A 9,900 kg object feels a gravitational force of 12 N due to a 52,000 kg object. What is the distance between the
two objects?

Answers

Answer 1

Answer:

0.05 m

Explanation:

From the question given above, the following data were obtained:

Mass of first object (M1) = 9900 kg

Gravitational force (F) = 12 N

Mass of second object (M2) = 52000 kg

Distance apart (r) =?

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Thus, we can obtain the distance between the two objects as shown below:

F = GM1M2/r²

12 = 6.67×10¯¹¹ × 9900 × 52000 /r²

Cross multiply

12 × r² = 6.67×10¯¹¹ × 9900 × 52000

Divide both side by 12

r² = (6.67×10¯¹¹ × 9900 × 52000)/12

Take the square root of both side

r = √[(6.67×10¯¹¹ × 9900 × 52000)/12]

r = 0.05 m

Therefore, the distance between the two objects is 0.05 m


Related Questions

A ship travels at a velocity of 42 m/s in north-westerly direction. A man on the ship is walking at a velocity of 3,2 m/s from the back of the ship to the front of the ship.

What is the man’s resultant velocity in magnitude and direction?

Answers

The man’s resultant velocity is 4m/s in the north-westerly direction.

What exactly is relative speed?

According to mathematics, the relative velocity is the vector difference between the velocities of two objects. The difference between the velocities of body A and body B determines the relative velocities between them.

What is the speed of resultant?

The total of an object's component vector velocities is the resulting vector velocity. The sum of the vector forces acting on an object is equal to the scalar product of its mass and acceleration vector.

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why is red light used in photographic dark rooms​

Answers

Photographic paper reacts to light to produce the image taken by a camera and stored on film. Darkrooms used red lighting to allow photographers to control light carefully, so that light-sensitive photographic paper would not become overexposed and ruin the pictures during the developing process.

Answer:

Photographic paper reacts to light to produce the image taken by a camera and stored on film.

Explanation:

Darkrooms used red lighting to allow photographers to control light carefully so that light-sensitive photographic paper would not become overexposed and ruin the pictures during the developing process.

A car is travelling in a straight line and has its velocity uniformly reduced from 20 m * s ^ - 1 to 12m * s ^ - 1 in a distance of 80 m. The car the travels at the lower velocity for 1 minute, and then decelerates uniformly to rest in a further 12 sec. show the whole journey on a velocity-time graph and calculate
(i) the initial deceleration and the time taken to travel 80 m.
(ii) the final deceleration
(iii) the total displacement for the whole journey​

Answers

i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

What is the initial deceleration of the car?

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

v is the initial velocityu is the final velocitya is acceleration/decelerations is the displacement

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

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A force of x Newtons is applied at an angle of x degrees above the horizontal to

a mass of x kg which sits on an incline of angle x degrees. The coefficient

of friction between the mass and the incline is x. For a sufficient applied force so

that the mass moves upward , the net force is given by the expression


F_net = F * cos(α + β) - m * g * sin(β) - u * N


Note:

F_net = net force

F = applied force

α = angle of the applied force

β = angle that the mass sits on

m = mass

g = gravity

u = coefficient of friction between the mass and the incline

N = normal force of the object



Determine the expression to find the angle of the applied force (α).


Show all work/steps.

Answers

Hello,

I hope you and your family are doing well!

To find the angle of the applied force (α), you can rearrange the equation for the net force to solve for α. The equation for the net force is:

F_net = F * cos(α + β) - m * g * sin(β) - u * N

To solve for α, you can start by isolating the term containing α. You can do this by subtracting the other terms from both sides of the equation, which gives you:

F_net - F * cos(β) + m * g * sin(β) + u * N = F * cos(α + β)

Then, you can divide both sides of the equation by F * cos(β) to get:

[F_net - F * cos(β) + m * g * sin(β) + u * N] / (F * cos(β)) = cos(α + β)

Next, you can use the identity cos(a + b) = cos(a)cos(b) - sin(a)sin(b) to rewrite the right side of the equation:

[F_net - F * cos(β) + m * g * sin(β) + u * N] / (F * cos(β)) = cos(α)cos(β) - sin(α)sin(β)

Finally, you can rearrange this equation to solve for α:

α = atan2(sin(α) * cos(β) + cos(α) * sin(β), cos(α) * cos(β) - sin(α) * sin(β))

This equation gives the angle of the applied force (α) in terms of the other variables in the equation for the net force.

