A bank wants to migrate their e-banking system to AWS.
(a) State ANY ONE major risk incurred by the bank in migrating their e-banking system to AWS.
(b) The bank accepts the risk stated in part (a) of this question and has decided using AWS. Which AWS price model is the MOST suitable for this case? Justify your answer. (c) Assume that the bank owns an on-premise system already. Suggest ONE alternative solution if the bank still wants to migrate their e-banking system to cloud with taking advantage of using cloud.

The plaintext corresponding to the ciphertext 5859 using the given RSA parameters is 7648.

To find the plaintext from the given ciphertext 5859, we need to use the RSA decryption formula:

plaintext = (ciphertext d) mod n

where d is the private key and n is the product of two large prime numbers p and q. To calculate d, we need to use Euler's totient function φ(n), which is defined as the number of positive integers less than n that are coprime to n. In RSA, φ(n) is calculated as (p-1) × (q-1).

To find d, we can use the extended Euclidean algorithm to calculate the modular inverse of e (public key exponent) modulo φ(n):

e × d ≡ 1 (mod φ(n))

Substituting the given values, we have:

φ(n) = (101-1) × (113-1) = 11200

e = 7467

We need to find d such that:

7467 × d ≡ 1 (mod 11200)

Using the extended Euclidean algorithm, we get:

11200 = 1 × 7467 + 3733
7467 = 2 × 3733 + 1
1 = 7467 - 2 × 3733

So, d = 7473 (Note: we add 11200 to d to ensure it is positive)

Now, we can decrypt the ciphertext using the RSA decryption formula:

plaintext = (5859⁷⁴⁷³) mod 11413

Using modular exponentiation, we can calculate:

(5859⁷⁴⁷³) mod 11413 = 7648

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Answer:

Explanation:

"Safety helmet" redirects here. It is not to be confused with hard hat.

Drug Enforcement Administration (DEA) agents wearing Level B hazmat suits

Personal protective equipment (PPE) is protective clothing, helmets, goggles, or other garments or equipment designed to protect the wearer's body from injury or infection. The hazards addressed by protective equipment include physical, electrical, heat, chemicals, biohazards, and airborne particulate matter. Protective equipment may be worn for job-related occupational safety and health purposes, as well as for sports and other recreational activities. "Protective clothing" is applied to traditional categories of clothing, and "protective gear" applies to items such as pads, guards, shields, or masks, and others. PPE suits can be similar in appearance to a cleanroom suit.

The purpose of personal protective equipment is to reduce employee exposure to hazards when engineering controls and administrative controls are not feasible or effective to reduce these risks to acceptable levels. PPE is needed when there are hazards present. PPE has the serious limitation that it does not eliminate the hazard at the source and may result in employees being exposed to the hazard if the equipment fails.[1]

Any item of PPE imposes a barrier between the wearer/user and the working environment. This can create additional strains on the wearer; impair their ability to carry out their work and create significant levels of discomfort. Any of these can discourage wearers from using PPE correctly, therefore placing them at risk of injury, ill-health or, under extreme circumstances, death. Good ergonomic design can help to minimise these barriers and can therefore help to ensure safe and healthy working conditions through the correct use of PPE.

Practices of occupational safety and health can use hazard controls and interventions to mitigate workplace hazards, which pose a threat to the safety and quality of life of workers. The hierarchy of hazard controls provides a policy framework which ranks the types of hazard controls in terms of absolute risk reduction. At the top of the hierarchy are elimination and substitution, which remove the hazard entirely or replace the hazard with a safer alternative. If elimination or substitution measures cannot apply, engineering controls and administrative controls, which seek to design safer mechanisms and coach safer human behavior, are implemented. Personal protective equipment ranks last on the hierarchy of controls, as the workers are regularly exposed to the hazard, with a barrier of protection. The hierarchy of controls is important in acknowledging that, while personal protective equipment has tremendous utility, it is not the desired mechanism of control in terms of worker safety.rly PPE such as body armor, boots and gloves focused on protecting the wearer's body from physical injury. The plague doctors of sixteenth-century Europe also wore protective uniforms consisting of a full-length gown, helmet, glass eye coverings, gloves and boots (see Plague doctor costume) to prevent contagion when dealing with plague victims. These were made of thick material which was then covered in wax to make it water-resistant. A mask with a beak-like structure which was filled with pleasant-smelling flowers, herbs and spices to prevent the spread of miasma, the prescientific belief of bad smells which spread disease through the air.[2] In more recent years, scientific personal protective equipment is generally believed to have begun with the cloth facemasks promoted by Wu Lien-teh in the 1910–11 Manchurian pneumonic plague outbreak, although many Western medics doubted the efficacy of facemasks in preventing the spread of disease.[3]

