantage???
Answer: YES.
Explanation: OK, lets say you have a basket of fruit, it has a large mass, and a large gravity, it takes more force to lift it up. now, if we try to carry it lets say, across the yard, its gonna be pretty heavy! now, when we put it in a wheel barrow, the force goes onto the wheels. it takes less force to move it.
A researcher is studying the effects of
negative outcomes on the human brain in
a psychological experiment. The
researcher shows ten participants various pictures
and designs. When the participants see a red star,
they are immediately given a brief, painful shock
and their brainwaves are analyzed. A different
group of ten participants is given the same
pictures and designs but are given no shock when
they see the red star.
What was the control in the experiment?
A.The picture of the red star.
B.The group that is given no
shock.
C.The electrical shock.
D.The pictures and designs.
The control in the experiment is option B. The group that is given no shock.
What do experimental controls mean in terms of science?The method utilized by the researcher in scientific study to reduce the impact of unimportant factors is known as experimental control. The power of the independent variable to alter the dependent variable is further strengthened by experimental control. 9 Nov 2021
A controlled experiment is a scientific test carried out under predetermined circumstances in which only one (or a small number of) variables are altered at a time while all other variables are maintained constant.
Researchers use experimental controls to reduce the impact of unrelated experience and environmental factors, as well as to strengthen the conclusion that changes in the dependent variable are caused by the independent variable (the ability to infer causality).
Hence, option B is correct as it is not receiving any special treatment in the experiment.
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Which properties can be used to differentiate between oxygen and hellium, based on the information in the chart?
There are properties can be used to differentiate between oxygen and helium, based on the information in the chart.
At normal temperature, they are both gases, however Helium is a noble gas that is chemically inert. These two elements have entirely different chemical characteristics from one another. For instance, while helium doesn't react with any substances, oxygen reacts with a variety of substances quickly.Which is denser, helium or oxygen?While oxygen has a density of 0.001429 cubic centimeters, helium has a density of 0.0001785. Since helium is lighter than oxygen, it will cause the balloon filled with oxygen to rise higher.Helium is it less dense than oxygen?The helium atoms tend to move more quickly and occupy more space at the same temperature because they are smaller, lighter, and more weakly attracted to one another. In contrast, the mixture of gases that makes up air includes both nitrogen and oxygen.To learn more about periodic table elements visit:
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VOTING BRAINLIEST FOR ANYONE WHO ANSWERS RIGHT!!
PLS HELP
Answer:
B
Explanation:
-1 e so the atomic number should increase so,
B. Np
Planet Force (N) Mass (kg)
A 8.0 0.50
B 30 3.0
C 45 3.0
D 60 6.0
The gravitational force acting on various masses is measured on different planets. Measured values for the forces acting on the corresponding masses are shown in the data table. Analyze the data and develop a method for comparing the gravitational field strengths on the different planets. Use your method to compare the gravitational field strengths, and report your conclusions.
From the analysis, it can be concluded that planet A has the strongest gravitational field, followed by planet C, and planets B and D have the same gravitational field strength.
The gravitational force acting on various masses is measured on different planets. The table shows the measured values for the forces acting on the corresponding masses:Planet Force (N) Mass (kg)A 8.0 0.50B 30 3.0C 45 3.0D 60 6.0
Method for comparing the gravitational field strengths on the different planets:First, we can use the formula for calculating gravitational force: \(`F = G (m_1m_2 / r^2)`\)where G is the universal gravitational constant `\(6.67 * 10^{-11 }Nm^2/kg^2\), m1 and m2 are the masses of the two objects in kg, and r is the distance between the centers of the objects in meters.
We know that the force is proportional to mass (F = ma). So we can calculate the acceleration due to gravity (g) on each planet by dividing the force by the mass. Therefore, we can use the formula: `g = F / m`.
Comparing the gravitational field strengths on the different planets:We will calculate the acceleration due to gravity (g) on each planet.
For planet A: `
g = F / m
= 8.0 N / 0.50 kg
= 16 \(m/s^2\)`
For planet B: `g = F / m
= 30 N / 3.0 kg
= 10 \(m/s^2\)
For planet C: `g = F / m
= 45 N / 3.0 kg
= 15 \(m/s^2\)
For planet D: `g = F / m
= 60 N / 6.0 kg
= 10 \(m/s^2\)
`So we see that planet A has the strongest gravitational field, followed by planet C, then planet B and planet D have the same gravitational field strength.