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Happy Holidays!

If the unit of force is 100 N, unit of length is 10 m and unit of time is 100 s. What is the unit of mass in this system of units?​

Answers

Answer: 10 kg

Explanation:

Using dimensional analysis, we can find the unit of mass in the given system:

Force (F) = mass (m) × acceleration (a)

In the given system, the unit of force is 100 N, which can be written as:

100 N = (100 kg · m/s²) × (10 m/s²)

Thus, we can see that the unit of force is equivalent to 100 kg·m/s².

Now, we can rearrange the equation to solve for mass (m):

m = F/a

Substituting the units:

m = (100 kg·m/s²) / (10 m/s²)

m = 10 kg

Therefore, the unit of mass in the given system is 10 kg.

The volume coefficient of thermal expansion for gasoline is 950 × 10 -6 K -1. By how many cubic centimeters does the volume of 1.00 L of gasoline change when the temperature rises from 30°C to 50°C?

Answers

Answer:

  19 cm³

Explanation:

The coefficient of thermal expansion is the ratio of the change in volume to the reference volume for each degree change in temperature. Hence the change in volume is found by multiplying by the reference volume and the change in temperature.

  (1000 cm³)(0.950·10⁻³/K)(50-30)K = 19 cm³ . . . volume increase

If an elevator accelerates upward at 10 ms−2 , what is the average blood pressure in the brain? What is the average blood pressure in the feet? If the elevator accelerates downward with the same acceleration, what is the average blood pressure in the brain and feet? take g = 10 ​

Answers

The average blood pressure in the brain will be higher than the average blood pressure in the feet. the average blood pressure in the brain will be lower than the average blood pressure in the feet.

When the elevator accelerates upward at \(10 ms^{-2}\), the blood pressure in the brain and feet of a person changes.

Similarly, when the elevator accelerates downward with the same acceleration, the blood pressure in the brain and feet of a person changes.

Let's discuss them one by one:Blood Pressure When Elevator Accelerates Upward at \(10 ms^{-2}\)

When the elevator accelerates upward at \(10 ms^{-2}\),  the blood pressure in the brain of a person increases, while the blood pressure in the feet of a person decreases.

This happens due to the gravitational force acting on the body.

Since the gravitational force on the head is greater than the gravitational force on the feet, the blood pressure in the brain increases while the blood pressure in the feet decreases.

Therefore, the average blood pressure in the brain will be higher than the average blood pressure in the feet.

Blood Pressure When Elevator Accelerates Downward at  \(10 ms^{-2}\) When the elevator accelerates downward at \(10 ms^{-2}\), the blood pressure in the brain of a person decreases, while the blood pressure in the feet of a person increases.

This also happens due to the gravitational force acting on the body. Since the gravitational force on the head is less than the gravitational force on the feet, the blood pressure in the brain decreases while the blood pressure in the feet increases.

Therefore, the average blood pressure in the brain will be lower than the average blood pressure in the feet.

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QUESTION 5 (Start on a new page.) A block of mass 4 kg starting from rest, at point A, slides down an inclined plane of length 3 m as shown in the diagram below. The plane is inclined by an angle of 30° to the ground. The coefficient of kinetic friction (p) is 0,2 on the inclined plane 5.2 4 kg 5.3 3 m. 30 At the bottom of the inclined plane, at point B, the object slides along a rough horizontal surface experiencing a kinetic frictional force of 19.6 N until it comes to rest at point C 5.1 B State the work-energy theorem in words. Draw a labelled free-body diagram for the block as it slides down the incline. Calculate the: 5.3.1 Kinetic frictional force the block experiences on the incline 5.3.2 Magnitude of the velocity of the block at point B 5.3.3 Distance that the object will slides on the rough horizontal surface until it stops (2) (3) (4) (5) (4) [18]​

Answers

1 Therefore, the kinetic frictional force experienced by the block on the incline is 6.784 N.

2 The magnitude of the velocity of the block at point B is approximately 5.11 m/s.

How to calculate the value

1. The formula for the kinetic frictional force is given by f = μN, where μ is the coefficient of kinetic friction and N is the normal force. Since the block is on an incline, the normal force can be calculated as N = mg * cos(θ), where θ is the angle of inclination.

