a 9.00-kg hanging block (m2) is connected by a string over a pulley to a 5.00-kg block that is sliding on a flat table (m1). if the coefficient of kinetic friction is 0.200, find the tension in the string.
Answers
Kinetic friction coefficient is denoted with µ s. is given by; The Normal force has the same magnitude as the weight.
Newton’s second law for the 5.00kg mass gives
T–f k =(5.00kg)a
Similarly, for the 9.00−kg mass,
(9.00kg)g–T=(9.00kg)a
Adding these two equations gives:
(9.00kg)(9.80m/s −0.200(5.00kg)(9.80m/s
=(14.0kg)a
Which yields a=5.60m/s
2 . Plugging this into the first equation above gives
T=(5.00kg)(5.60m/s 2 )+0.200(5.00kg)(9.80m/s 2 )=37.8N
If the object or plane is inclined at an angle (), the normal force is: where m is the object's mass. And g denotes gravity's acceleration.
How do you find the coefficient of kinetic friction?The coefficient of kinetic friction is the ratio of the kinetic friction force of contacting surfaces to the normal force. Explore the definition and formula for the coefficient of kinetic friction, and learn from calculation examples for friction on an inclined plane.
This is important for understanding the coefficient of kinetic friction, which is the proportion obtained by dividing the pulling force by the pulling force.
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Related Questions
A diagnostic x-ray machine emits photons with maximum frequency of 1.03 x1019 Hz. The maximum photon energy is _____ keV.
Answers
The correct answer is 30 keV.
hf=(1.60×10−19C)(50.0×103V)
What is a x-ray machine ?Any device that uses X-rays is referred to as an X-ray machine. An X-ray generator and an X-ray detector might be part of it.
Examples comprise:
medical projection radiography equipmentcomputed tomography equipmentAirport security uses backscatter X-ray devices as "body scanners."In X-ray astronomy, detectorslearn more about x-ray machine refer:
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A rocket is launched and the observer measuring the rocket altitude is standing at a distance of 200 feet from the launcher. When the rocket reaches apogee, the observer measures an angle of 45° using an altitude scope. Calculate the altitude of the rocket to the nearest foot.
Answers
Answer:
100 foot
Explanation:
Using the formula for calculating range to calculate the speed first as shown;
Range R = U²sin 2theta/gU is the speed
theta is the observe angle
g is the acceleration due to gravity.
200 = U²sin 2(45)/9.8
Usin90 = 200 * 9.8
U² = 1960
U = √1960
U = 44.27 m/s
Get the required altitude
Altitude H = u²/2g
H = 44.27²/2(9.8)
H = 1,959.8329/19.6
H = 99.99 feet
Hence the altitude of the rocket to the nearest foot is 100 foot
To tune an instrument using beats, more information than just the beat frequency is needed. In addition to recording the intial beat frequency fnt. records the change in the frequency fbeat (increase or decrease) when they increase the tension in their low E string each member Part B Rank each member on the basis of the initial frequency of their low E string Rank from largest to smallest. To rank items as equivalent, overlap them. Hints Reset Help Aiko Evita feat, increases | hrau increases | fleau decreases | /bm/ decreases| |ん.. decreases
Answers
The ranking of the members based on the initial frequency of their low E string is as follows: Aiko, Evita, fleau, hrau, /bm/,\(ン.\)
What is the ranking of the members based on the initial frequency of their low E string?Based on the given information, the ranking of the members can be determined by considering the changes in the frequency of their low E string when they increase the tension. The members are ranked from largest to smallest initial frequency.
The ranking indicates that Aiko has the highest initial frequency, followed by Evita. Fleau has a lower initial frequency than Evita, and hrau has a lower initial frequency than fleau. /bm/ has a lower initial frequency than hrau, and\(ン\)has the smallest initial frequency among all the members.
This ranking suggests that Aiko's low E string has the highest pitch, while \(ン'\)s low E string has the lowest pitch among the members. It provides an order based on the relative frequencies of their low E strings.