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Which is the correct quark pairing?
A. top with down, up with bottom, strange with charm
B. top with bottom, up with down, strange with charm
C. top with strange, down with bottom, charm with up
D. charm with down, top with up, strange with bottom
Answer:B make sure it’s the same order
Explanation:
Correct on Plato
a boy whose mass is 40kg runs up a flight of 30 step each 150 mm in 60 second find the averse power develop expansion explain the anomalous of two of water
The average power developed by the boy during the climb is approximately 29.4 W.
What is power?In physics, the amount of energy transferred or converted per unit time is called power.
total height = number of steps x height of each step
total height = 30 x 0.15 m = 4.5 m
Given, time = 60 s
As power = work done / time
work done = force x distance
force = mass x gravity
mass is boy's mass (40 kg) and gravity is acceleration due to gravity (9.81 m/s²).
force = 40 kg x 9.81 m/s² = 392.4 N
The distance that the boy moves is equal to the total height that he has climbed: distance = total height = 4.5 m
work done = force x distance
work done = 392.4 N x 4.5 m = 1765.8 J
power = work done / time
power = 1765.8 J / 60 s
power ≈ 29.4 W
Therefore, the average power developed by the boy during the climb is approximately 29.4 W.
As for the anomalous behavior of water, water has a higher boiling point and melting point as compared to other substances with similar molecular weight. This is due to the strong hydrogen bonding between water molecules, which requires more energy to break the bonds and change the state of water from solid to liquid to gas.
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Which of the following graphs have the same wavelengths?
At what point on the position-time graph shown is the object's instantaneous velocity smallest?
A
D
C
B
anyone have the answers lol ????
Answer:
I do have the answer
Explanation:
What wavelength photon would have the same energy as a 145-gram baseball moving 30.2 m/s ?
Answer:
Approximately \(3.01 \times 10^{-27}\; {\rm m}\) (when measured in a vacuum.)
Explanation:
Apply unit conversion and ensure that the mass of the baseball is in standard units (kilograms):
\(m = 145\; {\rm g} = 0.145\; {\rm kg}\).
The kinetic energy of the baseball will be:
\(\displaystyle E = \frac{1}{2}\, m\, v^{2}\),
Where \(v = 30.2\; {\rm m\cdot s^{-1}}\) is the speed of the baseball.
\(\begin{aligned}E &= \frac{1}{2}\, m\, v^{2} \\ &= \frac{1}{2}\, (0.145)\, (30.2)^{2}\; {\rm J} \\ &= 66.12290\; {\rm J}\end{aligned}\).
The energy of a photon of frequency \(f\) is:
\(E = h\, f\),
Where \(h \approx 6.62607 \times 10^{-34}\; {\rm m^{2}\cdot kg \cdot s^{-1}}\) is Planck's constant.
When measured in a vacuum where speed of light is \(c \approx 3.00 \times 10^{8}\; {\rm m\cdot s^{-1}}\), the wavelength \(\lambda\) of this photon will be:
\(\displaystyle \lambda = \frac{c}{f}\).
\(\displaystyle f = \frac{c}{\lambda}\).
Hence, the expression for the energy of this photon can be rewritten as:
\(\displaystyle E = h\, f = \frac{h\, c}{\lambda}\).
Rearrange this equation to find \(\lambda\):
\(\displaystyle \lambda &= \frac{h\, c}{E}\).
Assuming that the energy of this photon to be equal to the kinetic energy of that baseball, \(66.12290\; {\rm J}\):
\(\begin{aligned}\lambda &= \frac{h\, c}{E} \\ &\approx \frac{(6.62607\times 10^{-34})\, (3.00 \times 10^{8})}{(66.12290)}\; {\rm m} \\ &\approx 3.01 \times 10^{-27}\; {\rm m}\end{aligned}\).
Calculate the acceleration of the car in stage A if it has a mass of 1200kg
stage A: 3000N
Answer:
2.5 m/s²
Explanation:
F = ma (Newton's 2nd Law)
a = F/m = 3,000 N / 1,200 kg = 2.5 m/s²
When work is done by a system, does the internal energy of the system increase or decrease?
