(a) A logic circuit is designed for controlling the lift doors and they should close (Y) if: (i) the master switch (W) is on AND either (ii) a call (X) is received from any other floor, OR (iii) the doors (Y) have been open for more than 10 seconds, OR (iv) the selector push within the lift (Z) is pressed for another floor. Devise a logic circuit to meet these requirements. (b) Use logic circuit derived in part (a) and provide the 2-input NAND gate only implementation of the expression. Show necessary steps. (c) Use K-map to simplify the following Canonical SOP expression. F(A,B,C,D) = = mc m(0,2,4,5,6,7,8, 10, 13, 15)

The correct answer is b. uplink. In satellite communication, the uplink refers to the transmission of data from an earth-based station to a satellite.

This is typically done using a dish antenna that sends a signal up to the satellite. Once the satellite receives the signal, it can then retransmit the data back own to earth using a downlink. The uplink is an important component of satellite communication and is used for a variety of applications, such as satellite television, internet access, and military communication. It is crucial that the uplink be reliable and stable in order to ensure that the data being transmitted is accurate and timely.

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Answer:

  μ ≈ 0.408

Explanation:

The coefficient of friction is the ratio of friction force to normal force. The normal force is ...

  F = mg = (2500 kg)(9.8 m/s²) = 24.5 kN

Then the coefficient of friction (μ) is ...

  μ = (10 kN)/(24.5 kN) ≈ 0.408

Answer:

umm u need to work that out

Explanation:

Answer:

speed(0)

square_length = int(input("What is the length of the square?"))

def draw_square():

   pendown()

   for i in range(4):

       forward(square_length)

       left(90)

   penup()

penup()

setposition(-200, -200)

draw_square()

penup()

setposition(-200, 200 - square_length)

draw_square()

penup()

setposition(200 - square_length, 200 - square_length)

draw_square()

penup()

setposition(200 - square_length, -200)

draw_square()Explanation:

Answer:

Explanation:

Given that:

f = 250 Hz

\(\delta\)= 2%

\(f_n\)= 600 Hz

\(\zeta\) = 0.5 to 1.5  increment by 0.05

\(F = A sin (Xt)\)

For 250 Hz = 250 cycle/sec

\(X = 2 \pi t 250\)

\(X = 500 \pi t\)

\(X = Asin (500 \pi t)\)

\(\omega = 250 \\ \\ \omega_n = 600\)

M = 0.98 , 1.02

\(M_{(w)}} = \sqrt{[1-(\frac{w}{w_n})^2 + ( 2\zeta \frac{w}{w_n})^2}\)

\(\frac{1}{M} = [1-(\frac{w}{w_n})^2]+(2 \zeta \frac{w}{w_n})^2\)

\(\zeta = \frac{w_n}{2w}\sqrt{\frac{1}{M^2}-(1-(\frac{w}{w_n})^2)^2}\)

\(\zeta = \frac{600}{2(250)}\sqrt{\frac{1}{0.98^2}-(1-(\frac{250}{600})^2)^2}\)

\(\zeta = 0.7183\)

At 0.7183 value of damping ratio the error value was 2% at 0.98 value of M

\(\frac{1}{M} = [1-(\frac{w}{w_n})^2]+(2 \zeta \frac{w}{w_n})^2\)

\(\zeta = \frac{w_n}{2w}\sqrt{\frac{1}{M^2}-(1-(\frac{w}{w_n})^2)^2}\)

\(\zeta = \frac{600}{2(250)}\sqrt{\frac{1}{1.02^2}-(1-(\frac{250}{600})^2)^2}\)

\(\zeta = 0.6330\)

At  0.6330 value of damping ratio the error value was 2% at 1.02 value of M.