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Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
Answers
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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Help please ;((((((((
Answers
Answer:
42- electromagnetic force
Explanation:
electrons keep orbiting around the nucleus thanks to electromagnetic force :)
hope this helped!
What is the location for the valence electron(s) for an atom of Barium, Ba?
O 2 electrons in energy level 3
O 2 electrons in energy level 6
O 6 electrons in energy level 2
O 1 valence electron in energy level 6
Answers
Answer:
2 electrons in energy level 6
a belt is placed around a pulley 41 cm in diameter and rotating at 242 rpm, what is the linear speed in m/s of the belt
Answers
Given
d: diameter
d = 41 cm
We need radius information so we will calculate it:
r: radius
r = d/2
r = 41/2
r = 20.5 cm
Rotating speed
w = 242 rpm
Procedure
At a distance r from the center of the rotation, a point on the object has a linear speed equal to the angular speed multiplied by the distance r. The units of linear speed are meters per second, m/s.
\(v=\omega r\)But before using the formula we need to have all the units in the same system. So we need to go from rpm to rad/s and from cm to m
\(\begin{gathered} 242\cdot\frac{\text{rev}}{\min}\cdot\frac{2\text{ pi rad }}{1\text{ rev}}\cdot\frac{1\text{ min}}{60\text{ s}} \\ 25.34\text{ rad/s} \\ \\ 20.5\text{ cm}\cdot\frac{1m}{100\operatorname{cm}} \\ 0.205\text{ m} \end{gathered}\)Now we can calculate the linear velocity of the belt.
\(\begin{gathered} v=\omega r \\ v=25.34\text{ rad/s}\cdot0.205\text{ m} \\ v=5.1947\text{ m/s} \end{gathered}\)Answer
The linear velocity of the belt would be 5.2 m/s.
Using the star finder according to the instructions given in lab and those listed on the previous page, complete each of the following: 4) Which zodiacal constellations are visible in the western sky at 6 am on January 25 ? The star finder is a device that aids in locating celestial objects when viewing the sky. Its design enables an observer to determine valuable information such as rising time, setting time, position, etc. The instructor will provide details during the lab time, but some information requires additional emphasis: - When using the star finder for actually locating celestial objects for viewing, it must be held overhead, with the compass points on the star finder matching the compass points in reality. (You may have noticed that east and west are reversed when looking down on the star finder.) - The entire star field contained within the open ellipse on the star finder represents the sky for the time and date shown. The edges of the ellipse correspond to the observer's horizon. - East and west are not located at the midpoint along the elliptical horizon between south and north. Because of the distortion involved in trying to map a threedimensional hemisphere onto a flat page, the east and west cardinal points are located north along the ellipse from their respective midpoints. - The zenth is located directly overhead for all observers and the zenith never moves. To locate and fix the position of the zenith, tape both ends of a piece of string between N and S (or noon and midnight) on the star finder, across the entire visible sky. Use an ink pen to place a dot on the string midway between the northern and southern horizons. Do not remove the string. The dot is the zenith. (Notice, as the sky moves, the zenith remains stationary and directly overhead.) - The brass rivet, about which the entire star field rotates, is the celestial north pole. Polaris happens to be located at this position. (In the real sky, all stars seem to wheel or revolve around this point.) The star finder is a device that aids in locating celestial objects when viewing the sky. Its design enables an observer to determine valuable information such as rising time, setting time, position, etc. The instructor will provide details during the lab time, but some information requires additional emphasis: - When using the star finder for actually locating celestial objects for viewing, it must be held overhead, with the compass points on the star finder matching the compass points in reality. (You may have noticed that east and west are reversed when looking down on the star finder.) - The entire star field contained within the open ellipse on the star finder represents the sky for the time and date shown. The edges of the ellipse correspond to the observer's horizon. - East and west are not located at the midpoint along the elliptical horizon between south and north. Because of the distortion involved in trying to map a threedimensional hemisphere onto a flat page, the east and west cardinal points are located north along the ellipse from their respective midpoints. - The zenith is located directly overhead for all observers and the zenith never moves. To locate and fix the position of the zenith, tape both ends of a piece of string between N and S (or noon and midnight) on the star finder, across the entire visible sky. Use an ink pen to place a dot on the string midway between the northern and southern horizons. Do not remove the string. The dot is the zenith. (Notice, as the sky moves, the zenith remains stationary and directly overhead.) - The brass rivet, about which the entire star field rotates, is the celestial north pole. Polaris happens to be located at this position. (In the real sky, all stars seem to wheel or revolve around this point.)
