If the baseball player jumps and launches the ball at the angle of 51° , then the initial speed of the ball is 11.85 m/s .
The baseball player takes the jump at a height(R) of 14 m from the basket ;
the launch angle of the ball(θ) = 51° ;
let the launch (initial) speed of the ball is = "v" ;
Since , the ball is released at same height as that of basket. So , this is a case of complete projectile motion
the formula for the horizontal range of the projectile is given as :
⇒ R = V²*Sin(2θ)/g ...where g = 9.8 m/s² .
substituting the values ,
we get ;
14 = v²*Sin(2*51)/9.8
v² = 14*9.8/Sin(2*51)°
v = √140.2561
v = 11.8426
v ≈ 11.85 m/s .
Therefore , the initial speed of the ball is 11.85 m/s .
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Acceleration is a change in what quantity Over time?A- speed B- distance C- force D- displacement
To find
Acceleration is a change in what quantity Over time?
Explanation
Acceleration is defined as the change in velocity with respect to time interval.
Conclusion
The required quantity is
A. speed
What is the density of a 150cm 3 block with a mass of 700 grams?
Answer:
The Density of the block is 4.667g/mL
Explanation:
Given the following data;
Mass of block = 700g
Volume of block = 150cm³
Density = ?
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
\(Density = \frac{mass}{volume}\)
Substituting into the equation, we have;
\(Density = \frac{700}{150}\)
Density = 4.667g/mL
which of the following best describes the composition of an atom
Answer: its the third one
a nucleus of positive and neutral particles surrounded by negative particles.
in which the neutral particles are neutrons, the positive ones are protons and the negative ones are electrons.
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What is the momentum of a 3 kg bowling ball moving at 3 m/s?
1 kg • m/s
3 kg • m/s
6 kg • m/s
9 kg • m/s
HELPP!!
Formula for momentum:
\(p=mv\)
momentum(measured in kg*m/s) = mass(measured in kg) * velocity(measured in m/s)
__________________________________________________________
Given:
\(m=3kg\)
\(v=3m/s\)
\(p=?\)
__________________________________________________________
Finding momentum:
\(p=mv\)
\(p=3\times3\)
__________________________________________________________
Answer:
\(\fbox{p = 9 kg*m/s}\)
Before you start your engine, __________ A. adjust the seat so you can reach all controls. B. make sure your car is in reverse or neutral gear before starting the engine. C. move your car before you have looked in front, behind and to the side for pedestrians and oncoming traffic. D. all of the above
Answer:
A. adjust the seat so you can reach all controls
------------------------------------------------------
This is so you can reach the gas petal, break petal, steering wheel, (and other things) easier so you won't have to lean forward and it makes it easier for when you're driving. Especially if you need to quickly press your breaks, you'll be able to do this a lot faster if you're closer to them than if you had to reach in order to do so.
I hope this helped, im not the best at explaining things lol
If the frequency of this light is tripled, the maximum kinetic energy of the emitted electrons will be
If the frequency of this light is tripled, the maximum kinetic energy of the emitted electrons will double.
KE stands for incoming photon energy plus work function.
Since the work function is now constant for every person, doubling the energy of an electron will result in an increase in its KE.
Kinetic energy, which may be seen in the movement of an object, particle, or group of particles, is the energy of motion. Any moving item uses kinetic energy, such as a person walking, a baseball being thrown, a piece of food falling from a table, or a charged particle in an electric field.
The energy of a body in motion, or kinetic energy (KE), is essentially the energy of all moving objects. Along with potential energy, it is one of the two primary types of energy.
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A block of mass 5.00 kg rests on a horizontal surface where the coefficient of kinetic friction between the two is 0.200. a string attached to the block is pulled in direction 25 degrees with horizontal, resulting in a 2.50-m/s2 acceleration by the block. find the tension in the string. (g = 9.80 m/s2)
The tension in the string is 19.8 N.