Hence, the damping ratio \(\zeta\) of the transducer must be placed between 0.6330 to 0.7183

The values of h at the two internal boundaries are :

Given data :

Z₁ = Z₂ = Z₃ = 25 m

h top = 120 m

h bottom = 100 m

K₁ = 0.0001 m/s

K₂ = 0.0005 m/s

K₃ = 0.0010 m/s

we will apply the formula below since flow is perpendicular to the bedding plane

Keq = \(\frac{Z1 + Z2 + Z3 }{\frac{Z1}{K1}+\frac{Z2}{K2} + \frac{Z3}{K3} }\)  ----- ( 1 )

Insert values given above into equation 1

Therefore ; Keq = 2.307 * 10⁻⁴ m/s

Hydraulic gradient ( Ieq ) = head loss / length

                                          = ( 120 - 100 ) / 3 * 25

                                   Ieq  = 0.266

Given that the flow is perpendicular to bedding plane

q1 = q2 = q3

V₁ = V₂ = V₃ = V

K₁i₁ = K₂i₂ = K₃i₃ = Keq * ieq

Hence :

V = Keq* Ieq

   = 2.307 * 10⁻⁴ * 0.266

   = 6.15 * 10⁻⁵ m/s .

Also;

K₁i₁ =  Keq * ieq = K₂i₂ = K₃i₃

therefore :

  i₁ = 0.615

  i₂ =  0.123

  i₃ = 0.0615

Pressure at point 1 ( i.e. pressure between first two formations )

h₁ = h top - i₁L₁

   = 120 - 0.615 * 25

   = 104.625 m

Pressure at point 2 ( i.e. pressure between the 2nd and 3rd formation )

h₂ = h₁ - i₂L₂

    = 104.625 - 0.123 * 25

    = 101.55 m

Therefore we can conclude that The values of h at the two internal boundaries are :  h₁ = 104.625 m , h₂ = 101.55 m

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Explanation:

whats

the question choices

The RTS/CTS (Request-to-Send/Clear-to-Send) protocol is designed to prevent collisions in wireless communication. Collisions occur when two or more devices try to transmit data at the same time, resulting in data corruption or loss.

The RTS/CTS protocol is used to avoid collisions by allowing a device to check if the wireless medium is free before transmitting. When a device wants to transmit data, it sends an RTS frame to the receiving device, requesting permission to transmit. The receiving device then responds with a CTS frame, indicating that it is ready to receive the data. This process ensures that only one device transmits at a time, preventing collisions and improving the overall efficiency of the wireless network.

While the RTS/CTS protocol does involve handshakes between devices, it is primarily designed to prevent collisions rather than improve handshaking. It also does not directly address negative acknowledgements or CRC errors. Instead, it focuses on avoiding collisions, which can be a significant issue in wireless networks with multiple devices competing for the same channel. By implementing the RTS/CTS protocol, wireless networks can reduce collisions, improve data transmission rates, and minimize the potential for data loss or corruption.

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Answer:

a bowl, plate,

Explanation:

Answer: So you are dealing with maximum and minimum weights and you want to know what MINIMUM number of supporting strands for this block and tackle system are needed I believe. If so you are dealing with economic imbalances Though we are not worrying about money Right? Right we need physics which Physics study matter and how it moves You would need 8 STRANDS

Explanation: Step By Step

Answer:

\(Q_2 = 32\) mL/s

Explanation:

Given :

The flow is incompressible viscous flow.

The initial flow rate, \(Q_1\) = 1 mL/s

Initial diameter, \(D_1= D_0\)

Initial length, \(L_1=L_0\)

The initial pressure difference to maintain the flow, \(P_1=P_0\)

We know for a viscous flow,

\($\Delta P = \frac{32 \mu V L}{D^2}$\)

\($\Delta P = \frac{32 \mu Q L}{\frac{\pi}{4}D^4}$\)

\($Q \propto \Delta P \times D^4$\)

\($\frac{Q_1}{Q_2}= \frac{P_1}{P_2} \times \left( \frac{D_1}{D_2} \right)^4$\)

\($\frac{1}{Q_2}= \frac{P_0}{2P_0} \times \left( \frac{D_0}{2D_0} \right)^4$\)

\($\frac{1}{Q_2}= \frac{1}{2} \times \left( \frac{1}{2} \right)^4$\)

\($\frac{1}{Q_2}= \frac{1}{32}$\)

