A beam of light travels into a new denser medium causing the speed of light to change to 2.5 x 10 8 m/s. what is the index of refraction for the new medium?

The more  a star has, the shorter its main sequence life. "The mass-luminosity relation, which is used to describe the relationship between a star's mass and its luminosity, tells us that the more massive a star is, the brighter it is.

However, the mass of a star also determines how long it spends on the main sequence. A star spends most of its life in the main sequence, a stage during which it fuses hydrogen in its core to produce helium. The amount of time a star spends on the main sequence is determined by its mass, with more massive stars having shorter lifetimes than less mass stars.

As a result, the more massive a star is, the shorter its main speed life, which means that option D, "the more mass a star has, the shorter its main sequence life," is the correct answer. The other options, "all stars have the same ages," "all stars have equal life spans," and "none of the above," are all incorrect because they do not accurately describe the relationship between a star's mass and its main sequence lifetime.

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The new orbital speed after friction from the earth's upper atmosphere is 8674.15 m/s.

When the work done by a force does not depend on the choice of path, the force is called the conservative force. Some examples are a gravitational force, elastic spring force and electric force. On the other hand, when the work done by a force relies on the choice of the path of the motion, it is called non-conservative force.

The net work done by non-conservative force is W = ΔK + ΔP ----(1)

Given that, work done W = -7.5 * 10⁹ J

Change in kinetic energy = (Kf - Ki)

Final kinetic energy Kf = 1/2* m * Vf²

Initial kinetic energy Ki = 1/2* m * Vi²

Mass of the satellite m = 848 kg

Vf = Final speed

Vi = Initial speed = 9640 m/s

Change in gravitational potential energy ΔP = 0

Substituting the values in (1),

1/2* m (Vf² - Vi²) = W

1/2 * 848( Vf² -9640²) = W

Making Vf as subject,

Vf = √( 2W/m + Vi²)

⇒ √( -2* 7.5 * 10⁹/848 + 9640²)

⇒ 8674.15 m/s

Thus, the final speed decreases due to friction.

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Hey there!

A pulley is a "system" that has a rope attached to carry heavy materials off the ground. Once you pull the rope, the heavy item will be carried.

Hope this helps!

Have a great day!

Answer:

36.5 kJ

Explanation:

Energy by machine = energy to machine × efficiency

E = 52.1 kJ × 0.70

E = 36.5 kJ

The initial acceleration of the mass if it is released and allowed to move is 83.33 m/s².

Given data;Masses = 2 * 1.8 kg = 3.6 kg

Distance between masses = 1.1 mCharge on each mass = +10 μC

Friction is frictionlessWe know that Coulomb's Law states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. That is,F = k q₁ q₂ / r²where k is Coulomb's constant = 9 × 10⁹ N m² C⁻², q₁ and q₂ are the charges in Coulombs, and r is the distance between the two charges in meters.

Let us calculate the force between the two masses.

Since both the masses have same charge, and they are equidistant, force on either of the two masses can be found using this formula.F = k q₁ q₂ / r²F = (9 * 10^9) * (10 * 10^-6)^2 / (1.1/2)^2F = 150 N

So the magnitude of the electric force on one of the masses is 150 N.The initial acceleration of the mass if it is released and allowed to move is given by the formula;

a = F/mwhere F is force, and m is the mass of the object.a = 150 N / 1.8 kg = 83.33 m/s²Thus, the initial acceleration of the mass, if it is released and allowed to move, is 83.33 m/s².

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The work done is 43200 joules.

Work is defined as the distance traveled in the direction of the force in the product of the forces. In physics, work is energy transferred to or from an object by applying a force along a displacement. In its simplest form, work done with a constant force in the direction of motion is equal to the product of the force and the distance traveled. Work is the product of the displacement and the force component in the direction of displacement. When you do work, the kinetic energy of an object changes. In this task the force is given as 180 N to move the car he 240 m.

Work = 180 N x 240 m = 43200 J

In this case, the 1260 kg mass of the car is not needed. 