What is mass?Mass is a physical body's total amount of matter. It also serves as a gauge for the body's inertia or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.The kilogram is the SI unit of mass (kg). In science and technology, a body's weight in a given reference frame is the force that causes it to accelerate at a rate equal to the local acceleration of free fall in that frame.For instance, a kilogram mass weighs around 2.2 pounds at the surface of the planet. However, the same kilogram mass would weigh just about 0.8 pounds on Mars and about 5.5 pounds on Jupiter.An object's mass is a crucial indicator of how much stuff it contains. Weight is a measurement of an object's gravitational pull. It is influenced by the object's location in addition to its mass. As a result, weight is a measurement of force.Find the tension in the string:
The net force on the block will be:
T - Fr = Fnet = ma
Where T is the tension and Fr is the frictional force
T - ukR = ma
Where R is the upwards normal force equal to the block's weight. R = mg
therefore,
T - uk mg = ma
T - 0.2(5 x 9.8) = 5(2)
=> T = (0.2 x 5 x 9.8) + 5(2) = 19.8 N
This is the tension in the string.
For the free body diagram, draw a block and show a rope connected horizontally to it. The tension in the string will be along the rope outwards from the block. Now, the frictional force will be between the ground and the block and it will be in the opposite direction to the direction of tension of the rope. The force due to gravity will act vertically downwards while the normal force R will act vertically upwards.
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A cliff diver from the top of a 100 (m) cliff. He begins his dive by jumping up with a velocity of 5 (m/s) a. How
long does it take for him to hit the water below? b. What is his velocity right before he hits the water?
Answer:
A.) 4.81 seconds
B.) 44.6 m/s
Explanation:
He begins his dive by jumping up with a velocity of 5 (m/s).
Let us first calculate the maximum height reached by using third equation of motion
V^2 = U^2 - 2gH
At maximum height, V = 0
0 = 5^5 - 2 × 9.8H
19.6H = 25
H = 25 /19.6
H = 1.28 m
The time taken for the diver to reach the water from the maximum height can be calculated by using second equation of motion.
Where height h = 1.28 + 100 = 101.28 m
h = Ut + 1/2gt^2
As the diver drop from maximum height, U = 0
101.28 = 1/2 × 9.8 × t^2
4.9t^2 = 101.28
t^2 = 101.28/4.9
t^2 = 20.669
t = sqrt ( 20.669)
t = 4.55s
As the diver jumped up, the time taken to reach the maximum height will be
Time = 1.28 / 5 = 0.256
The time taken for him to hit the water below will be 0.256 + 4.55 = 4.81 seconds
B.) Velocity right before he hits the water will be
V^2 = U^2 + 2gH
But U = 0
V^2 = 2 × 9.8 × 101.28
V^2 = 1985.09
V = 44.6 m/s
A.) The time taken should be 4.81 seconds
B.) The velocity should be 44.6 m/s
Calculation of the time taken and velocity:Here we used third equation of motion
V^2 = U^2 - 2gH
At maximum height, V = 0
Now
0 = 5^5 - 2 × 9.8H
19.6H = 25
H = 25 /19.6
H = 1.28 m
Here the second equation of motion.
Here height h = 1.28 + 100 = 101.28 m
So,
h = Ut + 1/2gt^2
Since the diver drop from maximum height, U = 0
So,
101.28 = 1/2 × 9.8 × t^2
4.9t^2 = 101.28
t^2 = 101.28/4.9
t^2 = 20.669
t = sqrt ( 20.669)
t = 4.55s
Now
Time = 1.28 / 5 = 0.256
Finally the time should be
= 0.256 + 4.55
= 4.81 seconds
B.)
We know that
V^2 = U^2 + 2gH
But U = 0
So,
V^2 = 2 × 9.8 × 101.28
V^2 = 1985.09
V = 44.6 m/s
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Determined by the Direction and Position of the electron's movement within its sublevel
A)Energy levels
B)Sublevels
C)Orbitals
D)Valances
consider the relationship between the energy of electromagnetic radiation and its wavelength. what will happen if the energy increases? the wavelength will remain the same. the wavelength will increase. the wavelength will decrease. what will happen if the wavelength increases? the energy will increase. the energy will remain the same. the energy will decrease.
Electromagnetic radiation is a sort of energy emission. This has two components, electrical and magnetic components, as is clear from the name. The radiation is hence known as electromagnetic radiation. In Fig. 1.1, it is depicted. From a very low frequency of 3 Hz to a very high frequency of 300 EHz (1 EHz = 1018 Hz), this radiation has a wide frequency range. Table 1.1 lists the metric prefixes along with their symbols.
