It's not the complete question
Solve 7x - 9 = 28 + 4(x - 1).
A X = -11
B x = 11
C X = 3
D x=-3
Simplify 5^-4/5^3
5^7
5^-1
1/5
1/5^7
simplification :
\( \dfrac{ {5}^{ - 4} }{5 {}^{3} }\)\( \dfrac{1}{5 {}^{4} \times 5 {}^{3} } \)\( \dfrac{1}{5 {}^{7} } \)therefore , the correct option is D
90% as a decimal simplified
Answer:
0.9
Step-by-step explanation:
Answer:
The answer is 0.9
Step-by-step explanation:
90% = 0.9 in decimal form.
90 ÷ 100 = 0.9%
For z=re^iϕ =x+iy, let f(z)=u(r,θ)+iv(r,θ). Derive the form of the Cauchy-Riemann equations in r,θ variables.
These equations relate the partial derivatives of u and v with respect to r and θ, and they must be satisfied for a complex function f(z) = u(r,θ) + iv(r,θ) to be analytic.
We can write z in terms of its polar coordinates as:
z = r e^(iϕ)
where r is the radial distance from the origin to z, and ϕ is the angle between the positive x-axis and the line connecting the origin to z.
Using the chain rule, we can express the partial derivatives of u and v with respect to r and θ as follows:
∂u/∂r = ∂u/∂x * ∂x/∂r + ∂u/∂y * ∂y/∂r
= ∂u/∂x * cos(θ) + ∂u/∂y * sin(θ)
∂u/∂θ = ∂u/∂x * ∂x/∂θ + ∂u/∂y * ∂y/∂θ
= -∂u/∂x * r sin(θ) + ∂u/∂y * r cos(θ)
∂v/∂r = ∂v/∂x * ∂x/∂r + ∂v/∂y * ∂y/∂r
= ∂v/∂x * cos(θ) + ∂v/∂y * sin(θ)
∂v/∂θ = ∂v/∂x * ∂x/∂θ + ∂v/∂y * ∂y/∂θ
= -∂v/∂x * r sin(θ) + ∂v/∂y * r cos(θ)
To obtain the Cauchy-Riemann equations in polar coordinates, we first write out the standard Cauchy-Riemann equations in terms of the real and imaginary parts of z:
∂u/∂x = ∂v/∂y
∂u/∂y = -∂v/∂x
Substituting x = r cos(θ) and y = r sin(θ), we get:
∂u/∂r * cos(θ) + ∂u/∂θ * (-r sin(θ)) = ∂v/∂θ * cos(θ) + ∂v/∂r * sin(θ)
-∂u/∂r * r sin(θ) + ∂u/∂θ * r cos(θ) = -∂v/∂θ * r sin(θ) + ∂v/∂r * cos(θ)
Simplifying and rearranging, we obtain the Cauchy-Riemann equations in polar coordinates:
∂u/∂r = (1/r) ∂v/∂θ
(1/r) ∂u/∂θ = -∂v/∂r
These equations relate the partial derivatives of u and v with respect to r and θ, and they must be satisfied for a complex function f(z) = u(r,θ) + iv(r,θ) to be analytic.
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I NEED HELP ASAP! THANKS :)
Answer: A) stretched vertically by 2 and shifted up 6 units
Step-by-step explanation:
y = A log(Bx - C) + D where
A = vertical stretch by a factor of AB = horizontal shrink by a factor of 1/BC = horizontal shift C units (positive = right, negative = left)D = vertical shift D units (positive = up, negative = down)Given: f(x) = log x
g(x) = 2 log x + 6
→ A = 2 vertical stretch by a factor of 2
→ D = +6 vertical shift UP 6 units
PLEASE HELP!
What is the value of (−14)3 when evaluated?
A. −2,744
B. −196
C. 42
D. 2,744
Answer:
−2,744
Step-by-step explanation:
What is the value of \((-14)^{3}\) when evaluated?
A. −2,744
B. −196
C. 42
D. 2,744
x+y=3
x^2+y^2=17
Solve the simultaneous equations
The possible solution set for the system is (- 1, 4) and (4, - 1).
What are algebraic expressions?In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.Given are the equations as -
x + y = 3
x² + y² = 17
Refer to the graph of the function attached. The points of intersection represents the possible solution set.