Answers
To determine which zodiacal constellations are visible in the western sky at 6 am on January 25, refer to the star finder and locate the corresponding positions on the celestial map.
The star finder is a helpful tool for locating celestial objects and obtaining information about the night sky. To use the star finder effectively, it should be held overhead with the compass points aligned to match the actual compass points. Keep in mind that east and west may appear reversed when looking down at the star finder.
The star finder consists of an open ellipse representing the sky for a specific time and date. The edges of the ellipse correspond to the observer's horizon. East and west are not located at the midpoint along the elliptical horizon due to the distortion caused by representing a three-dimensional hemisphere on a flat page. The east and west cardinal points are positioned north along the ellipse from their respective midpoints.
Locating the zenith is essential, as it is directly overhead for all observers and remains stationary. To find the zenith, tape both ends of a string between the north and south points on the star finder, spanning the entire visible sky. Mark a dot on the string midway between the northern and southern horizons using an ink pen. This dot represents the zenith.
By using the star finder and aligning it with the correct date and time, you can identify the zodiacal constellations visible in the western sky at 6 am on January 25. Simply locate the corresponding constellations on the star finder and observe their positions in the western region of the celestial map.
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can someone do my physics test please? 100P
Answers
your answer is c bro but if not then it's b
because you just choose c or b either one should work if you right it down right
In a closed system, as kinetic energy increases, what happens to potential energy?
Answers
1.-Sean los siguientes vectores A=3i + 2j - 7 k B=3J + 6 K + 5 i Hallar a) |A| b) A+B c) |A+B| d) A-B e) 2A+3B
Answers
Answer:
A = 2,
Explanation:
(3 + 2) - 7
2 - A: 2
3 + 6 + 5
14 - B: 14
YOUR WELCOME
Someone plz help I’ll give the right answer branliest
Answers
Answer:
the one that is clicked in the photo I think is right
Michael’s mom is driving the soccer carpool. They leave the field at 7 pm, with an odometer reading of 78,753 km. Combined the minivan and players have a mass of 2900 kg. After all the players are dropped off, it is 7:56 pm and the odometer reads 78,802 km. What was the average velocity of the minivan while traveling?
Answers
Answer:
0.875 miles/minute
Explanation:
The formula for velocity if final position - initial position divided by final time - initial time. Here, the final position
of the van was 49 km away from house, and its initial was 0, because you didn't travel anywhere initially. The final time was 56 minutes because that was how long it took to get home, and the initial was 0, because you were 0 minutes into travel at the beginning.
During a baseball game, a batter hits a pop-up to a fielder 93 m away.The acceleration of gravity is 9.8 m/s2.If the ball remains in the air for 5.4 s, howhigh does it rise?Answer in units of m
Answers
Explanation:
It is given that, a batter hits a pop-up to a fielder 93 m away, range of the projectile, R = 93 m
The ball remains in the air for 5.4 s, the time of flight is 5.4 s
Time of flight : \(T=\dfrac{2v\sin\theta}{g}\)
\(5.4=\dfrac{2v\sin\theta}{g}\\\\v\sin\theta=\dfrac{5.4\times 9.8}{2}\\\\v\sin\theta=26.46\)
Maximum height of the projectile : \(H=\dfrac{v^2\sin^2\theta}{2g}\)
We need to find H.
