A block hangs at rest from the ceiling by a piece of rope. Consider the forces acting on the block.

A block hangs from the ceiling by a spring. Consider the forces acting on the block when it is as rest.

A ball is shot into the air with a spring-loaded cannon. Consider the forces acting on the ball while it is in the air.
A skydiver ( who hasn’t opened his parachute yet) falls at terminal velocity. Consider the forces acting on the skydiver)

Force Present or Absent?
-Gravity
-Spring
-Tension
-Normal
-Friction
-Air Resistance

The initial volume of the liquid is 31.4 cm³. The volume coefficient of thermal expansion of the liquid is 0.002 per degree Celsius. A temperature increase of 109.5°C is needed for the liquid to rise to a height of 49cm.

The initial volume of the liquid can be found using the formula for the volume of a cylinder:

V = πr²h

where r is the radius (half the diameter), h is the height, and π is approximately 3.14. Plugging in the given values, we get:

V = π(0.5 cm)²(40 cm)

V = 31.4 cm³

The volume coefficient of thermal expansion (β) is defined as the fractional change in volume per degree Celsius change in temperature. It can be calculated using the formula:

β = ΔV/(VΔT)

where ΔV is the change in volume, V is the initial volume, and ΔT is the change in temperature. We can rearrange this formula to solve for ΔV:

ΔV = βVΔT

We know that ΔT = -10°C (a decrease of 10°C) and that the height decreased from 40cm to 37cm, or by 3cm. The change in volume can be found using the formula for the volume of a cylinder again, with the new height of 37cm:

ΔV = π(0.5 cm)²(40 cm - 37 cm)

ΔV = 0.59 cm³

Plugging in all the values, we get:

0.59 cm³ = β(31.4 cm³)(-10°C)

β = 0.002

To find the change in temperature needed for the liquid to rise to a height of 49cm, we can use the same formula as before, but solve for ΔT:

ΔT = ΔV/(βV)

We know that ΔV is the difference between the initial volume and the volume at the new height, which is:

ΔV = π(0.5 cm)²(49 cm - 40 cm)

ΔV = 6.86 cm³

Plugging in all the values, we get:

ΔT = 6.86 cm³/(0.002)(31.4 cm³)

ΔT = 109.5°C

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The energy that it needs to reach the maximum speed is 7583.4 Cal

In Physics, we know that the work done is the product of the force and the distance moved. However, work can be converted to energy since the both have the same dimensions. We define energy in physics as the ability or the capacity to do work.

Given these information, we know that the work done in moving the cheetah as it accelerates from the bottom to the top of the mountain is equal to the kinetic energy of the cheetah thus we can write;

W = KE = 1/2 mv^2

W= 0.5 * 62.0-kg * ( 32.0 m/s)^2

W = 31744 J

Given that;

1 calories = 4.186 J

x calories = 31744 J

x = 7583.4 Cal

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If a planet has an orbital eccentricity equal to 0.70, then its orbit is

Eccentricity is a measure of how squashed an ellipse is compared to a perfect circle.

The value of eccentricity ranges from 0 to 1, where 0 represents a perfect circle and 1 represents a parabolic orbit (which is not a closed orbit).

An eccentricity of 0.70 indicates that the planet's orbit is significantly elongated and not close to a perfect circle.

Therefore, the correct answer is - A very elongated ellipse.

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Venus has days that are longer than a day or. Venus takes longer to complete one rotation of its axis than it does to complete an orbit around the Sun. Earth days are needed for one orbit around the Sun.

Because Venus rotates in the opposite way from Earth and the majority of other planets, it is peculiar. Additionally, it rotates rather slowly. About 243 days to assess for the Earth to make one complete revolution.

The majority of astronomers believe that life could not possibly exist on Venus. Venus is an extremely unfriendly environment right now. The surface of this very dry planet shows no signs of water, and its environment is so dense that lead may melt on it.

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The force experienced by an object is 144.76 N.

O\ption B is correct.

A force is described as an influence that can change the motion of an object or that can cause an object with mass to change its velocity

The force can be calculated using the equation of force = change in momentum / time.

So, force = 1.52 kg·m/s / 0.0105 s = 145 N

Therefore, the answer is 144.76 N.

