a ball of mass 0.5 kg, initially at rest, acquires a speed of 4 m/s immediately after begin kicked by a force of strength 20 n. for how long did this act on the ball?

A) Minimum recommended spiral parameter: 150.03m.

b) Distance P: 150.03m.

c) Distance Q: 4.122m.

d) Angle Φs: 16°30'14.0".

e) Distance Tc: 150.03m.

a) Calculation for the minimum recommended spiral parameter:

Design radius (R) = 300 m

Maximum superelevation (e_max) = 0.06 m/m

Spiral Parameter (A) = (R + e_max) / 2

A = (300 m + 0.06 m/m) / 2

A ≈ 150.03 m

b) Calculation for the distance P:

Distance P is equal to the length of the first spiral curve, which is the same as the minimum recommended spiral parameter.

P ≈ 150.03 m

c) Calculation for the distance Q:

Distance Q represents the length of the circular curve. It is given by the formula:

Q = (Deflection angle at Point of Intersection) / (Degree of Curve, D)

Deflection angle at Point of Intersection = 16°30'14.0"

Converting the angle to decimal degrees:

16° + (30'/60) + (14.0"/3600) = 16.504°

Q = 16.504° / (360° / D)

Q ≈ D / 21.814

Since the RAU80 has 4 lanes, the degree of curve (D) is 360° / 4 = 90°.

Q ≈ 90° / 21.814

Q ≈ 4.122 m

d) Calculation for the angle Φs:

The angle Φs is the deflection angle at the Point of Intersection.

Φs = 16°30'14.0"

e) Calculation for the distance Tc:

Distance Tc is equal to the length of the second spiral curve, which is the same as the minimum recommended spiral parameter.

Tc ≈ 150.03 m

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[Questoin 1] Volume

     "Charles's law is an experimental gas law that describes how gases tend to expand when heated." Expand = volume, so this answer is correct

[Question 2] b) move faster

     An increase in heat is an increase in energy, which is an increase in particle movement. This means that b is correct, because the particles will be moving faster

[Question 3] a) Celsius

     Charles' Law uses Celsius, so when doing Charles' Law problems you should use Celsius, aka °C

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

a. We have no genuine moral obligations to future generations. This means that there is no inherent ethical responsibility towards the well-being and interests of those who will come after us.

The statement suggests that we do not have any genuine moral obligations towards future generations. This perspective questions the ethical responsibility we have towards those who will come after us.

It implies that our actions and decisions should not be guided by considerations for the well-being and interests of future generations.

However, this view is subject to debate and ethical considerations vary among individuals and cultures.

It is important to note that moral obligations to future generations are often discussed within the context of sustainable development and intergenerational equity. Many argue that we have a responsibility to ensure the long-term viability of the planet and its resources for the benefit of future generations.

This includes addressing issues such as climate change, environmental degradation, and social justice. While different perspectives exist, recognizing and fulfilling our moral obligations to future generations can contribute to a more sustainable and equitable future.

Therefore, (a) We are not morally obliged to prioritize the well-being and interests of future generations, indicating that there is no inherent ethical responsibility towards them.

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Answer:

4 km/hr

Explanation:

The computation of the actual velocity is shown below:

Because the path of its paddles is opposed to the current direction, the real velocity can be determined by deducting the current velocity to its velocity while paddling

So, the actual velocity is

= Upstream - downstream

= 19 km/hr - 15 km/hr

= 4 km/hr

As we can see it is in positive, so it is an upstream direction  

Answer:

since the direction of his paddles is opposite of the the direction of the current, so the actual velocity can be calculated by subtracting the velocity of current to to his velocity when paddling

v = 19 - 15

v = 4 since the answer is positive, then the direction is upstream

Explanation:

Answer:

Weight

Explanation:

"An object will float if the buoyancy force exerted on it by the fluid balances its weight, i.e. if FB=mg F B = mg . But the Archimedes principle states that the buoyant force is the weight of the fluid displaced. So, for a floating object on a liquid, the weight of the displaced liquid is the weight of the object."

Hope this helps! :)

The analysis using pressure and work yields the same formula for power output as the energy analysis presented in §31.1.1.

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It would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

To calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet, we need to use the formula: time = distance / speed.