Types

Personal protective equipment can be categorized by the area of the body protected, by the types of hazard, and by the type of garment or accessory. A single item, for example boots, may provide multiple forms of protection: a steel toe cap and steel insoles for protection of the feet from crushing or puncture injuries, impervious rubber and lining for protection from water and chemicals, high reflectivity and heat resistance for protection from radiant heat, and high electrical resistivity for protection from electric shock. The protective attributes of each piece of equipment must be compared with the hazards expected to be found in the workplace. More breathable types of personal protective equipment may not lead to more contamination but do result in greater user satisfaction.[4]

The use of a faulty PPE could be just as dangerous as not using any PPE at all because the user is still exposed to potential hazards and harm.

PPE is an acronym for personal protective equipment and it can be defined as a terminology that is used to denote any piece of equipment which offer protection to different parts of the body while working in a potentially hazardous environment.

Some examples of personal protective equipment (PPE) used to protect the different parts of the body are:

According to OSHA, the use of a faulty PPE could be just as dangerous as not using any PPE at all because the user is offered little or no protection at all.

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answer

d just too the test

a) hardware

The physical layer is the lowest layer of the OSI model, which defines the communication protocol used in computer networks.

It is responsible for the transmission and reception of raw bit streams over a physical medium, such as copper wires, optical fibers, or radio waves.

The physical layer includes all the physical components that make up a computer network, including cables, connectors, network interface cards, switches, routers, and other devices.

These components are collectively known as "hardware," which refers to any physical device that can be touched or seen. In the context of information systems, hardware is the physical infrastructure that supports the storage, processing, and communication of data.

Examples of hardware in an information system include servers, workstations, printers, scanners, and other peripheral devices.

Therefore, the correct answer to the question is "a) hardware."

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A thorough examination of a large region that could be utilized as a road or an airport is called a reconnaissance survey.

What is the goal of the reconnaissance survey?

Its goal is to discover the more attractive routes or places while excluding the unworkable or impractical options. Existing maps and aerial photos could be very helpful.

The following are the fundamentals of the reconnaissance survey:

Since the examination is an important part of reconnaissance survey is considered the important aspect

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Explanation:

Work = Force * distance

        = 5 N * 1 m = 5 J

Answer:

Explanation:uhhhhhh all?

Answer:

The total force resisted by the flange bolts is  163.98 N

Explanation:

Solution

The first step is to find  the pipe cross section at the inlet section

Now,

A₁ = π /4 D₁²

D₁ =  diameter of the pipe at the inlet section

Now we insert 8 cm for D₁ which gives us A₁ = π /4 D (8)²

=50.265 cm² * ( 1 m²/100² cm²)

= 5.0265 * 10^⁻³ m²

Secondly, we find cross section area of  the pipe at the inlet section

A₂ = π /4 D₂²

D₂ =  diameter of the pipe at the inlet section

Now we insert 5 cm for D₁ which gives us A₁ = π /4 D (5)²

= 19.63 cm² * ( 1 m²/100² cm²)

= 1.963 * 10^⁻³ m²

Now,

we write down the conversation mass relation which is stated as follows:

Q₁ = Q₂

Where Q₁ and Q₂ are both the flow rate at the exist and inlet.

We now insert A₁V₁ for Q₁ and A₂V₂ for Q₂

So,

V₁ and V₂ are defined as the velocities at the inlet and exit

We now insert 5.0265 * 10^⁻³ m² for A₁ 5 m/s for V₁ and 1.963 * 10^⁻³ m² for A₂

= 5.0265  * 5 = 1.963 * V₂

V₂ = 12.8 m/s

Note: Kindly find an attached copy of the part of the solution to the given question below

Answer: I believe the answer is 963.75 if I am reading the question right.

Explanation:

ACH=60L/V

ACH=2.25

V=25,700

25,700*2.25=57,825

57,825/60=963.75

L=963.75

60(963.75)/25,700=2.25

The maximum amount of air leakage that would result in an ACH of no more than 2.25 would be approximately 956.25 cfm (cubic feet per minute).

Given that ACH of a house is a measure of its​ air-tightness and the formula for ACH is ACH = 60L/V. It means that ACH is inversely proportional to air-tightness or leakage. Therefore, the lower the air leakage the higher the ACH and vice versa.Mathematically, it is represented as:ACH ∝ 1/L or L ∝ 1/ACH

We can solve the question as follows:ACH = 2.25 (since the maximum ACH is 2.25)The volume of the house, V = 25,700 cubic feet.Substituting in the formula,2.25 = 60L/25,700Dividing both sides by 2.25 gives us,L = (2.25 * 25,700)/60L = 956.25 cubic feet per minute (cfm)

Therefore, the maximum amount of air leakage that would result in an ACH of no more than 2.25 is approximately 956.25 cfm (cubic feet per minute).

