a. A crane at a construction site lifts a concrete block with a mass of m = 277 kg from the ground to the top of a building with a height of h = 22.3 m. How much work did the motor of the crane do? (Assume zero energy loss in the lifting mechanism due to friction.)

b. If the duration of the lift was 2.85 minutes, then what was the average power performed by the crane?

Answer:

v= 4.823 × 10⁻⁹ cm/s

Explanation:

given

flow rate = 9.6 x10-5 cm³/s, d = 0.080mm

r = d/2= 0.080/2= 0.0040 cm

speed = rate of blood flow × area

v = (9.6 x 10⁻⁵ cm³/s) × (πr²)

v = (9.6 x 10⁻⁵ cm³/s) × π(0.0040 × cm)²

v= 1.536 × 10⁻⁹π cm/s

v= 4.823 × 10⁻⁹ cm/s

The law of conservation energy

PE₁ + KE₁ = PE₂ + KE₂

From rest ⇒ v₁ = 0 ⇒ KE₁ = 0

Input the value:

PE₁ = PE₂ + KE₂

\(\tt mgh_1=mgh_2+\dfrac{1}{2}mv_2^2\rightarrow divide\:m\\\\gh_1=gh_2+\dfrac{1}{2}v_2^2\\\\9.8(1.226-0.126)=\dfrac{1}{2}v_2^2\\\\v_2=4.64\:m/s\)

Answer:

Explanation:

Eek

The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.

Accurate findings are desired when any quantity is being measured. Closeness of the measurements to a particular value is referred to as accuracy (like the theoretical value). It is not insignificant that measurements can contain inaccuracies; as a result, the outcome frequently includes a margin error. The sentence above displays the radius's measured value along with its margin of error.

In other words, the aforementioned statement represents a quantity's numerical value along with its tolerance, or the only permissible (and conceivable) values to ensure that the measurement is accurate. The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.

These are all valid radius values, along with all others within this interval. By increasing the number of trials in a measurement, the value for the upper and lower bounds of the error can be decreased.

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Answer:

intensity of this field around the conductor is proportional to the distance from it with the strongest point being next to the conductor and progressively getting weaker further away from the conductor

Answer:

\(\boxed {\boxed {\sf 6,000 \ Newtons}}\)

Explanation:

Force is the product of mass and acceleration.

\(F=ma\)

The mass of the Kia Soul is 1200 kilograms and its acceleration is 5 meters per square second.

\(m= 1200 \ kg \\a= 5 \ m/s^2\)

Substitute the values into the formula.

\(F= 1200 \ kg * 5 \ m/s^2\)

Multiply.

\(F= 6000 \ kg*m/s^2\)

\(F= 6000 \ N\)

Answer:

Force

We know that

F = ma

F = Force

m = mass

a = acceleration

F = 1200 × 5

F = 6000 N

\( \\ \)

The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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The electrical power dissipated by the circuit is 575 W.

The amount of heat energy released in half hour is 0.2875 kWh.

The electrical power dissipated by the circuit is calculated as follows;

P = IV

where;

P = I²R

where;

P = 5² x 23

P = 575 W

The amount of heat energy released in half hour is calculated as follows;

E = Pt

where;

E = 575 W x 0.5 hr

E = 287.5 kW

E = 0.2875 kWh

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Answer: the radius of the circular path is approximately 1637.58 meters.

Explanation:

The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:

F_c = m * g * tan(banking angle)

Where:

F_c is the centripetal force

m is the mass of the airplane

g is the acceleration due to gravity

tan(banking angle) is the tangent of the banking angle

Now, the centripetal force is also given by the formula:

F_c = (m * v^2) / r

Where:

v is the speed of the airplane

r is the radius of the circular path

Equating the two expressions for F_c, we get:

(m * g * tan(banking angle)) = (m * v^2) / r

Canceling out the mass (m) on both sides of the equation, we have:

g * tan(banking angle) = v^2 / r

Solving for r, we get:

r = (v^2) / (g * tan(banking angle))

Substituting the given values:

v = 400 km/h = 400,000 m/h

g = 9.8 m/s^2

banking angle = 20°

Converting the speed to m/s:

v = 400,000 m/h * (1/3600) h/s = 111.11 m/s

Converting the banking angle to radians:

banking angle = 20° * (π/180) rad/° = 0.3491 rad

Now, substituting the values into the formula:

r = (111.11^2) / (9.8 * tan(0.3491))

r ≈ 1637.58 meters

Therefore, the radius of the circular path is approximately 1637.58 meters.

Answer:

Temperate marine climates are humid and have mild winters. There are three kinds of temperate marine climates: marine west coast, humid subtropical, and mediterranean. Marine west coast climates are the coolest temperate marine climates. Humid ocean air brings cool, rainy summers and mild, rainy winters.