Given that the jet in NGC 5128 is traveling at 5000 km/s and is 40 kpc (kiloparsecs) long, we first need to convert the distance from kpc to km. 1 kpc = 3.086 × 10^16 meters, which means 1 kpc = 3.086 × 10^19 km.

Therefore, the length of the jet in kilometers is 40 x 3.086 × 10^19 km = 1.2344 × 10^21 km.

Now we can calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet as follows:

time = distance / speed
time = 1.2344 × 10^21 km / 5000 km/s
time = 2.4688 × 10^17 seconds

So, it would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

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Answer:

Explanation:

dwadad

The ratio of the sun's gravitational force on the moon to the earth's gravitational force on the moon is approximately 2:1.

The gravitational force that an object with mass exerts on another object with mass is directly proportional to the masses of the objects and inversely proportional to the square of the distance between them. This is known as the universal law of gravitation.

                        The force of gravity between the moon and the earth is stronger than the force of gravity between the moon and the sun because the moon is much closer to the earth than it is to the sun. The sun's gravitational force on the moon is about 46% of the earth's gravitational force on the moon.

                             This means that the ratio of the sun's gravitational force on the moon to the earth's gravitational force on the moon is approximately 2:1 .

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Braking up to -8 meters per second squared is more risky than the other one.

According to the definition of inertia, matter has the ability to remain at rest or to move uniformly in a single direction unless applied with an external force.

The ability of moving object to remain in moving  uniformly in a single direction  is called inertia of moving.

In this case, the car moving with certain velocity has inertia of moving. By certain applying brakes  of more deceleration is more risky as it works opposite to the  inertia of moving. Hence, braking up to -8 meters per second squared is more risky than breaking up to -3 meters per second squared.

As 8 meters per second squared acceleration or deceleration is larger compare to other; there may have no  situation where it can be the opposite.

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500kg box slides down a frictionless plane at an angle of 60.0° the normal force on the box is approximately 2450 N.

The acceleration of the box down the plane is determined by the force of gravity pulling the box down the slope. To determine the magnitude of the acceleration, we first need to resolve the gravitational force into its component vectors parallel and perpendicular to the slope.

The force of gravity on the box is given by:

Fg = m*g

where m is the mass of the box and g is the acceleration due to gravity (9.8 m/\(s^2\)).

The component of the force of gravity parallel to the slope is given by:

Fpar = Fg*sin(60.0°)

Fpar = 500 kg * 9.8 m/\(s^2\) * sin(60.0°) ≈ 4286 N

The component of the force of gravity perpendicular to the slope is given by:

Fperp = Fg*cos(60.0°)

Fperp = 500 kg * 9.8 m/\(s^2\) * cos(60.0°) ≈ 2450 N

The net force down the slope is given by:

Fnet = Fpar

Fnet = 4286 N

The magnitude of the acceleration down the slope is given by:

a = Fnet/m

a = 4286 N / 500 kg ≈ 8.57 m/\(s^2\)

Therefore, the magnitude of the box's acceleration down the slope is approximately 8.57 m/\(s^2\).

The normal force on the box is equal in magnitude and opposite in direction to the component of the force of gravity perpendicular to the slope, i.e.,

Fn = Fperp

Fn = 2450 N

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Answer:

D. It decreases

Explanation:

The magnitude of the acceleration due to the gravity on the surface of planet X is 4 m/s².

From Newton's second law:

The net force is directly proportional to the product of mass and acceleration of the body.

From the given,

mass of the planet X = 10 kg

Weight of the planet X = 40 N

acceleration of the planet (a) =?

W = m×a

a = W / m

 = 40 / 10

 = 4 m/s²

Hence, the acceleration of planet X is 4 m/s².

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The potential energy  and kinetic energy of the bowling ball are 2,205 J and 37.5 J respectively.

The bowling ball at the given position and speed possess gravitational potential energy and kinetic energy.

The potential energy  and kinetic energy of the bowling ball is calculated as follows;

P.E = mgh

where;

P.E =  (3 x 9.8 x 75 )

P.E = 2,205 J

The kinetic energy of the bowling ball is calculated as;

K.E = ¹/₂ mv²

where;

K.E = ¹/₂ ( 3 ) x (5²)

K.E = 37.5 J

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The ball will have a constant velocity of 11 m/s.