∴ \(Q_2 = 32\) mL/s

The flow rate if the pressure difference was increased to 2P0 and the diameter was increased to 2D0 is; Q2 = 32 mL/s

We are given;

Initial flow rate; Q1 = 1 mL/s

Initial uniform diameter; D0

Initial Length; L0

Initial Pressure difference; P0

Relationship between pressure, flow rate and diameter for vicious flow is given by;

Q1/Q2 = (P1/P2) × (D1/D2)⁴

Where;

Q1 is initial flow rate

Q2 is final flow rate

P1 is initial pressure difference

P2 is final pressure difference

D1 is initial diameter

D2 is final diameter

We are told that the pressure difference was increased to 2P0 and the diameter was increased to 2D0. Thus;

P2 = 2P0

D2 = 2D0

Thus;

1/Q2 = (P0/2P0) × (D0/2D0)⁴

>> 1/Q2 = ½ × (½)⁴

1/Q2 = 1/32

Q2 = 32 mL/s

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The correct answer is A. The inputRDD is computed and the data is loaded when the count() action is applied.

In Apache Spark, transformations are lazily evaluated, meaning they are not executed immediately when defined.

The actual computation happens when an action is called on the RDD. In this case, count() is an action that triggers the computation of the RDD and returns the count of elements.

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On the orifice with a 50 mm in diameter opening:

(a) The volume flow rate of water through the pipe is:

\(Q = A_v v\)

where A_v = area of the orifice and v = velocity of the flow.

The area of the orifice is:

\(A_v = \pi ( \frac{d}{2} )^2 = \pi (\frac{50}{2})^2 = 1962.5 mm^2\)

The velocity of the flow is:

\(v = \sqrt{2gH} = \sqrt{2(9.81)(0.15)} = 1.715 m/s\)

Therefore, the volume flow rate is:

Q = 1962.5 mm² × 1.715 m/s = 3.375 m³/s

(b) The average velocity of the flow is:

\(v_avg = Q/A_p = Q/(\pi (\frac{d}{2})^2) = 3.375 m^3/s / (\pi (\frac{100}{2})^2) = 1.082 m/s\)

(c) The head loss caused by the orifice meter is:

\(H_L = \frac{v^2}{2g} = \frac{(1.715)^2}{2(9.81)} = 0.15 m\)

(d) The height of water column required if replaced with water manometer is:

\(H_w = \frac{\rho_m}{\rho_w} H_m = \frac{13.6}{1} (0.15) = 2.04 m\)

Therefore, the answers to your questions are:

(a) The volume flow rate of water through the pipe is 3.375 m^3/s.

(b) The average velocity of the flow is 1.082 m/s.

(c) The head loss caused by the orifice meter is 0.15 m.

(d) The height of water column required if replaced with water manometer is 2.04 m.

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Answer:

b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.

Explanation:

An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.

It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.

Answer:

business operation Manager

Answer:

What are u asking for?

Explanation:

Byzantine architectural exteriors can be characterized as highly decorative, featuring intricate mosaics, ornate details, and extensive use of brickwork.

Byzantine architectural exteriors are characterized by their intricate mosaics, domed roofs, and ornate facades. The use of marble, brick, and stone create a rich and varied texture, while the incorporation of elaborate decoration and geometric patterns add to the opulence of the structures. The use of arches and columns are also prominent in Byzantine architecture, lending a sense of grandeur and solidity to the overall design. The exteriors of Byzantine buildings often serve as a reflection of the wealth and power of the empire, showcasing the artistic and engineering achievements of the time. They are also known for their domes, which are a central element in the design, along with a focus on symmetry and a clear sense of hierarchy in the layout of the structures.

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Neither technician A or B is correct. See the meaning of Yaw sensor below.

The yaw rate sensor detects if the vehicle is spinning around its vertical axis. It assists the ESP control unit in determining the vehicle's present driving-dynamic condition. It must be situated near the vehicle's center of gravity for this function.

When it fails, you will lose traction control and notice warning lights such as the Check Engine light, the stability or traction control light, and OBD2 fault codes. This tutorial will teach you all there is to know about yaw sensors and what they are used for.

