A baseball team plays in a stadium that holds 50000 spectators. With the ticket price at $12 the average attendence has been 22000. When the price dropped to $11, the average attendence rose to 25000. Assume that attendence is linearly related to ticket price.

What ticket price would maximize revenue?

Answer:

H(1 , 0.5)

F(3 , 2,5)

G(5 , 0.5)

Step-by-step explanation:

First step is to get the coordinates of the points.

H(2,1)

F(6,5)

G(10,1)

To find the vertices after a dilation, we multiply the coordinates by the scale factor of the dilation. Since the scale factor is 0.5, its the same as dividing by two.

The new points are

H(1 , 0.5)

F(3 , 2,5)

G(5 , 0.5)

the best description of a population that has a stable age distribution is (e) a growing population in which the proportions of individuals in the different age classes remain constant.

Such a population will have a steady age distribution since the proportion of people in each age group will remain constant.   Independent of the initial age distribution is this steady age distribution and is solely dependent on maintaining stable fertility and death rates.

It has been demonstrated that a closed population's annual rate of increase tends to become constant when it is exposed to age-specific fertility and mortality rates for a considerable amount of time.

A population that has reached this point is referred to as stable, and this consistent rate of growth is known as the intrinsic rate of natural increase.

Such a population will have a steady age distribution since the proportion of people in each age group will remain constant.

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Answer:

Step-by-step explanation:

Play 1 they lose 4y

-4

Play 2 they lose 13y

-13

Total so far we have

-17

play three they gain 2y

-17+2=-15

Over the course of three plays the team loses 15 Yards.

Answer:

f (x) =|x-3| + 7

Step-by-step explanation:

in x value goes from left,right so you make a -3 value to make 3 right shifting and then you add the factor of 4 (1+2+4) and makes it 7

The function describes the graph of the transformed function of f(x) = |x| if, the function is shifted to the right 3 units and stretched vertically by a factor of 4, is f(x) = 4|x - 3|. The graph is attached below.

A graph is a structure made up of a number of objects, some of which are theoretically "connected" to one another. Each pair of connected vertices is referred to as an edge, and the objects are symbolized by so-called vertices, which are mathematical abstractions.

Given:

f(x) = |x|

The function is shifted to the right 3 units and stretched vertically by a factor of 4,

Write the function after the translation by 3 units on the right,

f(x) = |x - 3|      (To translate into right, the x-intercept should be 3)

Write the function after the stretched vertically by factor 4,

f(x) = 4|x - 3|   (To stretch vertically you have to multiply the factor to the function)

Thus,  f(x) = 4|x - 3|

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Answer:

9 is the answer.

Both negative signs cancel eachother, so you just have 45/5.

Step-by-step explanation:

Good luck! <3

The domain of a function refers to the set of all values of the independent variable (usually denoted by x) for which the function is defined.

For the function f(x) = 2, the expression is defined for all real values of x. Therefore, the domain of f(x) is all real numbers.

If the function was f(x) = 2 / (x - 9), then the expression is undefined for x = 9. Therefore, the domain of f(x) would be all real numbers except 9.

If the function was f(x) = 2 / (x - 3)(x + 3), then the expression is undefined for x = 3 and x = -3. Therefore, the domain of f(x) would be all real numbers except 3 and -3.

If the function was f(x) = sqrt(2x - 5), then the expression is only defined for values of x that make the argument of the square root non-negative. Therefore, the domain of f(x) would be all real numbers such that 2x - 5 >= 0, which simplifies to x >= 5/2.

Therefore, without more information about the function, it is impossible to determine its domain.

Step-by-step explanation:

area of circle = πr²

radius ² = 9.15 = 83.72 (approx.)

now,

→ 22/7 × 83.72

→ 22 × 11.96 = 263.02 m²

therefore, area the centre circle is 263.02 according to nearest circle the area is 263 m².

hope this answer helps you dear..take care and may u have a great day ahead!

Answer: (A) \(12+12\sqrt{12}\) .

Step-by-step explanation:

Perimter is the sum of the all sides of a figure.

As the given design has three exactly same or identical triangles with side-lengths \(2\sqrt{2}\ in, 2\sqrt{2}\ in, 4\ in\) joined by ending vertices.

Then, the combined operimetr of thge design would be :

3 x (Perimeter of the one triangle)

For this , Perimeter of one triangle = \(2\sqrt{2}+2\sqrt{2}+4\ in =(4\sqrt{2}+4) = 4(\sqrt{2}+1) \ in\)

Now , the combined operimetr of thge design would be :

\(3\times4(\sqrt{2}+1)=12(\sqrt{2}+1)\ in\)  or   \(12+12\sqrt{12}\ in\)

Hence, the correct option is (A) \(12+12\sqrt{12}\) .