Since there is no gravity in space, the ball is not subject to the effects of gravity.

Thus, there is no acceleration acting on the ball in space. So, there is no change in velocity with time.

Therefore, the ball will move with a constant velocity of 11 m/s in space even after travelling 7 meters.

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So 245×10³ N/m the force needed to open the hatch from the inside.

We are aware that pressure rises as we go deeper into any liquid, even water.

Following are the changes in fluid pressure with depth.

P = ρgh

Here, represents the fluid's density.

The height of the liquid column is equal to h and the acceleration caused by gravity is g.

Keep in mind that gh represents the pressure increase caused by the liquid column, while the actual pressure would be

P =  ρgh  + P₀

P₀ is the atmospheric pressure

Hatch present at height 25m

Diameter of the hatch = 0.45m , Radius = 0.225m

Pressure inside the submarine = 1 atm

Pressure on hatch from outside = 1 atm + ρgh

Pressure from inside the submarine on the hatch = 1 atm

Net pressure on the hatch = ρgh

ρgh = 10³ × 9.8 × 25 = 245×10³ N/m.

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Answer: I never said anything to them but if i did it would be "I need a break from you, i love you but sometimes I have to find the path on my own." i would say this if i wasn't scared to hurt them.

Explanation:

Answer:

1. What is the orbit of the Earth?

365 days

2. Is the Sun at the center of the Earth’s orbit?

Yes

3. Describe the motion of the Earth throughout its orbit? Does it move at constant speed?

Yes, the Earth moves pretty quickly and orbits around the Sun at a rate of approximately 67,000 miles per hour.

1. What is the orbit of Mars?

The shape is circular, 687 days

2. Is the Sun at the center of Mars’s orbit?

Yes

3. Describe the motion of Mars throughout its orbit? Does it move at constant speed?

Travels at a regular steady speed, yes moves at a constant speed

1. What is the orbit of Saturn?

Circular, 29 years

2. Is the Sun at the center of Saturn’s orbit?

Yes

3. Describe the motion of Saturn throughout its orbit? Does it move at constant speed?

Just like Mars, it moves faster when it is closer to the sun, so yes.

1. What is the orbit of Neptune?

Circular, 165 years

2. Is the Sun at the center of Nepturn’s orbit?

Yes

3. Describe the motion of Neptune throughout its orbit? Does it move at constant speed?

A steady consistent speed and yes it moves at a constant speed.

1. What is the orbit of the comet?

An oval, 200 years

2. Is the Sun at the center of the comet’s orbit?

No

3. Describe the motion of the comet throughout its orbit? Does it move at constant speed?

A comet starts off slow then picks up speed and no it does not move at a constant speed.

Explanation:

I hope this helps, You're welcome.

Answer:

Explanation:

A simple pendulum consists of a mass (usually represented as a small object or bob) attached to a string or rod of negligible mass. The mass is free to swing back and forth under the influence of gravity.

In the figure, the point of suspension is denoted by "O," and the mass (bob) is represented by the small circle. The string or rod is represented by the vertical line connecting the point of suspension to the bob.

Amplitude:

The amplitude of a pendulum refers to the maximum displacement or swing of the bob from its equilibrium position. In the figure, the amplitude can be represented by the angle formed between the vertical position and the position of the bob when it swings to its maximum distance on one side. It is usually denoted by the symbol "A."

Effective Length:

The effective length of a pendulum refers to the distance from the point of suspension to the center of mass of the bob. It represents the distance over which the mass swings back and forth. In the figure, the effective length can be measured as the length of the string or rod from the point of suspension to the center of the bob. It is usually denoted by the symbol "L."

It is important to note that the amplitude and effective length of a simple pendulum affect its period of oscillation (the time taken for one complete swing). The relationship between these parameters and the period can be described by mathematical formulas.

Overall, the simple pendulum is a fundamental concept in physics and provides a simplified model for understanding oscillatory motion and the principles of periodic motion.

The critical depth in the hydraulic jump can be calculated using the specific energy equation. In this case, with a flow rate of 1.17 m³/s, channel width of 1.7 m, and a depth of 149 mm, the critical depth can be determined.

