A ball is dropped from rest and takes 1.3 s to hit the ground. from what height was it dropped?

Answer:

is the name of your school alpha omega, because i recogize the bottom of the page

Step-by-step explanation:

Tameka can paint a house in 4 hours, and Rasheeda can paint the same house in 6 hours. If Tameka and Rasheed paint the house together, the can finish it in 2.4 hours.

This problem can be solved using unitary method.

Using this method, the required value is obtained by multiplying the quantity with the unit value.

Tamika can paint a house in 4 hours. It means:

In 1 hours Tamika can paint 1/4 house

Rasheeda can paint a house in 6 hours. It means:

In 1 hours Rasheeda can paint 1/6 house

If  Rasheeda and Tameka work together, they can paint 1/4 + 1/6 = 5/12 house in 1 hour.

It means, for 1 house, Rasheeda + Tameka need 12/5 = 2.4 hours

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Using Little's Law, the average waiting time in line for the baggage check-in of a small airline was found to be approximately 6.47 minutes, given an arrival rate of 4.25 passengers per minute and an average check-in time of 2 minutes per passenger.

We can use Little's Law to find the average waiting time:

Average number of passengers in system = Average arrival rate x Average time in system

We are given the average number of passengers waiting in line (35) and the arrival rate (255/60 = 4.25 passengers per minute). We need to find the average time in the system, which is the sum of the time spent waiting in line and the time spent being checked in.

Let's assume that the check-in process takes on average 2 minutes per passenger. Then the average time in the system is:

Average time in system = Average time in line + Average check-in time

Average time in system = x + 2

We know that the average number of passengers in the system is 35, so:

35 = 4.25(x + 2)

Solving for x, we get:

x = 6.47 minutes

Therefore, the average passenger had to wait in line for approximately 6.47 minutes

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Answer:

i believe x=11

Step-by-step explanation:

if the top is 11 then the bottom is 11

the answer x is eleven(11)

Given :

You rent an apartment that costs $1700 per month during the first year, but the rent is set to go up 9% per year.

To Find :

The rent of the apartment during the 12th year of living in the apartment.

Solution :

Let, A is the final price after 12 year and P is the principal amount.

We know, by formula of compounding :

\(A = P( 1 + \dfrac{r}{100})^t\\\\A = 1700( 1 + \dfrac{9}{100} )^{12}\\\\A = \$4781.53\)

Therefore, the rent of the apartment during the 12th year of living in the apartment is $4781.53 .

Answer:

Sophia's monthly spent on food is $300 while she wants to spend $245.

As her real monthly spent is greater than what she wants, she is not meeting the 10% criteria. In fact, she exceed her budget for month

Step-by-step explanation:

Net income of Sophia = $2,450

% of money she wants to spend on food = 10% of Net income of Sophia

thus,

Amount of money she wants to spend on food in $

           =  10% of $2,450

           = 10/100 * $2,450 = $245

Hence, Sophia wants to spend $245 in a month on food.

__________________________

it is given that last week she spent $75 on food

thus, weekly spent on food = $75

as there are 4 weeks in a months

money spent by her in 4 weeks = $75* 4 = $300

Thus, her monthly spent on food is $300 while she wants to spend $245.

As her real monthly spent is greater than what she wants, she is not meeting the 10% criteria. In fact, she exceed her budget for month

Answer:

x = -5

Step-by-step explanation:

9(x+4)=1+2x

9x+36 = 1 + 2x

35 = -7x

Divide

-5 = x

x= -5

\( \: \: \: \: \: \: \: 9(x + 4) = 1 + 2x \\ \\ = > 9x + 36 = 1 + 2x \\ \\ = > 9x - 2x = 1 - 36 \\ \\ = > 7x = ( - 35) \\ \\ = > x = (- \frac{35}{7} ) \\ \\ = > x = \green{\boxed{ - 5}}\)

Answer:

7^11 / 4^11

Step-by-step explanation:

( 7/4) ^ 11

We know that ( a/b) ^c = a^c / b^c

7^11 / 4^11

Answer: B. \((\frac{7}{4})^{11} = \frac{7^{11}}{4^{11}}\)

Step-by-step explanation:

There is exponent rule that states \((\frac{a}{b})^{x} = \frac{a^x}{b^x}\)

So we can apply this rule to this problem.

