Answer:
The ball takes 2.23 seconds to reach the ground
Explanation:
Free Fall Motion
A free-falling object falls under the influence of gravity only. An object being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not have air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is \(g = 9.8 m/s^2\).
The distance traveled by a dropped object is:
\(\displaystyle y=\frac{gt^2}{2}\)
Knowing the height h from which the object was dropped, we can find the time it takes fo hit the ground:
\(\displaystyle t=\sqrt{\frac{2h}{g}}\)
Since y=24.3 m:
\(\displaystyle t=\sqrt{\frac{2\cdot 24.3}{9.8}}\)
t=2.23 seconds
The ball takes 2.23 seconds to reach the ground
What must the sum of the Formal Charge of the atoms in a molecule/polyatomic ion equal?
The sum of the formal charges of the atoms in a molecule or polyatomic ion must equal the overall charge of the species. Formal charge is a way of keeping track of the distribution of electrons in a molecule or ion.
It is calculated by subtracting the number of electrons assigned to an atom in a molecule from the number of valence electrons of that atom in the neutral state. For a neutral molecule, the sum of the formal charges of all the atoms should be zero. For a polyatomic ion with a positive or negative charge, the sum of the formal charges of all the atoms should be equal to the overall charge of the ion. This is a useful tool for determining the most likely arrangement of atoms in a molecule or ion, and for predicting the polarity of a molecule.
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What type of radiation is emitted by planets and star-forming clouds?.
Infrared radiation is emitted by planets and star-forming clouds.
Infrared radiation is a type of electromagnetic radiation with a longer wavelength than visible light, but shorter than radio waves. It is emitted by all objects with a temperature above absolute zero, including planets and star-forming clouds. This type of radiation is useful for observing astronomical objects because it can penetrate through dust and gas clouds that block visible light.
Infrared radiation is emitted by planets due to their thermal energy. The planets absorb radiation from the Sun and re-emit it as infrared radiation. Observing the infrared radiation from a planet can reveal information about its temperature, composition, and surface features.
Star-forming clouds also emit infrared radiation due to the heat generated by the formation of new stars. As these clouds collapse and fragment, they heat up and emit radiation across the electromagnetic spectrum, including in the infrared region. This allows astronomers to study the early stages of star formation and the physical conditions within these clouds.
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why is ""friction"" (also called viscosity when it pertains to a gas) crucial for accretion disks?
Because Friction between gas orbiting at different speeds transfers angular momentum, also generating heat.
Friction is nothing but the opposing force acting on the device. In this case when accretion disks moves, it transfers angular momentum and and due to friction it also generates heat.
And as we know from conservations of energy that whatever heat is generated and angular momentum gets transferred, both will act as a negative parameter for a accretion disks.
That is the reason it is vey important to know and take care of the friction during designing or using of accretion disks.
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What does acceleration measure?
A. Change in velocity over time
B. Change in speed over time
C. Change in distance over time
D. Change in displacement over time
Answer: A.) Change in Velocity over Time
Explanation:
The definition of acceleration is Δv/t, or the change in velocity over time. Acceleration, like velocity, will therefore have a magnitude, as well as a direction.
Consider the system shown in the figure. The rope and pulley have negligible mass, and the pulley is frictionless. The coefficient of kinetic friction between the 8.00-kg block and the tabletop is m_k=.25 . The blocks are released from rest.Use energy methods to calculate the speed of the 6.00-kg block after it has descended 1.50 m. How do i calculate work on the 8kg block.
Plugging in the given values and solving for the final velocity of the 6kg block will give you the speed of the 6.00-kg block after it has descended 1.50 m. In this case, the normal force is the weight of the 8kg block, and the displacement is the distance that the 8kg block moves.
Energy Method Block SpeedTo calculate the speed of the 6.00-kg block after it has descended 1.50 m, you can use the conservation of mechanical energy. The initial mechanical energy of the system is the potential energy of the 6.00-kg block (mgh) and the potential energy of the 8.00-kg block (mgh). As the blocks move, some of this energy is converted into kinetic energy, and some is lost to friction. The equation for the conservation of mechanical energy is:
E_initial = E_final + W_friction
Where E_initial is the initial mechanical energy of the system, E_final is the final mechanical energy of the system, and W_friction is the work done by friction.