N = 4 kg * 9.8 m/s² * cos(30°) = 33.92 N

f = 0.2 * 33.92 N

= 6.784 N

2. Potential energy at point A = mgh, where h is the vertical height of the incline.

Potential energy at point A = 4 kg * 9.8 m/s² * 3 m * sin(30°)

= 58.8 J

The work done by friction is given by W = f * d, where d is the distance traveled along the incline (3 m).

Work done by friction = 6.784 N * 3 m = 20.352 J

Since the work done by friction is negative (opposite to the direction of motion), the total work done on the block is:

Total work = Potential energy at A - Work done by friction

Total work = 58.8 J - 20.352 J = 38.448 J

According to the work-energy theorem, this work done on the block is equal to the change in its kinetic energy. Therefore, we have:

38.448 J = 0.5 * 4 kg * B²

Solving for B, we find:

B = √(38.448 J / (0.5 * 4 kg)) ≈ 5.11 m/s

Therefore, the magnitude of the velocity of the block at point B is approximately 5.11 m/s.

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Consider the video tutorial you just watched. Suppose we repeat the experiment, but this time place the divider closer to one side of the tube than to the other. How will the speed of the air on the wide and narrow sides of the divider compare

Answers

Answer:

The answer is "The air will move faster on the narrow side".

Explanation:

The air on the top slows down in hypertensive. This is why light travels quicker on top. This results in air deflection downwards, required for its energy conservation to generate lift, and that is why air has to be moved quicker on the narrow side by the very same airflow per unit time as it departs.

i have no question d d d d

Answers

Answer:

okay

Explanation:

why don't you have any question in this app?

The force as a function of displacement of a moving object is presented by the graph. How much work is done when the object moves from 5 m to 8 m? *

The force as a function of displacement of a moving object is presented by the graph. How much work is

Answers

Answer:

Explanation:

Work is the area under the curve between the limits

W = ½(5)(8 - 5) = 7.5 J

The work done when an object moves from 5 m to 8 m is 7.5 J.

Work done

The work done in moving an object from one point to another is equal to the product of force and displacement of the object.

W = Fs

Area under a curve

The work done on an object is equal to area under the curve

The area between point 5 m and 8 m = ¹/₂ x (8 - 5) x 5 = 7.5 J

Thus, the work done when an object moves from 5 m to 8 m is 7.5 J.

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which statements describe the Gironde ecosystem

Answers

Answer:

Gironde Ecosystem is an important biological and cultural area.

Explanation:

A spring is stretched by 0.35 m and attached to a 0.5 kg air-track glider, which is then released. The spring does 0.15 J of work on the glider as it returns to its equilibrium length. What is the value of the spring constant?

Answers

The value of the spring constant is k = 2.44 N/m

We know that work done by a spring is given by :W =  \(\frac{1}{2} kx^{2}\)

Where,

W = Work done = 0.15 J

x = stretched distance = 0.35 m

k = spring constant

Putting these values in above equation we get, k = 2.44 N/m

Spring is an object which extends or compresses on applying force. The force required should be more than the spring constant (k) to displace the spring from its equilibrium position. We use the work done by the spring formula to calculate this force. Spring also possess potential energy. For calculating the potential energy of a spring, we use Hooke’s Law. Consider a spring, when we apply force on one side of the spring, it will get compressed, as they are elastic. At this time the spring exerts its force in the direction opposite to the applied force, to expand to its original size.

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how much power does it take to do 104 J of work in 8 sec?

Answers

Answer:

Given:

W=104J

t=8sec

Solve:

P=?

Equation:

P=W/t or Fd/t

P= 104J'8sec

P=13W

A torsional pendulum has a centroidal mass moment of inertia of 0.40 kg·m2 and when given an initial twist and released is found to have a frequency of oscillation of 200 rpm. Knowing that when this pendulum is immersed in oil and given the same initial condition it is found to have a frequency of oscillation of 180 rpm, determine the damping constant for the oil. The damping constant for the oil is

Answers

0.00246914 come to the damping of the constant for the oil

Knowing that when this pendulum is immersed in oil and given the same initial condition it is found to have a frequency of oscillation of 180 rpm,0.00246914 come to the damping of the constant for the oil

what is frequency ?