\((\frac{7}{4})^{11} = \frac{7^{11}}{4^{11}}\)

Answer:

median 6.5

mean 6.166

range 6

Step-by-step explanation:

The process to subtract the mixed fractions with the whole numbers is explained below.

The Mixed Fractions are defined as type of fraction that consists of a whole number and a proper fraction.

Step(i) : We multiply whole number by denominator of fraction and add numerator.

For example, if mixed fraction 2(1/3), we multiply 2 by 3 and add 1 to get 7. So, 2(1/3) is equivalent to improper fraction 7/3.

Step(ii) : Find a common denominator for fractions. We find least common multiple (LCM) of denominators.

For example, if you want to subtract 2(1/3) from 5, denominators are 3 and 1, and LCM is 3.

Step(iii) : Convert whole number to a fraction with same denominator as common denominator.

For example, if LCM is 3 and we want to subtract 2(1/3) from 5, we will convert 5 to fraction 15/3.

Step(iv) : Rewrite each fraction with common denominator.

For example, if we want to subtract 2(1/3) from 5, we rewrite 2(1/3) as 7/3 and 15/3 as 5.

Step(v) : Subtract the fractions.

For example, to subtract 7/3 from 5, we subtract numerators and keep the denominator: 15/3 - 7/3 = 8/3.

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Answer:

8

Step-by-step explanation:

You can think as vertices as the corners of the shape

Answer:

the shape have 8 vertices.

Answer:

1) 40kg

2) 245kg

Step-by-step explanation:

Answer:

Infinite

Step-by-step explanation:

ANY line segment can have INFINITE bisectors crossing it

Answer:

64 pictures

Step-by-step explanation:

36 + 28 = 64 pictures

Answer:

36+28=64

Step-by-step explanation:

that should be right

The system of linear equations can be written in the augmented matrix form as;  

The augmented matrix is [A|B] = \($\begin{pmatrix}1 & 2 & 3 & -2 & 1 & 2\\2 & 3 & 4 & -3 & -2 & 0\\0 & 2 & 1 & 5 & 0 & 4\\-3 & 0 & 0 & 0 & -1 & 0\end{pmatrix}$\)

Using Gaussian elimination, we obtain:

\($\begin{pmatrix}1 & 2 & 3 & -2 & 1 & 2\\2 & 3 & 4 & -3 & -2 & 0\\0 & 2 & 1 & 5 & 0 & 4\\-3 & 0 & 0 & 0 & -1 & 0\end{pmatrix}$ $\xrightarrow[]{R_2 - 2R_1}$\)

\($\begin{pmatrix}1 & 2 & 3 & -2 & 1 & 2\\0 & -1 & -2 & 1 & -4 & -4\\0 & 2 & 1 & 5 & 0 & 4\\-3 & 0 & 0 & 0 & -1 & 0\end{pmatrix}$\)

\($\xrightarrow[]{R_3 + 2R_2}$\)

\($\begin{pmatrix}1 & 2 & 3 & -2 & 1 & 2\\0 & -1 & -2 & 1 & -4 & -4\\0 & 0 & -3 & 7 & -8 & -4\\-3 & 0 & 0 & 0 & -1 & 0\end{pmatrix}$\)

\($\xrightarrow[]{-\frac{1}{3}R_4}$\)

\($\begin{pmatrix}1 & 2 & 3 & -2 & 1 & 2\\0 & -1 & -2 & 1 & -4 & -4\\0 & 0 & -3 & 7 & -8 & -4\\1 & 0 & 0 & 0 & \frac{1}{3} & 0\end{pmatrix}$\)

\($\xrightarrow[]{R_3 - 3R_2}$\)

\($\begin{pmatrix}1 & 2 & 3 & -2 & 1 & 2\\0 & -1 & -2 & 1 & -4 & -4\\0 & 0 & 1 & -2 & \frac{8}{3} & \frac{4}{3}\\1 & 0 & 0 & 0 & \frac{1}{3} & 0\end{pmatrix}$\)

\($\xrightarrow[]{R_2 + 2R_3}$\)

\($\begin{pmatrix}1 & 2 & 3 & -2 & 1 & 2\\0 & -1 & 0 & -3 & -\frac{4}{3} & -\frac{2}{3}\\0 & 0 & 1 & -2 & \frac{8}{3} & \frac{4}{3}\\1 & 0 & 0 & 0 & \frac{1}{3} & 0\end{pmatrix}$\)