The magnetic and electric vectors are perpendicular to one another and to the path of propagation. In Fig. 1, this is depicted. 1. Depending on the frequency, this electromagnetic spectrum is separated into different section
Wavelength and Frequency Relationship
Wavelength
According , a wavelength is the separation between two crests or troughs. It is described in the "electronic spectrum" in terms of nm. 1 nm = 10−9 m. Radiation's energy and wavelength are inversely related. In other words, energy increases when the wavelength lowers and decreases when the wavelength grows.
In the IR spectrum, wavenumber, which has the SI value of cm1, is used in place of or v.
The relationship between frequency and wavelength
where is the wavenumber, is the wavelength, c is the speed of light, and is the frequency of the radiation.
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A 20 kg wooden crate is dragged 12 m across a rough level floor by a rope. The force of tension in the rope is 50 N at an angle of 25° above the horizontal and the crate is moving at a constant speed of 1.50 m/s. Find the magnitude of the normal force [N].
To solve this problem, we can use the equations of motion and Newton's second law of motion. The equation of motion for an object moving at constant speed is:
x = x0 + v0t + (1/2)at^2
where x is the final position, x0 is the initial position, v0 is the initial velocity, t is the time, and a is the acceleration.
In this case, the initial position is 0 m (since the crate starts at the beginning of the 12 m distance), the initial velocity is 0 m/s (since the crate starts at rest), and the time is 12 s (since the crate moves at a constant speed of 1.50 m/s).
We can use these values to solve for the acceleration:
12 m = (1/2)(a)(12 s)^2
a = 0.5 m/s^2
Now that we know the acceleration, we can use Newton's second law of motion to find the normal force:
F = ma
N = (20 kg)(0.5 m/s^2)
N = 10 N
This is the magnitude of the normal force on the crate. Note that this is the normal force exerted by the floor on the crate, not the force of tension in the rope. To find the force of tension in the rope, we would need to consider the angle of the rope and the direction of the force.
three resistor 5 ohms 8 ohms and 9 ohms are connected so that the total resistance is 22 ohms. Which of the following statements is true
Options are below in the image
Answer:
all the resistors are connected in series.
What is concentration gradient?
Answer:
The difference in the concentration of a substance between two areas is called the concentration gradient . The bigger the difference, the steeper the concentration gradient and the faster the molecules of a substance will diffuse. The direction of diffusion is said to be 'down' or 'with' the concentration gradient.
Explanation:
g Assume that a parcel of unsaturated air is at a temperature of 24 degrees C at sea level before it rises up a mountain slope, and that the lifting condensation level of this parcel is 3000 meters. What is the temperature of this parcel after it has risen to 2000 meters
The temperature of the parcel of unsaturated air after it has risen to 2000 meters would depend on the lapse rate, which is the rate at which temperature changes with altitude. Typically, the lapse rate is around 6.5 degrees Celsius per 1000 meters.
Since the parcel has risen to 2000 meters, we can calculate the change in temperature using the lapse rate:
Change in temperature = lapse rate * (change in altitude / 1000)
In this case:
Change in temperature = 6.5 degrees Celsius per 1000 meters * (2000 meters / 1000)
Calculating this:
Change in temperature = 6.5 degrees Celsius per 1000 meters * 2
So, the change in temperature would be 13 degrees Celsius.
To find the final temperature of the parcel after rising to 2000 meters, we can add the change in temperature to the initial temperature of 24 degrees Celsius:
Final temperature = initial temperature + change in temperature
Final temperature = 24 degrees Celsius + 13 degrees Celsius
Thus, the temperature of the parcel after rising to 2000 meters would be 37 degrees Celsius.
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An object is thrown off a cliff with a horizontal speed of 10 m/sec and some unknown initial vertical velocity. After 3 seconds the object hits the ground which is 30 meters below the cliff. Find the initial vertical velocity and the total horizontal distance traveled by the object.
a. What do you know?
b. What do you need to solve for?
c. What equation(s) will you use?
d. What is the solution to this problem?