Some types of force available includes the following:

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Answer:

As a substance reaches the melting point, the particles begin to move faster, causing the substance to become a liquid.

Explanation:

lmk if you need a different or more detailed answer :)

have a wonderous day <3

The movement of particles  in solid substance increases at the melting point.

A liquid's melting point is the temperature at which it transforms from a solid to a liquid under atmospheric pressure. This is the location where the liquid and solid phases are equally present. The substance's melting point varies with pressure as well and is reported at standard pressure.

In solid, the particles are closely packed to each other and there is no movement of particles.

According to the question, when the solid substance is heated the space between molecules increases with increase in temperature because intermolecular forces between the solid particles gets weak with increase in temperature.

When the space between molecules increases degree of randomness of particles also increases and kinetic energy of particles also increases with degree of randomness.

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The spring constant, k will be 18 N/m.The ratio of force to one unit of displaced length is known as the spring constant.

Spring constant is defined as the ratio of force per unit displaced length.

Given data;

Mass of  block,m=0.250 k

Amplitude,A = 0.125 m

Velocity,V=3.00 m/

Spring constant,K=?

The formula for the spring constant when the spring is oscillate at the given amplitude A:

\(\rm K = \frac{V_{max}^2 m}{A} \\\\ K = \frac{3.0 \times 0.250}{0.125} \\\\ K=18 \ N/m\)

Hence, the spring constant, k will be 18 N/m

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Answer:

Star Y is showing radial motion

Star Y is moving toward the Earth

Explanation:

Just answered this question on a quiz and got it right.

Star Y is showing radial motion

Star Y is moving towards earth.

Spectrum is defined as the arrangement of radiations emitted by atoms or molecules based on their characteristic wavelength and frequency.

Here,

The spectrum of the star Y is given and is compared to a reference hydrogen spectrum. The range of wavelengths of the star is given. The spectrum of the star shows that the wavelengths are shifted such that from longer wavelengths to shorter wavelength. This phenomenon of shift in wavelengths from higher to lower is known as blue shift. The star shows blue shift that means shifted to shorter wavelength or it can be said as shifted from lower frequency to higher frequency. As a result, it can be concluded that the star Y is moving towards the earth which implies Star Y is showing radial motion.

Hence,

The star Y is showing radial motion.

Star Y is moving towards the earth.

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The lift required for the pilot to complete the loop is provided by the net force, which has a negative magnitude and is acting in the opposite direction of the centripetal force.

f_grav = m * g

f_grav = 75.2 kg * 9.8 m/s^2 = 736.36 N

f_norm = -f_grav

f_norm = -736.36 N

The centripetal force acting on the pilot can be calculated using the equation:

f_cent = m * v^2 / r

f_cent = 75.2 kg * 63.1 m/s^2 / 96 m = 607.71 N

f_net = f_norm + f_cent = -736.36 N + 607.71 N = -128.65 N

So, the numerical values are:

f_norm = -736.36 N

a = 9.8 m/s^2

f_grav = 736.36 N

f_net = -128.65 N

Whether a roller coaster moves uphill, downhill, or in a loop, gravity exerts a constant downward force on the vehicle and its passengers. The centripetal force required to maintain the cars on the arching course as they pass through the loop is provided by the solid steel tracks in conjunction with gravity.

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The lift required for the pilot to complete the loop is provided by the net force, which has a negative magnitude and is acting in the opposite direction of the centripetal force.

Whether a roller coaster moves uphill, downhill, or in a loop, gravity exerts a constant downward force on the vehicle and its passengers. The centripetal force required to maintain the cars on the arching course as they pass through the loop is provided by the solid steel tracks in conjunction with gravity.

\(f_{grav} = m times g \\f_grav = 75.2 kg \times 9.8 m/s^2 = 736.36 N\\f_{norm} = -f_{grav}\\f_{norm} = -736.36 N\)

The centripetal force acting on the pilot can be calculated using the equation:

\(f_{cent} = m \times v^2 / r\\f_{cent} = 75.2 kg \times 63.1 m/s^2 / 96 m = 607.71 N\\f_{net} = f_{norm} + f_{cent} = -736.36 N + 607.71 N = -128.65 N\)

So, the numerical values are:

\(f_{norm} = -736.36 N\\a = 9.8 m/s^2\\f_{grav} = 736.36 N\\f_{net} = -128.65 N\)

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It will take approximately 8 years for a radioactive substance of mass 800g to have 8g undecayed.