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Condensed water droplets collect other water droplets to form the collector drop until they fall from the clouds as rain. In this way rain is formed in the tropics where the air is warmer.

A significant volume of water evaporates and is released into the atmosphere when water bodies are heated during the day. Evaporation is the term for this. Water vapour is carried upward by the hot air as it rises. The air cools and expands as it rises. Condensation is the term for this occurrence. Clouds are created as a result of water vapour condensation. With the assistance of the wind, these clouds are transported away, and when they become heavy, they drop to the ground as rain.

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Infection is one of the factors that can inhibit fracture healing.

Infection is one of the factors that can inhibit fracture healing. Other factors that can interfere with the healing process include poor blood supply to the affected area, inadequate immobilization of the fracture, and underlying medical conditions such as diabetes or osteoporosis.

Option preexisting bone density, is incorrect because individuals with higher bone density are typically better able to heal from fractures. Option overlapping bone ends, may hinder fracture healing if it results in a misalignment of the bone, but it is not a major factor that inhibits healing. Option prepuce retraction, is unrelated to fracture healing and is not a factor that inhibits the process.

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--The question is incomplete, answering to the question below--

"which factor inhibits fracture healing?

a. Prepuce retraction

b. Overlapping bone ends

c. Preexisting bone density

d. Infection"

Answer: Answer for current is 6.667 A and resistance is 0.75 ohm

Explanation:

R1 R2 and R3 are in series because you can see its bent and joint.

So that whole branch is 3 ohm.

3 ohm parallel to 1 ohm is 0.75 ohm

Then by Ohm's Law

I= V/R= 5/0.75

= 6.667 A

please mark my answer the brainliest

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Answer:

Current is 6.667 A and resistance is 0.75 ohm

Explanation:

Answer:

The net force is zero because both volleyball players are hitting the ball with same force.

Explanation:

A. The expression for the focal length of the glasses is 1/f = 1/do + 1/di. B. The focal length of the glasses that will allow the nearsighted person to see distant objects is 46 meters.

(a) To find the focal length of the glasses that will allow the nearsighted person to see distant objects clearly, we can use the formula:

1/f = 1/do + 1/di

where f is the focal length, do is the distance of the far point (in meters), and di is the distance of the image formed by the glasses (in meters). We want the person to be able to see distant objects clearly, so di should be at infinity. Therefore, the equation becomes:

1/f = 1/do + 1/infinity

1/f = 1/do

Solving for f, we get:

f = do

Substituting the given value of do, we get:

f = -46 m

However, the focal length should be a positive value, so we take the absolute value of f, which gives:

f = 46 m

(b) Numerically, the focal length of the glasses is 46 meters.

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The complete question goes thus:

A person who is nearsighted has a far point of do-46 m. She wears glasses that are designed to sit d = 2.7 cm rom her eyes Randomized Variables do-4.6 m d-2.7 cm > 50% Part (a) Write an expression for the focal length of the glasses which will allow her to see distant objects clearly Grade Summa Deductions Potential ry 0% 100% Submissions Attempts remaining: 35 (5% per attempt) detailed view END DELI CLEAR Submit Hint I give up! Hints: 200 deduction per hint. Hints remaining: 5 Feedback: 296 deduction per feedback. là 50% Part (b) Numerically, what is the focal length in m?

The distance between the central axis and the first dark fringe in the given single-slit diffraction experiment is approximately 4221.75 mm.

The distance between the central axis and the first dark fringe in a single-slit diffraction experiment can be determined using the formula:

y = (λL) / w

where:

y is the distance between the central axis and the first dark fringe,

λ is the wavelength of light,

L is the distance between the slit and the screen,

and w is the width of the slit.

λ = 573 nm

λ= 573 × 10⁻³m

w = 0.312 mm

w = 0.312 × 10⁻³ m

L = 2.30 m

Now, let's calculate the distance between the central axis and the first dark fringe (y):

y = (λL) / w

y = (573 × 10⁻⁹ m) × (2.30 m) / (0.312 × 10⁻³ m)

y  = 4.22175 m

We need to convert this result to millimeters (mm) since the question asks for the answer in that unit:

y = 4.22175 m × 1000 mm/m

y  ≈ 4221.75 mm

Therefore, the distance between the central axis and the first dark fringe is approximately 4221.75 mm.