The final mechanical energy of the system is the kinetic energy of the 6.00-kg block (1/2 mv²) and the potential energy of the 8.00-kg block (mgh).
To calculate the work done by friction, you can use the equation:
W_friction = force x distance x cos(theta)
Where force is the force of friction, distance is the distance over which the force of friction acts, and theta is the angle between the force of friction and the displacement. The force of friction is the coefficient of kinetic friction times the normal force.
In this case, the normal force is the weight of the 8kg block, and the displacement is the distance that the 8kg block moves.
W_friction = m_kF_nd
Where m_k = 0.25 is the coefficient of kinetic friction, F_n = 8*9.8 N is the normal force, and d = 1.5m is the distance that the 8kg block moves.
Plugging in the given values and solving for the final velocity of the 6kg block will give you the speed of the 6.00-kg block after it has descended 1.50 m.
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A cyclist traveled 8 kilometers per hour faster than an in-line skater. In the time it took the cyclist to travel 65 kilometers, the skater had gone 39 kilometers. Find the speed of the skater.
The speed of the skater is 22km per hour.
What is speed?
speed is simply defined as The rate of change of position of an object in any direction.
Sol-so a cyclist is traveling 11 km/h faster than an incline skater. And the time it took the Travis the cyclists go, 18 km skater has gone nine, find the speed of the skater. Okay, so let's translate this like solving for X is Okay, let's say X is the speed of the skater. Um And then cyclists speed would be why uh the cyclist went faster than in line. So that would make 11 faster. That'd be like X plus 11. So, The cyclist is skater and 11 more. Cool. Okay, it took the cyclist 18 km. It took the skater, nine km the same amount of time. Okay, so what does that mean? Well, 18 divided by nine is to, so basically that means the the cyclist is well twice as fast as the as a skater really. And now we have these to form these ones, notice they both say y equals and that means well, since these wires are really the same thing, they're both the speed the cyclists, that means that you can actually just make both sides equal to each other. Um I'm sorry. That should be an equal sign. Why equals X plus, I love it. All right. And now you subtract X from both sides and then you find out that well, X is 11. So, that is the speedof the skater. The skater is going 11 kilometres ah for our um And that would mean the
Thus,
cyclist is going 22 kilometres per hour.
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The magnetic force on a straight wire 0.30 m long is 2.6 x 10^-3 N. The current in the wire is 15.0 A. What is the magnitude of the magnetic field that is perpendicular to the wire?
Answer: the magnitude of the magnetic field perpendicular to the wire is approximately 1.93 x 10^-3 T.
Explanation:
The magnetic force on a straight wire carrying current is given by the formula:
F = B * I * L * sin(theta),
where F is the magnetic force, B is the magnetic field, I is the current, L is the length of the wire, and theta is the angle between the magnetic field and the wire (which is 90 degrees in this case since the field is perpendicular to the wire).
Given:
Length of the wire (L) = 0.30 m
Current (I) = 15.0 A
Magnetic force (F) = 2.6 x 10^-3 N
Theta (angle) = 90 degrees
We can rearrange the formula to solve for the magnetic field (B):
B = F / (I * L * sin(theta))
Plugging in the given values:
B = (2.6 x 10^-3 N) / (15.0 A * 0.30 m * sin(90 degrees))
Since sin(90 degrees) equals 1:
B = (2.6 x 10^-3 N) / (15.0 A * 0.30 m * 1)
B = 2.6 x 10^-3 N / (4.5 A * 0.30 m)
B = 2.6 x 10^-3 N / 1.35 A*m
B ≈ 1.93 x 10^-3 T (Tesla)
1. What is the voltage across each resistor?
2. What is the current in each branch?
3. What is the total current provided by the batteries?
For top and bottom picture.
For top picture, I also need to know: Use the total current and the total voltage to calculate the total resistance of the circuit.
The current provided in each branch for 12V circuit are 6 A and 4 A.
The total current provided for the 12 V circuit is 10 A.