The half-life of the radioactive substance in question is 4 years. The half-life of a radioactive substance is the amount of time it takes for half of the original amount of the substance to decay. In this case, after 4 years, half of the initial 800g of the radioactive substance will have decayed, leaving 400g remaining. This means that the decay rate of the radioactive substance is 50% per 4 years. The half-life is a constant for a specific radioactive substance and it does not change, this means that if we wait another 4 years, half of the remaining 400g will decay leaving only 200g, and so on.

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The intensity increases by a factor of 16.

option D.

According to the inverse-square law of sound propagation, the intensity of a sound wave decreases proportionally to the square of the distance from the source.

I ∝ 1/r²

where;

when distance from the source is reduced by a factor of 4, the intensity of the sound wave becomes;

I ∝ 1/4²

I ∝ 1/16

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Answer:

\(\displaystyle \sqrt{\frac{(5/2)\, (g - a)\, m\, R^{2}}{M^{2}\, a}}\), assuming that the tension in the rope is the only tangential force on the sphere (\(g\) denote the gravitational acceleration.)

Explanation:

The forces on the bucket are:

Since the weight of the bucket and the tension from the rope are in opposite directions, the magnitude of the net force would be:

\(\begin{aligned} \|\text{Net Force}\| =\; & \|\text{Weight}\| - \|\text{Tension}\| \end{aligned}\).

The upward tension in the rope prevents the bucket from accelerating at \(g\) (free fall.) Rather, the bucket is accelerating at an acceleration of only \(a\). The net force on the bucket would be thus \(m\, a\).

Rearrange the equation for the net force on the bucket to find the magnitude of the tension in the rope would be:

\(\begin{aligned} & \|\text{Tension}\| \\ =\; & \|\text{Weight}\| - \|\text{Net Force}\| \\ =\; & m\, g - m\, a \\ =\; & (g - a)\, m\end{aligned}\).

At a distance of \(R\) from the center of the sphere, the tension in the rope \((g - a)\, m\) would exert a torque of \((g - a)\, m\, R\) on the sphere. If this tension is the only tangential force on this sphere, the net torque on the sphere would be \((g - a)\, m\, R\!\).

Let \(M\) denote the mass of this sphere. The moment of inertia of this filled sphere would be \(I = (2/5)\, M^{2}\).

Therefore, the magnitude of the angular acceleration of this sphere would be:

\(\begin{aligned}& \|\text{Angular Acceleration}\| \\ =\; & \frac{\|\text{Net Torque}\|}{(\text{Moment of Inertia})} \\ =\; & \frac{(g - a)\, m\, R}{(2/5)\, M^{2}} \end{aligned}\).

The bucket is accelerating at a magnutide of \(a\) downwards. The rope around the sphere need to unroll at an acceleration of the same magnitude, \(a\!\). The tangential acceleration of the sphere at the surface would also need to be \(\! a\).

Since the surface of the sphere is at a distance of \(R\) from the center, the angular acceleration of this sphere would be \((a / R)\).

Hence the equation:

\(\begin{aligned}& \frac{(g - a)\, m\, R^{2}}{(2/5)\, M^{2}} = \|\text{Angular Acceleration}\| = \frac{a}{R} \end{aligned}\).

Solve this equation for \(M\), the mass of this sphere:

\(\begin{aligned}& \frac{(g - a)\, m\, R^{2}}{(2/5)\, M^{2}} = \frac{a}{R} \end{aligned}\).

\(\begin{aligned}M^{2} &= \frac{(g - a)\, m\, R^{2}}{(2/5)\, a} \\ &= \frac{(5/2)\, (g - a)\, m\, R^{2}}{a}\end{aligned}\).

\(\begin{aligned}M&= \sqrt{\frac{(5/2)\, (g - a)\, m\, R^{2}}{a}}\end{aligned}\).