Answer:

it is a

Step-by-step explanation:

Given that the vertex of the function is at the point (0, 0.5).We are required to find the recommended amount of mulch for a flowerbed with a radius of 20 feet.

Let us find the equation of the parabola with the vertex at (0,0.5).

The general equation of the parabola is given as:y = a(x - h)² + k

Where(h, k) = (0, 0.5)

=> h = 0 and k = 0.5

Therefore, the equation of the parabola is:

y = a(x - 0)² + 0.5y = ax² + 0.5

We have another point on the parabola given as (20, 2).We can use this point to find the value of a.

Substituting the point (20, 2) in the equation of the parabola we get:

2 = a(20)² + 0.52

= 400a + 0.5a

= 1.5/400

a = 3/8000

Substituting the value of a in the equation of the parabola, we get:

y = (3/8000)x² + 0.5

Let us now find the volume of the flowerbed with a radius of 20 feet.We know that the flowerbed is in the shape of a hemisphere.

Hence,Volume of the flowerbed = (2/3)πr³ = (2/3) × π × (20)³

= 33,510.32 cubic feet

Let us find the height of the flowerbed at a distance of 20 feet from the center.The distance from the center of the flowerbed to the edge is 20 feet.

Therefore, the point on the parabola at a distance of 20 feet from the origin will be (20, h).Let us find the value of h.

Substituting x = 20 in the equation of the parabola, we get:

h = (3/8000)(20)² + 0.5

= 0.8 feet

The height of the flowerbed at a distance of 20 feet from the center is 0.8 feet.The volume of the mulch required will be the volume of the hemisphere with radius 20 and height 0.8 feet.

Volume of mulch required = (2/3)πr²h

= (2/3) × π × (20)² × 0.8

= 6716.32 cubic feet

Therefore, the recommended amount of mulch for a flowerbed with a radius of 20 feet is 6716.32 cubic feet.

Therefore, the recommended amount of mulch for a flowerbed with a radius of 20 feet is 6716.32 cubic feet.

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Answer:

Step-by-step explanation:

We may not be able to fit 16 cases in the box because their combined volume will be greater than the box which will make it impossible.

The dimensions of the big box is given as:

Length= 26 cm

Breadth= 15 cm

Height= 20 cm

So its volume can be calculated by:

Volume= Length x Breadth x Height

Volume= 26 cm x 15 cm x 20 cm

Volume1= 7800 cm³

Now, the dimension of one disc case is given as:

Length= 1.6 cm

Breadth= 14.2 cm

Height= 19.3 cm

The volume of one disc case will be:

Volume= 1.6 cm x 14.2 cm x 19.3 cm

Volume= 438.496 cm³

So, volume of 16 disc cases= 16 X volume of one disc case

Volume2= 16 x 438.496 cm³

Volume2= 7015.936 cm³

Since Volume1 < Volume2

So, 16 disc cases cannot be fit into a box.

The translation of the question given is

A line that passes through the points A (2,1) and B (6,3) and another line passes through A and through the point (0, y). What is y worth, if both lines are perpendicular?

Answer:

y = 5

Step-by-step explanation:

Line 1 that passes through A (2,1) and B (6,3)  

Slope (m1) = 3-1/6-2 = 2/4 = 1/2

y - 1 = \(\frac{1}{2}\) ( x -2)

2y - 2 = x- 2

y = \(\frac{x}{2}\)

Line 2 passes through A (2,1) and (0,y)

slope (m2) =\(\frac{y-1}{-2}\)

Line 1 and Line 2  are perpendicular

m1*m2 = -1

\(\frac{1}{2}\)  * \(\frac{y-1}{-2}\) = -1

y-1 = 4

y = 5

slope = -2

Equation of Line 2

Y-1 = -2(x-2)

y -1 = -2x +4

2x +y = 5

Answer:

Assume we want to find the solution to this system of equations.

The solution is (2,-2)

Step-by-step explanation:

We can find the solution either mathematically or by graphing.  I'll do both.

Math:

Rearrange:

-2x-6y=8

-6y=8 +2x

y = -(1/3)x -(4/3)

---

Now use this expression of y in the second equation:

-6x-6y=0

-6x-6(-(1/3)x -(4/3)) =0

-6x + 2x +8 =0

-4x = - 8

x = 2

---

Use x = 2 in the first equation to find y:

y = -(1/3)x -(4/3)

y = -(1/3)*(2) -(4/3)

y = -(2/3) -(4/3)

y = -(6/3) or -2

The solution is (2,-2)

===============

Graphing:

See attached graph.

Answer:

Step-by-step explanation:

-2x - 6y = 8

6x + 6y = 0

4x = 8

x = 2

-4 - 6y = 8

-6y = 12

y = -2

(2, -2)

The remainder when a 90-digit number 9999 is divided by 89 is 0, as the result of applying the divisibility rule of 89, which involves reversing the digits of the number and subtracting the smaller from the larger.