The frequency can be defined as the  number of oscillation per unit time which is used for defining the cyclic process like rotation, oscillation, wave etc.

The SI unit of the frequency is denoted as  Hertz and the symbol λ represents it where one hertz means the wave completed one cycle in one second.

The frequency which explains the phenomenon of oscillatory and vibration like the mechanical vibration, sound signals, light, frequency waves etc. The  “period” represented as the time required by the wave for one oscillation, i.e., it is inversely proportional to the frequency.

If the flashes, then the period is the time between the two flashes. And the frequency is the total number of flashes per second.

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6. How much heat energy is required to change a 0.3 kg ice cube from a solid at -20 °C to steam at 120 °℃ ?​

Answers

The heat energy required to change a 0.3 kg ice cube from a solid at -20 °C to steam at 120 ℃ is 915.78 kJ.

The process of changing a 0.3 kg ice cube from solid at -20 ℃ to steam at 120 ℃ involves the following steps:

1. First, the ice cube must be warmed from -20 ℃ to 0 ℃.

The quantity of heat required can be calculated using the formula Q = mcΔT, where Q is the heat required, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

Since the ice is at a constant temperature, ΔT is equal to 0.

Hence, no heat is required to change the temperature of the ice cube from -20 ℃ to 0 ℃.

2. Second, the ice cube must be melted at 0 ℃.

The heat required to melt the ice cube can be calculated using the formula Q = mL, where Q is the heat required, m is the mass of the substance, and L is the latent heat of fusion of the substance.

For water, the latent heat of fusion is 334 J/g.

Hence, the heat required to melt the 0.3 kg ice cube is 0.3 kg x 334 J/g = 100.2 kJ.

3. Third, the liquid water must be warmed from 0 ℃ to 100 ℃.

The quantity of heat required can be calculated using the formula Q = mcΔT, where Q is the heat required, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For water, the specific heat capacity is 4.184 J/g℃.

Hence, the heat required to warm the 0.3 kg of liquid water from 0 ℃ to 100 ℃ is 0.3 kg x 4.184 J/g℃ x 100 ℃ = 125.52 kJ.

4. Fourth, the liquid water must be boiled at 100 ℃ to form steam at 100 ℃.

The heat required to boil the liquid water can be calculated using the formula Q = mL, where Q is the heat required, m is the mass of the substance, and L is the latent heat of vaporization of the substance.

For water, the latent heat of vaporization is 2260 J/g.

Hence, the heat required to boil the 0.3 kg of liquid water is 0.3 kg x 2260 J/g = 678 kJ.

5. Fifth, the steam must be heated from 100 ℃ to 120 ℃.

The quantity of heat required can be calculated using the formula Q = mcΔT, where Q is the heat required, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For steam, the specific heat capacity is 2.010 J/g℃.

Hence, the heat required to heat the 0.3 kg of steam from 100 ℃ to 120 ℃ is 0.3 kg x 2.010 J/g℃ x 20 ℃ = 12.06 kJ.6.

The total heat required to change the 0.3 kg ice cube from solid at -20 ℃ to steam at 120 ℃ is the sum of the heat required for each step.

Hence, the total heat required is 100.2 kJ + 125.52 kJ + 678 kJ + 12.06 kJ = 915.78 kJ.

Therefore, the heat energy required to change a 0.3 kg ice cube from a solid at -20 °C to steam at 120 °℃ is 915.78 kJ.

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What is the kinetic energy of a 700 kg race car that has a velocity of 80 m/s?

Answers

KE = 1/2 mv^2

KE = 1/2 (700)(80)^2

KE = 2240000 J

The diagram shows a charge moving into an electric field. Two horizontal parallel plates have equally spaced vectors going from the bottom plate to the top plate. A negatively charged sphere labeled Z in traveling horizontally in between the plates. A vector is pointing right. The top plate is labeled W. There is an X at the far end of the top plate and a Y at the far end of the bottom plate. The charge will most likely leave the electric field near which letter? W X Y Z

Answers

The negatively charged sphere Z is most likely to leave the electric field near the center of plates, which is closest to letter Y.

What is an electric field?

Physical field that surrounds electrically charged particles and exerts force on all the other charged particles in the field is called an electric field.

