Answers
Answer:
(A)
Explanation:
30 J
Related Questions
state the two motion equations.
Answers
Answer:
Equations of motion relate the displacement of an object with its velocity, acceleration and time. s=vt where s is the displacement, v the (constant) speed and t the time over which the motion occurred. ...
Displacement with negative acceleration: s, equals, v, t, minus, one half, a, t, square...
Displacement with positive acceleration: s, equals, u, t, plus, one half, a, t, squared,s...
Velocity squared: v, squared, equals, u, squared, plus, 2, a, s,v2=u2+2as
Velocity: v, equals, u, plus, a, t,v=u+at
4. 9.222 m/s5. 5.523 m/s27. Answer: Dv²=85.04v² = 9.2217=19.22228.) Under the influence of some forces, the speedof a 21.325 kg object changed from 6 m/s to a certain speed.If the net work done on the object is 1450 J.Calculate its final speed.1. 13.115 m/s2. 15.634 m/s19.322 m/s4. 7.263 m/s3.5. 21.714 m/s29. Answer: A
Answers
By the work energy theorem we know that the net work done on an object is equal to its change in kinetic energy, that is:
\(W=\Delta K\)where
\(K=\frac{1}{2}mv^2\)Then, the work energy theorem can be express as:
\(W=\frac{1}{2}mv_f^2-\frac{1}{2}mv_0^2\)In this case we know that the work done is 1450 J, that the mass is 21.325 kg and the initial velocity is 6 m/s; plugging these values and solving for the final velocity we have:
\(\begin{gathered} \frac{1}{2}(21.325)v_f^2-\frac{1}{2}(21.325)(6)^2=1450 \\ \frac{1}{2}(21.325)v_f^2=1450+\frac{1}{2}(21.325)(6)^2 \\ v_f^2=\frac{2}{21.325}(1450+\frac{1}{2}(21.325)(6)^2) \\ v_f=\sqrt{\frac{2}{21.325}(1450+\frac{1}{2}(21.325)(6)^2)} \\ v_f=13.115 \end{gathered}\)Therefore, the final velocity is 13.115 m/s and the correct option is A.
why do astronauts weigh less on the moon than on earth
Answers
Answer:
Explanation: The moon of the Earth is much lighter in mass than the planet itself. In addition to being smaller than Earth, the Moon is also only approximately 60% as dense. A human weighs less on the Moon because there is less gravitational attraction there than there is on Earth.
Moon has lesser mass as conpared to earth, therefore gravitational force exerted by moon on any object is lesser than that of gravitational force exerted by earth on the same object, hence we can say that astronauts weight less on moon, i.e approximately 1/6 th of their weight on earth.
 A wooden box with a mass of 10.0 kg rest on a ramp that is incline at an angle of 25° to the horizontal. A rope attached to the box runs parallel to the ramp and then passes over a frictionless bully. A bucket with a mass of M hangs at the end of the rope. The coefficient of static friction between the ramp in the box is 0.50. The coefficient of Connecticut friction between the ramp in the box is 0.35.
Suppose the box remains at rest relative to the ramp. What is the maximum magnitude of the friction force exerted on the box by the ramp?
Answers
The maximum magnitude of the friction force exerted on the box by the ramp is 44.41 N.
The given parameters;
Mass of the box, m = 10 kgInclination of the ramp, θ = 25⁰Coefficient of static friction, μ = 0.5 Coefficient of kinetic friction, μk = 0.35The normal force on the wooden box is calculated as follows;
\(F_n = mg \times cos(\theta)\\\\F_n = 10 \times 9.8 \times cos(25)\\\\F_n = 88.8 2 \ N\)
The maximum magnitude of the friction force exerted on the box by the ramp is calculated as follows;
\(F_f = \mu \times F_n\\\\F_f = 0.5 \times 88.82 \\\\F_f = 44.41 \ N\)
Learn more about static frictional forces here: https://brainly.com/question/4515354
statics and strength of materials
Answers
The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.
What is the force P?The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;
Take moment about the joint to determine the magnitude of the force along part BC.
120 kN x 750 mm = F x 1000 mm
F = ( 120 kN x 750 mm ) / ( 1000 mm )
F = 90 kN
Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.
Stress in AB = 2 times stress in BC
P/A₁ = 2F/A₂
where;
A₁ is the area of segment ABA₂ is the area of segment BCA₁ = πd²/4 = π(50 x 10⁻³)²/4
A₁ = 1.96 x 10⁻⁵ m²
A₂ = πd²/4 = π(75 x 10⁻³)²/4
A₂ = 4.42 x 10⁻³ m²
P/A₁ = 2F/A₂
P = (2F x A₁) / (A₂)
P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = 798.2 N
P = 0.798 kN
P ≈ 0.8 kN
Learn more about stress-forces here: https://brainly.com/question/929277
#SPJ1
How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food
A. The amount of oxygen in the atmosphere increased
B. Mass extinctions occurred
C. The oceans became larger
D. Rainfall increased
Answers
What is amplitude and phase in electrical and electronics circuit?