In conclusion, the distance between the central axis and the first dark fringe in the given single-slit diffraction experiment is approximately 4221.75 mm.

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The process of the blue giant start includes stellar Formation, main Sequence Phase, expansion and Cooling, helium Fusion, variable Behavior, and supernova.

The stage in the formation of a star just before nuclear reactions ignite. After a massive red giant star ejects its outer layers, its hot inner core is exposed, and it becomes a blue giant star.

During the process of a blue giant star,  once a star consumes all its hydrogen, the core superheats and pushes its surface layers far out into space.

The process of the blue giant start includes;

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Answer: Total distance = 4π meters and the Total Displacement = 0

Explanation: 1.5 rounds around the pole = 1.5 times the circumference of the circle form by the rope.

Circumference of a Circle = 2πr

from the question the radius = 2m, hence the total circumference = 2π*2 = 4π meters.

Displacement which is distance between initial position and final position. When the horse takes one and a half rounds around the pole, it ends up back at the starting point. Hence, the displacement is zero.

Answer:

If it is not an object in motion, all forces are balanced.

The equation mentioned in the manual is:

m = (n2/n1) * (cos(theta1)/cos(theta2))

n1 = 2.42

The equation mentioned in the manual is:

m = (n2/n1) * (cos(theta1)/cos(theta2))

where m is the slope obtained from the graph of sin(theta1) vs. sin(theta2), n1 and n2 are the refractive indices of the two materials, and theta1 and theta2 are the angles of incidence and refraction, respectively.

In this problem, we have n2 = 1.0003 (since the second material is air). We also know that sin(theta1) = sin(theta2), since the graph is of sin(theta1) vs. sin(theta2). Therefore, cos(theta1) = sqrt(1-sin^2(theta1)) = sqrt(1-sin^2(theta2)) = cos(theta2).

Substituting these values into the equation above, we get:

0.413 = (1.0003/n1) * 1

Simplifying this expression, we get:

n1 = 1.0003/0.413 = 2.42

Therefore, the correct answer is n1 = 2.42.

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Answer:

150 N

Explanation:

Force is equal to mass times acceleration.  50 kg accelerating at a mass of 3m/3² is undergoing a force of 150 m/s², or 150 Newtons

The elastic potential energy of the spring is 1.6 J.

The elastic potential energy of the spring is the energy stored in the spring and it is calculated as follows;

U = ¹/₂kx²

where;

The given parameters include;

U = ¹/₂kx²

U = ¹/₂ (80) (0.2)²

U = 1.6 J

Thus, the elastic potential energy of the spring is a function of the spring constant and the extension of the spring.

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The magnitude of the gravitational force acting on the satellite is  7.43 × 10⁻¹⁷ Newton.

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

A spring balance can be used to calculate the Force. The Newton is the SI unit of force.

The magnitude of the gravitational force acting on the satellite = GMm/(R+ 2R)²

= (6.67 × 10⁻¹¹× 4500 × 3.39× 10⁶)/(3 × 3.39 × 10⁶)² Newton

= 7.43 × 10⁻¹⁷ Newton.

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Answer:

621 N.

Explanation:

Answer:

5

Explanation:

1

In quantum mechanics, an orbital is a mathematical function that describes the probability of finding an electron in a particular region of space around an atom's nucleus.

Quantum refers to the smallest indivisible unit of energy, matter, or any other physical quantity. It is a term used in quantum mechanics, the branch of physics that describes the behavior of matter and energy at the scale of atoms and subatomic particles.

Orbitals are characterized by three quantum numbers: the principal quantum number (n), the azimuthal quantum number (l), and the magnetic quantum number (m).

The principal quantum number determines the size and energy level of the orbital, while the azimuthal quantum number determines the shape of the orbital. The magnetic quantum number determines the orientation of the orbital in space.

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Correct question:

Identify each of the following orbitals, and determine the n and l quantum numbers. Explain your answers.