To find the remainder when a 90-digit number 9999 is divided by 89, we can use the divisibility rule of 89. The rule states that for any integer n, the number obtained by reversing the digits of n and subtracting the smaller from the larger is divisible by 89.

In this case, we reverse the digits of 9999 to get 9999 again, and subtract the smaller from the larger to get 0. Since 0 is divisible by any number, including 89, the remainder when 9999 is divided by 89 is 0.

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Answer:

yes, Send me your questions

Answer:

it's one of this two. if it's exactly how you have written it , it's the first picture.

Answer:

12\(\sqrt{5}\)x^5

Step-by-step explanation:

Apply exponent rule

Add the numbers

Multiply the numbers

Factor integer

Distributing to create an equivalent expression with fewest symbols possible will result to 24m - 28

According to the Distributive Law, multiplying a number by a collection of numbers is equivalent to performing each multiplication independently.

In mathematics, the law linking the operations of multiplication and addition is known as distributive law, sometimes known as distributive property. It is symbolically expressed as a(b + c) = ab + ac.

For the problem the law is applied as follows

(6m - 7 )* 4

multiplying each term

24m - 28

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The statement is True only for independent events and False otherwise. The statement "p (A ∩ B) = p(A). p(B)" is not always true for any two events A and B defined on a sample space S of an experiment.

This equation only holds true if A and B are independent events, meaning that the occurrence of one event does not affect the probability of the other event happening. In other words, p(A|B) = p(A) and p(B|A) = p(B).

If A and B are dependent events, meaning that the occurrence of one event affects the probability of the other event happening, then the equation does not hold true. In this case, the probability of A and B occurring together (p(A ∩ B)) would be less than the product of the probabilities of A and B occurring separately (p(A).p(B)).

Therefore, the statement is not always true and depends on whether A and B are independent or dependent events.

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Answer:

cos^2x + (1+1)cos x + 1 = 0

or,cos^2x + cos x + cos x + 1 = 0

or,cos x(cos x + 1) + 1 (cos x + 1) = 0

or, (cosx + 1) + (cosx + 1) = 0

either

cosx + 1 =0 or cosx +1 =0

Answer:

C = -5

Step-by-step explanation:

Functions

F(x) is defined as:

\(\displaystyleF(x)=\frac{C-x}{D-x}\)

We know F(-2) is undefined. It comes from the fact that the denominator is 0 for this value of x, thus:

D - (-2) = 0

Solving:

D = -2

Substituting:

\(\displaystyleF(x)=\frac{C-x}{-2-x}\)

We also know F(-1) = 4:

\(\displaystyle \frac{C-(-1)}{-2-(-1)}=4\)

\(\displaystyle \frac{C+1}{-2+1}=4\)

\(\displaystyle \frac{C+1}{-1}=4\)

Multiplying by -1

C + 1 = -4

Solving for C:

C = -5

Step-by-step explanation:

21/20 = m/100

m = 100 * (21/20) = 105.

Answer:

1. D

2. C

3. B

4. A

Step-by-step explanation:

just match up the number y is on the right side and x on the left side like this (x,y)

Hence , the price of the system $295 .

Let the price of the system be "x" .

It is given that in the first week her savings were $8 less than 2/5 the price of the system which can be represented by equation

First week savings =  (2/5)x -8

It is also given that in the second week, she saved 50 cents more than 1/2 the price of the system which can be represented by equation

Second week savings = (1/2)x +0.5

savings + short = price of system

(2/5)x -8 + (1/2)x +0.5 + 37 = x

 (2/5)x +  (1/2)x + 29.5 = x

   4x + 5x/ 10 + 29.5 = x

     9x/10+ 29.5 = x

       0.9x + 29.5 = x

          29.5 = x - 0.9x

           29.5 = 0.1x

           $ 295 = x

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I will send you on comment section the statics and it's correct answer. Please mark me as a brainist.

Answer:

58 in ^2

Step-by-step explanation:

Triangle on top   area = 1/2 base * height = 1/2 * 6 * 3 = 9 in^2

Triangle on bottom   = 1/2 base * height = 1/2 * 8 * 6 = 24 in^2

For trapezoid in the middle area = 1/2 ( 4+6)*5 = 25 in^2

Sum = 58 in^2

Average rate of change of population between 1930 and 1950 is 0.25.

Average rate refers to the rate of change in a quantity over a certain period of time. It is calculated by dividing the change in quantity by the time interval over which the change occurred.

For example, if a car travels a distance of 100 miles in 2 hours, the average rate of the car is 50 miles per hour. Here, the quantity is the distance traveled, the change in quantity is 100 miles, and the time interval is 2 hours.