So,
\(H=\dfrac{(v\sin\theta)^2}{2g}\\\\H=\dfrac{(26.46)^2}{2\times 9.8}\\\\H=35.72\ m\)
So, it will rise to a height of 35.72 m.
S An ideal gas with specific heat ratio γ confined to a cylinder is put through a closed cycle. Initially, the gas is at P_i, V_i, and T_i . First, its pressure is tripled under constant. volume. It then expands adiabatically to its original pressure and finally is compressed isobarically to its original volume.(e) What was the net work done on the gas for this cycle?
Answers
The net work done on the gas for this cycle can be found by adding up the work done in each process. Where, First, its pressure is tripled under constant. volume. It then expands adiabatically to its original pressure and finally is compressed isobarically to its original volume.
In this closed cycle, the net work done on the gas can be calculated by considering the individual processes. Let's break it down step-by-step:
1. Initially, the gas is at pressure P_i, volume V_i, and temperature T_i.
2. The pressure is tripled under constant volume, which means the gas undergoes an isochoric process. In this case, no work is done because the volume remains constant.
3. Next, the gas expands adiabatically to its original pressure. During an adiabatic process, there is no heat exchange with the surroundings. The work done during an adiabatic expansion can be calculated using the formula:
W = (P_f * V_f - P_i * V_i) / (γ - 1), where P_f and V_f are the final pressure and volume, and γ is the specific heat ratio.
4. Finally, the gas is compressed isobarically to its original volume. During an isobaric process, the pressure remains constant. The work done during an isobaric compression can be calculated using the formula: W = P * (V_i - V_f), where P is the constant pressure and V_f is the final volume.
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In an exothermic reaction, energy is
the surroundings.
In an endothermic reaction, energy is
the surroundings.
Answers
Trick to identify:-
Exothermic reaction has +∆H sign on product sideEndothermic reaction has -∆H sign on product side or +∆H sign on reactant sideAnswer:
In an exothermic reaction, energy is
✔ released to
the surroundings.
In an endothermic reaction, energy is
✔ absorbed from
the surroundings.
Explanation:
To report the position of an object, first choose a reference point. Then, describe the of the object with respect to the reference point. Next, measure the from the reference point to the object.
Answers
We will understand the given concept through an example
The rat serves as your point of reference if you mentioned that the rabbit was to the left of it. You are expressing its position when you specify the distance and direction. The present separation and direction of an object from a reference point is its position.
When something moves with relation to a reference frame, like when a passenger gets off an airline or a lecturer gets up to leave, the object's position changes.the right in relation to a whiteboard. Displacement describes this shift in location.Every location helps you to achieve various location positions.Your position is defined by how you describe your place. The separation in the first illustration is one meter. The reference point helps to locate each and every point.To know more about reference point here
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The velocity in metres per second v of a car at time t seconds after the brakes are applied is given by: v = 15e-¹ m/s Predict the distance the vehicle will travel in the first two seconds of braking.
Answers
In the first two seconds of braking, the vehicle will travel approximately 20.85 meters..
How can we predict the distance traveled by the vehicle during the first two seconds of braking?The distance traveled by a vehicle during the first two seconds of braking can be predicted by integrating the velocity equation. In this case, the velocity of the car at time t seconds after the brakes are applied is given by v = \(15e^(^-^t)\) m/s.
To calculate the distance traveled, we need to integrate the velocity function over the time interval from 0 to 2 seconds.
Integrating the equation v = 15\(e^(^-^t)\)with respect to time from 0 to 2 seconds gives us:
Distance = ∫[0 to 2]( \(15e^(^-^t^)\)) dt
Evaluating the integral, we find:
Distance = \([-15e^(^-^t^)]\)from 0 to 2
Distance = \(-15e^(^-^2^) - (-15e^(^-^0^))\)
Distance = \(-15e^(^-^2^)\)+ 15
Therefore, the predicted distance the vehicle will travel in the first two seconds of braking is approximately\(-15e^(^-^2^)\)+ 15 meters.