Negatively charged sphere labeled Z will experience a force due to  electric field created by parallel plates. Since the vector is pointing right, we can assume that electric field is also pointing right.

Electric field lines are perpendicular to plates and are equally spaced. Therefore, electric field is uniform in magnitude and direction between the plates.

As the negatively charged sphere Z travels horizontally between plates, it will experience force in the direction opposite to electric field due to its negative charge. This force will cause sphere to slow down and  stop.

Since the electric field lines are equally spaced between the plates, electric field will be strongest at the edges of plates and weakest in the center. Therefore, negatively charged sphere Z is most likely to leave the electric field near the center of plates, which is closest to letter Y.

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A 68 kg
man's arm, including the hand, can be modeled as a 79-cm
-long uniform cylinder with a mass of 3.3 kg. In raising both his arms, from hanging down to straight up, by how much does he raise his center of gravity?

Answers

Answer:

Explanation:

We can calculate the change in the man's center of gravity by considering the initial and final positions of the center of gravity of his arms.

Assuming the man's arms are initially hanging down by his sides, the center of gravity of his arms is located at the midpoint of the cylinder, which is at a distance of L/2 = 79/2 = 39.5 cm from the shoulder joint.

When the man raises his arms straight up, the center of gravity of his arms is located at the top of the cylinder, which is at a distance of L = 79 cm from the shoulder joint.

The change in the man's center of gravity is therefore:

Δh = h_final - h_initial

= L - L/2

= 79 cm - 39.5 cm

= 39.5 cm

Therefore, the man raises his center of gravity by 39.5 cm when he raises both his arms from hanging down to straight up.

Find the x-component of this
vector:
15.3 m
65.0°
Please help!

Answers

Given :

Magnitude of vector, v = 15.3 m

Angle of vector from horizon, \(\theta = 65^o\) .

To Find :

The x - component of the given vector.

Solution :

We know, a vector is given by :

\(\vec{v} = vsin\ \theta \hat{i} + v cos \ \theta \hat{j}\\\)

Now, the x - component is :

\(\vec{v_x} = vcos\ \theta \hat{j}\\\\\vec{v_x} = 15.3 \times cos\ 65^o \hat{j}\\\\\vec{v_x} = 15.3 \times 0.42\ \hat{j}\\\\\vec{v_x} = 6.426\ \hat{j}\)

Hence, this is the required solution.

Power is measured in unit of Joules per second or
a) seconds
b) hertz
c) joules
d) watts
e) newtons​

Answers

D watts yw .yea yww

What is the potential gravitational energy of a 2 kg ball thrown up in the air to a height of 7 m?

Answers

Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

This model shows DNA, chromosomes, and genes. If B is a cell and C is the nucleus, what is A?

Answers

Based on the information, we can infer that A. represents a Mitochondria.

What is a mitochondria?

Mitochondria is a term to refer to the eukaryotic cell organelles responsible for supplying most of the energy necessary for cell activity through the process called cellular respiration.

Based on the information, we can infer that the element that is labeled with the letter A is a mitochondrion because its location is that of a mitochondrion. In this case, the mitochondria is red, although in other models it can be represented with another color. In general, it is given this shape and this color to distinguish it from other elements of the cell.

Note: This question is incomplete. Here is the complete information:

Attached image

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This model shows DNA, chromosomes, and genes. If B is a cell and C is the nucleus, what is A?

You are driving home from school St at 97 km/h for 190 km and then it begins to rain and you slow to 61 km/h instantly you arrive home after five hours how far is your hometown from school

Answers

The distance of your hometown from school is 318.64 km.

Given data

Distance S = 190 km

Speed v = 97 km / h

Now, the time taken to travel S distance is calculated as,

t = S / v

t = 180 / 95

t = 1.958 hrs

Now, the total time is given as

Total time T = 4.0 h

So, remaining time t ' = T - t = 4 hrs - 1.958 hrs = 2.042 hrs

Now, the velocity after travel 190 km is v ' = 63 km/ h

Distance travel in this velocity S ' = v ' t '

= 128.6 km

Now, the distance of your hometown from school , S " = S + S '

= 190 km + 128.6 km = 318.64 km

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a stone falls From rest From the Top of a Higher tower. Ignore Air resistance and take g=9.8m/s2. calculate:
a. speed of the stone after 2 seconds
b. how far the stone has travelled after 2 seconds

Answers

a)It takes 0 seconds for the stone to hit the ground.

b)The stone has traveled 19.6 meters after 2 seconds.