The answers to the questions of the object thrown off a cliff with a horizontal speed of 10 m/s and that reach the ground which is 30 m below after 3 seconds, are:
a. We know:
The height of the cliff = 30 mThe time for the object to reach the ground = 3 sThe initial horizontal velocity = 10 m/sb. We need to find the initial vertical velocity and the total horizontal distance traveled.
c. To calculate the initial vertical velocity and the total horizontal distance traveled by the object, we need to use the following equations:
\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \) (1)
\( v_{i_{x}} = \frac{x}{t} \) (2)
d. The initial vertical velocity and the horizontal distance traveled by the object are 4.72 m/s and 30 m, respectively.
a. From the statement, we know:
The initial horizontal velocity (\(v_{i_{x}} \)) = 10 m/sThe time for the object to reach the ground = 3 sThe height of the cliff = 30 mb. We need to find the initial vertical velocity and the total horizontal distance traveled.
c. To calculate the initial vertical velocity we can use the following equation:
\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \) (1)
Where:
\( y_{f}\): is the final height = 0 m
\( y_{i}\): is the initial height = 30 m
\( v_{i_{y}}\): is the initial vertical velocity =?
g: is the acceleration due to gravity = 9.81 m/s²
t: is the time = 3 s
And, to find the horizontal distance traveled by the object we need to use the equation:
\( v_{i_{x}} = \frac{x}{t} \) (2)
Where:
\(v_{i_{x}} \): is the initial horizontal velocity = 10 m/s
x: is the horizontal distance =?
d. The solution to this problem is the following.
Calculation of the initial vertical velocity (eq 1)\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)
\( 0 = 30 m + v_{i_{y}}*3 s - \frac{1}{2}*9.81 m/s^{2}*(3 s)^{2} \)
Solving for \(v_{i_{y}}\)
\( v_{i_{y}} = \frac{\frac{1}{2}*9.81 m/s^{2}*(3 s)^{2} - 30 m}{3 s} = 4.72 m/s \)
Hence, the initial vertical velocity is 4.72 m/s.
Calculation of the horizontal distance (eq 2)\( v_{i_{x}} = \frac{x}{t} \)
\( 10 m/s = \frac{x}{3 s} \)
\( x = 10 m/s*3 s = 30 m \)
Therefore, the horizontal distance traveled by the object is 30 m.
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If x(t) and y(t) denote the system input and output, respectively, state whether the following systems are linear or nonlinear, causal or noncausal, time-variant or time-invariant, memoryless or with memory: a) y(t) = tx(t) b) y(t) = ax(t) +b, where a and b are constants. c) y(t) = ax² (t) +bx(t)+c, where a, b and c are constants. d) y(t) = x(T) dT
y(t) = tx(t) is a linear system, causal, time-variant, and with memory. Let's show that this system is linear using superposition. Suppose x1(t) and x2(t) are two input signals, and we apply them to the system to get y1(t) and y2(t), respectively.
Consider the input signal x(t) = a1x1(t) + a2x2(t),
where a1 and a2 are constants.
Then the output of the system is given by
y(t) = tx(t) = t(a1x1(t) + a2x2(t)) = a1
tx1(t) + a2
tx2(t) = a1y1
(t) + a2y2(t).
Therefore, this system is linear.b) y(t) = ax(t) + b,
where a and b are constants is a linear system, causal, time-invariant, and with memory.Let's show that this system is linear using superposition. Suppose
x1(t) and x2(t) are two input signals, and we apply them to the system to get y1(t) and y2(t), respectively. Consider the input signal
x(t) = a1x1(t) + a2x2(t),
where a1 and a2 are constants. Then the output of the system is given by
y(t) = ax(t) + b = a(a1x1(
t) + a2x2(t)) + b = a1ax1(t) + a2ax2(t) + b = a1y1(t) + a2y2(t).
Therefore, this system is linear.c)
y(t) = ax²(t) + bx(t) + c,
where a, b, and c are constants, is a nonlinear system, causal, time-invariant, and with memory. To see that it's nonlinear, consider two input signals, x1(t) and x2(t), and let y1(t) and y2(t) be the corresponding outputs. Let x(t) = a1x1(t) + a2x2(t), where a1 and a2 are constants.
Then the output of the system is given
byy(t) = ax²(t) + bx(t) + c = a(a1x1(t) + a2x2(t))² + b(a1x1(t) + a2x2(t)) + c ≠ a1y1(t) + a2y2(t).
Therefore, this system is .d) y(t) = x(T)dT is a linear system, time-invariant, and with memory. Let's show that this system is linear using superposition. Suppose x1(t) and x2(t) are two input signals, and we apply them to the system to get y1(t) and y2(t), respectively. Consider the input signal x(t) = a1x1(t) + a2x2(t), where a1 and a2 are constants. Then the output of the system is given by
y(t) = x(T)dT = (a1x1(T) + a2x2(T))dT = a1x1(T)dT + a2x2(T)
dT = a1y1(t) + a2y2(t).