Answers
In electrical and electronics circuits, amplitude is the maximum value of a signal. This is known as the strength or intensity of the signal. Phase, can be seen as the timing relationship between two signals or waveforms. It tell the time it takes betwen the peaks or zero crossings of two waveforms
What more should you know about phase in electrical and electronics circuits?In electrical and electronics circuits, phase tell us about the the relationship between currents in different parts of the circuit, For example in AC circuits with multiple components.
We the amplitude and phase of signals in electrical and electronics circuits is understood, it becomes easier to design and analyz circuits, and can even be used for troubleshooting and maintaining them.
Learn more about amplitude ;
https://brainly.com/question/15930409
#SPJ1
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
Answers
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
For more questions on energy
https://brainly.com/question/30403434
#SPJ8
4. Two people each have a mass of 55 kg. They are both in an
elevator that has a mass of 240 kg. When the elevator
begins to move, the people and the elevator have an upward
acceleration of 1.00 m/s2. What is the net force that acts on
the elevator as it accelerates upward at 1.00 m/s2?
Answers
Answer:
350 N
Explanation:
F=ma
\(f = force \\ m = mass \\ a = acceleration\)
\(m = 2(55kg) + 240kg \\ a = 1.0 \frac{m}{ {s}^{2} } \)
Force = 350 Newtons
The net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2.
What is Newton's second law?
Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The mathematical expression for Newton's second law is as follows
F = ma
As given in the problem two people each have a mass of 55 kg. They are both in an elevator that has a mass of 240 kg. When the elevator begins to move, the people and the elevator have an upward acceleration of 1.00 m/s2, then we have to find the net force acting on the elevator,
The net force acting on the elevator,
F = ma
F =(2×55 + 240)×1
= 350 Newtons
Thus, the net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2
Learn more about Newton's second law, here
brainly.com/question/13447525
#SPJ6
Olivia is rolling down a hill on a skateboard and is accelerating at 2.4 m/s2. After 3 seconds, she runs into Reid at the bottom of the hill. If her initial velocity was 1.5 m/s, what was her velocity when she hit Reid?
Answers
did you ever get the answer?
Answer:
8.7
Explanation:
A=2.4m/s2 1.5m/s + (2.4m/s2)(3s)
Vi=1.5m/s 1.5m/s + 7.2
Vf=? Vf= 8.7m/s
T=3s
If an object accelerates at a rate of 3 m/s2, it will exert a force of 15 N. How much force will the same object exert if it accelerates at a rate of 7 m/s2 ?
If someone can answer this question they will get 100 points.
And not this: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Answers
Answer:
\(F=ma \\ m = \frac{F}{a} = \frac{15}{3} = 5kg \\ F = 5 \times 7 = 35N\)
Answer:35N
Explanation:If it goes 3 m/s 2 and the N is 15 and 3x5=15 then 7x5=35
Describe the best way to identify the constellation Cassiopeia.
Please hurry!
I am giving Brainlyist
And to points
Answers
Answer:
look for the "W" in the North. Remember that, the "W" may be on its side or inverted to form an "M." If you can recognize the Big Dipper (Ursa Major), the two stars at the edge of the Dipper point toward the North Star (Polaris)
Explanation:
A boy drops a rock into a well and times how long it takes for him to hear it strike the water below. If the rock takes 2.1 seconds to hit the water, how deep is the well?
Answers
Answer:
kkikkiioomooonnioonnoooo
Distinguish between elastic collasin
and inelastic collasin
Answers
Explanation:
In an elastic collision, two or more bodies are in contact with one another and there is no net loss of kinetic energy in the system. By the virtue of this, the bodies and objects do not stick together after they collide.
Both momentum and kinetic energy are conserved in an elastic collision. An example is when a football hits a wall.
For an inelastic collision, the bodies sticks together after they collide and there is a loss of kinetic energy after they collide. An example of this type of collision is when a gum is throw against a wall.
A 700N marine in basic training climbs a 10m vertical rope at constant speed in 8sec. what is power put
Answers
Answer:
875 Watts
Explanation:
P = W/t = mgh/t = 700(10)/8 = 875 Watts
Estimate the distance (in cm) between the central bright region and the third dark fringe on a screen 5.00 m from two double slits 0.500 mm apart illuminated by 500-nm light.