When an object is dropped from a height, the motion is described as free fall. It is a special form of motion in which an object is under the sole influence of gravity. The gravitational force acting on an object is always directed towards the center of the Earth, i.e., downwards. Therefore, when an object is dropped from a height, it falls freely towards the ground, and the acceleration of the object is equal to the acceleration due to gravity, which is approximately 9.8 m/s².

In the problem given, a stone is dropped from rest from the top of a higher tower. Therefore, the initial velocity of the stone, u = 0 m/s.

a. Time taken by the stone to reach the ground:
We can use the following equation of motion to calculate the time taken by the stone to reach the ground.
v = u + at

where,
v = final velocity of the object
u = initial velocity of the object
a = acceleration of the object
t = time taken by the object to reach from initial velocity to final velocity

Since the stone is dropped from rest, the initial velocity of the stone, u = 0 m/s.

At the ground level, the final velocity of the stone, v = ?
Again, the acceleration due to gravity, a = 9.8 m/s².

Therefore, we can write the equation as:

v = u + at
v = 0 + 9.8×t
v = 9.8t m/s

When the stone hits the ground, the final velocity of the stone, v = 0 m/s.

Therefore, we can rewrite the equation as:

0 = 9.8t
t = 0 seconds (when the stone is at the top of the tower)

We have found that it takes 0 seconds for the stone to hit the ground.

b. How far the stone has travelled after 2 seconds:
We can use the following equation of motion to calculate how far the stone has travelled after 2 seconds.
s = ut + (1/2)at²

where,
s = displacement of the object
u = initial velocity of the object
a = acceleration of the object
t = time taken by the object to reach from initial velocity to final velocity

Since the stone is dropped from rest, the initial velocity of the stone, u = 0 m/s.

The acceleration due to gravity, a = 9.8 m/s².

Therefore, we can write the equation as:

s = ut + (1/2)at²
s = 0×2 + (1/2)×9.8×(2)²
s = 19.6 m

Therefore, the stone has traveled 19.6 meters after 2 seconds.

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1. Is the image projected on a movie screen real or virtual? What about the image of yourself seen in a bathroom mirror?


2. Hold a shiny spoon in front of you. What differences do you notice about the image of your face seen in the convex and concave sides?


3. Where are the images formed by each side of the spoon? In front or behind the spoon? (Try the parallax method. Look at the image of an overhead light. Hold the tip of a pencil where you think the image is. Move your head from side to side. If the image and pencil tip appear to move relative to each other, adjust the position of the pencil back and forth until they appear as one)

Answers

Answer: 1. The movie one is virtual and the bathroom mirror is real

2. The image is distorted in a way

3. Behind the spoon

Explanation:

The movie one is virtual and the bathroom mirror is real and The image is distorted in a way and Behind the spoon.

What is virtual screen?

In virtual desktops, the desktop environment is segregated from the physical device being used to access it. They are preloaded images of operating systems and apps. Over a network, users can remotely view their virtual desktops.

A virtual desktop can be accessed from any endpoint device, including a laptop, smartphone, or tablet. The user interacts with the client software that was installed on the endpoint device by the virtual desktop provider.

A virtual desktop mimics the appearance and feel of a real workstation. Because robust resources, like storage and back-end databases, are easily accessible, the user experience is frequently even better than that of a physical workstation.

Therefore, The movie one is virtual and the bathroom mirror is real and The image is distorted in a way and Behind the spoon.

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A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?

Answers

The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

What is Speed ?

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

h = 52 mu = 0Range R = 35 mg = 9.8 m/s²

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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Convert the following statement to the language used by physicists, "I am cold, please turn on the heat."​

Answers

Answer:

Explanation:fog

Why must an object turning in a circle be accelerating?

Answers

Answer:-

\( \: \)

Because the direction of the velocity vector is changing.

\( \: \)

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What kind of mirror is used in automobiles and trucks to give the
driver a wider area and smaller image of traffic behind him.?​

Answers

Answer:

Mirror used in automobile and trucks for wider area and smaller image is convex mirror.

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