Decrease
Explanation:The mathematical relationship between heat, internal energy and work done by the system is given as:
△U = Q + W
where △U is the change in the internal energy
W is the workdone by the system
Q is the heat energy in the system
Since the workdone by the system is negative, when a system does work, there is a depletion in the amount of energy possessed by the system.
Due to this loss of energy by the system as a result of the workdone, the internal energy decreases.
Part A if we run an ideal Carnot heat engine in reverse, which of the following statements about it must be true? (There may be more than one correct choice A. Heat enters the gas at the cold reservoir and goes out of the gas at the hot reservoir B. The amount of heat transferred at the hot reservoir is equal to the amount of heat transferred at the cold reservoit C. lt is able to perform a net amount of useful work such as pumping water from a well during each cycle D. It can transfer heat from a cold object to a hot object Type alphabetically the letters corresponding to the correct choicet. For instance, if you think that only choices A, B, and C are correct, type ABC
The correct choices are A and B.
A. Heat enters the gas at the cold reservoir and goes out of the gas at the hot reservoir B. The amount of heat transferred at the hot reservoir is equal to the amount of heat transferred at the cold reservoit
When an ideal Carnot heat engine is run in reverse, heat enters the gas at the cold reservoir and goes out of the gas at the hot reservoir (Choice A). This is the opposite of the normal operation of a Carnot heat engine, where heat enters at the hot reservoir and goes out at the cold reservoir.
In a reversible process, the amount of heat transferred at the hot reservoir is equal to the amount of heat transferred at the cold reservoir (Choice B). This is a fundamental principle of thermodynamics known as the conservation of energy. In a reversible cycle, the heat transfer is reversible, meaning that the system can be restored to its original state without any net change in energy.
However, the other choices (C and D) are not true for a Carnot heat engine running in reverse. In the reversed operation, it cannot perform a net amount of useful work such as pumping water from a well during each cycle (Choice C). This is because the work input required to reverse the cycle would be greater than the work output obtained.
Similarly, it cannot transfer heat from a cold object to a hot object (Choice D). The reversed operation of a Carnot heat engine is not capable of violating the second law of thermodynamics, which states that heat cannot spontaneously flow from a colder object to a hotter object.
In summary, when an ideal Carnot heat engine is run in reverse, it follows the principles of thermodynamics, with heat entering at the cold reservoir and going out at the hot reservoir. The amount of heat transferred at both reservoirs is equal, but it cannot perform a net amount of useful work or transfer heat from a cold object to a hot object.
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Iron ball sinks in water but not in mercury. Why?
Answer:
mercury is more dense
Explanation:
Explanation:
Iron ball sinks in water but not in mercury because of the difference in the density iron used in iron ball. The iron ball has more density than water and less than the mercury.
Hence, Iron ball sinks in water but not in mercury.
-TheUnknownScientist
It is 5.00 km from your home to the physics lab. As part of your physical fitness program, you could run that distance at 10.0 km/hr (which uses up energy at the rate of 700 W ), or you could walk it leisurely at 3.00 km/hr (which uses energy at 290 W ).A. Which choice would burn up more energy? 1. running.2. walking.B. How much energy (in joules) would it burn?C. Why is it that the more intense exercise actually burns up less energy than the less intense one?
Answer:
a. Walking burns up more energy.
b. 1740 kJ
c. This is because more intense exercise releases a lot of energy in a short period of time, whereas, less intense energy releases it energy gradually over a long period of time.
Explanation:
a. We know energy W = Pt where P = power and t = time.
Now for walking, t = d/v where d = distance = 5.00 km and v = speed = 3.00 km/hr and P = 290 W
So, t = d/v = 5.00 km/3.00 km/hr = 5/3 hr = 5/3 × 3600 s = 6000 s
W = Pt = 290 W × 6000 s = 1740000 = 1740 kJ
Now for running, t = d/v where d = distance = 5.00 km and v = speed = 10.00 km/hr
So, t = d/v = 5.00 km/10.00 km/hr = 0.5 hr = 0.5 × 3600 s = 1800 s and P = 700 W
W = Pt = 700 W × 1800 s = 1260000 = 1260 kJ
Since walking burns up 1740 kJ and running burns up 1260 kJ, walking burns up more energy.
b. It burns up 1740 kJ
c. This is because more intense exercise releases a lot of energy in a short period of time, whereas, less intense energy releases it energy gradually over a long period of time.