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Answer:

Mach number = 0.68168

The flow should be treated as compressible.

Explanation:

Given that:

The altitude of a commercial jet = 35000

The properties of air at that given altitude are as follows:

Pressure = 24.577 kPa

Temperature T = 50.78176° C

Temperature T = ( 50.78176 + 273 )K = 328.78176 K

\(\varphi = 0.38428 \ kg/m^3\)

The velocity is also given as: 550 mph = 245.872 m/s

Therefore, the sonic velocity is firstly determined by using the formula:

\(a = \sqrt{ \vartheta \times R \times T\\)

\(a = \sqrt{1.4 \times 287 \times 323.78176\)

\(a = \sqrt{130095.5112\)

a = 360.68755 m/s

Then, we can calculate the Mach number by using the expression:

\({Mach \ number = \dfrac{V}{a}}\)

\(Mach \ number = \dfrac{245.872}{360.68755}\)

Mach number = 0.68168

b) Ideally, all flows are compressible because the Mach number is greater than 0.3, suppose the Mach number is lesser than 0.3, then it is incompressible.

Therefore, roughly 12 drain holes with a diameter of 0.4 inches would be required to prevent the sink from overflowing with water.

Two gal of water per minute enter the sink. The water will eventually go through the overflow drain holes if the drain is closed as opposed to over the edge of the sink. number of 0.4-in.

Equation: The rate of flow through a circular hole can be determined.

\(Q = C \times A \times \sqrt{(2gH) (2gH)}\)

Calculate the following to determine the cross-sectional area of a hole with dimension d:

\(A = \frac{\pi}{4} \times d^2\)

To prevent the water from overflowing the sink, we can set the flow rate through each hole to be equal to the incoming flow rate and solve for the necessary number of holes.

\(n = \frac{2}{(0.61 \times \frac{\pi}{4} \times 0.16 \times \sqrt{(64.4 \times 6)})}\)

  \(= \frac{2}{(0.61 \times \frac{\pi}{4} \times 0.16 \times 2.51)}\)

  ≈ 12

where,

2 gal/min

\(= n \times C \times \frac{\pi}{4} \times d^{2} \times \sqrt{(2gH)}\)

Now,

\(n = \frac{2}{C \times \frac{\pi}{4} \times d^{2} \times \sqrt{(2gH)}}\)

  \(= \frac{2}{(0.61 \times \frac{\pi}{4} \times (0.4^{2}\ i\ n^2) \times \sqrt{(2 \times 32.2 \times H)})}\)

  \(= \frac{2}{(0.61 \times \frac{\pi}{4} \times 0.16 \times \sqrt{(64.4 \times H)})}\)

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Proper, smooth shifting is important because shifting before your vehicle is ready will cause it to je-rk forward and your drive wheels may lock.

A proper, smooth shifting of the gears of an automobile vehicle is very important because shifting them before the vehicle is ready would cause the following:

As a good driver, proper, smooth shifting is important because shifting before your vehicle is ready will cause it to je-rk forward and your drive wheels may lock.

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A Master of Science (MS) program in information security is typically focused on providing students with advanced technical skills and knowledge in the field of information security.

This may include topics such as computer systems and network security, cryptography, data security, and risk management. An MS program in information security is typically geared towards preparing students to perform information security work, such as designing and implementing security systems, conducting security assessments, and responding to security incidents.

On the other hand, a Master of Business Administration (MBA) program is typically focused on providing students with business and management skills and knowledge. This may include topics such as finance, marketing, operations, and strategy. An MBA program is typically geared towards preparing students to manage and maintain the people and environment of information security. This may include tasks such as developing and implementing security policies, managing security budgets, and leading security teams.

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Answer:

Hooke’s Law

Explanation:

Hooke's law explains that the strain of the material is proportional to the applied stress within the elastic limit of that material. When the elastic materials are stretched, the atoms and molecules deform until stress is applied, and when the stress is removed, they return to their initial state.

As per Phil, the method used for measuring parallax angle allows to determine the positions of stars. The correct answer is a. 1000 light years.