Therefore, this system is linear.
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i) Show that total energy of the body at points A, B and C during the fall is same. ii) Find the distance from A to B and final velocity of the ball just reach before C. mass =5 kg, total height (h)= 100m
The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.
d (distance) from A to B is = √2gh
In this case given are, g = 9.8 m/s² and h = 100m,
so here d = √(2⋅9.8⋅100) = 44.3m.
Final velocity ,v = √2gh
Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,
g = 9.8 m/s² ,h = 100m,
v = √(2⋅9.8⋅100)
= 44.3 m/s (final velocity)
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14.4 K.L of heat is required to raise the temperature of
a 12 kg substance from 275 K to 275.5 K. Identify the
substance
Answer:
The substance is Ethanol
Explanation:
To solve this problem we must use the expression of thermal energy calculation that relates the mass of a body with the specific heat of this and the temperature difference.
Q = m*Cp*(T_f - T_i)
where:
Q = amount of heat = 14.4 [kJ]
m = mass = 12 [kg]
Cp = specific heat [kJ/kg*K]
T_f = final temperature = 275.5 [K]
T_i = initial temperature = 275 [K]
Therefore we need to calculate Cp, and then compare this with the values in the given table attached.
Cp = 14.4/(12*(275.5 - 275))
Cp = 2.4 [kJ/kg*K]
Now we compare the Cp with the values given in the table.
So the substance is Ethanol
What is the principle of vernier callipers?
\({ \blue{ \bold{Here \: is \: your \: answer...}}}\)
The vernier callipers is mainly used to measure the diameter of spherical ball and the principle states that "The magnitude of 'n' vernier scale divisions is equal to the magnitude of (n-1) number of main scale division".
A constant pressure and temperature chamber, full with 50 % air and 50 % carbon dioxide (by mass) at 1 bar and 30 °C, is fed with a flow of steam. Determine the specific humidity at which the mixture will become saturated.
A constant pressure and temperature chamber, full with 50 % air and 50 % carbon dioxide (by mass) at 1 bar and 30 °C, is fed with a flow of steam. The specific humidity is zero
The specific humidity at which the mixture becomes saturated can be determined through the following approach:
A constant pressure and temperature chamber contains a mixture of 50% air and 50% carbon dioxide (by mass) at a pressure of 1 bar and temperature of 30°C, which is fed with a flow of steam.
Therefore, the total pressure within the chamber will be the sum of the pressure of the dry air component, the pressure of the CO2 component, and the pressure of the water vapor in the chamber.
The total pressure in the chamber can be determined as follows:
P = P_air + P_CO2 + P_H2OP_air = 0.5(1 bar) = 0.5 barP_CO2 = 0.5(1 bar) = 0.5 barThe partial pressure of the water vapor can be determined using the following formula:P_H2O = ϕ(P-P_H2O)
where
P = total pressure in the chamberP_H2O = vapor pressure at the chamber temperatureϕ = specific humidity
The vapor pressure of water at 30°C can be found from a steam table to be 4.246 kPa.
Therefore,P_H2O = 4.246/100 = 0.04246 bar
Substituting the given values,P_H2O = ϕ(1 - 0.5 - 0.5)P_H2O = ϕ(0)P_H2O = 0
Therefore, the specific humidity at which the mixture will become saturated is ϕ = P_H2O/(P-P_H2O) = 0/1 = 0.The specific humidity is zero.
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1,400 g
12 kg
Which is greater
Answer:
12kg is greater because 12kg is 12000g
Answer:
12kg is the answer cause if it wasn't 12 kg then 1,400 g would not be the answer so you would pick 12kg as the answer.
cant find a solution online for this one, help is very appreciated!!
An archer is practising on a training course and
moves a distance 11 m [E] of her original position,
which is due south of her target. She is now firing in a
direction of N 28° W. How far is she from her target?
The distance force between the archer and her intended target is therefore 20.22 meters.
Which force does the arrow represent?Arrows of force are used to depict the direction and strength of forces. The force's magnitude is indicated by the length of the arrow, with longer arrows denoting stronger forces. The arrow points in the direction in which the force is really being applied.