A unit showing the intensity of the sound level is known as the decibel. In physics, this unit of sound intensity is shown by dB. The loudness of a sound depends on its density. The correct option is B.

The formula used to calculate the intensity of sound is:

Intensity in dB = 10 log (Intensity in W/m² / Threshold intensity)

β = 10 log (I / I₀)

80 = 10 log (I/ 1 × 10⁻¹²)

log (I/ 1 × 10⁻¹²) = 80 / 10

log (I/ 1 × 10⁻¹²) = 8

I / 1 × 10⁻¹² = 10⁸

I = 10⁸ ( 1 × 10⁻¹²)

I =  10⁸ × 10⁻¹²

I = 10⁻⁴ W / m²

I₁ = I / 100

10⁻⁴ / 100 = 10⁻⁶ W / m²

β₂ = 10 log (I₁ / I₀)

10 log ( 10⁻⁶ /  1 × 10⁻¹²) = 60 dB

Thus the correct option is B.

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The lamp descends with the elevator so its acceleration is also 2.9 m/s². Take downward to be the positive direction. Then the net force on the lamp is

∑ F = w - t = ma

where w = mg = weight of lamp, t = tension in the cord, m = mass of lamp, and a = acceleration. Then

mg - t = ma

mg - ma = t

m (g - a) = t

m = t / (g - a)

so that the lamp's mass is

m = (52 N) / (9.8 m/s² - 2.9 m/s²) ≈ 7.5 kg

A radio wave travels at the speed of light, which is equal to approximately 300,000 km/s.

So, to travel a distance of 998.25 km, the time needed is:

Therefore the time required is approximately 3327.5 microseconds.

Ethan's velocity between 9:30 and 10:00 in km/hr is 10.​

To know the velocity of the in between 9.30 and 10,

Use the formula,

speed = distance / time

Given,

distance 1 = 10 km

distance 2 = 15 km

time = 30 min

v = ?

Putting values,

v = Δs/Δt

v = 15 - 10 / 30 min

v = 5 / 1800 sec

v = 5000 m / 1800 sec

v = 2.78 m/sec

Or,

v = 5 km / 0.5 h

v = 10.0 km/h

The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.

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Answer:

i think it is 20.5

Explanation:

Answer:

Explanation:

Force of friction acting on the crate = μ mg

= .4 x 100 x 9.8 = 392 N

Net force acting on the crate = 400 -392 N = 8 N .

acceleration = net force / mass

= 8 N / 100 kg

= .08 m /s²

velocity after 3 s.

v = u + at

= 0 + .08 x 3

= 0.24 m/s .

Answer:

Computer hard drives use magnetism to store the data on a rotating disk. More complex applications include: televisions, radios, microwave ovens, telephone systems, and computers. An industrial application of magnetic force is an electromagnetic crane that is used for lifting metal objects.

Answer:

Examples of magnetic force is a compass, a motor, the magnets that hold stuff on the refrigerator, train tracks, and new roller coasters. All moving charges give rise to a magnetic field and the charges that move through its regions, experience a force.

I Hope this will help you if not then sorry :)

Cosmic Dust.

Why? When stars explode, or die, they releases dust and gas.

To solve this we must be knowing each and every concept related to galaxy. Therefore, cosmic dust of a galaxy consists of tiny particles that look smoky or cloudy and can be found in the space between stars.

Galaxies are collections of stars as well as other celestial objects that are gravitationally bound. The cosmos contains and over 100 billion galaxies, each of which has stunning formations seen in photographs captured by telescopes of the far sky.

According to Samuel, a galaxy's shape is the result of continual interactions between its many components. The majority of the mass is provided by the dark matter, which uses gravity to hold everything together. Cosmic dust of a galaxy consists of tiny particles that look smoky or cloudy and can be found in the space between stars.

Therefore, cosmic dust of a galaxy consists of tiny particles that look smoky or cloudy and can be found in the space between stars.

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Answer:

Explanation:

time =d/s

therefore, t =8.5/2.8

t=3.02s