Answer:

i) Mr. Dunn arrives to home first.

ii) 3 min

Explanation:

i. To find who arrives first to home you calculate the time, by using the following formula:

\(t=\frac{x}{v}\)

x: distance

v: velocity

Mr. Dunn:

\(t=\frac{64.8km}{48km/h}=1.35h\)

Mrs. Dunn:

\(t=\frac{81.2km}{58km/h}=1.4h\)

Hence, Mr. Dunn arrives to home first.

ii. To calculate the difference in minutes, you convert hours to minutes:

\(1.35h*\frac{60min}{1h}=81min\\\\1.40h*\frac{60min}{1h}=84min\\\\\Delta\ t=(84-81)min=3min\)

the difference between the times is 3min

(i) Mr. Dunn takes less time so he arrives at home first.

(ii) The second person arrives 3 min late.

(i) We have to calculate the time taken to reach home by Mr. Dunn and Mrs. Dunn.

t = x/v

where x is the distance

and v is the velocity

Time taken by Mr. Dunn:

distance x = 64.8 km

speed v  = 48 km/h

t = 64.8 / 48

t = 1.35 h

Time taken by Mrs. Dunn:

distance x = 81.2 km

speed v  = 58 km/h

t' = 81.2 / 58

t' = 1.4 h

Hence, Mr. Dunn arrives at home first.

(ii) To calculate the difference in minutes, you convert hours to minutes:

The time taken by Mr. Dunn in minutes is:

t = 1.35×60 = 81 minutes

The time taken by Mrs. Dunn in minutes is:

t' = 1.4×60 = 84 minutes

the difference between the times is 3min

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The final amount of pressure caused by the force is 90 N/m².

Initial amount of force, F₁ = 22 x 10³ N

Initial amount of pressure produced, P₁ = 110 N/m²

Final amount of force exerted, F₂ = 18 x 10³ N

Pressure is defined as the amount of force acting on an object per unit area of the object.

So, we can say that the force and pressure are directly proportional.

F ∝ P

So, F₁/P₁ = F₂/P₂

Therefore, the final amount of pressure caused by the force is,

P₂ = F₂P₁/F₁

P₂ = 18 x 10³x 110/22 x 10³

P₂ = 18/0.2

P₂ = 90 N/m²

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Answer:

a) False, b) True, c) true, d) true, e) True, g)  False

Explanation:

Se pide que analicemos cada expresión, f) true

a) False.   La  antena vertical tiene cargas eléctricas que se pueden mover en la direccion vertical, una onda electromagnética polarizada horizontal el campo eléctrico esta en la dirección horizontal por lo cual no puede mover los electrones que están en direccional vertical

be) True.  La radiación ultravioleta es absorvidad por la melanina del la piel y crea las quemaduras comunes de insolación.

C) False.  Todas la ondas electromagnetismo viajan en la misma velocidad c

d) True.  La Temperatura del sol es 5800K por lo cual la radiación mas intensa esta en el rango visible

e) True.  Los rayos gamma son de muy alta energía, por lo cual se producen en ransicio0n de los núcleos atmicos.

f) True.  El rango de frecuencia para las onda de radio va desde 500 Kahoy hasta 110 MHz, por lo tanto el rango de longitudes de onda es

           c= lam f

           lam = c/f

           lam = 3 108/500 103

           lam = 6 102 m

           lam = 3 108 / 110 106  

           lam = 2,72 m

los lo ttnato en todo el rango de las frecuecias de radio la lambda> 1 m

g) False.  Todas las ondas electromagnéticas viajan a la misma velocidad c( 3 108m/s)

Answer: B.

Explanation:

Weather changes more frequently than climate.

The total displacement of the object was 7.5 meters.

There's a relation between the common movement analysis graphs that we can always use. These relations are the following:

The derivative (slope) of a displacement vs. time graph gives you the function of speed vs. time. Also, when you take the speed vs. time graph and find its derivative, you will get the acceleration function of the observed body.

Now, doing to opposite of derivation (integration), we are able to calculate the displacement of an object when we integrate the function of velocity vs. time. This is not a complicated process when we have a linear function, because integration is just calculating the area under the curve or line of a graph.

In this case, the graph forms a right triangle with the x axis, therefore, we are able to calculate displacement by finding the area under the line of the graph. It could also be made with integration, we are going to do it with both processes as they are both used, and in some cases you have to strictly use one of the 2 in order to get the most precise answers.

When we observe the line, we can crearly tell that the area under the graph constitutes a right triangle. Hence, the area under the graph is given by the following formula:

\(A=\frac{bh}{2}\)

Substitute the values and calculate.

(Check attached image 1 to see where the values of b and h are taken from).

\(A=\frac{(5)(3)}{2}\\ \\A=7.5\)

Hence, the total displacement of the object was 7.5 meters.

In this method, we'll need to find the equation of the line and then generate and solve a definite integral.

Take 2 points from the line.