The current provided in each branch for 9V circuit are 4.5 A, 3 A and 9 A.
The total current provided for the 12 V circuit is 16.5 A.
What is the current in each branch?The current provided in each branch of the parallel circuit is calculated as follows;
For the 12V circuit;
I = V/R
where;
V is voltageR is the resistancebranch 1 = 12/2 = 6 A
branch 2 = 12/3 = 4 A
Total resistance;
1/Rt = 1/2 + 1/3
1/Rt = 5/6
Rt = 6/5 = 1.2 ohm
Total current is calculated as;
I_t = 12 V/1.2 ohm = 10 A
For the 9 V circuit:
branch 1 = 9/2 = 4.5 A
branch 2 = 9/3 = 3 A
branch 3 = 9/1 = 9 A
Total resistance;
1/Rt = 1/2 + 1/3 + 1/1
1/Rt = 11/6
Rt = 6/11 = 0.545 ohms
Total current is calculated as;
I_t = 9 V/0.545 ohm = 16.5 A
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A 1000 kg car travels on a highway with a speed of 30 m/s. The driver sees a roadblock and applies the brakes, which provide a
constant braking force of 4 kN. What is the acceleration of the car?
A. 4 m/s
Answer:
-4m/s
Explanation:
use the formula
\(f = ma\)
where f-force
m-mass
a-accleration
so
1kN=1000N
so apply
4000=1000×a
a=4m/s
(the negative is because the car was braking)
Answer:
Your answer is -4 m/s^2
Explanation:
Set Up: Let +x be the direction the car is traveling.
List the known & unknown quantities:
m = mass of the car = 1000 kg
υ = 30 m/s
Fx = –4 kN = –4000 N (negative since it is a braking force)
ax = acceleration =?
Solve: Use Newton’s second law of motion.
Fx=max
ax=Fx/m = −4000 N /1000 kg = −4000 kg·m/s^2 / 1000 kg =−4m/s^2
what would happen after a warm front passes to the air
After a warm front passes through the air, the air becomes more warm and humid.
If warm air mass replaces the cold air mass, it is called as warm front. A warm front is called as transition zone. Warm fronts usually move from southwest to northeast. Warm fronts move slower than cold fronts.
When a warm front passes over a region there will be some significant weather changes. Before the warm front passes precipitation will be light to moderate, snow, sleet or drizzle and after the front has passed there will be usually no precipitation.
Therefore, after a warm front passes through the air, the air becomes more warm and humid.
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Friction _____.
1.happens whenever work is done
2.occurs when objects rub against each other
3.releases energy as heat
4.all of the above
Answer:
all above
Explanation:
friction is necessary to live
Answer:
All of above
Explanation:
Based on what you learned about astronomy from space, select all of the correct statements from the following list.
The Compton, Chandra and Spitzer telescopes are all examples of space telescopes.
Most types of electromagnetic waves are not visible to ground-based telescopes.
Enough infrared energy gets to Earth's surface that infrared telescopes do not need to be put in orbit.
Cosmic rays are the absolute highest-energy type of electromagnetic wave.
The Hubble Space Telescope makes observations at all wavelengths.
Earth's atmosphere has no effect on visible light, so there is no need to place an optical telescope in space.
All for the sattement A, B, and E is True and satement C, D, and F is False where you learned about astronomy from space.
A .The Compton, Chandra and Spitzer telescopes are all examples of space telescopes.
-This statement is True.
B. Most types of electromagnetic waves are not visible to ground-based telescopes.
-This statement is True.
C. Enough infrared energy gets to Earth's surface that infrared telescopes do not need to be put in orbit.
-This statement is False.
D. Cosmic rays are the absolute highest-energy type of electromagnetic wave.
-This statement is False.
E. The Hubble Space Telescope makes observations at all wavelengths.
-This statement is True.
F. Earth's atmosphere has no effect on visible light, so there is no need to place an optical telescope in space.
-This statement is False.
Astronomy is the scientific study of celestial objects and phenomena, including stars, planets, galaxies, and the universe as a whole. Astronomers use various tools and techniques, such as telescopes, spectroscopy, and astrophysics, to observe and understand the properties and behavior of these celestial objects.