Answer:

22 s

Explanation:

time = distance / velocity

We know that distance = 770 m and velocity = 35 m/s.

t = d / v

t = 770 m / 35 m/s

t = 22 s

It takes 22 seconds to cover 770 m. Hope this helps, thank you !!

Answer:

Explanation:

Part A:

Using the formula for electric potential due to a charged spherical shell:

V1 = kq1/R1 and V2 = kq2/R2

where k is the Coulomb constant.

For r < R1, the electric potential due to both shells is:

V = V1 + V2 = kq1/R1 + kq2/R2

For R1 < r < R2, the electric potential due to the outer shell is:

V = V2 = kq2/R2

For r > R2, the electric potential due to both shells is:

V = V1 + V2 = kq1/r + kq2/R2

Substituting the given values, we get:

V = (9.0x10^9 Nm^2/C^2)(5.00x10^-6 C)/0.025 m + (9.0x10^9 Nm^2/C^2)(-6.00x10^-6 C)/0.15 m

V = -4.32x10^5 V

Therefore, the electric potential due to the two shells at a distance of 2.50 cm from their common center is -4.32x10^5 V.

Part B:

For r < R1, the electric potential due to both shells is:

V = V1 + V2 = kq1/R1 + kq2/R2

For R1 < r < R2, the electric potential due to both shells is:

V = V1 + V2 = kq1/r + kq2/R2

For r > R2, the electric potential due to both shells is:

V = V1 + V2 = kq1/r + kq2/r

Substituting the given values, we get:

V = (9.0x10^9 Nm^2/C^2)(5.00x10^-6 C)/0.1 m + (9.0x10^9 Nm^2/C^2)(-6.00x10^-6 C)/0.1 m

V = 4.80x10^5 V

Therefore, the electric potential due to the two shells at a distance of 10.0 cm from their common center is 4.80x10^5 V.

Answer:

The speed each person travels and the distance they travel depends on their mass, friction of the scooter, etc. How would the distance moved by the scooter boards compare if one person had a lot more mass than the other person? The person with less mass would move away faster and would likely move a greater distance.

Explanation:

The lower the level of resistivity the more electrical conductivity a metal has. Copper has low resistivity, and therefore is an excellent conductor. Copper is also less oxidative than other metals

Answer:

6 hours because 6×5=30 so 6 hours is the right answer

Answer:

B

Explanation:

Answer:

C. 2666W

Explanation:

m =200kg

h =20m

t =15s

g =10ms^-2

p = mgt/t

=200×20×10/15

=40,000/15

=2666.6

≈2666W

Answer:

newton's first law of motion was developed by English scientist Isaac Newton around 1700. Newton was one of the greatest scientists of all time. He developed three laws of motion and the law of gravity, among many other contributions.

Explanation:

Answer:

The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.

Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:

Free Fall Velocity Graph

Answer:

what are the choices

Explanation:

don't worry i'll edit it

9.8 N is the magnitude of the force that maintains circular motion acting on the puck.

32.53 m/sec is the linear speed of the puck.

The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. An item does not have a force inside of it or within it. Another item applies a force to another. The concept of a force is not restricted to living or non-living entities. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

As we know, from free body diagram, when the system is in equillibrium, the force acting on the puck on the table is as follows:

When the air puck of mass is revolving round the circle, then the tension (T) in the top string and the bottom of the string is same.

F = T

F = 9.8 N

Now, calculate the velocity of the puck:

From the given data, the air puck moves in a circular path. Hence, the tension in the top string is equal to the centripetal force acting on the puck.

Thus, the expression for the tension in the top string is as follows:

T = mv² / R

The velocity of the puck is as follows:

Mg = mv² / R

v² = MgR / m

v² = (2.7 × 9.8 × 1.2 ) / 0.030

v² = 1058.4

v = \(\sqrt{1058.4}\)

v = 32.53 m/sec

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Answer:

3, 5, and 6, that should be the answer

Answer: It rotates a coil of wire through a magnetic field. ... When either of them is moving there will be a change in the magnetic field in the coil and the changing magnetic field is what induces and electric current in the wire.

Explanation:hope this helps

Answer: The Company has spent $5 million in research and development over the past 12 months developing cutting-edge battery technology which will be incorporated ...

Explanation: uhmmmmmm i dont know this one but it is pretty ez

The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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