To calculate the critical depth in the hydraulic jump, we can use the specific energy equation, which relates the flow rate, channel dimensions, and water depth. The equation can be written as:

E = (Q² / (2g)) + (y² / (2g)) + (A² / (P * g))

Where:

E is the specific energy,

Q is the flow rate,

g is the acceleration due to gravity,

y is the water depth,

A is the cross-sectional area of flow,

P is the wetted perimeter of the channel.

In this case, we have a flow rate of 1.17 m³/s, a channel width of 1.7 m, and a depth of 149 mm (or 0.149 m). We need to find the critical depth, which occurs at the hydraulic jump. At the critical depth, the specific energy reaches its minimum value.

To determine the critical depth, we need to set the derivative of the specific energy equation with respect to the water depth equal to zero and solve for y. This will give us the critical depth. However, calculating the critical depth requires knowing additional parameters such as the cross-sectional area and wetted perimeter, which are not provided in the given information. Without these values, it is not possible to calculate the critical depth accurately.

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Answer:

1200

Explanation:

f=ma

f_ force

m_ mass

a_ acceleration

Part D: I = (2/5)(3.00 kg)(0.13 m)^2 = 0.2535 kg m^2. Part E:  I = (2/3)(3.00 kg)(0.13 m)^2 = 0.5574 kg m^2. Part F:  I = (1/2)(6.00 kg)(0.06 m)^2 = 0.0216 kg m^2. Part G: I = (1/12)(6.00 kg)(0.195 m)^2 + (1/4)(6.00 kg)(0.06 m)^2 = 0.1235 kg m^2.

Part D: The moment of inertia of a solid sphere about its diameter is (2/5)MR^2, where M is the mass and R is the radius (half of the diameter). In this case, the radius is 13.0 cm (half of 26.0 cm).
To find the moment of inertia (I) for a solid sphere, use the formula:
I = (2/5) * M * R^2

M = 3.00 kg (mass of the sphere)
Diameter = 26.0 cm = 0.26 m (convert cm to meters)
Radius (R) = Diameter/2 = 0.26/2 = 0.13 m

I = (2/5) * 3.00 * (0.13)^2
I ≈ 0.01638 kg•m^2

Part E: The moment of inertia of a thin-walled hollow sphere about its diameter is (2/3)MR^2. In this case, the radius is 13.0 cm (half of 26.0 cm), and the mass is still 3.00 kg.
For a thin-walled hollow shell sphere, the formula is:
I = (2/3) * M * R^2

Using the same values from Part D:
I = (2/3) * 3.00 * (0.13)^2
I ≈ 0.03276 kg•m^2

Part F: The moment of inertia of a thin-walled hollow cylinder about its central axis is (1/2)MR^2, where M is the mass and R is the radius. In this case, the radius is 0.06 m (half of 0.12 m), and the length is 0.195 m.
For a thin-walled hollow cylinder, the formula is:
I = M * R^2

M = 6.00 kg (mass of the cylinder)
Diameter = 12.0 cm = 0.12 m (convert cm to meters)
Radius (R) = Diameter/2 = 0.12/2 = 0.06 m

I = 6.00 * (0.06)^2
I ≈ 0.0216 kg•m^2

Part G: The moment of inertia of a solid cylinder about its central axis is (1/12)ML^2 + (1/4)MR^2, where M is the mass, L is the length, and R is the radius. In this case, the mass is 6.00 kg, the length is 0.195 m, and the radius is 0.06 m.
For a solid cylinder, the formula is:
I = (1/2) * M * R^2

Using the same values from Part F:
I = (1/2) * 6.00 * (0.06)^2
I ≈ 0.0108 kg•m^2

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Part D: I = (2/5)(3.00 kg)(0.13 m)^2 = 0.2535 kg m^2. Part E:  I = (2/3)(3.00 kg)(0.13 m)^2 = 0.5574 kg m^2. Part F:  I = (1/2)(6.00 kg)(0.06 m)^2 = 0.0216 kg m^2. Part G: I = (1/12)(6.00 kg)(0.195 m)^2 + (1/4)(6.00 kg)(0.06 m)^2 = 0.1235 kg m^2.