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An 80.8kg man is standing on a frictionless ice surface when he throws a 2.3kg book at 11.8m/s. with what velocity does the man move across the ice?
Answers
The man moves across the ice with a velocity of -1 m/s.
Formula:
To calculate the velocity we would be using the formula,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Given:
After applying the law of linear momentum, we get the following value before the throw;
M₁ = Man's initial mass= 80kg,
U₁ = Initial velocity of Man = 0,
M₂= Initial mass of Book = 4kg,
U₂= Initial velocity of Book = 0.
After the throw, the book's velocity will be
M₁ = Man final mass = 80kg,
V₁ = Man's final velocity = V.
M₂ = Final mass of Book = 4kg,
V₂ = Final velocity of Book = 20 m/s
After substituting the values in the formula, we get,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Or, (80 x 0) + (4 x 0) = (80V) + (4 x 20)
Or, 0 = 80V + 80
Or, 80V = -80
Or, V = -80/80
V= -1m/s
[Note: The -ve sign shows the opposite direction]
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For a science project, you would like to horizontally suspend an 8.5 by 11 inch sheet of black paper in a vertical beam of light whose dimensions exactly match the paper.
A) If the mass of the sheet is 1.0 g, what light intensity will you need?
Answers
Thus, the light intensity needs to be equal to or greater than 0.0098 N in order to horizontally suspend the paper in the vertical beam of light.
To horizontally suspend the black paper in a vertical beam of light, the light intensity needs to be strong enough to counteract the force of gravity on the paper.
This means that the light intensity needs to be equal to or greater than the force of gravity on the paper.
The force of gravity on the paper can be calculated using the formula F = m*g, where F is the force, m is the mass, and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Plugging in the values given, we get:
F = 1.0 g * 9.8 m/s^2
F = 0.0098 N
Therefore, the light intensity needs to be equal to or greater than 0.0098 N in order to horizontally suspend the paper in the vertical beam of light.
Note that the dimensions of the vertical beam of light are not relevant to this calculation, as long as the beam is large enough to fully illuminate the paper.
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There is a 90 kg woman attached at the end of a bungee cord (k = 35 N/m) that is experiencing simple harmonic motion. How long does it take the woman to complete one cycle?
Answers
Answer:
The value is \(T =10.1 \ s\)
Explanation:
From the question we are told that
The mass of the woman is \(m = 90 \ kg\)
The spring constant of the bungee cord is \(k = 35 \ N/ m\)
Generally the period of the oscillation (i,e time taken to complete on cycle ) is mathematically represented as
\(T = 2 \pi * \sqrt{ \frac{m}{k} }\)
=> \(T = 2 * 3.142 * \sqrt{ \frac{90 }{ 35} }\)
=> \(T =10.1 \ s\)
A 5kg object is accelerated from rest to a speed of 47.5 m a second and 22 seconds what average force was exerted on the object during this period of acceleration
Answers
The force exerted by the object having a mass of 5 kg is 10.79 N
The mass of the object, m = 5 kg
The velocity of the object from rest, v = 47.5 m/s
The time taken, t = 22 s
The formula to find the force exerted on the object is
F = ma
where m is the mass of the object
a is the acceleration of the object
But we know that
a = v/t
where v is the velocity of the object
t is the time taken
So, let us substitute the equation of the acceleration in the force equation, we get
F = mv/t
Now, let us substitute the known values in the above equation,
F = 5 x 47.5 / 22
= 237.5 / 22
= 10.79
Therefore, the force exerted by the object is 10.79 N
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A string under a tension of 170 N has a frequency of 300 Hz.What will its frequency become if the tension is increased to 340 N?