Therefore, the possible solution set for the system is (- 1, 4) and (4, - 1).
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Juan bought a basketball for 40% off. If
he paid $36 for the basketball, what was
the original price?
Answer:
$24
Step-by-step explanation:
since 40% is in 100% i did 100 - 40 which i got 60
then it says that he paid $36 so I subtracted 60 - 36 and I got $24 as the answer iihope this helps! :)
100 - 40 = 60
60 - 36 = 24
The original price when he paid $36 for the basketball should be considered as the $24.
Calculation of the original price:Since
Juan bought a basketball for 40% off And, If he paid $36 for the basketball.
So it be like
= 60% of $100 - $36
= $60 - $36
= $24
Hence, The original price when he paid $36 for the basketball should be considered as the $24.
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I want you to set a goal of signing up 25% of your new customers for our new service feature." Representative: "If I get 96 new customers that means I have to get
If he get 96 new customers that means he will have to sign 24 customers
for the new service features.
The deal is to get 25% of your new customer to sign the new service features.
When the new customers are 96 in numbers, the number of individuals(25%
of the new customers) to be signed for the new features can be calculated as
follows:
New customer to sign for the new features = 25% of 96
New customer to sign for the new features = 25 / 100 × 96
New customer to sign for the new features = 2400 / 100
New customer to sign for the new features = 24
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This means that if I get 96 new customers that means I have to get 24 new customers
From the question, I want to set a goal of signing up 25% of your new customers for our new service feature.
Since we have 96 new customers, hence the total amount of new customers needed will be expressed as:
= 25% of 96
= 0.25 * 96
= 24 new customers
This means that if I get 96 new customers that means I have to get 24 new customers
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pls help this is homework
Answer:
f(-9)= 135
Substitute the -9 everywhere there's an x.
Find the values of theta. Explain how you found your answer or upload a picture showing your work.
Answer:
Step-by-step explanation:
\(\frac{\pi }{3}\) and \(\frac{2\pi }{3}\)
What is the quotient?
o -5
O 5
a+3b = 7, c= 3 , then the value of a+3 (b+c ) =............
a) 10
b) 16
c) 21
d) 30
step by step pls
Answer:
16
Step-by-step explanation:
a+ 3(b + c)
a + 3b + 3c
but a + 3b = 7 and c = 3
7+3(3)
7 + 9
=16
See attachment for math work.
the y-intercept of the parent quartic function, f(x) = x^4, is translated 3 units to the right and 1 unit down. Which equation represents this transformation
The equation of the transformed function is g(x) = (x - 3)⁴ - 1
How to describe the transformation from the parent function?From the question, we have the following function that can be used in our computation:
f(x) = x⁴
Transformation = translated 3 units to the right and 1 unit down
Mathematically, this can be represented as
g(x) = f(x - 3) - 1
Substitute the known values in the above equation, so, we have the following representation
g(x) = (x - 3)⁴ - 1
Hence, the transformed function is g(x) = (x - 3)⁴ - 1
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19. Macy bought new tires for her car. She chose tires that cost $73 each. However, the tire store was offering a Buy 3Get 1 Free Sale. After this special sale, she had to pay % sales tax . What was , Macy's final cost for all 4 tires?
Answer:
$219 without tax
Step-by-step explanation:
im not sure how to calculate tax
hope this helps :)
Parallel to y=-3x+4,xintercept at 4
Answer: Equation: y=−3x+12
Explanation:
The x-intercept means y=0andx=4
Use the equation:
0=−3⋅4+b
Add 3⋅4=12 to both sides:
12=12
−12
=b→b=12
plz mark brainleist
If you want to prove you have correctly found the solution to a linear system, why do you have to substitute the solution into both equations?
Answer:
See below for explanation.
Step-by-step explanation:
As we know, if we substitute a solution in an equation, there can be two circumstances:
True - If both sides of equation are equal or same after substituting the solution in an equation, that equation is true and that means a point or solution lies on the graph.False - If both sides of equation are not equivalent or different after substituting the solution in an equation, that equation is false and that means a point or solution does not lie on graph.What does substituting the solution tell you? It tells you whether if that solution you have solved or got is correct or not. Graph wise, a point is a part of an equation if LHS = RHS but a point lies differently or separates from graph if LHS ≠ RHS.