Part D: The moment of inertia of a solid sphere about its diameter is (2/5)MR^2, where M is the mass and R is the radius (half of the diameter). In this case, the radius is 13.0 cm (half of 26.0 cm).
To find the moment of inertia (I) for a solid sphere, use the formula:
I = (2/5) * M * R^2

M = 3.00 kg (mass of the sphere)
Diameter = 26.0 cm = 0.26 m (convert cm to meters)
Radius (R) = Diameter/2 = 0.26/2 = 0.13 m

I = (2/5) * 3.00 * (0.13)^2
I ≈ 0.01638 kg•m^2

Part E: The moment of inertia of a thin-walled hollow sphere about its diameter is (2/3)MR^2. In this case, the radius is 13.0 cm (half of 26.0 cm), and the mass is still 3.00 kg.
For a thin-walled hollow shell sphere, the formula is:
I = (2/3) * M * R^2

Using the same values from Part D:
I = (2/3) * 3.00 * (0.13)^2
I ≈ 0.03276 kg•m^2

Part F: The moment of inertia of a thin-walled hollow cylinder about its central axis is (1/2)MR^2, where M is the mass and R is the radius. In this case, the radius is 0.06 m (half of 0.12 m), and the length is 0.195 m.
For a thin-walled hollow cylinder, the formula is:
I = M * R^2

M = 6.00 kg (mass of the cylinder)
Diameter = 12.0 cm = 0.12 m (convert cm to meters)
Radius (R) = Diameter/2 = 0.12/2 = 0.06 m

I = 6.00 * (0.06)^2
I ≈ 0.0216 kg•m^2

Part G: The moment of inertia of a solid cylinder about its central axis is (1/12)ML^2 + (1/4)MR^2, where M is the mass, L is the length, and R is the radius. In this case, the mass is 6.00 kg, the length is 0.195 m, and the radius is 0.06 m.
For a solid cylinder, the formula is:
I = (1/2) * M * R^2

Using the same values from Part F:
I = (1/2) * 6.00 * (0.06)^2
I ≈ 0.0108 kg•m^2

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Answer:

0.40km/h

I think.. Hope this helps <3

The absolute pressure was found to be 15.56 psi

Explain about absolute pressure ?

Absolute pressure refers to the pressure described above. It is often necessary to distinguish between absolute pressure and gauge pressure. Unless otherwise specified, the term pressure in this article refers to absolute pressure. However, in engineering, we frequently deal with pressures, which are measured by various equipment. Although absolute pressures must be utilised in thermodynamic relationships, pressure-measuring equipment frequently indicate the difference between the absolute pressure in a system and the absolute pressure of the atmosphere existent outside the measuring device. They gauge the pressure.

hydrostatic pressure

P=ρgh

or

P=γh

where γγ = ρgρg = specific weight of the fluid

γ=62.4lb/ft³

P=γh=62.4lb/ft³(2)

P=124.8lbft²

or

P=124.8lbft²(ft²/144in²)=0.86psi

Pa=0.86psi+14.7psi=15.56psi

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Two cars X and Y start from two points separated by 75 m. Y which is ahead of X. starts from rest with acceleration of 10 m/s2 and X starts with uniform velocity of 40 m/s . The time gap between the two meetings would be approximately 1.44 seconds.

Let's assume that the two cars meet for the first time after time t₁, and then they meet for the second time after time t₂.

We can start by finding the time it takes for car Y to catch up to car X for the first time. We can use the following kinematic equation:

d = ut + (1/2)at²

where d is the distance between the two cars, u is the initial velocity of car X, a is the acceleration of car Y, and t is the time it takes for car Y to catch up to car X.

Plugging in the values, we get:

75 = 40t₁ + (1/2)(10)t₁²

Simplifying the equation, we get:

5t₁² + 8t₁ - 15 = 0

Solving for t1 using the quadratic formula, we get:

-t₁ = 1.5 seconds or -1 seconds

Since time cannot be negative, we discard the negative solution and conclude that the two cars meet for the first time after 1.5 seconds.

Now, let's find the time it takes for the two cars to meet for the second time. We can use the fact that the two cars have covered the same distance between their first and second meetings.

The distance covered by car Y during the time t₁ is:

d₁ = (1/2)(10)(1.5)² = 11.25 m

The distance remaining between the two cars is:

75 - 2d₂ = 52.5 m

To find the time it takes for car Y to cover this distance, we can use the same kinematic equation as before:

52.5 = 0t₂ + (1/2)(10)t₂²

Simplifying the equation, we get:

t₂ = (21)

Therefore, the time gap between the two meetings is:

t₂ - t₁ = √(21) - 1.5 seconds

So, the time gap between the two meetings is approximately 1.44 seconds.