\($\xrightarrow[]{R_1 - 3R_3}$\)

\($\begin{pmatrix}1 & 2 & 0 & 4 & -7 & -2\\0 & -1 & 0 & -3 & -\frac{4}{3} & -\frac{2}{3}\\0 & 0 & 1 & -2 & \frac{8}{3} & \frac{4}{3}\\1 & 0 & 0 & 0 & \frac{1}{3} & 0\end{pmatrix}$\)

\($\xrightarrow[]{R_1 - 2R_2}$ $\begin{pmatrix}1 & 0 & 0 & 10 & -\frac{5}{3} & -\frac{4}{3}\\0 & -1 & 0 & -3 & -\frac{4}{3} & -\frac{2}{3}\\0 & 0 & 1 & -2 & \frac{8}{3} & \frac{4}{3}\\1 & 0 & 0 & 0 & \frac{1}{3} & 0\end{pmatrix}$\)

Thus, the solution to the system of linear equations is

\($\begin{pmatrix}x\\y\\z\\w\end{pmatrix}$ = $\begin{pmatrix}10\\-3\\-2\\0\end{pmatrix}$ $+$ $t\begin{pmatrix}-\frac{5}{3}\\-\frac{4}{3}\\0\\0\end{pmatrix}$ $+$ $s\begin{pmatrix}-\frac{4}{3}\\-\frac{2}{3}\\\frac{4}{3}\\1\end{pmatrix}$\)

Therefore, the general solution in vector form is;

\($\begin{pmatrix}x\\y\\z\\w\end{pmatrix}$ = $\begin{pmatrix}10\\-3\\-2\\0\end{pmatrix}$ $+$ $t\begin{pmatrix}-\frac{5}{3}\\-\frac{4}{3}\\0\\0\end{pmatrix}$ $+$ $s\begin{pmatrix}-\frac{4}{3}\\-\frac{2}{3}\\\frac{4}{3}\\1\end{pmatrix}$\)

(a) The corresponding homogeneous system is given as;

\($\begin{pmatrix}1 & 2 & 3 & -2\\2 & 3 & 4 & -3\\0 & 2 & 1 & 5\\-3 & 0 & 0 & 0\end{pmatrix}$\)

\($\begin{pmatrix}x\\y\\z\\w\end{pmatrix}$\)\($=$\) \($\begin{pmatrix}0\\0\\0\\0\end{pmatrix}$\)

The solution to the homogeneous system is

\($\begin{pmatrix}x\\y\\z\\w\end{pmatrix}$ = $t_1\begin{pmatrix}-\frac{5}{3}\\-\frac{4}{3}\\0\\0\end{pmatrix}$ $+$ $t_2\begin{pmatrix}-\frac{4}{3}\\-\frac{2}{3}\\\frac{4}{3}\\1\end{pmatrix}$\)

Therefore, the general solution in vector form is;

\($\begin{pmatrix}x\\y\\z\\w\end{pmatrix}$ $=$ $t_1\begin{pmatrix}-\frac{5}{3}\\-\frac{4}{3}\\0\\0\end{pmatrix}$ $+$ $t_2\begin{pmatrix}-\frac{4}{3}\\-\frac{2}{3}\\\frac{4}{3}\\1\end{pmatrix}$\)

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a) The system of linear equations can be represented in augmented matrix form as follows:

\($$\left[\begin{array}{cccc|c}1&2&3&-2&1\\2&3&4&-3&-2\\0&2&1&5&4\\-3&0&0&0&0\\\end{array}\right]$$\)

Applying Gaussian elimination to the above matrix, we get

\($$\left[\begin{array}{cccc|c}1&2&3&-2&1\\0&-1&-2&1&-4\\0&0&1&4&6\\0&0&9&-6&-3\\\end{array}\right]$$\)

Therefore, the system of linear equations has the general solution in vector form as:

\($$\boxed{\begin{aligned}x &= 8s + 7t - \frac{17}{3}\\y &= -4s - 3t + \frac{10}{3}\\z &= -6t - 6\\w &= t\\\end{aligned}}$$\)

where s, t are arbitrary constants.

b) The corresponding homogeneous system is obtained by replacing the constants on the right-hand side of the above equations with zeros as follows:

\($$\left[\begin{array}{cccc|c}1&2&3&-2&0\\2&3&4&-3&0\\0&2&1&5&0\\-3&0&0&0&0\\\end{array}\right]$$\)

Applying Gaussian elimination to the above matrix, we get

\($$\left[\begin{array}{cccc|c}1&2&3&-2&0\\0&-1&-2&1&0\\0&0&1&4&0\\0&0&0&0&0\\\end{array}\right]$$\)

Therefore, the general solution of the homogeneous system can be written as:

\($$\boxed{\begin{aligned}x &= -2s - 3t\\y &= -2t\\z &= -4t\\w &= s\\\end{aligned}}$$\)

where s, t are arbitrary constants.