Answers
The speed of the wave on a string is given by Taylor's formula:
\(v=\sqrt[]{\frac{F}{\mu}}\)where
F = tension force
μ = linear density = mass per unit length
But also we can say the speed of any wave is given by:
\(v=\lambda\times f\)where:
λ = wave length
f = frequency
Plug the second equation in the first one. We get:
\(\lambda\times f=\sqrt[]{\frac{F}{\mu}}\)Now solve for f:
\(f=\frac{1}{\lambda}\times\sqrt[]{\frac{F}{\mu}}\)Lets say wave length is the same on the second case. Since it's the same string μ will also be the same.
See that 340 N = 2 x 170, so we can write:
\(\begin{gathered} f_{new}=\sqrt[]{2}\times\frac{1}{\lambda}\sqrt[]{\frac{F}{\mu}} \\ f_{new}=\sqrt[]{2}\times f_{old} \\ f_{new}=\sqrt[]{2}\times300 \\ f_{new}\approx424Hz \end{gathered}\)What is/are the possible genotype(s) of full color coats in rabbits?
Answers
The possible genotype(s) of full color coats in rabbits is include CC, Ccch, Cch, and Cc
The genotypes can be attributed to the C gene, which controls the coat color expression. The C gene has multiple alleles: C, cch, ch, and c. In this context, full color coats in rabbits are associated with the dominant C allele. The genotype CC represents homozygous dominant rabbits, which display full color coats due to the presence of two dominant C alleles.
Heterozygous rabbits with the genotype Ccch, Cch, or Cc also exhibit full color coats, as the presence of a single dominant C allele is sufficient to express the trait fully. In these cases, the dominant C allele masks the effects of the other recessive alleles (cch, ch, and c). In summary, the possible genotypes for full color coats in rabbits include CC, Ccch, Cch, and Cc. These genotypes involve the dominant C allele, which ensures the expression of a full color coat in rabbits, regardless of the other recessive alleles present in the genotype.
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A 1.0-kg ball moving at 2.0m/s perpendicular to a wall rebounds from the wall at 1.5m/s. The change in the momentum of the ball is
Answers
The change in the momentum is -0.5 Kgm/s
What is the momentum of the object?Momentum is the product of the mass of a particle and its velocity. As a vector quantity, momentum possesses both magnitude and direction.
The amount of motion is multiplied by the mass and speed of the object in motion to determine its momentum. The fact that the thing is moving makes it a vector quantity. The result of the object's mass and velocity is what determines it.
Now we know that;
Momentum = mass * velocity
We have that the change in the momentum is;
Δp = mv - mu
Thus we have that;
Δp = 1(1.5 - 2)
Δp = -0.5 Kgm/s
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Heat always flows from ______________________ materials to ______________________ materials.
Answers
Not sure what the exact wording would be, but heat always flows from the hotter object to the colder object.
50 points!!pls help
A student has designed a car as a system. The student has included the drawing below. The student has said the car would include a GPS, a big engine, and good shocks. Is this a good design that is complete with all needed parts? If yes, your answer is complete. If no, tell me what it is missing.
Answers
Does anyone mind helping me??
Answers
Answer:i think it’s D
Explanation:
The temperature of the pressing comb and the amount of pressure used are adjusted based on the _______ of the hair. length style texture cleanliness
Answers
The temperature of the pressing comb and the amount of pressure used are adjusted based on the texture of the hair. length style texture cleanliness
Temperature is defined as the measure of the amount of hotness or coldness of the body. There are various units used to measure temperature. The most used temperature scales are Celsius, Fahrenheit and Kelvin.
Pressure is defined as the amount of force exerted per unit area. Pressure is expressed using a variety of units, some of these come from dividing a unit of force by a unit of area; the standard unit of pressure in the imperial system is the pound-force per square inch (psi), which is equivalent to one newton per square meter (N/m2) in the SI.
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the measure of the duration of an even is called ______ ?
Answers
Answer:
Time
Explanation:
Time.measures the duration in which an event occured.