Answers
Answer:
1.25cm
Explanation:
Using
Minimum, as dsinစ = (m+1/2) lambda
Third dark fringe m= 2
dsinစ = (2+1/2)lambda
d(y/L)= (5/2) lambda
Y= 5/2* lambda *L/d
So substituting
=[ (500E-9m)(5m)/0.5E-3] 5/2
=0.0125m
= 1.25cm
Explanation:
Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF
Answers
The mass of Car B is -6000 kg.
To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
Therefore, we can write the equation for the conservation of momentum as:
(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision
Let's substitute the given values into the equation:
(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)
Simplifying the equation:
20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)
Dividing both sides by -5 m/s:
-4000 kg = 2000 kg + mass of Car B
Subtracting 2000 kg from both sides:
mass of Car B = -4000 kg - 2000 kg
mass of Car B = -6000 kg
know more about momentum here:
https://brainly.com/question/30487676
#SPJ8
2 What distance will a sprinter travel in 4.0 s if his or her
acceleration is 2.5 m/s²? Assume the sprinter starts
from rest.
A 13 m
B 20 m
C 80 m
D 90 m
Answers
The distance travelled by sprinter in 4 sec is 20 m
It is given that
acceleration of sprinter = 2.5 m/s²
time taken by sprinter = 4.0 s
initial speed of sprinter = 0 m/s
We have to find distance travelled by sprinter
We will use the following equation of motion
S = ut + 1/2at^2
S = 1/2at^2
S = 1/2 x 2.5 x (4)^2
S = 1/2 x 2.5 x 16
S = 20 m
Hence, distance travelled by sprinter in 4 sec is 20 m
Learn more about Distance here:
https://brainly.com/question/26046491
#SPJ1
In which soil layer do plant seeds germinate and plant roots thrive?
subsoil
organic
bedrock
topsoil
Answers
Answer: Topsoil
Explanation:
Bio
Answer:
topsoil
Explanation:
A particle changed q= 3,10x10^-6 C stays still on point P, a second particle with the same value q and a mass of 1,80x10^-2 kg is initially in repose at a distance of r1 = 9,00 cm from point P. This is second particle is released and repelled by the first. Determine the velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P.
note 1: from what i know i have to use the potential energy formula (U= mV^2/2), and possible calculate the electric force ? but from there i get lost
note 2: sorry if this isn't grammatically correct, i translated it from spanish
Answers
The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is 17.22 m/s.
What is the electric force between the two particles?The electric force between the two particles is calculated from Coulomb's law of electrostatic force.
F = kq₁q₂/r²
where;
k is Coulomb's constantq₁ is magnitude of first chargeq₂ is magnitude of second charger is the distance between the two chargesF = (9 x 10⁹ x 3.10 x 10⁻⁶ x 3.10 x 10⁻⁶) / (0.09 m)²
F = 10.68 N
The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is calculated by applying the principle of conservation of energy.
W = ΔK.E
where;
W is work doneΔK.E is kinetic energy of the particleFr = ¹/₂mv²
2Fr = mv²
v² = 2Fr/m
v = √(2Fr/m)
v = √(2 x 10.68 x 0.25 / 1.8 x 10⁻²)
v = 17.22 m/s
Learn more about electric force here: https://brainly.com/question/17692887
#SPJ1
what is a water resavore.......................................
Answers
Answer: A Water resavoir is a place where they hold water until needed. Like let's say there was a drought in Arizona, the state would rely on the resavoir's until the drought is gone. I hope I explained it well.
In hiking, what fitness component is required of you
Answers
which state can you infer that average home prices are the highest? Florida California Texas New York
Answers
Answer:
California
Explanation:
just took the test
The state you can infer where average home prices are the highest is California. Option B. This is further explained below.
What is an average home price?Generally, an average home price refers to a cumulative average to the house or home pricing in a state.
In conclusion, California has the highest average home prices highest in America.
Read more about House
https://brainly.com/question/1023637
#SPJ2
Three capacitors (4.7, 6.5, and 15.5 F) are connected in series across a 50.0-V battery. Find the voltage across the 4.7-F capacitor
Answers
Answer: 50 V
Explanation:
Given
Three capacitors are connected in parallel across 50 V battery
When capacitor are connected in parallel, net capacitance is the sum of all the values
Net capacitance
\(\Rightarrow C=4.7+6.5+15.5\\\Rightarrow C=26.7\ F\)
Voltage in parallel circuit is same across each capacitor. Therefore, voltage across 4.7 F capacitor is 50 V
An organ pipe of length L has one end closed but the other end open. What is the wavelength of the fundamental node emitted?
a. Slightly smaller than 4 L
b. Slightly larger than 4 L c. Roughly equal to 3/2
d. Slightly larger than 2 L
Answers
Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores
Explanation:
The answer is 50 i.e. C
Answers
Answer:
Explanation:
If the potentiometer is assumed to be linear
Then one one quarter of the total resistance will be below the slider and three quarters of the resistance will be above the slider.