Through the study of astronomy, scientists have discovered many fascinating things about the universe, such as the existence of black holes, the age and size of the universe, and the formation and evolution of stars and galaxies. Astronomy has also played a significant role in advancing our understanding of fundamental physics, including the laws of gravity and the behavior of matter and energy at extreme conditions.
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Consider an extension of our Cobb-Douglas technology Y=AK
α
L
β
M
γ
where, in addition to the known variables, M is the amount of raw materials consumed in production. All parameters A,α,β,γ are strictly positive. What is the condition on the parameters that makes the technology constant returns to scale in K,L and M ? Increasing returns to scale? Hint: Observe that by setting γ=0, you will obtain the production function we used in class. Is your answer when you set γ=0 consistent with what we learned in class? Question 3.2 Consider the so-called constant elasticity of substitution (CES) technology Y=[aK
α
+bL
α
]
β
where a,b>0 and α and β are nonzero. What is the restriction on the parameters that makes the production function be constant returns to scale in K and L ?
The production function will have constant returns to scale if 2αβ = 1
Constant returns to scale (CRS) implies that if all inputs increase by a factor of λ, the output increases by λ as well. The requirement for constant returns to scale (CRS) in a Cobb-Douglas production function with a new input factor is given by the sum of exponents on all variables equal to 1.
In this case, Y = AKαLβMγ.
Thus, we have that α + β + γ = 1 for constant returns to scale in K, L, and M, because the sum of the exponents is 1.
If the sum of the exponents is less than 1, it indicates decreasing returns to scale. If the sum of the exponents is greater than 1, it indicates increasing returns to scale. If we take γ = 0, we obtain the production function used in class, which is Y = AKαLβ, thus α + β = 1 for constant returns to scale in K and L.
When γ = 0, the answer we get is consistent with what we learned in class. Now, we consider the constant elasticity of substitution (CES) technology, where Y = [aKα + bLα]β. The production function will have constant returns to scale (CRS) in K and L if the sum of the exponents of K and L is equal to 1.
Therefore, αβ + αβ = 1, implying 2αβ = 1.
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which one of the following is true
a. momentum results in a change of force
B. a force results in a change of momentum
Answer:
B
Explanation:
You need a specific force to change the momentum of something.
Hope this helps!
a closed end manometer was constructed from a u-shaped glass tube which was 80.0 cm high. it was loaded with mercury so that the closed side was filled all the way to the top (80.0 cm above the neck) while the open end was at a level 18.0 cm above the neck. it was taken into a chamber used for training astronauts. what is the highest pressure, in torr, that can be read on this manometer? a. 62.0 torr b. 62.5 torr c. 98.0 torr d. 98.5 torr e. 620. torr
The highest pressure which can be read in the closed-end glass manometer is given by option e 620 torr
At the highest pressure, the height of mercury in the closed end will be 80 cm. The height of mercury in the open end will be 18 cm. The pressure read on the manometer = pressure exerted be difference in heights of mercury in the closed end manometer = 80-18 cm of mercury = 62 cm of mercury= 62 cm of Hg
62 cm of Hg = 620 mm of Hg
We know that 1 mm Hg = 1 Torr.
Therefore 620 mm Hg = 620 Torr. answer
Thus the answer for the highest pressure that can be read in torr on this manometer is option e which is 620 torr
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The Rodriguez family roasted marshmallows over a campfire one night. They noticed that they all had to help carry the logs to the backyard, but only one of them had to sweep up the ashes and carry them away. In other words, the mass of the ashes was much less than the mass of the original logs. The mass of the logs was 10Kg before burning and after combustion, the ashes had a mass of 1Kg
Write a CER for this please!
The total mass of the system after combustion is therefore 1Kg (ashes) + 9Kg (gases and water vapor) = 10Kg, which is the same as the total mass before combustion.
What is law of conservation of mass?Therefore, if the mass of the logs before burning was 10Kg, the total mass of the system before combustion was 10Kg (logs) + 0Kg (oxygen) = 10Kg. After combustion, the mass of the ashes was 1Kg, so the mass of the remaining gases and water vapor released into the atmosphere was 10Kg - 1Kg = 9Kg.
