Answer:
Explanation:
You can see that on the x-axis Vx is equal to Vcos and the velocity on the x-axis is all the same.
On the y-axis, Vy is equal to Vsin
Vy : B ( Vsin ) = F ( - Vsin ) > E ( 0 )
The velocity is the same.
Vx B Tap Me E Tap Me F Tap Me
Vу B Tap Me E Tap Me F Tap Me
What is Projectile motion?Projectile motion is the movement of an item thrown or projected into the air, which challenges the most effective acceleration because of gravity. The applications of projectile motion in physics and engineering are numerous. a few examples consist of meteors as they enter Earth’s atmosphere, fireworks, and the movement of any ball in sports activities. Such gadgets are called projectiles and their direction is known as a trajectory.
What are projectile motion examples?Tossing an item into the bin, water flowing from a faucet, jumping from a bus, and so on are all common examples of projectile motion that we encounter each day.
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Three resistors 2 k\ohm, 2.5 k\ohm and 3 k\ohm are connected in series. A power supply is connected in the circuit, and applies a voltage of 10.00 V across all three. Calculate the current in the circuit. Enter results in terms of milliamps (mA).
Answer:
1.33 mA
Explanation:
V=IR
I=10/(7.5×10³)
=1.33×10-³A
=1.33mA
A hiker of mass 69 kg is going to climb to the top of Mount Tam, which has an elevation of 2.574 ft. 4 50% Part (n) If the hiker starts climbing at an elevation of 395 ft what will their change in gravitational potential energy be, in joules, once they reach the top? Assume the zero of gravitational potential energy is at sea level AV- Grade Summary Deductions 0 Potential 100 Soheissions Atempts remaining: e per attempt detailed view sino cos tan cotano asino acos atan acotano sinho cosh tanho cotanho Degrees O Radians ( 7 8 9 ET 4 5 6 123 + - 0 vo Submit Hini I give up! Hints: deduction per hint. Hints remaining: Feedback deduction per feedback A 50% Part (b) Repeat the above calculation for the change in gravitational potential energy, but assume the gravitational potential is zero at the top of the mountain
a. The gravitational potential energy change is 449.105 kJ
b. The gravitational potential energy change is 449.105 kJ
What is gravitational potential energy?Gravitational potential energy is the energy due to the position of an object. It is given by U = mgh where
m = mass of object, g = acceleration due to gravity and h = height of objectPart (a) If the hiker starts climbing at an elevation of 395 ft what will their change in gravitational potential energy be, in joules, once they reach the top?Since the mountain is 2574 ft high, the gravitational potential energy change is given by ΔU = mg(h' - h) where
m = mass of man = 69 kgg = acceleration due to gravity = 9.8 m/s²h = height at top of mountain = 2574 ft = 2574 × 0.3048 m = 784.56 m and h' = height where he starts climbing = 395 ft = 395 × 0.3048 m = 120.40 mSubstituting the values of the variables into the equation, we have
ΔU = mg(h' - h)
ΔU = 69 kg × 9.8 m/s²(784.56 - 120.40) m
ΔU = 69 kg × 9.8 m/s² × 664.16 m
ΔU = 449104.992 J
ΔU = 449.104992 kJ
ΔU ≅ 449.105 kJ
So, the gravitational potential energy change is 449.105 kJ
Part (b) Repeat the above calculation for the change in gravitational potential energy, but assume the gravitational potential is zero at the top of the mountain?We know that the gravitational potential energy change is ΔU = U' - U = mg(h' - h) where
U' = gravitational potential energy at top = 0, U' = gravitational potential energy at starting point, m = mass of man = 69 kg g = acceleration due to gravity = 9.8 m/s²h = height at top of mountain = 2574 ft = 2574 × 0.3048 m = 784.56 m and h' = height where he starts climbing = 395 ft = 395 × 0.3048 m = 120.40 mSubstituting the values of the variables into the equation, we have
ΔU = U - U' = mg(h' - h)
ΔU = 0 - U' = 69 kg × 9.8 m/s²(784.56 - 120.40) m
ΔU = 69 kg × 9.8 m/s² × 664.16 m
ΔU = 449104.992 J
ΔU = 449.104992 kJ
ΔU ≅ 449.105 kJ
So, the gravitational potential energy change is 449.105 kJ
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Data Table:
Coefficient of friction
(=tan(angle)
Trial #
Length of book
Angle
(=sin(height/length))
Height of end
average
Diagram:
length of book
(block
boek
height of
end
table
Extension Questions:
1. If the coefficient of friction between a wheelchair wheel and concrete was 0.4, what is the
maximum angle the ramp could have?
