a balloon will stick to a wooden wall if the balloon is charged negatively. positively. either positively or negatively. none of the above choices are correct.
Answers
A balloon will stick to a wooden wall if the balloon is charged either positively or negatively.
This occurs due to the principle of electrostatic attraction. When the balloon is charged (either positively or negatively), it creates an imbalance of charges between the balloon and the wooden wall. This causes the charges in the wall to rearrange themselves to be opposite the charge of the balloon. As a result, the opposite charges attract, and the balloon sticks to the wall.
Electrostatic attraction is the force of attraction between two electrically charged objects or particles due to their opposite charges. When two objects with opposite charges come near each other, the electric field created by one object induces an opposite charge on the other object.
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If a balloon is charged positively or negatively, it will adhere to a wooden wall.
The electrostatic attraction concept is what causes this to happen. There is an imbalance of charges between the balloon and the wooden wall when the balloon is charged, either positively or negatively. As a result, the charges in the wall are repositioned so that they are in opposition to the charge of the balloon. The balloon attaches to the wall as a result of the attraction between the opposing charges.
The force that draws two electrically charged objects or particles together due to their opposing charges is known as electrostatic attraction. When two items with opposing charges are brought close to one another, the electric field produced by one of the objects causes the other object to acquire the opposing charge.
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Related Questions
methane at 1 mpa, 250 k is throttled through a valve to 100 kpa. assume no change in the kinetic energy. what is the exit temperature?
Answers
Answer:
When a gas undergoes throttling, there is no heat transfer between the gas and its surroundings, and there is no work done by or on the gas. Therefore, the throttling process is considered to be adiabatic and isenthalpic.
In this problem, the initial state of the methane is given as P1 = 1 MPa, T1 = 250 K, and the final pressure is P2 = 100 kPa. Since the process is isenthalpic, we can use the following equation to relate the initial and final temperatures:
H1 = H2
where H is the enthalpy of the gas. Since the kinetic energy of the gas is assumed to be constant, the enthalpy can be approximated as:
H = U + PV
where U is the internal energy of the gas and P and V are its pressure and volume, respectively.
Using the ideal gas law, we can relate the pressure, volume, and temperature of the gas:
PV = nRT
where n is the number of moles of gas and R is the gas constant. Since the mass of the gas is not given, we can assume a convenient value such as 1 kg. The number of moles of methane can then be calculated as:
n = m/M
where m is the mass of the gas and M is its molar mass. For methane, M ≈ 16 g/mol.
Substituting the ideal gas law into the expression for enthalpy, we get:
H = U + nRT
Since the process is isenthalpic, we can set H1 = H2 and simplify:
U1 + nRT1 = U2 + nRT2
The internal energy of an ideal gas is a function of temperature only, so we can write:
U1 = U2
Substituting and rearranging, we get:
T2 = (P2/P1) * T1
T2 = (100 kPa / 1 MPa) * 250 K
T2 ≈ 25 K
Therefore, the exit temperature of the methane after throttling is approximately 25 K.
5. A coil of resistance wire is immersed in liquid in a calorimeter of a total heat capacity 950JK. If the temperature rises from 9°C to 29°C in 5 minutes when a steady current of 4A is passed, find: (i) The resistance of the coil
Answers
Answer:
0.495 Ω.
Explanation:
To solve this problem, we will use the formula for heat:
Q = mcΔT
Where Q is the heat transferred, m is the mass of the liquid, c is the specific heat capacity of the liquid, and ΔT is the change in temperature.
Since the calorimeter has a total heat capacity of 950 J/K, we can write:
Q = 950ΔT
where ΔT is the temperature change of the calorimeter.
The heat generated by the coil can be calculated using the formula:
Q = I²Rt
where I is the current, R is the resistance of the coil, and t is the time the current is passed.
Substituting the given values, we get:
Q = (4A)²R(5min*60s/min) = 960Rs
where Rs is the heat generated per unit resistance.
Since the heat generated by the coil is transferred to the calorimeter, we can equate the two expressions for Q:
960Rs = 950ΔT
Solving for R, we get:
R = (950ΔT) / (960s)
Substituting the given values, we get:
R = (950J/K * (29°C - 9°C)) / (960s * 4²)
R = 0.495 Ω
Therefore, the resistance of the coil is 0.495 Ω.
Answer: the resistance of the coil is 300 ohms.
Explanation:
We can use the formula for heat generated by a resistor to find the power generated by the coil:
P = I^2 * R
where P is power, I is current, and R is resistance.