What are the three laws of energy conservation?There are three fundamental quantities in mechanics that are conserved. These are power, forward motion, and angular momentum.
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You observe that exoplanet A has satellite B.We measure the
period at which satellite B orbits around planet A, and it is 7.14
days. Let's assume that the orbital is fully constant-speed
circular moti
Satellite B orbits exoplanet A in a circular motion with a constant speed, completing one orbit every 7.14 days.
The period of satellite B's orbit around exoplanet A is 7.14 days. This means that it takes 7.14 days for the satellite to complete one full revolution around the planet. The fact that the orbit is described as "constant-speed circular motion" indicates that the satellite moves in a circular path around the planet with a consistent speed. In a circular orbit, the satellite maintains a fixed distance from the planet throughout its journey. The orbital speed of the satellite remains constant, meaning that it covers equal distances in equal intervals of time. This behavior is consistent with the laws of planetary motion, particularly Kepler's laws, which govern the motion of objects in space. Therefore, based on the given information, we can conclude that satellite B consistently completes one orbit around exoplanet A every 7.14 days in a circular path with a constant speed.
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A riverbed with a shallow slope will yield high velocity streamflow. True False
Streamflow is the flow of water in streams, rivers, and other channels, and is a key component of the water cycle. It's influenced by a variety of factors, including the shape and depth of the riverbed, the gradient of the stream, the size and shape of the channel, and the amount of water flowing through it. The given statement is false.It is affected by many factors.
All of these factors influence the velocity of the streamflow. Riverbed and streamflow relationshipThe velocity of streamflow is primarily influenced by the gradient or slope of the riverbed. A shallow slope will not yield high velocity streamflow, but instead will create a slow-moving, meandering stream with a high potential for sedimentation and erosion. In contrast, a steep gradient will create a fast-moving stream with a higher velocity and more turbulent water. As a result, a steeper slope will produce higher velocity streamflow than a shallower slope, which will produce slower-moving streamflow. Therefore, a riverbed with a shallow slope will not yield high velocity streamflow. The statement is false.
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One of the largest planes ever to fly, and the largest to fly frequently, is the Ukranian-built Antonov An-124 Ruslan. Its wingspan is 73.2 m and its length is 69.2 m. The GPE associated with the plane at an altitude of 1.45 km is 3.36 x 10⁹ J. What is the plane’s mass? (You must convert from km to m.)
GPE = mgh
3.36 x 10⁹ J = m x 9.8 m/s² x 1.45 x 10³ m
m = 2.36 x 10⁵ kg
what is the physical state of gold at room temperature
Answer:
solid
Explanation:
Gold is a chemical element with symbol Au and atomic number 79. Classified as a transition metal, Gold is a solid at room temperature.
The earth's atmosphere has about \( 10^{-4} \% \) helium and about \( 10^{-5} \% \) hydrogen Can this be explained from kinetic theory considerations?
The presence of helium and hydrogen in the Earth's atmosphere can be explained through kinetic theory considerations. The different masses and velocities of gas particles lead to variations in their distribution, resulting in the observed concentrations of helium and hydrogen.
According to the kinetic theory of gases, gases consist of numerous particles in constant random motion. The average kinetic energy of gas particles is directly proportional to the temperature. However, the speed and mass of particles also play a role in determining their distribution in the atmosphere.
Helium (He) has a lower mass compared to other gases, including nitrogen and oxygen, which are the primary components of the Earth's atmosphere. Due to its lower mass, helium atoms have higher average velocities at a given temperature.
Consequently, helium tends to have a higher probability of reaching escape velocity and escaping the Earth's gravitational field. This results in a relatively low concentration of helium in the atmosphere.
Similarly, hydrogen (H₂) has an even lower mass than helium, making it more likely to have higher average velocities and escape the atmosphere.
However, hydrogen is also highly reactive and tends to react with other elements, forming compounds or escaping into space. This leads to a very low concentration of hydrogen in the Earth's atmosphere.