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The government of Smartypants would need to subsidize college education per student by $2,000.

The question is asking about how much the government of Smartypants would need to subsidize college education per student to achieve the socially optimal level of education.

As per the graph given below, the socially optimal level of education is where MSB = MPC.

So, the government of Smartypants would need to subsidize college education per student by $2,000 to achieve the socially optimal level of education.

The subsidy shifts the supply curve to the right, and so the equilibrium quantity demanded of education increases from QP to QS.

As a result, the market price decreases from PP to PS.The diagram below shows the effects of a subsidy on the market for education. The supply curve shifts to the right, which increases the quantity of education from Q1 to Q2.

The demand curve does not shift as the cost to consumers has not changed, and the price of education falls from P1 to P2. The subsidy per student is represented by the distance between the original MPC and the new MSC curves at the socially optimal level of education.

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Answer:

x= -1, y = -1

Step-by-step explanation:

-16x +24y = -8

16x -8y = -8

16y = -16

y=-1

16x = -16

x = -1

Answer:

x = - 0.25 = - 1 / 4

y = 0.5 = 1 / 2

Step-by-step explanation:

4x + 6y = 2

Divide 2 on both sides,

2x + 3y = 1 ----> eq. 1

16x - 8y = - 8

Divide - 8 on both sides,

- 2x + y = 1 ----> eq. 2

Add eq. 1 and 2,

2x + 3y = 1

- 2x + y = 1

_________

0 + 4y = 2

4y = 2

y = 2 / 4

y = 1 / 2

y = 0.5

Substitute y = 0.5 in eq. 2,

- 2x + y = 1

- 2x + 0.5 = 1

- 2x = 1 - 0.5

- 2x = 0.5

x = 0.5 / - 2

x = - 0.25

Answer: i think b

Step-by-step explanation:

The stationing of BC1, EC1, BC, and EC2 can be determined by adding the respective distances to the station of Point A.

To determine the station of BC1, EC1, BC, and EC2, we need to understand the concept of stations in road centerline alignment. In road design and construction, stations are used to measure distances along the centerline of the road. The station of a point refers to its distance from a reference point, typically the starting point of the road.

Given that the station of Point A is 3+ def ghi, we can assume that the stationing system used is based on chainage, where the main stations are represented by whole numbers and the sub-stations are represented by decimals or fractions.

Let's break down the given distances:

The distance from Point A to Pls is 222.841.

The distance from Point Ply to Ply is 345.036.

The distance from Point Pl2 to b is 214.761.

Based on the given information, we can determine the stations as follows:

Station of Point A: 3+ def ghi (given).

Station of BC1: Station of Point A + Distance from Point A to Pls = 3+ def ghi + 222.841.

Station of EC1: Station of BC1 + Distance from Point Ply to Ply = (3+ def ghi + 222.841) + 345.036.

Station of BC: Station of EC1 + Distance from Point Pl2 to b = ((3+ def ghi + 222.841) + 345.036) + 214.761.

Station of EC2: Station of BC + Distance from Point Pl2 to b = ((3+ def ghi + 222.841) + 345.036 + 214.761) + 214.761.

The above equations represent the stationing along the road centerline from Point A to BC1, EC1, BC, and EC2, respectively. By substituting the given station of Point A and the distances into the equations, we can calculate the stations of BC1, EC1, BC, and EC2.

Please note that the specific numerical values for def, ghi, and the distances are not provided in the question, so the actual station values cannot be determined without those values. However, you can substitute the known values into the equations to calculate the stations once you have the complete information.

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Answer:

0

Step-by-step explanation:

So we have the function:

\(p(x)=(x-1)(x+1)\)

To find p(1), substitute x for 1:

\(p(1)=((1)-1)((1)+1)\\\)

Simplify:

\(p(1)=(0)(2)\\p(1)=0\)

Thus, p(1) is 0.