2. Would it make a difference, when determining the maximum angle of a ramp, if you were to use
the coefficient of kinetic friction rather than static friction? Which would be a better choice?
Justify your answer.
3. What is the purpose of a switch-back when driving up the side of a mountain (a switchback is
when the road zig-zags, reversing direction and appearing to go back the way it came, but at a
higher elevation)?
Hi there!
1.
To find the maximum angle that the ramp can have, we must find the angle at which the net force on the wheelchair wheel along the axis of the plane is still 0 N.
We can do this using a summation of forces. The only two forces acting on the wheelchair wheel in this situation is the force due to STATIC friction and gravity:
⇒ Force due to static friction: Fs = μN
In this case, N = mgcosθ, so :
\(F_s = \mu mgcos\theta\)
⇒ Force due to gravity along the axis:
\(F_g = mgsin\theta\)
These two must sum up to zero, so:
\(\Sigma F = mgsin\theta - \mu mgcos\theta = 0 \\
\\
mgsin\theta = \mu mgcos\theta\)
Cancel the mass and gravity:
\(sin\theta = \mu cos\theta\\
\\
tan\theta = \mu \\
\\
tan\theta = 0.4\\
\\
tan^{-1}(0.4) = \boxed{21.80^o}\)
2.
Yes. The coefficient of static friction provides you with the MAXIMUM amount of friction force (resistance) that must be overcome for the object to begin moving, while the coefficient of kinetic friction allows you to find the friction force experienced by a MOVING object. In this instance, the coefficient of KINETIC friction is most appropriate because the wheelchair is moving on the ramp. However, if finding the maximum angle of a ramp with an object placed on it, the coefficient of STATIC friction would need to be used in determining the angle that will cause the object to begin sliding.
3.
A switch-back decreases the angle of inclination that a car must travel, so the risk of the car sliding down is decreased because as the angle DECREASES, the force due to friction INCREASES. Friction is what prevents a car from sliding, so minimizing the angle of a ramp/road will increase the friction force and lower the risk of sliding down.
How does work done on an object affect its kinetic energy
According to the work-energy theorem, the work done on an object by a net force equals the change in kinetic energy of the object. Essentially kinetic energy is the energy used for motion. Interestingly, as work is done on an object, potential energy can be stored in that object. A moving object has kinetic energy because work has been done on it. When work is done energy in one form is transferred to the kinetic energy of the moving object. To stop the object again, the same amount of work would have to be done to bring it back to rest.
Initial velocity: U = ?
Final velocity: v = 0
Gravity: g = 9,8 ms²
Height: h = 20m
v² = u² + 2gh
0 = u² + 2 (-9,8ms²) x 20m
The initial velocity of the object in motion is determined as 19.8 m/s.
What is the initial velocity of the object?The initial velocity of the object in motion is calculated by applying the third equation of motion as follows;
v² = u² + 2gh
where;
v is the final velocity of the objectu is the initial velocity of the objectg is acceleration due to gravityh is the height through which the object riseswhen the object reaches maximum height, the final velocity, v = 0
The initial velocity of the object in motion is calculated as;
0 = u² + 2 (-9,8ms²) x 20m
0 = u² - 392
u² = 392
u = √392
u = 19.8 m/s
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A boy starts at rest and slides down a frictionless slide as in the figure below. The bottom of the track is a height h above the ground. The boy then leaves the track horizontally, striking the ground a distance d as shown. Using energy methods, determine the initial height H of the boy in terms of h and d.
The initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track: H = h + d.