In contrast, gases like nitrogen (N₂) and oxygen (O₂) have higher molecular masses and lower velocities, making them less likely to escape and allowing them to accumulate in larger quantities in the atmosphere.
Therefore, the variations in the mass and velocity of gas particles, as explained by kinetic theory considerations, help us understand the relatively low concentrations of helium and hydrogen in the Earth's atmosphere.
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WHAT FITNESS INJERIES ARE AMOUNG THE EASIEST TO AVIOD
Answer:
eye ,mouth,and,ears face
Answer:
knee, elbow, and wrist
Explanation:
Which amateur service HF bands have frequencies authorized to space stations?Correct AnswerA.Only 40m, 20m, 17m, 15m, 12m and 10mB.Only 40m, 20m, 17m, 15m and 10m bandsC.40m, 30m, 20m, 15m, 12m and 10m bandsD.All HF bands
The correct answer to the question about which amateur service HF bands have frequencies authorized to space stations is Only 40m, 20m, 17m, 15m, 12m and 10m amateur service HF bands have frequencies authorized to space stations. Option A.
This is because these frequencies have been allocated specifically for amateur radio communication with space stations. It is important to note that there are strict regulations and procedures in place for communicating with space stations on these bands, and operators must have the necessary licenses and equipment to do so. Overall, amateur radio communication with space stations can be an exciting and rewarding experience, but it requires a high level of skill and dedication. Option A.
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A parallel plate capacitor is made of plates 1.0 sqm and has a separation of 1 mm. The space between the plates is filled with dielectric of εr = 25. If 1.0-kV potential difference is applied to the plates, find the force squeezing the plates together.
The force squeezing the plates of the parallel plate capacitor together is approximately 1,106,250 N.
To find the force squeezing the plates of a parallel plate capacitor together, we can use the formula:
F = (1/2) × ε₀ × εᵣ × A × (V/d)²
Where:
F is the force
ε₀ is the vacuum permittivity (ε₀ ≈ 8.85 × \(10^{-12\) F/m)
εᵣ is the relative permittivity (dielectric constant)
A is the area of the plates
V is the potential difference applied to the plates
d is the separation between the plates
Given:
Area of the plates (A) = 1.0 m²
Separation between the plates (d) = 1 mm = 0.001 m
Relative permittivity (εᵣ) = 25
Potential difference (V) = 1.0 kV = 1000 V
Now let's substitute the values into the formula to calculate the force:
F = (1/2) × ε₀ × εᵣ × A × (V/d)²
F = (1/2) × (8.85 × \(10^{-12\) F/m) × 25 × 1.0 m² × (1000 V / 0.001 m)²
Simplifying the calculation:
F = 0.5 × 8.85 × 25 × 1.0 × (10³ / \(10^{-3\))² N
F = 0.5 × 8.85 × 25 × 1.0 × 10^6 N
F ≈ 1106250 N
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According to Loftus, why is the study of eyewitness memory important? Be sure to include a specific quotation from the excerpt above to support your explanation.
Do the Loftus studies support the use of eyewitness testimony as evidence? Be sure to include specific details from the studies to support your position.
Loftus thought that, to a certain extent, eye witness recollection was significant during a court case or prosecution. Eye witness memory, according to Loftus, is crucial since it provides a different perspective and gauges how reliable a witness's testimony is.
What is eyewitness memory?A person's memory of a particular occurrence, sometimes a crime or accident of some sort, that he or she directly witnessed or experienced. Given the occurrence of phenomena like the weapon-focus effect and the disinformation effect, the credibility of eyewitness evidence is a significant problem in forensic psychology.The law certainly cares about knowing something about the precision, completeness, and malleability of such memories, he said. So he doesn't entirely back the use of eye witness memory. This is so that, because an eyewitness's memory is "malleable," the prosecutor's tone of voice could persuade the witness to alter his or her statement.According to Loftus, eye witness recall is crucial since it provides a different viewpoint and gauges how reliable a witness's testimony is. It also gauges the degree to which it can be trusted. It is evident that the law is interested in learning more about the precision, completeness, and malleability of such memories." His assertion amply supports the significance of eye witness recall.To know more about eyewitness memory, visit:
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An ambulance emits a frequency of 450 Hz from its siren. What frequency is heard by a man as the ambulance moves toward him? less than 450 Hz more than 450 Hz 450 Hz 0 Hz.