To get the angle between the archer's present location and the target, we may utilize the supplied direction of N 28° W. This angle will be (90° - 28°) = 62°'s complement.
We may calculate the separation x between the archer's present location and the target using trigonometry:
tan(62°) = x / 11 m
x = 11 m * tan(62°)
x ≈ 20.22 m.
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please help physics statics.. don't understand how to solve
When Weight of 7294.3 N can be supported by boom if force 7800 is applied on the cable and there is no resultant rotation at point C.
What is Torque ?Torque is defined as force times perpendicular distance from axis of rotation to the point at which force is applied. Torque is denoted by τ and its SI unit is Nm. i.e Torque is given by, τ = F×d sinθ. Torque is vector quantity.
Torque is analogous to force in rotational motion. like there angular velocity ω is analogous linear velocity v. means Torque is a force in rotational motion.
Looking at the answered figure I have resolved forces, there will be no resultant rotation when opposite torques due to opposite horizontal forces gets balanced.
We get,
τ₁ = τ₂
F×d Cos40⁰ = W×d Sin55°
F Cos40° = W Sin55°
W = F×(Cos40°÷Sin55°)
W = F×0.93516
W = 7800 ×0.93516
W = 7294.3 N
Hence Weight that can be supported is 7294.3 N.
b) When we assume that there is no cable, Then
Torque τ = W×d Sin35°
τ = 7294.3×10 Sin35°
τ = 41838.3 Nm
bloom will rotate with 41838.3 Nm torque.
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Which graph represents a car with positive acceleration?.
Explanation: a graph showing a steeper or none uniform or increase
Which type of energy is stored in an elastic material stretched by a force
Potential energy is stored in the elastic material when we stretch it by some distance.
The energy stored when a force is used to deform an elastic object is called elastic potential energy. The energy is conserved until the force is released and the object returns to its original shape, doing work in the process. Objects can be compressed, stretched, or twisted when deformed.
Elastic material produces elasticity when stretched or compressed. The more the material is crushed or stretched, the greater this force.
Springs have many applications, including bed springs.
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Uma bola é lançada para cima com a velocidade inicial de 20m/s. A sua aceleração é constante e igual a 10m/s² para baixo. Quanto tempo permanece a bola no ar? Qual é a maior altura atingida pela bola? Quando a bola está a 15 m de altura em relação ao solo?
Answer:
sorry but i cannot understand your language, can you speak in english
Why cant Analog Thermometers measure temperature below 0 °C?
Answer:
Alcohol thermometers are used rather than mercury thermometers in very cold regions because alcohol has a lower freezing point than mercury.
the earth had a mass of 6,000,000,000,000,000,000,000,000 kg. and a radius of 6,371,000 m, what will be the gravitational force experienced by a puppy with a mass of 4.6 kg playing on the earth sur face
Answer:
Mass of Earth (M1) = 6×10^24 kg
Mass of Puppy (M2) = 3.6 kg
Radius (R) = 6371000 m
Universal Gravitational Constant (G) = 6.67 × 10^11
Now,
Gravitational Force = G×M1×M2 / R^2
GF = 6.67 × 10^11 × 6 × 10^24 × 3.6 / (6371000)^2
GF = 144.072 × 10^35 / 40,589,641,000,000
GF = 3549.477 × 10^20
Air pollution caused by the reaction of nitrogen compounds and other pollutants in the presence of sunlight is
Nitrogen oxides play a critical role in photochemical smog. They give the smog its yellowish-brown hue. Indoor residential appliances like gas stoves and gas or wood heaters can be significant emitters of nitrogen oxides in poorly ventilated environments.
Nitrogen dioxide (NO₂), ozone (O₃), peroxyacetyl nitrate (PAN), and chemical compounds with the -CHO group are the main harmful elements of photochemical smog (aldehydes). If present in high enough amounts, PAN and aldehydes can harm plants and irritate the eyes.The greatest sources of emissions are power plants, heavy construction equipment driven by diesel, other moveable engines, and industrial boilers. Cars, trucks, and buses are next in line.Therefore , on conclusion i.e. two gases with molecules consisting of nitrogen and oxygen atoms are nitric oxide (NO) and nitrogen dioxide (NO₂). These nitrogen oxides play a part in the development of smog and acid rain, adding to the issue of air pollution.
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The flow of electricity in a certain path is called.
The flow of electricity in a certain path is the circuit.