To determine the initial height H of the boy in terms of h and d, we can use the principle of conservation of energy. The total mechanical energy of the system remains constant throughout the motion.
At the top of the slide, the boy has gravitational potential energy given by mgh, where m is the mass of the boy, g is the acceleration due to gravity, and h is the height of the slide above the ground.
As the boy slides down the slide, there is no friction or other dissipative forces, so there is no change in mechanical energy. At the bottom of the track, the gravitational potential energy is converted entirely into kinetic energy.
Therefore, we can equate the initial potential energy to the final kinetic energy:
mgh = 1/2 m\(v^{2}\),
where v is the horizontal velocity of the boy when he leaves the track.
Since the boy leaves the track horizontally, the vertical component of his velocity is zero. Therefore, we can use the relationship between horizontal distance d and horizontal velocity v:
d = vt.
Solving these equations, we can express the initial height H in terms of h and d:
H = h + d.
So the initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track.G
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A cell phone weighing 80 grams is flying through the air at 15 m/s what is the kinetic energy
Answer:
\(9\:\mathrm{J}\)
Explanation:
Kinetic energy is given by the following equation:
\(KE=\frac{1}{2}mv^2\), where \(m\) is mass in \(\mathrm{kg}\) and \(v\) is velocity in \(\mathrm{m/s}\).
Since the cell phone's mass is given in grams, we need to convert this into kilograms:
\(80\:\mathrm{g}\cdot \frac{1\:\mathrm{kg}}{1000\:\mathrm{g}}=0.08\:\mathrm{kg}\).
Therefore, the kinetic energy of the cell phone is:
\(KE=\frac{1}{2}\cdot 0.08\cdot 15^2=\fbox{$9\:\mathrm{J}$}\).
You have three flowers. You give
each a different amount of
water. What do you think is the
dependent variable?
Answer:
The plant growth height
Explanation:
What net force would be required to accelerate a 5 Kg object 2 m/s2? [show all work, including the
equation, substitutions with units, and answer with units]
Answer:
10 Newtons.
Explanation:
F=MA
F=(5kg)(2 m/s^2)
10 N
A car going at 75 miles/hr slows down to 25 miles/hr in 2.5 sec; calculate the acceleration.
vi = initial speed = 75 miles/hour =167.7 m/s
vf = final speed = 25 miles/hour = 55.9234 m/s
t = time = 2.5 seconds=
a = acceleration
\(a=\frac{vf-vi}{t}\)Replacing with the values given:
\(a=\frac{55.9234-167.7}{2.5}\)a = 44.74 m/s^2
Show your work
A 2.0 kg block rests on a level surface. The coefficient of static friction is µs = 0.50, and the coefficient of kinetic friction is µk = 0.30. A horizontal force, F, is applied to the block. As F is increased, the block begins moving.
a)Find the minimum force, F, required for the block to just start to move.
b)Find the force, F, required for the block to continue to move at a constant velocity.
c)Explain what happens to the motion of the block if a force is applied greater than those found above.
a. The minimum force required to start moving the block is 9.8 N
b. The force required to continue moving the block at a constant velocity is 5.88 N.
c. If a force greater than 9.8 N is applied, the block will start moving and continue to move until the applied force is less than 5.88 N.
How to calculate?a. Force = μs * N
N = m * g = 2.0 kg * 9.8 m/s^2 = 19.6 N
Force = μs * N = 0.50 * 19.6 N = 9.8 N
b. Force = μk * N = 0.30 * 19.6= 5.88 N N
c. In conclusion, If a force greater than 5.88 N is applied, the block will accelerate. If a force less than 5.88 N is applied, the block will decelerate and eventually stop if the force becomes less than the force of static friction (9.8 N).
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SuperPointParticleDog is playing tug of war with two other dogs, Isaac and Newton. Isaac is pulling with a force of 255 N, 13 degrees North of East on one rope attached to a ball. Newton is pulling with a force of 156 N, 34 degrees South of East on another rope attached to the ball. If the ball is moving with constant momentum toward SuperPointParticleDog, what is the East/West component of her force on the ball?