KEYWORD
LHS - Left-Handed Side - It is always used to refer as left side of equation.RHS - Right-Handed Side - It is always used to refer as right side of equation.Do you know? A single equation such as x + 5 = 2 can be written in simultaneous equations by letting both LHS and RHS = y as we obtain y = x + 5 for first equation and y = 2 as second equation.
Next, let’s talk about simultaneous equations or system of equations. They are technically the same as one-variable equation except you learn how to convert from one-variable equations to two-variable simultaneous equations and some substitutions method as well as learn some tricks to solve for simultaneous equations. The solution in two-variable simultaneous equations is in (x,y) term so you have both x and y solution. Instead of substituting one x-value solution, unlike simultaneous equations, you need to substitute both x and y.
I said that substituting the solution(s) in mathematics are to check whether if that point or solution does lie on a graph. If a point lies on a graph or equation, that solution is valid and correct - if not, the solution is incorrect.
We have cleared out the reason why we have to substitute the solution(s) in to check. Now, why do we have to substitute in both equations rather only one? The answer is to make sure in 100%. Sometimes, when substituting the (x,y) solution in simultaneous equations, one of two equations may not have same LHS and RHS respectively.
For example, when substituting x = 2 and y = 4 in first equation, we get 2 = 2 but when we substitute in the second equation, we get 4 = 2. See that the first equation is true when substituting the solution in because both sides are equal but the second equation is false because both sides are not equal. That means (2,4) is not solution to the simultaneous equations as the second equation is false. For a solution to exist in simultaneous equations, a point (x,y) must satisfy both equations which means both equations have to be true when substituting a solution (x,y).
To summarize what I said all above:-
Substituting solutions in the simultaneous equations is to check whether if the solutions are correct or apart of graphs/equations.If a one-variable equation is true i.e 3 = 3 as example when substituting a solution in then the solution is correct. Otherwise, it’s not correct.If a two-variable equations are true for both LHS and RHS i.e both equations must have same LHS and RHS respectively then the solutions are correct. Otherwise, it’s not, even if one equation has same LHS and RHS but if the second equation does not have same LHS and RHS then the solutions are false.If you still have questions or queries about this problem or my answer, you can let me know in the comment!
If the forecast for two consecutive periods is 1,500 and 1,400 and the actual demand is 1,200 and 1,500 , then the mean absolute deviation is 1) 500 2) 700 3) 200 4) 100
200 is the mean absolute deviation. Therefore, choice three (200) is the right one.
How to calculate the mean absolute deviation
The absolute difference between the predicted and actual values must be determined, added together, and divided by the total number of periods.
Forecasted values are as follows: 1,500 and 1,400
Values in actuality: 1,200 and 1,500
Absolute differences:
|1,500 - 1,200| = 300
|1,400 - 1,500| = 100
Now, we calculate the MAD:
MAD = (300 + 100) / 2 = 400 / 2 = 200
Therefore, 200 is the mean absolute deviation. Therefore, choice three (200) is the right one.
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given 10 french books, 20 Spanish books, 8 German books, 15 Russian books, and 25 Italian books, how many books must be chosen to guarantee there are:(a) twelve books of the same language?(b) a book of each language
a) We need to select at least 56 books to guarantee that there are 12 books in the same language.
b) We need to select at least 78 books to guarantee that we have at least one book from each language.
For the given problems, in the first case, there are a total of 12 books of the same language, so we need to consider the least case which is we select 11 books from each language group and still don't have 12 books of the same language, that moment we select a total of 11 x55 = 55 books, to get a total of 12 books of the same language.
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what are the coordinates of c’s after abc is translated 3 units to the left and 5 units up
Answer:
the coordinates are -2, -1.
Step-by-step explanation:
Answer:
(-2,-2)
Step-by-step explanation:
A car driving at 10.0 m/s southward accelerates at 4.11 m/s2 southward for 7.25 s. what is the car's speed after this amount of time?
The car's speed after the given amout of time is 19.8 m/s²
How would you define acceleration?The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration. A point or object going straight ahead is accelerated when it accelerates or decelerates. Any alteration in an object's velocity could take the form of a change in direction of motion or a speed increase or reduction. The moon orbiting the earth, an apple falling to the ground, and a car stopped at a stop sign are a few instances of acceleration.