To get zero voltage reading, 150 must be 3/4 of the total resistance of the right leg
150 = 0.75(150 + R)
150 = 112.5 + 0.75R
37.5 = 0.75R
R = 50 Ω
TRUE OR FALSE: Increasing the time of impact during a collision increases the force experienced by the object.
Answers
Answer: True
Explanation:
A team of students conducts a series of experiments to investigate collisions. In the first experiment, the two carts collide with each other on a smooth surface. The carts stick together and continue to move forward. In the second experiment, the two carts collide with each other on a rough surface. The carts stick together and quickly come to rest. In both experiments, the initial speeds of the carts are identical. Is there a difference in the total energy of the two experiments?
A.
No, because the kinetic energy of the two-cart system after the collision is the same in both the experiments.
B.
No, because the sum of the kinetic energy and thermal energy of the two-cart system after the collision is the same in both experiments.
C.
Yes, because the kinetic energy of the two-cart system in the second experiment after the collision is less than that of the first experiment.
D.
Yes, because the sum of the kinetic energy and thermal energy of the two cart system in the second experiment after the collision is less than that of the first experiment.
Answers
If a team of students conducts a series of experiments to investigate collisions. C. Yes, because the kinetic energy of the two-cart system in the second experiment after the collision is less than that of the first experiment.
What is difference in the total energy of the two experiments?In the first experiment, the two carts collide on a smooth surface and stick together, so the kinetic energy of the system after the collision is entirely in the form of translational kinetic energy of the combined carts.
In the second experiment, the two carts collide on a rough surface and stick together, so some of the kinetic energy is converted into thermal energy due to friction between the carts and the surface. This means that the kinetic energy of the system after the collision is less than in the first experiment.
Option A is incorrect because the kinetic energy is not necessarily the same in both experiments.
Option B is incorrect because the thermal energy is not necessarily the same in both experiments.
Option D is incorrect because the thermal energy is not considered in the calculation of the total energy of the system after the collision.
Learn more about total energy here:https://brainly.com/question/29581211
#SPJ1
A positive force on the balance indicates a downward force on the silver sphere while a negative force on the balance indicates an upward force on the silver sphere.With that in mind, do the two spheres have like charges or opposite charges? Give your answer as a CER.
Answers
The two spheres have opposite charges.
What are types charge?A charge can be negatively charged or positively charged.When two charges have opposite signs, that is positive and negative signs, the two charges will attract each other.When the two charges have the same sign, it causes repulsion.When a positive charge points downwards ↓ and the negative charge points upwards ↑, this causes attraction and shows that the two charges are different.
Thus, we can conclude that the two spheres have opposite charges.
Learn more about attraction and repulsion of charges here: https://brainly.com/question/2396080
1)What is the pressure at point D in kPa ?
2)Temperature at point D
3)What is the net work done on the gas as it is taken through four cycles?
4)What is the internal energy of the gas when it is at point A?
5)What is the total change in internal energy of this gas during four complete cycles?
Answers
The answer is 1) The pressure at point D is 80 kPa. 2) The temperature at point D is 800 K. 3) The net work done on the gas over four cycles is zero. 4) The internal energy of the gas at point A is 100 J. 5) The total change in internal energy during four complete cycles is zero.
The total change in internal energy of this gas during four complete cycles is zero. The given diagram represents the Carnot cycle involving four stages. The four stages of the Carnot cycle are reversible and follow an ideal gas that is placed in a cylinder with a movable piston.Let's solve each question asked one by one.1) From the graph, it can be observed that the pressure at point D is 0.08 M Pa, which is equal to 80 kPa. Hence, the pressure at point D in kPa is 80 kPa.2) Temperature at point D The isotherm at point D is about 800 K. Hence, the temperature at point D is 800 K.3) The net work done on the gas as it is taken through four cycles is zero because the Carnot cycle is a cycle that has four stages. In each cycle, the net work done is the area enclosed by the cycle. Therefore, for a complete cycle, the net work done is zero because the area enclosed is a loop.4) The internal energy of the gas when it is at point A is 100 J because the internal energy of the gas is directly proportional to the temperature and volume. Here, at point A, the temperature is 500 K, and the volume is 2 m³, so the internal energy of the gas when it is at point A is 100 J.5) The Carnot cycle is a reversible cycle that is used to determine the efficiency of heat engines. It is a closed cycle that does not involve any net energy exchange with the surroundings. Therefore, the total change in internal energy of this gas during four complete cycles is zero since the initial and final states are the same. Hence, the total change in internal energy of this gas during four complete cycles is zero.For more questions on the Carnot cycle, click on:
https://brainly.com/question/25819144
#SPJ8