Parallax is a method used for measuring two angles and sides of a triangle formed by the star,  and earth six months later. Astronomers find the distance of nearby stars in the space by using a parallax method as the distance of star increases, the parallax angle decreases, and great degree of accuracy is required for its measurement. Keeping in view the practical limitation in measuring the parallax angle, the maximum distance of a star we can measure by parallax method is limited to 100 light year

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Technician A states that this may be because the damaged thread is located in a large expensive component is correct.

If a thread's damage is minor, it might be feasible to reform the threads by passing a nut upward as well as downward, but doing so carries the risk of the nut gluing to the thread. Damaged threads on screws and bolts can frequently be repaired by running a die over them (galling).

Note that for one to be able replace a damaged part, it may be that the thread is seen in a large, expensive part , such as the engine block or cylinder head and thus it can be difficult.

Therefore, Technician A states that this may be because the damaged thread is located in a large expensive component is correct.

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Answer:

2200 watts

Explanation:

# of Watts = Volts × Amps

Have a lovely rest of your day/night, and good luck with your assignments! ♡

The thread is crucial for ensuring the quality and durability of the garment. It is formed by spinning and twisting fibers together, creating a continuous strand that is used to hold the various components of the garment together.

The quality of the thread directly affects the overall quality of the garment. A strong and well-constructed thread is essential for providing structural integrity and preventing the garment from unraveling or falling apart over time. It must be able to withstand the stresses and strains that occur during regular use, including stretching, pulling, and washing.

When choosing the appropriate thread for a garment, several factors are considered, including the type of fabric, the intended use of the garment, and the desired aesthetic. Different threads have varying levels of strength, elasticity, and resistance to abrasion. For example, a heavier fabric might require a thicker and more robust thread, while a delicate fabric may require a finer and more delicate thread to prevent damage.

The quality of the thread also relates to its consistency and uniformity. Irregularities in the thread's thickness or tension can result in uneven stitches, which may compromise the appearance and functionality of the garment. In addition, the thread's color and texture should be chosen carefully to complement the fabric and enhance the overall aesthetic appeal.

In the manufacturing process, quality control measures are implemented to ensure that the thread meets the required standards. This involves testing the thread for strength, colorfastness, and resistance to abrasion. By using high-quality thread and maintaining strict quality control, garment manufacturers can ensure that the final product meets or exceeds the expectations of customers in terms of both appearance and durability.

In summary, the thread plays a vital role in holding a garment together and contributes significantly to its quality and longevity. Choosing the right thread and ensuring its consistent quality throughout the manufacturing process are essential for creating garments that are durable, aesthetically pleasing, and able to withstand regular use.

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A worm gear clamp is a type of clamp that can be adjusted using a nut driver.

A common type of clamp that can be adjusted using a nut driver is a worm gear clamp. This type of clamp consists of a metal band with a series of raised ridges, and a screw mechanism with a slotted head.

By using a nut driver, you can turn the screw, which tightens or loosens the clamp by drawing the band closer or further apart. The ridges on the band interlock with the screw, providing a secure and adjustable grip.

Worm gear clamps are commonly used in automotive, plumbing, and other applications where a reliable and adjustable clamping force is required.

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Answer:

what are the answers?

Explanation:

Answer:

Weight Percentage of Ash = 3.4

Explanation:

Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.

To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?

Solution -

Given that,

Coal Burned Rate = 10,000 kg/hr

                              = \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)

                              = 166.6666 kg/min

⇒Coal Burned Rate = 166.6666 kg/min

Now,

Given that,

Ash content in coal = 21 %

⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min

                                             = 34.9999 ≈ 35 kg/min

⇒Ash in (coal that burned) = 35 kg/min

Now,

We know,

Density of water = 1000 kg/m³

Now,

Water flow Rate = \(1\frac{m^{3} }{min} * density\)

                           = 1000 kg/min

⇒Water flow Rate = 1000 kg/min

Now,

Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min

                                                                           = 1035 kg/min

⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min

So,

Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100

                                            = (35 ÷ 1035) × 100

                                            = 3.38 ≈ 3.4

∴ we get

Weight Percentage of Ash = 3.4

The reaction effluent goes to a condenser from which two streams emergers a liquid product stream containing essentially all of the methanol formed in the reactor, and a gas stream containing all of the CO, H2 leaving the reactor.

A methanol synthesis loop with a stoichiometric feed of CO and H2 is to be designed for 95% overall conversion of CO. All the methanol formed leaves in the product stream.

Not more than 2% of the CO and 0.5% of the H2 emerging form the reactor is to leave in the product stream- the remainder is recycled.

Therefore, The reaction effluent goes to a condenser from which two streams emergers a liquid product stream containing essentially all of the methanol formed in the reactor, and a gas stream containing all of the CO, H2 leaving the reactor.

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