The power generated by the coil will be equal to the heat absorbed by the liquid in the calorimeter:
P = Q/t
where Q is the heat absorbed, and t is the time.
We can use the formula for heat absorbed by a substance to find the heat absorbed by the liquid:
Q = C * m * ΔT
where Q is the heat absorbed, C is the specific heat capacity of the liquid, m is the mass of the liquid, and ΔT is the change in temperature.
We are given the total heat capacity of the calorimeter, which is equal to the sum of the heat capacities of the liquid and the calorimeter:
C_total = C_liquid + C_calorimeter
We can rearrange this equation to solve for the specific heat capacity of the liquid:
C_liquid = C_total - C_calorimeter
Plugging in the given values, we get:
C_liquid = 950 J/K - unknown
We need to find the unknown value of C_calorimeter in order to solve for the specific heat capacity of the liquid. We can do this by using the formula for heat absorbed:
Q = C_total * ΔT
where Q is the heat absorbed by the calorimeter and the liquid, and ΔT is the change in temperature of the calorimeter and the liquid.
Plugging in the given values, we get:
Q = 950 J/K * (29°C - 9°C) = 19000 J
The power generated by the coil is:
P = I^2 * R = 4^2 * R = 16R
The heat absorbed by the liquid is:
Q = P * t = 16R * 300 s = 4800R J
Setting these two equations equal to each other, we get:
16R = 4800R
Dividing both sides by 16, we get:
R = 300 ohms
Therefore, the resistance of the coil is 300 ohms.
Which type of wave has particles moving in an elliptical or circular motion?
O surface
o longitudinal
O sound
O transverse
Answers
\(\huge \rm༆ Answer ༄\)
The Correct choice is ~
\( \sf \boxed{ \sf surface \: \: wave}\)
_________________________________
\( \\ \\ \\ \\ \\ \\\)
\( ꧁ \:\large \cal{Kaul}\: ꧂\)
\(\huge\bold\purple{answer} \)
Option A : surface
A surface wave is a wave in which particles of the medium undergo a circular motion.a heat engine accepts heat from a source at a rate of 500 kw, and it rejects heat to a sink at a rate of 300 kw. the remainder of the heat is converted to net work output. determine the thermal efficiency of the engine. multiple choice question. 40% 20% 30% 60%
Answers
The thermal efficiency of the engine is 40%. The correct answer is (a).
The thermal efficiency of a heat engine is given by:
efficiency = (net work output) / (heat input)
We are given the heat input rate as 500 kW and the heat output rate as 300 kW. The net work output rate can be found by subtracting the heat output rate from the heat input rate:
net work output = heat input - heat output = 500 kW - 300 kW = 200 kW
Substituting these values into the efficiency equation, we get:
efficiency = 200 kW / 500 kW = 0.4 = 40%
Option a is correct.
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Mass 2 has a mass of 1.00 kg. Mass 2 rolls
across the surface with no friction or
resistance. If the acceleration of Mass 2 is
downward at 2.50 m/s?, determine...
a) The tension in the string
b) The mass of Mi
Answers
Answer:
please take clean picture
A weight of mass 1.71 kg is suspended by a string wrapped around a pulley wheel, which consists of a solid disk of mass 4.83 kg and radius 0.689 m. the system is released from rest. over what vertical distance does the hanging mass move in 3.0 seconds? ignore friction and drag forces, and assume that the string does not slip.
Answers
The hanging mass moves at 6.925 meters vertically in 3.0 seconds.
How do we calculate?Mass of hanging weight (m1) = 1.71 kg
Mass of pulley wheel (m2) = 4.83 kg
Radius of pulley wheel (r) = 0.689 m
Time (t) = 3.0 seconds
We have that d = (1/2) * a * t²
We know that a = linear acceleration and
a = (m1 * g) / (m1 + m2)
a = (1.71 kg * 9.8 m/s²) / (1.71 kg + 4.83 kg)
a = 1.534 m/s²
We then substitute the values of a and t into the equation for distance :
distance = (1/2) * 1.534 m/s² * (3.0 s)²
distance = 6.925 m
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How much work is required to lift a 35-kg object from the ground 3.0-m into the air?
Also; How much Gravitational Potential Energy did the object gain?
Answers
The amount of work required to lift the object is 1029 J. And the amount of potential energy gained by the object is 1029 J.
What is work?Work can be defined as the product of force and distance. The s.i unit of work is Joules (J).