The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
How to explain tje informationIsaac's force:
Magnitude: 255 N
Angle: 13 degrees North of East
x-component: 255*cos(13) = 245.1 N (Eastward)
y-component: 255*sin(13) = 58.1 N (Northward)
Newton's force:
Magnitude: 156 N
Angle: 34 degrees South of East
x-component: 156*cos(34) = 129.4 N (Westward)
y-component: 156*sin(34) = 86.5 N (Southward)
Now we can add the x- and y-components of the forces to find the net force:
Net force:
x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)
y-component: 58.1 N - 86.5 N = -28.4 N (Southward)
The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
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What length should a tube closed at one end have on a day when the air temperature is 0ºC, if its fundamental frequency is to be 96 Hz (C below middle C)?What is the frequency of its sixth over tone
The frequency of the sixth overtone would be 576 Hz.
To determine the length of a tube closed at one end, we can use the formula:
L = (v/4f) * (2n - 1)
where L is the length of the tube, v is the speed of sound in air, f is the fundamental frequency, and n is the harmonic number.
Given that the fundamental frequency is 96 Hz, we can substitute the values into the formula:
L = (v/4f) * (2n - 1)
L = (v/4*96) * (2*1 - 1)
L = v/384
To find the length at 0ºC, we need to know the speed of sound at that temperature. The speed of sound in air depends on temperature and other factors. At 0ºC, the speed of sound in dry air is approximately 331.4 m/s.
L = 331.4/384
L ≈ 0.862 m
Therefore, the tube closed at one end should have a length of approximately 0.862 meters when the air temperature is 0ºC.
To find the frequency of the sixth overtone, we multiply the fundamental frequency by six: Frequency of sixth overtone = 96 Hz * 6 = 576 Hz.
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1. What outdoor activities do you prefer? Why? 2. What outdoor activities are you interested in, but have never tried?
The outdoor activities u prefers most is swimming because I feel relaxed after that.
The outdoor activities I am more interested in but I have not tried is mountain climbing.
What is outdoor activities?Outdoor activities refers to exercises or activities that is carried out outside an enclosed areas. These include swimming, mountain climbing, running and the rest.
Therefore, The outdoor activities u prefers most is swimming because I feel relaxed after that.
The outdoor activities I am more interested in but I have not tried is mountain climbing.
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Which statement describes the process shown?
2H
4He
3H
neutron
A. The process is nuclear fission, in which one nucleus splits apart to
form two smaller nuclei.
B. The process is nuclear fusion in which one nucleus splits apart to
form two smaller nuclei.
C. The process is nuclear fission, in which two smaller nuclei
combine to form one larger nucleus.
D. The process is nuclear fusion, in which two smaller nuclei
combine to form one larger nucleus.
Lam Lesson Name: Uncovering Your Personality
m number: 700047RR
Exam Guidelines
Exam Instructions
Question 10 of 20:
Select the best answer for the question.
10. Which characteristic of a turbulent person causes them to always strive for self-improvement, and to never see accomplishing a goal as good enough?
O A. Confident
B. Self-critical
O C. Ignorant
O D. Calm
Mark for review (Will be highlighted on the review page)
ex Previous Question
Next Questin
Review My F
The correct answer is Self-critical.
Why is self-improvement?
Enhancing strengths, mental health, and even mending relationships benefit self-improvement. Simple actions like reading a book, trying something new, meditating, or even getting up early are some ways to improve oneself. There are so many easy, efficient methods to begin the process of improving oneself.A self-improvement strategy enables you to build the life you want for yourself. It enables you to maintain perspective on your priorities and the things most important to you in life to experience greater meaning and fulfillment.Self-development is taking steps to better yourself, such as by learning new skills or overcoming bad habits. An example of self-development is taking courses at the university to learn new skills and interesting things.Self-critical:
Self-critical causes them to always strive for self-improvement and never to see accomplishing a goal as good enough.
The characteristic of a turbulent person causes them to always strive for self-improvement and to never see accomplishing a goal as good enough is Self-critical.