The rate of change of the distance with respect to time that the box submarine traveled is 11 feet per second

A rate of change describes how one quantity changes in relation to another quantity.

Mathematically, it is defined as the change in one quantity divided by the change in the other quantity.

In this case, we have:

rate of change = change in distance / change in time

Use the data in the table:

rate of change = 545-380/15-0

rate of change = 165/15 = 11

Note: You can pick any 2 data points for the calculation

Therefore, 11 feeet per second is the rate of change of the distance in feet below sea level with respect to time that the box submarine traveled

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Answer:

x ≥ 2 4/9 days

Step-by-step explanation:

Rosa runs 3 1/3 miles on Monday. Each day after that, she runs the same 1 1/2 mile route every morning. Her goal is to run at least 7 miles by the end of the week. Which inequality represents the least number of days after Monday that Rosa needs to run to reach her goal?

Let the number of days left after Monday to run = x

At least 7 miles = Greater than or equal to

Hence:

Our inequality equation is given as:

3 1/3 + 1 1/2x ≥ 7

1 1/2x ≥ 7 - 3 1/3

1 1/2x ≥ 3 2/3

x ≥ 3 2/3 ÷ 1 1/2

x ≥ 11/3 ÷ 3/2

x ≥ 11/3 × 2/3

x ≥ 22/9

x ≥ 2 4/9 days

Therefore, the inequality that represents the least number of days after Monday that Rosa needs to run to reach her goal is

x ≥ 2 4/9 days

Answer: 2

Step-by-step explanation:

The points (0, 4) and (2, 8) lie on the line. Using the gradient formula,

\(m=\frac{8-4}{2-0}=2\)

The ordered pair equivalent to (x, y) is (cos 0, sin 0) which evaluated to  (1, 0). Therefore the correct option is (D).

Ordered Pair (x, y) represents the coordinates of a point on the Cartesian plane.

Evaluating each of the given options:

A. (sin 0, cos 0):

At angle 0,

sin(0) = 0  

cos(0) = 1.

So, this ordered pair is (0, 1).

B. (cot 0, tan 0):

At angle 0,

cotangent is not defined,  

tangent(0) = 0.

So, this ordered pair is undefined.

C. (tan 0, cot 0):

At angle 0,

tangent(0) = 0,

cotangent is not defined.

So, this ordered pair is undefined.

D. (cos 0, sin 0):

At angle 0,

cos(0) = 1,

sin(0) = 0.

So, this ordered pair is (1, 0).

Based on the evaluations, the ordered pair (x, y) equivalent to (x, y) is option D: (cos 0, sin 0), which is (1, 0).

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Answer:

A possible solution of (60, 10) does not make sense for this function, unless multiple people can come together to donate an item.

Check explanation for more explanantion.

Step-by-step explanation:

If x represents the number of people who donated an item and g(x) represents the number of items collected.

The x and g(x) values are usally presented in a coordinates format like (x, y) where y = g(x).

So, (60, 10) means that 60 people donated 10 items.

Unless multiple people can come together to donate an item, it isn't possible for 60 people to donate 10 items.

Hence, a possible solution of (60, 10) does not make sense for this function, unless multiple people can come together to donate an item.

Hope this Helps!!!

The operations involving complex numbers that have solutions represented by point A on the graph include the following:

C. 2(-1 + 2i) - (4 - 3i).

D. (-2 + 4i) + (-4 + 3i).

In Mathematics and Geometry, a complex number can be defined as any numerical value or quantity that is composed of two (2) main parts, which include a real number and an imaginary number.

Next, we would evaluate each of the complex numbers in order to determine if their solutions represented by point A on the graph as follows;

2(1 - 2i) - (4 + 3i).

2 - 4i - 4 - 3i

-2 - 7i (not represented by point A).

2(1 + 2i) + (-4 - 3i).

2 + 4i - 4 - 3i

-2 + i (not represented by point A).

2(-1 + 2i) - (4 - 3i).

-2 + 4i - 4 + 3i

-6 + 7i (represented by point A).

(-2 + 4i) + (-4 + 3i).

-2 + 4i - 4 + 3i

-6 + 7i (represented by point A).

(-2 - 4i) + (4 - 3i).

-2 - 4i + 4 - 3i

2 - 7i (not represented by point A).

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

Distributive Property

Step-by-step explanation:

This is my best guess because you didn't put the topic or give an more information.