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When wind turns the blades of a wind turbine and then this energy is used to power homes, this is an example of an energy transfer from mechanical to electrical energy.

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Answer:20Hz to 20000Hz

Explanation:

Humans can detect sounds in a frequency range from about 20 Hz to 20 kHz.

The object, initially moving at a speed of 60 m/s, undergoes a constant deceleration of 12 meters per second squared when the brakes are fully applied. The time taken for the object to come to a complete stop and the distance it travels during this deceleration can be determined using basic kinematic equations.

To calculate the distance traveled during deceleration:

Therefore, when the brakes are fully applied, the object takes 5 seconds to come to a complete stop and travels a distance of 150 meters during this deceleration.

The object's time to stop and distance traveled can be determined by using the kinematic equations. By calculating the time taken to be 5 seconds and the distance traveled to be 150 meters, we can understand the object's behavior under the given conditions.

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The variable in equation 12.4 that determines if the emitted light is in the Balmer series is the principal quantum number (n).the value of the principal quantum number (n) determines if the emitted light is in the Balmer series or not.

In the Balmer series, the emitted light is a result of transitions of electrons within hydrogen atoms from higher energy levels to the second energy level (n=2). The Balmer series corresponds to the visible light spectrum of hydrogen.

The equation that relates the wavelength of the emitted light to the principal quantum number is known as the Balmer formula:

1/λ = R_H * (1/2^2 - 1/n^2)

where λ is the wavelength of the emitted light, R_H is the Rydberg constant for hydrogen, and n is the principal quantum number.

By varying the value of the principal quantum number (n) in the Balmer formula, different wavelengths of light can be calculated. Only the transitions with n=2 will fall within the visible light spectrum, which defines the Balmer series. Transitions with other values of n will correspond to different series in the hydrogen spectrum, such as the Lyman series (n=1) or the Paschen series (n=3).

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Answer:

a) We can use the following formula to calculate the acceleration of the object:

a = (v_f - v_i) / t

where a is the acceleration, v_f is the final velocity, v_i is the initial velocity, and t is the time interval. Substituting the given values, we get:

a = (90 m/s - 40 m/s) / (2 min * 60 s/min) = 0.83 m/s^2

The force applied causing it to speed up can be found using Newton's second law of motion:

F = m * a

where F is the net force, m is the mass of the object, and a is the acceleration. Substituting the given values, we get:

F = 0.05 kg * 0.83 m/s^2 = 0.042 N

Therefore, the force applied causing the object to speed up is 0.042 N.

b) The work done by this force can be calculated using the following formula:

W = F * d

where W is the work done, F is the net force, and d is the displacement of the object. The displacement of the object is given by:

d = 670 m

Substituting the given values, we get:

W = 0.042 N * 670 m = 28.14 J

Therefore, the work done by the force is 28.14 J.

c) The work done by friction can be calculated using the formula:

W_friction = F_friction * d

where W_friction is the work done by friction, F_friction is the force of friction, and d is the displacement of the object. The force of friction can be calculated using:

F_friction = μ * F_norm

where μ is the coefficient of friction and F_norm is the normal force. The normal force is equal to the weight of the object, which is given by:

F_weight = m * g

where m is the mass of the object and g is the acceleration due to gravity. Substituting the given values, we get:

F_weight = 0.05 kg * 9.81 m/s^2 = 0.49 N

The normal force is equal in magnitude to the weight of the object, so we have:

F_norm = F_weight = 0.49 N

Substituting the given coefficient of friction, we get:

F_friction = 0.34 * 0.49 N = 0.17 N

The work done by friction can now be calculated by substituting the values we have found:

W_friction = 0.17 N * 670 m = 113.9 J

Therefore, the work done by friction is 113.9 J.

d) The net work done can be calculated as the sum of the work done by the applied force and the work done by friction:

W_net = W_applied + W_friction

Substituting the values we have found, we get:

W_net = 28.14 J + 113.9 J = 142.0 J

Therefore, the net work done is 142.0 J.