Average Acceleration =Change in Velocity/ Time Taken
So Change in Velocity is 10-x m/s
Time taken is 7.25 s
Given accelaration 4.11 m/s²
Putting the values we get,
4.11 = (10-x)/7.25
⇒29.8 = 10-x
⇒x=19.8 m/s²
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how does algebra work im not very good at it
use function notation (with the appropriate functions above) to represent the area of a regular pentagon whose perimeter is 140 cm.
However, we need to substitute a with s since that is the value we have calculated. Therefore, we get \(A(s) = (1/4)(5 + sqrt(5))s^2.\) This is the function notation that represents the area of a regular pentagon whose perimeter is 140 cm.
Let's consider that s be the length of a side of the regular pentagon.
The perimeter of the regular pentagon will be 5s. Therefore, we have the equation:5s = 140s = 28 cm
Also,
we have the formula for the area of a regular pentagon as:
\($A=\frac{1}{4}(5 +\sqrt{5})a^{2}$,\)
where a is the length of a side of the pentagon.
In order to represent the area of a regular pentagon whose perimeter is 140 cm, we need to substitute a with s, which we have already calculated.
Therefore, we have:\(A(s) = $\frac{1}{{4}(5 +\sqrt{5})s^{2}}$\)
Now, we have successfully used function notation (with the appropriate functions above) to represent the area of a regular pentagon whose perimeter is 140 cm.
The area of a regular pentagon can be represented using function notation (with the appropriate functions above). The first step is to calculate the length of a side of the regular pentagon by dividing the perimeter by 5, since there are 5 sides in a pentagon.
In this case, we are given that the perimeter is 140 cm, so we get 5s = 140, which simplifies to s = 28 cm. We can now use the formula for the area of a regular pentagon, which is\(A = (1/4)(5 + sqrt(5))a^2\), where a is the length of a side of the pentagon.
However, we need to substitute a with s since that is the value we have calculated. Therefore, we get\(A(s) = (1/4)(5 + sqrt(5))s^2.\) This is the function notation that represents the area of a regular pentagon whose perimeter is 140 cm.
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I need help on this homework
Convert the capacity of 5 liters
Based on the above, the capacity of a 5-liter tin is about 500 cm³.
What is the capacity?To be able to convert the capacity of a 5-liter tin to its volume in cm³, One need to use the conversion factor that is, 1 liter is equivalent to 100 cm³.
So, to be able to calculate the volume of a 5-liter tin in cm³, one have to multiply the capacity (5 liters) by the conversion factor (100 cm³/liter):
Volume in cm³ = 5 liters x 1000 cm³/liter
= 500 cm³
Therefore, the capacity of a 5-liter tin is about 500 cm³.
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See full text below
Convert the capacity of a 5 litre tin to its volume in cm³.1litre is equivalent to 100cm³
This question tests your understanding of the equivalence between DFAs and NFAs. Consider NFA M=({q1,q2},{0,1},δ,q1,{q1}) for δ defined as: (a) (4 points) Draw the state diagrams for M. (b) (2 points) Based on the construction of Theorem 1.39 in the text, start to build the DFA M′ that is equivalent to M by identifying the number of DFA states and listing them. (c) (2 points) Identify the DFA M′ starting and acceptance states. (d) (4 points) Draw the state diagram for the DFA M′ equivalent to M based on the construction of Theorem 1.39 in the text (recall the latter proves that DFAs and NFAs are equivalent).
The NFA M has two states (q1 and q2) with the given transition function. The equivalent DFA M' has four states (q1, q2, q3, {q2, q3}) with the transition diagram as shown above. The starting state of M' is q1, and the acceptance states are {q2, q3}.
(a) The state diagram for NFA M is as follows:
ε 0 ε
→q1 ----→q2 ←-- q3
The NFA M has two states q1 and q2. The transition function δ is defined as follows: δ(q1, ε) = {q2} δ(q2, 0) = {q2} δ(q2, 1) = {q3} δ(q3, ε) = {q2}
(b) To construct the equivalent DFA M', we need to determine the number of DFA states and list them. The DFA M' will have 2^n states, where n is the number of states in the NFA M. In this case, n = 2, so M' will have 2^2 = 4 states.