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Answer:

4. Competent person

Explanation:

A competent person should inspect the crane

OSHA regulations only require that such equipment be inspected during initial use and annually thereafter by a "competent person"

From the discussion we know that tehcnician A is the correct statement abaout valve train components. Because of the stamped rocker arms arms are more resistant to more aggressive engine conditions.

Whether you're dealing mostly with small blocks from a junkyard or a heavily modified race engine, rocker arms play a big role in unleashing horsepower and reducing friction in the valve train. Automotive rocker arms are typically made of stamped steel or aluminum for high speed applications. Some rocker arms (called roller rocker arms) incorporate bearings at the contact points to reduce wear and friction at the contact points. So we know that technician A has correct statement.

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Answer:

g the djnsbsgsuks bbvv

Answer:i want to be brainliest

Explanation: im new here

Answer:

in the previous sections you have seen that any real number have been the symbol of expenses have asked to represent it on the number line literacy house suppose you want to locate on the number line we know that this line is between two entry so let us look closely at the portions of the number line between between 2 to 25 by 50 bye-bye 2.00 with this into 5

Answer:

B) Inspection Interval of other equipment located near the tank under consideration is not a consideration that must be addressed in determining inspection intervals for AST's.

Explanation:

The capacitive reactance of a DC series circuit increases when its capacitance decreases and vice-versa.

A DC series circuit can be defined as a type of circuit in which all of its resistive components are connected end to end, so as to form a single path for the flow of current.

This ultimately implies that, the same amount of current flows through a direct current (DC) series circuit.

Mathematically, the capacitive reactance of a DC series circuit is given by this formula:

\(X_C = \frac{1}{2\pi fC}\)

Where:

From the above formula, we can deduce that the capacitive reactance of a DC series circuit is inversely proportional to both frequency and capacitance. Thus, the capacitive reactance of a DC series circuit increases when its capacitance decreases and vice-versa.

In conclusion, a capacitor would influence a simple DC series circuit by blocking the flow of direct current (DC) through it.

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The while loop is given as follows in C++:

#include <iostream>

#include <vector>

using namespace std;

int main() {

 vector<int> vect1; // create a vector to store the integers

 int n = 1; // initialize n to 1 to enter the while loop

 while (n != 0) { // continue reading integers until 0 is read

   cin >> n; // read the next integer from input

   if (n != 0) { // if the integer is not 0, add it to the vector

     vect1.push_back(n);

   }

 }

 // print the contents of the vector

 for (int i = 0; i < vect1.size(); i++) {

   cout << vect1[i] << " ";

 }

 return 0;

}

A while loop is a control flow statement in most computer programming languages that allows code to be performed repeatedly based on a supplied Boolean condition. The while loop is similar to a looping if statement.

The code above is an example of a while loop that reads integers from input until zero is read. For each integer read before zero, the code adds the integer to a vector named vect1. After the while loop ends, the code prints the contents of the vector. If the input is 3 8 7 9 0, the output will be 3 8 7 9. See the attached output.

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A 60Hz, 0.5-HP single-phase motor in a washing machine (120V RMS) has an efficiency of 78% at full load (rated output power) and a power factor of 0.72 lagging.

To find the line current, first determine the real power (P) using the formula P = HP × 746, where HP is 0.5. This gives P = 373W. Since efficiency is 78%, the input power (Pin) is P/0.78 = 478.21W. Now, use the power factor (0.72) to find the apparent power (S) by dividing Pin by the power factor: S = 478.21/0.72 = 664.18 VA. To find the line current (I), divide the apparent power (S) by the voltage (120V): I = 664.18/120 = 5.53 A.
The reactive power (Q) can be found using the formula Q = S × sin(arccos(0.72)), resulting in Q = 664.18 × sin(arccos(0.72)) = 536.65 VAR. In summary, the line current is 5.53 A, the reactive power is 536.65 VAR, and the apparent power is 664.18 VA.

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I guess you got the one

hope it helps you better

Explanation:

I have asked question in my profile please tell me the answer