To calculate the amount of work required to lift the object, we use the formula below.
Formula:
W = mgh........... Equation 1Where:
P.E = work required to lift the objectm = mass of the objecth = height of the objectg = acceleration due to gravityFrom the question,
Given:
m = 35 kgh = 3 mg = 9.8 m/s²Substitute these values into equation 1
W = 35×3×9.8W = 1029 J.The amount of gravitational potential energy gained by the object is the same s the amount of work required to lift the object
Therefore,
P.E = W = 1029 JHence, The amount of work required to lift the object is 1029 J. And the amount of potential energy gained by the object is 1029 J.
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Objects x and y are connected by a string of negligible mass and suspended vertically over a pulley of negligible mass, creating an atwood’s machine, as shown in the figure. The objects are initially at rest, and the mass of object y is greater than the mass of object x. As object y falls, how does the gravitational potential energy of the object x-object y-earth system change? all frictional forces are considered to be negligible.
Answers
We have that the gravitational potential energy effect on the system is mathematically given as
The gravitational potential energy decreases because the center of mass of Object X and Object Y moves downward.Option C
From the question we are told
The objects are initially at rest, and the mass of object y is greater than the mass of object x. As object y falls, how does the gravitational potential energy of the object x-object y-earth system change? all frictional forces are considered to be negligible.Centre of massDue to reduce in top of Y, doable strength will limit and due to amplify in peak of X, achievable power will increase.
Now, PE = mgh.
Generally the equation for the Velocity of centre of mass is mathematically given as
\(V =\frac{ m1v1 + m2v2}{ m1 + m2}\\\\Therefore \\\\V =\frac{ (m1 - m2) v}{ m1 + m2}\)
Hence, V is positive as m1 > m2
Therefore
centre of mass of system moves downwards.The conclusion
The gravitational potential energy decreases because the center of mass of Object X and Object Y moves downward.
Option C
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Complete QuestionObjects X and Y are connected by a string of negligible mass and suspended vertically over a pulley of negligible mass, creating an Atwood’s machine, as shown in the figure.
The objects are initially at rest, and the mass of Object Y is greater than the mass of Object X. As Object Y falls, how does the gravitational potential energy of the Object Y-Object Y-Earth system change? All frictional forces are considered to be negligible.
a
The gravitational potential energy increases because the center of mass of Object X and Object Y moves upward.
b
The gravitational potential energy increases because the center of mass of Object X and Object Y moves downward.
c
The gravitational potential energy decreases because the center of mass of Object X and Object Y moves downward.
d
The gravitational potential energy decreases because the center of mass of Object X and Object Y moves upward.
the oracle equivalent to an ms access autonumber is a(n)
Answers
A Sequence in Oracle is a database object that generates a sequence of unique numbers. The Oracle equivalent to an MS Access Autonumber is a "Sequence" object.
In MS Access, an Autonumber field automatically generates a unique numeric value for each record added to a table. It ensures that each record has a distinct identifier. In Oracle, the equivalent functionality is achieved using a "Sequence" object.
A Sequence in Oracle is a database object that generates a sequence of unique numbers. It can be used to generate primary key values or any other numeric identifier. Similar to an Autonumber field, a Sequence in Oracle automatically generates a new number each time it is accessed. It provides a reliable way to assign unique values to records.
To use a Sequence in Oracle, you typically associate it with a column in a table, specifying the Sequence as the default value for that column. When a new record is inserted into the table, the Sequence generates a new unique number for the associated column.
Therefore, the Oracle equivalent to an MS Access Autonumber is a "Sequence" object, which generates unique numeric values for records in a similar manner as the Autonumber field in MS Access.
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what is the answer of this
a car is travelling at a speed 38.0×10⁸m/s on an interstate highway where the speed limit is 75.0 mi/h. is the driver exceeding the speed limit
Answers
Answer:
He exceeded the speed limit
Explanation:
\({ \tt{ \frac{38 \times {10}^{8} \: m }{1 \: s} }} = { \tt{ \frac{ \frac{1}{1609} \: mi}{ \frac{1}{3600} \: hr} }} \\ \\ { \tt{ = ( \frac{1}{1609} \times 38 \times {10}^{8} ) \times (3600)}} \\ \\ = 8.5 \times {10}^{9 } \: mih {}^{ - 1} \)
What is a living factor in the environment
Answers
Answer:
A living factor in the environment refers to any living organism or species that play a role in the ecosystem and contributes to the balance of the natural environment. Examples of living factors in the environment include plants, animals, fungi, and microorganisms.