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A particle is projected vertically upwards from the ground with a speed of 36m/s^-1, calculate.
a. The time for which it is above a height of 63m.
b. The speed which it has at this height on its way down
c. The total time of flight
To solve this problem, we can use the equations of motion for a freely falling body with constant acceleration due to gravity (g = 9.81 m/s²).
a. The time for which it is above a height of 63m:
We can use the following equation of motion to find the time t it takes for the particle to reach a height of 63 m above the ground:
y = uyt + (1/2)gt²
where y is the displacement (height) of the particle, uy is the initial velocity in the y-direction (upward), and t is the time.
At the highest point of its trajectory, the particle will have zero velocity, so we can use the initial velocity as uy = 36 m/s. We want to find the time t when the particle reaches a height of y = 63 m, so we can rearrange the equation to solve for t:
t = (-uy ± sqrt(uy² + 2gy))/g
where the ± sign indicates that there are two possible solutions, one for when the particle is going up (positive root) and one for when the particle is coming down (negative root).
Plugging in the values for uy, g, and y, we get:
t = (-36 ± sqrt(36² + 2*(-9.81)*63))/(-9.81)
t = 6.53 s (upward)
b. The speed which it has at this height on its way down:
When the particle reaches a height of 63 m on its way down, we can use the following equation to find its velocity vy:
vy² = uy²+ 2g(y - yo)
where yo is the initial height (0 m) and uy is the initial velocity in the y-direction (upward).
We can plug in the values for uy, g, and y, and solve for vy:
vy²= 36²+ 2(-9.81)(63 - 0)
vy = 32.2 m/s (downward)
c. The total time of flight:
The total time of flight is twice the time it takes for the particle to reach the maximum height, since it takes the same amount of time to come back down to the ground. Therefore, the total time of flight is:
t_total = 2t_upward = 2(6.53) = 13.06 s
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Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Answer:
Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Explanation:
Grabens drop down relative to adjacent blocks and create valleys. Horsts rise up relative to adjacent down-dropped blocks and become areas of higher topography.
1) Un objeto realiza un movimiento circular uniforme en una circunferencia de 10 metros de diámetro y efectúa 20 vueltas por minuto. Se pide hallar:
a) El periodo.
b) La frecuencia en Hertz.
c) La velocidad tangencial. d) La velocidad angular.
e) La aceleración centrípeta.
Answer:
A RECIPE NEEDS A COMBINED WEIGHT OF 720G OF FLOUR AND SUGAR. IF THE RECIPE NEEDS 5TIME FLOUR THAN SUGAR,HOW MUCH OF EACH IS NEEDED
For which type of pathogens do immunizations/vaccinations help prevent?
To reduce the risk of atherosclerosis, it is important to cut down on?
The pathogen that immunization helps to prevent is virus.
To reduce the risk of atherosclerosis cut down on saturated fatty foods.
What is immunization?Immunization is defined as the prevention of pathogenic viral organisms from harming a living human host through the exposure of the host to an attenuated form of the virus to develop immunity prior to a future exposure.
Atherosclerosis is the deposition of fatty substances on the arterial wall leading to blocking of the blood vessels.
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basics of gravitation:
Planet a exerts a force on planet b. What can be said about the magnitude and direction of the gravitational force planet b exerts on planet a?
Answer:
Explanation:
According to Newton's Law of Gravitation, the gravitational force between two objects is always mutual, meaning that the force that one object exerts on the other is equal in magnitude but opposite in direction.
This means that if planet A exerts a gravitational force on planet B, then planet B will also exert a gravitational force on planet A. The magnitude of this force will be equal to the magnitude of the force that planet A exerts on planet B, but the direction will be opposite.
For example, if planet A exerts a gravitational force on planet B that is pulling planet B towards planet A, then planet B will also exert a gravitational force on planet A that is pulling planet A towards planet B. The magnitude of these two forces will be equal, but the directions will be opposite.
hat he sais
Answer:w
Explanation:
the researcher wants to find out how much curiosity freshman American high schools experience when taking the first elective course
Answer:
they are prob really curious its new to them
Explanation:
this is most likely not right but ia m a freash man so whatever
Watching Gladiators was a favorite pastime of which civilization? A. Greeks B. Norwegians C. Romans D. Kiwis
Watching Gladiators was a a favorite pastime of Roman civilization. It was a game based on the Roman martial ethics. It lasted for nearly thousands of years. Hence option C is correct.