(0, 0) and (5, 3).

Find the slope.

Formula: \(m=\frac{y_{2} -y_{1} }{x_{2}- x_{1} }\)

\(m=\frac{3-0}{5-0}= \\ \\m= \frac{3}{5}\)

Find the equation of the line.

Formula: \(y-y_{1} =m(x-x_{1} )\)

\(y-(0) =\frac{3}{5} (x-(0) )\\ \\y=\frac{3}{5} x\\ \\\)

Integrate within the interval of interest (from 0 to 5).

\(\int\limits^5_0 {(\frac{3}{5} x)} \, dx \\ \\=\frac{3}{5} x^{2} *\frac{1}{2} \\ \\=\frac{3}{10} x^{2} \\\\ (\frac{3}{10} (5)^{2})-(\frac{3}{10} (0)^{2})\\ \\(\frac{3}{10} *25)-(0)\\ \\\frac{75}{10} \\ \\7.5\)

Once again, the total displacement of the object was 7.5 meters.

Answer:

I think it would be C since it doesn't say anything about the gravity, basically things around u change, but you don't change

Explanation:

Sorry if I got this wrong, hope this helped and have a nice day!

Answer:

4 Newton

Explanation:

because you minus 1 Newton from 5 newton

The net force on the box is equal to 4N. Therefore, option (1) is correct.

The net force can be described as the vector sum of forces acting on a particle or object. The net force can be defined as a single force showing same the effect of the original forces on the particle's motion. Net force gives the same acceleration as all those actual forces together.

The net force becomes the resultant force. It has the same effect on the rotational motion as all actual forces taken together by the object. Force is a vector quantity as it has a magnitude and a direction.

In the given problem, the applied force is in the opposite direction of the frictional force so we can find the net force by subtracting these two forces.

Given, the applied force to push the box = 5N

The frictional force on the box, = 1 N

The net force on the box = 5N + (-1N) = 4N

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Answer:

The temperature of this newly discovered planet violates the third law of thermodynamic, there is a mistake in this value.

Explanation:

The third law of the Thermodynamic says:

At zero kelvin all molecular movement stops, which means that the entropy will be zero at this temperature.

So we can say there is no thermodynamic system that has temperature values less than 0 K.

The conclusion of the report will be.

The temperature of this new planet violates the third law of thermodynamic, there is a mistake in this value.

I hope it helps you!

Explanation:

Here is the first one....you should try the second one...

Answer:

Explanation:

Total mass of cable m = 190 x .402 = 76.38 lb

moment of inertial due to this cable = m r²

= 76.38 x (14/12)²

= 103.96 lb ft²

moment of inertia of empty spoon

= mR² where R is radius of gyration

= 65 x (11 / 12 )²

= 54.61 lb ft²

Total moment of inertia I = 158.57 lb ft²

Net force applied = force applied - frictional force

= 33 - 15 = 18 lb

= 18 x 32 poundal

= 576 poundal

Torque applied = force x radius

= 576 x 14/12

= 672 unit

Angular acceleration = torque / total moment of inertia

= 672 / 158.57

= 4.238 radian / s²

Answer:A

Explanation:

Answer:

D. Mixtures are classified based on the distribution of particles in them.

Explanation:

A is wrong because mixtures are not made of elements that are bonded together chemically.

B is wrong because elements and compounds are types of pure substances.

C is wrong because pure substances are not made up of mixtures.

Please give brainliest

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

I think you would need too time your friend and know how too divide that time by other racers to see how much faster she needs to get. I THINK.

Answer:

While catching a ball, a cricket player lowers his hands, because by doing so, he increases the time of catch. That is, the person increases the time to bring about a given change in momentum, and hence rate of change of momentum decreases. Thus, a small force is exerted by ball on the hands.

Explanation:

:)

Answer:

it is your answer....... if it is helpful plzz like and comment

Answer:

\(\frac{1}{512}\) seconds

Explanation:

T = 1 / f

    where T is the period and f is frequency.

Here the frequency is 512 Hz.

Using the formula:

                                  T = \(\frac{1}{512}\) seconds

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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Answer:

Two major muscles must work together in an agonist and antagonist form to be able to move an arm.

Explanation:

The statement states that the force between both the bodies at a distance of 7.5 km equals F = 32 N.

This force that earth applies to a body is referred to as gravitational force. Its down motion of water in the river, the downwards motion if water in a stream, or an upwards motion of a ball being thrown are examples of motion brought on by gravitational influence.

F = k/d²  where k is the inverse variation's constant.

18 N = k / (10 km)²

18 N = k / 100 km²

k = (18 N) (100 km²)

k = 1800 (N)(km²)

F = ?

d = 7.5 km

k = 1800 (N) (km²)

F = 1800 (N)(km²) / (7.5 km)²

F = 1800 (N) (km²) / (55.25 km²)

F = 32 N

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