The DFA states of M' are: Q' = {q1, q2, q3, {q2, q3}}
(c) The starting state of M' is the set of starting states of M, which is {q1}. The acceptance states of M' are the states that contain an acceptance state of M, which is {q2, q3}.
Starting state of M': q1 Acceptance states of M': {q2, q3}
(d) The state diagram for the DFA M' is as follows:
0 1
→q1 ---- q2 ←-- q3
| |
|ε |ε
↓ ↓
{q2,q3} ∅
Here, q1 is the starting state of M', q2 and q3 are the intermediate states, and {q2, q3} is the acceptance state. The transition from q1 to q2 is labeled with 0, from q2 to q2 is labeled with 0, from q2 to q3 is labeled with 1, and the transitions with ε are shown as dashed lines.
In conclusion, the NFA M has two states (q1 and q2) with the given transition function. The equivalent DFA M' has four states (q1, q2, q3, {q2, q3}) with the transition diagram as shown above. The starting state of M' is q1, and the acceptance states are {q2, q3}.
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Stossel is listening to an audiobook that at normal speed will last 10 hours. Stossel decides listen the audiobook at 2.5 faster. How long will the book be?
Answer:
4 hoursStep-by-step explanation:
Speed and time are inverse functions.
At normal speed the time is 10 hours.
If the speed is 2.5 times faster, then time is 2.5 times less:
10 hours / 2.5 = 4 hoursSpeed is 2.5
Distance is 10
Time
10/2.510/(25/10)100/254hrs
Abstract Algebra Problem:
Given a ring R with multiplicative identity 1, prove that if
0R = 1R then R= {0}.
Using the properties of multiplication we have proven that if 0R = 1R, then R = {0}.
To prove that if 0R = 1R, then R = {0}, we need to use the properties of rings.
Let's assume that R is a ring with a multiplicative identity 1, and 0R = 1R.
First, we need to recall the definition of 0R. 0R is the additive identity of the ring R, which means that for any element a in R, we have a + 0R = a.
Now, let's consider any element b in R. Since 0R = 1R, we have b = b * 1R.
Multiplying both sides of the equation by 0R, we get b * 0R = b * (0R * 1R).
Using the associative property of multiplication, we can rewrite this as b * 0R = (b * 0R) * 1R.
Now, let's cancel out b * 0R on both sides.
This gives us 0R = 1R.
Since 0R is the additive identity, it means that for any element c in R, we have c + 0R = c.
Therefore, 1R must be equal to 0R.
Now, let's consider any element d in R. We know that d = d * 1R = d * 0R.
Using the properties of multiplication, we can rewrite this as d = 0R.
Therefore, any element in R must be equal to 0R, which means R = {0}.
Hence, we have proven that if 0R = 1R, then R = {0}.
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Write an exponential function for the graph that passes through the points (–1, 0.8) and (2,100)
Answer:
y = 4(5)^x
Step-by-step explanation:
We can use the form y = ab^x to write the exponential function that passes through the given points.
First, we need to find the values of a and b. We can use the two points to create a system of equations:
0.8 = ab^(-1)
100 = ab^(2)
We can solve for a by multiplying the first equation by b and substituting it into the second equation:
100 = ab^(2)
100 = (0.8b)b^2
125 = b^3
b = 5
Now we can solve for a using either of the original equations:
0.8 = ab^(-1)
0.8 = a/5
a = 4
Therefore, the exponential function that passes through the given points is:
y = 4(5)^x
What are the 2 theoretical quantities of ANOVA?
The two theoretical quantities of ANOVA (Analysis of Variance) are:
1. Between-group variance.
2. Within-group variance:
1. Between-group variance.
This is the variance that can be attributed to differences between the group means.
It is calculated by comparing the mean of each group to the overall mean of all the data points.
The larger the between-group variance, the more likely there are significant differences between the groups.
2. Within-group variance:
This is the variance that can be attributed to differences within each group, i.e., the individual differences among the data points in each group.
It is calculated by comparing the individual data points in each group to their respective group mean.
The smaller the within-group variance, the more likely the groups are homogeneous.
In ANOVA, these two quantities are compared using an F-ratio.
If the between-group variance is significantly larger than the within-group variance, it indicates that there are significant differences between the group means, and the null hypothesis can be rejected.
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