What natural process is responsible for the shape of the mushroom rock?
(PLEASE HELP ME!!!!!)
Answers
Answer:
A mushroom rock, rock pedestal, or gour is a typical mushroom-shaped landform that is formed by the action of wind erosion. ... In some cases, harder rocks are arranged horizontally over a softer rock, resulting in such erosion.
Explanation:
Answer:
wind erosion
Explanation:
You observe that exoplanet A has satellite B.We measure the
period at which satellite B orbits around planet A, and it is 7.14
days. Let's assume that the orbital is fully constant-speed
circular moti
Answers
Satellite B orbits exoplanet A in a circular motion with a constant speed, completing one orbit every 7.14 days.
The period of satellite B's orbit around exoplanet A is 7.14 days. This means that it takes 7.14 days for the satellite to complete one full revolution around the planet. The fact that the orbit is described as "constant-speed circular motion" indicates that the satellite moves in a circular path around the planet with a consistent speed. In a circular orbit, the satellite maintains a fixed distance from the planet throughout its journey. The orbital speed of the satellite remains constant, meaning that it covers equal distances in equal intervals of time. This behavior is consistent with the laws of planetary motion, particularly Kepler's laws, which govern the motion of objects in space. Therefore, based on the given information, we can conclude that satellite B consistently completes one orbit around exoplanet A every 7.14 days in a circular path with a constant speed.
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A 65-year-old man's energy intake should focus on meals:a.) high in calories with nutrient-dense foodsb.) low in calories and high in fiber and meatc.) with a lower caloric density and increased nutrient densityd.) high calorie level for middle age with lowered nutrient density
Answers
A 65-year-old man's energy intake should focus on meals c.) with a lower caloric density and increased nutrient density
Calorie density represents a metric that is employed to determine how many calories are contained in a given amount of food. For a 65-year-old male, meals with a lower calorie density and a higher nutritional density would be ideal. People's metabolisms tend to slow down as they become older, so they need fewer calories.
To preserve their health, they still require enough nourishment, though. By choosing foods that are high in nutrients yet low in calories, such as fruits, vegetables, whole grains, lean proteins, and healthy fats, one may meet nutritional needs while limiting calorie intake. Adding more fibre to your diet can also help ya person to lose weight and maintain good digestive health.
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HELPPPPPPP!!!!!
why are cations drawn towards cathode and anions towards anode?
Answers
Explanation:
Cations are positive and anions are negative, since opposite charged attract, the cations are drawn towards the cathode, which is the negatively charged electrode and anions are drawn towards the anode (positive electrode)
Answer:
because cations are negatively charged particles and their attracted towards a positive electrode that is anode while anions and positively charged particles and I attracted towards the negative electrode that is cathode
Explanation:
Q2. Fill in the blanks:
North Pole of a magnet will.....
.. North pole of another magnet.
South Pole of a magnet will.
North pole of a another magnet.
Needle of a compass lines up with the......
of a magnet.
You can find the shape of a magnetic field using........
...... and also a plotting.
Answers
Answer:
repel , attract,l am sure with these two blanks only
Answer:
Magnetic fields
A magnet creates a magnetic field around it. You cannot see a magnetic field, but you can observe its effects. A force is exerted on a magnetic material brought into a magnetic field. The force is a non-contact force because the magnet and the material do not have to touch each other.
a stone attached to 1m long string is moving with the speed of 5ms in a circle find the centripetal acceleration of the stone
Answers
Answer:
The centripetal acceleration of the stone is 5 m/s²
Explanation:
The length of the string to which the stone is attached, r = 1 m
The speed with which the string is rotated, v = 5 m/s
The centripetal acceleration, \(a_c\), is given as follows;
\(a_c = \dfrac{v^2}{r}\)
Therefore, the centripetal acceleration of the stone found as follows;
\(a_c = \dfrac{(5 \ m/s)^2}{1 \ m} = 5 \ m/s^2\)
The centripetal acceleration of the stone, \(a_c\) = 5 m/s².
what is the kinetic energy of a flying bird of mass 600g flying with velocity of 10m/s
Answers
Answer:
30 J
Explanation:
You have to transform g in kg, so 600 g=0,6 kg
the kinetic energy value is
K= ½ mv² so it is K=½ (0.6×100)=30 J
\(\text{Kinetic energy,}\\\\~~~~~~E_k = \dfrac 12 mv^2\\\\~~~~~~~~~~=\dfrac 12 \times 6\times 10^{-1} \times 10^2~~~~~~~;[m = 600 g = 600 \times 10^{-3}~ \text{kg} = 6\times 10^{-1}~ \text{kg}]\\\\~~~~~~~~~~=\dfrac{60}2\\\\~~~~~~~~~~= 30~ J\)
Dans car has broken down. He decides to push it to a garage 800m away qlong a flat road. He pushes the car with qn average force of 600N. What is the smallest amount of work he must do to get the car into the garage
Answers
Answer:
Answer = 480000 joule.