Frequency is defined as the number of repetitions of waves occurring in 1 second. The frequency heard by the man as the ambulance move toward him will be greater than 450 Hz.
What is the frequency ?Frequency is defined as the number of cycles completed in 1 second. Frequency is given by the formula as,
\(\rm{Frequency =\frac{1}{time } }\)
As the formula shows frequency is inversely proportional to the time that shows if the time is decreasing frequency will increase and vice versa.
In the above case, the ambulance is moving toward the men. So that the time to meet up is decreased that's why the frequency will be greater than the initial frequency from the siren.
Hence the frequency heard by the man as the ambulance move toward him will be greater than 450 Hz.
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Answer: the answer is b more than 450 hz
Explanation: i took the test
the average human body contains approximately 5 liters of blood. if the blood has a density of 1060 kg/m3, what is the total mass of blood in the average human? (note: 1 l
The total mass of blood in the average human is approximately 5.3 kilograms.
To find the total mass of blood in the average human, we need to multiply the volume of blood by its density.
Given that the average human body contains approximately 5 liters of blood and the density of blood is 1060 kg/m^3, we can proceed as follows:
1. Convert 5 liters to cubic meters:
1 liter = 1/1000 cubic meters
So, 5 liters = 5/1000 = 0.005 cubic meters
2. Multiply the volume of blood by its density:
Mass = Volume × Density
Mass = 0.005 cubic meters × 1060 kg/m^3
3. Calculate the total mass of blood:
Mass = 5.3 kg
Therefore, the total mass of blood in the average human is approximately 5.3 kilograms.
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Describe why drawing a line of best fit is useful.
Answer:
Cause life
Explanation:
Cause life
Determine d 2 y d x 2 d2ydx2 as a function of t t , then find the concavity of the parametric curve at t = 6 t=6 .
Substituting these derivatives into the expression we derived earlier, we can find the concavity of the parametric curve at t = 6.
To determine the second derivative of y with respect to x, expressed as a function of t, we need to apply the chain rule twice. Let's denote the second derivative as d^2y/dx^2.
First, we express dy/dx in terms of t using the chain rule:
dy/dt = (dy/dx) * (dx/dt)
Next, we differentiate both sides with respect to t using the chain rule again:
d^2y/dt^2 = (d^2y/dx^2) * (dx/dt)^2 + (dy/dx) * (d^2x/dt^2)
Since we want to find d^2y/dx^2 as a function of t, we can rearrange the equation as follows:
(d^2y/dx^2) = (d^2y/dt^2) / [(dx/dt)^2] - (dy/dx) * (d^2x/dt^2) / [(dx/dt)^3]
Now, to find the concavity of the parametric curve at t = 6, we need to evaluate (d^2y/dx^2) at t = 6.
For this step, we would need additional information. Specifically, we need the functions y(t) and x(t) that describe the parametric curve. Once we have these functions, we can substitute t = 6 into them to find the corresponding values of y and x at t = 6.
With the values of y and x at t = 6, we can compute the first and second derivatives using the appropriate formulas. Finally, substituting these derivatives into the expression we derived earlier, we can find the concavity of the parametric curve at t = 6.
It's important to note that without the specific functions y(t) and x(t), it is not possible to determine the concavity at t = 6 or the second derivative as a function of t.
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do you expect the friction force to have a larger effect on the two accelerations if the angle is larger or smaller? why?
As the angle of incline is increased then acceleration will also increase.
As the angle of the incline is increased, normal force is decreases, which decreases the frictional force also. The incline can be raised until the object begins to slide. The force acting parallel to the plane causes the object to accelerate down the incline and the force of friction opposes the object's motion so it acts upward.
When the angle is increased, the component of weight along the plane also (mg sin θ) increases. To balance this, the frictional force has to increase.
Angular acceleration represents time rate of change of angular velocity. The units for this acceleration is rads/s2 or degrees/s2.
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