What is Gladiator ?An armed warrior known as a gladiator amused spectators in the Roman Republic and Roman Empire by engaging in bloody fights with other gladiators, wild animals, and condemned prisoners.
Some gladiators were unpaid volunteers who jeopardized their lives as well as their position in society and the law by participating in the fight. The majority endured severe education, were treated like inferiors in society, and were separated even in death.
Regardless of where they came from, gladiators served as a living example of Rome's martial virtues to onlookers, and by fighting or dying honorably, they may win adulation and widespread renown.
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A wave has an amplitude of 0.0800 m
and is moving 7.33 m/s. One oscillator
in the wave takes 0.230 s to go from
one crest to the next crest. Find the
wavelength of the wave.
(Unit = m)
If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The
wavelength of the wave is 1.69m.
What is the wavelength?The wavelength of a wave can be determined using the equation:
Wavelength = velocity / frequency
To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.
frequency = 1 / time
frequency = 1 / 0.230
frequency ≈ 4.35 Hz
Substitute the values into the wavelength equation:
wavelength = velocity / frequency
wavelength = 7.33 / 4.35
wavelength ≈ 1.69m
Therefore the wavelength of the wave is approximately 1.69 meters.
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A magnet gets demagnetized when it is heated.
Answer:
The delicate balance between temperature and magnetic domains is destabilized when a magnet is subjected to high temperatures. If a magnet is exposed to this temperature for an extended length of time or heated over its Curie temperature, it will lose its magnetism and become irreversibly demagnetized.
Explanation:
Which level of organization is all the same type of ecosystem found on Earth
that share common characteristics?
A biome, in simple terms, is a set of ecosystems sharing similar characteristics with their abiotic factors adapted to their environments.
An organ pipe open at both ends has a length of 0.80 m. If the velocity of sound in air is 340 m/s, what is the frequency of the second harmonic of this pipe
Answer:
the frequency of the second harmonic of the pipe is 425 Hz
Explanation:
Given;
length of the open pipe, L = 0.8 m
velocity of sound, v = 340 m/s
The wavelength of the second harmonic is calculated as follows;
L = A ---> N + N--->N + N--->A
where;
L is the length of the pipe in the second harmonic
A represents antinode of the wave
N represents the node of the wave
\(L = \frac{\lambda}{4} + \frac{\lambda}{2} + \frac{\lambda}{4} \\\\L = \lambda\)
The frequency is calculated as follows;
\(F_1 = \frac{V}{\lambda} = \frac{340}{0.8} = 425 \ Hz\)
Therefore, the frequency of the second harmonic of the pipe is 425 Hz.
The frequency of the second harmonic of the pipe is 425 Hz.
What is the frequency?Frequency is the number of oscillations per second in the sinusoidal wave.
Given is length of the open pipe, L = 0.8 m, and velocity of sound, v = 340 m/s
The wavelength of the second harmonic is represented as
L = A → N + N→N + N→A
where, L is the length of the pipe in the second harmonic, A represents antinode of the wave, N represents the node of the wave
Length = λ/4 +λ/2 +λ/4
Length = λ
The frequency is calculated
frequency = speed of light / wavelength
Put the values, we get
f = 340/0.80
f = 425 Hz
Therefore, the frequency of the second harmonic of the pipe is 425 Hz.
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A student with a mass of 52 kg, starts from rest and travels down a 2 m slide. What is
the KE of the student at the bottom of the slide?
Answer:
https://www.ux1.eiu.edu/~cfadd/1350/Hmwk/Ch08/Ch8.html
Explanation:
Which is an isotope?
Answer: B.
Explanation:
An isotope is a variation of the same element with a different number of neutrons in its nucleus. The only thing that changes is the top component, which is the total number of protons and neutrons. The bottom component remains the same (the number of protons).
Frequency= Wavelength = 502 km Speed= 100 m/s
Answer:
Explanation:
Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.