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what is the gravitational acceleration on a planet where a 2-kilogram mass has a weight of 16 newtons on the planet's surface, in meters per second squared?
Answers
The gravitational acceleration of the planet on an object of mass 2 kg is 8 m/s²
The mass of the object = 2 kg
The weight of the object on that planet = 16 N
The gravitational acceleration can be found using the formula,
W = mg
where W is the weight of the object on that planet
m is the mass of the object
g is the gravitational acceleration
Let us rearrange the above equation,
g = W/m
Let us substitute the known values in the above equation, we get
g = 16 / 2
= 8 m/s²
Therefore, the gravitational acceleration of the planet is 8 m/s²
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I'll give brainliest!
During the last 5 million years, how often have the poles reversed
themselves?
5
20
10
15
Answers
the answer to this problem is 15
Answer:itts 20 15 is incorrect ill show u proof
Explanation:
An 1.1 kW dryer is used for 30 minutes every day. What would Georgia Power charge for the month (30 days) if their going rate is 11 cent/kWhr?
Answers
Answer:
$108.90
Explanation:
step 1. multiply kw by rate of change ( 1.1kw x .11 = .121)
step 2. multiply the product above by the time use which is 30 mins in this case so .121 x 30 = 3.63
step 3. last step is to multiply the product you just got by the time per month soooo 3.63 times 30 days = 108.90 :)
The power charge of the dryer for a month for a period of 30 minutes every day will be 108.9 watts.
What is Electric power?
Electric power is the rate at which the electrical energy is transferred by an electric circuit. The SI unit of power is the watt, one watt is equal to one joule per second.
The amount of power rate for one minute = 1.1 × 11/100 = 1.1 × 0.11 = 0.121 watts
The amount of power rate for 30 minutes = 0.121 × 30 = 3.63 watts
The power rate for 30 days = 3.63 × 30 = 108.9 watts
Therefore, the power charge for the month is 108.9 watts.
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The pattern shown in the photo is the result of a time-lapsr video of a clear night sky
Which mostly likely causes the apparent motion of the stars seen in this photo?
A. Earth's revolution around the Sun
B. The revolution of the Stars around the Sun
C. Earth's rotation on its axis
D. The revolution of the stars
around Earth
Answers
Answer:
C.
Explanation:
Answer:
C
Explanation:
The earths rotation on its axis
A 100g mass is attached to a string that is 75 cm long. The mass is swung in a horizontal circle that goes around once every 0.80 seconds.
What is the centripetal acceleration of the mass?
What is the tension in the string?
Answers
Answer:
Centripetal acceleration = 46.26m/s2
Tension = 4.6N
Explanation:
Centripetal acceleration is given by the following formula: \(a_c = \frac{v^2}{r}\)
So, to calculate acceleration we first need velocity and radius.
The radius is given to us as 75cm = 0.75m, and we can find velocity from the following formula:\(v=r\omega\) where w = the angular velocity given by: \(\omega = \frac{2\pi}{T}\)
We are given a period of 0.80s, meaning that our angular velocity is:
\(\frac{2\pi}{0.80} = 7.85 rad s^{-1}\)
Now we just need to multiply is by the radius to find the velocity:
\(0.75*7.85=5.89ms^{-1}\)
Finally we square the velocity and divide by the radius to find the final centripetal acceleration: \(\frac{5.89^{2} }{0.75} =46.26ms^{-2}\)
\(F=\frac{mv^{2} }{r}\) so we just need to multiply the centripetal acceleration by mass to get the tension force of the string: \(46.26*0.1 = 4.6N\)
Hope this helped!
While undergoing a transition from the n = 1 to the n = 2 energy level, a harmonic oscillator absorbs a photon of wavelength 6. 90 μm. A. What is the wavelength of the absorbed photon when this oscillator undergoes a transition from the n = 2 to the n = 3 energy level?
