A blacksmith making a tool heats 525 grams of steel to 1230°C. After hammering the steel, she places it into a bucket of water to cool it. When
she removes the steel from the water, it's at 50°C. How much heat does the steel release if its specific heat capacity is 0.486 Joules/gram degree
Celslus?
A. 301,000 Joules
B. 12,800 Joules
C. 1,270 joules
D. 241 Joules
E. 4.62 joules

The heat energy released here can be determines using calorimetric equation. The heat energy released by the steel is 301077 J. Hence, option A is correct.

Calorimetry is an analytical technique used to determine the heat energy absorbed or released by a system. The calorimetric equation  connecting the heat energy with the mass m, specific heat capacity of the substance c and the temperature difference ΔT is given below:

q = m c  ΔT.

given ,

mass of the steel m = 1230 °C

c for steel = 0.486 J/g °C

ΔT = 1230 - 50 °C = 1180 °C.

Then, the heat energy released by the steel into water is determined as follows:

q = 1180 °C × 525 g × 0.486 J/g °C

  =  301077 J.

Therefore, the heat energy released by the steel is 301077 J.

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