Average rate is commonly used in various fields such as physics, chemistry, economics, and finance to measure the change in a quantity over time. It provides a simple way to measure the effectiveness or efficiency of a process, the speed of an object, or the growth of an investment.

We have given graph that shows the population of a city from 1900 to 2000.

Average rate of change of function on interval [a,b]  is given as:

\(A(x)=\frac{f(b)-f(a)}{b-a}\)

We have to find the average rate of change of the population between 1930 and 1950.

Here, we have a= 1930  and b=1950

From from given graph we can find that:

f(1930)=40&f(1950)= 45

Therefore, the average rate of change of population between 1930 and 1950 will be:

Average rate of change=  \(\frac{f(1950)-f(1930)}{1950-1930} \\\frac{45-40}{20} \\\frac{5}{20} \\=0.25\)

Hence, average rate of change of population between 1930 and 1950 is 0.25.

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The complete question is:

Answer:

2 * ( x+2.9) = 97.4

2x + 5.8 = 97.4

2x = 97.4 - 5.8

2x = 88.9

x = 88.9 / 2

x = 44.45

Answer:

(x+2)(x+8)=0

therefore if x+2=0

x+2-2=0-2

x=-2

and in standard form -2×10ⁿ where n=0

The solution for system of equation provided as per the given question will be x = -19 and y = 55 or (-19,55).

It is given that the equations are:

y = –3x – 2

Simplifying it further, we get:

y + 3x = -2 (equation 1)

5x + 2y = 15 (equation 2)

Multiplying y + 3x = -2 by 2 and subtracting from 5x + 2y = 15, we get:

2y - 2y + 5x -6x = 15 + 4

-x = 19

x = -19

Plugging the value of x in the equation y + 3x = -2, we get:

y + 3 × - 19 = -2

y - 57 = -2

y = -2 + 57

y = 55

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The required function be  y = 5000 - 250x.

Given that,

Amount of saving = $5000

Amount of withdraw and spend = $250

Number of months = x

If the total money in Ken's savings account after x number of months is represented by y,

Then, to calculate the entire amount in his savings account after x number of months, the program deducts 250x from the beginning amount of $5000.

Therefore, The function be,

y = 5000 - 250x

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Answer:

\(\frac{(2x^{2} + y^{2}) (5x^{2} - 3^{2} }{x^{2} y^{2} }\)

Step-by-step explanation:

Find the solution below.

Answer:    (5x2 + 3y2) • (2x2 + y2) ————————————————————————           x2y2

Step-by-step explanation:

    STEP 1:  y2

Simplify   ——

                  x2

Equation at the end of step 1:       (x2)        y2

 ((10•————)-1)-(3•——)

      (y2)        x2

STEP 2 :            x2

Simplify   ——

           y2

Equation at the end of step 2:         x2           3y2

 ((10 • ——) -  1) -  ———

        y2           x2

STEP 3:Rewriting the whole as an Equivalent Fraction  3.1   Subtracting a whole from a fraction Rewrite the whole as a fraction using  y2  as the denominator :         1     1 • y2

   1 =  —  =  ——————

        1       y2  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominatorAdding fractions that have a common denominator : 3.2       Adding up the two equivalent fractions Add the two equivalent fractions which now have a common denominatorCombine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible: 10x2 - (y2)     10x2 - y2

———————————  =  —————————

    y2             y2    

Equation at the end of step 3:  (10x2 - y2)    3y2

 ——————————— -  ———

     y2         x2

STEP 4:Trying to factor as a Difference of Squares: 4.1      Factoring:  10x2-y2 Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)Proof :  (A+B) • (A-B) =         A2 - AB + BA - B2 =         A2 - AB + AB - B2 =          A2 - B2Note :  AB = BA is the commutative property of multiplication. Note :  - AB + AB equals zero and is therefore eliminated from the expression.Check :  10  is not a square !! Ruling : Binomial can not be factored as thedifference of two perfect squaresCalculating the Least Common Multiple : 4.2    Find the Least Common Multiple       The left denominator is :       y2       The right denominator is :       x2                   Number of times each Algebraic Factor            appears in the factorization of:    Algebraic        Factor     Left  Denominator  Right  Denominator  L.C.M = Max  {Left,Right}  x 022 y 202      Least Common Multiple:       x2y2 Calculating Multipliers : 4.3    Calculate multipliers for the two fractions     Denote the Least Common Multiple by  L.C.M     Denote the Left Multiplier by  Left_M     Denote the Right Multiplier by  Right_M     Denote the Left Deniminator by  L_Deno     Denote the Right Multiplier by  R_Deno    Left_M = L.C.M / L_Deno = x2   Right_M = L.C.M / R_Deno = y2Making Equivalent Fractions : 4.4      Rewrite the two fractions into equivalent fractionsTwo fractions are called equivalent if they have the same numeric value.