Answers
The wavelength of the absorbed photon when the oscillator undergoes a transition from the n = 2 to the n = 3 energy level is 4.93 μm.
The energy of a photon with a particular wavelength is given by the equation:
E = hc/λ
where E is the energy of the photon, h is Planck's constant (6.626 x 10⁻³⁴ J s), c is the speed of light (2.998 x 10⁸ m/s), and λ is the wavelength of the photon.
When a harmonic oscillator undergoes a transition from the n = 1 to the n = 2 energy level, the energy absorbed is equal to the difference in energy between the two levels:
ΔE = E₂ - E₁ = hν
where ΔE is the energy absorbed, E₁ is the energy of the n = 1 level, E₂ is the energy of the n = 2 level, and ν is the frequency of the absorbed photon. Since the oscillator is a harmonic oscillator, the energy levels are given by the equation:
En = (n + 1/2)hν0
where En is the energy of the nth level, ν0 is the frequency of the oscillator, and n is an integer.
We can rearrange this equation to solve for the frequency of the oscillator:
ν₀ = En / ((n + 1/2)h)
For the n = 1 to n = 2 transition, we can set n = 1 and n = 2 to find the frequencies of the two levels:
ν₁ = E1 / (3/2 h)
ν₂ = E2 / (5/2 h)
Substituting the energy difference ΔE = hν and the wavelength λ = c/ν into these equations, we get:
ν₂ = (E₁ + ΔE) / (5/2 h) = (hc/λ + ΔE) / (5/2 h)
λ = hc / (ν₂ (5/2 h) - ΔE)
λ = (6.626 x 10⁻³⁴ J s x 2.998 x 10⁸ m/s) / ((1.5 x 6.90 x 10⁻⁶ m⁻¹) x (5/2 x 6.626 x 10⁻³⁴J s) - (4.64 x 10⁻¹⁹J))
λ = 4.93 μm
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7. The Earth orbits the sun at 25.42 km/s. What is this in mph (1 mile = 1.609
km)?
Answers
Answer:
40.90 mph if I did the math right
a cannonball is fired with a velocity of 551 m/s in the cannon is aimed 12° above the ground , how far away does the cannonball land?
Answers
The cannonball lands 12.4 km from the cannon if the cannonball is fired with a velocity of 551 m/s in the cannon is aimed 12° above the ground.
R = u² sin 2θ / g
R = Horizontal range
u = Initial velocity
θ = Angle made with ground
g = Acceleration due to gravity
u = 551 m / s
θ = 12°
g = 9.8 m / s²
R = 551² sin 2 ( 12° ) / 9.8
R = 303601 * 0.4 / 9.8
R = 12392 m
R = 12.4 km
The horizontal range of a projectile is the horizontal distance travelled by the projectile from the point from which it was launched. It is denoted by R.
Therefore, the cannonball lands 12.4 km from the cannon
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What Are You Doing With Your Life?
Answers
Answer:
Living it:) thats all
28) Refraction results from differences in light's. A) frequency. B) incident angles. C) speed. D) all of the above. E) none of the above.
Answers
Refraction results from differences in light's speed. The correct answer is C) speed.
Refraction is the term for the bending of light as it passes through transparent materials (it also occurs with sound, water, and other waves). We are able to create lenses, magnifying glasses, prisms, and rainbows because to this bending caused by refraction.
Refraction occurs when light passes through different mediums and changes its speed. This change in speed causes the light to bend, creating the effect of refraction.
This is why objects appear to be in different positions when viewed through water or a lens. The frequency and incident angles of the light do not affect refraction, only the speed of the light does.
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A crane does work at the rate of 2.5 x10^3 watts to lift a 200-newton weight vertically for duration of 8.0 seconds. Calculate the height the crane lifts the weight over this time period.
Answers
The height the crane lifts the weight over the time period of 8.0s is 100m when it does work at the rate of \(2.5 *10^3\) watts to lift a 200-newton weight.
Given the rate of work done by crane (P) = \(2.5 * 10^3\)watts
The force exerted to lift a weight (F) = 200N
The duration of which weight was lifted (t) = 8.0s
Let the height the crane lifts the weight during this period = h
Also power is calculated as work done per unit time such that: P = W/t
\(2.5 * 10^3 = W/8.0s\)
\(W = 2*10^4\)
We know that work done on any object = force x distance moved
Work: W = F * d
W = F * h where d = distance = h
\(h = 2 * 10^4/200 = 100m\)
Hence the height the crane lifts the weight over this time period is 100m
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